Can someone help me out on these geometry fill in the blanks questions? Just questions 2,3,4.. it’s urgent

Using the inverse function concept, the table that represents the inverse of the table given is table a.

The inverse of the function is given by the set that contains point (y,x), that is, the coordinates are exchanged.

In the table given, we have points (0,0), (2,1) and (4,2), hence the inverse table has points (0,0), (1,2) and (2,4), which is table a.

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For the given system of equation, the value of x = 4 and the value of y = -1

From the question, we are to solve the given system of equations

-7x + 4y = -32 -------- (1)

9x - 2y = 38   -------- (2)

From equation (2)

9x - 2y = 38

2y = 9x - 38

y = 4.5x - 19 -------- (3)

Substitute this into equation (1)

-7x + 4y = -32

-7x + 4(4.5x -19) = -32

-7x + 18x - 76 = -32

-7x + 18x = -32 + 76

11x = 44

x = 44/11

x = 4

Substitute the value of x into equation (3)

y = 4.5x - 19

y = 4.5(4) - 19

y = 18 - 19

y = -1

Hence, the value of x = 4 and the value of y = -1

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The value for each interior angle in the polygon will be 147.27°.

The total angles in the 11 sided polygon will be:

= (n - 2) × 180

= (11 - 2) × 180

= 9 × 180°

= 1620°

Each angle will be:

= 1620°/11

= 147.27°

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Answer:

the answer to this problem is D:(-2,4)(1,1)

Answer:

B

Step-by-step explanation:

y = x² → (1)

y = 3x - 2 → (2)

substitute y = x² into (2)

x² = 3x - 2 ← subtract 3x - 2 from both sides

x² - 3x + 2 = 0 ← in standard form

(x - 1)(x - 2) = 0 ← in factored form

equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 2 = 0 ⇒ x = 2

substitute these values into (2) for corresponding values of y

x = 1 : y = 3(1) - 2 = 3 - 2 = 1 ⇒ (1, 1 )

x = 2 : y = 3(2) - 2 = 6 - 2 = 4 ⇒ (2, 4 )

The range of this function is all real numbers such that 0 ≤ y ≤ 40.

A range is the set of all real numbers that connects with the elements of a domain. This simply means that, a range is the solution set on the y-axis.

Based on the table (see attachment), we can logically deduce that when the time (x) is zero (0), the amount of water remaining in the bathtub (y) is 40.

Therefore, the range of this function is all real numbers such that 0 ≤ y ≤ 40.

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Answer:

  C.  Ian rode less than 1 hour

Step-by-step explanation:

It never hurts to think about what the problem statement is telling you. Ian rode at a speed that would take him 18 miles in 1 hour.

Clearly, Ian would pass the 15-mile mark in a 1-hour ride before an hour had elapsed. If he only rode 15 miles, he rode less than 1 hour.

The actual time Ian rode is given by the relation between speed, time, and distance.

  time = distance/speed

  time = (15 mi)/(18 mi/h) = (15/18) h = 5/6 h

Ian's riding time was 5/6 of an hour, which is less than 1 hour.

Each daylily cost $3 and one bunch of ornamental grass cost $8.

Build two equation's: (Let 'd' be daylilies, 'o' be ornamental grass)

$118 on 2 daylilies and 14 bunches of ornamental grass.

$98 on 14 daylilies and 7 bunches of ornamental grass.

Make d subject for first equation.

2d + 14o = 118

2d = 118 - 14o

d = (118 - 14o)/2

d = 59 - 7o

Insert this into second equation.

14(59 - 7o) + 7o = 98

826 - 98o + 7o = 98

-91o = -728

o = 8

Find value of d:

d = 59 - 7o

d = 59 - 7(8)

d = 3

Answer:

Cost of one daylily = $3

Cost of one bunch of ornamental grass = $8

Step-by-step explanation:

Define the variables:

Given information:

Create a system of equations with the given information and defined variables:

[tex]\begin{cases}2d+14g=118\\14d+7g=98 \end{cases}[/tex]

Multiply the second equation by 2:

[tex]\implies 2(14d+7g)=2(98)[/tex]

[tex]\implies 28d+14g=196[/tex]

Subtract the first equation from this equation to eliminate the variable g:

[tex]\begin{array}{r r r}28d & +14g = & 196\\- \quad \quad2d & +14g = & 118\\\cline{1-3}26d & = & 78\end{array}[/tex]

Solve for d:

[tex]\implies 26d=78[/tex]

[tex]\implies d=3[/tex]

Substitute the found value of d into one of the equations and solve for g:

[tex]\implies 2d+14g=118[/tex]

[tex]\implies 2(3)+14g=118[/tex]

[tex]\implies 6+14g=118[/tex]

[tex]\implies 14g=112[/tex]

[tex]\implies g=8[/tex]

Therefore, the cost of one of each plant is:

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The ordered pair that is the possible solution for the equation is (-6,0) (0,-4).

The slope-intercept form of a linear equation takes the form y= mx + b.

Here:

The function f(x) = y = [tex]\mathbf{-\dfrac{2}{3}x-4}[/tex]

[tex]\mathbf{y = -\dfrac{2}{3}x-4}[/tex]

The slope (m) = -2/3

The x-intercept is the value of x for which y = 0

The y-intercept is the value of y for which x = 0

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Switch the variable x and y with each other. Then the correct option is B.

Let the function will be

f: X → Y

Then the inverse function will be

f⁻¹: Y → X

The function is given below.

f(x) = 3x – 10

Then the inverse function of the f(x) will be

Put y in place of f(x).

    x = 3y – 10

  3y = x + 10

    y = (x + 10) / 3

Switch the variable x and y with each other.

Then the correct option is B.

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Answer:

wouldn't it be 0.1

Step-by-step explanation:

Answer:

radius = 5

Step-by-step explanation:

Since the line is a tangent, that means the PT and OP are perpendicular (they make a right angle) Sooo, the triangle is a right triangle. Use Pythagorean Theorem to calculate or Pythagorean Triples for a shortcut (5, 12, 13)

r^2 + 12^2 = 13^2

r^2 + 144 = 169

Subtract 144

r^2 = 25

Squareroot both sides.

sqrt(r^2) = sqrt25

r = 5

The radius is 5.

The value of p is 60°

The figure given is a triangle and it is important to note that sum of angles in a triangle = 180 degrees

The other sides are gotten by;

Angle on a straight line = 180

110 + x = 180

x = 180 - 110

x = 70

The other interior angle

130 + y = 180

y = 180 - 130

y = 50

We have,

x + y + p = 180

70 + 50 + p = 180

120 + p = 180

p = 180 -120

p = 60°

Thus, the value of p is 60°

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Hello,

Answer: We have f(x) = g(x) when x ≈ 1

(a) x = 1, is an approximate solution for f(x) = g(x).

Here, we have,

given that,

A graph of two functions is shown

f(x) and, g(x)

now, we have,

The graph has two functions, which are f(x) and g(x) and a graph.

In the graph, we can follow their intersections.

Those would be the parts of the line that would make the functions to have the same value.

The first intersection is really close to 1,

and second is very unclear, most likely beyond -2.5.

Since the highest number is 1 and the intersection is very close to 1,

we have to go with the approximate answer.

We have f(x) = g(x) when x ≈ 1.

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Answer:

The answer is 20

Step-by-step explanation:

Their are two bases and three sides in a triangular prism so the total surface area is 20

Answer:

y=3

Step-by-step explanation:

The solutions when y = 0 are x = -4.796 and x = 4.796

The function is given as:

[tex]y = (\frac{x + 5}{x + 1} \div \frac{(x + 3)(x - 2)}{(x -4)(x + 1)})- \frac{1}{x - 2}[/tex]

See attachment for the graph of the function

When the function is simplified, we have:

(x +3)(x -2) at the denominator of one of the terms

Set this factor to 0

(x +3)(x -2) = 0

Expand

x + 3 = 0 and x -2 = 0

Solve for x

x = -3 and x = 2

Hence, the vertical asymptotes are x = -3 and x = 2

The feature at x = -1 is a hole and, not a vertical asymptote.

This is so because the absolute value of -1 is less than the absolute values of the vertical asymptotes at x = -3 and x = 2

From the attached graph, we have:

x = -4.796 and x = 4.796 when y = 0

Hence, the solutions when y = 0 are x = -4.796 and x = 4.796

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The x- and y-coordinates of point C, which partitions the directed line segment from A to B into the ratio 3:10 is; (-2.6, 5.2)

The coordinate of the points are given as:

A(-4, 8)

B(2, -4)

Ratio of partition is given as; 3:10

Now, the point at the given ratio is calculated from the formula;

C = [(mx2 + nx1)/(m + n)], [(my2 + ny1)/(m + n)]

Thus;

C = [(3*2 + 10*-4)/(3 + 10)], [(3*-4 + 10*8)/(3 + 2)]

C = (-34/13, 68/13)

C = (-2.6, 5.2)

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Answer:

-2.6, 5.2

Step-by-step explanation:

Absolutely, over result will match in part b and c

Geogebra tools are software which is used to study an absolute geometry with zero errors.

Since, Geogebra contains various tools, In part b we have drawn a square through polygon command. Its allows  to select the number of sides, so we select 4 cause square requires 4 equal sides.
Now, we very it in c part just by drawing a 4 connected lines which have 90° adjacent angles.
                    Here, by comparing their geometry it seems identical

Thus, the result, in part b and c matches for each other.

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Answer:

∠C and ∠F are right angles

Step-by-step explanation:

To prove that two triangles are congruent using HL, one must have:

For this problem, there are two sides of the triangle already congruent:  one could be the hypotenuse (if the right angle were across from it), and the other congruent side could be a leg.  So, if we can prove either that angles C & F are right angles, or that angles A & D are right angles, that would be enough to use HL congruence.

Hence, from the answer choices provided, proving that angle C and angle F are both right angles would be sufficient to prove the triangles are congruent via HL congruence.

Side note:  Proving angles B and E would not be enough to use HL congruence, because the hypotenuse is always across from the right angle.  So, if angle B were a right angle, it would mean that side AC was the hypotenuse (which hadn't yet been proven or stated to be congruent).

While not enough to prove triangle congruence via HL, if angle B and E were congruent at all (right angles or not), it would be enough to prove that the triangles were congruent by SAS (side-angle-side) because it would have proven that two sides and the included angle were congruent.

Answer: B, D, E

Step-by-step explanation:

Statement 1 cannot be true because f(1)<0.

Statement 2 might be true.

Statement 3 cannot be true because if f is continuous, then for some value between -1 and 0, f(x) is positive by the Intermediate Value Theorem.

Statement 4 might be true.

Statement 5 might be true

(a) i. See comment...

(a) ii. We have

[tex]\vec p = 6\,\vec\imath - 3\,\vec\jmath + 9\,\vec k[/tex]

and

[tex]\vec q = 3\,\vec\imath - 6\,\vec\jmath - 3\,\vec k[/tex]

(b) We can parameterize the line segment from P to Q by the vector function

[tex]\vec r(t) = (1-t) \vec p + t \vec q = (6-3t) \, \vec\imath + (-3-3t) \,\vec\jmath + (9-6t) \,\vec k[/tex]

with [tex]0\le t\le1[/tex]. The point R is located 1/3 of the way along this line segment, i.e. at [tex]t=\frac13[/tex], so its position vector is

[tex]\vec r\left(\dfrac13\right) = 5\,\vec\imath -4\,\vec\jmath + 7\,\vec k[/tex]

and hence its coordinates are [tex]\boxed{(5,-4,7)}[/tex].

Answer:

adding

Step-by-step explanation:

The number of boys and girls assigned to each team is 6 and 15 respectively.

= 63/3

= 21 students

Number of girls = 5/7 × 63

= 315/7

Number of girls = 45 students

Number of boys = 63 - 45 = 18 students

If the three groups have equal composition of boys and girls, then,

Number of boys and girls in each group is 6 and 15 respectively.

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Minimizing the sum of the squared deviations around the line is called Least square estimation.

It is given that the sum of squares is around the line.

Least squares estimations minimize the sum of squared deviations around the estimated regression function. It is between observed data, on the one hand, and their expected values on the other. This is called least squares estimation because it gives the least value for the sum of squared errors. Finding the best estimates of the coefficients is often called “fitting” the model to the data, or sometimes “learning” or “training” the model.

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Answer:

5x + 25

Step-by-step explanation:

2x+29+3x+4

Step 1: Arrange it:- 2x+3x+29-4

Step 2:- Add and Subtract the terms:- 5x + 25

HOPE IT HELPS!

Hey there!

EQUATION:
2x + 29 + 3x - 4

COMBINE the LIKE TERMS

(2x + 3x) + (29 - 4)

2x + 3x + 29 - 4

SIMPLIFY IT!

5x + 25

Therefore, your answer should be:

5x + 25

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

The slope formula is used to find the slope of a line that joins two points (x₁, y₁) and (x₂, y₂). Using this formula, the slope of the line is, m = (y₂ - y₁) / (x₂ - x₁). We can use the same formula to find the slope of a line from its graph also.

The value of x in the congruent triangles abc and dec is 1

The question implies that the triangles  abc and dec are congruent triangles.

The congruent sides are:

ab = de

bc = ce = 4

ac = cd = 5

The congruent side ab = de implies that:

4x - 1 = x + 2

Collect like terms

4x - x = 2 + 1

Evaluate the like terms

3x = 3

Divide through by 3

x = 1

Hence, the value of x is 1

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Complete question

Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2

The answer is 1/2 .

In given question ,

Dalinda spins a spinner = 60 times.

                           blue = 30

The probability that the pointer will land on blue =   30 / 60  ⇒ 1/2

Therefore, the answer is 1/2 .

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Answer: can you show us the graph?

Step-by-step explanation:

Answer:

66 dollars

Step-by-step explanation:

15+6=22

15×2=30

15+22+30=66

Answer:

Tim had 15 dollars. Paul had 6 dollars more than Tim. Rick had double Tim’s money. How much did they have ALTOGETHER is 66 dollars.

Step-by-step explanation:

→ Is know :

→ Asked :

How much did they have ALTOGETHER ?

→ Solution :

[tex] \bf{x =Tim's \: \: money + Paul's \: \: money + Rick's \: \: money }[/tex]

[tex]\bf{x =15 + (15 + 6) + (2 \times 15) }[/tex]

[tex]\bf{x =15 + 21 + 30 }[/tex]

[tex]\bf{x =36 + 30 }[/tex]

[tex]\bf{x =66 \: \: dollars }[/tex]

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