Consider the reaction of (CH3)3CO- with iodomethane or 1-chlorobutane. Will the reaction rate increase, decrease, or remain the same if the concentration of iodomethane is increase? Explain

Answers

Answer 1

The reaction of (CH₃)₃CO- with iodomethane or 1-chlorobutane will increase the reaction rate due to an increased frequency of collisions and an increased concentration of electrophiles.

The reaction between (CH₃)₃CO- (tert-butoxide ion) and iodomethane or 1-chlorobutane is an example of an SN₂ nucleophilic substitution reaction. In SN₂ reactions, the rate-determining step involves the simultaneous attack of the nucleophile (tert-butoxide ion) on the electrophile (iodomethane or 1-chlorobutane) with the inversion of configuration.

When the concentration of iodomethane is increased in the reaction mixture, it will lead to an increase in the reaction rate. This increase occurs due to the collision theory and the effect of concentration on the reaction kinetics.

According to the collision theory, for a reaction to occur, the reactant molecules must collide with sufficient energy and proper orientation. By increasing the concentration of iodomethane, there are more iodomethane molecules available in the reaction mixture. Consequently, there will be an increased frequency of collisions between the nucleophile (tert-butoxide ion) and the electrophile (iodomethane), increasing the likelihood of successful collisions leading to a reaction.

Additionally, the rate of an SN₂ reaction is dependent on the concentration of both the nucleophile and the electrophile. In this case, as the concentration of iodomethane increases, the concentration of the electrophile increases. This increase in electrophile concentration will result in a higher reaction rate, as more electrophiles are available for reaction with the nucleophile.

Therefore, increasing the concentration of iodomethane or 1-chlorobutane in the reaction mixture will increase the reaction rate due to an increased frequency of collisions and an increased concentration of electrophiles.

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Related Questions

Which of the following chemical reactions is most likely to have the largest equilibrium constant K?
A. CH3COOH(aq) + H2O(l) CH3COO- (aq) + H3O+(aq)
B. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)
C. H3PO4(aq) + NH3(aq) H2PO4-(aq) + NH4+(aq)
D. CH3COO- (aq) + H2O(l) CH3COOH(aq) + OH-(aq)

Answers

Answer:

The answer to this question is HCl(aq) + H2O(l) = H3O+(aq) + Cl-(aq). HCl is considered a strong acid meaning it is 100% ionized in solution. The equilibrium constant is therefore very large.

Calculate the value of the equilibrium constant, kp, at 298k. N2(g) + 2NO2(g) ↹ 2NO2(g) from the following Kp values at 298 K
N2(g) + O2(g) ↹ 2NO(g), Kp = 4,0 x 10^-31 2NO(g) + O2(g) ↹ 2 NO2(g), Kp = 2.4 x 10^12

Answers

After considering the given data we conclude that the value of the equilibrium constant, Kp, for the reaction [tex]N_2(g) + 2NO_2(g)--- > 2NO_2(g)[/tex] at 298 K is [tex]4.8*10^{-17}[/tex].

To evaluate the value of the equilibrium constant, Kp, for the reaction [tex]N_2(g) + 2NO_2(g)--- > 2NO_2(g)[/tex] at 298 K, we can apply the following steps:
Write the balanced chemical equation for the reaction.
[tex]N_2(g) + 2NO_2(g) - - - > 2NO_2(g)[/tex]
Write the expression for Kp for each of the two reactions given.
[tex]Kp_1 = [NO]^2/[N_2][O_2][/tex]
[tex]Kp_2 = [NO_2]^2/[NO]^2[O_2][/tex]
Here,[tex][NO], [N_2], [O_2], and [NO_2][/tex]are the partial pressures of the respective species at equilibrium.
Stage the given values of [tex]Kp_1[/tex] and [tex]Kp_2[/tex] into the expression for Kp for the desired reaction.
[tex]Kp = Kp_2/Kp_1 = ([NO_2]^2/[NO]^2[O_2])/([NO]^2/[N_2][O_2]) = ([NO_2]^2[N_2])/[NO]^4[/tex]
Restructure the expression for Kp to solve for the unknown partial pressure of [tex]NO_2[/tex].
[tex][NO_2]^2 = Kp[NO]^4/[N_2][/tex]
Stage the given values of [tex]Kp_1[/tex] and [tex]Kp_2[/tex], and the given partial pressures of N2 and O2, into the expression for [NO].
[tex][NO] = \sqrt(Kp_1[N_2][O_2])[/tex]
Stage the calculated value of [NO] into the expression for[tex][NO_2][/tex] to obtain the equilibrium partial pressure of [tex]NO_2[/tex].
[tex][NO_2]^2 = Kp[NO]^4/[N_2][/tex]
[tex][NO_2]^2 = (2.4*10^{12} )(4.0*10^{-31} )([N_2][O_2])^2/[N_2][/tex]
[tex][NO_2]^2 = 9.6*10^{-19} [N_2][O_2]^2[/tex]
[tex][NO_2] = \sqrt(9.6*10^{-19} [N_2][O_2]^2)[/tex]
[tex][NO_2] = 3.1*10^{-10} atm[/tex]
Stage the evaluated values of [NO] and[tex][NO_2][/tex] into the expression for Kp to obtain the equilibrium constant.
[tex]Kp = ([NO_2]^2[N_2])/[NO]^4[/tex]
[tex]Kp = (9.6*10^{-19} )(3.1*10^{-10} )^2/[/\sqrt(4.0*10^{-31*1} atm)]^4[/tex]
[tex]Kp = 4.8*10^{-17}[/tex]
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A set of aqueous solution s are prepared containing different acids at the same concentration: acid, and hydrobromic acid. Which solution(s) are the most electrically acetic acid, chloric conductive? (a) chloric acid (b) hydrobromic acid (c) acetic acid (d) both chloric acid and hydrobromic acid (e) all three solutions have the same electrical conductivity

Answers

The most electrically conductive solution among the three given solutions is hydrobromic acid, which ionizes completely in the solution and produces a high amount of ions. Therefore, option (b) hydrobromic acid is the correct answer to this question.

Acids produce ions in solution, which leads to the solution being more conductive. The more ions an acid produces, the higher the electrical conductivity of the solution. Hence, to determine the electrical conductivity of the acid, we need to know the number of ions generated by the acid in the solution. Here, three acids: hydrobromic acid, acetic acid, and chloric acid have been taken at the same concentration. So, let's check the number of ions produced by each of the acids: Hydrobromic acid: It is a strong acid that dissociates completely in the aqueous solution.

The dissociation reaction is: HBr → H+ + Br−Since it ionizes completely in the solution, the electrical conductivity of the solution would be high. Acetic acid: It is a weak acid that dissociates partially in the aqueous solution. The dissociation reaction is: CH3COOH ↔ H+ + CH3COO−Since it does not ionize completely in the solution, the electrical conductivity of the solution would be low compared to hydrobromic acid. Chloric acid: It is a strong acid that dissociates completely in the aqueous solution. The dissociation reaction is: HClO3 → H+ + ClO3−Since it ionizes completely in the solution, the electrical conductivity of the solution would be high. So, the most electrically conductive solution among the three given solutions is hydrobromic acid, which ionizes completely in the solution and produces a high amount of ions. Therefore, option (b) hydrobromic acid is the correct answer to this question.

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why was there no reaction seen between barium nitrate and sodium chloride?

Answers

Barium nitrate and sodium chloride do not react with each other because both of them are soluble in water. The chemical equation for the reaction between barium nitrate and sodium chloride is given below.

Ba(NO₃)₂ + 2NaCl → BaCl₂ + 2NaNO₃

The reaction between barium nitrate and sodium chloride is a double displacement reaction, where barium cation is exchanged with sodium cation and nitrate anion is exchanged with chloride anion. But the reaction does not occur due to the solubility of barium nitrate and sodium chloride in water.The solution of barium nitrate and sodium chloride will remain clear and colorless with no precipitation forming. In fact, it is a method of testing the presence of sulfate ions in a solution. A small amount of barium nitrate is added to the solution to form barium sulfate. Since barium sulfate is insoluble, it forms a white precipitate.

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What is a chemical bond?

Answers

A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds

Explain Newton's 2nd Law of motion

Answers

Answer:

Newtons second law says that acceleration (gaining speed) happens when a force acts on a mass (object)

Explanation:

For example riding your bicycle, your bicycle is the mass and your leg muscles pushing on the pedals of your bicycle is the force.

i’m rly sorry this isn’t an answer i just need points so i can ask a test question

What is the hybridization of bromine in each of thefollowing:
a)BrF3
b)BrO2-
c)BrF5

Answers

The bromine atom in BrF3 is sp3d hybridized, in BrO2- it is sp3 hybridized, and in BrF5 it is sp3d2 hybridized.

The hybridization of bromine in each of the following compounds is as follows:

a) BrF3:

The central atom, bromine (Br), in BrF3 undergoes sp3d hybridization. It forms three sigma bonds with three fluorine atoms and has two lone pairs of electrons. The three sigma bonds are formed by overlapping of the sp3d hybrid orbitals of bromine with the 2p orbitals of the fluorine atoms.

b) BrO2-:

The central atom, bromine (Br), in BrO2- undergoes sp3 hybridization. It forms two sigma bonds with two oxygen atoms and has two lone pairs of electrons. The two sigma bonds are formed by overlapping of the sp3 hybrid orbitals of bromine with the 2p orbitals of the oxygen atoms.

c) BrF5:

The central atom, bromine (Br), in BrF5 undergoes sp3d2 hybridization. It forms five sigma bonds with five fluorine atoms and has one lone pair of electrons. The five sigma bonds are formed by overlapping of the sp3d2 hybrid orbitals of bromine with the 2p orbitals of the fluorine atoms.

Hybridization is a concept used to describe the mixing of atomic orbitals to form new hybrid orbitals in a molecule. It helps to explain the molecular geometry and bonding in the molecule. The hybridization of an atom depends on the number of sigma bonds it forms and the number of lone pairs of electrons it possesses.

In summary, the bromine atom in BrF3 is sp3d hybridized, in BrO2- it is sp3 hybridized, and in BrF5 it is sp3d2 hybridized. The hybridization of bromine determines the shape and geometry of the molecules and provides insights into the nature of their chemical bonding.

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What would be the most effective way for a scientist to get an idea of the actual age of a rock?

Answers

Answer:

Radiometric dating

Explanation:

Radiometric dating would be the most effective way since it is a technique that can establish the age of objects older than a few thousand years.

At another temperature, the rate constant is 3.25 M-2 s-1. What is the rate at this temperature for the
given concentrations?

Answers

Answer:

It's 0.00015

Explanation:

got it right on edge 2021

a. Identify the different parts of the chemical equation below. (2 points) A(s) B(l) C(g) D(aq) 1. A: _________________________
2. B: _________________________
3. C: _________________________
4. D: _________________________
5. (s): _________________________
6. (l): _________________________
7. (g): _________________________

Answers

The different parts of the chemical equation below are identified as follows:

1. A: Solid

2. B: Liquid

3. C: Gas

4. D: Aqueous

5. (s): Solid

6. (l): Liquid

7. (g): Gas

A chemical equation is a symbolic representation of a chemical reaction where reactants are written on the left side and products on the right side. These reactants and products are identified with their respective states such as solid, liquid, gas, and aqueous.

The symbols for the physical states of the reactants and products are included in parentheses, alongside their respective chemical formulas.

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KOH is used to precipitate each of the cations from the respective solutions. Determine the minimum hydroxide required for the precipitation to begin
0.085 M Fe(NO3)2 Ksp (Fe(OH)2) = 4.87x10^-17

Answers

The minimum hydroxide concentration required for the precipitation of [tex]Fe(OH)_2[/tex] to begin is [tex]1.691* 10^-^8 M.[/tex]

How do we calculate?

The balanced chemical equation for the precipitation reaction is:

[tex]Fe(OH)_2[/tex](s) ⇌ [tex]Fe^2^+[/tex](aq) + [tex]2OH^-[/tex](aq)

Ksp = [tex][Fe^2^+][OH^-]^2[/tex]

Ksp [tex]Fe(OH)_2[/tex] = [tex]4.87*10^-^1^7[/tex]

Ksp = [tex][Fe^2^+][OH^-]^2[/tex]

[tex]4.87*10^-^1^7[/tex] = (0.085)(2x)²

[tex]4.87*10^-^1^7[/tex] = 0.17x²

x² =[tex]4.87*10^-^1^7[/tex] / 0.17

x² = [tex]2.8647* 10^-^1^6[/tex]

x = [tex]1.691*10^-^8[/tex] M

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What type pf asexual reproduction produces the most offspring?

Binary Fission
Budding
Sporulation

Answers

thats kinda hot not even gon'

This is a wild guess so don’t thank me but I’m pretty sure budding or sporulation

What is an example of an organism that undergoes binary fission?

Answers

The asexual reproduction of prokaryotic cells, such as bacteria and archaea, are examples of binary fission in cellular biology.

Unicellular organisms such as amoeba and leishmania undergo binary fission.

What is binary fission?

Binary fission can be described as a form of asexual reproduction where an organism divides into two, each part having one copy of genetic material.

Binary fission can be described as a kind of asexual reproduction observed in prokaryotes and a few single-celled eukaryotes. In asexual reproduction, there is a separation of the parent cell into 2 new daughter cells. This process occurs with the division and duplication into two parts.

Binary fission is a primary of reproduction in prokaryotic organisms. Binary Fission happens without spindle apparatus formation in the cell.  The single DNA molecule starts replication and attaches each copy to parts of the cell membrane.

Prokaryotes and eukaryotes such as euglena reproduce via binary fission. This process is rapid, and its speed varies in species. The time needed by bacteria to double the cells it has is called known as doubling time.

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Which of the following pictures is a chemical change, and which is a
physical change? Explain in the boxes next to the picture.

Plz explain

Answers

Answer:

left is chemical because its chemicals, and right is physical because the ice cream is melting and thats physical

Explanation:

alcohol has a polar area at the top of the molecule and a large area that is not polar. the entire water molecule is polar. explain how these differences in polarity between alcohol and water can help explain why water evaporates more slowly than alcohol?

Answers

Water evaporates more slowly than alcohol because water has more surface tension and more cohesive force than alcohol, So it takes more time for water to evaporate than for alcohol.

In alcohol, only O-H present is hydrophilic i.e. polar. Apart from this alcohol has a large hydrocarbon group i.e. C-H present in it, which is non-polar in nature. As a result, the attractive force between the atoms in alcohol is less. As a result, during boiling, the bonds between the atoms vibrate and break quickly. So alcohol evaporates faster.

In water, the entire molecule is polar. So there exists a strong attractive force between them. So the cohesive force is more in the case of water as compared to that of alcohol. As water is boiled the O-H bonds start to vibrate, since the bond is stronger, it requires higher energy for boiling. Thus it evaporates slower.

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Identify each of the following half-reactions as either an oxidation half-reaction or a reduction half-reaction.
half-reaction
identification
Br2(1)+2e- →→2Br (aq)
Zn(s) Zn2+(aq) + 2e

Answers

The half-reaction Br[tex]_2[/tex](l) + 2[tex]e^-[/tex] → 2[tex]Br^-[/tex](aq) is a reduction half-reaction, while the half-reaction Zn(s) → [tex]Zn^{2+}[/tex](aq) + 2[tex]e^-[/tex] is an oxidation half-reaction.

The given half-reactions are:

Br[tex]_2[/tex](l) + 2[tex]e^-[/tex] → 2[tex]Br^-[/tex](aq)

Zn(s) → [tex]Zn^{2+}[/tex](aq) + 2[tex]e^-[/tex]

The oxidation and reduction reactions are defined as follows:

Oxidation reaction: A half-reaction that includes the loss of electrons is referred to as an oxidation reaction. The oxidation number of the species involved in the reaction is increased in this process.

Reduction reaction: A half-reaction that involves gaining electrons is referred to as a reduction reaction. The oxidation number of the species involved in the reaction is decreased in this process.

Now let us identify which half-reaction is oxidation and which is reduction:

Br[tex]_2[/tex](l) + 2[tex]e^-[/tex] → 2[tex]Br^-[/tex](aq) (reduction reaction)

Zn(s) → [tex]Zn^{2+}[/tex](aq) + 2[tex]e^-[/tex](oxidation reaction)

Thus, the half-reaction Br[tex]_2[/tex](l) + 2[tex]e^-[/tex] → 2[tex]Br^-[/tex](aq) is an example of a reduction half-reaction, while the half-reaction Zn(s) → [tex]Zn^{2+}[/tex](aq) + 2[tex]e^-[/tex] is an example of an oxidation half-reaction.

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consider the reaction 4 ko2(s) 2 co2(g) → 2 k2co3(s) 3 o2(g). how much oxygen is produced at stp if 10.5 moles of carbon dioxide are used at stp?

Answers

In the given reaction, 4 moles of KO2 react to produce 3 moles of O2. Therefore, if 10.5 moles of carbon dioxide (CO2) are used at STP, an equal amount of oxygen (O2) is produced. Hence, 10.5 moles of O2 will be generated.

According to the balanced chemical equation, the reaction 4 KO2(s) + 2 CO2(g) → 2 K2CO3(s) + 3 O2(g) shows that for every 4 moles of KO2, 3 moles of O2 are produced. Therefore, the molar ratio between KO2 and O2 is 4:3.

Since 10.5 moles of CO2 are used, we can use the stoichiometry of the reaction to determine the amount of O2 produced. As the reaction equation does not involve CO2, the amount of CO2 used does not directly affect the production of O2. Thus, 10.5 moles of CO2 will yield an equal amount of O2, resulting in 10.5 moles of O2 being produced at STP.

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What type of reaction does this model represent?
1. single replacement
2. double replacement
3. Decomposition
4. double displacement

Answers

Answer:

1. single replacement

Explanation:

Single replacement can be represented by AB+C ⇄B+AC, which matches the picture

Double replacement and double displacement are the same kind of reaction and can be represented by AB+CD ⇄BD+AC

Decomposition reaction can be represented by AB ⇄A+B

a 20.-milliliter sample of 0.60 m hcl is diluted with water to a volume of 40. milliliters. what is the new concentration of the solution?

Answers

The new concentration of the solution is 0.30 M.

To calculate the new concentration of the solution, we need to consider the dilution process.

Given information:

Initial volume of the HCl solution = 20 mL

Initial concentration of the HCl solution = 0.60 M

Final volume of the diluted solution = 40 mL

The number of moles of HCl in the initial solution can be calculated using the formula:

Moles = Concentration × Volume (in liters)

Initial moles of HCl = 0.60 M × (20 mL / 1000 mL/L) = 0.012 moles

During dilution, the moles of solute remain constant. Therefore, the moles of HCl in the diluted solution will also be 0.012 moles.

The final concentration of the solution can be calculated using the formula:

Final Concentration = Moles / Volume (in liters)

Final concentration = 0.012 moles / (40 mL / 1000 mL/L) = 0.30 M

Therefore, the new concentration of the solution after dilution is 0.30 M.

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Write a question here it’s simple.

Answers

Answer:

what type of question?

Explanation:

whats your favorite color???

does anyone wanna help me with my question for chemistry [i'll comment the question to you lol someone keeps sending links into my questions]

Answers

Answer:

same I was looking for a question like this I was asking question and someone kept commenting this bitly thing i dont kno I though it was just weird and frustrating lol

Here is the skeleton reaction for combustion of methane (natural gas)
CH4+O2→CO2+H2O
What are the reactants of this reaction?
Please help me :(

Answers

Answer:

CH4 and O2

Explanation:

The reactants of a chemical reaction are those that are on the left side of the chemical equation. In this case, methane (CH4) and oxygen (O2) which are on the left side, are the reactants.

How does this equation show that transmutation has taken place? 238 U – 334 Th + He 92 O A. The numbers of neither nucleons nor atoms are conserved. B. One element changes into another. O C. Atoms of different elements are present. O D. The number of nucleons is not conserved.​

Answers

Answer:

B. One element changes into another.

Explanation:

We can see from the equation that uranium is changed to thorium and helium. Transmutation is the process by which one element is changed to another through radioactive decay, nuclear bombardment, or other similar processes.

Answer:b

Explanation:

Pls someone help me hurry pls someone?????

Answers

Answer:

Becxause there is no whee5r else for the flame to go out fromk

Explanation:

NaCl

Na = 1

Cl=1

Answer:

19. because fire needs oxygen or air to keep the fire burning.

20.A molecule of sodium chloride, NaCl, consists of one atom each of sodium and chlorine. Hence, each molecule of NaCl has 2 atoms total. Similarly, we can calculate the total number of atoms in 1 mole of sodium chloride. Since 1 molecule contains 1 atom each of Na and Cl, 1 mole of NaCl will contain 1 mole each of Na and Cl.

Explanation:

Hope this helps!

Select all that apply.
Which of the following are density labels?
Okg
L
09
m
og
mL
g

Answers

ANSWER:

mL, g, m


MARK ME BRAINLIEST PLEASE

3. How much energy is needed to raise 45 grams of water from 40°C to 115 °C?

The specific heat capacity of ice is 2.06 J/g °C

The specific heat capacity of water is 4.18 J/g °C

The specific heat capacity of steam is 2.02 J/g °C

The heat of fusion of water is 334 J/g

The heat of vaporization of water is 2260 J/g.

Answers

Answer:

Q = 114349.5 J

Explanation:

Hello there!

In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:

[tex]Q_1=45g*4.18\frac{J}{g\°C}*(100\°C-40\°C)=11286J\\\\Q_2=45g* 2260 \frac{J}{g} =101700J\\\\Q_3=45*2.02\frac{J}{g\°C}*(115\°C-100\°C)=1363.5J[/tex]

Thus, the total energy turns out to be:

[tex]Q_T=11286J+101700J+1363.5J\\\\Q_T=114349.5J[/tex]

Best regards!

Hydrochloric acid can dissolve solid iron according to the following reaction
Fe(s)+2HCl(aq)>FeCl2(aq) + H2(g). What minimum mass of HCl in grams would you need to dissolve a 2.3g iron bar on a padlock? Also I need to know how much H2 would be produced by the complete reaction of the iron bar (but I can ask this as a seperate question if necessary).

Answers

The mass of the HCl that is required for the reaction is 2.92 g

The mass of the hydrogen gas produced is 0.08 g

What is stoichiometry?

Number of moles of the iron = 2.3 g/56 g/mol

= 0.04 moles

We have that 1 mole of the iron reacts with 2 moles of HCl

0.04 moles of iron would react with 0.04 * 2/1

= 0.08 moles

Mass of the HCl required = 0.08 moles * 36.5 g/mol

= 2.92 g

We have that the mole ratio of the iron and the hydrogen is 1:1 kit then follows that mass of the hydrogen produced would now be;

0.04 moles * 2 g/mol

= 0.08 g

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What do you divide the mass by to get the concentration of a solute?

Answers

You divide by the mass of the solution.

Percent by mass is the mass of the solute divided by the mass of the solution, multiplied by 100.

Example:

You dissolve a 4.00 g sugar cube in 350 mL of tea at 80 °C. The density of water at 80 °C is 0.975 g/mL. What is the percent by mass of sugar in the solution?

Solution

Step 1 — Determine mass of the solute.

The solute is the sugar cube. Mass of solute = 4.00 g.

Step 2 — Determine mass of solvent.

The solvent is the 80 °C water. Use the density of the water to find the mass.

mass of solvent = 350 mL ×

0.975

g

1

mL

= 341 g

Step 3— Determine the total mass of the solution

mass of solution = mass of solute + mass of solvent = 4.00 g + 341 g = 345 g

Step 4 — Determine percent composition by mass of the sugar solution.

% by mass =

mass of solute

mass of solution

× 100 % =

4.00

g

345

g

× 100 % = 1.159 %

The percent composition by mass of the sugar solution is 1.159 %.

The use of uranium-238 to determine the age of a geological formation is a beneficial use of
O 1.
nuclear fusion
2.
nuclear fission
3.
radioactive isomers
4.
radioactive isotopes

Answers

Answer:

4- radioactive isotopes

Explanation:

I don't remember exactly but this question was on the regents

Uranium-238  is a non- fissile element. It is a radioactive isotope that can be best used to determine geological formations. Thus, option 4 is correct.

What are radioactive isotopes?

Radioactive isotopes are elements that have an unstable atomic nucleus and can undergo radioactive decay to produce new particles and energy. They have the same atomic number as that of their parent species.

Isobars are a substance that has atomic mass and do not include uranium. Nuclear fusion and fission are the processes of nuclear energy that combine or splits the unstable nucleus to form a new particle.

Therefore, option 4. Uranium-238 is a radioactive isotope.

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1. Which graph represents the endothermic reaction?


2. Which graph represents the exothermic reaction?

Answers

A is endothermic because heat is gained
B is exothermic because heat is lost
Other Questions
In the Stage 3 Decision Stage of the Strategy Formulation and Analytical Framework ("SFAF"), it uses Quantitative Strategic Planning Matrix ("QSPM") to evaluate and select the optimal strategy alternative. Discuss seven positive features and three limitations of QSPM. Give reasons to support your answers. A 6-month 80-strike put option on a stock is selling for $3.5. The risk-free interest rate, compounded continuously, is 2% per annum. The stock has a current price of $90 and the dividend yield of the stock (also compounded continuously) is 3% per annum. All options in this question are European. (a) A 6-month 80-strike call option is also available. Calculate the price of this option using the put-call parity. (b) A 6-month 70-strike call option on the same stock has a price of $15, and a 6-month 90-strike call option on the same stock has a price of $7. Show that at least one of the options mentioned in this question is mispriced by constructing a portfolio that allows you to effect arbitrage using: the 70-strike call option; the 80-strike call option in part (a); and the 90-strike call option. Assume that you can borrow and lend at the risk-free rate and that there are no transaction costs.(c) Suppose the stock's annual volatility is 30%. Using a 3-period binomial tree model, calculate the price of a 6-month 60-strike call option. Apparel Leasing Company signs a lease agreement on January 1, 2021, to lease equipment to Oman Company. The term of the non-cancelable lease is & years, and payments arerequired at the end of each year. The following information related to this agreement:1. The equipment has a cost and fair value of $28,500,000 to Apparel, an estimated useful life of 10 years, and no residual value at the end of that time. Annual lease rental is$4,324,818.2. Apparel Company desires to earn an 8% return on its investment.Instructions:A) Prepare an amortization schedule for the lessor for 2021 and 2022.B) Prepare the journal entries on the lessor's books on January 1, 2021 and December 31, 2021. __ is the problem confronting the decision maker. it asks what the decision maker needs to do. True or false? What Initial markup % is need for this specialty store buyer? Remember- your book examples include markdowns in this equation, but it should also include ALL items that reduce income (also known as Reductions). Take a look at the list below. Add those items to the markdown figure and use that total as your markdown total. Write your answer as a number carried to two decimal places - do not include the % sign. Net Sales $500,000 Expenses 28% Markdowns $115,000 Shortages $8,880 Employee discounts $30,400 Profit Goal 25% Which of the following rights do common stockholders typically not have?Select one:A. Right to vote and the right to elect the board of directorsB. Right to receive the final distribution of assets in liquidation after prior claims have been settledC. Right to participate in additional issues of stockD. Right to receive dividends at a predetermined rate when describing the environment at the restaurant, what are three details that you need to include to describe the place? american sign language Given below are the transactions for B. Stern Company. For each transaction state the account(s) to be debited and account(s) to be credited and indicate the journal (whether it is Purchase Journal, Sales Journal, Cash Payment Journal, Cash Receipt Journal or General Journal) in which each transaction should be recorded.a. Purchased supplies on accountb. Paid utilities expensesC. Returned half of the goods purchased in transaction a.D. Purchased merchandise for cash.Use the following headings to answer the above questionDebit Credit Journal What is wrong with this experiment? In 1668 Francesco Redi did a series of experiments on spontaneous generation. He began by putting similar pieces of meat into 12 identical jars. Four jars were left open to the air, four were sealed, and four were covered with gauze (the gauze will exclude the flies while allowing the meat to be exposed to air). In both experiments, he monitored the jars and recorded whether or not maggots (young flies) appeared in the meat. In both experiments, flies appeared in all of the open jars and only in the open jars.- - - - -Answers:- This experiment does not have a control group.- There was no dependent variable.- The experiment does not have a question.- This experiment is a well-designed experiment and has nothing wrong with it. This week, we have examined the professional certificationstandards of two professional human resource organizations - theSociety for Human Resource Management, and the Human ResourcesCertification 4.1 According to Generally Recognised Accounting Practice (GRAP) 1.96 list six items that should appear on the face of the statement of financial performance.4.2 Complete the table provided by ticking or X to show where the items on the left column would appear on Stanford & Sons purchases ledger control account. Also, indicate by a tick or X in the column titled no entry if the item would not appear in the purchases ledger control account. When the bond sells at par, the implicit /S exchange rate at maturity of a Euro/U.S. dollar dual currency bond that pays $625 at maturity per 1,000, is O 1.79/$1.00. O 1/$1.00. 1,54/51.00. 1.80/$1.00. eighty year old bill cosby was convicted for bootlegging moonshine with Two friends, Karen and Jodi, work different shifts for the same ambulance service. They wonder if the different shifts average different numbers of calls. Looking at past records, Karen determines from a random sample of 31 shifts that she had a mean of 5.3 calls per shift. She knows that the population standard deviation for her shift is 1.1 calls. Jodi calculates from a random sample of 41 shifts that her mean was 4.7 calls per shift. She knows that the population standard deviation for her shift is 1.5 calls. Test the claim that there is a difference between the mean numbers of calls for the two shifts at the 0.01 level of significance. Let Karen's shifts be Population 1 and let Jodi's shifts be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places. Answer Tables Keypad Keyboard Shortcuts A calendar-year taxpayer must make total estimated tax paymentsof $4,000 for 2021. To avoid an underpayment penalty, what amountshould the taxpayer pay for each installment? A candy distributor wants to determine the average water content of bottles of maple syrup from a particular producer in Nebraska. The bottles contain 12 fluid ounces, and you decide to determine the water content of 40 of these bottles. What can the distributor say about the maximum error of the mean, with probability 0.95, if the highest possible standard deviation it intends to accept is = 2.0 ounces? if alice consumes two times as many calories as claire, and claire consumes 2,500 calories a day. how many calories does alice consume a week? Consider the relation R = {A, B, C, D, E, F, G, H, I, J} and functional dependencies {A,B} {C} {A} {D,E) {B} {F} {F} (G,H) {D} (I,J} What is the key for R? Decompose R into 2NF and then 3NF relations. Use the information provided below to prepare the Cash Flow Statement for the year ended 31 December 2021. (20 Marks) INFORMATION The information given below was obtained from the books of Libra Limited on 31 December 2021, the end of the financial year. STATEMENT OF FINANCIAL POSITION AS AT 31 DECEMBER: 2021 2020 R R ASSETS Non-current assets 988 400 933 200 Property, plant and equipment 988 400 933 200 Current assets 576 200 446 000 Inventory 102 600 109 200 Accounts receivable 397 600 304 800 Bank 75 300 31 100 Cash Float 700 900 1 564 600 1 379 200 EQUITY AND LIABILITIES Equity 755 400 661 400 Ordinary share capital (issue price R1 each) 620 000 548 000 Retained income 135 400 113 400 Non-current liabilities 700 000 396 000 Mortgage bond (18% p.a.) 700 000 396 000 Current liabilities 109 200 321 800 Accounts payable 60 000 236 600 Company tax payable 43 000 37 600 Dividends payable 6 200 47 600 1 564 600 1 379 200 EXTRACT FROM THE STATEMENT OF COMPREHENSIVE INCOME FOR THE YEAR ENDED 31 DECEMBER 2021 R Sales 800 000 Cost of sales 320 000 Interest on Loan 93 600 Depreciation on Vehicles 82 200 Depreciation on Equipment 72 200 Operating profit 253 400 Profit before tax 159 800 Company tax 77 400 Profit after tax 82 400 EXTRACT FROM THE STATEMENT OF CHANGES IN EQUITY FOR THE YEAR ENDED 31 DECEMBER 2021 Ordinary share dividends for the year: R60 400 EXTRACT FROM THE NOTES TO THE FINANCIAL STATEMENTS AS AT 31 DECEMBER: Property, plant and equipment 2021 2020 R R Vehicles (Cost) 490 000 556 000 Accumulated Depreciation on Vehicles 167 200 96 200 Equipment (Cost) 1 060 400 796 000 Accumulated Depreciation on Equipment 394 800 322 600 Note: A vehicle was sold for R54 800 during the year, but no new vehicles were bought. Equipment was purchased for cash but no equipment was sold. ADDITIONAL INFORMATION All purchases of inventories are on credit. Consider an L1 cache that has 8 sets, is direct-mapped (1-way), and supports a block size of 64 bytes. For the following memory access pattern (shown as byte addresses), show which accesses are hits and misses. For each hit, indicate the set that yields the hit. (30 points)0, 48, 84, 32, 96, 360, 560, 48, 84, 600, 84, 48.please explain answers