Classify the molecules based on whether the molecule has a standard enthalpy of formation, AH;, equal to 0. Assume all
conditions are at standard pressure and temperature (STP).

Answer:

Radiation therapy

Explanation:

I hope this helps

Answer:

The answer has to be A, greater force of attraction than the gas, only

Explanation:

I really hope this helps! Have a good day and good luck!

Answer:

19.3 g/cm3

A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper? 19.3 g/cm3

Answer:

W I think good luck I think

Answer: w

Explanation: potential energy is greater when higher from the ground. i took the test

Answer:

should be earthquake

Explanation:

Phosphorous has 5 valence electrons and so gaining 3 electrons will make it isoelectronic with the stable noble gas argon, and will produce the P3- ion

Billions of time smaller

The sum of the coefficients for all reactants and products is: 12.

Here, we first need to balance the equation of the reaction between Fe2S3(s) and H+.

The sum of the coefficients for all reactants and products is therefore;

Sum = 1 + 6 + 3 + 2.

Sum of coefficients = 12

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Answer:

424 grams of sodium are contained in 4moles of na2co3

125 milliliters of a 6.00 M sulfuric acid solution are required if 0.750 moles of H2SO4 are needed for a reaction.

HOW TO CALCULATE VOLUME:

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Answer:

Technology

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Answer:

if he drops them some where there is no air they will both land at the same time as they have no air resistance and gravity pulls every item equally but if they just do it of a building in the middle of the street then the baseball would hit first as it has a larger mass  

Explanation:

Answer:

hydrogen cloride

Explanation:

Answer:

Approximately [tex]81.84\%[/tex].

Explanation:

Balanced equation for this reaction:

[tex]{\rm Na_{2}CO_{3}}\, (aq) + {\rm CaCl_{2}} \, (aq) \to 2\; {\rm NaCl}\, (aq) + {\rm CaCO_{3}}\, (s)[/tex].

Look up the relative atomic mass of elements in the limiting reactant, [tex]\rm CaCl_{2}[/tex], as well as those in the product of interest, [tex]\rm CaCO_{3}[/tex]:

Calculate the formula mass for both the limiting reactant and the product of interest:

[tex]\begin{aligned}& M({\rm CaCl_{2}}) \\ &= (40.078 + 2 \times 35.45)\; {\rm g \cdot mol^{-1}} \\ &= 110.978\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

[tex]\begin{aligned}& M({\rm CaCO_{3}}) \\ &= (40.078 + 12.011 + 3 \times 15.999)\; {\rm g \cdot mol^{-1}} \\ &= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the quantity of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) available to this reaction:

[tex]\begin{aligned}n({\rm CaCl_{2}) &= \frac{m({\rm {CaCl_{2}})}}{M({\rm CaCl_{2}})} \\ &= \frac{17.87\; \rm g}{110.978\; \rm g \cdot mol^{-1}} \\ &\approx 0.161023\; \rm mol \end{aligned}[/tex].

Refer to the balanced equation for this reaction. The coefficients of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) and the product ([tex]{\rm CaCO_{3}}[/tex]) are both [tex]1[/tex]. Thus:

[tex]\displaystyle \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} = 1[/tex].

In other words, for every [tex]1\; \rm mol[/tex] of [tex]\rm CaCl_{2}[/tex] formula units that are consumed, [tex]1\; \rm mol\![/tex] of [tex]\rm CaCO_{3}[/tex] formula units would (in theory) be produced. Thus, calculate the theoretical yield of [tex]\rm CaCO_{3}\![/tex] in this experiment:

[tex]\begin{aligned} & n(\text{${\rm CaCO_{3}}$, theoretical}) \\ =\; & n({\rm CaCl_{2}}) \cdot \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} \\ \approx \; & 0.161023\; {\rm mol} \times 1 \\ =\; & 0.161023\; \rm mol\end{aligned}[/tex].

Calculate the theoretical yield of this experiment in terms of the mass of [tex]\rm CaCO_{3}[/tex] expected to be produced:

[tex]\begin{aligned} & m(\text{${\rm CaCO_{3}}$, theoretical}) \\ = \; & n(\text{${\rm CaCO_{3}}$, theoretical}) \cdot M(({\rm CaCO_{3}}) \\ \approx \; & 0.161023\; {\rm mol} \times 100.086\; {\rm g \cdot mol^{-1}} \\ \approx \; & 16.1161\; \rm g \end{aligned}[/tex].

Given that the actual yield in this question (in terms of the mass of [tex]\rm CaCO_{3}[/tex]) is [tex]13.19\; \rm g[/tex], calculate the percentage yield of this experiment:

[tex]\begin{aligned} & \text{percentage yield} \\ =\; & \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\% \\ \approx \; & \frac{13.19\; {\rm g}}{16.1161\; {\rm g}} \times 100\% \\ \approx \; & 81.84\%\end{aligned}[/tex].

Answer:

your welcome :)

Explanation:

Answer:

i

b because it says it in the question

Answer:

The rice will move

Explanation:

the sound vibration and waves will cause the rice to move

Answer:

The rice will begin to move.

Explanation:

Answer:

It takes the shape of a container.

Answer:

Someone Said Telophase II. Ill update if its right or wrong when I finish.

Update : He is.... Wong. False.

Explanation:

The answer is Prophase I. It is not Telophase II.

Answer:

eat this

Explanation:

Answer:

yes

Explanation:

it's easy

Answer:

strawberry blueberry raspberry walang compound at element

i hope this calculation will help you  

Answer:

P1V1=P2V2

65 mmHg × 600 mL = 385 mmHg × V2

V2 = 101.30 mL

Explanation:

We can use Boyle's law

Answer:

Together, the number of protons and the number of neutrons determine an element's mass number: mass number = protons + neutrons. If you want to calculate how many neutrons an atom has, you can simply subtract the number of protons, or atomic number, from the mass number.

Explanation:

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Answer:

C(s) + O2(g) --> CO2(g)

Explanation:

Answer:

True

Explanation:

Solid carbon and oxygen gas when mixed together reacts, and forms carbon dioxide gas.

Answer:

850

Explanation:

It's between 840 and 860

Answer:

fafsafwafsxDlmfao

Explanation: