Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, there are limitations. Canadians visiting in the United States for more than 2 days are allowed to bring into Canada one bottle of liquor and one carton of cigarettes. A Canada Customs agent has produced the following joint probability distribution of the number of bottles of liquor and the number of cartons of cigarettes imported by Canadians who have visited the United States for 2 or more days.

a. Find the marginal probability distribution of the number of bottles imported.

P(0 Bottles) =
P(1 Bottle) =

b. Find the marginal probability distribution of the number of cigarette cartons imported.

P(0 Cartons) =
P(1 Carton) =

c. Compute the mean and variance of the number of bottles of liquor imported.

Mean =
Variance =

d. Compute the mean and variance of the number of cigarette cartons imported.

Mean =
Variance =

e. Compute the covariance and the coefficient of correlation.

Covariance =
Coefficient of Correlation =

Answers

Answer 1

Answer:

(a): Marginal pmf of x

[tex]P(0) = 0.72[/tex]

[tex]P(1) = 0.28[/tex]

(b): Marginal pmf of y

[tex]P(0) = 0.81[/tex]

[tex]P(1) = 0.19[/tex]

(c): Mean and Variance of x

[tex]E(x) = 0.28[/tex]

[tex]Var(x) = 0.2016[/tex]

(d): Mean and Variance of y

[tex]E(y) = 0.19[/tex]

[tex]Var(y) = 0.1539[/tex]

(e): The covariance and the coefficient of correlation

[tex]Cov(x,y) = 0.0468[/tex]

[tex]r \approx 0.2657[/tex]

Step-by-step explanation:

Given

x = bottles

y = carton

See attachment for complete question

Solving (a): Marginal pmf of x

This is calculated as:

[tex]P(x) = \sum\limits^{}_y\ P(x,y)[/tex]

So:

[tex]P(0) = P(0,0) + P(0,1)[/tex]

[tex]P(0) = 0.63 + 0.09[/tex]

[tex]P(0) = 0.72[/tex]

[tex]P(1) = P(1,0) + P(1,1)[/tex]

[tex]P(1) = 0.18 + 0.10[/tex]

[tex]P(1) = 0.28[/tex]

Solving (b): Marginal pmf of y

This is calculated as:

[tex]P(y) = \sum\limits^{}_x\ P(x,y)[/tex]

So:

[tex]P(0) = P(0,0) + P(1,0)[/tex]

[tex]P(0) = 0.63 + 0.18[/tex]

[tex]P(0) = 0.81[/tex]

[tex]P(1) = P(0,1) + P(1,1)[/tex]

[tex]P(1) = 0.09 + 0.10[/tex]

[tex]P(1) = 0.19[/tex]

Solving (c): Mean and Variance of x

Mean is calculated as:

[tex]E(x) = \sum( x * P(x))[/tex]

So, we have:

[tex]E(x) = 0 * P(0) + 1 * P(1)[/tex]

[tex]E(x) = 0 * 0.72 + 1 * 0.28[/tex]

[tex]E(x) = 0 + 0.28[/tex]

[tex]E(x) = 0.28[/tex]

Variance is calculated as:

[tex]Var(x) = E(x^2) - (E(x))^2[/tex]

Calculate [tex]E(x^2)[/tex]

[tex]E(x^2) = \sum( x^2 * P(x))[/tex]

[tex]E(x^2) = 0^2 * 0.72 + 1^2 * 0.28[/tex]

[tex]E(x^2) = 0 + 0.28[/tex]

[tex]E(x^2) = 0.28[/tex]

So:

[tex]Var(x) = E(x^2) - (E(x))^2[/tex]

[tex]Var(x) = 0.28 - 0.28^2[/tex]

[tex]Var(x) = 0.28 - 0.0784[/tex]

[tex]Var(x) = 0.2016[/tex]

Solving (d): Mean and Variance of y

Mean is calculated as:

[tex]E(y) = \sum(y * P(y))[/tex]

So, we have:

[tex]E(y) = 0 * P(0) + 1 * P(1)[/tex]

[tex]E(y) = 0 * 0.81 + 1 * 0.19[/tex]

[tex]E(y) = 0+0.19[/tex]

[tex]E(y) = 0.19[/tex]

Variance is calculated as:

[tex]Var(y) = E(y^2) - (E(y))^2[/tex]

Calculate [tex]E(y^2)[/tex]

[tex]E(y^2) = \sum(y^2 * P(y))[/tex]

[tex]E(y^2) = 0^2 * 0.81 + 1^2 * 0.19[/tex]

[tex]E(y^2) = 0 + 0.19[/tex]

[tex]E(y^2) = 0.19[/tex]

So:

[tex]Var(y) = E(y^2) - (E(y))^2[/tex]

[tex]Var(y) = 0.19 - 0.19^2[/tex]

[tex]Var(y) = 0.19 - 0.0361[/tex]

[tex]Var(y) = 0.1539[/tex]

Solving (e): The covariance and the coefficient of correlation

Covariance is calculated as:

[tex]COV(x,y) = E(xy) - E(x) * E(y)[/tex]

Calculate E(xy)

[tex]E(xy) = \sum (xy * P(xy))[/tex]

This gives:

[tex]E(xy) = x_0y_0 * P(0,0) + x_1y_0 * P(1,0) +x_0y_1 * P(0,1) + x_1y_1 * P(1,1)[/tex]

[tex]E(xy) = 0*0 * 0.63 + 1*0 * 0.18 +0*1 * 0.09 + 1*1 * 0.1[/tex]

[tex]E(xy) = 0+0+0 + 0.1[/tex]

[tex]E(xy) = 0.1[/tex]

So:

[tex]COV(x,y) = E(xy) - E(x) * E(y)[/tex]

[tex]Cov(x,y) = 0.1 - 0.28 * 0.19[/tex]

[tex]Cov(x,y) = 0.1 - 0.0532[/tex]

[tex]Cov(x,y) = 0.0468[/tex]

The coefficient of correlation is then calculated as:

[tex]r = \frac{Cov(x,y)}{\sqrt{Var(x) * Var(y)}}[/tex]

[tex]r = \frac{0.0468}{\sqrt{0.2016 * 0.1539}}[/tex]

[tex]r = \frac{0.0468}{\sqrt{0.03102624}}[/tex]

[tex]r = \frac{0.0468}{0.17614266944}[/tex]

[tex]r = 0.26569371378[/tex]

[tex]r \approx 0.2657[/tex] --- approximated

Canadians Who Visit The United States Often Buy Liquor And Cigarettes, Which Are Much Cheaper In The

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Answers

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Answer:

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Step-by-step explanation:

[tex] \frac{88}{400} = \frac{11}{50 } [/tex]

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A study of the effects of exercise used rats bred to have high or low capacity for exercise. The 8 high-capacity rats had mean blood pressure 89 mm Hg and variance 81 (mm Hg)'; the 8 low-capacity rats had mean blood pressure 105 mm Hg with variance 169 (mm Hg). What is the value of the two-sample t statistic for comparing the two population means

Answers

Answer:

T statistic = 0.256

Step-by-step explanation:

Given :

High capacity rats:

nh = 8

Xh = 89

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(Xh - Xl) ÷ Sp(sqrt(1/nh + 1/nl))

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[(nh - 1)s²h + (nl - 1)s²l] ÷ (nh + nl - 2)

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Answers

Answer:

2.30 :) hope this helps!!!!!!! :)

Step-by-step explanation:

w = wheat     c = corn    r = rye

6w + 3c + 6r = 45.90

3w + 6c + 6r = 49.20

6w + 6c + 3r = 41.40

since you want the answer for c, manipulate then add 2 equations that will get rid of 1 variable:

if we multiply the first equation by -1 then add it to the second equation, it will eliminate the r

-6w -  3c -  6r = - 45.90

3w + 6c + 6r =   49.20

------------------------------------

- 3w +3c  =      3.30    or     w - c = - 1.10

If we multiply the 3rd equation by -2 then add it to the first equation, it will eliminate the  r  again:

-12w - 12c -  6r = - 82.80

  6w + 3c + 6r =    45.90

------------------------------------------

- 6w - 9c         =  - 36.90   or       2w + 3c  =   12.30

now we have 2 equations and 2 variables that we can solve by substitution:

w = c - 1.10

2(c - 1.10)  + 3c = 12.30

2c - 2.20 + 3c   =   12.30

5c = 14.50

c = 2.90      

w = c - 1.10   or  1.80

3r = 41.40 - 6(1.80) - 6(2.90)

3r = 13.20    r = 4.40

I will pick the 2nd equation to check my answers :)!

3(1.80) +  6(2.90)  + 6(4.40)  = 49.20

5.40 + 17.40 + 26.40 =  49.20

As per linear equation, the price per bushel for corn is $22.8.

What is a linear equation?

A linear equation is an equation that has one or multiple variable with the highest power of the variable is 1.

Given, a grain dealer sold to one customer 5 bushels of wheat, 2 of corn, and 3 of rye, for $228.

To another customer, he sold 2 of wheat, 3 of corn, and 5 of rye, for $228.

To a third customer, 3 of wheat, 5 of corn, and 2 of rye, for $228.

Let, per piece of wheat is of $x.

Per piece of corn is of $y.

Per piece of rye is of $z.

Therefore, 5x + 2y + 3z = 228 ....(1)

2x + 3y + 5z = 228 .........................(2)

3x + 5y +2z = 228 ..........................(3)

Multiplying equation(1) by '2' and equation(2) by '5' and substract, we get:

2(5x + 2y + 3z) - 5(2x + 3y + 5z) = 2(228) - 5(228)

⇒ (10x + 4y + 6z) - (10x + 15y + 25z) = - 3(228)

⇒ (- 11y - 19z) = - 684

⇒ 11y + 19z = 684 ......(4)

Multiplying equation(2) by '3' and equation(3) by '2' and substract, we get:

3(2x + 3y + 5z) - 2(3x + 5y +2z) = 3(228) - 2(228)

⇒ (6x + 9y + 15z) - (6x + 10y + 4z) = 228

⇒ - y + 11z = 228 .......(5)

Now, multiplying equation(5) by '11' and then add with equation (4), we get:

 11y + 19z + 11(- y + 11z) = 684 + 11(228)

⇒ 140z = 3192

⇒ z = 22.8

Putting the value of 'z' in equation (5) we get:

- y + 11(22.8) = 228

⇒ y = 22.8

Now, putting the values of 'y' and 'z' in equation (1), we get:

5x + 2(22.8) + 3(22.8) = 228

⇒ 5x = 114

⇒ x = 22.8

Learn more about linear equation here: https://brainly.com/question/22990272

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Write an expression for the area of each section of the wall.
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Answers

Answer:

50

Step-by-step explanation:

10*5=50

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Answers

Answer:

The cube root and square root are not given, but I'm going to give a chart that might help.

Square roots:

2 = √4

3 = √9

4 = √16

5 = √25

9 = √81

10 = √100

Cube roots:

2 = ^3√8

3 = ^3√27

4 = ^3√64

5 = ^3√125

9 = ^3√729

10 = ^3√1000

What’s the correct answer for this question?

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Answer is 7
Step by step explanation
|-7|=7
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