Answers
Given,
The distance of the race, d=100 m
The extended distance of the race, s=200 m
The velocity of the red car throughout the race, u₁=10 m/s
The initial velocity of the blue car, u₂=0 m/s
The blue car gains a velocity of 2 m/s every second.The constant acceleration of the blue car is
hus t
[tex]\begin{gathered} a=\frac{2}{1} \\ =2\text{ m/s}^2 \end{gathered}[/tex]As the red car maintains the same velocity, the speed when it reaches the finish line will be 10 m/s.The time it takes for the red car to reach the finish line when the race was 100 m
[tex](t_1)_{100}=\frac{d}{u_1}[/tex]On substituting the known values,
[tex]\begin{gathered} (t_1)_{100}=\frac{100}{10} \\ =10\text{ s} \end{gathered}[/tex]The time it takes for the red car to reach the finish line after the race is extended,
[tex](t_1)_{200}=\frac{s}{u_1}[/tex]On substituting the known values,
[tex]\begin{gathered} (t_1)_{200}=\frac{200}{10} \\ =20\text{ s} \end{gathered}[/tex]From the equation of motion,
The final velocity of the blue car, when it reaches the finish line of 100 m race is given by the equation of motion,
[tex]v^2_{100}=u^2_2+2ad[/tex]Where v₁₀O is the final velocity of the blue car at the end of the 100 m race.n substituting the known values,₀
[tex]\begin{gathered} v^2_{^{}100}=0+2\times2\times100 \\ =400 \\ v=\sqrt[]{400} \\ =20\text{ m/s} \end{gathered}[/tex]hus the speed of the blue car when it reaches the finish line of 100 m race is 20 m/s
he time it takes for the blue car to reach the end of the 100 m race is given by,
[tex]v_{100}=u_2+a(t_2)_{100}[/tex]Where (t₂)₁₀₀ is the time it takes for the blue car to reach the end of the 100 m race.
On substituting the known values in the above equation,
[tex]\begin{gathered} 20=0+2(t_2)_{100} \\ \Rightarrow(t_2)_{100}=\frac{20}{2} \\ =10\text{ s} \end{gathered}[/tex]hus both cars take 10 s to reach the end of the 100 m race. Thus they both reach the finitsh line together.
The time it takes for the blue car to reach the end of the 200 m race can be calculated using the equation,
[tex]s=u_2(t_2)_{200}+\frac{1}{2}a\lbrack(t_2)_{200}\rbrack^2[/tex]Where (t₂)₂₀₀ is the time it takes for the blue car to reach the end of the 200 m race.
On substituting the known values,
[tex]\begin{gathered} 200=0+\frac{1}{2}\times2\times\lbrack(t_2)_{200}\rbrack^2 \\ \lbrack(t_2)_{200}\rbrack^2=200 \\ \Rightarrow(t_2)_{200}=\sqrt[]{200} \\ =14.14\text{ s} \end{gathered}[/tex]hus while rthe ed car takes 200 s to reach the finish line of the 200 m race, the blue car takes 14.14 s.
Therefore, if the race was extended, the blue car will reach the finish line first.
Related Questions
A runaway train car that has a mass of 13000 kg travels at a speed of 5.2 m/s down a track.
A Compute the time required, in seconds, for a force of 1700 N to bring the car to rest.
Answers
The time necessary to bring the automobile to a stop is 54 seconds, and the correct answer is 54 seconds.
t = -81000/-1500
t = 54 seconds
t 54 seconds
Which of these is Newton's Second Law of Motion?F = ma, or force is equal to mass times acceleration, is the second of Newton's three laws of motion. Learn how to compute acceleration using this formula.
According to the first law, an item won't alter its motion unless a force acts on it. According to the second law, an object's force is equal to its mass times its acceleration. The third law asserts that every action has a corresponding and opposing response.
Newton's third rule of motion explains that when two bodies contact, they exert force on one another.
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John recently suffered a gunshot wound to the abdomen and has undergone surgery. He is 37 years old, 6’ 0”, and weighs 200 lbs. John is currently on a medical ventilator to help him breathe.
1. Describe the metabolic response to injury (ebb phase and flow phase
Answers
Answer:
The flow phase is the "all or nothing" phase. it is trying to prevent bleeding and infection. It is compensating for the trauma and volume replacement.
Explanation:
hope it helps ;-;
an earth satellite remains in orbit at a distance of 6540 from the center of the earth. what is the period? the universal gravitational constant is 6.67 x 10^-11 and the mass of the earth is 5.98 x 10^24
Answers
The period of the earth satellite in its orbit can be calculated from 5.3 * 10^5 s.
Wat are Kepler's laws?We know that the force of gravity is the force that tens to throw objects back to the earth after they have been thrown up. We can then ay that the gravitational force is the force that has its direction as the center of the earth. It pulls objects right to the center of the earth.
From the Kepler's laws, we can tell that the square of the period of a given planet is directly proportional to the cube of the distance of that planet from the sun. We can now be able to accurately make good use of the Kepler's law to obtain the period.
We then have; T^2 = r^3
T = period of the planet
r = distance of the planet
It then follows that;
T = r^3/2
T = (6540 )^3/2
T = 5.3 * 10^5 s
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Find the quantity of heat needed to change a 0.80- g ice cube at absolute zero (-273 ∘C ) to 0.80 g of boiling water. Express your answer in calories
Answers
The quantity of heat needed to change a 0.80- g ice cube at absolute zero (-273 ∘C ) to 0.80 g of boiling water is 253.2 Cals
q = m c ΔT
q = m L
q = Heat
m = Mass
c = Specific heat
ΔT = Change in temperature
L = Latent heat
From absolute zero to melting temperature of ice,
[tex]q_{1}[/tex] = m c ΔT
[tex]q_{1}[/tex] = 0.8 x 0.5 x ( 0 - ( - 273 ) )
[tex]q_{1}[/tex] = 109.2 Cal
Energy required to melt the ice,
[tex]q_{2}[/tex] = m * L
[tex]q_{2}[/tex] = 0.8 x 80
[tex]q_{2}[/tex] = 64 Cal
From melting temperature to boiling temperature which is 100 °C,
[tex]q_{3}[/tex] = m c ΔT
[tex]q_{3}[/tex] = 0.8 x 1 x ( 100 - 0 )
[tex]q_{3}[/tex] = 80 Cal
Total heat required = [tex]q_{1}[/tex] + [tex]q_{2}[/tex] + [tex]q_{3}[/tex]
Q = 109.2 + 64 + 80
Q = 253.2 Cals.
Therefore, the quantity of heat needed is 253.2 Cals
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Victor is driving south. He is traveling at 12m/s, when he enters an area with a new speed limit. Aver a period of 6 seconds, his speed increases for 12m/s to 29m/s. What is Victors acceleration during this period?
Answers
Victor's acceleration when he increases from 12 m/s to 29 m/s over a period of 6 seconds is 2.83 m/s².
What is acceleration?
Acceleration can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s².
To calculate Victor's acceleration, we use the formula below.
Formula:
a = (v-u)/t........... Equation 1Where:
a = Accelerationv = Final velocityu = Initial velocityt = Time.From the question,
Given:
v = 29 m/su = 12 m/st = 6 secondsSubstitute these values above into equation 1
a = (29-12)/6a = 2.83 m/s²Hence, Victor's acceleration when he increases from 12 m/s to 29 m/s over a period of 6 seconds is 2.83 m/s².
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Without performing a calculation, predict which of the following compounds will have the greatest molar solubility in water.
AgCl (Ksp=1.8x10-10); AgBr (Ksp=5.0x10-15);
AgI (Ksp=8.3x10-17)
Answers
Answer:
the third one because it is greater then the other ones
If the temperature of a gas were to decrease, what would happen to the volume of a gas?
Answers
Answer:
The volume will decrease also.
increase in temperature leads to an increase in volume and vice versa.
three glasses of thickness 2cm , 4cm and 7cm are arranged adjacent .if their refractive indices arec 1.5 , 1.6 and 1.8 respectively. find the bottom of the prism to be raised above.
*Solution*
d = (2/1.5)+(4/1.6)+(7/1.8)
d =
Answers
A translucent, triangular object made of glass or plastic is referred to as a prism (or any transparent material). When white light enters a prism, a phenomenon called refraction causes the light to curve. Through the phenomenon of refraction, light is curved as it moves from one medium (like air) to another medium (like water or glass).
The efficiency with which an optical medium bends light is indicated by the medium's refractive index, which is a dimensionless quantity. The refractive index of a substance determines how much of the light that enters it is bent or refracted.
When an object is immersed in a transparent medium, the distance between its actual depth and its image is reduced by a factor equal to the medium's relative index of refraction with respect to air.
Actual depth divided by refractive index equals apparent depth.
(4/1.6) + (2/1.5) + (7/1.8) = d
d = 5.741 cm
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Zach takes out his slingshot and shoots a rock into the air at 35 m/s.
What is the total time that the rock will be in the air?
How high will the rock go?
At what velocity will the rock return to where it started from?
Answers
Answer:
take downwards as negative and upwards as positive
Explanation:
the velocity of the rock to return to where it started from will be -35m/s
Calculate the magnitude of the repulsive force between a +500μC charge and a +100μC charge which are 5 m apart. [k=9×109 Nm2C-1]
Answers
(9x10^9)(500x10^-6)(100x10^-6)/(5)
(450)/(5)
90 Newtons
Assuming motion is on a straight path, what would result in two positive components of a vector?
a train moving north of east at an angle of 25°
a bus moving north of east at an angle of 95°
a boat moving south of west at an angle of 40°
a car moving south of west at an angle of 10°
Answers
Answer:
Last one is a right answer.
Explanation:
a car moving south of west at an angle of 10 ⁰
The maximum amount of pulling force a truck can apply when driving on
concrete is 10,560 N. If the coefficient of static friction between a trailer and
concrete is 0.8, what is the heaviest that the trailer can be and still be pulled
by the truck?
Answers
The truck needs to draw the trailer with 13200 N of force at its maximum capacity.
What Does Static Friction Mean?Every physical object has a small amount of "stickiness," which is where friction gets its power. Where two surfaces touch, there will be some resistance to motion in that direction. When two surfaces are stationary in relation to one another, there is static friction. Because static friction creates resistance, a certain amount of force must be exerted to get objects moving. There won't be any movement at all if the force applied to one of the surfaces does not surpass the static friction force.
Let the weight of the truck be W . reaction force R = W
Maximum frictional force = μ R
= .8 x W
So for movement of truck
Pulling force = frictional force
10560 = .8W
W = 13200 N
weight of heaviest truck required = 13200 N .
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You return the person tennis serve and hit a smashing winner into the corner of the backcourt. Your racket hits the tennis ball with a force of 50N
and a duration of 0.2 s. The mass of the ball is 0.5 kg. What was the velocity of the ball?
Answers
F = ma
Therefore:
F = m(v/t)
- The force is 50 N
- The mass is 0.5 kg
- Time is 0.2 seconds
50 = 0.5(v/0.2)
Solve for v and you get the velocity of the ball after it leaves the racket.
Velocity = 20 m/s
A student fires a cannonball vertically upwards with an initial speed v. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the cannonball. Calculate the maximum height (h) and total flight time (t) in each of the following cases.
Answers
This is projectile motion. We know that in this kind of motion the maximum height is given by:
[tex]h_{\max }=\frac{v^2_0\sin \theta}{2g}[/tex]and that, when the motion is complete (this means that the object stops at the same height it begins, like in this case) the total time of flight is given by:
[tex]t=\frac{2v_0\sin \theta}{g}[/tex]In both of this equations the angle theta represents the angle of launch.
Now, in this case the student fires the cannonball upwards, this means that the angle of launch is 90°; since:
[tex]\sin 90=1[/tex]Then, for this problem, the equations above reduced to:
[tex]h_{\max }=\frac{v^2_0}{2g}[/tex]and
[tex]t=\frac{2v_0}{g}[/tex]Now that we know this we can plug the initial velocity of each case in the equations above to determine the maximum height and time of flight. For example, if the initial velocity is 13 m/s then we have that:
[tex]\begin{gathered} h_{\max }=\frac{13^2}{2(9.8)}=8.62\text{ m} \\ \text{and} \\ t=\frac{2(13)}{9.8}=2.65\text{ s} \end{gathered}[/tex]With this procedure we have that the table would be:
A ship travels at a velocity of 42 m/s in north-westerly direction. A man on the ship is walking at a velocity of 3,2 m/s from the back of the ship to the front of the ship.
What is the man’s resultant velocity in magnitude and direction?
Answers
The man’s resultant velocity is 4m/s in the north-westerly direction.
What exactly is relative speed?According to mathematics, the relative velocity is the vector difference between the velocities of two objects. The difference between the velocities of body A and body B determines the relative velocities between them.
What is the speed of resultant?The total of an object's component vector velocities is the resulting vector velocity. The sum of the vector forces acting on an object is equal to the scalar product of its mass and acceleration vector.
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8. A graph of a car's motion is shown below
Answers
From the graph of the motion of the car, the deceleration of the car is -1.5 m/s².
What is motion?Motions is defined as the change in the position of a body.
There are several forms of motion that a body can undergo, they include:
translational motion - this is motion along a straight lineCircular or rotational motion - this is motion of a body in a circular pathOscillatory motion - this is a periodically repeating motion of a bodyRandom motion - this is the haphazard motion of a body.Considering the motion graph of the car as shown, the car undergoes a translational motion in a straight path. The car changes its speed over time.
Between O and A, the speed of the car increases steadily, and this part is known as acceleration.
Between A and, the car moves with constant speed.
Between B and C, the speed of the car steadily decreases which is known as deceleration.
deceleration= change in speed/ change in timeThe deceleration of the car = (0 - 30) / (50 - 30)
The deceleration of the car =-1.5 m/s²
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Complete question:
A graph of a car's motion is shown below. What is the deceleration of the car from B to C?
a semi permeable membrane is stretched across a chamber filled with water . the membrane is only permeable to water. 60 mg of salt is added to the left side of the chamber what will happen
Answers
If 60 mg of salt is added to the left side of the chamber then water will move toward the left side.
Semi permeable membrane :A membrane that permits some molecules to pass through it but not others is said to be semi-permeable. A semipermeable membrane is the cell membrane. Because of the hydrophobic nature of the tails, the phospholipid bilayer prevents most molecules from diffusing across the membrane, making the cell membrane semi-permeable. The most effective membrane is made of cellophane.
What passes through a membrane that is semipermeable?Osmosis is the naturally occurring transfer of solvent molecules from a lower concentration solution to a higher concentration solution across a semi-permeable membrane. Kidney tissue is an example of a semipermeable membrane. Some molecules can pass through kidneys without being blocked by others, such as waste products from people. For water filtration or desalination, semipermeable membranes made of synthetic materials are employed.
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what is a major impact of global climate change?
Answers
Answer: Pollution and humans
Hotter temperatures
Nearly all land areas are seeing more hot days and heat waves; 2020 was one of the hottest years on record. Higher temperatures increase heat-related illnesses and can make it more difficult to work and move around. Wildfires start more easily and spread more rapidly when conditions are hotter.
Changes in temperature cause changes in rainfall. This results in more severe and frequent storms. They cause flooding and landslides, destroying homes and communities, and costing billions of dollars.
ncreased drought
Water is becoming scarcer in more regions. Droughts can stir destructive sand and dust storms that can move billions of tons of sand across continents. Deserts are expanding, reducing land for growing food. Many people now face the threat of not having enough water on a regular basis.
More frequent and intense drought, storms, heat waves, rising sea levels, melting glaciers and warming oceans can directly harm animals, destroy the places they live, and wreak havoc on people's livelihoods and communities.
Hope this helps!
What is the horizontal velocity at each point of the trajectory?
Answers
Answer:
Constant velocity across x-axis(horizontal)
Sanjay uses 225 N of force to move a wheelbarrow 18 m at a velocity of 1.8 m/s. What was the amount of power used?
Answers
The amount of power used by Sanjay when he uses a force of 225 N to move a wheelbarrow 18 m at a velocity of 1.8 m/s is 405 N
What is power?
Power can be defined as the product of force and velocity.
To calculate the amount of power used by Sanjay, we use the formula below.
Formula:
P = FV........... Equation 1Where:
P = PowerF = ForceV = Velocity.From the question,
Given:
F = 225 NV = 1.8 m/sSubstitiute these values into equation 1
P = 225×1.8P = 405 NHence, the amount of power is 405 N.
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3 pts. A 500-g particle moving along the x-axis experiences the force shown in the figure. The particle’s velocity is 2.0 m/s at x = 0 m. For each part, give your answer in m/s to 2 significant figures.
Answers
(a) The velocity of the particle at position x = 1 m is 3.74 m/s.
(b) The velocity of the particle at position x = 2 m is 6.63 m/s.
(c) The velocity of the particle at position x = 3 m is 9.7 m/s.
What is force constant?The force constant or spring constant of a spring is the measure of stiffness of a spring.
The force constant of the spring is the slope of the graph and it is calculated as follows;
k = F/x
k = ΔF/Δx
where;
ΔF is change in forceΔx is change in extension of the springk = (15 N - 10 N) / (3m - 2m)
k = 5 N/m
The speed of the particle at each position is determined by applying the principle of conservation of energy as follows;
ΔK.E = ΔU
where;
ΔK.E is change in kinetic energy of the particleΔU is change in potential energy of the particle¹/₂m(v² - u²) = ¹/₂k(x₂² - x₁²)
m(v² - u²) = k(x₂² - x₁²)
v² - u² = k(x₂² - x₁²) / m
v² = k(x₂² - x₁²)/m + u²
v = √[ k(x₂² - x₁²)/m + u²]
where;
v is the final velocity of the particleu is the initial velocity of the particle = 2 m/sk is spring constantm is mass of the particle = 500 g =0.5 kgx₁ is the initial position of the particle = 0 mFor x = 1 m
v = √[5 (1² - 0²)/0.5 + 2²]
v = 3.74 m/s
For x = 2 m
v = √[5 (2² - 0²)/0.5 + 2²]
v = 6.63 m/s
For x = 3 m
v = √[5 (3² - 0²)/0.5 + 2²]
v = 9.7 m/s
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What are some products that you could purchase to help your performance in your current physical activity?
How would the product? Do you really think it is effective
Answers
Being physically active can improve your brain health, help manage weight, reduce the risk of disease, strengthen bones and muscles, and improve your ability to do everyday activities.
Physical Activity Product?Numerous bodily processes, like your heart rate and respiratory rate, depend on aerobic activity. It builds endurance and exercises your heart and lungs. One of the most well-liked pieces of commercial gym equipment is the treadmillFitness Products are those that are primarily designed for physical activity, physical training, health, or relaxation in a setting that emphasizes health and fitness, as well as similar uses and associated services, such as, but not limited to, health, fitness, nutrition (such as vitamins, health foods, and other sports, nutrition, body-...
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Give three examples of object in equilibrium in the classroom and draw an approximate scale diagram for the object
Answers
Three examples of object in equilibrium in a classroom are table at rest, book on a desk at rest and a chalk on a chalk holder at rest.
Equilibrium is the state in which all the individual forces acting on the object are balanced and so the net force will be zero. An object not necessarily be in a state of rest to be at equilibrium. If an object is moving with constant velocity it is in a state of equilibrium unless interfered with an outside force.
Examples of object in equilibrium in a classroom are:
Table at restBook on a desk at rest Chalk on a chalk holder at restTherefore, three examples of object in equilibrium in a classroom are table at rest, book on a desk at rest and a chalk on a chalk holder at rest.
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7/21/22, 7:37 AMProblem Set ThreeNotes: Use 9.8 m/s 2 for the acceleration due to gravity. Formust be expressed in m/sLaw calculations, mass must be expressed in kg and velocity.A force of 3.2 N is applied to an 8.5 gram rifle bullet. What is the bullet’s acceleration?
Answers
ANSWER:
376.47 m/s²
STEP-BY-STEP EXPLANATION:
Given:
Force (F) = 3.2 N
Mass (m) = 8.5 gram = 0.0085 kg
We can determine the acceleration by the following formula:
[tex]\begin{gathered} F=m\cdot a \\ \\ \text{ We replacing:} \\ \\ 3.2=0.0085\cdot \:a\: \\ \\ a=\frac{3.2}{0.0085} \\ \\ a=376.47\text{ m/s^^b2} \end{gathered}[/tex]The acceleration is 376.47 m/s²
Which statement describes the horizontal motion of a horizontally launched projectile? The projectile’s acceleration is zero, so its velocity is zero. The projectile’s acceleration is –9.8 m/s2, so its velocity is changing. The projectile’s acceleration is zero, so its velocity is constant. The projectile’s acceleration is –9.8 m/s2, so its velocity is constant.
Answers
The statement that describes horizontal motion is the projectile’s acceleration is –9.8 m/s2, so its velocity is constant.
How does velocity of a projectile motion change with time?
During the upward motion of a projectile, the vertical velocity decreases with increase in the height of the motion due to the opposing force of gravity.
The vertical velocity of the projectile will be zero at maximum height. As the projectile begins to the descend, the vertical velocity starts to increase and eventually becomes maximum before the projectile hits the ground.
The horizontal velocity of the projectile will be constant since the effect of gravity is not felt in a horizontal motion.
Thus, we can conclude that during a projectile motion, the vertical velocity will change, the horizontal velocity will be constant and the acceleration due to gravity will 9.8 m/s².
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Answer:
C : The projectile’s acceleration is zero, so its velocity is constant.
Explanation:
Carolina is trying to assess the popularity of a number of politicians. She has people rate a series of politicians and she uses this information to organize the politicians from most popular to least popular (e.g., Senator Johnson is first, Senator White is second, etc.). What scale of measurement is this variable?
Answers
The scale of measurement in this variable ( i.e., popularity of a number of politicians ) is ordinal scale.
Here Carolina is asking people to rate a series of politicians and is using that information to organize the politicians from most popular to least popular. Since there is an ordering / ranking of the collected data, this scale of measurement falls under ordinal scale.
There are 4 types of scales of measurement. It can also be called as 4 levels such as:
Nominal scaleOrdinal scaleInterval scaleRatio scaleTherefore, the scale of measurement in this variable is ordinal scale.
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Energy is the ability to cause ________________ . Your goal is to avoid change to the structure of the egg. Kinetic energy is the energy of ____________. In order to save your egg, you will need to lower the kinetic energy of the egg just before the egg strikes the ground. The formula for kinetic energy is ___________. You can’t change the mass, so you must try to adjust the __________. How can we do this? Think about forces we studied in our first unit. The force that can lower the velocity of a falling object is _________________. The two factors that affect this force are __________ and ____________.I’m not sure if this is even a type of question you could do
Answers
ANSWER:
Work
Movement
1/2*m*v^2
Velocity
Weight.
Mass
Gravity
STEP-BY-STEP EXPLANATION:
Energy is the ability to cause work .
Your goal is to avoid change to the structure of the egg. Kinetic energy is the energy of movement.
In order to save your egg, you will need to lower the kinetic energy of the egg just before the egg strikes the ground. The formula for kinetic energy is 1/2*m*v^2. You can’t change the mass, so you must try to adjust the velocity. How can we do this?
Think about forces we studied in our first unit. The force that can lower the velocity of a falling object is weight. The two factors that affect this force are mass and gravity.
In the particle model, the object in motion is represented by a series of single points.
Answers
Answer:
In the particle model, the object in motion is represented by a series of single points. A time interval is the difference between two locations. A vector has both location and direction. The zero point in a coordinate system is called the resultant.
The displacement
of a particle from a
reference point at any instant is given
by s = 31² 4t + 5, where s is in
metres and t is time in seconds.
Calculate the average velocity of the
particle in the time interval between 3
s and 5 s, and its instantaneous
velocity at 4 s.
Answers
The average velocity of the particle in the time interval between 3 s and 5 s is 28 m / s. The instantaneous velocity at 4 s is 28 m / s.
Average velocity = ( s2 - s1 ) / ( t2 - t1 )
s = 3t² + 4t + 5
At t = 3s,
s1 = 3 ( 3 )² + 4 ( 3 ) + 5
s1 = 27 + 12 + 5
s1 = 44 m
At t = 5 s,
s2 = 3 ( 5 )² + 4 ( 5 ) + 5
s2 = 75 + 20 + 5
s2 = 100 m
Average velocity = ( 100 - 44 ) / ( 5 - 3 )
Average velocity = 28 m / s
At t = 4 s, the instantaneous velocity,
v ( t ) = ds / dt
v ( t ) = d ( 3t² + 4t + 5 ) / dt
v ( t ) = 6t + 4
v ( 4 ) = 6 ( 4 ) + 4
v ( 4 ) = 28 m / s
Therefore,
The average velocity of the particle = 28 m / s. The instantaneous velocity = 28 m / s.To know more about Instantaneous velocity
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In outer space, a constant force is applied to a 33.2 kg probe initially at rest. The probe moves a distance of 101 m in 15 s. What acceleration does this force produce? What is the magnitude of the force?
Answers
Answer:
a
=
F
M
a
=
137
30.8
x
=
1
2
a
t
2
x
=
1
2
⋅
137
30.8
⋅
13
2
x
=
375.86
Explanation: Hope this helps ;)