Calculate the mass of water produced by metabolism 84.0 g of glucose

Answers

Answer 1

The amount of water that will be produced is 50.36 grams

Stoichiometric problems

The metabolism of glucose is represented by the following equation:

[tex]C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)[/tex]

The mole ratio of glucose metabolized to the water produced is 1:6.

Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles

Equivalent mole of water = 0.4662 x 6 = 2.7975 moles

Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams

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Related Questions

kinetic energy is proportional to what

Answers

Answer:

mass and the square of the magnitude of velocity.

Explanation:

Which of the following molecules contains a polar covalent bond?
O A. Og
O B. N₂
O G. H₂
O D. CO

Answers

Answer:

CO contains polar covalent bond, because these atoms share unequal electrons.

Answer:

N₂

Explicacion:

Si la diferencia de electronegatividad es muy alta, por ejemplo entre un metal y un no metal, se forman enlaces iónicos

Which most likely describes results from their experiments? tristan and arya would exert more energy to overcome friction than anoush and keran. tristan and anoush would exert more energy to overcome friction than arya and keran. tristan and keran would exert less energy to overcome friction than arya and anoush. tristan and arya would exert less energy to overcome friction than anoush and keran.

Answers

The statement that most likely describes the results from their experiments is Tristan and Arya would exert more energy to overcome friction than Anoush and Keran. Thus, the correct option is A.

What is Friction?

Friction may be characterized as the force that counters the proximate motion between two surfaces of objects when they reach to contact.

According to the question, Tristan is working with static friction and Arya is working with sliding friction; static friction operates on things when they are catnapping on a surface, whereas sliding friction functions on objects when they are gliding over a surface.

Sliding friction is much more fragile and weaker than static friction and is comparatively uncomplicated and utilizes less energy to drag the objects.

The complete question is as follows:

Four students are doing different friction experiments with a cylinder.

Tristan is working with static friction,Arya is working with sliding friction,Anoush is working with rolling friction,Keran is working with fluid friction.

Therefore, the correct option for this question is A, i.e. Tristan and Arya would exert more energy to overcome friction than Anoush and Keran.

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Gamma-ray bursters emit pulses of gamma rays with high energies. The frequency of the most energetic pulses has been measured at around 3.0x10 21 hz. What is the wavelength of the gamma rays

Answers

The wavelength of these gamma rays will be  1x1[tex]10^{-13}[/tex] m.

How do you define wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometres, and other units since it is a distance measurement.

The relationship between the wave's wavelength, frequency, and speed is given as

wavelength = speed of light ÷ frequency

wavelength = [tex]\frac{3 X10^8}{3.0 X10^{21}}[/tex]

wavelength = 1x[tex]10^{-13}[/tex] m

Hence the wavelength of these gamma rays will be [tex]1 X 10^{-13}[/tex]m.

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The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is __________ atm.

Answers

Answer: 0.42 atm

Explanation:

For this problem, we are going to use the ideal gas law for pressure, which is [tex]P=\frac{nRT}{V}[/tex]. If you do not know yet, R is the ideal gas constant, [tex]0.0821\frac{L*atm}{mol*K}[/tex]First, we must find the number of CH₄ moles.

[tex]6.022gCH_{4} *\frac{1molCH_{4} }{16.043gCH_{4} } =0.38molCH_{4}[/tex]

Next, we will plug in our given information to the ideal gas law for pressure.

[tex]P=\frac{nRT}{V}[/tex]

[tex]P=\frac{0.38mol*0.0821\frac{L*atm}{mol*K} *402K}{30.0L} =0.42 atm[/tex]

The answer to this, according to the work done above, is 0.42 atm.

I hope this helps! Pls mark brainliest!! :)

The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is  0.413 atm.

How do we calculate the pressure of gas?

Pressure of gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = ?

V = volume of gas = 30L

R = universal gas constant = 0.082 L·atm·K⁻¹·mol⁻¹

T = temperature of gas = 402 K

n is moles of gas & it will be calculated as:

n = W/M, where

W = given mass of CH₄ = 6.022g

M = molar mass of CH₄ = 16g/mol

n = 6.022 / 16 = 0.376mol

Now putting all these values on the above equation, we get

P = (0.376)(0.082)(402) / (30)

P = 0.413 atm

Hence required pressure of methane gas is 0.413 atm.

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Is it possible to use subatomic particles as an energy source?

Answers

Yes, Is it possible to use subatomic particles as an energy source.

What are subatomic particles?

A subatomic particle is nothing but a particle which is smaller than an atom in size. Typically, an atom can be broken down into three subatomic particles, namely: protons, electrons, and neutrons.

Yes, Is it possible to use subatomic particles as an energy source.

There are instances when the protons and electrons in an atom's outermost shells are not strongly attracted to one another. It is possible to force these electrons out of their orbits.

They may move from one atom to another by exerting force. Electricity is made up of these moving electrons.

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What would be the mass in grams of 8.94 x 10 22 formula units of copper(II) fluoride, CuF 2

Answers

The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

Avogadro's hypothesis

6.02×10²³ formula units = 1 mole of CuF₂

But

1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

How to determine the mass of 8.94×10²² formula units of CuF₂

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

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Diamonds are composed of __________ in a ___________lattice. A. silicon, trigonal planar B. quartz, octahedral lattice C. carbon, tetrahedral D. diamond, trigonal bipyramid

Answers

Diamonds are composed of carbon in a tetrahedral lattice. That is option C.

What is a diamond?

A diamond of defined as an allotrope or one of the major forms of the element, carbon in nature.

These carbon atoms are arranged within the diamond in a face centered cubic tetrahedral lattice shape.

Therefore, Diamonds are composed of carbon in a tetrahedral lattice.

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Diamonds are composed of carbon in a tetrahedral lattice. The correct option is C.

What are diamonds?

Diamonds are one of the allotropes of carbon. The other allotrope of carbon is graphite.

Thus, diamonds are made up of carbon atoms that are tightly packed together. Each carbon atom in a diamond is strongly bonded to 4 other carbon atoms, resulting in the formation of a tetrahedral structure.

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Cellular Respiration is the process of what? A. Producing oxygen at the cellular level. B. The release of energy from food. C. Breathing. D. The creation of food, powered by the energy of the sun.

Answers

Cellular Respiration is the process of the release of energy from food. Hence, option B is correct.

What is cellular respiration?

Cellular respiration is the process by which organisms use oxygen to break down food molecules to get chemical energy for cell functions.

Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.

Hence, option B is correct.

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How many moles are in 213 mg of calcium fluoride, CaF2?


2.73 mols
0.00273 mols
16.6 mols
1.66 mols

Answers

Answer:

2.73

Explanation:

2.72815277835894

i used an online converter lol it is much faster. if you'd like a step by step guide comment and ill give you one :)

2.73 I think is the answer

Question 101 p
Simple syrup is the original, the most basic, and general one of the most common ways to add sweetness to a cocktail. You can choose from a range of suga
when making your simple syrup.
a White Sugar
Ob Splenda
De Raw Sugar
Od Brown Sugar

Answers

Answer:

splenda

Explanation:

Hechar azucar no es del todo una buena opcion ya que puede poducir caries

Hi please help, tysm. Answer is in nm

What is the wavelength of a photon if
the
energy is 7.41 x 10-19 J? (h= 6.626 x 10-34 J.
s)

Answers

Answer:

268 nm

Explanation:

The equation needed to find wavelength is:

E = hc / w

In this equation,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> c = speed of light (3.0 x 10⁸ m/s)

-----> w = wavelength (m)

To find the wavelength, you can plug the given values into the equation and simplify. Then, you can convert meters to nanometers.

E = hc / w

7.41 x 10⁻¹⁹ J = (6.626 x 10⁻³⁴ J*s)(3.0 x 10⁸ m/s) / w     <---- Input given values

7.41 x 10⁻¹⁹ J = 1.9878 x 10⁻²⁵ / w                                   <----- Simplify

(7.41 x 10⁻¹⁹ J) x w = 1.9878 x 10⁻²⁵                                <----- Rearrange

w = 2.68 x 10⁻⁷ m                                                          <----- Simplify

 2.68 x 10⁻⁷ m           1 x 10⁹ nm
----------------------  x  ----------------------  = 268 nm
                                         1 m

A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C. Use the chart to complete the multiple steps required to arrive at the final answer. Type in your answers below using 3 digits.
q1 = ___ kJ
q2 = ___ kJ
q3 = ___ kJ
qtot = ___ kJ

Answers

The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

Quantity heat required to convert the ice to liquid

The total quantity of heat required is calculated as follows;

q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)

q(tot) = mcΔθ₁  + mΔHf    +   mcΔθ₂

q(tot) = (100)(4.2)(0 - -45) + (334)(100)  + (100)(4.2)(75 - 0)

q(tot) = 18,900 J  +  33,400 J   +  31,500 J

q(tot) = 18.900 kJ  +  33.400 kJ   +  31.500 kJ

q(tot) = 83,800 J = 83.8 kJ

Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

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Answer:

q1 9.42

q2 226

q3 31.4

qtot 267

Explanation:

hope this help

For the decomposition of ammonia on a platinum surface at 856 °C
2 NH3(g)N2(g) + 3 H2(g)
the average rate of disappearance of NH3 over the time period from t = 0 s to t = 5.48×103 s is found to be 1.50×10-6 M s-1.

What is the average rate of appearance of H2 over the same time period?


M s-1.

Answers

[tex]\\ \tt\leadsto \dfrac{d[NH_3]}{dt}=1.50\times 10^{-6}[/tex]

dt remains same for reaction

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}\dfrac{d[NH_3]}{dt}[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}(1.5\times 10^{-6})[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=2.25\times 10^{-6}Ms^{-1}[/tex]

M is molarity here not metre

The average rate of appearance of H2 over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.

To find the average rate of appearance of [tex]\rm H_2[/tex], we can use the stoichiometry of the reaction to relate it to the rate of disappearance of [tex]\rm NH_3[/tex].

From the balanced equation: [tex]\rm 2NH_3(g) - > N_2(g) + 3 H_2(g)[/tex]

We can see that for every 2 moles of [tex]\rm NH_3[/tex] that disappear, 3 moles of [tex]\rm H_2[/tex] appear.

Given that the average rate of disappearance of [tex]\rm NH_3\ is\ 1.50\times10^{-6} M/s[/tex], we can calculate the average rate of appearance of [tex]\rm H_2[/tex] as follows:

Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x (Average rate of disappearance of [tex]\rm NH_3[/tex])

Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x [tex]\rm (1.50\times10^{-6} M/s)[/tex]

Average rate of appearance of [tex]\rm H_2[/tex] = [tex]\rm 2.25\times10^{-6} M/s[/tex]

Therefore, the average rate of appearance of [tex]\rm H_2[/tex] over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.

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Compare the shape of a chemical signalling molecule and a receptor.

Answers

Cell signalling is a process by which cells communicate with each other and transfer messages.

What is a receptor?

A molecule inside or on the surface of a cell binds to a specific substance and causes a specific effect in the cell.

Cell signalling is a process by which cells communicate with each other and transfer messages. When a signal molecule binds to a receptor protein, changes occur in the receptor proteins. Two changes are listed below:

1. The receptor protein undergoes conformational changes and acts as an enzyme.

2. The receptor protein that makes a second messenger molecule that leads the reaction further to other cells or molecules.

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Feedback
Consult a peer or a family member about ways your design could be improved. Describe the feedback and provide the name of the reviewer. These are only suggestions that you can use to plan for Design Two. Use complete sentences and detailed examples.
l need this answer first one to get it gets brainlist

Answers

Explanation:

We gujra weeeeeeeeeeeeeee

We gujra weeeeeeeeeeeeeee

We gujra weeeeeeeeeeeeeee

We gujra weeeeeeeeeeeeeee

Which of the following stars is a B class main sequence star?

Answers

The B class main sequence star from the given images is Star 3.

What are B class main sequence stars?

B class main-sequence stars are of spectral type B and luminosity class V. They are very luminous and blue with surface temperatures between 10,000 and 30,000 K.

The stars that are blue as shown in the image are Star 1 and Star 3. However, Star is the one that has surface temperature between 10,000 and 30,000 K.

Therefore, Star 3 is a B class main sequence star.

In conclusion, stars are luminous objects with very high surface temperatures.

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How does the study and understaning of the biological macromolecules impact your everday life?

Answers

The study and understanding of the biological macromolecules impact our everyday life by making us know what to eat and the different processes which occur in the body.

What are Biological macromolecules?

These are cellular components of the body which are natural and vital for the growth and survival of organisms.

Examples include carbohydrates, protein etc which contain nutrients vital for our daily life.

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Perform the following
mathematical operation, and
report the answer to the
correct number of significant
figures.
9.635 ÷ 12.9 = [?]

Answers

The answer is .747

What are significant figures?

There are 5 main rules to determining what are and what are not significant figures.

All non-zero digits are significant.If a decimal point is expressed, all zeros following non-zero digits are significant.If a decimal point is not explicitly expressed, zeros following the last non-zero digit are not significant.If a zero is bounded by non-zero digits, the zero is significant.Zeros preceding the first non-zero digit are not significant, they are placeholders only.

NOTE: In any measurement, the last digit is always assumed to be estimated.

How do I divide/multiply with significant figures?

The number of significant figures retained may not exceed the least number of digits in either of the factors. There will always be the same number of significant figures in the answer as the factor with the least amount of digits.

How do I apply that to this problem?

Given:

[tex]9.635 /12.9 =?[/tex]

In the given problem, the number with the least amount of digits is 12.9. As we recall from above, all non-zero numbers are significant, therefore all of these numbers are significant. Hence, we should have 3 significant figures in our final answer.

Now we use a calculator to simply calculate the above and we obtain:

[tex]0.7468992248[/tex]

We want to have 3 significant figures, so we will take the first 3 significant figures in that answer, .746, and use that. We apply rounding properties and obtain our final answer of .747.

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Question 1 of 25 Hydrogen gas can be produced using this equilibrium reaction. Which change would drive this process toward the product side? C + H₂O CO + H₂ + energy A. Removing the H₂O as it forms B. Increasing the temperature C. Removing the C as it forms D. Removing the CO as it forms SUBMIT​

Answers

What we need to do to drive the equilibrium to the products side is removing the CO as it forms.

What is the equilibrium position?

The equilibrium position is dependent in the conditions of the reaction. We know that the direction to which the equilibrium is shifted can be altered by manipulating the parameters of the reaction.

Now the reaction is; C + H₂O -----> CO + H₂ + energy. The case in point here is to drive the equilibrium position towards the products side.

What we need to do to drive the equilibrium to the products side is removing the CO as it forms.

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What is the equation for density?
O D= m
V
OD=V
m
OD=m
OD=mv²

Answers

Answer:

D = m/V

Explanation:

Density represents the following ratio:

Density (D) = mass (m) / volume (V)

In this formula, the volume is being divided from the mass. The typical units for mass is grams and the unit for volume is milliliters.


A plum with a mass of 35 g contains 30 Cal of nutritional energy. How many plums should a person consume to get
120 Cal of energy

Answers

35g —> 30cal
1cal —> 7/6g
120cal — 140g

Therefore, A person should eat 140gm of plums

If a Plum with a mass of 35 g contains 30 Cal of nutritional energy, then a  person should consume four plums to get 120 Cal of energy.

What is multiplication?

Finding the product of two or more numbers in mathematics is done by multiplying the numbers.

It is one of the fundamental operations in mathematics that we perform on a daily basis.

As given in the problem If a Plum with a mass of 35 g contains 30 Cal of nutritional energy, then we have to find out a person should consume how much plums to get 120 Cal of energy.

30 cal of nutritional energy = 1 plum

1 cal of nutritional energy = 1/30 plums

120 cal of nutritional energy = 120/30 plums

                                               = 4 plums

Thus,  a  person should consume four plums to get 120 Cal of energy.

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I NEED HELP! A rigid cylinder contains 3.00 liters of gas at a temperature of 25°C. If the pressure of this gas is changed from
0.500 atmospheres to 1.50 atmospheres, what will be the new temperature of the gas? (R= 0.0821 Latm/mol K)
O 612 °C
894 °C
99.3 °C
885 °C
O 75.0 °C

Answers

Gay Lussac's Law

P₁/T₁=P₂/T₂

25°C = 25+273 = 298 K

0.5/298 = 1.5/T₂

T₂ = 894 K = 621 °C

A gas law known as Gay-Lussac's law asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature. The new temperature is 612 °C and the correct option is A.

When the mass is fixed and the volume is constant, the pressure a gas exerts is proportional to the temperature of the gas. In the year 1808, French scientist Joseph Gay-Lussac created this law. Gay-Lussac's law can be expressed mathematically as follows:

P₁ / T₁ = P₂ / T₂

25°C = 25 + 273 = 298 K

0.5 / 298 = 1.5 / T₂

T₂ = 894 K

T₂ = 894-273

T₂  = 621 °C

Thus the correct option is A.

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How much heat will be absorbed by a 66.3 g
piece of aluminum (specific heat = 0.930 J/
g. °C) as it changes temperature from 23.0°C
to 67.0°C?

Answers

Q=mcΔt

Q=66.3 x 0.93 x (67-23)

Q=2712.996 J

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: Q = ms\Delta T[/tex]

[tex] \textsf{Q = heat evolved/absorbed = ??} [/tex]

[tex] \textsf{m = mass in gram = 66.3 g} [/tex]

[tex] \textsf{s = specific heat = 0.930 J/g °C} [/tex]

[tex] \textsf{ΔT = change in temp = 67 - 23 =44°C} [/tex]

[tex] \large\textsf{Find Q : } [/tex]

[tex]\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2713 \: \: joules[/tex]

[tex]\qquad \tt \rightarrow \:Q= 2.713 \: \: kj[/tex]

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Which of the following ions is formed when an acid is dissolved in a solution?
OH+
0-
OH-
OSO4²+

Answers

Answer:

The ion that is formed when an acid is dissolved in a solution is OH-.

Explanation:

An acid is a molecule that donates hydrogen ions, or protons, to another molecule. In solution, the acid dissociates, or breaks apart, to form hydrogen ions and the negatively-charged anion of the acid. The anion of a typical acid is the molecule minus the hydrogen ions, so it is OH- for hydrochloric acid, HCl.

A hurricane is a type of severe cyclone

Answers

A hurricane is a type of severe cyclone formed when winds rotate as the pressure between low and high-pressure areas increases.

What is a hurricane?

A cyclone is a violent storm that occurs when cyclone winds exceeds a speed of 74 miles (119 kilometers) per hour.

Hurricanes are classified according to their strength and catastrophic potential on a scale ranging from 1 to 5 (more violent).

In conclusion, a hurricane is a cyclone formed when a it rotates as the low and high-pressure areas increases.

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During quiet breathing, a person breathes in about
6 L of air per minute. If a person breathes in an
average of 6.814 L of air per minute, what volume
of air in liters does this person breathe in 1 day

Answers

Answer:

[tex]\huge\boxed{\sf 9812.16\ L\ of\ air}[/tex]

Explanation:

Given that,

A person breathes 6.814 L of air in a minute.

1 minute = 6.814 L

Minutes in a day:

= 1 × 24 × 60 (24 hours in a day; 60 minutes in an hour)

= 1440 minutes

Volume of air that person breathes in a day:

1 minute = 6.814 L of air

1440 minutes = 6.814 L × 1440

1 day = 9812.16 L of air

[tex]\rule[225]{225}{2}[/tex]

Please help with Question 4 :(

Answers

Answer:

cf4, ch20,vhjuyu8hc hi l bro tap

(GIVING BRANLYEST) John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Which of the following is the best way to explain why the clouds have formed? O The temperature of the air is below zero. O There is a low amount of moisture in the air. O The warm, wet air in a low pressure system has risen up and cooled down. O The wind is traveling at a slow speed.​

Answers

John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.

Hence, Option C is correct answer.

How are Clouds formed ?

Clouds are formed by the process of evaporation and which is followed by condensation. Clouds are small droplets of water crystallization which float in the air. When the moist air rises upwards then the formation of clouds take place because when air rises upwards it becomes colder.

Thus from the above conclusion we can ay that John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.

Hence, Option C is correct answer.

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Answer: Answer would be C I read the assignment and got it correct

Explanation:

How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution

Answers

The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

Balanced equation

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 1

How to determine the volume of Ca(OH)₂ Molarity of base, Ca(OH)₂ (Mb) = 1.48 MVolume of acid, HCl (Va) = 36 mL Molarity of acid, HCl (Ma) = 1.63 MVolume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

2.96 × Vb = 58.68

Divide both side by 2.96

Vb = 58.68 / 2.96

Vb = 19.8 mL

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