Calculate weight if an object, given its mass

Answer: C Adding salt to water increases the boiling point and decreases the freezing point

Explanation:

0.99 joule must the work done by friction to stop the box.

m=87g

k=82N/m

x=11cm=0.11m

spring force=kx

spring force=82N/m×0.11m

spring force=9.02 N

work done= Fx

work done=9.02 N×=0.11m

work done=0.99 joule

When an item is moved across a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work done in physics. By multiplying the length of the path by the component of the force operating along the path, work may be calculated if the force is constant. The work W is equal to the force f times the distance h, or W = mgh, to mathematically describe this idea. The work is W = mas if the force is applied at an angle of to the displacement.

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The PEN model is a biological theory of nature developed by influential psychologist Hans Eysenck (1916-1997). The model pivot on three broad personality factors: psychoticism, extraversion, and neuroticism (PEN).

In the PEN model, character comprises three major dimensions: extraversion, neuroticism, and psychoticism. These pictorial dimensions have Former developing the PEN model, Eysenck chase to quantify personality based on two sizes: extraversion-introversion. Before evolving the PEN model, Eysenck sought to measure nature in two sizes: extraversion-introversion and neuroticism-emotional. Eysenck's PEN theory has suggested an influential classification for the biological basis of personality dimensions: Psychoticism

So we can conclude that The PEN model contains three personality dimensions based on psychophysiology: Psychoticism, Extraversion, and Neuroticism.

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As per Drag theory , one possible explanation is v=0 that means velocity of earth relative to ether is zero.

For t1=t2, as per equation

[tex]t1=2l/c [ 1 + v^{2} /c^{2} ]\\t2= 2l/c [ 1 + v^{2} /2c^{2} ][/tex]

Then there is no relative velocity between earth and ether. In other words the ether is dragged with the motion of earth with the same velocity as the earth. However if this explanation is acceptable for there should be no aberration of light. Even if the ether is considered to be dragged partially , the absence of fringes shift and value of aberration cannot be explained simultaneously.

It has been verified by experiments that newton's frame of reference taking stars to be fixed , is an inertial one , while the other one i.e. reference frame fixed to earth  is not an inertial frame. Since the earth rotates about its axis as well as round the sun.

Even Galilean Transformation equations explain the structure of inertial frames.

For example - Length of a rod is invariant under Galilean transformations.

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vf = vi + at = 2 m/s + (4 m/s²) (2 s) = 10 m/s

It would take the star 2 seconds to lose all it's mass.

I got this by dividing 12.044×10⁴⁶ by  6.022×10²³

The work done by the elevator over the 55 meters is easily calculable: W = mgh = (2400)(9.8)(55) = 1293600Joules. The total time of the trip can be calculated from the velocity of the elevator: t = x/v=55/18.9 = 2.91. Thus the average power is given by: P =W/t=1293600/2.91=444536   Watts

Answer: Displacement between 0s and 6s = 2

Explanation:0+2=2

Formula connecting acceleration, initial speed, final speed and time.

v=u+at,

v2=u2+2as,

s=ut+1/2at2.

For motion on a straight line with constant acceleration, there are five common formulas. The formulas are provided in terms of the initial velocity (u), final velocity (v), displacement (x), acceleration (a), and time (t).

The following equation can be used to determine distance from acceleration: D = v*t + 1/2*a*t2. where an is the acceleration, t is the passage of time, and v is the velocity.

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Explanation:

1. Dimension formula of luminous flux matches with which of the following?

Force

Rotational impulse

Momentum

Power

Answer: d) Power

Answer:

35.2 AU

Explanation:

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

[tex]\boxed{T^2 \propto a^3 \implies T^2=ka^3}[/tex]

Kepler's Third Law

[tex]T^2=\dfrac{4 \pi^2}{GM}a^3[/tex]

where a is the semi-major axis of the ellipse.

If expressed in the following units:

then:

[tex]\implies\dfrac{4 \pi^2}{GM}=1[/tex]

Therefore Kepler's Third Law can be expressed as:

[tex]\boxed{T^2=a^3}[/tex]

Given:

From inspection of the given diagram:

[tex]\implies 2a=x+0.57[/tex]

[tex]\implies a=\dfrac{x+0.57}{2}[/tex]

Substitute these values into the equation and solve for x:

[tex]\implies (75.6)^2=\left(\dfrac{x+0.57}{2}\right)^3[/tex]

[tex]\implies (75.6)^\frac{2}{3}=\dfrac{x+0.57}{2}[/tex]

[tex]\implies 2(75.6)^\frac{2}{3}=x+0.57[/tex]

[tex]\implies x=2(75.6)^\frac{2}{3}-0.57[/tex]

[tex]\implies x=35.1883819...[/tex]

[tex]\implies x=35.2\; \text{AU}[/tex]

Answer:

A) 1000 kg

Explanation:

vf = vi + at

0 = 20 + (a)(10)

a = -2.0 m/s^2

F = ma

2000 = (m)(2)

m = 1000 kg

Answer:

The force of friction and air resistance slow down the movement of the bus.

c) A forse is changing the motion of the bus

The change in angular velocity for the object from t=1s to t=3s is most nearly  24 rad/s².

The change in the angular velocity of the object is the angular acceleration of the object and the magnitude is calculated as follows;

α = Δω/Δt

where;

α = at³ - w₂

α = d(at³ - w₂)/dt

α = 3at²

The given parameters;

α = 3(2)(2)²

α = 24 rad/s²

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(a) The speed of the student at the bottom of the hill is 15.34 m/s.

(b) The speed of the student at the presence of friction force is 11.88 m/s.

The speed of the student at the bottom of the hill is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy at the bottom hill = potential energy at maximum height

¹/₂mv² = mgh

where;

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

The speed of the student at the presence of friction force is calculated as;

Kinetic energy at the bottom hill + work done against friction  = potential energy at maximum height

¹/₂mv² + μmgh = mgh

¹/₂v² + μgh = gh

v²  +  2μgh = 2gh

v² = 2gh - 2μgh

v² = (2 x 9.8 x 12) - (2 x 0.4 x 9.8 x 12)

v² = 141.12

v = √141.12

v = 11.88 m/s

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1.125 joule work done does air resistance do on the ball

work done= kinetic energy= mΔv²/2

m=0.25kg

Δv=3 m/s

work done= mΔv²/2

work done=-0.25×9÷2

work done=-1.125 joule

When an item is moved across a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work done in physics. By multiplying the length of the path by the component of the force operating along the path, work may be calculated if the force is constant. The work W is equal to the force f times the distance h, or W = mgh, to mathematically describe this idea. The work is W = mas if the force is applied at an angle of to the displacement.

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Velocity is different from speed because it has both size and direction.

Velocity is a vector quantity that denotes the rate of change of position with respect to time, combining speed with a directional component.

On the other hand, speed is the magnitude of the velocity; the rate distance is traversed in a given time.

Speed is a scalar quantity meaning that is does not have direction while velocity is a vector quantity meaning that it posseses both magnitude (size) and direction.

Therefore, speed and velocity differs in the sense that the latter is a vector quantity.

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The force needed to pull the wrench of 30 cm long is 643.95 N.

Force can be defined as the product of mass and aceleration.

To calculate the force that must be pull, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Note: The negative sign tells the direction of the force and can be ignored (Pull)

Hence, the force need to pull is 643.95 N.

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The net work done on the block over the given distance is 39.4d (joules)

The net work done on the block over the given distance is calculated by applying the following equation as shown below:

W(net) = F(net) x d where;

F(net) = F - μmgcosθ where;

F(net) = 50 N - (0.25 x 5 x 9.8 x cos30)

NF(net) = 50 N - 10.6 NF(net) = 39.4 N

The net work done on the block over the given distance is calculated as: W = 39.4 N x dwhere;

d is the distance moved by the block = length of the incline

W = 39.4d (joules)

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Answer:

seismic waves

Explanation:

Answer: 12 ounce steak on venus

Explanation: venus = closer to the sun. The sun = more potential gravity, which would make it heavier than a quarter pound hamburger on jupiter.

Answer:

The Cascadia Subduction Zone has not produced an earthquake since 1700 and is building up pressure where the Juan de Fuca Plate is subsiding underneath the North American plate.

Explanation:

At depths shallower than 30 km (19 mi) or so, the Cascadia zone is locked by friction while stress slowly builds up as the subduction forces act, until the fault's frictional strength is exceeded and the rocks slip past each other along the fault in a megathrust earthquake. Below 30 km (19 mi) the plate interface exhibits episodic tremor and slip .

Answer:

1039 N

Explanation:

The 'x' components of their pulling forces = the force of friction:

2 x 600 cos 30 = 1039 N

Answer:

a. 1.1 m/s^2

Explanation:

Force of Application = (60)(cos30)

= 51.96 N

Force of Friction = 30 N

Total Force = 51.96 - 30

= 21.56 N

F = ma

21.56 = 20a

a = 1.09

a = 1.1 m/s^2

(a) The mechanical energy of the particle at the origin is 0 J.

(b) The mechanical energy of the particle at 4 m is 625 J.

(c)  The particle’s velocity at 1.0m is 17.32 m/s.

The mechanical energy of the particle is the total energy of the particle due to its motion and position above the ground such as kinetic energy and potential energy.

E = P.E + K.E

E = mgh + ¹/₂mv²

where;

at the origin, the displacement of the particle is zero and the velocity of the particle is zero.

E = (2 x 9.8 x 0) +  ¹/₂(2)(0)²

E = 0 J

The acceleration of the particle is calculated as follows;

F = ma

a = F/m

where;

a = (300)/2

a = 150 m/s²

The velocity of the particle at distance 4 m is calculated as follows;

v² = u² + 2as

where;

v² = (5)² + 2(150)(2)

v² = 625

v = √625

v = 25 m/s

E = ¹/₂mv²

E = ¹/₂(2)(25²)

E = 625 J

The particle's velocity at 1 m is calculated as follows;

Apply the principle of conservation of energy;

Work done by force = kinetic energy of the particle

Fd = ¹/₂mv²

where;

300 x 1 = ¹/₂(2)v²

300 = v²

v = √300

v = 17.32 m/s

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0.212 m/s²  is the average acceleration of the treadmill.

during this period

initial velocity, u = -1.2 m/s

time= 25 min

final velocity, v=  −6.5 m/s

acceleration = (v-u)÷ t

acceleration =5.3/25

acceleration =0.212 m/s²

The rate at which an item changes its velocity is known as acceleration, a vector variable. If an object's velocity is changing, it is accelerating. A moving object can occasionally alter its velocity by the same amount every second. a moving object that changes its speed by 10 m/s per second. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration. It is important to distinguish between an item with a constant acceleration and one with a constant velocity. Be not deceived! An object is accelerating if its velocity is changing, whether by a fixed amount or a variable quantity. Additionally, a moving item with a constant speed is not accelerating.

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Answer:

Charge q = 37.27 micro coulombs

Explanation:

Given:

q₁ = q₂ = q

r = 2.5 m

F = 2.0 N

________

q - ?

Coulomb's law:

F =k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²

Charge:

q = √ (F·r² / k)

q = √ (2·2.5² / (9·10⁹) ≈ 37.27·10⁻⁹  C

or q = 37.27 micro coulombs

The correct answer is not 52, but !!! :))

Stars that have a mass greater than the 1.4 solar masses or the Chandrasekhar limit will not become white dwarfs.

The Chandrasekhar limit is the maximum mass that a stable white dwarf star can have. It was noted by E.C. Stoner and Willhelm Anderson in their works, and they gave it the name Subrahmanyan Chandrasekhar in honour of the Indian astronomer who made important, independent findings for enhancing calculation accuracy.

The limit was first disregarded by the scientific community since it would have supported the existence of black holes (technically unrealistic at this turn-off time). The white dwarf stars resist the gravitational collapse of the black hole due to the pressure of electron degeneration.

The Chandrasekhar limit is established at a mass where the gravitational field's self-attraction cannot be balanced by the pressure from electron decay.  The limit that has been established these days is 1.39 solar mass.

Hence, Stars that have a mass greater than the 1.39 solar masses or the Chandrasekhar limit will not become white dwarfs.

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According to the given statement = 14ms⁻¹ his speed just before he enters the water.

Potentially energy is a type of energy that depends on how various system elements interact with one another. A spring's potential energy rises when it is crushed or stretched. A steel ball has more potential energy when it is hoisted above the soil than how it was brought closer to it.

Since the decrease in kinetic energy equals the variation in g.p.e. out from peak of the dive to the time just before kate enters the water, we may say that.

mgh= 1/2mv²

This means that just before she enters the water, her speed is

v= √2gh

v= √2 *9.81 *10

v= √196

v= 14ms⁻¹.

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It takes a black hole an astonishingly long time to convert all of its mass into energy via Hawking radiation. A googol, or 10100 years, would be required for a supermassive black hole to completely vanish.

A black hole radiates, losing mass as it does so and beginning to release more radiation, which accelerates the evaporation of the black hole. It eventually contracts to a size close to the Planck mass, where its Schwarzschild radius and DeBroglie wavelength coincide.

Sagittarius A* 1087 years for Ton 618, the biggest black hole ever detected, and Sagittarius A* 1087 years for Sagittarius A* to evaporate from Hawking radiation It would take more than 10100 years for it to evaporate away (weighing a staggering 66 billion solar masses).

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