Can you answer it right now pls

Answer:

m = - 6 :)

Step-by-step explanation:

Answer:

each friend ate 1/4 of pizza

Step-by-step explanation:

3/4 ÷ 3

= 1/4

The population at time n=9 is approximately 11.95. The term "population" refers to the entire set of individuals, objects, or events that are of interest to a researcher or analyst.

Based on the given information, we have:

Initial population (P0) = 10

Growth rate (r) = 0.2

To find an explicit formula for Pn, we can use the formula for exponential growth:

Pn = P0 * (1 + r)^n

Substituting the given values:

Pn = 10 * (1 + 0.2)^n

Simplifying the formula, we have:

Pn = 10 * 1.2^n

Using this formula, we can find P9:

P9 = 10 * 1.2^9 ≈ 11.95

Therefore, the population at time n=9 is approximately 11.95.

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Answer:

C.

Step-by-step explanation:

Since the slope is 1 meaning it goes up and over by 1 the GPA would increase by 1 every hour

Answer:

c

Step-by-step explanation:

Answer:

A,C and D

Step-by-step explanation:

A: 3x2=6

    3x4X=12X

     6+12X

C: 5x1=5

    5x2X=10X

    5+10X+1+2X

   6+12X

D: 7x1=7

    7x2X=14X

     7+14X-2X-1

     6+14X-2X

     6+12X

The probability of event E is 0.20, the probability of event F is 0.45, and the probability of both E and F occurring is 0.10. Therefore, the probability of either event E or event F occurring, denoted as P(E or F), is 0.65.

Given that P(E) = 0.20 and P(F) = 0.45, we also know that P(E and F) = 0.10. Using the formula P(E or F) = P(E) + P(F) - P(E and F), we can substitute the values and calculate the probability of either event E or event F occurring.

P(E or F) = P(E) + P(F) - P(E and F)

P(E or F) = 0.20 + 0.45 - 0.10

P(E or F) = 0.65

Therefore, the probability of either event E or event F occurring, denoted as P(E or F), is 0.65.

The concept behind this formula is that when we add the individual probabilities of E and F, we count their intersection (P(E and F)) twice. Since we want to avoid double-counting the intersection, we subtract P(E and F) from the sum of P(E) and P(F). This gives us the probability of either event E or event F occurring.

In this case, the probability of either event E or event F occurring is 0.65, indicating a relatively high likelihood of one of the events happening.

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There is a significance at the level 0.01.

We can use a two-sample t-test for this purpose.

A two-sample t-test is used to examine whether two data samples have a mean difference that is statistically significant.The null hypothesis for this test is that there is no significant difference between the mean systolic blood pressure of those adolescents classified as having low sleep efficiency and that of other adolescents.

Hence, H0: μ1 = μ2

where μ1 is the mean systolic blood pressure of those adolescents classified as having low sleep efficiency and μ2 is the mean systolic blood pressure of other adolescents.

The alternative hypothesis is that there is a significant difference between the two means:

H1: μ1 ≠ μ2

The level of significance (α) is 0.01, so the critical value of t can be found using a t-distribution table with 254 degrees of freedom (n1+n2-2=254).

The critical value at a 0.01 level of significance is ±2.576.

From the question, we know that the mean difference between the two groups is 5.6 mm Hg and the standard deviation of this difference is 1.8 mm Hg.

Therefore, the t-statistic can be calculated as:

t = (5.6 - 0) / (1.8 / sqrt(256))

= 56 / 1.8 = 31.11

Since the calculated t-statistic (31.11) is greater than the critical value (±2.576), we reject the null hypothesis.

Thus, we can conclude that there is a significant difference in systolic blood pressure between the two groups at the 0.01 level of significance.

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Answer:

95 < 75 + 0.80m 20 < m Company A will charge less than Company B for mileages less than 20.

Answer:

131.92ft²

Step-by-step explanation:

okay, so we have to find the area of both circles, and the circumference then multiply that with the height, it's confusing, so:

3² x 3.14 = 28.26 x 2 = 56.52 so that the area of the bases

3 x 2 x 3.14 = 18.85 x 4 = 75.4

75.4 + 56.52 = 131.92

So the surface area of the cylinder is 131.92ft²

Answer:

the answer is B on USA Prep

Step-by-step explanation:

"A potential outlier at (50, 12)" is the statement that best describes the data shown in the scatter plot.

A straight line that minimizes the gap between it and certain data is called a line of best fit. In a scatter plot containing several data points, a relationship is expressed using the line of best fit. It is a result of regression analysis and a tool for forecasting indicators and price changes.

Given:

The scatter plot shows the relationship between backpack weight and student weight.

From the given choices:

An outlier is a value that nowhere near the range of the data set.

From the scatter plot:

A potential outlier at (50, 12).

Therefore, a potential outlier at (50, 12).

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Answer : 1/2 gallon

Explanation:

There were a total of 5 gallons collected, as the question states.

There are 3 x's above 1/4, 2 x's above 3/8, 4 x's above 5/8 and 1 x above 1. This is a total of

3+2+4+1 = 10 x's. This means there were 10 trees.

If 5 gallons is evenly distributed among 10 trees, this would give us the ratio 5/10, which simplifies to 1/2 gallon per tree.

....this answer is not from me. The same question was asked on brainy and I've copy pated it, it is the right answer tho. Credit goes to "MsEHolt" for answering.

Answer:

1. 4 less than x

2. v = 15.00n

Answer:

4 minus x and v = 15.00n

Step-by-step explanation:

Answer:

umm, i think the question is incomplete

Step-by-step explanation:

The probability of event B given event A P(B|A) is approximately 0.2857

P(B|A), the probability of event B given event A, we use the formula:

P(B|A) = P(A and B) / P(A)

P(B|A) denotes conditional probability the probability of event B depends on another event A.

Given the following probabilities:

Probability of event A P(A) = 0.35

Probability of event B P(B) = 0.55

Probability of event  A  and B (A and B) = 0.10

We can calculate P(B|A) as follows:

P(B|A) = P(A and B) / P(A)

P(B|A) = 0.10 / 0.35

P(B|A) ≈ 0.2857

Therefore, P(B|A) is approximately 0.2857.

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The equation for the line of reflection is x = 6

An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.

For example, 3x + 5 = 15.

Given that, a graph, we need to find the equation of the reflection of the polygon graphed,

We can see, all the vertices on the polygon are being mirrored across the line x = 6.

So, we can say the line of reflection is x = 6.

Hence, the equation for the line of reflection is x = 6

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Given Info : What is the difference of the value of Lily's expression , 6x-3, when x=5 and the value of Pedro's expression when x=5 .

To Find :- Show or explain how you got your answer.

Solution:-

The expression is 6x-3 , and we need to find its value at x = 5 , On putting x =5 we have

6*5-3 = 30-3 = 27.

This value will come same in case of Pedro, therefore our required answer is 5

Step-by-step explanation:

2 would be the answer .

hope it helps u .

2 cubed = 8

equasion; 2 Cubed = [tex]2^{3}[/tex] = 2 × 2 x 2 = 8

i hope this helps <3

9514 1404 393

Answer:

  a) ∆RLG ~ ∆NCP; SF: 3/2 (smaller to larger)

  b) no; different angles

Step-by-step explanation:

a) The triangles will be similar if their angles are congruent. The scale factor will be the ratio of any side to its corresponding side.

The third angle in ∆RLG is 180° -79° -67° = 34°. So, the two angles 34° and 67° in ∆RLG match the corresponding angles in ∆NCP. The triangles are similar by the AA postulate.

Working clockwise around each figure, the sequence of angles from lower left is 34°, 79°, 67°. So, we can write the similarity statement by naming the vertices in the same order: ∆RLG ~ ∆NCP.

The scale factor relating the second triangle to the first is ...

  NC/RL = 45/30 = 3/2

__

b) In order for the angles of one triangle to be congruent to the angles of the other triangle, at least one member of a list of two of the angles must match for the two triangles. Neither of the numbers 57°, 85° match either of the numbers 38°, 54°, so we know the two triangles have different angle measures. They cannot be similar.

The solution to the differential equation y' + 3y = f(t), y(0) = α using Laplace transforms is y(t) = αe⁻³ᵗ + F(s)/(s+3), where F(s) is the Laplace transform of f(t).

We use the Laplace transform on both sides of the problem in order to solve the given differential equation. Let Y(s) and F(s) represent the Laplace transforms of y(t) and f(t), respectively. Taking the Laplace transform of both sides of the equation, we have:

sY(s) - y(0) + 3Y(s) = F(s)

Substituting y(0) = α, we get,

sY(s) - α + 3Y(s) = F(s)

Rearranging the equation and solving for Y(s), we have,

Y(s) = (F(s) + α)/(s + 3)

Now, we need to find the inverse Laplace transform of Y(s) to obtain y(t). Using the properties of Laplace transforms, we know that the inverse Laplace transform of Y(s) is y(t) = L⁻¹{Y(s)}. Applying the inverse Laplace transform, we find,

y(t) = αe⁻³ᵗ + L⁻¹{F(s)/(s+3)}

The term αe⁻³ᵗ corresponds to the initial condition y(0) = α. The remaining term L⁻¹{F(s)/(s+3)} represents the inverse Laplace transform of F(s)/(s+3), which depends on the specific function f(t) and its Laplace transform.

Therefore, the solution to the differential equation is y(t) = αe⁻³ᵗ + F(s)/(s+3), where F(s) is the Laplace transform of f(t).

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a. Null hypothesis (H0): The average caloric intake among female Canadian athletes is equal to or greater than the recommended amount (µ ≥ 2811.5 kcal/day).

Alternative hypothesis (H1): The average caloric intake among female Canadian athletes is less than the recommended amount (µ < 2811.5 kcal/day).

b. The value of n that should be used is 201

c. SEM = 880 / √201

d. To sketch the normal curve and label the test statistic, we need the test statistic value and the critical region corresponding to the significance level α = 0.05

e. Without the test statistic or critical region, we cannot calculate the p-value.

f. Since we don't have the test statistic, critical region, or p-value, we cannot make a decision to reject or fail to reject the null hypothesis at this point.

g. Without the test statistic, critical region, or p-value, we cannot draw a conclusion regarding the evidence for or against the deficiency in caloric intake among female Canadian athletes.

a. The appropriate null and alternative hypotheses to test whether female Canadian athletes are deficient in caloric intake can be stated as follows:

Null hypothesis (H0): The average caloric intake among female Canadian athletes is equal to or greater than the recommended amount (µ ≥ 2811.5 kcal/day).

Alternative hypothesis (H1): The average caloric intake among female Canadian athletes is less than the recommended amount (µ < 2811.5 kcal/day).

b. The value of n that should be used is 201, which represents the number of female athletes in the study. The key word in the last sentence of the paragraph ("n=201 women") indicates that the information provided specifically pertains to the female athletes, not the entire sample of 324 athletes.

c. To calculate the test statistic, we need to determine the standard error of the mean (SEM) using the formula:

SEM = σ / √n

where σ is the population standard deviation and n is the sample size. In this case, the population standard deviation is given as 880 kcal/day, and the sample size is 201.

SEM = 880 / √201

d. To sketch the normal curve and label the test statistic, we need the test statistic value and the critical region corresponding to the significance level α = 0.05. However, the critical region is not provided in the given information.

e. The p-value represents the probability of obtaining a test statistic as extreme as or more extreme than the observed value, assuming the null hypothesis is true. Without the test statistic or critical region, we cannot calculate the p-value.

f. Since we don't have the test statistic, critical region, or p-value, we cannot make a decision to reject or fail to reject the null hypothesis at this point.

g. Without the test statistic, critical region, or p-value, we cannot draw a conclusion regarding the evidence for or against the deficiency in caloric intake among female Canadian athletes. Further analysis is required to obtain the missing information and make a conclusive statement.

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Answer:

B

Step-by-step explanation:

got it right on edg

The theorem states that for positive natural numbers a and n, the statements "GCD(a, n) = 1" (a and n are relatively prime), "a is not a zero divisor," and "there exists a natural number b such that ab ≡ 1 (mod n)" are all equivalent.

The theorem establishes the equivalence of three statements concerning positive natural numbers a and n. Firstly, if the greatest common divisor (GCD) of a and n is 1, it indicates that a and n are relatively prime.

This means that they have no common factors other than 1.

The second statement states that if a is not a zero divisor, then it implies that a multiplied by any nonzero element b is not equal to zero. In other words, a does not "annihilate" any nonzero element in multiplication.

Lastly, the theorem asserts that if there exists a natural number b such that ab ≡ 1 (mod n), it signifies the existence of a multiplicative inverse of a modulo n.

This means that a and n have a modular inverse, which is a natural number that, when multiplied by a, gives a remainder of 1 when divided by n.

The theorem shows that these three statements are equivalent, meaning that if one statement is true, then the other two statements will also hold.

The proof of this theorem involves establishing the logical connections between these statements and demonstrating that they are always true under the given conditions.

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The curvature of y = sin(–1x) at x = pi/4 is 2√2/3.

Curvature is the measure of how much a curve bends. It is the rate at which the unit tangent vector changes with respect to arc length. It is given by the formula,K = |dT/ds|Where K is curvature, T is the unit tangent vector, and s is arc length.So, the first step is to find the first derivative of y, which is given by,dy/dx = -1/√(1-x²)Now, we find the second derivative of y which is given by,d²y/dx² = x/(1-x²)^(3/2)At x = pi/4, we have,d²y/dx² = (π/4)/(1-(π/4)²)^(3/2) = 2√2/3Therefore, the curvature of y = sin(–1x) at x = pi/4 is 2√2/3.

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To show that the relation T defined on the set of integers Z is an equivalence relation, we need to prove three properties: reflexivity, symmetry, and transitivity.

1. Reflexivity: For any integer a, we need to show that aTa (mod). In modular arithmetic, a is congruent to itself modulo any integer, so this property holds.

2. Symmetry: For any integers a and b, if aTb (mod), then we need to show that bTa (mod). In modular arithmetic, if a is congruent to b modulo some integer, then b is also congruent to a modulo the same integer. Therefore, the symmetry property holds.

3. Transitivity: For any integers a, b, and c, if aTb (mod) and bTc (mod), then we need to show that aTc (mod). In modular arithmetic, if a is congruent to b modulo some integer and b is congruent to c modulo the same integer, then a is also congruent to c modulo that integer. Therefore, the transitivity property holds.

Since the relation T satisfies all three properties (reflexivity, symmetry, and transitivity), we can conclude that T is an equivalence relation.

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Answer:

The train is more reliable.

Step-by-step explanation:

The train is more reliable. The bus is on-time 87.5% of the time, while the train is on-time 90% of the time.

Answer:

It would be 4 quarts.

Step-by-step explanation:

The answer is 2 quarts

well, the triangle is an isosceles with twin sides, and so twin sides stemming from a common vertex will make twin angles on the other sides, the heck all that means?

well, it means that the twin sides of BC and BD make twin angles at C and D, so

[tex]6x-9~~ = ~~3x+24\implies 3x-9=24\implies 3x=33 \\\\\\ x=\cfrac{33}{3} \implies x=11 \\\\[-0.35em] ~\dotfill\\\\ \underset{ C }{\stackrel{ 6(11)-9 }{\text{\LARGE 57}^o}}\hspace{5em}\underset{ D }{\stackrel{ 3(11)+24 }{\text{\LARGE 57}^o}}\hspace{5em}\underset{ B }{\text{\LARGE 66}^o}[/tex]