Three problems faced by Mark Watney are :
The first major problem Watney faces is getting stranded and wounded on Mars. The second problem Watney faces is how he is going to survive on mars till help can come. The final problem he faces is how is he going to get to Ares, so he can leave Mars.What did Mark Watney do on Mars?
Mark Watney was also selected to perform experiments on plant growth using Martian Soil and Martian gravity.
Why was Mark Watney left on Mars?
Watney gets stranded on the Red Planet when a massive dust storm gravely injures him and forces his crewmates to escape, leaving him dead.
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calculate the response of an undamped system with stiffness k and mass m to the excitation given in fig. 7, assuming the system is initially at rest.
The undamped natural frequency, the damping ratio and the damped natural frequency are 3.162 rad / s, 0.211 and 3.098 rad / s respectively.
ωn = √ ( k / m )
ζ = c / 2 √ k m
ωn = Undamped natural frequency
k = Stiffness
m = Mass
ζ = Damping ratio
c = Damping co-efficient
m = 150 kg
k = 1500 N / m
c = 200 kg / s
ωn = √ ( 1500 / 150 )
ωn = 3.162 rad / s
ζ = 200 / 2 √ ( 1500 * 150 )
ζ = 0.211
Since ζ < 1, the system is underdamped and the solution will oscillate.
ωd = ωn √ ( 1 - ζ² )
ωd = Damped natural frequency
ωd = 3.162 √ ( 1 - 0.211² )
ωd = 3.162 √ 0.96
ωd = 3.162 * 0.98
ωd = 3.098 rad / s
Therefore,
Undamped natural frequency, ωn = 3.162 rad / sDamping ratio, ζ = 0.211Damped natural frequency, ωd = 3.098 rad / sThe system is underdampedThe solution will oscillateThe given question is incomplete. The complete question is:
A spring-mass-damper system has mass of 150 kg, stiffness of 1500 N/m and damping coefficient of 200 kg/s. Calculate the undamped natural frequency, the damping ratio and the damped natural frequency. Is the system overdamped, underdamped or critically damped? Does the solution oscillate?
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What is the net force in this image?
Answer:
D
Explanation:
If we ignore certain factors, then the net force is 0N, because we have two equal but opposite forces (10N-10N).
what is the effect on electrostatic force if distance increase 3 times
Here is your Answer:-
If the distance separating the objects is tripled, then what is the new force? Explanation: -The electrostatic force is inversely related to the square of the separation distance. So if d is three times larger, then F is nine times smaller – that is, one-ninth the original value.
Answer:
Explanation:
Given:
r₂ = 3·r₁
________
F₂ / F₁ - ?
According to Coulomb's law:
F₁ = k·q₁·q₂ / r₁²
F₂ = k·q₁·q₂ / r₂²
F₂ / F₁ = (r₁ / r₂)²
F₂ / F₁ = ( r₁ / (3·r₁)² = (1 / 3)² = 1 / 9
Strength will decrease by 9 times
Imagine that you jump out of an airplane and wait 3.8 seconds before pulling the parachute.
a. How fast are you going when you pull the chute?
b. How far have you fallen before you pull the chute?
While pulling the speed is 37.24 m/s and distance before 70.76 m
Acceleration due to gravity
a = 9.8 m/s2
a. by the equation of motion
V = U + at
= 0 + (9.8 m/s2) ×(3.8 s)
= 37.24 m/s
b. distance fallen
S = ut + (1/2)at
= 0 + (1/2)×9.8×3.82
= 70.76 m
A parachute acts like a wing on an airplane though it acts with the same force as a human when falling. The T-11's main canopy uses a unique deployment sequence to reduce shock and canopy vibration when opening. The T-11 is designed for an average descent velocity of 19 feet per second for the 95th percentile service member, compared to 24 feet per second for the T-10C.
Even if the main parachute fails he can use his backup parachute to land. There are even tactics you can use to increase your chances of surviving a free fall to Earth if your reserves also fail. So if you have two parachutes of the same size and shape but different materials and one is heavier than the other the heavier parachute will fall faster.
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Choose the picture of how the Earth would move if you "turned off the gravity forces
Answer:
I think the answer is d; as the object is revolving around the earth in a circular motion due to centripetal force provided by gravity and if you "turned off" the gravity then it would tend to continue away from the planet but in the same direction.
The Tesla Model S Electric vehicle can go from 0 to 60 mi/hr (26.8 m/s) in only 1.9 seconds! How far does it move from rest until it reaches 60 mi/hr? Round your answer to the nearest whole meter.
Answer:
The Tesla moves approx. 25 meters from rest before reaching 60 mi/hr
Explanation:
Given:
Initial velocity = 0 m/s
Final velocity = 26.8 m/s
Time = 1.9 seconds
Acceleration = change in velocity/time
[tex]a = \frac{26.8}{1.9}[/tex]
The equation to find displacement (Δx) with given starting and final velocity, time, and acceleration is:
[tex]x = x_{0} + v_{0}t + \frac{1}{2} at^{2}[/tex]
Starting position and initial velocity both equal 0, so
[tex]x = \frac{1}{2} at^{2}[/tex]
[tex]x=\frac{1}{2} (\frac{26.8}{1.9})(1.9)^{2}[/tex]
x = 25.46m
Rounded to the nearest whole number, x = 25m
At which point is potential energy being transformed to kinetic energy
Point at which potential energy is being transformed to kinetic energy is point F.
When is potential energy converted to kinetic energy?An object has potential energy when it is not in motion. Once a force has been applied, the potential energy changes to kinetic energy.
When an object is released from height, it is naturally pulled down towards the ground by the force of gravity. Object falls towards the ground as potential energy transforms into its kinetic energy.
Potential energy becomes kinetic when the object storing the potential energy starts to move. Since the potential energy is stored in the object, movement would release the energy.
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The larger the frequency of a photon of light, the _______ the energy of the photon.
The larger the frequency of a photon of light, the increase the energy of the photon.
As frequency increases, the energy of emitted photons will increase. The opposite is also actual. as the frequency of radiation decreases, there may be a corresponding lower in the power of emitted photons.
The higher the frequency, the more energy the photon has. Of path, a beam of mild has many photons. This means that absolutely intense purple light can bring more electricity to a given area than less severe blue light.
The quantity of energy is directly proportional to the photon's electromagnetic frequency and consequently, equivalently, is inversely proportional to the wavelength. The better the photon's frequency, the better its energy. Equivalently, the longer the photon's wavelength, the decrease its power.
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Students performed an investigation on how aluminum cans taken to a recycle center were able to be reused. They found out an aluminum can undergoes which type of change?.
Answer:
below
Explanation:
When it is melted , the can undergoes a phase change from a solid to liquid.
Explain the difference between music and noise.
A passenger on a ferris wheel moves in a vertical circle at constant speed. Are the forces on her balanced?.
In order to prevent the Ferris wheel from accelerate, the forces must be balanced. Newton's first law of motion states that unless an unbalanced force acts upon a body.
it will remain in its state of rest or uniform motion. The Ferris wheel moves at a consistent speed in a vertical circle, as stated in the question. Unbalanced force is what happens when two forces operating in opposition to one another on a body are not of the same size and magnitude and accelerate.
Keep in mind that the constant speed implies that the forces are in balance, as the Ferris wheel would accelerate under an unbalanced force.
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a movie camera with a single lens (has a converging lens) of focal length 75 mm takes a picture of a 180 cm high person standing 2.7 m away. what is the position of the image of the person? (write the value in cm and use only one decimal place).
The position of the image of the person is 0.5 cm.
What is meant by focal length?An optical system's focal length is the inverse of its optical power; it indicates how strongly the system converges or diverges light. A positive focal length system converges light, while a negative focal length system diverges light.
The rays are bent more sharply in a system with a shorter focal length, bringing them closer to focus or diverging them faster. For the special case of a thin lens in air, a positive focal length is the distance over which initially collimated (parallel) rays are brought to a focus.
Given,
Focal length=75mm
Height of the person=2.7m
f=((1/f)-(1/p))⁻¹
f=fp/p-f
Thus, the height of the image is
[tex]h_{i}[/tex]=m[tex]h_{p}[/tex]
[tex]h_{i}[/tex]=(i/p)[tex]h_{p}[/tex]
[tex]h_{i}[/tex]=f[tex]h_{p}[/tex]/p-f
[tex]h_{i}[/tex]=(75mm)(1.80m)/(27m-0.075m)
[tex]h_{i}[/tex]=5mm
[tex]h_{i}[/tex]=0.5 cm
The position of the image of the person is 0.5 cm
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Why can’t we see planetary transits from planets in our solar system other than Mercury and Venus?
A. Because only Mercury and Venus orbit closer to the Sun than we do.
B. Because no other planets are large enough to see from Earth.
C. We can see transits from all of the planets in our solar system.
D. Nobody knows; it’s a complete mystery.
Answer:
A. Because only Mercury and Venus orbit closer to the Sun than we do.
Explanation:
From the earth, the only planetary transits we can see are those of Mercury and Venus, because those are the only planets that can be between us and the sun.
Answer:
a) Because only Mercury and Venus orbit closer to the Sun than we do.
Explanation:
We can’t see planetary transits from planets in our solar system other than Mercury and Venus because, only Mercury and Venus orbit closer to the Sun than we do. Hence, the option (a) is correct.
From the information given in the diagram below, find the coefficient of friction between
the 43 kg box and the surface on which it is pulled. Note that the box is accelerating at
0.79 m/s2.
Answer:
μ = 0.55
Explanation:
Given:
m = 43 kg
a = 0.79 m/s²
F pull = 265 N
_____________
μ - ? Friction coefficient
2 Newton's law:
m·a = Fpull - μ·m·g
μ·m·g = Fpull - m·a
Friction coefficient:
μ = (Fpull - m·a) / (m·g)
μ = (265 - 43·0.79) / (43·9.8) ≈ 0.55
An object is hung by two cables at an angle. Which of the following is ALWAYS true when it is at rest?
Your answer:
The tension force (FT) is equal to the weight (Fg) of the object
The weight (Fg) is equal to the sum of the tensions in both wires
The vertical tension force (FTy) is half the weight (Fg)
The weight is equal to the sum of the two vertical tension forces (FTy)
The weight or force due to gravity (Fg) is equal to the sum of the tensions in both wires.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Frictional force allows the ball to stay in the hand while muscular force is employed to stop the motion of the ball during catching. Throughout this activity, the Earth's gravitational pull on the ball is constant.
The weight or force due to gravity (Fg) is equal to the sum of the tensions in both wires.
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✓
Sarah is building an electric motor whilst listening to the radio. She notices
that when she switches the motor on, the radio makes clicking noises. Using
knowledge about how radio waves are produced, describe why the radio
makes clicking noises.
Type your answer here....
The reason for the sound is the fact that there are other channels that are interfering with the particular channel that she was looking for.
Why does the radio make clicking noises?We know that radio waves are part of the electromagnetic waves. These are waves that do not require any material medium for them to become propagated thus they are able to move from one place to another even in a vacuum. Radio waves are known to have a long wavelength thus they can travel a far distance.
Given what we have said, we know that a radio is a device that have been built so as to be able to receive the radio waves. However, there are a number of frequencies that we are looking at that could be received by the radio at the same time. This could be referred to by the use of the word co channel interference.
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Claify each planet a an inner planet or an outer planet. Planet A ha 67 moon, and
major part of it atmophere
are hydrogen and helium. Planet B ha ring but
not much atmophere. Planet C ha no moon but
ha high volcanic activity
Known a the red planet, planet
D ha high amount of carbon
dioxide in it atmophere and
ha two moon. Planet E ha a thin layer of
atmophere but no moon due
to the effect of the Sun’ gravity. Planet F ha 27 moon, and it
atmophere i motly compoed
of hydrogen, helium, and methane
The inner planets are Planets C , D and E.
The outer planets are Planets A. B and F.
How many types of planets are there in our Solar System?
Astronomers frequently divide our Solar System's planets into two groups: the inner planets and the outer planets.
Inner Planets
Due to their position, nearer to the Sun, the inner planets are smaller and more rocky. Mercury, Venus, Earth, and Mars are the inner planets, which are listed in order of proximity to the sun from closest to farthest. The four inner planets are referred to as "terrestrial planets" because they have solid surfaces and, as suggested by their names, are fairly similar to Earth. However, the term can be deceptive because the conditions on each of the four worlds vary greatly. They have either no moons or few moons, are primarily composed of heavy metals like iron and nickel, and are small in size.Outer Planets
The outer planets are much larger in size, farther distant, and mostly composed of gas.Jupiter, Saturn, Uranus, and Neptune are the outer planets that appear after an asteroid belt.The outer planets are large, gas-encased planets that are also referred to as gas giants or Jovian planets. Each has a large number of moons and each has rings. Even though they are large, only Jupiter and Saturn are visible without telescopes. Astronomers learned the solar system was larger than previously believed when Uranus and Neptune, the first planets identified since antiquity, were discovered.On the basis of the above comparison the planets in the question are classified as-
Planet A - Outer Planet as has 67 moon, and major part of it atmophere are hydrogen and helium.
Planet B - Outer Planet as has ring but not much atmophere.
Planet C - Inner Planet as has no moon but has high volcanic activity
Planet D - Inner Planet as has high amount of carbon dioxide in it atmophere and has two moon
Planet E - Inner Planet as has a thin layer of atmophere but no moon due to the effect of the Sun’ gravity
Planet F - Outer Planet as it has 27 moon, and it has atmophere mostly composed of hydrogen, helium, and methane
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assume mvp contains 410 story points of work. how long will it take to deliver mvp if velocity is 18 story points per sprint and each sprint is two weeks in duration?
To learn about the velocity and momentum.
What is velocity?
The direction of motion of a body or object is determined by its velocity. In most cases, speed is a scalar variable. In their most basic form, vector quantities are speeds. It measures how quickly a distance changes within an area. What counts is the change in displacement rate.
What is momentum?
Mass in motion is quantified by momentum, or how much mass is moving in how much space. It typically has the letter P.
find
how long would it take to complete the entire project Y each story point is two weeks long ?
The product story point is 410 story points and 18 story points per spirit.
so the number of spirits in the product is given as
the number of spirit = 410/18 = 23
23 spirits
the each spirits take a two weeks, so
the time to complete the entire project = so it take to complete entire project.
Therefore, 23 sprint and each sprint is two weeks in duration.
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The fastest recorded pitch in Major League Baseball, thrown by Aroldis Chapman in 2010, was clocked at 169.14 km/h (105.1 mi/h). If a pitch were thrown horizontally with this velocity, what would the ball's vertical displacement be by the time it reached home plate, 18.3 m (60.0 ft) away?
Answer:
The ball would fall vertically for 112.45m
Explanation:
The vertical height of a horizontal throw is affected only by the speed of the throw and the acceleration due to gravity.
At this point, we may use this formula to determine the vertical height of the throw
vertical height =
The initial throwing speed has to be converted to m/s to ensure uniformity during the calculations. To do this we multiply by 1000 and divide by 3600
169.1km/hr = 46.972m/s
Maximum height = m
The pitch would make the ball fall vertically for 112.45m by the time it reached the home plate 18.2 m away
Answer:
The ball's vertical displacement 5.7 cm
Explanation:
Given:
V₀ = 169.14 m
D = 18.3 m
g = 9,81 m/s²
____________
Δh - ?
Ball flight time:
t = D / V₀ = 18.3 / 169.14 ≈ 0.108 s
The ball's vertical displacement:
Δh = g·t² / 2
Δh = 9.81·0.108² / 2 ≈ 0,057 m or 5.7 cm
why is ""friction"" (also called viscosity when it pertains to a gas) crucial for accretion disks?
Because Friction between gas orbiting at different speeds transfers angular momentum, also generating heat.
Friction is nothing but the opposing force acting on the device. In this case when accretion disks moves, it transfers angular momentum and and due to friction it also generates heat.
And as we know from conservations of energy that whatever heat is generated and angular momentum gets transferred, both will act as a negative parameter for a accretion disks.
That is the reason it is vey important to know and take care of the friction during designing or using of accretion disks.
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Read the question, and write your response in the space provided.
20. A force of 6.2 x 10' N is needed to blast off a 5.0 x 10³ kg rocket from rest.
What is the rocket's average acceleration?
Answer: 124m/s2
Explanation: I'm pretty sure this is correct, if it is not I'm sorry, and have a good day!
Consider a box resting on a horizontal surface. The box has a mass of 2.13 kg and the coefficient of static friction between the box and the surface is 0.151. Determine the force that must be applied down at a 37.8º angle to the horizontal to make the box start moving.
The force that must be applied down at an angle of 37.8° to the horizontal to make the box start moving is 3.99 N.
What is force?Force is obtained by multiplying the mass of a body by its acceleration.
To calculate the force that must be applied to make the box start moving, we use the formula below.
Formula:
F = mgμ/cos∅......... Equation 1Where:
F = Force applied to the boxm = Mass of the boxg = Acceleration due to gravityμ = Cofficient of static friction∅ = AngleFrom the question,
Given:
m = 2.13 kgg = 9.8 m/sμ = 0.151∅ = 37.8°Substitute these values into equation 1
F = (2.13×9.8×0.151)/(cos37.8°)F = 3.99 NHence, the force that must be applied to the box is 3.99 N.
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A graph titled Position versus Time shows time in seconds on the x axis, numbered 0 to 5, and position in meters on the y axis, numbered 0 to 15. The graph is a straight line from the (0, 3) to (4, 15).
Based on the information presented in the graph, what is the velocity of the object?
Answer:
3 m/s
Explanation:
distance (rise) over time (run) gives speed, that is velocity
it can be found using the gradient (m) formula
m=(y2-y1)/(x2-x1)
m=(15-3)/(4-0) =12/4=3 m/s
Answer:
3 m/s
Explanation:
.....as the answer for your question is 3m/s ..
THANK YOU..
8. assume pulleys and ropes are massless and frictionless. the surface with the 80 kg block has a coefficient of kinetic friction
The coefficient of kinetic friction ∝=9.81
Given that mass of block is 80kg .
Pulleys and ropes are massless and frictionless.
Coefficient of kinetic friction ∝ means the ratio of kinetic friction force of contacting surfaces to normal force .
Being a ratio parameter its unitless parameter.
[tex]F= mg\\\\F=\alpha N[/tex]
from these equations
[tex]mg=\alpha N[/tex]
Since there is no involvement of tension, g=∝
∝=9.81
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How does the angle at which a ray of light strikes a pane of window glass compare with the angle at which it passes out the other side?.
The angle at which a ray of light leaves the other side of a window pane is the same as the angle at which it strikes the glass.
What is refraction of light?Refraction is the change in direction of a wave when it passes from one medium to another or from a gradual to a sudden change in the medium.
When a wave of light passes from one medium to another, its direction is changed. This phenomenon is called refraction. It occurs because the speed of light is different in different media.
The amount of refraction that occurs depends on the difference in the speed of light in the two media, and the angle at which the light wave is incident on the boundary between the two media. The greater the difference in the speed of light, the greater the amount of refraction. The angle of incidence also affects the amount of refraction; the greater the angle, the greater the refraction.
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HELP PLEASE!!! Match the correct term with the corresponding definition or description.
The image below provides the solution. To read the text, enlarge the jpeg.
the impulse one ball receives is equal to the blank force on it from the other ball multiplied by the time during which the force is applied. by newton's third law the force that the rubber ball exerts on the steel ball is blank the force t
The impulse one ball receives is equal to average force on it from the other ball multiplied by the time during which the force is applied
The impulse one ball receives is equal to average force on it from the other ball multiplied by the time during which the force is applied. By newton's third law the force that the rubber ball exerts on the steel ball is equal to the force that steel ball exerts on rubber ball. So the rubber ball receives the same amount of impulse , although the directions of impulse are opposite.
Jx = Fx Δt
Jx = Impulse acting on x
Fx = Average force acting on x ( Answer 1 )
Δt = Period of time
Jrubber = Frubber * Δt
Jsteel = Fsteel * Δt
According to Newton's third law,
Frubber = - F steel ( Answer 2 )
Jrubber = - Fsteel * Δt
Jrubber = - Jsteel ( Answer 3 and 4 )
Therefore, the answers are,
AverageEqual toThe sameOppositeThe given question is incomplete. The complete question is:
Suppose a rubber ball collides head-on with a more massive steel ball traveling in the opposite direction with equal speed. Which ball, if either, receives the larger impulse?
The impulse one ball receives is equal to the ___ force on it from the other ball multiplied by the time during which the force is applied. By Newton's third law the force that the rubber ball exerts on the steel ball is ___ the force the steel ball exerts on the rubber ball So the rubber ball receives ___ amount of impulse, although the directions of the impulses are ___
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a paper airplane gliding down towards the ground will experience the force of air resistance pushing up. the weight of the paper airplane is 16 N down and the force of air resistance is 9 N up. find the net force
The net force acting on the airplane is 25N.
Forces acting on the paper airplane when it is in the air:
The forward force generated by the engine, propeller, or rotor is called thrust. It resists or defeats the drag force. It operates generally perpendicular to the longitudinal axis. However, as will be discussed later, this is not always the case.Drag is an airflow disruption generated by the wing, rotor, fuselage, and other projecting surfaces that causes a backward, decelerating force. Drag acts backward and perpendicular to the relative wind, opposing thrust.Weight is the total load carried by airplane, including the weight of the crew, fuel, and any cargo or baggage. Due to the influence of gravity, weight pulls the airplane downward.Lift—acts perpendicular to the flight path through the center of lift and opposes the weight's downward force. It is produced by the air's dynamic influence on the airfoil.Given.
Weight of the paper airplane, F1 = 16N
The force of air resistance, F2 = 9N
Net force = F1 + F2
Net force = 25N
Thus, the net force acting on the airplane is 25N.
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A boat with a mass of 1000 kg drifts with the current down a straight section of river parallel to the +x axis with a speed of 2.0 m/s. At t 0 the boat engages its engines, and accelerates at 2.7 m/s7. If the boat is oriented with its nose 45 from the +x axis, which of the following is a possible value for the boat's momentum at t- 3.0 s after the engine had started?
8100 kgm/s is a possible value for the boat's momentum at t- 3.0 s after the engine had started
m=1000kg
a=2.7 m/s^2
t=3
I=F/t
I=2700/2
I=900
F×t=P
P = momentum
t=time
f= force
F×t=P
P=2700×3
P=8100 kgm/s
Momentum is the result of a particle's mass and velocity combined. A vector quantity with both magnitude and direction is momentum. A particle's force is equal to its rate of change in momentum over time, which is stated in Isaac Newton's second equation of motion.
Any grouping of particles has a momentum equal to the vector sum of its momenta. The third law of Newton asserts that forces between particles are equal and opposite, and that any change in one particle's momentum is totally counterbalanced by a similar change in another particle's momentum.
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the left end of a spring is attached to a wall. when bob pulls on the right end with a 200 nn force, he stretches the spring by 20 cmcm. the same spring is then used for a tug-of-war between bob and carlos. each pulls on his end of the spring with a 200 nn force.
When a spring is only pulled by Bob with 200 N force, the spring stretches 20 cm. If the same spring is pulled by Bob and Carlos with 200 N forces each, the string will stretch 40 cm.
The elasticity is followed the Hooke's Law:
F = kx
Where:
F = force applied
k = spring constant
x = length of extension / compression
From the Hooke's Law, we know that the applied force is directly proportional to the change of length, or
F2 : F1 = x2 : x1
Parameters given in the problem:
F1 = 200 N (Force applied by Bob)
x1 = 20 cm
F2 = 200 + 200 = 400 N (Forces applied aby Bob and Carlos)
Therefore,
400 : 200 = x2 : 20
x2 = 400 x 20 / 200 = 40 cm
Thus, when both Bob and Carlos pulls the spring, the spring will stretch 40 cm
Complete question:
The left end of a spring is attached to a wall. When Bob pulls on the right end with a 200 N force, he stretches the spring by 20 cm . The same spring is then used for a tug-of-war between Bob and Carlos. Each pulls on his end of the spring with a 200 N force.
How far does the spring stretch?
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