consider two medical tests, a and b, for a virus. test a is 90% effective at recognizing the virus when it is present, but has a 5% false positive rate (indicating that the virus is present, when it is not). test b is 95% effective at recognizing the virus, but has a 10% false positive rate. the two tests use independent methods of identifying the virus. the virus is carried by 2% of all people.Say that a person is tested for the virus using only one of the tests, and that test comes back positive for carrying the virus.Which test returning positive is more indicative of someone really carrying the virus? Justify your answer mathematically (i.e. writing down your calculations).

The average wait time to see an E.R. doctor is significantly less than 150 minutes, and we can recommend to the winery that the wait time is actually less than what is reported.

To test the hypothesis that the average wait time to see an E.R. doctor is less than 150 minutes, we can follow these steps:

State the null hypothesis: The null hypothesis is the assumption that there is no difference between the observed result and what we expect to see. In this case, the null hypothesis is that the average wait time to see an E.R. doctor is 150 minutes.

State the alternative hypothesis: The alternative hypothesis is the opposite of the null hypothesis. In this case, the alternative hypothesis is that the average wait time to see an E.R. doctor is less than 150 minutes.

Calculate the test statistic: The test statistic is a measure of the difference between the observed result and the expected result. In this case, the test statistic is the difference between the observed average wait time of 148 minutes and the expected average wait time of 150 minutes, divided by the standard deviation of 5 minutes.

Determine the critical value: The critical value is the value that determines whether the test statistic is significant or not. To determine the critical value, we need to determine the p-value of the test statistic using a significance level of 0.05.

Compare the test statistic to the critical value: If the test statistic is greater than the critical value, then the null hypothesis can be rejected. If the test statistic is less than the critical value, then the null hypothesis cannot be rejected.

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12090 people are there after 30 days when the growth rate of the population of a culture of bacteria, p(t).

Given that,

The growth rate of the population of a culture of bacteria, p(t), where t is the number of days, is 0.2 and is proportionate to the population's growth. Initially, there are 30 people.

We have to find how many people are there after 30 days. (Stop rounding your response.) and when will there be a population doubling.

We know that,

dp//dt directly proportional p

dp/dt=kp

Here,

k=0.2

dp/p=0.2dt

Integrating on both sides.

[tex]\int {1/p} \, dp =\int {0.2} \, dt[/tex]

logp=0.2t+c

p=c[tex]e^{0.2t}[/tex]

Here,

t=30

c=30

So,

p=30[tex]e^{0.2(30)}[/tex]

p=30×403

p=12090

Therefore, 12090 people are there after 30 days when the growth rate of the population of a culture of bacteria, p(t).

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Answer:

To answer these questions, we need to know the par value, coupon rate, and number of debentures issued by Charter Corp. Based on the information provided, Charter Corp. issued 2,500 debentures with a $1,000 par value and a 7% coupon rate.

a. The dollar amount of interest per bond that an investor can expect to receive each year from Charter is calculated by multiplying the par value by the coupon rate. In this case, the interest per bond would be $1,000 x 7% = $70.

b. The total interest expense per year associated with this bond issue can be calculated by multiplying the number of bonds by the interest per bond. In this case, the total interest expense would be 2,500 x $70 = $175,000.

c. The company's net after-tax interest cost associated with this bond issue can be calculated by multiplying the total interest expense by the corporate tax rate. In this case, the net after-tax interest cost would be $175,000 x 21% = $36,750.

Victor decide to go abroad and do a missionary work.

so, the correct option is A.

What happens in Frankenstein Chapter 21?

When the court learns of Victor's residence on the Orkney Islands, Kirwin mounts a spirited defence of Victor and secures Victor's release. Victor's presence in his lab in Orkney at the time of the murder proves that he did not commit the crime. Victor is taken home by Alphonse.

Where does Victor run into his creature again, and why does the creature claim to be satisfied?

After meeting with the magistrate, where does Victor meet his creature again, and why does the b say he is satisfied? They cross paths again in the cemetery. Victor is now b because he feels as miserable and alone as the monster.

Was Victor convicted at his trial?

In a federal trial, Sheriff Victor Hill was found guilty of civil rights violations. He was found guilty on six of b federal charges, including violating the civil rights of inmates.

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The required solutions following the sequence are given as,
(a) By the distance formula,
(b) By the addition of property,
(c) By the slope formula slopes of parallel lines are equal.

Here,
The coordinates of point D are (4, 5) and the coordinates of point E are (5, 3)
The distance formula is given as,

D = √[[x₂ - x₁]² + [y₂+ - y₁]²]

By distance formula,
DE = √5

Segment DE is half the length of segment AC
AC = DE + DE
AC = 2DE
AC = 2√5

The property used is an addition property.

Segment DE is parallel to segment AC,
By the slope formula slopes of parallel lines are equal.

Thus, the complete reasoning of the solution is shown above.

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Answer:

[tex]f(x)=2.6(4)^x[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{9 cm}\underline{General form of an Exponential Function}\\\\$f(x)=ab^x$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the initial value ($y$-intercept). \\ \phantom{ww}$\bullet$ $b$ is the base (growth/decay factor) in decimal form.\\\end{minipage}}[/tex]

Given points:

Substitute the given points into the formula to create two equations:

[tex]\implies 10.4=ab[/tex]

[tex]\implies 665.6=ab^4[/tex]

Divide the second equation by the first to eliminate a, then solve for b:

[tex]\implies \dfrac{665.6}{10.4}=\dfrac{ab^4}{ab}[/tex]

[tex]\implies 64=\dfrac{b^4}{b}[/tex]

[tex]\implies 64=b^3[/tex]

[tex]\implies b=\sqrt[3]{64}[/tex]

[tex]\implies b=4[/tex]

Substitute the found value of b into the first equation and solve for a:

[tex]\implies 10.4=4a[/tex]

[tex]\implies a=2.6[/tex]

Therefore, the exponential function is:

[tex]f(x)=2.6(4)^x[/tex]

The Z-value of 2.58 implies a 97.72% confidence interval. This is because the Z-value of 2.58 corresponds to a probability of 0.9974 (which is 1 - 0.0026). This 0.9974 probability is equivalent to a 97.72% confidence interval.

The Z-value of 2.58 corresponds to a probability of 0.9974 (or 1 - 0.0026). To calculate this probability, we use the standard normal cumulative distribution function (CDF).

Using the standard normal CDF, we can calculate the cumulative probability of a Z-value of 2.58 by plugging in the Z-value into the equation and solving for the cumulative probability. The standard normal CDF is given by the following equation:

P(Z <= z) = 1 - 1/2*(1 + erf(z/sqrt(2)))

Plugging in the Z-value of 2.58 into the equation, we get:

P(Z <= 2.58) = 1 - 1/2*(1 + erf(2.58/sqrt(2)))

Solving for the cumulative probability, we get:

P(Z <= 2.58) = 0.9974

This 0.9974 probability is equivalent to a 97.72% confidence interval.

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True, Building more movie theaters will cause the homicide rate to rise.There is a significant linear correlation.

What does a statistical correlation mean?

A statistical metric known as correlation, which is given as a number, describes the strength and direction of a relationship between two or more variables.

                Although there may be a correlation between two variables, this does not necessarily imply that the change in one variable is what led to the change in the values of the other variable.

Correlation does not always indicate cause. Many factors, such as multi colinearity between movie theaters and the number of killings, which both tend to rise with population, can contribute to a strong connection. In general, there are numerous factors that could account for the parallels between the two.

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Answer:

Prime numbers are odd that are greater than 2. Prime numbers are numbers that are not divisible by anything. EXAMPLE: 33 is not prime because if you take 3 times 11 then you get 33.

Step-by-step explanation:

(a) Sandy picked  [tex]1\frac{1}{2}[/tex] more buckets than Keith  .

(b) Jason have saved money for total of [tex]3\frac{3}{4}[/tex] months .

In the question ,,

Part(a)  ,

it is given that

number of buckets of apples Keith picked is =  [tex]2\frac{5}{6}[/tex] buckets ,

number of buckets of apples Sandy picked is = [tex]4\frac{1}{3}[/tex] buckets

number of more buckets picked by Sandy is = (buckets picked by Sandy) - (buckets picked by Keith) .

= [tex]4\frac{1}{3}[/tex]  -  [tex]2\frac{5}{6}[/tex]  

= 13/3 - 17/6  = 3/2 = [tex]1\frac{1}{2}[/tex] buckets .

Part(b)

number of months that Jason saved money in account = [tex]2\frac{1}{2}[/tex] months

number of months that Jason saved money in cash =  [tex]1\frac{1}{4}[/tex] months

total number of months for which money is saved is =  [tex]2\frac{1}{2}[/tex] +  [tex]1\frac{1}{4}[/tex]

Simplifying further ,

we get,

= 5/2 + 5/4

= 15/4

=  [tex]3\frac{3}{4}[/tex] months .

Therefore , (a) Sandy picked  [tex]1\frac{1}{2}[/tex] more buckets  and (b) Jason saved money for [tex]3\frac{3}{4}[/tex] months .

The given question is incomplete , the complete question is

(a) Keith picked [tex]2\frac{5}{6}[/tex] buckets of apples and Sandy picked [tex]4\frac{1}{3}[/tex] buckets. How many more buckets of apples did sandy pick ?

(b) Jayson has [tex]2\frac{1}{2}[/tex] months worth of pay saved in his account. He has [tex]1\frac{1}{4}[/tex] months worth of pay saved in cash. Altogether, how many months of  money has Jayson saved ?

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The 90% confidence interval for the true mean proportion is given by

[-0.049 , -0.001]

Given values of the problem are:

P₁ = 12.9%

P₂ = 14.9%

n₁ = 1250

n₂ = 1000

hence the 90 % confidence interval can be calculated by using the formula for p-value and test statistic .

[tex]z = (P_1 - P_2 ) \pm z\times \sqrt{\frac{P_1\times(1-p_1)}{n_1}+\frac{P_2\times(1-{P_2})}{n_2}}[/tex]

Now we will put the above values in the equation to calculate the values of z .

Using the normal distribution table we can get the z-values.

Upper limit = - 0.049

Lower limit = - 0.001

Hence the 90% confidence interval can be calculated by [-0.049 , -0.001]

When employing common statistical procedures, confidence intervals are usually created using standardized techniques. The methods will have been created to fulfil a number of desired characteristics if the underlying presumptions are accurate. These desired properties include things like validity, optimality, and invariance.

Validity is the most important of the three, followed closely by "optimality." "Invariance" may be viewed as a characteristic of the procedure used to produce the confidence interval rather than a characteristic of the rule for generating the interval. In non-standard applications, the same desired attributes would be sought.

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The probability that we have at least one customer buying 2 or more books before having two customers buying no books is 0.984.

Here is a possible MATLAB code to solve the problem:

%START

% Set the rate of the Poisson process

lambda = 4;

% Set the probabilities of N taking different values

p0 = 0.2;

p1 = 0.4;

p2 = 0.2;

% Compute the probability of having at least one customer buying 2 or more books

% before having two customers buying no books

prob = poisscdf(2-1, lambda*p0) - poisscdf(1-1, lambda*p0);

% Display the result

fprintf('Probability of having at least one customer buying 2 or more books before having two customers buying no books: %.4f\n', prob);

%END

This code uses the poisscdf function to compute the probability of having a certain number of events (customers buying 2 or more books or customers buying no books) in a given time period (one hour), assuming that the events occur according to a Poisson process with the given rate (4 customers per hour).

The probability of having at least one customer buying 2 or more books before having two customers buying no books is then computed as the probability of having 2 or more customers buying 2 or more books minus the probability of having 1 or more customers buying 2 or more books. The result is displayed using the fprintf function.

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The required simplified value o the given expression is 53.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Given expression,
= 8 - m/n + p²

Now, put m = 8 n = 2 and p = 7

So,
= 8 - 8 / 2 + 7²
= 8 - 4 + 49

= 4 + 49

= 53

Thus, the required simplified value o the given expression is 53.

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A unit increase in gender will result in decrement of -52.73 in wage provided holding all other parameter constant.

What is parameter?

A parameter is a piece of information that an equation passes on. In terms of statistics, it means something different. In contrast to statistics, which only provide information about a small portion of the population, this value provides information about the entire population.

A parameter is constant because it was determined by surveying everyone (or everything). The average age of the students in your class, for instance, might be of interest to you. Maybe after asking everyone, you discovered that the average age was 25. Given that you polled the entire class, that qualifies as a parameter. Let's say you were curious about the median age of your grade or year.

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Answer:

He need to memorize 20 times tables.

Step-by-step explanation:

.2 x 100 = 20

99 many edges must be included in any tree with 100 vertices.

This is because, in a tree, there must be one fewer edge than vertices. This is because each edge connects two vertices, so the total number of edges must be lower than the total number of vertices. Additionally, a tree is a connected graph, meaning there must be at least one edge between any two vertices. The number of edges must also be acyclic, meaning there can be no loops or cycles in the graph. Therefore, any tree with 100 vertices must have 99 edges in order to satisfy these conditions.

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Answer:

  about 323.9 mph

Step-by-step explanation:

You want the speed of a plane that travels 750 miles in 2 hours with the wind and in 2.75 hours against the wind.

The relation between time, distance, and speed is ...

  speed = distance/time

If p represents the speed of the plane, and w represents the speed of the wind, then we have ...

  p +w = 750/2 . . . . . . miles/hour with the wind

  p -w = 750/2.75 . . . . speed against the wind

Adding these two equations gives ...

  2p = 750(1/2 +1/2.75) = 750(4.75/5.50)

Dividing by 2, we have ...

  p = 375(19/22) ≈ 323.9 . . . . . miles per hour

The plane was flying about 323.9 miles per hour.

__

Additional comment

The wind speed was about 51.1 miles per hour.

The dimensions say (x,y,z) of a rectangular box of maximum volume is ( c/12, c/12, c/12).

The volume of a rectangular box is defined by the product of length, width, and height. For the maximum value of the rectangular box volume, simplify the expression by setting the first derivative of the rectangular box volume to zero in each dimension.

Let x, y, and z be the dimensions of the rectangular box. Since, the sum of the lengths of its 12 edges is a constant c. This implies

4x + 4y + 4z = c

=> x + y + z = c/4 --(1)

The volume of rectangular box = xyz

Consider xyz + lamda(x + y + z - c/4) where λ is Lagrange multiplier.

let f( x,y,z) = xyz + λ(x + y + z - c/4) --(*)

compute the partial derivatives of f( x,y,z) as

fx = yz + λ(1) = yz + λ

fy = xz + λ(1) = xz + λ

fz = xy + λ(1) = xy + λ

For critical points, set the partial derivatives equals to zero.

fx = yz + λ = 0

fy = xz + λ = 0

fz = xy + λ =0

=> xz = yz = xy = - λ

So, x = y = z

then, from equation (1) we get,

x + x + x = c/4

=> 3x = c/4 => x = c/12

thus, x = c/12, y = c/12, z = c/12

Thus, the dimensions of the rectangular box are x = y = z = c/12 or ( c/12, c/12, c/12) and

Maximum volume of rectangular box = xyz

= c³/1728

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Using the properties of the normal distribution we get the 90% confidence interval as (121.576 , 273.424)

The information given is : 185, 165, 85, 135, 80, and 225.

The mean and standard deviation can be determined.

Mean = x/n = 1185/6 = 197.5

46.125 is the standard deviation

The range of confidence

Error margin for the mean

T at 99%, df = n - 1; 6 - 1 = 5;

Margin of Error = Ts / √n

T = 4.032

And the margin of error is equal to 4.032 × 46.125 ÷ 6.

Error margin is 75.924

Range of confidence: 197.5 to 75.924

Lower border = 121.576 - 197.5 - 74.924

Upper limit: 197.5 + 74.924 = 273.424

is a collection of estimations for an unnamed parameter known as a confidence interval (CI). The most common confidence level is 95%, but when calculating confidence intervals, other levels, such 90% or 99%, are also occasionally employed.

The confidence level is a measure of how many related CIs over the long run include the actual value of the parameter. For instance, the parameter's true value should be included in 95% of all intervals produced at the 95% confidence level.

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Based on the following graph, The hippocampus in the brain is the most likely site of the lesion.

The brain is a sophisticated organ that manages every bodily function as well as thought, memories, emotions, touch, motor function, vision, respiration, temperature, and hunger. Its central nervous system or CNS, is made up of the spinal cord that emerges from the brain.

The brain regulates many bodily functions, including the function of numerous organs as well as thinking, memory, language, arm and leg motions. By controlling heart and breathing rates, it also affects how people react to stressful situations (such as completing an exam, losing a job, having a baby, being ill, etc.).

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Answer:

Step-by-step explanation:

To determine who was closer to the state record, we need to compare the distances of the jumps to the state records. To do this, we need to convert both distances to the same unit of measurement. We can convert inches to feet by dividing by 12. 38 feet 11 2/3 inches is equal to 38 + 11 2/3/12 = 38 + 0.9583333 feet = 39.9583333 feet.

Now we can compare the distances to the state records. The eighth-grade record is 40.17 feet and Alex jumped 39.9583333 feet, so he was closer to the record. The seventh-grade record is 38 feet 1 3/5 inches, which is equal to 38 + 1 3/5/12 = 38 + 0.292 feet = 38.292 feet. Eric jumped 36.89 feet, so he was not as close to the record as Alex. Therefore, the eighth graders should be awarded 100 points.

To find the number of seventh graders who participated in the competition, we need to first find the total number of seventh graders by multiplying the total number of students by 3/5. 595 x 3/5 = 357. Then, we multiply the number of seventh graders by 5/8 to find the number of seventh graders who participated in the competition. 357 x 5/8 = 214.625, or about 215 seventh graders participated in the competition.

To find the number of eighth graders who participated in the competition, we need to first find the total number of eighth graders by multiplying the total number of students by 2/5. 595 x 2/5 = 238. Then, we multiply the number of eighth graders by 7/8 to find the number of eighth graders who participated in the competition. 238 x 7/8 = 205.75, or about 206 eighth graders participated in the competition.

If f(x,y,z) is a vector field rather than a scalar function. A vector-valued function is one that has a vector value and a calculable curl. Therefore, if we calculate this value, it will once more be a vector-valued function. The right response in this case is option B.

The following considerations must be made in order to answer this question: It is specified that the divergence of a vector field is a scalar-valued function.

A vector field's specified and actual curl is a vector field. A scalar field's divergence/Curl is not specified. A scalar field's gradient is a vector field that has a definite definition. A vector field's gradient is not known.

Since F is a vector-valued function, we may discover its divergence, which will be a scalar-valued function, and since the gradient of the scalar-valued function will be a vector-valued function, this calculation is attempting to compute the gradient of the divergence of the vector field F.

Complete question:

Let f(x,y,z) be a scalar-valued function, and F(x,y,z) be a vector field. Is the following defined? If it is defined, is it a scalar-valued function or a vector field? (You are only allowed one attempt for each part of this problem.)

(a) V (Vn Defined- it is a scalar-valued function O Defined - it is a vector field O Not defined

(b) VV F) O Defined - it is a scalar-valued function Defined - it is a vector field O Not defined

(c) V (V F) Defined it is a scalar-valued function Defined - it is a vector field Not defined

(d) V (V x F) Defined it is a scalar-valued function Defined it is a vector field Not defined

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The p-value (0.0324) < α (0.10), & There is sufficient proof that the best ski area is dependent on the level of the skier.

What is the p-value?

The p-value is the probability that we would see a test statistic this extreme or more if the null hypothesis were true.

(a) Hypotheses:          

H1 : Best ski area is independent of the level of the skier      

H2 : Best ski area is dependent on the level of the skier      

(b) Expected counts:          

                                              Beginner     Intermediate    Advanced     Total  

Tahoe     Observed                 20          30               40          90

             Expected               12.41            31.03            46.55   90.00

Utah     Observed                 10             30             60    100

             Expected              13.79           34.48           51.72  100.00

Colorado    Observed                 10             40             50    100

             Expected                13.79            34.48           51.72  100.00

Total     Observed                  40             100             150  290

             Expected               40.00          100.00       150.00     290.00

(c)

All the expected counts are > 5, so we can apply the test      

(d) Test statistic:

Square Contingency Table Test for Independence  

                                              Beginner     Intermediate    Advanced     Total

Tahoe     Observed                 20          30               40          90

             Expected               12.41            31.03            46.55   90.00

              O - E                       7.59            -1.03          -6.55   0.00

             (O - E)² / E               4.64              0.03           0.92   5.59

Utah     Observed                 10             30             60    100

             Expected              13.79           34.48           51.72  100.00

                      O - E               -3.79            -4.48          8.28   0.00

             (O - E)² / E               1.04              0.58           1.32    2.95

Colorado    Observed                 10             40             50    100

             Expected                13.79            34.48           51.72  100.00

                      O - E               -3.79            5.52          -1.72   0.00

             (O - E)² / E               1.04              0.88           0.06        1.98

Total     Observed                  40             100             150  290

             Expected               40.00          100.00       150.00     290.00

                      O - E               0.00            0.00          0.00    0.00

             (O - E)² / E               6.72               1.50            2.30        10.53

                                         10.53         chi-square    

                                                 4           df    

                                      0.0324           p-value  

x² = 10.53 and p-value = 0.0324        

(e) Since the p-value (0.0324) < α (0.10), we reject H1. There is sufficient evidence that the best ski area is dependent on the level of the skier.

Hence, the p-value (0.0324) < α (0.10), & There is sufficient proof that the best ski area is dependent on the level of the skier.

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Answer:

Lisa's original weight was 172.9 pounds.

Step-by-step explanation:

Let w be Lisa's original weight and l be the weight she lost. Since Lisa lost 27% of her original weight, we have:

0.27w = l

Substituting the known value of l, we get:

0.27w = 46.71

w = 46.71 / 0.27

w = 172.9

Thus, Lisa's original weight was 172.9 pounds.

Answer:

  120

Step-by-step explanation:

You want to know the measure of the third arc of a circle where one of the arcs is labeled 114°, and a second arc is intercepted by a 63° inscribed angle.

The measure of an inscribed angle (63°) is half the measure of the arc it intercepts:

  (1/2)(arc) = 63°

  arc = 2·63° = 126° . . . . . arc opposite the 63° angle

The total of arcs of a circle total 360°.

  114° +126° +x° = 360°

  x° = 120° . . . . . . . . . subtract 240°

The value of x is 120.

Answer:

A) -18

B) 14

Step-by-step explanation:

A:

f(x) = 3x -6

f(-4) = 3(-4) - 6

f(-4) = -12 - 6

f(-4) = -18

B:

36 = 3x - 6  Add 6 to both sides

36 + 6 = 3x - 6 + 6

42 = 3x  Divide both side by 3

[tex]\frac{42}{3}[/tex] = [tex]\frac{3x}{3}[/tex]

14 = x

Answer:

5/12 of a pizza

Step-by-step explanation:

The monomials with a GCF of 7x³y with degree 5 are 7x⁴y and 14x³y².

The Highest Common Factor (HCF) of two numbers is the highest possible number that is divisible by both numbers.

In other words, the highest common factor is the common factor between the two numbers but it should be the highest among all common factors.

As per the given GCF as 7x³y,

The GCF of 14 and 7 is 7.

The GCF of x⁴y and x³y² will be x³y.

Thus,

GCF of 7x⁴y and 14x³y² = 7x³y

So monomials are 7x⁴y and 14x³y².

Hence "The monomials are 7x⁴y and 14x³y²".

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1) On the basis of extensive tests, the yield point of a particular type of mild steel-reinforcing bar,

a) 90% CI for the true average yield point of the modified bar is 8459 +/- 23.5

b) 98% CI for the true average yield point of the modified bar is 8459 +/- 23.49

2) An article reported that for a sample of kitchens with gas cooking appliances monitored during a one-week period,

a) 95% (two-sided) confidence interval for true average CO2 level in the population is 654.16 +/- 185.0632

b) Sample size is 12.

The confidence interval for the population mean is constructed about the sample mean i.e. sample mean lies at the center of the interval.

1) The yield point of a particular type of mild steel-reinforcing bar is normally distributed with

Sample size,n = 49

Sample mean , X-bar = 8459 lb,

Standard deviations, σ = 100

We have to compute 90% CI for the true average yield point of the modified bar.

α = 1 - 90% = 1- 0.90 = 0.10

a)From Standard Normal Table, the critical value at the Zα/2 = Z₀.₀₅ level of significance is 1.645.

Confidence interval formula ,

X-bar +/- Zα/2(σ /√n)

90% CI for the true average yield point of the modified bar, is

8459 +/- 1.645(100/√49)

=> 8459 +/- 1.645(100/7)

=> 8459 +/- 1.645(14.2857) = 8459 +/- 23.5

b)

Now, we have to compute 98% CI for the true average yield point of the modified bar.

α = 1 - 98% = 1 - 0.98 = 0.02

From Standard Normal Table, the critical value at the Zα/2 = Z₀.₀₁ level of significance is 2.326.

Then, Confidence interval is,

CL = 8459 +/-2.326(100/√49)

= 8459 +/- 1.645( 14.285) = 8459 +/- 23.49

2) An article reported that for a sample of kitchens with gas cooking appliances monitored during a one-week period,

Sample size, n = 48

Sample mean , X-bar= 654.16

standard deviations, σ = 162.85

a) We have to calculate and interpret a 95% (two-sided) confidence interval for true average CO2 level. α = 1 - 0.95 = 0.05 ; α/2 = 0.025

From Standard Normal Table, the critical value at the Zα/2 = Z0.025 level of significance is 1.96

95% (two-sided) confidence interval for true average CO2 level is 654.16 +/- 1.96(654.16 /√48)

= 654.16 +/- 1.96(94.42)

= 654.16 +/- 185.0632

b) The distance between the two ends limits of the interval is known as the width of the interval and it is twice the margin of error.

We have width of the interval = 47 ppm

so, Margin of error , MOE = 94

Significance level, 95%

we have to determine sample size

Margin of error formula is

MOE = Zα/2(σ/√n)

where n is sample size.

94 = 1.96 (162.85/√n)

=> √n = 162.85 × 1.96/94 = 3.39559574468

=> n = 11.53 ~ 12

Hence, sample size is 12..

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