Convert 0.0555 m to mm

it is true because 14 is 1/14

Answer:

Step-by-step explanation:

Based on the clues in the problem wording, we assume the numbers given for C and D are the weights of planes, in pounds. For whatever reason, we seem to be interested in the difference of those weights.

The difference in weights is 22,489 pounds.

The difference in weights is given by the expression 79,473 - 56,984.

We can add 16 to both numbers to make the second number a multiple of 1000. To compensate, we also add 16 to the first number.

Doing this gives the new expression 79,489 - 57,000.

The value of this expression is 22,489.

_____

Additional comments

A number of thinking processes are taught for mental math. In this process, you recognize that 984 is near 1000, so you can add a small number to make all the rightmost digits be zeros. That number will have the digits that "make a ten" working from right to left. 4 needs 6 added to make a 10. Adding 6 to 84 makes it 90. Then the 9 needs 1 added to make a 10. Now, we have 984 with 16 added, which makes 1000. Adding that 16 to 79473 to make 79489 completes the transformation we're looking for: 79489 -57000.

I believe the answer is A

Answer

2

Step-by-step explanation:

6+2=8     15/5*2=6       8-6=2

Steps to solve:

40 + 5x > 95 - 4x

~Subtract 40 to both sides

5x > 55 - 4x

~Add 4x to both sides

9x > 55

~Divide 9 to both sides

x > 55/9

Best of Luck!

Answer:

Step-by-step explanation: I have no clue

answer: 1.13622

Step by step explanation:

n:

0=(3x-4)/5

0=3x/5-4/5

x=1.3.....

Answer:

= 3

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e ([tex]x_o, y_o, z_o[/tex]) and are parallel to [tex]\dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}[/tex]

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

[tex]x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct[/tex]

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

[tex]\begin {vmatrix} x = 4+ t \\ \\ \dfrac{x-4}{1} = t \begin {vmatirx} \end {vmatrix}[/tex][tex]\begin {vmatrix} y = - 5+2t \\ \\ \dfrac{y+5}{2} =t \end {vmatrix}[/tex][tex]\begin {vmatrix} z =2+t \\ \\ \dfrac{z-2}{1} =t \end {vmatrix}[/tex]

∴

[tex]\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}[/tex]

Answer:

no

Step-by-step explanation:

You will have more time to do it, but no, try extra credit

Sorry mate hope this helps<3

I cannot see the statements you are given as options, but if x = y, and y = z, you can write that as x = y = z, which means that x = z also.

I hope this helps!

Answer:

Step-by-step explanation:

If x=y and y=z, then x=z.

Answer:

3.78x10^5

Step-by-step explanation:

Answer:

Length  is 4 less than 3

Step-by-step explanation:

Answer:

a) [tex]c=\frac{-1+\sqrt{13}}{2}[/tex] and [tex]c=\frac{-1-\sqrt{13}}{2}[/tex]

Step-by-step explanation:

The idea for the solution of this equation is to find the value of c where both parts of the piecewise-defined function are the same. So we need to take the parts of the function and set them equal to each other, so we get:

[tex]3-x^{2}=x[/tex]

and then solve for x. We move everything to one side of the equation so we get:

[tex]x^{2}+x-3=0[/tex]

and we use the quadratic formula:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

and we substitute:

[tex]x=\frac{-1\pm \sqrt{(1)^2-4(1)(-3)}}{2(1)}[/tex]

and solve

[tex]x=\frac{-1\pm \sqrt{1+12}}{2}[/tex]

[tex]x=\frac{-1\pm \sqrt{13}}{2}[/tex]

so our two answers are:

a) [tex]c=\frac{-1+\sqrt{13}}{2}[/tex] and [tex]c=\frac{-1-\sqrt{13}}{2}[/tex]

Questions 1, 2, and 5 are correct.

Question 3:

To find the common difference, we can subtract the last two numbers.

60 - 47 = 13

So, the common difference is 13

We can add 13 to each term to get the next term.

8 + 13 = 21

21 + 13 = 34

So, 8, 21, 34, 47, 60

Question 4:

To find the common difference, we can subtract the last two numbers.

8/3 - 2 = 2/3

So, the common difference is 2/3

We can add 2/3 to each term to get the next term.

0 + 2/3 = 2/3

2/3 + 2/3 = 4/3

So, 0, 2/3, 4/3, 2, 8/3

Question 4:

Since we are only given the first and last number, we need to find a number we can subtract that we get -13 at the end. The distance between 3 and -13 is 16. We can divide this by 4 since there are 4 numbers before -13.

16 / 4 = 4

Since the number is going down, the common difference is going to be -4.

Subtract find the next terms.

3 - 4 = -1

-1 - 4 = -5

-5 - 4 = -9

-9 - 4 = -13

So, 3, -1, -5, -9, -13

Best of Luck!

Step-by-step explanation:

a) The distance is the integral of the velocity vs. time graph.  We can approximate the distance using a left hand Riemann sum.  That means for each interval, use the velocity at the beginning of the interval.  Don't forget to convert mi/hr to mi/s.

d₁ = (10 s − 0 s) (183.9 mi/hr × 1 hr / 3600 s) = 0.5108 mi

d₂ = (20 s − 10 s) (169.0 mi/hr × 1 hr / 3600 s) = 0.4694 mi

d₃ = (30 s − 20 s) (105.6 mi/hr × 1 hr / 3600 s) = 0.2933 mi

d₄ = (40 s − 30 s) (99.8 mi/hr × 1 hr / 3600 s) = 0.2772 mi

d₅ = (50 s − 40 s) (124.5 mi/hr × 1 hr / 3600 s) = 0.3458 mi

d₆ = (60 s − 50 s) (177.1 mi/hr × 1 hr / 3600 s) = 0.4936 mi

d = 0.5108 + 0.4694 + 0.2933 + 0.2772 + 0.3458 + 0.4936

d = 2.390 miles

b) Do the same as part a, but this time, use a right hand Riemann sum.  Instead of using the velocity at the beginning of the interval, use the velocity at the end of the interval.

d₁ = (10 s − 0 s) (169.0 mi/hr × 1 hr / 3600 s) = 0.4694 mi

d₂ = (20 s − 10 s) (105.6 mi/hr × 1 hr / 3600 s) = 0.2933 mi

d₃ = (30 s − 20 s) (99.8 mi/hr × 1 hr / 3600 s) = 0.2772 mi

d₄ = (40 s − 30 s) (124.5 mi/hr × 1 hr / 3600 s) = 0.3458 mi

d₅ = (50 s − 40 s) (177.1 mi/hr × 1 hr / 3600 s) = 0.4936 mi

d₆ = (60 s − 50 s) (175.6 mi/hr × 1 hr / 3600 s) = 0.4878 mi

d = 0.4694 + 0.2933 + 0.2772 + 0.3458 + 0.4936 + 0.4878

d = 2.367 miles

c) The velocity decreases from 0 s to 30 s, but then increases from 30 s to 50 s, and then decreases from 50 s to 60 s.

Since the velocity doesn't consistently increase or decrease, these Riemann sums are neither lower nor upper sums.

Answer:

D. (5,1)

Step-by-step explanation:

Because it is an isosceles triangle, the next point we choose must result in two sides with the same length. This means that either the two new sides are equal, or that one of the new sides is equal to the original side. If we wanted both of the new sides to be equal, they would have to be equal distance from the new point and one of the points of the original line. However, none of the options result in both new lines being the same length.

(2,1) would result in one new length being 1 unit long (2-1 x-coordinates) and the other being square root 5 (distance from point 2,1 to point 3,3 minus both coordinates and use Pythagoras). Points 3,2 and 4,1 yield the same result: Length 1=1 unit length 2=square root 5. Length 1 = 3 unit, length 2 = square root 5.

Therefore we are looking for a point which instead yields one length which is the same length as the original. The original length was 2^2 + 2^2 = c^2 = square root 8.

If we try the point 5,1 then we get two lengths of 4 and square root 8, it forms a isosceles triangle whose base line is parallel to the x-axis.

Sorry is my explanation was confusing, it's much easier to try and draw it on a grid and visualize it. Basically the overall idea is to test the side values you get by finding the distance between the points and going with the option which results in two sides with the same length.

Hope this helped!

Answer:

D. (5,1)

Step-by-step explanation: Because it is an isosceles triangle, the next point we choose must result in two sides with the same length. This means that either the two new sides are equal, or that one of the new sides is equal to the original side. If we wanted both of the new sides to be equal, they would have to be equal distance from the new point and one of the points of the original line. However, none of the options result in both new lines being the same length.

(2,1) would result in one new length being 1 unit long (2-1 x-coordinates) and the other being square root 5 (distance from point 2,1 to point 3,3 minus both coordinates and use Pythagoras). Points 3,2 and 4,1 yield the same result: Length 1=1 unit length 2=square root 5. Length 1 = 3 unit, length 2 = square root 5.

Therefore we are looking for a point which instead yields one length which is the same length as the original. The original length was 2^2 + 2^2 = c^2 = square root 8.

If we try the point 5,1 then we get two lengths of 4 and square root 8, it forms a isosceles triangle whose base line is parallel to the x-axis.

Sorry is my explanation was confusing, it's much easier to try and draw it on a grid and visualize it. Basically the overall idea is to test the side values you get by finding the distance between the points and going with the option which results in two sides with the same length.

Answer:

i think the answer would be 150. sorry if its wrong

Step-by-step explanation:

90/3*5=

30*5=

150

Answer: 24°

Step-by-step explanation:

Given the following :

supplement of an angle is 42 degrees less than 3 times the complement of the angle

Let the angle = θ

Supplement of angle = 180° - θ

Complement of angle = 90° - θ

Supplement of angle is also said to be:

(3 × complement) - 42° = 3(90° - θ) - 42°

= 270° - 3θ - 42° = 228° - 3θ

Hence,

180° - θ = 228° - 3θ

Solve for θ

-θ + 3θ = 228° - 180°

2θ = 48°

θ = 48°/2

θ = 24°

Answer:

Step-by-step explanation:

this problem is on vector

given the vectors

a = 5i + j, and

b = i − 2j

1. summation of vector a + b

[tex]= (5i+j)+(i-2j)\\\\=5i+j+i-2j\\\\[/tex]

collect like terms

[tex]=5i+i+j-2j\\\\=6i-j\\\\[/tex]

2. 2a + 3b

[tex]= 2(5i+j)+3(i-2j)\\\\=10i+2j+3i-6j\\\\[/tex]

collecting like terms we have

[tex]=10i+2j+3i-6j\\\\=10i+3i+2j-6j\\\\=13i-4j[/tex]

(3) |a|, and |a − b|.

|a|= |5i+j|

[tex]=\sqrt{5^2+1^2} \\\\=\sqrt{25+1} \\\\=\sqrt{26} \\\\= 5.1[/tex]

also,

[tex]|a - b|= |(5i+j) -(i-2j)| \\\\ a-b= 5i+j -i+2j \\\\ a-b=5i-i+j+2j \\\\a-b= 4i+3j\\\\[/tex]

[tex]|a -b|=\sqrt{4^2+3^2} \\\\|a -b|=\sqrt{16+9} \\\\|a -b|=\sqrt{25} \\\\|a -b|=25[/tex]

Answer:

you just times the number buy 9 and 3 then divid by 3

Step-by-step explanation:

Answer:

110.7 inches

Step-by-step explanation:

Width : Height ( 46:30 )

Width is 46 and Height is 30

So 46 = 170 inches

1 = ?

1 = 170/46

=3.69 inches.

To know the height, multiply that(3.69) with 30. And you will get the inches of the height which is "110.7 inches"

Answer:

0.16

Step-by-step explanation:

The calculation of probability by applying the is shown below:-

It is evident from the pedigree that the mode of inheritance is recessive and the characteristic is recessive that's also phenotype of disease is only seen if the genotype is aa.

The genotype of 1. In pedigree Can be either AA or Aa.

The chance that the offspring of the [tex]3\times 7[/tex] cousin marriage will have the characteristic is

[tex]= \frac{1}{6}[/tex]

which gives results

= 0.16

Answer:

a). y = 0.25x + 15

b). x = 480 cups

Step-by-step explanation:

(a). Let the equation of the linear function passing through a point (x', y') is,

y - y' = m(x - x')

'm' = slope of the line

b = y-intercept

Two points lying on the linear function will be (200, 65) and (250, 77.5).

Slope of the line 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m = [tex]\frac{77.5-65}{250-200}[/tex]

   = [tex]\frac{12.5}{50}[/tex]

   = 0.25

Therefore, equation of the line passing through (200, 65) and slope 0.25 will be,

y - 65 = 0.25(x - 200)

y - 65 = 0.25x - 50

y = 0.25x + 15

(b). For y = $135 we have to calculate the number of cups of coffee produced.

135 = 0.25x + 15

0.25x = 135 - 15

0.25x = 120

x = 480 cups

Therefore, 480 cups of coffee will be produced.

Answer:

distance =

[tex] \sqrt{ \frac{10}{3} } [/tex]

Step-by-step explanation:

Without going through and deriving this (my blackboard doesn't have space and a textbook, teacher, or online tutorial is probably better for that), the equation for the distance from some point on the plane to some point in space is as follows:

[tex]distance = \frac{ax + by + cz - d }{ \sqrt{ {a}^{2} + {b}^{2} + {c}^{2} } } [/tex]

•Note that the d in the equation should actually be D but Brainly doesn't allow me to do uppercase letters on mobile it seems... Anyway, d in the equation represents the value which the equation of the plane is equal to. You only gave the plane equation so I assumed d=0 in my calculations.

•x, y, and z all come from the point which you want to find the distance to. So (x,y,z)=(0,4,3) here.

•a, b, and c all come from the components of the vector normal to the surface. For planes, it simply somes to be the coefficients in front of each part. So (a,b,c)=(5,1,2) here.

With that you just need to plug the information in and simplify for your answer. My work is in the attachment, comment with questions or if anything seems off.

Answer:

  10 ft

Step-by-step explanation:

The formula for the area of a triangle can be used. Put the known values into the formula and solve for the unknown.

  A = (1/2)bh

  15 = (1/2)(3)h

  h = 15/1.5 = 10

The triangle's height is 10 feet.

Answer:

10

Step-by-step explanation:

A=1/2*b*h

15=1/2*3*h

15=3/2*h

15=3/2h

h=15/(3/2)

h=(15/1)(2/3)

h=30/3

simplify

h=10