Can I please get a full answer with steps? Thanks a bunch!

Answer:

False

Step-by-step explanation:

The slope is 0.

Answer: [tex]x=-2 \pm \sqrt{29/5}[/tex]

Step-by-step explanation:

[tex]5x^2 + 20x=9\\\\5(x^2 + 4x)=9\\\\5\left((x+2)^2 -4 \right)=9\\\\5(x+2)^2 - 20=9\\\\5(x+2)^2 = 29\\\\(x+2)^2 = \frac{29}{5}\\\\x+2 =\pm \sqrt{29/5}\\\\x=-2 \pm \sqrt{29/5}[/tex]

Answer:

14

Step-by-step explanation:

CB/AB = CE/ET

3/7 = 6/ET

ET = 14

Answer:

A. 1, 2, 3, 4, 6, 8, 12, 24

Answer:

960

Step-by-step explanation:

(if i made any typos, sorry it is kind of hard to type on computer over writing on paper.)

A=2AB+(a+b+c)h

AB=s(s﹣a)(s﹣b)(s﹣c)

s=(a+b+c)/2

Solving forA

A=ah+bh+ch+1/2 sqrt(﹣a^4+2(ab)^2+2(ac)^2﹣b4+2(bc)^2﹣c^4)=10·12+24·12+26·12+1

2·﹣104+2·(10·24)2+2·(10·26)2﹣244+2·(24·26)2﹣264=960

Answer:

Step-by-step explanation:

The distance between the poles is the segment d which connects the top of the shorter pole with the point at 5 m from the top of the longer pole, which is the difference of lengths of poles.

The three points form a right triangle, with hypotenuse of 16 m, and legs 5 m and d.

Use Pythagorean to find the value of d:

Answer:

Step-by-step explanation:

Surface Area Formula

SA = 2lw + 2lh + 2hw

2 * 2 * 5 + 2 * 2 * 3 + 2 * 3 * 5 =

62cm²

The information given about the proof does that Daniel made an error on line 2.

Given:

1. AB = 3x +2;  BC = 4x + 8;  AC = 38

2. AB + BC = AC      incorrect (not an angle angle addition postulate)

3. 3x+2 + 4x + 8 = 38         correct

4. 7x + 10 = 38                    correct

5. 7x = 28                           correct

6. x = 4

Daniel made an error on line 2.

Here is the complete question:

Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5

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Answer:

Hay 600 en el club de magia.

Answer:

x=-7

Step-by-step explanation:

0.3(8-2x) - 1.2(2-3x) < -21

2.4 - 0.6x - 2.4 + 3.6x < -21

3x < -21

x < -7

Answer:

170.833

Step-by-step explanation:

we have to find real value which has to be find.

let take it as x,

in the question they said reduction percentage is equal to $123

then x*72/100=$123

x=$123*100/72

x=12300/72

x=170.8333

Answer:

I believe it's 211.90$.

The value of w is -1 and -5.

The correct option is (B)

A mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value.

Given:

2w² + 12w + 10 = 0

First, divide through by 2

2w²/2 + 12w /2 + 10/2 =0/2

w² + 6w + 5 = 0

now, Take half of the w term and add - subtract the square of it

w² + 6w + 5 + 3² - 3² = 0

w² + 2*3w + 3² + 5 - 9 = 0

(w+3)² = 4

w+3 = ±2

w = +2 - 3, -2-2

w= -1 and -5.

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Answer:

[tex]\huge\boxed{\sf 37 }[/tex]

Step-by-step explanation:

Highest weight = 116 g

Lowest weight = 79 g

= 116 g - 79 g

= 37

[tex]\rule[225]{225}{2}[/tex]

Answer:

1654.9

Step-by-step explanation

1/0.1273 = 13000/x

x=1654.9

Answer:

Step-by-step explanation:

First, lets open up the parentheses.

3x - 6x + 4 = 8 - 2x + 3

Combine like terms.

-3x + 4 = 11 - 2x

Add 2x to both sides

-x + 4 = 11

Subtract 4 from both sides

-x + 4 -4 = 11 -4

Simplify

-x = 7

Divide both sides by -1

x = -7

Hope this helps! (:

Answer:

x = -7

Step-by-step explanation:

3x – 2(3x – 2) = 2(4 – x) + 3

The first step is to distribute when solving for x

3x – 6x +4 = 8 – 2x + 3

Then combine like terms

-3x+4=-2x+11

Add 3x to each side

-3x+3x+4=-2x+3x+11

4 = x+11

Subtract 11 from each side

4-11 = x+11-11

-7 = x

The points of intersection for the two functions and round to the nearest tenth are (0.5, 1.4) and (4.85, -0.3)

Given the following function

f(x) = - 0.5x + 2

g(x) = x^3 - 5x^2 + 3

The point of intersection is the point where f(x) = g(x)

x^3 - 5x^2 + 3 = - 0.5x + 2

x^3 - 5x^2 + 3 + 0.5x - 2 = 0

x^3 - 5x^2 + 0.5x + 1 = 0

Factorize and determine the value of x

x = 0.53 and 4.85

If x = 0.53

f(0.53) = -0.5(0.53) + 2

f(0.53) = -0.265 + 2

f(0.53) = 1.375

If x = 4.85

f(4.85) = -0.5(4.85) + 2

f(4.85) = -2.425 + 2

f(4.85) = -0.245

Hence the points of intersection for the two functions and round to the nearest tenth are (0.5, 1.4) and (4.85, -0.3)

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Answer: 76.5 meters

Step-by-step explanation:

To find the side lengths you use trig ratios for 30,60,90 triangles. The ratio is n (attached to the opposite side of the 30-degree angle, or the smallest leg), n[tex]\sqrt{3}[/tex] (attached to the opposite side of the 60-degree angle, or the longest leg), 2n (attached to the hypotenuse). Using the inner triangle you can use 2n=28 to find the side opposite the 30-degree angle, 14. Then you plug 14 into every n and add the sides. the full answer is 76.4974226 but this problem said to round making your final answer 76.5 meters. always remember to give proper units.  

The amount of dose is 10.5oz

The dosage is given as:

1/2oz 3x day for 7 days

This means that:

The patient will use 1/2 oz  3 times daily for 7 days

So, the dose is

Dose = 1/2 oz * 3 * 7

Evaluate the product

Dose = 10.5oz

Hence, the amount of dose is 10.5oz

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The  journal entries relating to the building for the fifth year is: Debit Depreciation expense   $10,500; Credit To accumulated depreciation        $10,500.

Bailand Company

1. Dec 31  

Debit Depreciation expense         $10,500

Credit Accumulated depreciation                     $10,500

(Being the depreciation expense recorded)

Book value=$148,000-($148,000-$8,000/10×4)]

Book value=$148,000-$56,000

Book value=$92,000

Depreciation=$92,000-$8,000/8

Depreciation=$10,500

2. Dec 31  

Debit Depreciation expense $24,000.00

Credit Accumulated depreciation a/c               $24,000.00

[($92,000-$8,000)×6/21]

(Being the depreciation expense recorded)

3. Dec 31    

Debit Accumulated depreciation $3,200.00

[($8,000×4)/10]

Credit  Retained earnings              $3,200.00

(Being prior year adjustment for depreciation expense)

Dec 31  

Debit  Depreciation expense         $10,000.00

Credit Accumulated depreciation             $10,000.00

[($148,000-$8,000)/10]

(Being the depreciation expense recorded)

Therefore the  journal entries relating to the building for the fifth year is: Debit Depreciation expense   $10,500; Credit To accumulated depreciation   $10,500.

The complete question is:

Bailand Company purchased a building for $148,000 that had an estimated residual value of $8,000 and an estimated service life of 10 years. Bailand purchased the building 4 years ago and has used straight-line depreciation. At the beginning of the fifth year (before it records depreciation expense for the year), the following independent situations occur:

1. Bailand estimates that the asset has 8 years’ life remaining (for a total of 12 years).

2. Bailand changes to the sum-of-the-years’-digits method.

3. Bailand discovers that the estimated residual value has been ignored in the computation of depreciation expense.

Required: For each of the independent situations, prepare all the journal entries relating to the building for the fifth year. Ignore income taxes.

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The first ten terms of the sequence [tex]a_n=1 + (-\frac{4}{9} )^n[/tex] is 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

[tex]a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\[/tex]

[tex]When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\[/tex]

The first ten terms of the sequence [tex]a_n=1 + (-\frac{4}{9} )^n[/tex] is 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003

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Answer:

f(x) = x^(1/2) + 3

Step-by-step explanation:

Translating to the right 3 units would change these:

0^(1/2) = 0 /// 3 units to the right would be (0,3)

1^(1/2) = 1 //// 3 units to the right would be (1,4)

4^(1/2) = 2 //// 3 units to the right would be (4,5) etc

Answer: 30

Step-by-step explanation: Formula for Area of a triangle = 1/2 Base * Height. 12*5 = 60; 60/2 = 30.

Answer:

30 cm squared

Step-by-step explanation:

This is a right angle triangle. That means that the base and height will just be the perpendicular sides of the triangle.

Our base in this case is 12 and our height is 5.

Area of a Triangle = 1/2(base)(height)

=1/2(12)(5)

=1/2(60)

=30

So, the area of this triangle is 30 cm squared.

Answer:

Like terms

Step-by-step explanation:

Both terms have the same unit, which is pounds.

The equations will be solved by putting the values of the variables in the bracket.

1. (b + a) = 4; use a = 1 and b = 3

( 1 + 3) = 4

2) c(b + b); use b = 1 and c = 5

5(1 + 1)

= 5 × 2 = 10

3) 4+ pm; use m = 4 and p =3

= 4 + (4 × 3)

= 4 + 12

= 16

4) 5+ pm; use m = 4 and p = 2

= 5 + (2 × 4)

= 5 + 8

= 13

5) m(p + 2); use m = 5 and p = 2

= 5(2 + 2)

= 5 × 4

= 20

6) h+j²; use h = 1 and j = 4

= 1 + 4²

= 17

7) y-(x - 5); use x = 5 and y = 6

= 6 - (5 - 5)

= 6 - 0

= 6

8) 4xy; use x = 5 and y = 2

= 4 × 5 × 2

= 40

9) n(p + 3); use n = 2 and p = 2

= 2(2 + 3)

= 10

10) y +x+x; use x = 3 and y=5

= 5 + 3 + 3

= 11

11) 6+ a-b; use a = 4 and b = 4

= 6 + 4 - 4

= 6

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The volume of the square prism shown is 1568 cubic meters

The formula for calculating the volume of square prism is expressed as;

V = Base area * height/3

Determine the base are

B = 14 * 14

B = 196 square meters

Determine the height

h = √25² - 7²

h = √625 - 49
h = 24m

Substitute

Volume = 196. * 24/3

Volume = 196 * 8

Volume = 1568 cubic meters

Hence the volume of the square prism shown is 1568 cubic meters

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