Calculate the molarity of 29.9 g of MgS in 911 mL of solution??

The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.

The molarity of 5% NaOH is 1.32 M

25 cc of NaOH neutralized 30cc of H₂SO₄ solution.

Equation of reaction is given below:

Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M

moles of H⁺ ions per mole of H₂SO₄ = 2

Normality of H₂SO₄ = 0.55 x 2 = 1.1 N

In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.

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If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 5.2 atm

V= 500 mL =0.5 L

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=?

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{45 g}{32}[/tex]

[tex]Moles = \frac{45 g}{32}[/tex]

Moles = 1.40625

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]1.40625= \frac{5.2 \;atm\; X \;0.5 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}[/tex]

T= 22.53167034 K= 22.53K

Hence, If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

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8.59 is the concentration of ethyl alcohol when 0.198 kg of ethyl alcohol.

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

Given data:

Volume of solution = 0.500 L

Given the mass of  [tex]C_2H_5OH[/tex]= 0.198 kg= 198g

Molar mass of [tex]C_2H_5OH[/tex] = 46.07 g/mol

Moles of [tex]C_2H_5OH[/tex] = 4.297807684

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{4.297807684}{0.500 L}[/tex]

Molality = 8.595615368 =8.59M

Hence,  8.59 is the concentration of ethyl alcohol when 0.198 kg of ethyl alcohol.

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In the given compound, 0.2 mole of C₂H₆O will contain 1.2 moles of hydrogen.

In the balanced chemical compound C₂H₆O, we can deduce the following;

1 mole of C₂H₆O contains 6 moles of hydrogen

0.2 mole of C₂H₆O = ?

= 0.2 x 6 moles = 1.2 moles of hydrogen

Thus, in the given compound, 0.2 mole of C₂H₆O will contain 1.2 moles of hydrogen.

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Moles of ammonia

1mol requires 5.66KJ energy

13.5mol requires

3.4x10^4 = 34000

3.4×104 = 3.4 ×10000 = 34×1000=34000

In linguistics, ordinal integers or ordinal digit words are terms representing place or rank in sequential ordering; the order may be of a size, significance, record, and so on (e.g., "third", "tertiary").

They vary from cardinal digits, which mean quantity (e.g., "three") and other kinds of numerals.

Thus, 34000 is the answer.

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Answer:

Molar mass of substance = 40.0 g/mol

Explanation:

• First calculate the number of moles in 3.66 × 10²³ :

no. of moles = number of particles / Avogadro's Number

                     = (3.66 × 10²³)  /  (6.022 × 10²³)

                     = 0.6078 mol

• Now use the following equation to calculate the molar mass:

Molar mass = mass of substance / no. of moles

                   = 24.31 / 0.6078

                   = 40.0 g/mol

A change to the investigation which would remove the source of this error is to test a fourth group in which the people do not receive the mineral supplements.

This is the experimental techniques employed in science and involves hypothesis, observations etc.

Removing an error in a scientific method involves repeated experiments and using a large sample which is why the fourth group should be taken into consideration.

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Answer:

Explanation:

d because a b and c is in correct

The only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

A triangle can be defined as a one of the plane shapes which has three sides and three angles

So therefore, the only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

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The osmotic pressure of the 0.250 L solution made with 1.60 g of glucose, in water at 25.00°C is 0.869atm.

The osmotic pressure of the solution can be calculated using the following expression:

PV = nRT

where;

no of moles of glucose = 1.60g ÷ 180g/mol = 8.89 × 10-³mol

P × 0.250 = 0.00889 × 0.08206 × 298

0.25P = 0.217

P = 0.217/0.25

P = 0.869atm

Therefore, the osmotic pressure of the 0.250 L solution made with 1.60 g of glucose, in water at 25.00°C is 0.869atm.

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Answer:

A

Explanation:

bc u have to think about it

Answer:

organic compounds with triple bonds are alkynes

3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ([tex]C_3H_8[/tex]) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Stoichiometric calculations:

[tex]C_3H_8(g) + 5 O_2(g)[/tex]→ [tex]3 CO_2(g) + 4 H_2O(g)[/tex]

From the equation of the reaction, the mole ratio of propane to oxygen is 1:5.

Mole of 815.74 grams of propane = [tex]\frac{ 815.74}{44.1 }[/tex]

Mole of 815.74 grams of propane = 18.49750567 moles

Mole of  1,006.29 grams of oxygen =[tex]\frac{ 1,006.29}{32 }[/tex]

Mole of  1,006.29 grams of oxygen = 31.4465625 moles

Going by the mole ratio, it appears propane is limiting while oxygen is in excess.

From the equation, 1 mole of propane produces 4 moles of water vapour. Thus, the equivalent mole of water vapour will be:

18.49750567 moles x 4 = 73.99 moles.

Using the ideal gas equation:

PV = nRT

v = (73.99  x 0.08206 x 623) ÷ 0.96

v =  3940.2

Hence, 3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ([tex]C_3H_8[/tex]) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

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Answer:

117.4 kJ (to 4 sf)

Explanation:

(141.3)(0.831) = 117.4 kJ (to 4 sf)

Answer:

C

Explanation:

C .       specific heat =    J / gm-C

Answer: 0.680 mol

Explanation:

From the coefficients of the equation, we know that for every 3 moles of carbon dioxide produced, 5 moles of oxygen gas are consumed.

So, the answer is (5/3)(0.408) = 0.680 mol (to 3 sf)

Answer:

54.7 L

Explanation:

To find the volume, you need to use the Ideal Gas Law. The formula looks like this:

PV = nRT

In this formula,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.821 L*atm/mol*K)

-----> T = temperature (K)

You need to use the second R constant because the pressure is measured in atmospheres (atm) and not kPa. Because you have the all of the necessary variables except for volume, you can substitute them into the Ideal Gas Law formula and solve.

P = 1.54 atm                       R = 0.821 L*atm/mol*K

V = ? L                                T = 300 K

n = 0.342 moles

PV = nRT

(1.54 atm)V = (0.342 moles)(0.821 L*atm/mol*K)(300 K)

(1.54 atm)V = 84.2346

V = 54.7 L

4.743 x [tex]10^{-3}[/tex] s-1 is the value of the rate constant.

The Arrhenius equation describes the relationship between the rate of reaction and temperature for many physical and chemical reactions.

As per Arrhenius equation,

k = Ae-Ea÷RT

T = 227 = 500.15 K

R = 0.008314 kJ/K mol

Ea = 150 kJ/mol

Ea÷RT

= 150÷(0.008314 x 500.15)

= 36.073

k = Ae-36.073 = (2.2 x [tex]10^{13}[/tex] s-1) (2.156 x [tex]10-{16}[/tex])

k = 4.743 x [tex]10^{-3}[/tex] s-1

So, the correct answer is option d) i.e. 4.7 x [tex]10^{-3}[/tex] s-1

As per Arrhenius equation,

k = Ae-Ea/RT

T = 227 = 500.15 K

R = 0.008314 kJ/K mol

Ea = 150 kJ/mol

Ea÷RT = 150÷(0.008314 x 500.15) = 36.073

k = Ae-36.073 = (2.2 x [tex]10^{13}[/tex] s-1)(2.156 x [tex]10^{-16}[/tex])

k = 4.743 x [tex]10^{-3}[/tex] s-1

Hence,  4.743 x [tex]10^{-3}[/tex] s-1 is the value of the rate constant.

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Answer:

6.97 atm is the osmotic pressure.

5.7744 g is the mass of the methane gas.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]0.36 mol = \frac{mass}{16.04 g/mol}[/tex]

Mass =5.7744 g

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The type of nuclear decay in which Oxygen decays to form nitrogen is beta plus decay.

A beta plus decay is a type of decay in which a proton in an element disintegrates to produce a neutron resulting in a decrease in the atomic number of the radioactive element.

In the given equation below:

Oxygen decays to form nitrogen due to a decrease in atomic number.

This is an example of beta plus decay.

In conclusion, oxygen decays to form nitrogen beta plus decay.

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Neither attract much nor allows it be free.

How the molecules behave in such way?

Because fluorine has a higher electronegativity than carbon and hydrogen, CH3F possesses a non-zero dipole moment. As a result, fluorine draws a partial negative charge whereas other atoms (such as carbon or hydrogen) draw a partial positive charge, leading to a non-zero dipole moment in CH3F. Lewis' structure, CH3F, is made up of one carbon atom, three hydrogen atoms, and one fluorine atom. Carbon is the key atom in the CH3F lewis structure because it is the least electronegative. The CH3F lewis dot structure consists of 3 lone pairs and a total of 4 bound pairs.

Properties of CH3F

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Answer:

D

Explanation:

best choice, makes the most sense

In the scientific method, conducting an experiment involves designing and performing controlled experiments to test a hypothesis and the correct option is option B.

Scientists manipulate the independent variable while controlling other variables (dependent and controlled variables) to observe and measure the effect on the dependent variable.

By controlling variables, scientists can isolate the factors that influence the outcome, ensuring that any observed changes are a result of the manipulated variable and not other unrelated factors. This step allows for the collection of reliable data, which is essential for drawing meaningful conclusions based on the evidence gathered from the experiment.

Thus, the ideal selection is option B.

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From the calculations that have been done, there are 3 drinks.

The information that we have been provided here is very important. We can obtain the amount of alcohol by looking at the fact that it contains  80-proof liquor.

This 80-proof liquor. is an equivalent of 40% alcohol this means that there is 1.5 ounce of distilled spirit.

Thus, the number of drinks there is;

4.5/1.5 = 3

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Using Newton's second law, the car is experiencing a net force parallel to the banked curve such that

[tex]mg \sin(\theta) = \dfrac{mv^2}r \implies \sin(\theta) = \dfrac{v^2}{rg}[/tex]

where [tex]v[/tex] is the tangential speed of the car and [tex]r[/tex] is the radius of the curve. Solve for [tex]\theta[/tex] :

[tex]\sin(\theta) = \dfrac{\left(61.0\frac{\rm m}{\rm s}\right)^2}{(1860\,\mathrm m)g} \approx 0.204 \implies \theta = \sin^{-1}(0.204) \approx \boxed{11.8^\circ}[/tex]

We know that 1 kmol = 1000 mol, so 2.43 kmol = 2430 mol.

This means the formula mass of sulfur trioxide is

[tex]32.06+3(15.9994)=80.0582 \text{ g/mol}[/tex]

Therefore, the mass is

[tex](80.0582)(2430)=\boxed{1.95 \times 10^{5} \text{ g (to 3 sf)}}[/tex]

The final temperature of the mass of gold is  737 °C.

The specific heat capacity of gold is 0.126 J/g/K

The final temperature, T2 of the gold is calculated as follows:

T2 = T + Q/mc

where;

T is initial temperature, m is mass, and c is specific heat capacity of gold.

T2 = 27 + 2.3 x 1000/(25 x 0.126)

T2 = 737 °C

Therefore, the mass and heat capacity of gold determines its final temperature.

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Answer:

Explanation:

Formula

Heat = m * c * delta t

t = temperature in centigrade.

The first thing you have to do is convert kelvin degrees to centigrade. The conversion factor is - 273. The formula is degrees centigrade = degrees kelvin - 273. It is easier to understand with a couple of examples.

Solution

Heat = 100.0 grams * 4.18 J/g*C * (52 - 17)

Heat = 100 * 4.18 * 35

Heat = 14630 Joules

But you want kj

Heat = 14630 / 100 = 14.63

Answer

Heat = 14.6 kj