consider an rlc circuit with resistance 2 ohms, inductance 0.1 henrys, capacitance 0.004 farads, and an impressed voltage, provided by an alternating current generator, of e ( t )

The net force's work is described as d=(3.82)(4.00)=15.3J for W=F net, where we made use of the fact that the canister began at rest and traveled horizontally while being affected by horizontal forces; the resulting effect is represented by the symbol F net.

Since all of these cases are in closed systems, the result is in a new preserved quantity.

Linear momentum and this new quantity, angular momentum, are comparable. In this chapter, we first define angular momentum and then examine it from a number of angles.

But first, we look into a single particle's angular momentum. This enables us to compute the force angular momentum of a rigid cylindrically symmetric body and a system of particles.

We used the fact that the canister started at rest and moved horizontally under the influence of horizontal forces; the ensuing effect is denoted by the symbol F (force) net.

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When two vectors have the same direction, they can be added and the direction of the resultant is the same as the direction of the vectors. Additionally, the magnitude of the resultant is simply the sum of the corresponding magnitudes of the vectors.

Therefore, the answer is:

1) The resultant is the sum of the two displacements having the same direction as the original vectors.

The independent variables of measuring physical properties are given below -

What is physical properties?

A physical properties in any property that is measurable, whose value describe a state of physical system.

The changes in the physical properties of a system can be used to describe its changes between the  momentary that state of

physical properties are often referred to as observables.

They are not modal properties.

Any variable that can be attributed a value without attributes a value to any to any other variables is called independent variables.

It is a variable that stands alone and isn't changed by other variables you are trying to measure.

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The most likely true about the person in front of you is any of the above could be true and is denoted as option D.

This is referred to as the matter or substance which is obtained so as to aid investigation processes and examples include hair, blood etc. It is useful as it helps to solve a crime and ensures that the culprit is punished.

Taking hair samples from pre-emptively could be because of any of the reasons listed such as being a suspect or a witness to a crime thereby making option D as the correct choice.

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The options are:

The refractive index of water is 1.3

Find the refractive index of water.

Lightspeed in water [tex]V_water}[/tex]= 2.25*10^8 m/s

We know that,

Speed of light in vaccum [tex]V_{vaccum}[/tex]=3*10^8 m/s

µ=[tex]\frac{C}{V_{m} }[/tex]

where,

µ= refractive index

C= speed of light in air/vaccum

[tex]V_{m}[/tex]=speed of light in any medium

µ=[tex]\frac{3*10^8 m/s}{2.25*10^8 m/s}[/tex]

µ=1.3

Hence, the refractive index of water is 1.3

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It will take 1.6s for the ice to melt.

First we have to write the expression for the heat balance equation for the system

Q supply = Qgain/

t= mLf/t

Here, m is the ice,

Lf is the latent heat of fusion

and t is the time taken to melt the ice.

Now we have to substitute the required value in the above expression to determine the value of time.

636 kJ/s = (3 kg)(334 kJ/kg) / tt =1.575 s

What is latent heat?
The heat or energy that is absorbed or released during a substance's phase shift is known as latent heat. It could go from a solid to a liquid or from a liquid to a gas, or vice versa. Enthalpy, a characteristic of heat, is connected to latent heat.

Therefore, the closest option is 1.6s

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a)Child's speed halfway down the slide is 9.89m/s.

b)Child's speed three fourth of the way down is 12.12 m/s.

Potential energy that a massive object has in relation to another massive object due to gravity is called gravitational potential energy. Potential energy associated with the gravitational field is converted to kinetic energy when the objects falls towards each other.

As we know that, ΔPE=KE

mgΔh=mv²/2

Now, v=sqrt(2gΔh)

Halfway down the slide,  Δh=5 m

gravity = 9.8 m/s²

v=sqrt(2gΔh)

v= √2* 9.8 * 5

=  √98

= 9.89 m/s

For the three fourth of the way down, Δh=7.5 m.

v= √2* 9.8 * 7.5

= 12.12 m/s

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Answer:

Explanation:

Given:

U =12 V

E = 60 J

________

q - ?

E = U·I·t

q = I·t

E = U·q

q = E / U = 60 / 12 = 5 С

The net work done will be zero on moving the ball to the right.

The net work done is equal to the change in kinetic energy. The initial velocity is - 30 m/s and the final velocity is + 30 m/s. Also, the formula for kinetic energy is: K.E. = 1/2m([tex] { v_{f} }^{2} [/tex]

- [tex] { v_{i} }^{2} [/tex]

Keep the values in formula to find the kinetic energy

K.E. = 1/2×20×(30² - (-30)²)

Taking square on Right Hand Side of the equation

K.E. = 10×(900 - 900)

Performing subtraction on Right Hand Side of the equation

K.E. = 0

Thus, the net work done will be zero. The work done on stopping the particle and then moving it to different direction will be equal. Thus, we get the value zero.

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acceleration a = F/M therefore acceleration the soccer ball from rest in the process is 40 m/s².

Given

mass of soccer ball, M = 0.57 kg

Force F = 22.8 n

acceleration a = F/M

a = 22.8 n/ 0.57 kg

a = 40m/s²

We refer to any process where the velocity changes as acceleration. You can only accelerate by changing your speed, direction, or both as velocity is a function of both speed and direction. When two things are moved against one another, instant friction results. The motion will be opposed by the friction, who will also be working against it. When an item is in motion and its velocity changes, the concept of acceleration takes place. Friction, which opposes motion, always lowers acceleration. An object and a surface come into contact and cause friction. The features of the surface and the item as well as whether or not the object is moving determine its magnitude.

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The variation of the components of the force with the angle of inclination of the direction of the applied force, as shown in the graph indicates that the Fₓ has a maximum, while [tex]F_y[/tex] has a minimum value given by Fₓ = 50 N × cos(0°) = 50 N, and [tex]F_y[/tex] = 50 N × sin(0°) at θ = 0°, while at 45°, Fₓ = [tex]F_y[/tex], with [tex]F_y[/tex] having a maximum value of 50 N, and Fₓ = 0 at 90°.

The component of a force are the mutually perpendicular forces to which a force acting at an angle, relative the coordinate axis can be resolved into.

The component of the force applied by the man to the force required to move the box in the horizontal direction, Fₓ, increases as the angle approaches zero, and decreases as the angle approaches, 90°, given that the horizontal component of the force is found from the equation, [tex]F_x = F \times cos(\theta)[/tex], where, [tex]\theta[/tex] is the angle the line of action of the force makes with the horizontal, and F, is the force the man applies' such that we have at θ = 0°, Fₓ = 50 N × cos(0°) = 50 N

When the angle is θ = 45°, Fₓ = 50 N × cos(45°) = 25·√2 N

When the angle θ = 90°, Fₓ = 50 N × cos(90°) = 0

The vertical component of the force applied [tex]F_y[/tex], however, increases as the angle made by the line of force with the horizontal, increases to 90°, as shown in the graph, and decreases to 0 as the inclination angle of the force decreases, such that the have:

When the angle made with the horizontal, θ = 0°, [tex]F_y[/tex] = 50 N × sin(0°) = 0

When the angle made with the horizontal, θ = 45°, [tex]F_y[/tex] = 50 N × sin(45°) = 25·√2 N

At θ = 90°, [tex]F_y[/tex] = 50 N × sin(90°) = 50 N

The graph of both components starts at 50 N and 0 N when θ = 0°, and both intersect when θ = 45°, while the values of the horizontal and vertical component changes, such that at 90°, the vertical force component is the largest.

Please see the attached graph.

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In the given question, a car coasts into a hill at 16.0 m/s and it slows down with a uniform acceleration of -1.0 m/S/S.

to find,

the displacement after 5.0s,    s=60m

the displacement after 10.0s,   s=80m

according to the equation of motion,

s=ut+1/2at^2

a) t=5second, u=16m/s

s=ut+1/2at^2

s= 16*5 + 1/2 (-1.6) 5^2

s=80-20

s=60m

b)t= 10second , u=16m/s

s=ut+1/2at^2

displacement s=16*10 + 1/2 (-1.6)*10^2

displacement s=80m

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The temperature of the box and floor eventually rise as a result of the thermal energy flowing as heat inside these two things.

This is further explained below.

Generally, The energy present in a system that determines its temperature is referred to as thermal energy.

Thermal energy flows as heat. Thermodynamics is a whole field of physics that studies how heat is transmitted across various systems and how work is performed in the process (see the first law of thermodynamics).

In conclusion, This thermal energy is transferred in the form of heat throughout the box as well as the floor, which eventually results in an increase in temperature for both of these locations.

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Answer:bus

Explanation:

Answer:

2.0m

Explanation:

The tension force applied to the rope when a rock-climber is being pulled up with an increase in speed of 0 to 2.9 m/s in 5.9 s is 30.97 N.

Tension force is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.

To calculate the tension force she applied to the rope, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the tension force applied to the rope is 30.97 N.

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The magnitude of the acceleration of the ball is 10 m/s².

The acceleration of an object is the change in the velocity of the object with time.

The acceleration of the object is calculated using the following kinematic equation as shown below,

h = vt + ¹/₂at²

where;

Substitute the given parameters and solve for the acceleration of the ball.

125 = 0 +  ¹/₂a(5)²

2(125) = 25a

250 = 25a

a = 250/25

a = 10 m/s²

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distance between A and B25002 m

V = 100 km/h

V = (100 x 1000)/3600 = 27.78 m/s when converted to a unit of speed.

t = 15 minutes = 15 x 60 = 900 seconds

displacement =?

Displacement times time equals velocity

Velocity times time equals displacement

displacement = 27.78 x 900

Displacement = 25002 meters

The distance between A and B is 25002 meters since displacement and distance are measured in the same unit.

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The greatest stress that a material can withstand before failing is referred to as its strength. Its stiffness describes how much it will flex or bend when pulled. High strength is frequently found in materials with high stiffness. The greatest stress that a material can withstand before failing is referred to as its strength.

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For the projectile motion of the stone a) The time taken T = 9.04s b) the angle of the projectile = 62.31° c) the Range attained R = 209.923m

A stone propelled from a catapult is an example of projectile motion.

Given, the initial velocity of the stone u = 50 m/s; This initial velocity with which the stone is thrown has two components 1) vertical [tex]u_{y}[/tex] = u sinθ along the Y axis and 2) horizontal [tex]u_{x}[/tex]=u cosθ along the X axis

where θ is the angle of projection

maximum vertical displacement or height attained by stone = H

(Use sign convention +ve for upwards and -ve for downwards)

a) equation for the maximum vertical height reached by a body during projectile motion   [tex]H=\frac{u^{2} sin^{2}\theta }{2g}[/tex]      (1)

equation for the time of flight of projectile motion [tex]T=\frac{2usin\theta}{g}[/tex]           (2)

Given H = displacement in the y direction = height attained = 100m

u =  initial velocity = 50m/s ; acceleration due to gravity g =9.8 m/[tex]s^{2}[/tex]

using equation (1)

[tex]100=\frac{50^{2}sin^{2}\theta }{2*9.8}[/tex]

⇒[tex]sin^{2} \theta= \frac{100*2*9.8}{50^{2} }[/tex]

⇒sinθ[tex]=\sqrt{\frac{10*2*9.8}{50^{2} } }[/tex]

⇒sinθ = 0.885437

⇒θ = [tex]sin^{-1} (0.885437)[/tex]

⇒θ = 62.31°

Hence  from equation (2) time of flight

[tex]T=\frac{2*50*sin\theta}{9.8}[/tex]

⇒[tex]T=\frac{2*50*0.885437}{9.8}[/tex]

⇒T = 9.04 s

Time is taken T =9.04s

b) Angle of projectile θ = 62.31°

c) The range attained [tex]R=\frac{u^{2}sin2\theta }{g}[/tex]

⇒[tex]R = \frac{50^{2}sin(2*62.31)}{9.8}[/tex]

⇒R = [tex]\frac{50^{2}*0.8229}{9.8}[/tex]

⇒R= 209.923m

horizontal range attained R= 209.923m

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Recall, Newton's gravitational law states that any particle of matter in the universe attracts any other particle with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as

F = Gm1m2/r^2

where

F is the force in Newton

G is gravitational constant = 6.673 x 10^-11 Nm^2/kg^2

m1 and m2 are the masses in kg

r is the distance in meters

From the information given,

r = 1.5

acceleration = 2cm^2/s

Recall, 100 cm = 1m

2 cm = 2/100 = 0.02m

Thus,

acceleration = 0.02m/s^2

Since the masses are identical, then m1 = m2

Each of them is accelerating at 0.02m/s^2

Recall,

Force = mass x acceleration

Force = m1 x 0.02 = 0.02m1 N

By substituting the given values into the formula, we have

0.02m1 = (6.673 x 10^-11 x m1 x m1)/1.5^2

m1 on the left cancels out one m1 on the right. It becomes

0.02 = (6.673 x 10^-11 x m1)/1.5^2

By crossmultiplying,

0.02 x 1.5^2 = 6.673 x 10^-11 x m1

0.045 = 6.673 x 10^-11 x m1

m1 = 0.045/6.673 x 10^-11

m1 = 6.74 x 10^8 kg

The mass of each ball is 6.74 x 10^8 kg

Its edges are subjected to a force of 2.8 x 1010 N at the specified shear stress and area.

The force known as shear stress is the tendency for a material to deform by slippage along a plane or planes parallel to the applied stress. Shear stress or pressures, as their name suggests, tend to "shear" objects or produce material deformation.

The formula for shear stress is given as:

F = Aτ

where;

F is the force applied, A is the area of the surface, and τ is the shear stress

We have,

Shear modulus, τ = 3.5 × 10¹⁰ Pa

The area of the plate is A = 0.8 m²

Then,

F = ( 0.8 m² ) × (3.5 × 10¹⁰ Pa)

F = 2.8 x 10¹⁰ N

As a result, as the shear stress grows, so does the force applied to each of its edges that causes the specified displacement.

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The current in the primary winding is 4.4 A.

What is primary winding?

A primary winding is the winding of a transformer  that is connected to and recive energy from an external source of electron.

The primary winding is the coil that draws power from the source.

Sol- As per the given question -

Current Is=0.22A

Primary winding Vp=120v

Voltage of winding Vs=2400v

Current of primary winding Ip?

Np/Ns=Vp/Vs=Is/Ip

Vp/Vs= Is/Ip

120/2400 =0.22/Ip

Ip= 20×0.22

Ip= 2.2×2

Ip=4.4 A

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Answer:

The one that has higher mass

The blackbody radiation energy emitted by star a is 1/16 factor of star b energy.

We need to know about black body radiation to solve this problem. The energy radiated by a black body object is proportional to the area and the fourth power of temperature. It can be determined as

P = A . e . σ . T⁴

where P is power, A is surface area, e is emissivity, σ is Stefan Boltzmann's constant ( 5.67 x 10¯⁸ W/m²K⁴) and T is temperature.

From the question above, we know that

Tb = 2 Ta

By using the black body radiation formula, the ratio of temperature is

Ta⁴ / Tb⁴ = Pa / Pb

Ta⁴ / Tb⁴ = Ea / Eb

Hence,

Ta⁴ / Tb⁴ = Ea / Eb

Ta⁴ / (2Ta)⁴ = Ea / Eb

Ta⁴ / 16Ta⁴ = Ea / Eb

1/16 . Eb = Ea

Thus, the energy of star a will have 1/16 factor of star b energy

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La situación planteada se muestra a continuación:

(El diagrama mostrado es para la caja inferior). A continuación mostramos el diagrama para la caja superior:

Si consideramos el sistema de dos cajas como uno solo tenemos el siguiente sistemas de ecuaciones:

De donde:

Ahora debemos determinar si la caja de arriba no se resbala al aplicar esta fuerza, para esto debemos recordar que la fricción es máxima con el coeficiente de fricción estático.

Entonces tenemos que la fricción es máxima para el bloque de arriba cuando:

Dado que la fuerza que debemos aplicar no es mayor a la fricción máxima concluimos que ambas cajas bajaran al mismo tiempo. Por lo tanto la fuerza que debemos aplicar es de 188.5 N.

..............................

The capacitance of each capacitor is 2.1 ×[tex]10^{-5}[/tex]F.

Let

Equivalent capacitance of the circuit = [tex]C_{eq}[/tex]

   [tex]C_{eq}[/tex] =Q/V

where Q is the charge and V is the potential difference.

Q = [tex]3.5[/tex]×[tex]10^{-4[/tex]

V = 5.55 V

Putting the values

   [tex]C_{eq}[/tex] =    [tex]3.5[/tex]×[tex]10^{-4[/tex]/5.5V

                   [tex]C_{eq}[/tex] = [tex]6.4[/tex]×[tex]10^{-5}[/tex]F

The circuit consists of 3 capacitors in parallel, each one having the same capacitance C.

To find C:

C = [tex]C_{eq}[/tex]/3

C = 2.1 ×[tex]10^{-5}[/tex]F

The capacitance of each capacitor is 2.1 ×[tex]10^{-5}[/tex]F.

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The full Question is :

Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 Ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.

Answer:

You weight would be doubled because gravitational force is doubled

2. Challenges:

a. Everyone’s body would have to adjust to the new weight and learn to walk again

b. Earth would be closer to the sun, so everything would be hotter on Earth

c. Flying airplanes and driving cars might no longer work at all (talk about how difficult this would make traveling)

3. Benefits:

a. Time would go by much slower so technically everyone would live longer

b. Balloons wouldn’t fly off anymore

4. You have to decide for yourself if you’d like it better or worse

Explanation:

Answer:

Amber use 25m for looking

Answer:

25 min's, that's what Amber used

The velocity–time graph of the Lunar Landing Powered Descent that has a domain of 10 ≤ t ≤ 25, and a range of -2 ≤ v ≤ -40, between the 24th and the 25th seconds gives;

C) The Lander's velocity decreases away from the reference

A velocity time graph is a graph that shows the variation of the velocity of an object with time.

The information with regards to the lunar landing powered descent graph are;

Coordinate points on the graph;

(10, -2); At time t = 10 seconds, the average velocity, v = 0

(10.5, -40); The velocity relative to the starting point changed and decreased from 0 m/s to -40 m/s

(15, -5); The velocity increased from -40 m/s to -5 m/s

(22, -3); The velocity increases from -5 m/s to -3 m/s

(24, -2); The velocity increases from -3 m/s to -2 m/s

(25, -15); The velocity decreases from -2 m/s to -15 m/s

Therefore, taking the reference point as the point where the velocity is zero, 0, we have that between approximately 24 seconds and 25 seconds, the Lander's velocity decreases away from the reference.

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