Can someone please help me w/ this I need to plot the points on the graph (picture provied) then the answer is where ever the points met on the graph. ( please draw a line were they met u can screen shot the photo)
THE ANSWER IS SUPOSE TO LOOK LIKE THIS ( ___,___) IXL cc.2 8th grade

Answer:

-4 - 8-=-4

Step-by-step explanation:

Answer:

166,400,000

Got the same one today and figured it out! Yw!❤

Answer:

x = 42 degrees

y = 37 degrees

Step-by-step explanation:

Those are right angle triangles. So you know the right angles are 90 degrees, and each triangle gives you the measurement of another angle.

So, take the triangle in the top left (x):

180 - 90 - 48 = x

Same with the other triangle (y)

180 - 90 - 53 = y

Answer:

None of the above

Step-by-step explanation:

20 x 4 = 80

20 + 20 +20 =20 = 80

Answer:

y = x-7

Step-by-step explanation:

Slope intercept form is

y = mx+b  where m is the slope and b is the y intercept

2y -2x = -14

Add 2x to each side

2y-2x+2x= 2x-14

2y = 2x-14

Divide by 2

2y/2 = 2x/2 -14/2

y = x-7

Answer:

84,350

Step-by-step explanation:

843.5 x 10^2 = answer

Answer:

84350

Step-by-step explanation:

Answer:

[tex]x=55[/tex]

Step-by-step explanation:

To solve this question you need to know some properties of a parallelogram which is the shape given.

Firstly, remember that in a parallelogram opposite angles are equal.

Secondly, remember that the diagonals of a parallelogram bisect each other.

Lastly, remember that the sum of the interior angles of a quadrilateral or a parallelogram is 360°.

So, by using the first property we can see that because [tex]<[/tex]PQR=70° then [tex]<[/tex]PSR must be equal to 70° as well.

Now, we can use the last property to find [tex]<[/tex]SPQ then, use the second property to find [tex]x[/tex].

Let's name [tex]<[/tex]SPQ, [tex]y[/tex].

and That gives:

[tex]2y+140=360[/tex]

Subtract 140 from both sides:

[tex]2y=360-140[/tex]

[tex]2y=220[/tex]

[tex]y=\frac{220}{2}[/tex]

[tex]y=110[/tex]

So, [tex]<[/tex]SPQ=110 and

Now using the second property we can find that:

[tex]<[/tex]SPQ=[tex]2x[/tex]

And [tex]2x=110[/tex]

[tex]x=\frac{110}{2}[/tex]

[tex]x=55[/tex]

Hope this helped.

Answer:

y < (2 - 3x)/2.

Step-by-step explanation:

(3x+2y)<2

2y < 2 - 3x

y < (2 - 3x)/2

Answer:

Q1 b = 105 c= 75 D=105

Step-by-step explanation:

A aNd C are the same and B and D are the same as they are opposite angles. So , 75 +75 = 150 . Then , 360 - 150 = 210 . 210÷ 2 = 105

Hence,

A= 75 B = 105 C=75 D = 105

Explanation:

On taking LHS

Cos[(3π/2)+θ]Cos(2π+θ)[Cot{(3π/2)-θ}+Cot(2π+θ)]

We know that

π = 180°

2π = 2×180° = 360°

3π/2 = (3×180°)/2 = 540°/2 = 270°

Now

LHS becomes

Cos(270°+θ)Cos(360°+θ)[Cot(270°-θ)+Cot(360°+θ)]

We know that

Cos (270°+θ) = Sin θ

Cos (360°+θ) = Cos θ

Cot (270°-θ) = Tan θ

Cot (360°+θ) = Cot θ

→ Sin θ Cos θ [Tan θ + Cot θ]

→ Sinθ Cosθ[(Sinθ/Cosθ)+(Cosθ/Sinθ)]

→ Sinθ Cosθ[(Sin²θ+Cos²θ)/(SinθCosθ)]

→ Sin θ Cos θ [1/(Sin θ Cos θ)]

Since Sin²θ+Cos²θ = 1

→ (Sin θ Cos θ)/(Sin θ Cos θ)

→ 1

→ RHS

→ LHS = RHS

Hence, Proved.

Here are the formulae that I have used:

→ π = 180°

→ Cos (270°+θ) = Sin θ

→ Cos (360°+θ) = Cos θ

→ Cot (270°-θ) = Tan θ

→ Cot (360°+θ) = Cot θ

Here are the Trigonometric Identities that I have used:

→ Sin²θ+Cos²θ = 1

Answer:

5

Step-by-step explanation:

x=-1/2

The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

V = 30 cm³

Let the density of the gold sample be represented by ρ

The formula for the density is:

[tex]Density = \frac{Mass}{Volume}[/tex]

[tex]\rho = \frac{m}{V} \\\rho = \frac{579}{30} \\\rho = 19.3 g/cm^3[/tex]

The density of the gold sample is 19.3g/cm³

Learn more here: https://brainly.com/question/17780219

Answer:

$750 that is the answer if you add them all up

Answer:

Step-by-step explanation:

g(-4) = 4   ,  x < -2

g(-2) = (x - 1)²     ; -2≤x< 1

        = (-2-1)²

         = (-3)²

g(-2) = 9

g(0) = (x -1)²      ;  -2 ≤ x < 1

      = (0 -1)²

       = (-1)²

       = 1

Answer:

45°

4 units

Step-by-step explanation:

Rotation changes nothing about the geometric relationships within the figure. Angle measures are unchanged; side lengths are unchanged.

The acute angles of an isosceles right triangle are (180° -90°)/2 = 45°. This is true regardless of the orientation of the triangle with respect to any coordinate axes.

The measures of the legs of your triangle are 0 -(-4) = 4 = (1 - (-3)). Rotating the figure any amount in any direction around any center doesn't change that.

Answer: The rule (x,y)=(y,-x) describes the

transformation

Step-by-step explanation:.........bc

Answer:

The lesson ends at 5:15 pm.

Answer:

Her piano lesson ends at 5:15pm

Hope it helps:)

Answer:we are not your servers to that i should solve this problems

Step-by-step explanation:

Answer:

I have no idea? the first is 11 the second is 5 the three is 11 again the last 2 are 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

option 2, gl

Answer:

A and C

Step-by-step explanation:

Answer:

arc VW = 66°

Step-by-step explanation:

The inscribed angle WXY is half the measure of its intercepted arc WY, so

WY = 2 × 57° = 114°

Arc YX = 180° ( semi- circle ) , then

VW = YX - WY = 180° - 114° = 66°

Answer:

66°

Step-by-step explanation:

1) m(WY)=2*57=114°;

2) m(WX)=180-m(WY)=180-114=66°

Explanation:

On taking LHS

Cos[(3π/2)+θ]Cos(2π+θ)[Cot{(3π/2)-θ}+Cot(2π+θ)]

We know that

π = 180°

2π = 2×180° = 360°

3π/2 = (3×180°)/2 = 540°/2 = 270°

Now

LHS becomes

Cos(270°+θ)Cos(360°+θ)[Cot(270°-θ)+Cot(360°+θ)]

We know that

Cos (270°+θ) = Sin θ

Cos (360°+θ) = Cos θ

Cot (270°-θ) = Tan θ

Cot (360°+θ) = Cot θ

→ Sin θ Cos θ [Tan θ + Cot θ]

→ Sinθ Cosθ[(Sinθ/Cosθ)+(Cosθ/Sinθ)]

→ Sinθ Cosθ[(Sin²θ+Cos²θ)/(SinθCosθ)]

→ Sin θ Cos θ [1/(Sin θ Cos θ)]

Since Sin²θ+Cos²θ = 1

→ (Sin θ Cos θ)/(Sin θ Cos θ)

→ 1

→ RHS

→ LHS = RHS

Hence, Proved.

Here are the formulae that I have used:

→ π = 180°

→ Cos (270°+θ) = Sin θ

→ Cos (360°+θ) = Cos θ

→ Cot (270°-θ) = Tan θ

→ Cot (360°+θ) = Cot θ

Here are the Trigonometric Identities that I have used:

→ Sin²θ+Cos²θ = 1

Hope this helps!!

Answer:

28125

Step-by-step explanation:

300÷20=15

15×1875=28125

Step-by-step explanation:

(4s + 2) × (5s² + 10s +3)

we know immediately the first and the last term of the result, because there is only one operation to build them :

20s³ and 6.

so, the first answer option is already eliminated.

let's multiply

4s×5s² + 4s×10s + 4×3s + 10s² + 20s + 6

20s³ + 40s² + 12s + 10s² + 20s + 6

20s³ + 50s² + 32s + 6

so, the last answer option is correct.

Answer:

(0,4) and (1,2)

Step-by-step explanation:

The standard equation of a straight line is given as y = mx + b

Given the equation y = -2x + 4

Is x = 0, then;

y = -2(0) + 4

y = 4

One of the point on the graph is (0,4)

If x = 1, then;

y = -2(1) + 4

y = -2 + 4

y = 2

Hence the second point is (1, 2)

Learn more on equation of a line here: https://brainly.com/question/19417700

1. 3n - 5

Five less = -5

Than thrice (three times) a number = 3n

2. 7n + 3

The product of 7 and a number = 7n

Added to 3 = + 3

3. 1/2(3n - 4)

One-half = 1/2

The difference of thrice a number and 4 = 3n - 4

Hope this helps!! :)

Answer:

1. 5-x

2. (7*x)+x

3. 1/2(3x-4)

Answer:

152558.75*5%=7627.9

Step-by-step explanation: