Can someone help me out and show work

Answer:

C=0,12N-1,15

Step-by-step explanation:

Answer:

9.375 miles

Step-by-step explanation:

1) Let's set up an equation.

2.60 + 1.50x = 17.60

1.50x = 17.60 - 2.60

1.60x = 15

x = 15/1.60

x = 9.375

The parent. function shifted down by 2 units to produce x² and to the right by 3 units to produce y = x^2 + 3

This is a way of changing the position of an object on an xy-plane.

Given the parent function expressed as  y = (x + 2^)2

From the resulting image after translation, we can see that the parent. function shifted down by 2 units to produce x² and to the right by 3 units to produce y = x^2 + 3

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Angle is 90°

The sector is 1/4 th of circle

Area of sector

Triangle is right angled

Area

Area of unshaded region

Answer:

4.6 in²  (nearest tenth)

Step-by-step explanation:

To find the area of the unshaded region, subtract the area of ΔAGB from the area of sector AGB.

The measure of an arc is equal to its corresponding central angle measure.  Therefore, the central angle of sector AGB is 90°.

As the two sides of ΔAGB adjacent the central angle are the radii of the circle they are therefore equal in length ⇒ ∠GAB = ∠GBA.  

Therefore, ΔAGB is an isosceles triangle.

Area of triangle (using the Sine Rule):

[tex]\sf A=\dfrac{1}{2}ab \sin C[/tex]

(where a and b are the side lengths and C is the included angle)

Given:

[tex]\implies \sf Area\:of\:triangle=\dfrac{1}{2}(4)(4)\sin 90^{\circ}=8\:in^2[/tex]

Area of a sector of a circle

[tex]\textsf{A}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2[/tex]

[tex]\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}[/tex]

Substituting the given angle and radius:

[tex]\implies \textsf{A}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (4)^2=4\pi\:\: \sf in^2[/tex]

Area of the unshaded region:

[tex]\begin{aligned}\textsf{Area of unshaded region} & =\textsf{Area of sector} - \textsf{Area of triangle}\\& = 4 \pi - 8\\& = 4.566370614...\\ & = 4.6\:\sf in^2\:\:(nearest\:tenth)\end{aligned}[/tex]

The evaluation of the algebraic fraction x+2x+1/x^2-25 is[tex]\mathbf{\implies -\dfrac{3}{5(x+5)} +\dfrac{18}{5(x-5)}}[/tex]

The division of an algebraic expression can be carried out by using the long division method or expansion of the.

Given that:

[tex]\mathbf{\dfrac{x+2x+21}{x^2-25}}[/tex]

where:

By expanding the denominator, we have:

[tex]\mathbf{\dfrac{x+2x+21}{(x+5)(x-5)}}[/tex]

[tex]\mathbf{\dfrac{3x+21}{(x+5)(x-5)}}[/tex]

Creating a partial fraction from the denominator, we have:

[tex]\mathbf{\dfrac{3x+21}{(x+5)(x-5)} = \dfrac{a_o}{x+5} +\dfrac{a_1}{x-5}}[/tex]

Multiply the equation by the denominator, and we have:

[tex]\mathbf{\dfrac{(3x+21)(x+5)+(x-5)}{(x+5)(x-5)} = \dfrac{a_o(x+5)(x-5)}{x+5} +\dfrac{a_1(x+5)(x-5)}{x-5}}[/tex]

Simplifying, we have:

3x + 21 = a₀(x-5)+a₁(x+5)

Solve for the unknown parameter by plugging the real roots of the denominator: -5, 5

[tex]\mathbf{a_o =\dfrac{-3}{5}}[/tex]

[tex]\mathbf{a_1 =\dfrac{18}{5}}[/tex]

Replacing the solutions into the partial fractions parameters to obtain the final result, we have:

[tex]\mathbf{\dfrac{-(\dfrac{3}{5})}{x+5} +\dfrac{\dfrac{18}{5}}{x-5}}[/tex]

[tex]\mathbf{\implies -\dfrac{3}{5(x+5)} +\dfrac{18}{5(x-5)}}[/tex]

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The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)

Let

f(x) = ax² + bx + c

Plug x = 0, and y = 2

c = 2 ...(1)

Plug x = 1 and y = 0

a + b + c = 0 ..(2)

Plug x = -1 and y = 0

a - b + c = 0  ...(3)

After solving (1), (2), and (3)

a = -2

b = 0

c = 2

f(x) = -2x² + 2

Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

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△MNQ ≅ △PNQ by SAS congruence theorem.

If two triangles are congruent by the SAS congruence theorem, then they have two pairs of corresponding congruent sides and a pair of corresponding included sides that are congruent.

∠MNQ ≅ ∠PNQ [congruent angles formed by angle bisector]

Therefore, opposite sides to the angles, MQ and PQ would also be congruent.

Thus, MQ ≅ PQ

NQ ≅ NQ [reflexive property]

This means that both triangles have two pairs of corresponding congruent sides and a pair of corresponding included sides that are congruent.

Thus, △MNQ ≅ △PNQ by SAS congruence theorem.

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The required expression is given by 179.2 - 10.6d.

There were 179.2 gallons of water in the barrel and 10.6 gallons are used each day

Volume, is defined as the ratio of the mass of object to its density.

the volume of water in a rain barrel after "d"days
When there were 179.2 gallons of water in the barrel and 10.6 gallons are used each day.

since the amount of water is getting consumed day by day
therefore, the expression can be given as
  =  179.2 - 10.6d

Thus, the required expression is 179.2 - 10.6d.

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Answer:

Step-by-step explanation:

I had this exact question and I figured it out.

the answer is: P(police officer and chooses car)

In order to get this answer I did the P(police officer) X P(choosing car)

It ended up being 36/45 X 15/45. Which is equal to around .2666667.

Now you take the Intersection of police officer and chooses car and you divide it by 45. That value on the chart is 12.

lucky enough, the product of 36/45 and 15/45 is equal to 12/45.

So 0.8 X 0.33 = .26

.26 = .26

Answer:

answer is P(police officer and chooses car)

Step-by-step explanation:

the probability of P(policer officer) and P(choose a car) are independent probabilities ( they are not overlapping probabilities)

Answer:

Step-by-step explanation:

that is my

Answer:

Muhammad ibn Musa al-Khwarizmi

محمد بن موسی خوارزمی

Answer:

a.

Step-by-step explanation:

> is a symbol of inequality representing greater than

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

Billy thinks of a nonzero number. He multiplies it by 3. He gets...? 3 options given

[tex]\Large\maltese\underline{\textsf{This problem has been solved!}}[/tex]

This problem does not give us the information about the starting number (we can't read Billy's mind).

First, I'm going to assume that the number is positive

[tex]\bf{A\;positive\;number\;multiplied\;by\;-3;\;yields\;a\;negative}[/tex]

Next, I'll assume that Billy's number is a negative one.

[tex]\bf{The\;number\;is\;a\;positive\;one}[/tex].

[tex]\rule{300}{1.7}[/tex]

[tex]\bf{Result:}[/tex]

              [tex]\bf{=The\;answer\;could\;be\;either\;positive\;or\;negative.\;It\;depends\;on\;the\;sign}\\of\:the\:starting\:number.[/tex]

Answer:

no man you should reconsider the question again

try typing again i guess its wrong

Answer: exponential, f(x), divided by 4, 1,6

Step-by-step explanation:

The solution of the quadratic equation 8x² – 5x – 4 = 0 will be 1.085 and negative 0.460.

The solution of the equation means the value of the unknown or variable.

The quadratic equation is given below.

8x² – 5x – 4 = 0

Then we have

a = 8, b = -5, c = -4

Then the solutions will be

[tex]\rm x = \dfrac{-b\pm \sqrt{b^2 - 4ac}}{2a}\\\\\\\rm x = \dfrac{-(-5)\pm \sqrt{(-5)^2 - 4 * 8 * (-4)}}{2 * 8 }\\\\\\x = \dfrac{5 \pm 12.37}{16}\\\\\\x = \dfrac{5- 12.37}{16}, \dfrac{5 +12.37}{16}[/tex]

On further solving, we have

x = 1.085, -0.460

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Answer:

x > -3     and     x ≤ 1

Step-by-step explanation:

   [First inequality]

Given:

 -2x + 8 < 14

Subtract 8 from both sides:

 -2x < -6

Divide both sides by -2, since it's negative we also flip the sign:

 x > 3

   [Second inequality]

Given:

 -3x - 9 ≥ -12

Add 9 to both sides:

 -3x ≥ -3

 Divide both sides by -3, since it's a negative we also flip the sign:

 x ≤ 1

The largest possible volume of the box is 6158.394 cm^3.

Define the dimensions of the box to be L, W, and H.

Square base, L = W

Area: A = L^2 * H

Surface Area (Base + Area of 4 sides):

1600 = L^2 + 4 (L*H) ⇒ H = (1600 - L^2) / (4L)

Area: A = 400L - (1/4)L^3

Maximum (Derivative) A' = 400 - (3/4)L^2

Solving for 0

0 = 400 - (3/4)L^2

L^2 ⇒ (40 * SQRT(3)) / 3 = 23.094 (Maximum)

Solving for dimensions, known L=23.094

L = 23.094 cm

W = 23.094 cm

H ⇒ (1600 - L^2) / (4L) = (20 * SQRT(3) / 3) = 11.547 cm

Volume ⇒ L*W*H = 6158.394 cm^3

To locate the most viable extent, add the greatest viable mistakes to every dimension, then multiply. To find the minimum viable volume, subtract the greatest feasible mistakes from each measurement, then multiply.

Volume is a scalar amount expressing the amount of 3-dimensional area enclosed by a closed surface. For example, the gap that a substance or 3-D shape occupies or consists of.

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Option b) [tex]x^{2} -x-\sqrt{x} +3[/tex] is not a polynomial

Polynomial equation is equation of dependent variables which is related to the independent variable.

since, the equation ,[tex]x^{2} -x-\sqrt{x} +3[/tex] contains the square root of variable that's why its not a polynomial.

Thus, Option b) [tex]x^{2} -x-\sqrt{x} +3[/tex] is not a polynomial

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Answer:

b 12

Step-by-step explanation:

62=5x+2(opposite angle are equal)

5x=60

x=12

Answer:

8. a , c

9. b

10. c

Linear programming which shows the best investment strategy for the client is Max Z=0.12I +0.09B and subject to constraints are :I+ B<=25000,

0.005 I +0.004B<=250.

Given maximum investment client can make is $55000, annual return= 9%, The investment advisor requires that at most $25,000 of the client's funds should be invested in the internet fund. The internet fund, which is the more risky of the two investment alternatives, has a risk rating of 5 per thousand dollars invested. the blue chip fund has a risk rating of 4 per thousand dollars invested.

We have to make a linear programming problem.

Let

I= Internet fund investment in thousands.

B=Blue chip fund  investment in thousands.

Objective function:

Max Z=0.12I+0.09B

subject to following constraints:

Investment amount: I+ B<=25000

Risk Rating: 5/100* I+4/100*B<=250 or 0.005 I +0.004B<=250

I,B>=0.

Hence the objective function is Max Z=0.12 I+ 0.09 B.

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Based on the game rules of randomly picking a card and multiplying it by the roll from a number cube, the following are true:

There are 6 sides to dice and 4 cards. The sample space is:

Dice             Card            Product        

1                 5                         5

1                 6                         6

1                 7                         7

1                 8                         8

2                 5                         10

2                 6                         12

2                 7                         14

2                 8                         16  

3                 5                         15

3                 6                         18

3                 7                         21

3                 8                         24

4                 5                         20

4                 6                         24

4                 7                         28

4                 8                         32

5                 5                         25

5                 6                         30

5                  7                         35

5                  8                         40

6                 5                         30                        

6                 6                         36

6                 7                         42

6                 8                         48

Frequency table

Product                     Frequency

5                                      1

6                                      1

7                                      1

8                                      1

10                                      1

12                                      1

14                                      1

16                                      1

15                                      1

18                                      1

21                                      1

24                                      2

20                                      1

28                                      1

30                                      2

32                                      1

25                                      1

35                                      1

40                                      1

36                                      1

42                                      1

48                                      1

Total                                24

The frequency table shows that to get 28 or more, a person will have a relative frequency of:

= 1 + 2 + 1 + 1 + 1 + 1 + 1 + 1

= 9

Probability is:

= 9 / 24

= 3/8

= 37.5%

The number of products required to win 25% of the time is:

= 25% x 24

= 6

To find the winning number, count down from the highest product 6 times to get 32.

The probability of getting 36 or higher is:

= ∑(Probabability of picking 36 and above numbers)

= 1 / 24 + 1/24 + 1/24 + 1/24

= 1 / 6

The probability of repeating this 4 times is:

= 1 / 6 x 1 / 6 x 1/ 6 x 1 / 6

= 1 / 1,296

= 0.0007716

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Answer:

8.49 units

Step-by-step explanation:

1. The distance formula is: [tex]\sqrt{(x2-x1)^{2} +(y2-y1)^{2} }[/tex]

2. Let's plug in the numbers: [tex]\sqrt{(-1-5)^{2} +(4--2)^{2} }[/tex]

3. [tex]\sqrt{(-6)^{2} +(6)^{2} }[/tex]

4. [tex]\sqrt{36 + 36}[/tex]

5. [tex]\sqrt{72}[/tex] ≈ 8.485

Answer:

$1,075

Step-by-step explanation:

Simple Intereat Formula:

A = P(1+rt)

where A is the final amount,

P is the principal(original amount invested)

r = annual interest rate

t = time in years

Given P = 1000

r = 2.5/100

t = 3 (Beginning of 4th year means the 4th year is not counted)

A = 1000(1+(0.025)(3))

= 1000(1.075)

=$1,075

Answer:

Step-by-step explanation:

[tex]L.H.S = 1^2+Sin^2A+Cos^2A+2SinA+2CosA+2SinACosA\\ \{(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca\}\\ = 1 + (Sin^2A+Cos^2A) + 2SinA+2CosA+2SinACosA \\ \{Sin^2A+Cos^2A=1\}\\ = 1 + 1 + 2SinA+2CosA+2SinACosA \\ = 2(1 + SinA+CosA+SinACosA)\\ = 2(1^2 + (SinA+CosA).1+ SinACosA )\\ \{x^2+(a+b)x + ab = (x+a)(x+b)\} \quad here \quad x=1\\ = 2(1+SinA)(1+CosA).\\[/tex]

Answer:

Step-by-step explanation:

Solution

I'm assuming you want this simplified. If not leave a note.

a(x + 1) - b(x + 1) - x - 1                     remove the brackets

ax + a - bx - b - x - 1                        gather like terms

ax - bx - x + a - b - 1

x(a - b - 1)  + (a - b - 1)                      Use the distributive property to simplify

Answer

(x + 1)(a - b - 1)

The common factor is (a - b - 1). That can be pulled out on either side of the isolated + sign

Answer:

[tex]\frac{\sqrt{7} }{4}[/tex]

Step-by-step explanation:

since sin theta = 3/4, opposite length = 3 units and hypotenuse length = 4 units

by pythagoras' theorem, adjacent length = [tex]\sqrt{7}[/tex]

thus cos theta = adjacent/hypotenuse = [tex]\frac{\sqrt{7} }{4}[/tex]

a. I and II only true statement.

b . ∠3  = 84°

c . m∠KJM = 138° and m∠KLM  = 59°

Therefore, i and ii are true for an isosceles trapezium.

∠2 ≅ ∠3

∠1 ≅ 96°

Therefore,

∠3  = 180 - 96

∠3  = 84°

m∠KJM = 180 - x - 14

5x - 2 = 180 - x - 14

5x - 2 = 180 - x  - 14

5x + x = 180 - 14 + 2

6x = 168

x = 168 /6

x = 28

m∠KJM = 5(28) - 2 = 138°

m∠KLM  = 180 - 10y + 29

3y + 14 = 180 - 10y + 29

3y + 10y = 180 + 29 - 14

13y = 195

y = 195 / 13

y = 15

m∠KLM  = 3(15) + 14

m∠KLM  = 45 + 14

m∠KLM  = 59°

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Step-by-step explanation:

no of people=2

time taken=1/60mins

no of people=10

time taken=1/x

2=1/60

10=1/x

x=12mins