CAN YOU GUYS PLEASE ANSWER THIS QUICKLY THIS IS DUE IN AN HOUR AND IM GETTING WORRIED​

Answer:

0.3106 seconds

Explanation:

Frequency= 20,000-Hz

The speed of echoes sounds can be calculated using the expression below;

Y= ( 2x/t) ...........................eqn(1)

t= overall time taken

x = maximum depth = 230m

Y= speed of echoes sounds

Speed of sound in water= 1,481 m/s which is a constant with little variation.

If we substitute the given values into eqn(1) we have

1481 = (2× 230)/ t

1481 × t= 460

t=460/1481

t=0.3106 seconds

Hence, the minimum time between pulses (in fresh water) is 0.3106 seconds

The factors that affect the viscosity of magma include temperature, crystal and rock fragments (composition), and the different dissolved gases.

It is a mixture of solid, volatile and liquid materials.

Therefore, we can conclude that the fluidity or viscosity of magma depends on its chemical composition and, in particular, the liquids and solids that the magma contains and the various gases dissolved in it.

Learn more about viscosity of magma here: https://brainly.com/question/20621986

Answer:

48 rev

Explanation:

a) we can calculate the distance covered by the tube using the formula:

θ = (ω + ωo)t/2

where ω is the final angular speed, θ is the distance covered, t is the time taken, ωo is the initial angular speed.

Firstly, we calculate the distance covered from 0 to 9 s then from 9s to 24 s.

within 9s, the tub runs from rest (0) to 4 rev/s, hence:

t = 9s, wo = 0, w = 4 rev/s = (4 * 2π) rad/s = 8π rad/s. Hence:

θ = (ω + ωo)t/2 = (0 + 8π)9 / 2 = 36π rad

θ = 36π rad = (36π)/2π rev = 18 rev

Also, within 15 s, the tub runs from 4 rev/s to rest, hence:

t = 15 s, wo = 4 rev/s = 8π rad/s, w = 0 rad/s. Hence:

θ = (ω + ωo)t/2 = (8π + 0)15 / 2 = 60π rad

θ = 60π rad = (60π)/2π rev = 30 rev

Therefore the total revolutions by the tube during 24 s interval = 30 rev + 18 rev = 48 rev

An arrow pointing from the bottom of the ramp to the top, I assume it would be friction.

Answer:

last one. c

Explanation:

atomic number; number of neutrons = mass number - atomic number​ is the very important to find the number of the question.

Answer:

3.75m on the left end

Explanation:

Given data

Tim's  weight = 500N= 0.5kN

Tim's fathers weight= 500*2= 1000N= 1kN

Tim and the fathers weight = 500+1000= 1500N= 1.5kN

Tim's uncle weight= 1.5kN

Length of seesaw= 5m

let the distance  Tim's uncle sits be x

We know that summation of clockwise moment equals the summation of anticlockwise moment

Taking moment about the center of the seesaw

1.5*2.5= 1*x

3.75= 1x

Divide boths sides by 1

x= 3.75/1

x= 3.75m

Hence Tim's uncle will sit 3.75m on the left end

Answer:

Angular acceleration of the disk ∝ = K

Explanation:

Given that;

Angular velocity function given by ω = Kt + L

Angular acceleration of the disk at t=T is = ?

Now,

Angular velocity;

ω = Kt + L

Angular acceleration is;

∝ = dω / dt

= [tex]\frac{d}{dt}[/tex] ( Kt + L )

At t = T

∝ = K

Because  ∝  is not dependent on t

Therefore

Angular acceleration of the disk ∝ = K

Answer:

The gravitational field strength (acceleration due to gravity) on the moon is 1.63 m/s²

Explanation:

From the question, the moon has a gravitational field strength (acceleration due to gravity) that is about 1/6 that of  Earth's.

To determine the gravitational field strength (acceleration due to gravity) on the moon, we will multiply the Earth's gravitational field strength (acceleration due to gravity) by 1/6.

Earth's gravitational field strength = 9.8 m/s²

∴ Moon's gravitational field strength = 1/6 × 9.8 m/s²

Moon's gravitational field strength  = 1.63 m/s²

Hence, the gravitational field strength (acceleration due to gravity) on the moon is 1.63 m/s².

Answer:

Below

Explanation: 1.Katie likes to read and would rather do that than play sports. Her friends make fun of her and tell her that reading is for nerds. Katie stops reading so much and starts to play sports more.

2. Marcus wants to go to a small community college close to home, but most of the kids in his class are applying to larger colleges out of state. Marcus decides that he should also apply to those colleges.

Answer:

the distance traveled by Charlotte in feet is 338.44 ft

Explanation:

Given;

speed of Charlotte, u = 66.5 mi/h

time of motion, t = 3.47 s

The distance traveled by Charlotte in feet is calculated as;

[tex]Distance = Speed \ \times \ time \\\\D = ut\\\\D = (\frac{66.5 \ mi}{h} \times \frac{5280 \ ft}{1 \ mi} \times \frac{1 \ h}{3600 \ s} )(3.47 \ s)\\\\D = 338.44 \ ft[/tex]

Therefore, the distance traveled by Charlotte in feet is 338.44 ft

Answer:

See explanation below

Explanation:

The question is incomplete. The missing part of this question is the following:

"While the block is in contact with the spring and being brought to rest, what are (a)the work done by the spring force and (b) the increase in thermal energy of the blockfloor system? (c) What is the blocks speed just as it reaches the spring?"

According to this we need to calculate three values: Work, Thermal Energy and Speed of the block when it reaches the spring.

Let's do this by parts.

a) Work done by the spring:

In this case, we need to apply the following expression:

W = -1/2 kx²  (1)

We know that k = 430 N/m, and x is the distance of compressed spring which is 5.8 cm (or 0.058 m). Replacing that into the expression:

W = -1/2 * 430 * (0.058)²

b) Increase in thermal energy

In this case we need to use the following expression:

ΔEt = Fk * x   (2)

And Fk is the force of the kinetic energy which is:

Fk = μk * N   (3)

Where μk is the coeffient of kinetic friction

N is the normal force which is the same as the weight, so:

N = mg (4)

Let's calculate first the Normal force (4), then Fk (3) and finally the chance in the thermal energy (2):

N = 4.8 * 9.8 = 47.04 N

Fk = 0.28 * 47.04 = 13.1712 N

Finally the Thermal energy:

ΔEt = 13.1712 * 0.058

c) Block's speed reaching the spring

As the block is just reaching the speed, the initial Work is 0. And the following expression will help us to get the speed:

V = √2Ki/m   (5)

And Ki, which is the initial kinetic energy can be calculated with:

Ki = ΔU + ΔEt   (6)

And ΔU is the same value of work calculated in part (a) but instead of being negative, it will be positive here. So replacing the data first in (6) and then in (5), we can calculate the speed:

Ki = 0.7233 + 0.7639 = 1.4872 J

Finally the speed:

V = √(2 * 1.4872) / 4.8

Hope this helps

Answer:

[tex]A_c=87.73*10^{21}m/s[/tex]

Explanation:

From the question we are told that

[tex]r=5\times 10^{-11}[/tex]

[tex]T=1.5 \times 10^{-16}[/tex]

Generally the equation for velocity is mathematically given as

[tex]Velocity (v)=\frac{2 \pi r}{t}[/tex]

[tex]V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}[/tex]

[tex]V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}[/tex]

Generally the equation for Centripetal acceleration is mathematically given as

[tex]A_c=\frac{V^2}{r}[/tex]

[tex]A_c=(\frac{20.944*10^5)}{r5*10^{-11}}[/tex]

[tex]A_c=87.73*10^{21}m/s[/tex]

Explanation:

Work done is the force applied to move a body through a specific or particular direction.

It is also the difference in the amount of energy expended in using an effort.

 Work done is given as;

 Work done  = F x d CosФ

F is the force applied

d is the displacement

Ф is the angle

 The unit of work done is in Joules.

Answer:

1 m/s

Explanation:

5m/s change in velocity, divided by 5 seconds= 1 meter/second/second

change in velocity/change in time

Acceleration = (change in velocity) / (time for the change)

that's = (change in speed and its direction) / (time for the change)

Change in velocity = (ending velocity) - (starting velocity)

Change in velocity = (20 m/s west) - (15 m/s west)

Change in velocity = 5 m/s west

Acceleration = (5 m/s west) / (5 seconds)

Acceleration = 1 m/s west

Answer:

a) - 72.5°c

b) pressure = 3625.13 Pa

c) density =  0.063 kg/m^3

d) it is a subsonic aircraft

Explanation:

a) Determine Temperature

Temperature at 19.5 km ( 19500 m )

T = -131 + ( 0.003 * altitude in meters )

  =  -131 + ( 0.003 * 19500 ) = - 72.5°c

b) Determine pressure and density at 19.5 km altitude

Given :

Po (atmospheric pressure at sea level )  = 101kpa

R ( gas constant of air ) = 0.287 KJ/Kgk

T = -72.5°c ≈ 200.5 k

pressure = 3625.13 Pa

hence density = 0.063 kg/m^3

attached below is the remaining part of the solution

C) determine if the aircraft is subsonic or super sonic

Velocity ( v ) = [tex]\sqrt{CRT}[/tex]  =  [tex]\sqrt{1.4*287*200.5 }[/tex] = 283.8 m/s

hence it is a subsonic aircraft

Answer:

A) they both have the same algebraic sign

B)6.377×10^-6 C

Explanation:

From columb's law, the force acting on both charges can be expressed as

F=( kq1*q2)/r^2

Where F= electrostatic force

r= distance between the charges

q1 and q2= charges

The force acting on a spring can be expressed as

F= kx..................eqn(2)

Where

K= spring constant = 180 N/m.

x= stretch of the string= 0.021m

Substitute the values into eqn (2)

F= (180×0.021)

F= 3.78N

If we compare with spring force,

Hence, F( electrostatic) = 3.78N

From

F=( kq1*q2)/r^2 ..............eqn(1)

Where

r= (0.29 m + 0.021m)= 0.311m

K= the electrostatic constant= 8.99×10^9 kg⋅m3⋅s−2⋅C−2.

If we substitute the values we have

Since the charges are the same, then

kq1 and q2 equals "q"

3.78= (8.99×10^9 ×q^2)/(0.311)^2

Making q^2 subject of the formula

3.78× (0.311)^2 = 8.99×10^9 × q^2

q^2= [(0.311)^2 × 3.78]/8.99×10^9

q^2= 40.668×10^-12

q=√40.668×10^-12

q= 6.377×10^-6 C

(a) the possible algebraic signs

They have the same algebraic sign

(b) the magnitude of the charges.

6.377×10^-6 C

Answer:

Explanation:

Sandy hears 8 such clicks every 3 seconds and a small twig, caught in the spokes, causes the tire to click once each revolution that means the wheel of the cycle is rotating at 8 rotations every 3 seconds or 8/3 rotation per second . In each rotation , it moves distance equal to its circumference .

circumference = 2π r = 2 x 3.14 x .65 / 2 m

= 2.041 m

In 8/3 rotation , distance covered = 8/3 x 2.041 = 5.44 m

So speed of cycle is 5.44 m per second

5.44 x 60 x 60 m per hour

19584 m per hour

= 19.584 km per hour .

= 20 km per hour approx.

Answer:

63.8 kJ

Explanation:

The net work output per cycle is the difference in heat input and heat output. The heat input and heat output are expressed as a function of volume ratios, while volume is expressed as a function of pressure and pressure as a function of temperature.

R = 287 J/kg.K, k = 1.4

Hence the net work input (W) is given as:

[tex]W=Q_{in}-Q_{out}\\\\W=mR[T_Hln\frac{V_2}{V_1} -T_Lln\frac{V_3}{V_4}]\\\\=mR[T_Hln\frac{P_1}{P_2} -T_Lln\frac{P_4}{P_3}]\\\\=mR[T_Hln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1}) -T_Lln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1})]\\\\=mR(T_H-T_L)ln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1})\\\\Substituting\ values:\\\\W=mR(T_H-T_L)ln(\frac{P_1}{P_3}(\frac{T_L}{T_H} )^\frac{k}{k-1})=0.6*287(1100-300)ln(\frac{3000*10^3}{2-*10^3}(\frac{300}{1100} )^\frac{1.4}{1.4-1})\\\\[/tex]

[tex]W=63.8\ kJ[/tex]

Answer:

4 m/s

Explanation:

From the question given above, the following data were obtained:

Mass of 1st cart (m₁) = 20 kg

Initial velocity of 1st cart (u₁) = +6 m/s

Mass of 2nd cart (m₂) = 30 kg

Finally velocity of both cart (v) = 0 m/s

Initial velocity of 2nd cart (u₂) =?

The initial velocity of the 2nd cart can be obtained as follow:

m₁u₁ – m₂u₂ = v(m₁ + m₂)

(20 × 6) – (30 × u₂) = 0 (20 + 30)

120 – 30u₂ = 0(50)

120 – 30u₂ = 0

Collect like terms

– 30u₂ = 0 – 120

– 30u₂ = – 120

Divide both side by –30

u₂ = –120 / –30

u₂ = 4 m/s

Thus, the 2nd (i.e the 30 kg) cart was initially moving with a velocity of 4 m/s.

Answer:

Potential energy: Greatest at the top of the hill

Kinetic energy: Greatest at the bottom of the hill

The two meet at some point on the way down!

Explanation:

Potential energy is energy that represents an object's potential for motion. Kinetic energy is that object's energy during motion. They're two sides of the same coin, and in fact, their sum gets a special name: mechanical energy. Potential energy builds up in reaction to working against certain forces - in the case of the roller coaster, that primary force is gravity. Gravity exerts a downward force on the roller coaster, and it takes work to pull it up the hill.

When it reaches the peak, the coasters potential energy is at its highest, and the moment it crests over the hill and begins its descent, that gravitational potential energy starts converting into kinetic energy: the coaster starts accelarating down the track, and the potential energy decreases at the same rate that the kinetic energy increases.

At the bottom of the hill, all of that potential energy has become kinetic energy, and the coaster zooms along the track, hopefully not giving too many riders nausea

Answer:

A

Explanation:

ive been buying loui i been shoppin

Answer: E) radon cannot be tested because it is odorless, colorless, and tasteless

Explanation:

edge2021

Answer:

d the net external force acting on the two-body system is zero

Explanation:

The net external force acting on the two-body system is zero .

During a collision , two internal forces appear on two bodies in opposite directions separately . As they act on each object separately , they do not cancel each other . But the net force on two body system is zero . Total momentum is always conserved during collision because no external force is involved . Collision is not always elastic .

Answer:

235.8 N

Explanation:

Given that

Jack

83.5 east

Jill

93.3√2/2 east

93.3√2/2 north

Jane

121√2/2 east

121√2/2 south

From the above listed, we can calculate the total force component on x axis to be

Fx = 83.5 + 93.3√2/2 + 121√2/2

Fx = 83.5 + 65.97 + 85.56

Fx = 235 N (east)

Again, we calculate the total force component on y axis to be

Fy = 93.3√2/2 - 121√2/2

Fy = 65.97 - 85.56

Fy = -19.59 N (south)

Finding the resultant, we have

F = √(Fx²+Fy²)

F = √(235² + (-19.59)²)

F = √55225 + 383.7681

F = √55608.7681

F = 235.8 N

Answer: a rubber band

Explanation: A rubber band has no conductivity and no electricity would be able to flow whereas steel and copper and aluminum would be able to allow electricity to flow due to how they are built

Answer:

2.59m/s

Explanation:

Using the equation of motion

v = u+at

v is the final velocity = 35ms

u is the initially velocity = 9m/s

t is the time = 13.5s

a is the acceleration

Substitute into the formula

35 = 0+13.5a

a = 35/13.5

a = 2.59m/s²

Hence the acceleration of the motorcycle is 2.59m/s

Answer:

b. Designing an uncontrolled experiment.

Explanation:

They always have it controlled.

Answer:

B. Designing an uncontrolled experiment.

Explanation:

Correct Answer!!!!!!