City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than three times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. The following system of equations models this scenario:

4x = 8 + 3y
x − 2y = −3

What was the temperature of City A and City B on that day?

City A was 5° C, and City B was 4° C.
City A was 3° C, and City B was −1° C.
City A was 8° C, and City B was −3° C.
City A was 5° C, and City B was −5° C.

Answer:

City A was 5 and city B was 4

Step-by-step explanation:

Use substitution. Move 2y over so you have x=-3+2y

Plug that into 4x=8+3y

4(-3+2y)=8+3y

-12+8y=8+3y

subtract 3y from both sides

add 12 to both sides

5y=20

20 divided by 5

y=4

then youd plug it into the other equation

x-2(4)=-3

x-8=-3

x=5

therefore the answer is A

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3
2
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2
5
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A)
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8)
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