convert (badfaced)16 from its hexadecimal expansion to its binary expansion

answer is y=-3x+(-1/3)

Answer:

The answer is 20 feet

Step-by-step explanation:

We know that her apartment sketch is 6 by 4 inches.

If the 6 inch side is actually 30 feet and 6 goes into 30 5 times, we should multiply 4 by 5 to get proportionate answers.

Therefore her apartment is 20*30 feet

Hope this helps

Answer: Simplifying

Step-by-step explanation:

Simplifying

4x + 6y = 12

Solving

4x + 6y = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6y' to each side of the equation.

4x + 6y + -6y = 12 + -6y

Combine like terms: 6y + -6y = 0

4x + 0 = 12 + -6y

4x = 12 + -6y

Divide each side by '4'.

x = 3 + -1.5y

Simplifying

x = 3 + -1.5y

Then you get your answer I think or hopeful get your answer. I hoped this helped!

Answer:

7y+r+8x+94

Explanation

Given the algebraic expression 7(y+2) + (8+r) + 8(x + 9)

Given A, B and C. According to distributive law;

A(B+C) = AB + AC

A is distributed over C. In the same vein

On expanding the expression;

7(y+2) + (8+r) + 8(x + 9)

7y+7(2) + 8 + r + 8(x)+ 8(9)

7y+14+8+r+8x+72

Bringing the variables and constants together

7y+r+8x+14+8+72

7y+r+8x+94

a. The function f(x) = 32/(x+4)³ for x < 0 is not a legitimate pdf

b. The function f(x) does not have a cumulative distribution function (cdf)

From the question, we have the following parameters that can be used in our computation:

f(x) = 32/(x+4)³ for x < 0

The density function f(x) is a legitimate pdf if

∫ f(x) dx = 1

So, we have

[tex]\int\limits^{\infty}_{-\infty} {\frac{32}{(x + 4)^3} \, dx = 1[/tex]

Integrate the function

[tex]-\frac{16}{(x + 4)^2}|\limits^{\infty}_{-\infty} = 1[/tex]

Expand the equation

So, we have

[tex]-\frac{16}{(\infty + 4)^2} + \frac{16}{(-\infty + 4)^2} = 1[/tex]

Evaluate the exponents

-16/∝ + 16/∝ = 1

So, we have

0 + 0 = 1

Evaluate

0 = 1

The above equation is false

This means that f(x) is not a legitimate pdf.

In (a), we proved that

f(x) is not a legitimate pdf.

This means that it does not have a cumulative distribution function (cdf)

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Answer:

8x12 and 2x2x53

Step-by-step explanation:

The sentence "All the nice girls love a sailor" can be interpreted in at least two different ways when it comes to the given sets Nice Girl and Sailor and the relation loves between them.

They are: All the nice girls love the same sailor. This interpretation would mean that there exists a sailor s ∈ Sailor such that all the girls in the set Nice Girl love s, i.e., ∀n ∈ Nice Girl, n loves s. This interpretation assumes that there is only one sailor that is loved by all the nice girls.

2. Each of the nice girls loves a different sailor. This interpretation would mean that for every girl n ∈ Nice Girl, there exists a sailor s ∈ Sailor such that n loves s, but s may be different for different girls. This interpretation assumes that each nice girl loves a different sailor.

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We are given a formula that uses the integral representation of Jy(x): $${x\over 2}\left[J_{v-1}(x) - J_{v+1}(x)\right] = v\int_0^\infty t^{v-1} J_{v-1}(xt)\,dt$$

We will use this formula to show that the spherical Bessel functions $j _v(x)$ are expressible in terms of trigonometric functions. Let $y=v-1$.

Substituting $v=y+1$, we have: $${x\over 2}\left[J_y(x) - J_{y+2}(x)\right] = (y+1)\int_0^\infty t^y J_y(xt)\,dt$$

This expression is known as a recurrence relation for spherical Bessel functions. Let us use this to derive the identity that was requested:

$${x\over 2}\left[J_{v-1}(x) - J_{v+1}(x)\right] = (v+1)\int_0^\infty t^v J_v(xt)\,dt - v\int_0^\infty t^v J_{v-1}(xt)\,dt$$

Rearranging and using the recurrence relation, we obtain:

$$J_{v+1}(x) = {2v\over x}J_v(x) - J_{v-1}(x)$$$$\begin{aligned}\sin x\,j_v(x) &= \sin x\left[{1\over x}J_v(x)\right]\\&= {1\over 2x}\left[J_{v-1}(x) - J_{v+1}(x)\right]\\&= {v+1\over x}\int_0^\infty t^v J_v(xt)\,dt - {v\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt\end{aligned}$$

Similarly, $$x^2\cos x\,j_v(x) = {v\over x}\int_0^\infty t^v J_v(xt)\,dt + {v+1\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt$$

Hence, we have shown that $j_v(x)$ can be expressed in terms of trigonometric functions as follows:$$\begin{aligned}\sin x\,j_v(x) &= {v+1\over x}\int_0^\infty t^v J_v(xt)\,dt - {v\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt\\\cos x\,j_v(x) &= {v\over x}\int_0^\infty t^v J_v(xt)\,dt + {v+1\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt\end{aligned}$$

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Answer:

4/5

Step-by-step explanation:

50-10 = 40

40/50 = 4/5

the answer is 40/50

Step-by-step explanation:

50-10=40

it's easy

The answer is 23v

steps-

remove the parentheses

2x7v+9v

multiply the number

2x7=14+19v

add them

14v+19v=23v

To determine the area of a region, we need to know the specific shape and dimensions of the region in question. The process for finding the area varies depending on the shape. P(Y - X < 1) = Area of region below y - x = 1 within the given constraints= 1/6 sq. units.

Given, f(x, y) = x + y, where 0 ≤ x ≤ 1 and 0 ≤ y ≤ 2 We are to find P(Y - X < 1)

Now, Y - X < 1 is the equation of the line in the XY plane. We have to find the area of the region below this line within the given constraints. To find this, we have to integrate over the region below the line,

i.e.,y - x = 1 implies x = y - 1∫∫R (x + y)dA = ∫₀² ∫₀^(y-1) (x + y) dx dy= ∫₀² [(y²/2) - y + (1/2)] dy= 1/6 sq. units.

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Answer:

Step-by-step explanation:

Given function f(x, y) = x + y, where 0 ≤ x ≤ 1 and 0 ≤ y ≤ 2. The probability of P(Y - X < 1) is 1/4.

Now we have to find P(Y - X < 1).

The probability of (Y - X < 1) is given by:

P(Y - X < 1) = Area of the region {(x, y): y - x < 1} / Area of the region R.

Here R is the region bounded by 0 ≤ x ≤ 1 and 0 ≤ y ≤ 2.

We know that the function f(x, y) = x + y is a plane with slope 1, and intersects the y-axis at (0, 0) and the x-axis at (0, 0).

Now the line y - x = 1 intersects the plane at x = 0 and y = 1, so the intersection point is (0, 1).

Now the area of the region {(x, y): y - x < 1} can be found by finding the area of the triangle ABC as shown below: [tex]A=\frac{1}{2}Base×Height[/tex], Where base BC is of length 1 and height AB is of length 2 - 1 = 1.

Therefore, the area of the triangle ABC is:

Area of the triangle ABC = 1/2 × 1 × 1

= 1/2

The area of the region R can be found by finding the area of the rectangle with sides of length 1 and 2.

Therefore, the area of R is:

Area of R = 1 × 2

= 2

P(Y - X < 1) = Area of the region {(x, y): y - x < 1} / Area of the region RP(Y - X < 1)

= (1/2) / 2P(Y - X < 1)

= 1/4

Therefore, P(Y - X < 1) = 1/4.

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Answer:

C. 40

Step-by-step explanation:

[tex]\frac{25}{100} = \frac{10}{y}[/tex]

[tex]\frac{1}{4} = \frac{10}{y}[/tex] (cross multiply)

40 = 1y (rewrite)

y = 40

Answer: Point Form: ( 4 , 3 ) Equation Form: x = 4 , y = 3  

Step-by-step explanation: Solve for the first variable in one of the equations, then substitute the result into the other equation.

Brainliest or a thank you please? :))

Answer:

(1) It is given that line AB is tangent to the circle at A.

∴ ∠CAB = 90º     (Tangent at any point of a circle is perpendicular to the radius throught the point of contact)

Thus, the measure of ∠CAB is 90º.

(2) Distance of point C from AB = 6 cm    (Radius of the circle)

(3) ∆ABC is a right triangle.

CA = 6 cm and AB = 6 cm

Using Pythagoras theorem, we have

BC2=AB2+CA2⇒BC=

√

62+62

⇒BC=6

√

2

 cm

Thus, d(B, C) = 6

√

2

cm

(4) In right ∆ABC, AB = CA = 6 cm

∴ ∠ACB = ∠ABC      (Equal sides have equal angles opposite to them)

Also, ∠ACB + ∠ABC = 90º            (Using angle sum property of triangle)

∴ 2∠ABC = 90º

⇒ ∠ABC =

90°

2

= 45º

Thus, the measure of ∠ABC is 45º.

Step-by-step explanation:

She should perform a correlation test.

Jenna works at a local sports bar and is interested in whether the percent tip she will receive is related to how many drinks people order. What test should she perform?

She should perform a correlation test.

What is a correlation test?

A correlation test is a statistical method used to examine the relationship between two variables. It is used to determine the degree of association between two continuous variables.

How do you carry out a correlation test?

To perform a correlation test, follow these steps:

Step 1: Collect your data.

Step 2: Determine the level of measurement of each variable.

Step 3: Calculate the correlation coefficient.

Step 4: Determine the p-value.

Step 5: Interpret the results.

Therefore she should perform a correlation test

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Answer:

77

Step-by-step explanation:

I got it right on my question

Approximately 6.3% of cups will be filled with less than 14 ounces is the answer.

Given, mean = 15 ounces and standard deviation = 0.65 ounces

The actual amount of coffee in the cup by the machine vanes according to a normal distribution.

For this, we need to calculate the z-score as z=(X-μ)/σ

We need to find the percentage of cups that will be filled with less than 14 ounces of coffee.

For this, we will calculate the probability that X < 14. So, we need to find P(X<14).

For this, we will first calculate the z-score as z = (X - μ) / σ= (14 - 15) / 0.65= -1.538

Now, we will find the area to the left of the z-score using the standard normal distribution table or calculator:

Using the standard normal distribution table, we get the area as 0.0630.

The percentage of cups that will be filled with less than 14 ounces is 6.3%.

Thus, approximately 6.3% of cups will be filled with less than 14 ounces.

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Find the sum:

1.1.1 2+6+(-7) + 10 = 11

​

11=11

The first derivative of the given function with respect to x is 0.9x^(-0.1)y^1.8 and the first derivative of the given function with respect to y is 1.8x^0.9y^0.8.

The given function is f(x, y) = x^0.9y^1.8. The question is to find the first derivative of the given function with respect to x and y respectively.

Here are the solutions; The first derivative of the given function with respect to x is given by ∂f(x, y)/∂x:∂f(x, y)/∂x = 0.9x^(-0.1)y^1.8

On the other hand, the first derivative of the given function with respect to y is given by ∂f(x, y)/∂y:∂f(x, y)/∂y = 1.8x^0.9y^(1.8 - 1)∂f(x, y)/∂y = 1.8x^0.9y^0.8

Therefore, the first derivative of the given function with respect to x is 0.9x^(-0.1)y^1.8 and the first derivative of the given function with respect to y is 1.8x^0.9y^0.8.

The above steps use the concept of partial derivatives of a function with respect to a variable that can be applied in such types of questions.

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The given function is

[tex]f(x,y) = x⁰.⁹ y¹.⁸[/tex]

Now, let's find the first derivative of the function with respect to x and y.

First derivative of the function with respect to x:

We have to use the chain rule here.

According to the chain rule,

the derivative of the outer function is multiplied by the derivative of the inner function.

The inner function is [tex]y¹.⁸,[/tex]

whose derivative with respect to x is 0.

Therefore, we only have to differentiate the outer function with respect to x.

[tex]f(x,y) = x⁰.⁹ y¹.⁸∂f/∂x = ∂/∂x (x⁰.⁹ y¹.⁸)∂f/∂x = 0.⁹x^(-0.1) y¹.⁸∂f/∂x = 0.⁹y¹.⁸/x^0.1[/tex]

First derivative of the function with respect to y:

We have to use the chain rule here.

According to the chain rule, the derivative of the outer function is multiplied by the derivative of the inner function.

The inner function is [tex]x⁰.⁹,[/tex]

whose derivative with respect to y is 0.

Therefore, we only have to differentiate the outer function with respect to y.

[tex]f(x,y) = x⁰.⁹ y¹.⁸∂f/∂y = ∂/∂y (x⁰.⁹ y¹.⁸)∂f/∂y = 1.⁸ x⁰.⁹ y^(0.8)∂f/∂y = 1.⁸x^0.9 y^0.8[/tex]

Hence, the first derivative of the given function with respect to x is

[tex]0.⁹y¹.⁸/x^0.1[/tex]

and with respect to y is [tex]1.⁸x^0.9 y^0.8.[/tex]

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Answer:

x = [tex]25.8^{o}[/tex] and y = [tex]51.4^{o}[/tex]

Step-by-step explanation:

Known that he sum of angles on a straight line is [tex]180^{o}[/tex]. From the diagram;

2y + x + y = [tex]180^{o}[/tex]

x + 3y = [tex]180^{o}[/tex] ................ 1

Also,

2x + x + 2y = [tex]180^{o}[/tex]

3x + 2y = [tex]180^{o}[/tex] .............. 2

Using the elimination method, multiply equation 1 by 3 and equation 2 by 1

3x + 9y = 540 ............ 3

3x + 2y = [tex]180^{o}[/tex] ............. 4

7y = 360

y = [tex]\frac{360}{7}[/tex]

y = [tex]51.4^{o}[/tex]

substitute the value of y in equation 1,

x + 3y = [tex]180^{o}[/tex]

x + 3(51.4) = [tex]180^{o}[/tex]

x + 154.2 = [tex]180^{o}[/tex]

x = [tex]180^{o}[/tex] - 154.2

x = [tex]25.8^{o}[/tex]

Thus, x = [tex]25.8^{o}[/tex] and y = [tex]51.4^{o}[/tex]

Answer:

(-4-y) = -6(7 - x)

Step-by-step explanation:

Answer:

3 units

Step-by-step explanation:

-1, 0, 1 ,2

( 1, 2 ,3)

Give the other person Brainliest :)

Answer:

56

Step-by-step explanation:

Answer:

just interest = 251,550. Plus loan = 446,550

Step-by-step explanation:

195,000 x 0.043(interest as a decimal) = 8385 per year.

8385 x 30(years) = 251,550

The total of $446550 amount of money have to pay after 30 years at the rate of 4.3% of the principal amount of $195000.

Compound interest is applicable when there will be a change in principle amount after the given time period.

For example, if you give anyone $500 at the rate of 10% annually then $500 is your principle amount. After 1 year the interest will be $50 and hence principle amount will become $550 now for the next year the interest will be $550, not $500.

Given that

the principle amount of $195000

The rate of interest is 4.3%

Time period 30 years.

By compound interest formula

A = P × [tex](1 + 0.00r)^{n}[/tex]

where A is the total amount, P is the principal amount,r is the rate of interest and n is the total time period.

A = $195000[tex](1 + 0.043)^{30}[/tex]

A = $689546.985

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