CH3CH2OH+3O2 2CO2+3H20 ( ethanol) explain this equation! if u didn't understand the wat I have written could u text in personal will sent u photo of questions​

The number of mole of ethanol present in the sample is 0.005 mole

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mole of ethanol

Mole = mass / molar mass

Mole of ethanol = 0.2301 / 46

Mole of ethanol = 0.005 mole

Complete question

A sample of ethanol (C2H6O) has a mass of 0.2301 g. Complete combustion of this sample causes the temperature of a bomb calorimeter to increase by 1.33°C. The calorimeter has a mass of 2.000 kg and a specific heat of 2.45 J/g•°C. How many moles of ethanol are present in the sample?

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Explanation:

sulphur has a low melting point.

sulphur has a low boiling point thus it can be extracted by pumping hot water which turns it ito solution form

Answer:

Option B

Explanation:

Therefore our answer must be Option B

Answer:

37

Explanation:

( 98.6 - 32 ) × 5(100c) ÷ 9(180f) = 37

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

The reactant that is entirely used up in a reaction is called a limiting reagent.

A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.

A product is a substance that is present at the end of a chemical reaction.

Hence,

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

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In a Base catalyst elimination, the base extracts a proton and the leaving group leaves simultaneously. In a Concentrated process, the leaving group leaves  the base abstracts a proton.

Just as there are two mechanisms of substitution (SN2 and S N1), there are two

mechanisms of elimination (E2 and E1).

E2 mechanism — bimolecular elimination

E1 mechanism — unimolecular elimination

The E2 and E1 mechanisms differ in the timing of bond cleavage and bond formation, analogous to the SN2 and S N1 mechanisms.

E2 and S N2 reactions have some features in common, as do E1 and SN1 reactions.

Base removes a proton from the β-carbon atom,

while the halogen atom leaves from the α-carbon resulting in the formation of a π-bond. Such eliminations are also called β-eliminatione liminations are also called β elimination reactions

In a base-catalyzed elimination reaction, the base takes away a proton from the β position of the leaving group (the group that goes away with the bonding pair of electrons) and a double bond is formed. When the base is bulky it prefers to take away the proton from the less hindered position.

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19.7 litre volume of carbon dioxide gas at 22.0o C and 102 kPa can be collected over water.

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

Moles of Butane = mass in grams / molar mass = 11.6 / 58.12 = 0.2

Volume of [tex]O_2[/tex] (V) = 40 liter

Temperature (T) = 22°C = 22 + 273 = 295 K

Pressure (P) = 102 kPa = 102 / 101.325 = 1.007 atm

Moles of [tex]O_2[/tex] (n) can be calculated by ideal gas equation.

PV = nRT

n = 1.007 40 ÷ 0.0821 295 = 1.663

Balanced chemical reaction;

2[tex]C_4H_10[/tex] + 13[tex]O_2[/tex] ---> 8[tex]CO_2[/tex] + 10[tex]H_2O[/tex]

From reaction;

13 moles [tex]O_2[/tex] require 2 moles [tex]C_4H_10[/tex]

So, 1.663 moles [tex]O_2[/tex] will require = 2 x 1.663 ÷13 = 0.256 moles of [tex]C_4H_10[/tex]

Thus [tex]C_4H_10[/tex] is a limiting reagent. So it will drive the yield of [tex]CO_2[/tex].

Moles of [tex]CO_2[/tex] produced = (8/2) 0.2 = 0.8 moles

Pressure of [tex]CO_2[/tex] (P) = 102 - 2.24 = 99.76 kPa = 99.76  ÷ 101.325 = 0.985 atm

Applying the ideal gas equation for [tex]CO_2[/tex],

PV = nRT

0.985 V = 0.8 0.0821 x 295

V = 19.7 liter

The volume of [tex]CO_2[/tex] produced = 19.7 liter.

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Answer:

C. None of these

2 volumes of zinc sulphide produces two volumes of Sulphur dioxide. So, 9.7g of ZnS will produce nothing less than 9.7g of SO2.

Answer: 2.11 g

Explanation:

[tex]$$Equation: $2 \mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Cu}(s) \longrightarrow \mathrm{Cu}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q)+2 \mathrm{Ag}(s)$[/tex]

[tex]$$No of moles of $\mathrm{Ag}$ produced from $\mathrm{Cu}=2.500 \mathrm{~g} \times \frac{1 \mathrm{~mol} \mathrm{Cu}}{63.55 \mathrm{~g}} \times \frac{2 \mathrm{~mol} \mathrm{Ag}}{1 \mathrm{~mol} \mathrm{Cu}}$ $=0.07868 \mathrm{~mol} \mathrm{Ag}$[/tex]

[tex]$$No of moles of $\mathrm{Ag}$ produced from $\mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}=200.0 \mathrm{~mL} \times \frac{1 \mathrm{~L}}{1000 \mathrm{~mL}} \times \frac{0.150 \mathrm{~mol} \mathrm{AgC_{2 } \mathrm { H } _ { 3 } \mathrm { O } _ { 2 }}}{1 \mathrm{~L}}$ $=0.0300 \mathrm{~mol} \mathrm{Ag}$[/tex]

[tex]Since $\mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}$ limits the production of $\mathrm{Ag}, \mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}$ acts as the limiting reactant \\\\No of moles of Ag formed $=0.0300 \mathrm{~mol}$\\Theoretical yield of $\mathrm{Ag}=0.0300 \mathrm{~mol} \mathrm{Ag} \times \frac{108 \mathrm{~g}}{1 \mathrm{~mol} \mathrm{Ag}}=3.24 \mathrm{~g}$\\Actual yield of silver $=65.0 \%(3.24 \mathrm{~g})$$$=\frac{65.0}{100}(3.24 \mathrm{~g})=2.106 \mathrm{~g} \approx 2.11 \mathrm{~g}$$[/tex]

A key element to a successful response to a chemical, biological, or radiological incident is the rapid identification of the hazard and immediate control over all responding units.

Rapid techniques commonly used for species identification consist of species-precise primer pairs and probes, randomly amplified polymorphic DNA (RAPD), amplified fragment period polymorphisms (AFLP), restriction fragment length polymorphisms (RFLP), and karyotyping.

Elements favoring fast identity kits are reduced time in getting ready, inoculating, incubating, and cleaning up; also a convenience, decreased area for trying out and garage, ease of operation, and saving of cloth and cash are many motives for the food industry to use rapid identification structures for ordinary.

A urine lifestyle test can discover micro organism or yeast causing urinary tract contamination (UTI). If microorganisms multiply, an antibiotic sensitivity take look at can discover the antibiotic most in all likelihood to kill those specific bacteria. Your healthcare issuer may additionally order a urine tradition if you get persistent or difficult-to-deal with UTIs.

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Answer:

6 (STI, SIT, TIS, ITS, IST

The balanced equation for the neutralization reactions is as below.

In order for chemical equations to be balanced, the number of atoms of each element before and after the reaction must be equal.

Thus:

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Molar mass

No of moles

Volume

Concentrations of alpha-fetoprotein (AFP):

Increased concentrations of alpha-fetoprotein (AFP) in adults are most characteristically associated with Hepatocellular carcinoma.

Alpha Fetoprotein (AFP):

It is a protein produced in a developing baby's liver. When a newborn is born, their AFP levels are typically high, but by the time they turn one, they are quite low. AFP levels in healthy persons should be extremely low. For adults, a typical AFP level ranges from 10 ng/mL to 20 ng/mL.

In reaction to cancer in the body, normal or cancerous cells produce chemicals known as tumor markers. High levels of AFP can indicate noncancerous liver illnesses such as cirrhosis and hepatitis as well as cancers of the testicles, ovaries, or liver.

Thus, one of the risk factors for Hepatocellular carcinoma has been proven to be a persistent increase in AFP serum levels.

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The total mass of the protons is 1.338 * 10^-23 g

A proton is the positively charged particle in an atom. It is found in the nucleus along with the neutrons and are collectively called the nucleons.

The hydrogen atom has only one proton while the nitrogen atom has seven protons. Thus makes a total of eight protons in the ammonia molecule.

Hence, the total mass of protons in the ammonia molecule =

8 ( 1.673 × 10^-24 g) = 1.338 * 10^-23 g

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The final concentration is 0.332 M.

Here, dilution formula is used,

The concentration of a solution is lowered by the process of dilution. This is commonly accomplished by increasing the solvent content of the solution, which lowers the moles per liter.

                                                    M₁V₁ = M₂V₂

where,

M₁ = Initial concentration

V₁ = Initial volume

M₂ = Final concentration

V₂ = Final volume

Given,

M₁ = 0.600 M

V₁ = 15.00 mL

V₂ = 27.13

To calculate,

M₂ =?

Put the given values in the above formula,

M₁V₁ = M₂V₂

0.600 × 15.00 = M₂ × 27.13

9 = M₂ × 27.13

M₂ = 9/27.13

M₂ = 0.332 M

Therefore the final concentration is 0.332 M.

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Answer: It has more neutrons. Its mass number is larger than the atomic mass number for carbon.

Explanation:

We can see that all the isotopes of Carbon occupies the same slot in the periodic table and thus the same periodic number.

Atomic number of carbon = 6

Periodic Table gives us the information of Atomic number and mass number of atoms of an element.

Atomic number does not give any information about the number of neutrons of an atom. Atomic number of an element is the number of protons in the nucleus of each atom of that element.

Mass number is defined as the total number of protons and neutrons in an atom. Mass number of a typical carbon atom is equal to 12.

Isotopes are variants of a particular chemical element which differ in number of neutrons. Hence, the mass number of different isotopes of the same element varies and gives us information about the number of neutrons present in that atom at the same time.

The mass number of Carbon-14 is equal to 14.

Atomic number of C-14 = Protons in Carbon-14 = 6

Neutrons in Carbon-14 = Mass Number - Atomic Number

Neutrons in C-14 = 14-6

= 8

Explanation:

show the volume of container is equal to 198.82ml

The volume of the piece of iron to the nearest cubic centimeter is 4473.6 cubic centimeter.

density = mass / volume

volume = mass/ density

            =35342/ 7.9

            =4473.6 cubic centimeter

The density of a substance indicates how dense it is in a given area. Mass per unit volume is the definition of a material's density. In essence, density is a measurement of how closely stuff is packed. It is a particular physical characteristic of a specific thing. The Greek scientist Archimedes made the discovery of the density principle. If you are familiar with the formula and the relevant units, calculating density is simple. The letter D can also be used to signify density instead of the symbol.

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Taking into account the Charles' law, the temperature of the gas if the volume drops to 75.0 L is 246 K or -27 C.

Charles' law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, the volume is directly proportional to the temperature of the gas.

Mathematically, Charles' law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

[tex]\frac{V}{T}=k[/tex]

Considering an initial state 1 and a final state 2, it is fulfilled:

[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]

In this case, you know:

Replacing in Charles's law:

[tex]\frac{100 L}{328 K}=\frac{75 L}{T2}[/tex]

Solving:

[tex]T2x\frac{100 L}{328 K}=75 L[/tex]

[tex]T2=\frac{75 L}{\frac{100 L}{328 K}}[/tex]

T2= 246 K= -27 C

Finally, the temperature of the gas if the volume drops to 75.0 L is 246 K or -27 C.

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Answer:

this problem was eventually overcome by arranging elements by increasing atomic number instead of atomic weight.

This problem was eventually overcome by arranging elements by increasing atomic number instead of atomic weight.

The total weight of an atom is called the atomic weight. It is approximately equal to the number of protons and neutrons, with a little extra added by the electrons.

Mendeleev arranged the elements in order of increasing weight and broke them into rows such that elements in each column shared valence, the number of other atoms they combined with, as well as other properties.

In his 1869 Periodic Table, Mendeleev left blanks with suggested atomic weights for elements he thought would be discovered someday. William Ramsay's discovery of argon initially posed a threat to the Periodic Table. At first, Mendeleev believed argon was not an element, because it didn't react with anything.

Hence, this problem was eventually overcome by arranging elements by increasing atomic number instead of atomic weight.

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The properties of water benefits our planet.

Yes, the properties of water benefits our planet because it can dissolve huge number of solutes due to its polarity while on the other hand, its normal viscosity allows water to flow easily around the globe.

No, in my opinion the planet may face no problems because of these unique properties because these properties are important for us.

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Answer:

the role of the microscope world in creating new material.

Explanation:

Trust me ;)

Answer: C. 1.40×10^24

Explanation:

To do this, we must convert this from grams to moles, then from moles to molecules. For the first step, you will need to find the molar mass of HCl on the periodic table, which is 36.461gHCl.

[tex]85.0gHCl*\frac{1molHCl}{36.461gHCl} =2.33molHCl[/tex]

Now that we have the moles, we must convert that to molecules by using Avogadro's number.

[tex]2.33molHCl*\frac{6.022*10^{24} }{1molHCl} =1.40*10^{24}[/tex]

Now we have our answer. The best answer choice here is C. 1.40×10²⁴.

I hope this helps! Pls mark brainliest!! :)

The rate constant is mathematically given as

K2=2.67sec^{-1}

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

[tex]ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})[/tex]

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

[tex]ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492[/tex]

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

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The Faradays transferred during the process is 86400 C.

An electric current in a circuit is calculated by dividing the total charge that runs in the circuit with the total time taken.

I = Q/t

Rearrange the formula to express it in terms of charge.

Q = I x t

Calculations:

Convert 12 h to s.

12 h = (12 x 60 x 60) s = 43200 s

Substitute the values in the above formula.

Q = 2.0 C/s x 43200 s

= 86400 C

Therefore, the charge (Faradays) transferred in an electrolytic cell is 86400 C.

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The concentration ratio for an oligopoly is Over 60 percent.

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The ratio between the energy and oxygen based on the equation is 683.5 KJ/mol

From the equation, we obtained the following:

Thus, the ratio of energy to oxygen is given as:

Energy / Oxygen = 1367 / 2

Energy / Oxygen = 683.5 KJ/mol

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Answer:

graduated cylinder

Explanation:

that is the most accurate one of the 3. The lines on a beaker or flask are just indicative.