Convert 459 L into milliliters

Answer:

____________

in real world conditions?

it seems the most plausible.

Answer (B)

Cars are tested on closed tracks and race tracks so rule out A, D. Tha leaves us with B, C. C is kind of a real-world situation so the answer is most likely, B.

Answer:

Gamma radiation .

Explanation:

Three types of emission result at the time of nuclear emission .

alpha emission

Beta emission

Gamma radiation emission

Gamma radiation results in the emission of gamma ray . This is a very high frequency radiation . It is not a particle having charge and mass like alpha and beta emission . So it has no effect on the mass and charge of the product that is formed after gamma radiation . The only effect it has on the product is that it reduces the kinetic energy of the emitting particles or it reduces the internal energy of the product . It causes negligible change in the mass of the product and no change in the charge of the product.

That is why , generally this product is not written in the nuclear reaction .

Answer:

The answer is Gamma ray

Explanation:

Because this is a very high frequency radiation, is not a particle having charge and mass like alpha and beta emission, so it has no effect on the mass and charge of the product that is formed after gamma radiation. The only effect it has on the product is that it reduces the kinetic energy of the emitting particles or it reduces the internal energy of the product, it causes negligible change in the mass of the product and no change in the charge of the product.

Answer:

proteins carbohydrates and fats

Explanation:

Answer:

Carbohydrates, Proteins, and Fats.

Answer:

It depends on how much you stress I recommend starting calm!

Explanation:

Answer:

I'm a senior right now, but I think the subjects gradually get more difficult, it's not all too difficult though, it's just stressful because the amount of work your expected to finish.

Explanation:

Answer:

Third charge should be placed at a distance d/3

Sign is negative

Magnitude is |q| = 4Q/3

Explanation:

To find a place where a third charge, q, is placed so that all three charges will be in equilibrium would be at;

E1 = E2

Now, let the distance between the charges +Q and +4Q be d. Also, let the distance from charge +Q to the third charge q be x.

Thus;

E1 = kQ/x²

E2 = k(4Q)/(d - x)²

Since equilibrium, then;

E1 = E2 gives;

kQ/x² = k(4Q)/(d - x)²

k and Q will cancel out to give;

1/x² = 4/(d - x)²

Cross multiply to get;

(d - x)² = 4x²

Taking square root of both sides gives;

√(d - x)² = √4x²

Gives;

d - x = 2x

d = x + 2x

d = 3x

x = d/3

This is the point at which E1 = E2.

Since at equilibrium, it means that Fq + F2 = 0

Now, electric force formula is;

F = kq1*q2/r²

So; Fq = kqQ/x²

F2 = kQ(4Q)/d²

Equating Fq + F2 = 0 gives;

kqQ/x² + kQ(4Q)/d² = 0

kqQ/x² = -kQ(4Q)/d²

Like terms cancel out to get;

q/x² = -4Q/d²

q = - 4Qx²/d²

earlier we saw that x = d/3.

So, q = -4Q × (d/3)²/d²

q = -4Q × ⅓

q = - 4Q/3

Thus,it's sign is negative.

It's magnitude will be the positive value.

Thus, magnitude is;

|q| = 4Q/3

1). The sign that will be of all the given three charges being in equilibrium would be:

A). Negative

2). The magnitude to allow all the given three charges to remain in equilibrium would be:

- Magnitude [tex]|q| = 4Q/3[/tex]

Given that,

First Charge [tex]= +Q[/tex]

Second Charge[tex]= +4Q[/tex]

Third Charge [tex]= q[/tex]

The location where they will be in equilibrium would be:

[tex]E1 = E2[/tex]

So,

We will assume the distance between the first two charges i.e. +Q and +4Q as d and assume the distance from charge +Q to the third charge q as x.

Now,

[tex]E1 = kQ/x^2[/tex]

[tex]E2 = k(4Q)/(d - x)^2[/tex]

Therefore,

The equilibrium will be at:

[tex]kQ/x^2 = k(4Q)/(d - x)^2[/tex]

by solving we get,

[tex]x = d/3[/tex]

Because at equilibrium [tex]Fq + F2 = 0[/tex],

So,

F [tex]= kq1*q2/r^2[/tex]

and [tex]Fq = kqQ/x^2[/tex]

[tex]F2 = kQ(4Q)/d^2[/tex]

by resolving the equation, we get;

[tex]Fq + F2 = 0[/tex]

[tex]kqQ/x^2 + kQ(4Q)/d^2 = 0[/tex]

By solving it, we get

[tex]Magnitude(q) = - 4Q/3[/tex]

Thus, the sign is negative.  

and Magnitude |q| = 4Q/3

Thus, options A and [tex]|q| = 4Q/3[/tex] would be the correct answer.

Learn more about "Charge" here:

brainly.com/question/3412043

Answer:

a

Explanation:

Answer:

C

Explanation:

Answer:

[tex] \boxed{\sf Potential \ energy \ (PE) = 7.35 \ kJ} [/tex]

Given:

Mass (m) = 75 kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

To Find:

Potential Energy (PE)

Explanation:

The formula for potential energy due to gravity:

[tex] \boxed{ \bold{PE = mgh}}[/tex]

Substituting value of m, g & h in the formula:

[tex] \sf \implies PE = 75 \times 10 \times 9.8 \\ \\ \sf \implies PE = 7350 \: J \\ \\ \sf \implies PE = 7.35 \: kJ[/tex]

Answer:

Oh, I didn't know if u meant decigram or decagram! So for decagram there would be 10 grams and deci gram is 0.1 grams.  Hope this helps!!

Explanation:

Answer:

Hey there!

There are 10 grams in one decagram.

Let me know if this helps :)

Answer:

disassemble, break apart,divide, separate

Explanation:

just know and have learned it....

Answer:

0.543 kilogram

Explanation:

thats the answer

Answer:

V=?

S= 40m

t=5s

V=S/t

V=40/5

V=8m/s

Answer:

6.93 m/s^2

Explanation:

Given that the The net external force on the propeller of a 3.32 kg model airplane is 23 N forward

Where

Mass M = 3.32kg

Force F = 23 N

Force = mass × acceleration

Substitute all the parameters into the formula

23 = 3.32 × a

a = 23/3.32

a = 6.93 m/s^2

Therefore, the acceleration of the airplane is 6.93 m/s^2

Answer:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation, while centrifugal force is the apparent force that is felt by an object moving in a curved path that acts outwardly away from the center of rotation

Explanation:

Hope this helps!

Brainliest if correct pls

Answer:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

:)

Answer: The complete length of the path between any two points is called distance. Displacement is the direct length between any two points when measured along the minimum path between them.

Explanation: It's what's!!

Given :

Mass of block , M = 20 kg .

Force applied , F = 80 N .

Acceleration of block , [tex]a=2.5\ m/s^2[/tex] .

To Find :

The coefficient is Kinetic force friction between the block and the table .

Solution :

We know , Force equation on block is given by :

[tex]F_{net }=F-\mu_k mg \\\\ma = F-\mu_k mg \\\\20\times 2.5 = 80 -\mu_k \times 20 \times 10\\\\\mu_k\times 200=30\\\\\mu_k=\dfrac{30}{200}\\\\\ mu_k=0.15[/tex]

Therefore , coefficient is Kinetic force friction between the block and the table is 0.15 .

Hence , this is the required solution .

Answer:

[tex] \boxed{\sf Heat \ produced \ (H) = 5 \ kWh} [/tex]

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

[tex] \boxed{ \bold{ \sf H = I^2Rt}}[/tex]

Substituting values of I, R & t in the equation:

[tex] \sf \implies H = {5}^{2} \times 100 \times 2 \\ \\ \sf \implies H = 25 \times 100 \times 2 \\ \\ \sf \implies H = 5000 \\ \\ \sf \implies H = 5 \: kWh [/tex]

[tex] \therefore[/tex]

Heat developed (H) in the electric iron = 15 kWh

Answer:

a) 1.91 c/m

b) 3.62 c/m

Explanation:

See attached image

Answer:

Power is a measure of the amount of work that can be done in a given amount of time. So, the formula is the energy or work divided by time:

P = W ÷ T, where p is power , w is work and t is time.

Answer:

different temperatures

Explanation:

The independent variable would be different temperatures.

The independent variable is the variable that is manipulated or varied in an experiment in order to see the effects it will produce on another variable - the dependent variable. The values of the independent variable are directly inputted by the researcher and are not changed by any other variable throughout the experiment.

In the illustration, the effect of a variation in temperature is determined by counting the number of yeast cells. This showed that the manipulated variable is the temperature and hence, the independent variable.

Answer:

distance=speed×time.

45×20=900m.

Answer:

The roadrunner will take approximately 5.285 seconds to catch up to the rattlesnake.

Explanation:

From the statement we notice that:

1) Rattlesnake moves a constant speed ([tex]v_{S} = 0.75\,\frac{m}{s}[/tex]), whereas the roadrunner accelerates uniformly from rest. ([tex]v_{o, R} = 0\,\frac{m}{s}[/tex], [tex]a = 1\,\frac{m}{s^{2}}[/tex])

2) Initial distance between the roadrunner and rattlesnake is 10 meters. ([tex]x_{o, R} = 0\,m[/tex], [tex]x_{o,S} = 10\,m[/tex])

3) The roadrunner catches up to the snake at the end. ([tex]x_{S} = x_{R}[/tex])

Now we construct kinematic expression for each animal:

Rattlesnake

[tex]x_{S} = x_{o,S}+v_{S}\cdot t[/tex]

Where:

[tex]x_{o, S}[/tex] - Initial position of the rattlesnake, measured in meters.

[tex]x_{S}[/tex] - Final position of the rattlesnake, measured in meters.

[tex]v_{S}[/tex] - Speed of the rattlesnake, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

Roadrunner

[tex]x_{R} = x_{o,R} +v_{o,R}\cdot t +\frac{1}{2}\cdot a\cdot t^{2}[/tex]

Where:

[tex]x_{o, R}[/tex] - Initial position of the roadrunner, measured in meters.

[tex]x_{R}[/tex] - Final position of the roadrunner, measured in meters.

[tex]v_{o,R}[/tex] - Initial speed of the roadrunner, measured in meters per second.

[tex]a[/tex] - Acceleration of the roadrunner, measured in meters per square second.

[tex]t[/tex] - Time, measured in seconds.

By eliminating the final positions of both creatures, we get the resulting quadratic function:

[tex]x_{o,S}+v_{S}\cdot t = x_{o,R}+v_{o,R}\cdot t +\frac{1}{2}\cdot a \cdot t^{2}[/tex]

[tex]\frac{1}{2}\cdot a \cdot t^{2} + (v_{o,R}-v_{S})\cdot t + (x_{o,R}-x_{o,S}) = 0[/tex]

If we know that [tex]a = 1\,\frac{m}{s^{2}}[/tex], [tex]v_{o, R} = 0\,\frac{m}{s}[/tex], [tex]v_{S} = 0.75\,\frac{m}{s}[/tex], [tex]x_{o, R} = 0\,m[/tex] and [tex]x_{o,S} = 10\,m[/tex], the resulting expression is:

[tex]0.5\cdot t^{2}-0.75\cdot t -10=0[/tex]

We can find its root via Quadratic Formula:

[tex]t_{1,2} = \frac{-(-0.75)\pm \sqrt{(-0.75)^{2}-4\cdot (0.5)\cdot (-10)}}{2\cdot (0.5)}[/tex]

[tex]t_{1,2} = \frac{3}{4}\pm \frac{\sqrt{329}}{4}[/tex]

Roots are [tex]t_{1} \approx 5.285\,s[/tex] and [tex]t_{2}\approx -3.785\,s[/tex], respectively. Both are valid mathematically, but only the first one is valid physically. Hence, the roadrunner will take approximately 5.285 seconds to catch up to the rattlesnake.

Answer:

answer is 0m/ sec

please follow me.

Answer:

Well i once did an expiremnet and it exploaded in my face lol

Explanation:

Answer:

so good

Explanation: