Chose the molecular formula that represents an organic molecule.

H 2O
Cu 2O
NH 2
C 6H 12O 6

Answers

Answer 1

Answer:

(D)C 6H 12O 6

Explanation:

Answer 2

Answer:

[tex]C_{6} H_{12} O_{6}[/tex].

Explanation:

To answer this question you will need to learn about the molecular formula and organic elements.  

So, Molecular Formulas tell you how many atoms of each element are in a compound or the actual whole number ratio; Multiple of Empirical*

Organic Elements - The Organic elements are Protein, Carbohydrates, Lipids, and Nucleic Acids. Lets break down each element. Proteins are made of amino acids. Carbohydrates are made of Carbon, oxygen and hydrogen. Lipids include fats and waxes and Nucleic acids are a long chain of components such as RNA and DNA. Also the other elements are nitrogen, oxygen.

*The Empirical Formula - Tells you the simplest of elements in a                     compound or the simplest whole number; ratio of the elements.

Next, Lets look at some examples of Molecular Formulas v.s The Empirical formula. To solve any problem with these 2, you simply simplify the Molecular formula.

Example 1 -

Empirical: [tex]C_{5} H_{11}[/tex]                 Molecular: [tex]C_{10} H_{22}[/tex]

See how you can do that? Simplify the molecular and it turns into an empirical.

Now lets dig in to the possible answers -

[tex]C_{6} H_{12} O_{6}[/tex] - Glucose. Glucose is a carbohydrate or sugar. It is one type of sugar. It is important to us and all living beings because cells in a organism uses it as energy. Remember, Glucose is a Carb and a Carb is one of The Organic Elements! so we can put this on the list of possible answers

[tex]NH_{2}[/tex] - Amino radical. Amino radical (aka the aminyl radical), is the neutral form of the amide ion. This means in terms of Positive and Negative, Amino radical is the neutral version of amide ion. Amide Ion is not a Organic Molecule, so it is not a possible answer.

[tex]CU_{2} O[/tex] - Copper(I) oxide. (aka cuprous oxide) is a chemical compound. It has copper in its +1 oxidation state and contains oxide ions. Copper(1) oxide is a chemical compound so it is not a possible answer.

[tex]H_{2} O[/tex] - Water. [tex]H_{2} O[/tex] is the symbol for water. Each molecule of water has 2 atoms of hydrogen and a single atom of oxygen. While this may seem a possible answer because water is a natural resource, it isn't a organic molecule.

So, the only possible answer is [tex]C_{6} H_{12} O_{6}[/tex].

Hope this helped you! I took a really, really long time on this question, i had the same one in school. Please mark me brainliest and Have a great day!


Related Questions

An energy bill indicates that the customer used 1024 kWh in July. How many joules did the customer use?

Answers

Answer:

3,686,400,000 Joules

Explanation:

Energy = 1024 kWh

To be converted to Joules.

The relationship between kwh and joules is;

1 kilowatt-hour = 3600000 J

So we have;

1 = 3600000

1024 = x

x = 1024 * 3600000

x = 3,686,400,000 Joules

Arrange the following compounds in order of increasing acidity, and explain the reasons for your choice of order. Enter your answer in the answer box below. a. 4-nitrophenol b. cyclohexanol c. 2,6-difluorocyclohexanol d. 4-bromophenol

Answers

Answer:

(a) > (d) > (c) > (b)

Explanation:

Acidic character is based upon inductive effect of the functional group that are attached to parent chain.

1. Nitro is a -I group which makes phenol acidic due to increased resonance,  2. bromine is a -I group but it is weaker than nitro group

3. phenol is more acidic than cyclohexanol due to resonance stabilization of resonance and among halogen F>Cl>Br>I is the order of acidity

4. cyclohexanol will be weakest as  it is not associated with any -I groups here.

so the order of acidity will be

(a). 4-nitropheno >  (d). 4-bromophenol > (c). 2,6-difluorocyclohexanol  >               (b). cyclohexanol

How many moles of hydrogen are present in 5.30 moles of C5H10O2, propyl acetate, the compound that provides the odor and taste of pears.
Note the type of problem this is - you are being asked to relate moles of an element to 1 mole of a compound (subscripts and moles).
a. 10.6
b. 5.30
c. 6.02 x 1023
d. 53.0

Answers

Answer:

Option D. 53 moles.

Explanation:

The following data were obtained from the question:

Number of mole of C5H10O2 = 5.3 moles

Number of mole of Hydrogen in 5.3 moles of C5H10O2 =?

From the chemical formula of propyl acetate, C5H10O2,

1 mole of C5H10O2 contains 10 moles of H.

Therefore, 5.3 moles of C5H10O2 will contain = 5.3 × 10 = 53 moles of H.

Thus, 5.3 moles of C5H10O2 contains 53 moles of H.

An organic chemist is planning to extract 1.00 g of an organic compound dissolved in 200.0 mL of water into a diethyl ether solvent. The partition coefficient for this system is 9.5, favoring the diethyl ether solvent. What percentage of the organic compound remains in the aqueous solvent if you perform three successive extractions with 50.0 mL of diethyl ether for each extraction?(a) 29.63% (b) 2.60% (c) 0.00169%

Answers

Answer:

(b) 2.60%

Explanation:

Partition coefficient of the organic compound in ether is:

9.5 = Concentration in ether / Concentration in water

In the first extraction, X is the amount of organic compound extracted:

9.5 = X/50mL / (1-X)/200mL

9.5 = 200X / (50-50X)

475 - 475X = 200X

475 = 675X

X = 0.7037g are extracted.

Remains = 1g - 0.7037g = 0.2963g

Second extraction:

9.5 = X/50mL / (0.2963-X)/200mL

9.5 = 200X / (14.815-50X)

140.74 - 475X = 200X

140.74 = 675X

X = 0.2085g are extracted.

Remains = 0.2963g - 0.2085g = 0.0878g

Third extraction:

9.5 = X/50mL / (0.0878g-X)/200mL

9.5 = 200X / (4.3899-50X)

41.70 - 475X = 200X

41.70 = 675X

X = 0.2085g are extracted.

Remains = 0.0878g - 0.0618g = 0.026g remains

Percentage: 0.026g / 1g * 100 =

(b) 2.60%

What mass of 2-naphthol would have to be ingested by each rat in a sample set of rats in order to kill half the population of rats? Assume each rat weighs 230 g. Show your calculations for full credit.

Answers

Answer:

303.6 mg

Explanation:

Given that:

The lethal dose [tex]LD_{50}[/tex] = 1320 mg/kg

The weight of the rat = 230 g

The lethal dose is the dose of a substance likely to cause death. SO a lethal dose of 50 will cause the death of 50% of the sample of test animals.

Therefore;

The mass of 2-naphthol that would have been ingested by each rat in a sample set of rats in order to kill half the population of rats will be equal to:

[tex]=\dfrac{LD_{50}}{1000} \times wt \ of \ rat[/tex]

[tex]=\dfrac{1320}{1000}\times 230[/tex]

= 303.6 mg

no question................................

Answers

Answer:

ok  

Explanation:

An atom of beryllium has 4 protons, 4 electrons, and 5 neutrons. What is its mass number?

Answers

Answer:

40 is correct

Explanation:

Your answer should be 4.

Hope this helped!

-candycchandler

Using the van der Waals equation, calculate the pressure for a 1.25 mol sample of xenon contained in a volume of 1.000L at 75°C; a = 4.194 L2 atm/mol2 and b = 0.05105 L/mol for Xe. Compare these results to that predicted by the ideal gas law.

Answers

Answer:

ABC

Explanation:

hrdjyt

SEP Develop Models Each helium atom has two protons. Sketch models
of helium-3 and helium-4, which have approximate masses of 3 amu
and 4 amu, respectively. Label and differentiate protons, neutrons, and
electrons in your models?

Answers

Protons and neutrons are located in the nucleus of the atom while the electrons move in the trajectory of the shell

Further explanation  

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.  

So Isotopes are elements that have the same Atomic Number (Proton)  

Isotopes of Helium : helium-3 and helium-4

₂³He :

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

₂³He :

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

₂⁴He

protons = 2

electrons=protons=2

neutron=mass number-atomic number=4-2=2

Protons and neutron in the nucleus, electrons in the shell

what are the three states of energy ​

Answers

chemical , mechanical, nuclear , gravitational energy there’s 4 :)

2. What group is Ballardium located? (Bu) *

Answers

Answer:

This question appears incomplete

Explanation:

There is no such element known as "Ballardium (Bu)" in the periodic table. However, there are elements with a bit of similarity in spellings and pronunciation such as Beryllium (Be) which is found in group 2 (meaning it is an alkali earth metal), Berkelium (Bk) which is an actinide (meaning it is radioactive) and Vanadium (V) which is found in group 5 of the periodic table (meaning it's a transition metal).

Which statement best describes evidence that a chemical reaction occurs as a cake bakes

Answers

Answer:  the cake rises as gas bubbles form in the cake

Explanation: Had a quizziz quiz on this

Answer: The cake rises as gas bubbles form in the baking cake.

Explanation: had a test, got it right.

Calculate the heat change in kilocalories for condensation of 6.5 kg of steam at 100 ° C

Answers

Answer:

6,500 gm of steam require= 3,510 kilo calories (approx)

Explanation:

Every 1 gram of water at 100° C  absorb 540 calories

So,

Total water = 6.5 kg = 6,500 gram

So,

6,500 gm of steam require = 6,500 x 540

6,500 gm of steam require= 3,510 kilo calories (approx)

The heat change will be "3,510 kilo calories (approx)".

According to the question,

Total water,

6.5 kg or 6,500 g

Temperature,

100°C

Now,

Required steam will be:

= [tex]6500\times 540[/tex]

= [tex]3510 \ kilo \ calories[/tex]

Thus the above answer is right.

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Which sentence is punctuated correctly? A. I bought all the ingredients for dinner, eggs, tomatoes, macaroni, and cheese and told Molly to preheat the oven. B. I bought all the ingredients for dinner: eggs, tomatoes, macaroni, and cheese—and told Molly to preheat the oven. C. I bought all the ingredients for dinner eggs, tomatoes—macaroni, and cheese and told Molly to preheat the oven. D. I bought all the ingredients for dinner (eggs, tomatoes), macaroni, and cheese and told Molly to preheat the oven.

Answers

B is punctuated correctly

The sentence that has an accurate punctuation is found in (Option B).

What are punctuation marks?

The punctuation marks are those marks that are use to make a piece of writing to have a complete meaning. A piece of writing will be meaningless if there are no attached punctuation marks.

The sentence that is correctly punctuated is;  "I bought all the ingredients for dinner: eggs, tomatoes, macaroni, and cheese—and told Molly to preheat the oven."(Option B)

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1. A 0.130 M solution of a weak base is titrated with a 0.130 M HCl solution. After the addition of 8.50 mL of the HCl solution to 25.00 mL of the weak base solution, the pH of the solution is 9.36 . Determine the pKb of the weak base.2. Calculate the pH of the resulting solution if 23.0 mL of 0.230 M HCl(aq) is added to (a) 33.0 mL of 0.230 M NaOH(aq).

Answers

Answer:

1. 4.93 = pKb of the weak base

2. pH = 12.61

Explanation:

1. When a weak base, B, is being titrated with HCl, the reaction occurs as follows:

B + HCl → BH⁺ + Cl⁻

That means the moles added of HCl are the moles of BH⁺ produced and moles of B are initial moles of B - Moles of HCl

Thus:

Moles B:

Initial moles:

0.0250L * (0.130mol / L) = 3.25x10⁻³ moles B

Moles HCl:

8.5x10⁻³L * (0.130mol / L) = 1.105x10⁻³ moles HCl

3.25x10⁻³ - 1.105x10⁻³ =

2.145x10⁻³ moles B

Moles BH⁺ = Moles HCl:

1.105x10⁻³ moles BH⁺

pH of the buffer made from B/BH⁺ is determined using H-H equation for weak bases:

pOH = pKb + log [BH⁺] / [B]

Where pOH is 14-pH = 14-9.36 = 4.64

pKb is pKb of the weak base, our unknown.

[BH⁺] could be taken as moles of BH⁺ =  1.105x10⁻³ moles

And [B] as moles of B = 2.145x10⁻³ moles B

Replacing:

pOH = pKb + log [BH⁺] / [B]

4.64 = pKb + log [1.105x10⁻³ moles] / [2.145x10⁻³ moles]

4.64 = pKb -0.288

4.93 = pKb of the weak base

2. When HCl and NaOH are in solution the reaction that occurs is:

HCl + NaOH → H₂O + NaCl

To find pH we need to determine, first, which reactant is in excess:

Moles HCl:

0.023L * (0.230mol / L) = 5.29x10⁻³ moles

Moles NaOH:

0.033L * (0.0230mol / L) = 7.59x10⁻³ moles

That means NaOH is in excess and after the reaction will remain:

7.59x10⁻³ moles - 5.29x10⁻³moles = 2.3x10⁻³ moles NaOH = Moles of OH⁻

In 23+33mL = 56mL = 0.056L:

2.3x10⁻³ moles OH⁻ / 0.056L = 0.0411M [OH-]

As pOH = -log [OH-]

pOH = 1.39

pH = 14 - pOH

pH = 12.61

On a statistical basis,smoking a single cigarrette lowers your life expectancy by 642,000--------------------------.Pls answer this question

Answers

Thank you, also what are the options then I can help!

Explain why a buffer can be prepared from a mixture of NH4CL and NaOH but not from NH3 and NaOH .​

Answers

A buffer solution is often referred to as a mixture of an aqueous solution of a weak acid and its conjugate base or weak base and its conjugate acid.

NH4CL is a weak base and NaOH is a strong base and when both it gives you a basic buffer and the result will give you an acid/base needed for the buffer.

NH 3 is a weak base, but NaOH is a strong base and therefore the combination of these solutes would not make a buffer solution because both will give you a base and no acid.

Conclusively we can say that an acid or base needed for making buffer solutions and not base alone

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Please it's due today

Answers

Answer:

The answer is the second one

Give the location in the Periodic Table of Elements that have the same number of valence electrons.

All groups (columns) have the same number of valence electrons
All periods (rows) have the same number of valence electrons
All groups (columns), with the exception of Helium in the Noble Gases, have the same number of valence electrons
There is no trend found on the periodic table

Answers

Answer:

• All groups (columns) have the same number of valence electrons

Explanation:

Every group or column have the same number of valence electrons as a suprise. Every column is aligned in this way.

Answer:

all members within any group

Explanation:

PLS HELP!!!!
How do the products of chemical reactions compare to their reactants?
The products usually have more atoms than the reactants.
The products usually weigh more than the reactants.
The products often have completely different properties than the reactants.
The products are usually more toxic than the reactants.

Answers

How do the products of chemical reactions compare to their reactants?

Answer:

The products often have completely different properties than the reactants.

The correct answer to the question is: The products often have completely different properties than the reactants.

In a chemical reaction, the reactants and products of the reaction have different properties because during the reaction, bonds were broken and new bonds were formed which generate a new substance called the product.

However, chemical equations must be balanced in order to conform to the law of conservation of matter which states that matter can neither be created nor destroyed  during a chemical reaction but can be transferred from one form to the other.    

For example, the reaction of Hydrogen gas (H₂) and oxygen gas (O₂) to produce water (H₂O)

2H₂(g) + O₂(g) —> 2H₂O(l)

From the equation, we can see that the reactants are gases but the product is a liquid which has a different properties from the gaseous reactants.

Therefore, the correct answer to the question is:  The products often have completely different properties than the reactants.

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The initial concentration of NOCl in the second-order reaction 2NOClâ2NO+Cl2 is 0.878M. After 763,200 seconds, the concentration of NOCl is 0.83M. What is the rate constant k for the reaction? Report your answer in scientific notation rounded to two significant figures. Use the multiplication symbol when reporting your answer rather than the letter x. Provide your answer below: $$ 1/M s

Answers

Answer:

[tex]k=8.63x10^{-8}\frac{1}{M*s}[/tex]

Explanation:

Hello!

In this case, since the differential rate law of a second-order reaction is:

[tex]\frac{dC_A}{dt}=-kC_A^2[/tex]

Whereas A stands for NOCl and the corresponding integrated rate law is:

[tex]\frac{1}{C_A} =kt+\frac{1}{C_A_0}[/tex]

Thus, since we know the concentrations and the elapsed time, we compute the rate constant as shown below:

[tex]k=( \frac{1}{C_A}-\frac{1}{C_A_0} )/t\\\\k=( \frac{1}{0.83M}-\frac{1}{0.878M} )/763,200s\\\\k=8.63x10^{-8}\frac{1}{M*s}[/tex]

Best regards!

The boiling point of propanoic acid is higher than that of 1-butanol because:

Answers

Explanation:

The boiling point of propanoic acid is higher than that of 1-butanol due to the prevalence of hydrogen bonding in propanoic acid.

Hydrogen bond forms as a result of the electrostatic attraction between the hydrogen of one molecule and a more electronegative specie on another molecule(N or O or F). In propanoic acid, the hydrogen bonding is more pronounced and strong. For 1-butanol, the bonding is weak and not strong.

Nitrogen dioxide (NO2) gas and liquid water (H2O) react to form aqueous nitric acid(HNO3) and nitrogen monoxide gas. Suppose you have 2.0 mol of NO2 and 7.0 mol of H20 in a reactor. Calculate the largest amount of NHO3 that could be produced. Round your answer to the nearest 0.1 mol.

Answers

Answer:

1.3 moles of HNO₃ will be produced

Explanation:

Equation for the reaction:

3NO₂ + H₂O ----> 2HNO₃ + NO

From the equation of the reaction, 3 moles of NO₂ reacts with 1 mole of H₂O to produce 2 moles of HNO₃

Suppose there are 2 moles of NO₂  and 7.0 moles of H₂O in a reactor, the limiting reactant will be NO₂ and H₂O will be in excess since 3 moles of NO₂ reacts with every 1 mole of H₂O.

Since 3 moles of NO₂ reacts to produce  2 moles of HNO₃;

2 moles of NO₂ will react to produce 2/3 * 2 moles HNO₃ = 1.3 moles of HNO₃

Therefore, 1.3 moles of HNO₃ will be produced

The largest amount of HNO₃ produced from the reaction between 2 mole of NO₂ and 7.0 mole of H₂O in a reactor is 1.3 mole

We'll begin by determining the limiting reactant. This can be obtained as follow:

3NO₂ + H₂O —> 2HNO₃ + NO

From the balanced equation above,

3 moles of NO₂ reacted with 1 mole of H₂O.

Therefore,

2 moles of NO₂ will react with = [tex]\frac{2}{3}\\\\[/tex] = 0.67 mole of H₂O.

From the calculation made above, we can see that only 0.67 mole of H₂O out of 7 moles given, reacted completely with 2 moles of NO₂. Thus, NO₂ is the limiting reactant and H₂O is the excess reactant.

Finally, we shall determine the largest amount of HNO₃ produced from the reaction. This can be obtained by using the limiting reactant as illustrated below:

From the balanced equation above,

3 moles of NO₂ reacted to produce 2 moles of HNO₃.

Therefore,

2 moles of NO₂ will react to produce = [tex]\frac{2 *2 }{3} \\\\[/tex] = 1.3 mole of HNO₃.

Thus, the largest amount of HNO₃ produced from the reaction is 1.3 mole

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A ball has a kinetic energy of 4.50 kJ. If the ball has a mass of 120.0 g, how fast is the ball traveling, in meters per second?

Answers

Answer:

273.9m/s

Explanation:

Given parameter:

Kinetic energy of the ball  = 4.5kJ

Mass of the ball  = 120g

Unknown:

Speed of the ball  = ?

Solution:

Kinetic energy of a body is the energy due to the motion of a body.

 K.E  = [tex]\frac{1}{2}[/tex] m v²

where m is the mass

           v is the speed

Convert the quantities to the appropriate units;

     4.5kJ to J  = 4.5 x 10³J

 120g to kg  = 0.12kg

Now insert the parameters and find the unknown:

       4500  = [tex]\frac{1}{2}[/tex] x 0.12 x V²  

      9000 = 0.12V²  

       V²  = [tex]\frac{9000}{0.12}[/tex]   = 75000

        V  = 273.9m/s

The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.

Answers

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

can someone put this in other words Conduct an investigation to explore the use of Punnett squares to predict genotypes and phenotypes of offspring.

Answers

To explore the use of punnett square to predict genotype and phenotypes of offsprings an investigation must be conducted

Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water

Answers

Molarity after dilution : 0.0058 M

Further explanation

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

[tex]\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M[/tex]

A microwave operates at 7.42 mm wavelength. How much energy is produced in Joules from 359 photons?



answer numerically using scientific notation with e and significant figures.

Answers

Answer:

[tex]E=9.62\times 10^{-21}\ J[/tex]

Explanation:

Given that,

The wavelength of a microwave is 7.42 mm or 0.00742 m

No. of photons, n = 359

We need to find the energy produced by this no of photons. It can be given by the formula as follows :

[tex]E=\dfrac{nhc}{\lambda}\\\\E=\dfrac{359\times 6.63\times 10^{-34}\times 3\times 10^8}{0.00742}\\\\=9.62\times 10^{-21}\ J[/tex]

or

[tex]E=9.62e^{-21}\ J[/tex]

So, the required energy is [tex]9.62\times 10^{-21}\ J[/tex].

Answer:

⬆️That guy deserves brainliest

Explanation:

Which classes of isomers are easier to separate from each other in the laboratory: enantiomers or diastereomers?

Answers

Answer:

diastereomers

Explanation:

Enantiomers are optical isomers that are mirror images of each other. Enantiomers can not be separated by physical methods because the both compounds have almost the same physical properties such as melting points, boiling points, etc. This makes it difficult to separate enanatiomers by conventional methods.

A common method of separating enantiomers is by converting them into diasteromers which are easily separated since diasteromers often have different chemical and physical properties.

1Water molecules can be ligands especially when they are bonded to
..........
A. alkaline earth metals
B. alkali metals
C. transition metals
D. group VII elements​

Answers

Answer:c

Explanation:

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