Physics High School

Consider a (pretty big!) balloon left out in the sun to heat up. It expands from V=1m to V=2 m?. Chec Led "If we write the atmospheric pressure as p, then how much work was done by the balloon? Op*(1m) O-p*(1m) o ln(p)*(1m3) Op* (2m) O-p*(2m3) Submit Your submis: DI?: Submitted: Monday, October 18 at 2:55 AM Feedback: Feedback will be available after 10:00 AM on Monday, October 18 Survey Question) 2) Briefly explain your reasoning. Work done (W) = P. Delta P(VI-VI) m^3 P(2-1)m^3 Submit 3) If we double the temperature, what happens to the average velocity of the particles? Increases by a factor of 2 O Increases by a factor of V2 Stays the same Decreases by a factor of 2 Decreases by a factor of 2 Submit (Survey Question) "Briefly explain your reasoning.

Answers

Answer 1

The Partial pressure of o₂ is 380 mm of Hg, atmospheric pressure is 760 mm of Hg.

What is pressure ?

The definition of pressure is the amount of force that is exerted to a certain region. It can be calculated mathematically as P=FA, where F is the force applied perpendicular to surface area A. The pascal (Pa), or one newton per square metre (N/m 2), is the accepted unit of pressure..

What is partial pressure ?

The idea of partial pressure arises from the fact that each individual gas contributes a portion of the total pressure, and that portion is the partial pressure of that gas. In order to describe all the pieces, it is essentially like taking a percentage or fraction of the whole.

Partial pressure of o₂= mole fraction of o₂ × total pressure

Po₂= 1/2 ×760

380 mm of Hg

Mole fraction of o₂ is 1/2 because 50% of particles is that of o₂

Also atmospheric pressure is 760 mm of Hg.

Therefore, the Partial pressure of o₂ is 380 mm of Hg, atmospheric pressure is 760 mm of Hg.

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Related Questions

why was the op-amp unable to source 1 ma current to the 22 kω load?

Answers

The op-amp was unable to source 1 mA current to the 22 kΩ load because of its output current limitations.

The reason is as follows-
1. An op-amp has a maximum output current rating, which is the maximum current it can provide to a load.
2. If the required current (1 mA in this case) exceeds the op-amp's maximum output current rating, it won't be able to source the necessary current.
3. To determine the required current for the 22 kΩ load, you can use Ohm's Law (V = I * R), where V is voltage, I is current, and R is resistance. In this case, we need to find I.
4. Rearrange the formula to solve for I: I = V / R.
5. Assuming the op-amp's output voltage is at its maximum value (let's call it Vmax), we can calculate the required current: I = Vmax / 22 kΩ.
6. If the calculated current (I) is greater than the op-amp's maximum output current rating, the op-amp will be unable to source 1 mA current to the 22 kΩ load.

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The Michelson interferometer can be used to measure extremely small distance scales. What is the smallest distance scale that can be measured? What uncertainty is associated with this? How could the precision be increased?

Answers

The Michelson interferometer can measure distance scales on the order of nanometers, which is extremely small.

However, the smallest distance scale that can be measured with this instrument is ultimately limited by the wavelength of the light being used. Typically, the wavelength of the light used in Michelson interferometers is in the visible range, which means the smallest distance scale that can be measured is on the order of a few hundred nanometers.

The uncertainty associated with this measurement depends on the quality of the instrument and the experimental setup. Factors such as vibration, temperature changes, and other environmental factors can introduce noise into the measurement, which can limit the precision of the instrument. In general, the uncertainty associated with a Michelson interferometer measurement can be on the order of a few nanometers or less.

To increase the precision of a Michelson interferometer, there are several strategies that can be employed. One approach is to use higher quality optics, which can reduce the amount of noise in the measurement. Another approach is to use longer-wavelength light, which can increase the resolution of the measurement. Additionally, the instrument can be operated in a vacuum or isolated from environmental factors to further reduce noise.

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Which of the following is considered a limitation of sensors?
O Ability to read value based on light level
O Measuring sound waves time to travel
O Having to calculate data for proper reading
O Need for work-around for extended power outage

Answers

Answer:

Option D) Need for work-around for extended power outage is considered a limitation of sensors.

Explanation:

True or False, in astronomical usage, all atoms heavier than helium.

Answers

Answer: false

Explanation:

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