Two different buses start their routes at the same corner at 9 A.M. Buses from one route stop at the library every 9 minutes. Buses from the other route stop at the library every 12 minutes. In what number of minutes will both buses end up at the library?
Answer: In 36 minutes both buses will end up at the library.
Step-by-step explanation:
Given: Buses from one route stop at the library every 9 minutes.
Buses from the other route stop at the library every 12 minutes.
The number of minutes in which both buses will end up at the library= LCM(9,12)
Now , 9= 3 x 3
12= 2 x 2 x 3
LCM(9,12) = 2 x 2 x 3 x 3 = 36
What is the value of x?
А.3
B.2
C.4
D.5
a3 + b3 = (a + b)(a2 - ab + b2)
Use the identity of the sum of two cubes to factor 8q6r3 + 27s6t3.
what is a?
what is b?
Answer:
Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]
a is [tex]2q^2r[/tex]
b is: [tex]3s^2t[/tex]
Step-by-step explanation:
We need to factor [tex]8q^6r^3 + 27s^6t^3[/tex]
[tex]8q^6r^3 + 27s^6t^3\\=(2q^2r)^3+(3s^2t)^3\\Applying \ formula: a^3 + b^3 = (a + b)(a^2 - ab + b^2)\\=(2q^2r+3s^2t)((2q^2r)^2-2(2q^2r)(3s^2t)+(3s^2t)^2)\\=(2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]
So, Factors of [tex]8q^6r^3 + 27s^6t^3[/tex] are [tex](2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)[/tex]
What is a? a is [tex]2q^2r[/tex]
What is b? b is: [tex]3s^2t[/tex]
Answer:
The next answers for the page are 2, 3, 4, 9
Step-by-step explanation:
after giving 20% discount a fan is sold at Rs 12480 find its marked price
Answer:
14976
Step-by-step explanation:
20/100=0.2
12480*0.2=2496
12480+2496=14976
8)
x + 24 - 9x = -8
Solve the equation
Answer:
x=4
Step-by-step explanation:
jus answered this
Answer:
X= +4
Step-by-step explanation:
[tex] - 8x + 24 = - 8 \\ - 8x = - 32 \\ x = \frac{ - 32}{ - 8} = + 4[/tex]
If BCDE is congruent to OPOR , then De is congruent to
One grade of tea costing $3.20 per pound is mixed with another grade costing $2 per pound to
make 20 lbs of a blend that will sell for $2.72 per pound. How much of the $2 tea is needed?
Answer:
12 of $3.2 grade is needed
Step-by-step explanation:
Help please!!!
12x + 6y= 162
2x + 10y= 126
Solve using system of equations. Show all work
Answer:
(8, 11)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesAlgebra I
Solving systems of equations using substitution/eliminationStep-by-step explanation:
Step 1: Define systems
12x + 6y = 162
2x + 10y = 126
Step 2: Simplify systems
2x + y = 27
x + 5y = 63
Step 3: Rewrite systems
2x + y = 27
x = 63 - 5y
Step 4: Solve for y
Substitute in x: 2(63 - 5y) + y = 27Distribute 2: 126 - 10y + y = 27Combine like terms: 126 - 9y = 27Isolate y term: -9y = -99Isolate y: y = 11Step 5: Solve for x
Define equation: x + 5y = 63Substitute in y: x + 5(11) = 63Multiply: x + 55 = 63Isolate x: x = 8Answer:
x = 8 and y = 11
Step-by-step explanation:
solve for y
12x + 6y = 162
-12x -12x
6y = 162 - 12x
/6 /6
y = 27 - 2x
substitute
2x + 10(y) = 126
2x + 10(27 - 2x) = 126
2x + 270 - 20x = 126
-18x + 270 = 126
-270 -270
-18x = -144
-18 -18
x = 8
substitute again:
y = 27 - 2(x)
y = 27 - 2(8)
y = 27 - 16
y = 11
Alpha JKL has vertices J(-3,7), K(2,8), and L(-3, 12). Find the perimeter of AJKL to the nearest tenth.
Answer:
Alpha JKL has vertices J(-3,7), K(2,8), and L(-3, 12). Find ...brainly.com › Mathematics › High School
20 hours ago — Alpha JKL has vertices J(-3,7), K(2,8), and L(-3, 12). Find the perimeter of AJKL to the nearest tenth. - 18900060.
Step-by-step explanation:
plz help me on this its due soon
Answer: -3
Step-by-step explanation: I just know this from my previous questions in math.
i know that someone asked this question already but I'm kinda struggling to get it right tho, but could you guys give me a helping hand?
Answer:
B
Step-by-step explanation:
A: 42/2 = 21
B: 87.5/5 = 17.5
C: 147/7 = 21
only B is not 21
help needed please solve
Answer:
Step-by-step explanation:
a) Perimeter = sum of the length of the sides
= 13.4 +9.8 +12.3 +11.5
= 47 cm
b) Perimeter = 55.3 cm
11.5 + 15.7 +19.8 +x = 55.3
47 + x = 55.3
x = 55.3 - 47
x = 8.3 cm
c) Perimeter of regular hexagon = 67.5 cm
Length of one side = 67.5÷ 6
= 11.25 cm
d) Cost of 1 metre = $ 8.95
Cost of 7.5 metres = 8.95 * 7.5
= $ 67.125
Janet is comparing prices of bottled water. One bottle of water costs $1.92 and contains 12 ounces. Another bottle of water costs $2.40 and contains 16 ounces. Which bottle of water costs less per ounce?
Answer:
The 16 ounce bottle is the cheapest costing only .15 cents per ounces wile the 12 ounce bottle costs .16 cents and ounce.
Step-by-step explanation:
Answer:
The Bottle that cost $2.40
Step-by-step explanation:
You divide the cost by the number of ounces to get the the cost per ounce
You do that to both bottles
The bottle with the less amount of money per ounce is the answer
Bottle that is $1.92 = $0.16 a ounce
Bottle that is $2.40 = $0.15 a ounce
Help asap now now ok thx
Ok, so you got the parent function y = x^2 and it changed to y = x^2 -8
#'s inside the parenthesis would move it left or right and #'s outside the parenthesis would move it up or down. Since there are no parenthesis the x coordinate is 0, hence it doesn't move left or right. Because of this we know that the graph will be moved up or down. Now we look to see is the # negative or positive. If negative, we move it down. If positive, we move it up. Looking at this problem, we see that it will move it down. Next look at the #. This will indicate how much you will move the graph. In this problem, we will move the graph down 8.
Therefore,
When you change the graph y = x^2 to y = x^2 -8, you are moving the graph down 8.
Answer: So if the equation change the graph as y=x^2-8 the graph will move 8 points down.
Step-by-step explanation:
What is the length of side s of the square shown below? A. 2 B. 4√2 C. 1 D. 4. E. 8√2F. √8
Answer:B
Step-by-step explanation:just took it
43,425-125m+200m=45,000-150m
Solve For m
SHOW WORK
Answer:
its 1575/255 or 6.176470588
Step-by-step explanation:
so i think the answer is 16 , but I'm not sure
Answer:
Im pretty sure its 16 but please for the love of god wait for someone else to answer
Hello help me please
Answer:ED=9, DF=9sqrt3, and EF=18
Step-by-step explanation:30-60-90 triangle, a:short, asqrt3:longer, 2a:longest
m∠E=60°
There are 3 green marbles and 15 blue marbles in a bag. What is the ratio of green marbles to total number of marbles?
Select all the equivalent ratios that represent this relationship.
03:15
1:6
02:12
1:5
03:18
2:10
Answer:
the ratio would be 03:18, 1:6, 2:12
Answer: I have the same problem exact same what grade are you in?
Step-by-step explanation:
Joes age is three times Arrons age. If the sum of their ages is 64, how old are Joe and Aaron
Answer:
Joe is 48 Aaron is 16
Step-by-step explanation:
64=3x+x
64=4x
64/4=16
16
16x3=48
can anyone help me with this?
complete the table of values of
f(x) = 3×
Answer:
See sample table below.
Step-by-step explanation:
The function is given as :
f(x) = 3ˣ
A table of values can be formed as ;
x calculations f(x)
-4 3⁻⁴ 0.0123
-3 3⁻³ 0.0370
-2 3⁻² 0.1111
-1 3⁻¹ 0.3333
0 3⁰ 1.000
1 3¹ 3.000
2 3² 9.000
3 3³ 27.00
4 3⁴ 81.00
plz answer...........................................................
Answer:
x ➡️ ×3 ➡️÷ 2 ➡️ - 4 ➡️ × 6 ➡️ 30
6⬅️ ÷3 ⬅️× 2 ⬅️ +4 ⬅️ ÷6 ⬅️ 30
x=6
Answer:
x=3.76 (3.7 recurring rounded to 2 decimal places)
x= [tex]\frac{34}{9}[/tex]
Step-by-step explanation:
You follow the simple steps of finding the value of a variable in an equation by doing PEMDAS/BOMDAS backwards
[tex]6(\frac{3x}{2}-4)=30[/tex]
[tex]6(\frac{3x}{2}-4+4)=30+4[/tex]
[tex]6(\frac{3x/3}{y})=\frac{34}{3}[/tex]
[tex]6(2\frac{x}{2})=2\times11.3 recurring[/tex]
[tex]\frac{6x}{6} = \frac{22.6}{6}[/tex]
[tex]x=3.76\\x=\frac{34}{9}[/tex]
Jeff got a 23/25 on his first math test, a 93% on his second test, and a 0.89 on his third test. Which of the following orders his scores from least to greatest?
Answer:
44554
Step-by-step explanation:
Josh works for a construction company that uses 150 pounds of gravel for each driveway they pour. He can buy a dump truck load with 30,000 pounds of gravel or a pick-up truck load with 2,500 pounds. Which amount should he buy so that no gravel is left after all of the driveways are poured and why?
Answer:
Josh should by the dump truck with 30,000 pounds of gravel in it
Step-by-step explanation:
the easiest way to find this out is divide 30,000 and 2,500 by 150 and if the answer is a whole number, then you know that is the correct answer.
30,000/150 = 200
2,500/150 = 16.6666666666666
May I have brainliest please? :)
is 21.5 x 103 in scientific notation? Explain.
Answer:
Scientific Notation:21.5*10^3
Standard Notation:21,500
Step-by-step explanation:
Jen wrapped a gift that was six inches wide and ten inches tall. The volume of the box was 120 inches. What was the length of the box?
Answer:
2
Step-by-step explanation:
120 divided by 60 = 2. The length of the box is 2 inches. This can be proven through substitution: 120 = 6 x 10 x 2.
Answer my math question I asked so many times I lost most of points by
A number is divided by 4, and the quotient is added to 3. The result is 24
Answer:
Step-by-step explanation:
24 - 3 = 21 • 4 = 84
Help please if you don’t know don’t answer thank you so much
Answer:
Step-by-step explanation:
1). Replace one equation with a multiple of itself.
2x + 7y = 3 ⇔ 4(2x) + 4(7y) = 4(3)
2). Yes, systems are equivalent.
Letang Industrial Systems Company (LISC) is trying to decide between two different conveyor belt systems. System A costs $280,000, has a four-year life, and requires $85,000 in pretax annual operating costs. System B costs $360,000, has a six-year life, and requires $79,000 in pretax annual operating costs. Both systems are to be depreciated straight-line to zero over their lives and will have zero salvage value. Whichever project is chosen, it will not be replaced when it wears out. The tax rate is 23 percent and the discount rate is 10 percent.
We have to calculate the EAC for both the conveyor belt system.
Solutions :
Equivalent Annual Cost or (EAC) for the SYSTEM-A
[tex]$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $[/tex]tax rate )
[tex]$=-855,000(1-0.23)+\left[\left(\frac{280,000}{4}\right)\times 0.23\right]$[/tex]
[tex]$= (-85,000 \times 0.77 ) + (70,000 \times 0.23)$[/tex]
= $ 49,350
Year Annual Cost flow Present value factor Present Value of Annual
at 10% cash flow
1 -49,350 0.909091 -44,863.64
2 -49,350 0.826446 -40,785.12
3 -49,350 0.751315 -37,077.39
4 -49,350 0.683013 -33,706.71
Total $ 3.169865 $ -156,432.86
Therefore, Net Present value = present value of the annual cash flow - initial investment.
= 156,432.86 - 280,000
= $ 436,432.86 (negative)
Now the EAC or the Equivalent Annual Cost for System A :
[tex]$\text{EAC}= \text{Net present value / (PVIFA 10 percent, 4 years)}$[/tex]
[tex]$=\frac{436,432.86}{3.169865}$[/tex]
[tex]$= 137,681.86 $[/tex] dollar (negative)
[tex]$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $[/tex]tax rate)
[tex]$=79,000(1-0.23)+\left[\left(\frac{360,000}{6}\right) \times 0.23\right]$[/tex]
[tex]$=(-78,000 \times 0.77)+(60,000 \times 0.23)$[/tex]
= -$ 47,030
Year Annual Cost flow Present value factor Present Value of Annual
at 10% cash flow
1 -47,030 0.909091 -42,754.55
2 -47,030 0.826446 -38,867.77
3 -47,030 0.751315 -35,334.34
4 -47,030 0.683013 -32,122.12
5 -47,030 0.620921 -29,201.93
6 -47,030 0.564474 -26,547.21
Total $ 4.355261 $ -204,827.91
Net Present Value = Present Value of annual cash inflows – Initial Investment
[tex]$= 204,827.91 - 360,000$[/tex]
= -$ 564,827.91 (negative)
EAC for system B:
Equivalent Annual Cost for system B [tex]$=\frac{\text{net present value}}{\text{PVIFA 10 \text percent, 6 years}}$[/tex]
[tex]$=\frac{-564,827.91}{4.355261}$[/tex]
= -$129,688.66 (negative)