Classify the following triangle as acute, obtuse, or right.

324 divided into 6.846 is 47.33

The statement is given as:

324 divided into 6.846

This is represented as:

324/6.846

Using a calculator, we have:

47.3269062226

Approximate

47.33

Hence, 324 divided into 6.846 is 47.33

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Answer:

proportional reasoning involved thinking about relationship and making comparisons of countries are values in the words of John went Diwali portion reasoning is difficulty find it is not something that you can or not to but is diploma over 3 reasoning

Answer:

$11,000

Step-by-step explanation:

Let amount invested for 12% yield be p . Amount for 4% yield is therefore (18000-p)

Interest for 12%: 12% of p=0.12p

Interest for 4%: 4% of (18000-p)=0.04(18000-p)=720-0.04p

Total interest:

=0.12p + (720-0.04p)

=0.12p-0.04p+720

=0.08p+720

But we already know the total interest is 1280

Therefore: 0.08p+720=1280

0.08p=1280-720

0.08p=560

p=560÷0.08

p=7000

Therefore at 4% the person invested:

(18000-p)

18000-7000

$11,000

1) 8

2) [tex]-\frac{3}{4}=-\frac{6}{8}[/tex], so it is equal to [tex]-\frac{6}{8}+\frac{5}{8}[/tex]

3) 1/8

The frequency which is to filled in the table is 3,1,2,4.

Given  shopping time of ten shopkeeper: 36,20,32,18,20,33,28,34,37,23.

We have to complete the frequency in the table. Frequency of something is the number of times that number is coming.

Shopping time is given as 36,20,32,18,20,33,28,34,37,23.

Intervals for which frequency is given is 18 to 22, 23 to 27, 28 to 32, 33 to 37.

Numbers in the range 18 to 22=18,20,23 therefore 3

Numbers in the range 23 to 27=23 therefore 1

Numbers in the range 28 to 32=32 , 28  therefore 2

Numbers in the range 33 to 37=36, 33, 37, 34 therefore 4.

Hence the frequency which is to filled are 3,1,2,4.

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Answer: B

Step-by-step explanation:

Each time x increases by 1, y is multiplied by 5.

Answer:

1 hour

Step-by-step explanation:

18 miles because if u go 18 miles per hour it takes a hour

Answer:

  $6.70 per hour

Step-by-step explanation:

We want to compare the pay for 1 hour's work.

The equation tells us that her pay for working 1 hour can be found from the equation using x=1.

  y = 22.2x

  y = 22.2×1 = 22.2 . . . . pay for 1 hour

Melanie earns $22.20 per hour.

We assume that Olivia's pay is proportional to hours worked, so pay for 40 hours will be 40 times 1 hour's pay.

  pay per hour = $1156/(40 h) = $28.90/h

Olivia earns $28.90 per hour.

The difference in their rates of pay is ...

  $28.90 -22.20 = $6.70

Melanie earns $6.70 less per hour than Olivia.

Answer:

[tex]g(s)=s^{2} +4s-3[/tex]

Step-by-step explanation:

So for our Question , we have  [tex]g(x)=x^{2} +4x-3[/tex]

and we want to find g(s) , so just substitute by x = s in the Equation of g(x)

[tex]g(s)=s^{2} +4s-3[/tex]

Answer:

B

Step-by-step explanation:

The missing value of the ordered triple for questions 7,8,9 and 10 will be  y=2,x=6,z=0, and z=-5 respectively.

A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.

The given equation in the problem is;

7) (4, ,0)

Substitute the values in the equation;

⇒x+2y-3z = 8,

⇒4+2y-3(0) = 8

⇒2y=8-4

⇒2y=4,

⇒y=4/2

⇒y=2

8) (, -2, -2)

Substitute the values in the equation;

x+2(-2) -3(-2)= 8

x-4+6 =8

x= 8-6+4

x=8-6+4

x=6

9)(2, 3, )

Substitute the values in the equation;

⇒2+2(3)-3z = 8

⇒8-3z = 8

⇒-3z = 0

⇒z = 0/-3

⇒z= 0

10) (-3, -2, )

Substitute the values in the equation;

⇒-3+2(-2) -3z = 8

⇒-7 -3z = 8

⇒-3z = 15

⇒z = 15/-3

⇒z = -5

Hence, the missing value of the ordered triple for questions  7,8,9, and 10 will be  y=2,x=6,z=0, and z=-5 respectively.

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Hello,

Answer:

1

Step-by-step explanation:

(5x)⁰ = 1

Rule : a⁰ = 1

Answer:

1

Step-by-step explanation:

(5x)^0

Any base raised to the zero power is 1

a^0 = 1

5^0 =1

(5x)^0 =1

Answer:

31465

Step-by-step explanation:

n!/((n-r)! r!)

= 31!/(31-4)! 4!

= 31!/ 27! 4!

= 31465

Answer:

Step-by-step explanation:

A= 2AB+(a+b+c)h

AB= s (s﹣a) ( s﹣b) (s﹣c)

s = a+b+c

2

Solving for A

A= ah +bh+ch+1

2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=17·8+14·8+15·8+1

2·﹣174+2·(17·14)2+2·(17·15)2﹣144+2·(14·15)2﹣154≈ 567.35897

Answer:

He needs to score 28 points.

Step-by-step explanation:

[tex]1^{st}\,\,score: 30\,\,points;\\\\2^{nd}\,\,score: 18\,\,points;\\\\3^{rd}\,\,score: 28\,\,points;\\\\4^{th}\,\,score: \,\,?[/tex]

Let's calculate Dante's 4th score, given that the average is 26 points:

[tex]\frac{S1 + S2 + S3 + S4}{4} = 26\\\\\frac{30 + 18 + 28 + S4}{4} = 26\\\\76 + S4 = 104\\\\S4 = 28\,\,points.[/tex]

Answer:

For this one the parallel slope is going to be 2/5

Step-by-step explanation:

The probability of drawing brown candies , orange candies,  yellow candies, red candies, green candies is 0.323 , 0.231 , 0.154 , 0.215 ,0.077

Probability is the study of likeliness of an event to happen.

It is given that a bag of  candies that have

21 brown candies

15 orange candies,

10 yellow candies,

14 red candies,

5 green candies,

probabilities of drawing each candy =?

Total Candies = 21 +15+10+14+5 = 65

Probability = No. of chances / Total outcomes

Probability of drawing Brown candies = P(B) = 21 /65 =  0.323

Probability of drawing Yellow candies = P(Y)= 10/65= 0.154

Probability of drawing Orange candies = P(O) = 15/65=  0.231

Probability of drawing Red candies =P( R) = 14/65= 0.215

Probability of drawing Green candies = P(G) = 5/65= 0.077

Therefore the probability of drawing brown candies , orange candies,  yellow candies, red candies, green candies is 0.323 , 0.231 , 0.154 , 0.215 ,0.077.

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There are two values of k based on the assumption that PQ = QR and the definition of distance and the Pythagorean theorem, k₁ = 7 and k₂ = 1.

Herein we can find the value of the missing coordinate of point by the Pythagorean theorem, which is described below:

PQ = QR     (1)

[tex](Q_{x}-P_{x})^{2} + (Q_{y}-P_{y})^{2} = (R_{x}-Q_{x})^{2} + (R_{y}-Q_{y})^{2}[/tex]

If we know that P(x, y) = (- 2, 1), Q(x, y) = (1, 4) and R(x, y) = (4, k), then the missing value of the point R is:

[1 - (- 2)]² + (4 - 1)² = (4 - 1)² + (k - 4)²

(k - 4)² = 9

k - 4 = ± 3

k = 4 ± 3

There are two values of k based on the assumption that PQ = QR and the definition of distance and the Pythagorean theorem, k₁ = 7 and k₂ = 1.

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Answer:

x<3

Step-by-step explanation:

There isn't a question that I can see for the first image, and I cannot see the yellow part, so I am not 100% sure if this is an accurate answer to the question you were asking.

Step-by-step explanation:

a number used multiplier variable

example 6z menas 6 times z and z is a variable so sixes coefficient variable with no number have a question of one example X is a really 1x

Using translation concepts, the functions that have a maximum and are transformed to the left and down of the parent function are given by:

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

For the translations, we have that:

The functions that respect these conditions are:

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Step-by-step explanation:

hope it helps!!

Answer:

x = 75°

Step-by-step explanation:

∠ p = 40°     [alternate interior angles]

∠ q = 35°    [alternate interior angles]

x = ∠ p + ∠ q

x = 40° + 35°

x = 75°  

Answer: L

Step-by-step explanation:

The two segments that form L meet at a 90 degree angle.

Answer:

  p(t) = 5*2^t

Step-by-step explanation:

We can solve for 'a' and 'b' using the point coordinates shown on the graph.

Substituting for (t, p(t)), the two equations we can make from the given points are ...

  p(t) = a*b^t

  5 = a*b^0 . . . . . . . (t, p(t)) = (0, 5)

  10 = a*b^1 . . . . . . . (t, p(t)) = (1, 10)

The first equation tells you ...

  5 = a

The second equation tells you ...

  10 = 5*b

  2 = b

The function is ...

  p(t) = a*b^t

  p(t) = 5*2^t

the simplified value of the exponential expression is 1/9

Answer:

[tex]\pm i\sqrt{2}\text{ and } \pm i[/tex]

Step-by-step explanation:

[tex]\text{let u = } x^2[/tex] so then [tex]u^2=x^4[/tex].

This gives you the equation: [tex]u^2+3u+2=0[/tex].

Now factor the equation by looking for factors of 2 that add up to 3, which is just 2 and 1. Use these to rewrite the equation: [tex](u+2)(u+1)[/tex]. So now just set each factor equal to 0:

[tex]u+2=0\\u=-2[/tex]

Now substitute x^2 back in as u

[tex]x^2=-2[/tex]

Take the square root of both sides

[tex]x=\pm \sqrt{-2}[/tex]

Separate the radical into sqrt(-1) * sqrt(2)

[tex]x=\pm \sqrt{-1}*\sqrt{2}[/tex]

Rewrite using i

[tex]x=\pm i\sqrt{2}[/tex]

Now set the other factor equal to 0

[tex]u+1=0\\u=-1[/tex]

substitute x^2 back in as u

[tex]x^2=-1[/tex]

Take the square root of both sides

[tex]x=\pm\sqrt{-1}[/tex]

rewrite using i

[tex]x=\pm i[/tex]