Calculate your % yield of CO2 in the reaction based on the grams of NaHCO3 being the limiting reagent in the reaction. .7656g NaHCO3 for Theoretical yield

Answers

Answer 1

The percent yield of CO₂ in the reaction based on the grams of NaHCO₃ is 93.3%.

Percent yield is use to assess the efficiency of a chemical reaction.    

To calculate percent yield is:                                                                

Percent yield = (Actual yield / Theoretical yield) × 100

Where,

Actual yield is the amount of product obtained from the reaction.

Theoretical yield is the maximum amount of product that could be obtained based on limiting reagent.

The equation of the reaction:

NaHCO₃  + CH₃ COOH ->CH₃ COONa +H₂O + CO₂

Moles of NaHCO₃ = 2.01/84 = 0.0239 moles

Theoretical yield of CO₂ = 0.0239 moles * 22.4 L/moles = 0.53536 = 0.536 L

Actual yield = 0.5 L

Percent yield = 0.50/0.536 * 100

= 93.3 %

Therefore, the percent yield is 93.3 %.

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The complete question is:

Calculate your % yield of CO₂ in the reaction based on the grams of NaHCO₃ being the limiting reagent in the reaction between 2.01 g of sodium bicarbonate and 24.6 mL of 1.5 acetic acid? They produce 0.50 L of at s.t.p.


Related Questions

Balancing chemical equation
_CoBr3 + _CaSO4 -> _CaBr2 + _Co2 (SO4)2
- solution please

Answers

Answer:

2 CoBr3 + 3 CaSO4 = 3 CaBr2 + Co2(SO4)2

Explanation:

An electron is a positively charged particle inside of an atom, just like the proton.



True
False

Answers

Answer:

no it's is false because an electron have negative charges and it is not inside the atom and it is found out side the nucleus

false bc the electrons are negative not positive & electrons is found outside the nucleus

a sample of an unknown gas is placed in a vessel with a volume of 4,372 ml at a temperature of 32.3 °c. if the pressure is 5.7 atm, how many moles of gas are present?

Answers

There are 0.893 moles of gas present in the sample.

The ideal gas law is PV = nRT, which expresses the relationship between the pressure, volume, temperature, and amount of gas present. We can use this equation to find the number of moles of gas present in a sample. Here's how: PV = nRTn = PV / RT, where P is the pressure in atm, V is the volume in litres, T is the temperature in Kelvin, R is the universal gas constant (0.0821 L atm/mol K), and n is the number of moles of gas. Let's convert the volume to litres and the temperature to Kelvin. 4,372 ml = 4.372 L, and 32.3 °C + 273.15 = 305.45 K. Now we can plug in the values: n = (5.7 atm) (4.372 L) / (0.0821 L atm/mol K) (305.45 K)n = 0.893 mol.

Therefore, there are 0.893 moles of gas present in the sample.

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a polymer with which type of tacticity is expected to exhibit the lowest degree of crystallinity? atactic isotactic syndiotactic

Answers

A polymer which is expected to exhibit the lowest degree of crystallinity is an atactic tacticity (Option A).

What is tacticity?

Tacticity is the configuration or spatial arrangement of monomer units in a polymer chain with respect to each other. It defines the regularity of the orientation of the pendant groups that are attached to the main chain of the polymer. Tacticity is a critical element that determines the physical and chemical properties of the polymer.

The three types of tacticities are atactic, isotactic, and syndiotactic. Atactic polymers have no specific tacticity because their pendant groups are randomly arranged with respect to each other. Since atactic polymers lack long-range order, they have the lowest degree of crystallinity.

Isotactic polymer have all of their pendant groups arranged in the same orientation, with respect to the main chain. As a result, these polymers have a high degree of crystallinity. Syndiotactic polymers have pendant groups that alternate in orientation along the main chain. The degree of crystallinity in syndiotactic polymers is moderate.

The degree of crystallinity for each type of polymer depends on the extent to which their pendant groups align, which affects their chain packing and orientation in the solid-state.

Thus, the correct option is A.

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One tank of gold fish is fed the normal amount of food once a day. A second tank is fed twice a day. A third tank is fed four times a day during a six week study. The fish's weight is recorded daily. What is the problem and the hypothesis?

Answers

Answer:

Problem: What is the effect of the amount of fish feed on the mass of goldfish?

Hypothesis: I think that feeding the goldfish four times a day will greatest increase in the mass of the goldfish.

Explanation:

The problem tends to ask question to which the research is conducted. It open ways for ideas towards a particular topic.

While the hypothesis is a tentative or assumed stand on a subject. It is further tested through an experiment or survey and if after many trials it gives same results and the obtained results is concordant with the hypothesis, the hypothesis will then become accepted and a theory or law is formed thereafter.

in a balanced exothermic reation, where does a heat term appear?

Answers

In a balanced exothermic reaction, the heat term appears on the product side of the chemical equation.

In a balanced chemical equation, the reactants and products are represented using chemical formulas and coefficients. The heat term, which represents the heat released or absorbed during the reaction, is often included as a separate term in the equation.

For an exothermic reaction, which releases heat to the surroundings, the heat term appears on the product side of the equation. It is typically denoted as a positive value since it represents the heat being released. The heat term is often written as "ΔH" or "heat" and may be accompanied by the corresponding value indicating the heat change.

The inclusion of the heat term allows us to account for the energy changes that occur during a chemical reaction. It provides information about the heat flow associated with the reaction and helps in understanding the thermodynamics of the process.

Therefore, in a balanced exothermic reaction, the heat term appears on the product side to indicate the heat being released.

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Were any paint chip cards missing from your set? How did you determine they were or were not missing? How would you describe the missing cards to someone?

Answers

Answer:

A continuous color sequence is a pattern that can be used to determine if paint chips are missing from the set. If the color change from chip to chip is not continuous, a chip is probably missing. This pattern is useful to display paint chips for customers.

How much heat will be produced when 0.58 moles of
hydrogen peroxide (H2O2) decomposes? *
98 kJ + 2H,02(1) → 2H2O(l) + O2(g)

Answers

Answer:57.6 kJ

Explanation:

Write a balanced equation from each line notation: a. (2 pts) Ag(s) Ag+(aq) || Cd2+(aq) Cd(s) b. (2 pts) Pb(s) Pb2+(aq) || MnO2(aq) | Mn2+(aq) | Pt(s)

Answers

a. The balanced equation from the line notation Ag(s) Ag+(aq) || Cd2+(aq) Cd(s) is given below;Ag(s) + Cd2+(aq) → Ag+(aq) + Cd(s)The given line notation represents an electrochemical cell where two half-cells are separated by a salt bridge.

The anode half-cell is on the left side of the double vertical line notation while the cathode half-cell is on the right side of the double vertical line notation. In the anode, oxidation takes place, and the electrode is considered negative, whereas in the cathode, reduction takes place, and the electrode is considered positive.b. The balanced equation from the line notation Pb(s) Pb2+(aq) || MnO2(aq) | Mn2+(aq) | Pt(s) is given below;Pb(s) + MnO2(s) + 4 H+(aq) → Pb2+(aq) + Mn2+(aq) + 2 H2O(l)The given line notation represents an electrochemical cell where two half-cells are separated by a salt bridge. The anode half-cell is on the left side of the double vertical line notation while the cathode half-cell is on the right side of the double vertical line notation. In the anode, oxidation takes place, and the electrode is considered negative, whereas in the cathode, reduction takes place, and the electrode is considered positive.

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consider the energy diagram for an exothermic reaction. what would you expect for the reverse reaction? a) to be exothermic and require the same activation energy b) to be endothermic and require the same activation energy c) to be endothermic and require a higher activation energy d) to be endothermic and require a lower activation energy e) to be exothermic and require a lower activation energy

Answers

Considering the energy diagram for an exothermic reaction, the expectations for the reverse reaction is: (c) The reverse reaction would be endothermic and require a higher activation energy.

In an exothermic reaction, the products have lower energy than the reactants, resulting in the release of energy. The energy diagram for an exothermic reaction typically shows a downward slope from the reactants to the products, with the energy of the products being lower than the energy of the reactants.

When considering the reverse reaction of an exothermic reaction, it would involve the conversion of products back into reactants. Since the energy diagram for the forward reaction shows a decrease in energy from reactants to products, the reverse reaction would be expected to have an increase in energy from products to reactants.

In the reverse reaction, energy would need to be absorbed from the surroundings, making it an endothermic process. Additionally, the activation energy for the reverse reaction is expected to be higher because the reverse reaction has to overcome a higher energy barrier to convert the products back into the reactants.

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an substance that is being dissolved by another object?​

Answers

Answer:

Solute - The solute is the substance that is being dissolved by another substance. In the example above, the salt is the solute. Solvent - The solvent is the substance that dissolves the other substance.

Explanation:

A sample of milk is found to have arsenic at a concentration of 3.57 ug/L. What is the concentration in ounces per gallon? 1 qt 946.4 mL 1 gal 4 qt 16 oz- 1 lb 1 lb- 0.4536 kg A) 2.68 x 103 oz/gal B) 4.77 x 10-7 oz/gal C) 2.46 ozlgal D) 3.84 x 104 oz/gal E) 3.32 x 108 oz/gal

Answers

The concentration of arsenic in milk, which is 3.57 μg/L, can be converted to ounces per gallon. The correct answer is option D) 3.84 x 10^4 oz/gal.

To convert the concentration of arsenic from micrograms per liter (μg/L) to ounces per gallon (oz/gal), we need to follow a series of conversion steps. First, we need to convert micrograms (μg) to grams (g). There are 1,000 micrograms in a milligram (mg) and 1,000 milligrams in a gram, so 3.57 μg is equivalent to 0.00357 mg. Next, we need to convert milliliters (mL) to gallons (gal). Since 1 liter (L) is equal to 1,000 milliliters (mL) and 1 gallon is approximately 3,785.41 milliliters, we can calculate that 946.4 mL is approximately 0.25 gallons. Now, we can calculate the concentration in ounces per gallon. One pound (lb) is equal to 16 ounces (oz), and we know that 1 lb is approximately 0.4536 kg. Since 1 gallon is equal to 4 quarts (qt), and 1 quart is equal to 32 ounces, we can multiply all the conversion factors together:

0.00357 mg/L * 0.25 gal * 16 oz/lb * (1 lb/0.4536 kg) = 3.84 x 10^4 oz/gal

Therefore, the concentration of arsenic in ounces per gallon is approximately 3.84 x 10^4 oz/gal, which corresponds to option D).

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If there are 27 grams of nitrogen dioxide at STP how many liters does this occupy?

Answers

Answer:

30 liters

Explanation:

Complete and balance the following half-reaction in acidic solution
Sn²+(aq) → Sn** (aq)

Answers

The complete and balanced half-reaction for [tex]Sn^{2+}[/tex] → Sn** in the acidic solution can be given as follows: [tex]Sn^{2+}[/tex](aq) → [tex]Sn^{4+}[/tex](aq) + 2[tex]e^-[/tex] (oxidation half-reaction)

Here, [tex]Sn^{2+}[/tex] undergoes oxidation to [tex]Sn^{4+}[/tex]. In this reaction, the oxidation state of Sn changes from +2 to +4. It means Sn loses 2 electrons in this reaction. Hence, it is an oxidation half-reaction.

2[tex]H^+[/tex](aq) + 2e- → [tex]H_2[/tex](g) (reduction half-reaction)

This half-reaction represents the reduction of [tex]H^+[/tex] ions. In this reaction, [tex]H^+[/tex] ions gain 2 electrons to form [tex]H_2[/tex]. This reaction occurs in an acidic solution.

Therefore, to obtain a completely balanced reaction, we have to combine both half-reactions as follows:

[tex]Sn^{2+}[/tex](aq) + 2[tex]H^+[/tex](aq) → [tex]Sn^{4+}[/tex](aq) + [tex]H_2[/tex](g)

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Brainliest and a free hug :) thank you!!
The mass in a chemical reaction is found in
the energy produced by the reaction
the explosion produced by the chemical reaction
the atoms involved in the chemical reaction
the bonds involved in the chemical reaction

Answers

Answer:atoms involved in reaction. Mass remains same in reaction

Explanation: hug would be fine!

consider a hydrogen atom in the ground state. what is the energy of its electron? = j now consider an excited‑state hydrogen atom. what is the energy of the electron in the =5 level?

Answers

The energy of an electron in a hydrogen atom can be determined based on its quantum state. In the ground state, the energy of the electron is -13.6 eV.

In a hydrogen atom, the energy of the electron is quantized, meaning it can only exist in certain discrete energy levels. The ground state is the lowest energy level, where the electron resides when it is not excited. The energy of the electron in the ground state is a well-known constant value of -13.6 eV.

When the hydrogen atom is excited to an excited state, such as the n=5 level, the energy of the electron in that level can be determined using the formula E = -13.6 eV/n^2. Here, n represents the principal quantum number, which corresponds to the energy level. Plugging in n=5 into the formula, we find that the energy of the electron in the n=5 level is -13.6 eV/5^2 = -0.544 eV.

In summary, the energy of an electron in a hydrogen atom depends on its quantum state. The ground state has an energy of -13.6 eV, while an excited state, such as the n=5 level, can be calculated using the formula E = -13.6 eV/n^2. For the n=5 level, the energy of the electron is -0.544 eV.

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Is riding the bus or riding a bike a quicker way to get to school?

Answers

maybe riding a bike???
Definitely a bus not a bicycle

Which of the following contains an element in a +1 oxidation state?CO2, PbO2, CaO, N2O5, Cu2O

Answers

The element Cu₂O (copper(I) oxide) contains a +1 oxidation state. Option E is correct.

This is because oxygen (O) typically has a -2 oxidation state, and since there are two oxygen atoms in Cu₂O, their combined oxidation state is -4. Therefore, in order for the compound to be electrically neutral, the oxidation state of copper must be +1.

CO₂ (carbon dioxide) contains carbon (C) in a +4 oxidation state and oxygen (O) in a -2 oxidation state.

PbO₂ (lead(IV) oxide) contains lead (Pb) in a +4 oxidation state and oxygen (O) in a -2 oxidation state.

CaO (calcium oxide) contains calcium (Ca) in a +2 oxidation state and oxygen (O) in a -2 oxidation state.

N₂O₅ (dinitrogen pentoxide) contains nitrogen (N) in a +5 oxidation state and oxygen (O) in a -2 oxidation state.

Hence, E. is the correct option.

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--The given question is incomplete, the complete question is

"Which of the following contains an element in a +1 oxidation state? A) CO₂, B) PbO₂, C) CaO, D) N₂O₅, E) Cu₂O

What mass Na2CO3 will completely react with 150 mL of 0.15 M HNO3?
a) write the balanced equation
b) construct the pathway of how you would approach the problem.
c) write out the calculation
d) calculate

Answers

a) Balanced equation:

2Na2CO3 + 2HNO3 -> 2NaNO3 + H2O + CO2

b) Pathway:

To determine the mass of Na2CO3 required to react with 150 mL of 0.15 M HNO3, we need to follow these steps:

Write the balanced equation to determine the stoichiometry between Na2CO3 and HNO3.

Convert the volume of HNO3 to moles using its molarity.

Use the stoichiometry from the balanced equation to determine the moles of Na2CO3 required.

Convert the moles of Na2CO3 to grams using its molar mass.

c) Calculation:

Given:

Volume of HNO3 = 150 mL = 0.150 L

Molarity of HNO3 = 0.15 M

Step 1: Balanced equation:

2Na2CO3 + 2HNO3 -> 2NaNO3 + H2O + CO2

Step 2: Convert volume of HNO3 to moles:

Moles of HNO3 = Volume (L) × Molarity

= 0.150 L × 0.15 M

= 0.0225 moles of HNO3

Step 3: Use stoichiometry to find moles of Na2CO3:

From the balanced equation, we can see that 2 moles of Na2CO3 react with 2 moles of HNO3.

Therefore, the moles of Na2CO3 required = 0.0225 moles of HNO3

Step 4: Convert moles of Na2CO3 to grams:

Molar mass of Na2CO3 = (2 × atomic mass of Na) + atomic mass of C + (3 × atomic mass of O)

= (2 × 22.99 g/mol) + 12.01 g/mol + (3 × 16.00 g/mol)

= 105.99 g/mol

Mass of Na2CO3 = Moles × Molar mass

= 0.0225 moles × 105.99 g/mol

= 2.384 g

d) Calculation:

The mass of Na2CO3 required to completely react with 150 mL of 0.15 M HNO3 is 2.384 grams.

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TRUE OR FALSE
“Acids are electrolytes”

Answers

Answer:

True mark brainlest

Explanation:

true hope this helped

What is the number of particles after gluecose is mixed with water

Answers

Answer: dissolves

Explanation:

When you stir a spoonful of sugar into a glass of water, you are forming a solution. This type of liquid solution is composed of a solid solute, which is the sugar, and a liquid solvent, which is the water. As the sugar molecules spread evenly throughout the water, the sugar dissolves.

Balanced Equations and Reaction Types. Write balanced, net ionic equations for each of the five reactions and, using the scheme outlined in the introduction, indicate the reaction type for each: redox, acid/base, or precipitation. Part 1: Cu(s) + 4 HNO_3(aq) rightarrow Cu(NO_3)_2(aq) + 2 NO_2(g) + 2 H_2O(l) Part 2: Cu(NO_3)_2(aq) + 2NaOH(aq) rightarrow Cu(OH)_2(s) + 2NaNO_3(aq) Part 3: Cu(OH)_2(s) rightarrow CuO(s) + H_2O(l) Part 4: CuO(s) + H_2SO_4(aq) rightarrow CuSO_4(aq) + H_2O(l) Part 5: Zn(.s) + CuSO_4(aq) rightarrow Cu(s) + ZnSO_4(aq)

Answers

Part 1: Cu(s) + 4 HNO₃(aq) ⇒ Cu(NO₃)2(aq) + 2 NO₂(g) + 2 H₂O(l) is a redοx reactiοn

Hοw dο yοu cοnstruct a reactiοn-specific balanced equatiοn?

The reactants and prοducts are placed οn the left and right sides οf the arrοw, respectively, tο create a balanced equatiοn. Cοefficients, which appear as a number befοre a chemical fοrmula, represent mοles οf a cοmpοund. The number οf atοms in a single mοlecule is indicated by the subscripts (numbers belοw an atοm).

When catiοns and aniοns in an aqueοus sοlutiοn react tο generate a precipitate, an insοluble iοnic sοlid, precipitatiοn prοcesses take place. The sοlubility principles fοr typical iοnic sοlids can be used tο determine whether οr nοt such a reactiοn takes place.

Part 2: Cu(NO₃)₂(aq) + 2NaOH(aq) ⇒ Cu(OH)2(s) + 2NaNO₃(aq) is a dοuble displacement reactiοn οr a precipitatiοn reactiοn.

Part 3: Cu(OH)₂ (s) ⇒ CuO(s) + H₂O(l)  is a Decοmpοsitiοn reactiοn

Part 4: CuO(s) + H₂SO₄(aq) ⇒ CuSO₄(aq) + H₂O(l)  is an acid-base neutralizatiοn reactiοn.

Part 5: Zn(.s) + CuSO₄(aq) ⇒ Cu(s) + ZnSO₄(aq) is a displacement reactiοn

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seaborgium mass number =

Answers

Explanation:

seaborgium Is a type of corn that is grown in warm countries.

answer is SG

Answer:

269 u

Explanation:

What is the formula mass of the fictitious compound: AB2?

Answers

For a molecule AB2, 3.5g of A represents one molar fraction, and 8.00g B represents 2 molar fractions (or 4.0+4.0). Therefore, a direct ratio can be given as 3.5:4.0, or 1:1.14. This means a molecule AnBm will give a mass ratio for A:B of n:1.14xm

For a molecule AB, for every 1g of A, you will have 1.14g of B.

For a molecule AB2, for every 1g of A, you will have 2.28g of B.

For a molecule A2B3, for every 1g of A, you will have (1.14x3/2) 1.71g of B.

What is Chemical bond ?

Answers

Answer:

Chemical bonding, any of the interactions that account for the association of atoms into molecules, ions, crystals, and other stable species that make up the familiar substances of the everyday world.

Explanation:

Have a nice day:)

Answer: A connection between two surfaces or objects that have been joined together, especially by means of an adhesive substance, heat, or pressure.

Explanation: The bond may result from the electrostatic force or attraction between oppositely charged icons as in iconic bonds or through the sharing of electrons as in covalent bonds.

Determine the pH, pOH, [H+], and [OH−] of a solution in which 0.300 g of aluminum hydroxide is dissolved in 184 mL of solution.

Answers

Answer:

[OH⁻] = 0.0627M

pOH = 1.20

pH = 12.8

[H⁺] = 1.59x10⁻¹³M

Explanation:

To solve this question we must, as first, find the molarity of Al(OH)₃ in the solution -Molar mass Al(OH)₃: 78.00g/mol-:

0.300g * (1mol/ 78.00g) = 3.846x10⁻³ moles

In 184mL = 0.184L:

3.846x10⁻³ moles / 0.184L = 0.0209M Al(OH)₃. Three times this molarity = [OH⁻]:

[OH⁻] = 0.0209M * 3

[OH⁻] = 0.0627M

pOH = -log [OH⁻] =

pOH = 1.20

pH = 14 - pOH

pH = 12.8

And [H⁺] = 10^-pH

[H⁺] = 1.59x10⁻¹³M

why is the molar specific heat of a gas at constant pressure larger than the molar specific heat at constant volume?
Match the words in the left column to the appropriate blanks in the sentences on the right. options: on done by isochoric isobaric
volume pressure According to the first law of thermodynamics, the heat transferred to the gas equals the sum of the change in thermal energy and the work________ the gas. During an _______ process the work is zero. In process with a constant _________ with increasing temperature some energy leaves the system as work.

Answers

The heat transferred to the gas equals the total of the change in thermal energy and the work done on the gas, according to the first law of thermodynamics. During an isochoric process the work is zero. In process with a constant pressure with increasing temperature some energy leaves the system as work.

The heat provided to a gas (Q) equals the change in thermal energy (U) plus the work performed by the gas (W), as stated by the first law of thermodynamics. During an isochoric (constant volume) process, the work done by the gas is zero (W = 0) because there is no change in volume. In this case, all the heat energy transferred to the gas increases its thermal energy, resulting in a larger temperature increase and a larger molar specific heat at constant volume.

In a process with a constant pressure (isobaric), the gas can expand and do work against the external pressure. As the gas expands, it does work by pushing against the external pressure, and some of the heat energy is used to perform this work. Therefore, less heat energy is available to solely increase the thermal energy of the gas. This results in a smaller temperature increase compared to the constant volume process, leading to a smaller molar specific heat at constant pressure.

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For the reaction CH3 COOH → CH3 COO^- + H+, which statement is true?
O CH3 COO^- is a Brønsted-Lowry acid.
O CH3 COO^- is a conjugate base.
O CH3 COOH is a Brønsted-Lowry base.
O CH3 COO^- is an Arrhenius base.

Answers

In the given reaction CH3COOH → CH3COO^- + H+, the statement "CH3COO^- is a conjugate base" is true.The statement "CH3COO^- is a conjugate base" is true for the given reaction.

In the Brønsted-Lowry theory of acids and bases, an acid is a species that donates a proton (H+), while a base is a species that accepts a proton. In this reaction, CH3COOH donates a proton to form CH3COO^- and H+. The species that remains after the acid donates a proton is called the conjugate base.

In the reaction, CH3COOH acts as the acid by donating a proton, and CH3COO^- is the species that forms after the donation. Since CH3COO^- accepts the proton, it is considered the conjugate base of CH3COOH.

To determine whether a species is an acid or a base, we need to consider its behavior in a given reaction. In this case, CH3COOH donates a proton, making it the Brønsted-Lowry acid, while CH3COO^- accepts the proton, making it the conjugate base.

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A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?

Answers

Answer:

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

bittuly/3a8Nt8

Explanation:

According to molar concentration, molarity of the resulting solution is 4.32 molar.

What is molar concentration?

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Substitution in formula M₁V₁=M₂V₂ gives M₂=6.2×2/3=4.32 M.

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Would glucose be considered a natural resource of synthetic product?

Answers

Yes, glucose itself is considered a natural resource.
Other Questions
Of the following events, which is are likely to cause an increase in demand for coffee. You may select more than one answer The price of coffee decrease An increase in the price of tea O A hurricane destroys a large coffee bean farm O A new Harvard study shows that drinking coffee reduces the risk of heart disease 1. Does the insect have wings? a. Yes go to step 2 b. No. Order Hemiptera 2. Does the insect have parallel wings? (hint: Parallel wings dont stick out to the side) a. Yes go to step 3 b. No. go to step 4 3. Does the insect have a parallel line down the back that divides the wings? a. Yes Order Coleoptera b. No Order Orthoptera 4. Does the insect have 4 total wings? a. Yes go to step 5 b. No Order Diptera 5. Does the insect have long antennae? a. Yesgo to step 6 b. No Order Odonata 6. Does the insect have a small body with large fan shaped wings? a. Yes Order Lepidoptera b. NoOrder Hymenoptera Which two words are antonyms?1. strain,plague 2. remedy, recompense 3. Uncivil, beseech 4. Commended, slander how to inspire a Lifelong reader for kids A number than can be written as a ratioof two integers a and b, where b is notzero gases are really _______ and molecules are full of _______, bouncing around constantly Carrefour is one of the largest retailers in the U.A.E. They exert strong influence on the manufacturers that supply products to Carrefour to gain co-operation from the intermediaries. Which type of marketing system does this represent?a.Horizontal marketing systemb.Administered vertical marketing systemc.Corporate vertical marketing systemd.Contractual vertical marketing syste Generally speaking, atypical sexual behaviors are MORE frequently reported ina.males.b.females.c.men and women who have been in a long-term relationship.d.married couples. .Which of the following is NOT a purpose of Black cyberfeminism, as outlined by Kishonna Gray?a.interrogating structural inequality through interlocking forms of oppressionb.combining intellectualism with activismc.asserting power and superiority over White societyd.creating space for women of color to resist controlling images through self-definition b + -73 = -58help please Production costs chargeable to the Finishing Department in May at Kim Company are materials $7,700, labor $19,700, overhead $18,289, and transferred-in costs $66,801. Equivalent units of production are materials 20,300 and conversion costs 18,900. Kim uses the FIFO method to compute equivalent units. Compute the unit costs for materials and conversion costs. Transferred-in costs are considered materials costs. (Round answers to 2 decimal places, e.g. 2.25.) Materials cost per unit $ 5.54 Conversion cost per unit $ Question Completion Status: 2 3 D & Moving to another question will save this response points Kingdom Corporation has the following. - Preferred stock, $10 par value, 8%, 50.000 shares issued $500,000 You have an investment project with the following expected cash flows. Right now, it will cost you $ 130,000. You will net $ 20,000 in the first year, $ 40,000 in the second year, $ 50,000 in the third year, $ 50,000 in the fourth year, and $ 40,000 in the fifth year which is also the last year of the project. Your WACC is 11.5% and your pre tax cost of debt is 13%. The Pl is: _ How can the next term in the infinite sequence 1, 5, 12, 22, 35, ... be generated? A. Square the term number, subtract the tem number from the result, multiply by 3, and divide the result by 2. B. Square the term number, multiply the result by 3. divide by 2, and subtract the term number from the result. C. Square the term number, divide the result by 2 subtract the term number, and multiply the result by 3. D. Square the term number, multiply the result by 3 subtract the tem number, and divide the result by 2. warning number 777777777777777777777777777777 factor the trinomial 16x2 + 14x + 3 Bias can be defined as a blank something that benefits you were others unequally Marginal and average tax rates Partner A, a single taxpayer, is one of two partners in a small business. As such, she receives pass-through income that is taxed at her personal tax rates. After all adjustments and deductions have been made, including the 20% qualified business income deduction, she is preparing to calculate her taxes owed for the year. Using the tax rate schedule given here , perform the following: a. Calculate the tax liability, after-tax earnings, and average tax rates for the following levels of partnership earnings before taxes: $14,400; $80,500; $303,000; $495,000; $1.1 million; $1.6 million; and $1.8 million. b. Plot the average tax rates (measured on the y-axis) against the pretax income levels (measured on the x-axis). What generalization can be made concerning the relationship between these variables? More info 303,000; Tax Rates-Single Taxpayers-2018 . + + + + Range of taxable income $0 to $9,525 9,525 to 38,700 38,700 to 82,500 82,500 to 157,500 157,500 to 200,000 200,000 to 500,000 Over 500,000 Base tax $0 953 4,454 14,090 32,090 45,690 150,690 (10% (12% (22% (24% (32% (35% (37% Tax calculation (Marginal rate x amount over base bracket) x amount over $0) x amount over 9,525) x amount over 38,700) x amount over 82,500) x amount over 157,500) x amount over 200,000) x amount over 500,000) An investor invests in two portfolios (A & B) and does not add funds or remove funds from either portfolio for one year. The return over that time period of Portfolio A is 17.3% and of Portfolio B is 3.2%. The investor initially allocated 70% of capital to Portfolio A and 30% to Portfolio B. What is the investor's weighted average return? (Answers in decimal format) Cardiorespiratory fitness is widely recognized as a major component of overall physical well-being. Direct measurement of maximal oxygen uptake (VO2max) is the single best measure of such fitness, but direct measurement is time-consuming and expensive. It is therefore desirable to have a prediction equation for VO2max in terms of easily obtained quantities. Consider the following variables.y = VO2max (L/min)x1 = weight (kg)x2 = age (yr)x3 = time necessary to walk 1 mile (min)x4 = heart rate at the end of the walk (beats/min)Here is one possible model for male students, consistent with the information given in the article "Validation of the Rockport Fitness Walking Test in College Males and Females."Y = 5.0 + 0.01x1 0.05x2 0.13x3 0.01x4 + = 0.4(a) Interpret 1.A. Holding all other variables constant, a 1 kg increase in weight will result in a 0.01 L/min increase in VO2max.B. Holding all other variables constant, a 1 kg increase in weight will result in a 0.01 L/min decrease in VO2max. C. Holding all other variables constant, a 0.01 kg increase in weight will result in a 1 L/min increase in VO2max. D. Holding all other variables constant, a 0.01 kg increase in weight will result in a 1 L/min decrease in vo2max. Interpret 3 D. Holding all other variables constant, a 0.13 min increase in walk time will result in a 1 L/min decrease in VO2max Interpret 3A. Holding all other variables constant, a 0.13 min increase in walk time will result in a 1 L/min decrease in VO2max.B. Holding all other variables constant, a 1 min increase in walk time will result in a 0.13 L/min decrease in vo2max. C. Holding all other variables constant, a 1 min increase in walk time will result in a 0.13 L/min increase in VO2max D. Holding all other variables constant, a 0.13 min increase in walk time will result in a 1 L/min increase in VO2max.(b) What is the expected value of VO2max when weight is 76 kg, age is 25 yr, walk time is 14 min, and heart rate is 138 b/m?L/min(c) What is the probability that VO2max will be between 0.59 and 2.03 for a single observation made when the values of the predictors are as stated in part (b)? (Round your answer to four decimal places.)