The energy required to ionize a hydrogen atom from the n = 3 energy level is 2.422 x 10 ⁻¹⁹J.
Explanation:The amount of energy required to remove an electron from an atom from its excited state to a ground state is referred to as the energy required for ionization.The energy of ionization is determined by two factors: the force of attraction between electrons and the nucleus. The repulsion force between electrons.Determine the number of electrons in the atom. Unless the atom has already lost some electrons, this number is the same as Z. Calculate the ionization energy of a one-electron atom in electron volts by squaring Z and then multiplying the result by 13.6.in the given question ,
The ionization energy can be expressed as follows:
E = 2.18 x 10 ⁻¹⁸ (1/n₁² - 1/∞²)
given , n = 3
E = 2.18 x 10 ⁻¹⁸ (1/3² - 1/∞²)
E = (2.18 x 10 ⁻¹⁸) / 9
E = 2.422 x 10 ⁻¹⁹
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What is the volume if 58.41g of o2 are pumped into a balloon that is at a pressure of 1183.mmHg and 151.4 degrees F?
The volume of the oxygen into a balloon is, V = 1.70 ml.
Equation :To calculate the volume of the oxygen using the formula
PV = nRT
where,
P is pressure
V is volume
n is number of moles
R is gas constant
T is temperature
So, the known values are :
P = 1183 mmHg
R = 8.314 J/mol
T = 151.4°F = 66.33°C
mass = 58.41g
n = ?
V = ?
While we don't know the value of n but we know mass so we can calculate number of mole by using formula,
n = m / M
That is,
n is number of mole
m is mass
M is molecular mass
Now, putting values in this
n = 58.41 / 15.99
n = 3.65 mol
Thus, now we know the value of n
Put the value in formula
PV =nRT
1183 mmHg x V = 3.65 mol x 8.314 J/mol x 66.33°C
V = 2012.86 / 1183
V = 1.70 ml
Hence, the volume of the oxygen into a balloon is 1.70 ml.
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13. What are the 3 main types of radiation and what does each emit?
Answer:
[tex]\begin{gathered} a)\text{ Alpha Radiation (emits helium atom)} \\ b)\text{ Beta Particle (emits electron)} \\ c)\text{ Gamma Ray (has no charge, nor mass, are by-products of radiation)} \end{gathered}[/tex]Explanation:
The three main radiation types are:
a) Alpha particles
b) Beta Particles
c) Gamma rays
Alpha Particles
Alpha particles are essentially helium atoms. When radiated, the value 4 is subtracted from the parent's molecule mass number while the value 2 is subtracted from the parent's molecule atomic number. Due to their heaviness, they are less penetrative, compared to other radiation types. They are positively charged.
[tex]\alpha^{\text{ }}particle=^4_2He[/tex]Beta Particles
Beta particles are more energetic radiation emission with a charge equal to -1. They are negatively charged. They are high energetic electrons which can be represented generally as follows:
[tex]\beta^{\text{ }}particle=^{_{}0_{}}_{-1}e[/tex]They weigh much more less and have a higher penetrating power when compared to alpha particles
Gamma Rays
These are the lightest and are simply radiation by products. They have more penetrating power than both beta particles and alpha particles. They are neutrally charged. They have no charge nor mass:
[tex]^0_0\gamma\text{ }[/tex]They have low ionizing power
Match the particle with its charge.
neutron
proton
electron
positive (+)
neutral ( )
negative (-)
Answer:
electron(negative)
neutron(neutral)
proton(positive)
A 3.627g sample of a new organic material is combusted in a bomb calorimeter. The temp of the calorimeter and contents increases from 25.39 Celcius to 30.14 Celcius. Heat capacity (calorimeter constant) is 45.35 KJ/degree C. What is the heat of combusion per gram of the material.
I tried to work this out and need to know if this is correct:
I'm assuming -Qrxn =C(calorimeter) x Delta T
45.35J/degree C x 4.75 (which is change of T) = -20.67KJ since exothermic.
THen Delta Urxn= Qrxn/g of organic material.: -20.57KJ/g sample x gram sample/3.62g
This would be -5.699KJ/g.
Please let me know if this is correct or where I have made an error.
The heat of combustion per gram of the material is 59.4 kJ/g
What is the heat of combustion per gram?The heat of combustion per gram is the heat that is evolved when a substance is burnt in oxygen under standard condition. We know that combustion is an exothermic process thus it is clear that heat is given out.
Heat evolved = cdT
c = heat capacity
dT = temperature rise of the material
It then follows that;
Heat evolved = 45.35 * 10^3 J/degree C * (30.14 Celcius - 25.39 Celcius )
= 215412.5 J
Then;
heat of combustion per gram = 215412.5 J * 10^-3/3.627g
= 59.4 kJ/g
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Water has a density of 2g/ml. What is the mass of the water if it fills a 10ml container
20 Grams of Water.
Grams : mL
2 : 1
4 : 2
6 : 3
8 : 4
10 : 5
12 : 6
14 : 7
16 : 8
18 : 9
20 : 10
Answer:
20 grams
Explanation:
mass = Density × Volume
= M = 2g/ml × 10ml
= 20g
A solution is made by mixing 84. g of water and 100. g of hexane ()Calculate the mole fraction of water solution .
The mole fraction of the water solution is 0.77.
The mole fraction or molar fraction is defined as a unit of the quantity of a constituent, nᵢ, divided by the total quantity of all parts in a combination.
Moles of water = given mass/ molar mass
Moles of water = 84/18
Moles of water = 4.6
Moles of hexane = given mass/ molar mass
Moles of hexane = 100/76
Moles of hexane = 1.3
Total moles = Moles of water + Moles of hexane
Total moles = 4.6 + 1.3 = 5.9
Mole fraction of water = Moles of water / Total moles
Mole fraction of water = 4.6/5.9
Mole fraction of water = 0.77
Hence, the Mole fraction of water is 0.77.
The mole fraction is the same as the mole percent however in a specific shape in chemistry. Inside the given combination, the range of moles of one constituent is divided by the total number of moles is referred to as the mole fraction. Multiplying the mole fraction of the thing by then we gain the mole percentage of the aspect.
Mole fraction is a unit of awareness, described to be equal to the range of moles of an aspect divided through the whole wide variety of moles of a solution. Because it's miles a ratio, the mole fraction is a unitless expression.
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Give the percent yield when 28.16 g of CO2 are formed from the reaction of 8.000 moles of C8H18 with 16.00 moles of O2.
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
The percent yield when 28.16 g of [tex]CO_2[/tex] is formed from 8.000 moles [tex]C_8H_1_8[/tex] reaction with 16.00 moles [tex]O_2[/tex] is 6.25%.
Percent yieldThe percent yield of a reaction is given by:
Percent yield = actual yield/theoretical yield x 100%
From the equation of the reaction, the mole ratio of the two reactants is 2:25.
With 8.00 moles [tex]C_8H_1_8[/tex] , 200 moles of [tex]O_2[/tex] should be used. But only 16 moles is available. Thus, [tex]O_2[/tex] is the limiting reactant.
The mole ratio of [tex]O_2[/tex] to [tex]CO_2[/tex] is 25:16.
With 16 moles [tex]O_2[/tex], the moles of [tex]CO_2[/tex] would be:
16 x 16/25 = 10.24 moles
Mass of 10.24 moles [tex]CO_2[/tex] = 10.24 x 44.01
= 450.7 grams
Percent yield of [tex]CO_2[/tex] = 28.16/450.7 x 100
= 6.25%
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Solid manganese(IV) oxide reacts with the solid aluminum metal to produce solid manganese and solid aluminum oxide. Balance the equation for this reaction (in the lowest multiple integers). What are the formulas for the reactants and products?
1. Balanced equation of the reaction = [tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]
2. Formulas of reactants
solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]
solid aluminum metal = [tex]Al(s)[/tex]
solid manganese = [tex]Mn (s)[/tex]
solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]
Balancing chemical equationsA balanced chemical equation agrees with the law of conservation. In other words, the number of participating atoms must balance between the reactants and the products of the same equation.
Formula for solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]
Formula for solid aluminum metal = [tex]Al(s)[/tex]
Formula for solid manganese = [tex]Mn (s)[/tex]
Formula for solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]
Thus, the balanced equation for the reaction is written as:
[tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]
One can see from the that the number of atoms of each element in the reactants is equal to the number of atoms of the same elements in the product.
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Write and balance the equation for the decomposition of aluminum chloride into its elements. phase symbols are optional.
Balance the equation for the decomposition of aluminum chloride into its elements is 2AlCl₃ → 2Al + 3Cl₂
Decomposition reactions are processes in which chemical species break up into simpler parts and here given compound is aluminum chloride is hexahydrate is thermally decomposed to alumina by sequential treatment in two dense fluidized bed decomposers the first decomposer being operated at a temperature of about 200° to 400° C and the second at a temperature of about 900° to 1100° C
Here we have to write and balance the equation for the decomposition of aluminum chloride into its elements so balanced equation for aluminum chloride for decomposition is
2AlCl₃ → 2Al + 3Cl₂
2 mole of AlCl₃ gives 2 mole of Al and 3 mole of Cl₂
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This is a part of the antihistamines in pharmaceutical chemistry
The classification of Rupatadine is H-1 receptor antagonists or H-1 blockers.
What is rupatadine?As a platelet-activating factor antagonist and second-generation antihistamine, rupatadine is used to treat allergies. It was found and developed by Uriach [es][2], and it is sold under the trade names Rupafin and a few other names as well. For the treatment of chronic urticaria and allergic rhinitis in adults and children older than 12 years, rutadine fumarate has been approved. It is offered as round, light salmon-colored tablets to be taken orally once day that contain 10 mg of rupatadine (as fumarate).
Rupatadine's effectiveness as a treatment for allergic rhinitis (AR) and chronic idiopathic urticaria (CIU) has been examined in adults and adolescents (aged over 12 years) in several controlled studies, demonstrating a rapid action onset and a great safety characteristics even in long treatment durations of a year.
The drug rupatadine, a dual antagonist of the histamine H1 and platelet activating factor receptors, is used to treat the symptoms of chronic spontaneous urticaria and seasonal and perennial rhinitis. It is available in tablet and liquid formulations for adult and pediatric usage in Canada and has received marketing approval under the trade name Rupel.
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Liquid octane (CH₂(CH₂)6 CH₂) reacts with gaseous oxygen gas (₂) to produce gaseous carbon dioxide (CO₂) & gaseous water (H₂O). If 85.8g of carbon dioxide is produced from the reaction of 31.98g of octane. & 190.4g of oxygen gas, calculate the percent yield of carbon dioxide.
The percent yield of carbon dioxide is 87%.
The balanced chemical equation for reaction of octane with oxygen,
CH₂(CH₂)₆CH₂+ 12O₂ → 8CO₂ + 8H₂O
We can use the mole concept here,
Mole = Given mass/molar mass.
From the reaction,
1 mole of Octane = 8 moles of carbon dioxide.
Now, moles of octane N,
N = 31.98/114.23
N = 0.2799
Moles of Carbon dioxide = 8 x 0.2799
Moles of Carbon dioxide = 2.239
Mass of CO₂ formed,
2.239 = Mass of CO₂/44
Mass of CO₂ = 98.54 grams/mole.
Percentage yield = theoretical mass/experimental mass x 100
Theoretical mass = 98.54 grams/mole.
Experimental mass = 85.8 grams/mole.
Percentage yield of CO₂ = 85.8/98.54 x 100
Percentage yield of CO₂ = 87%
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Hello, can you give me a concept of what anhydrides are and examples, please?
Anhydrides are binary substances or compounds that are the result of a nonmetal with oxygen.
I leave you 2 steps to make the anhydrides:
1: To make anhydrides, write your nonmetal symbol followed by oxygen.
2: The oxidation numbers must be the same and for this the exchange of oxidation numbers or valence between its non-metallic element and Oxygen is used.
Examples of anhydrides:
1: Chlorous anhydride
[tex]\bold{ \: Cl + O₂ \rightarrow \: Cl₂ O₃}[/tex]
Keep in mind that when it ends in OSO we look for its valence, which in this case would be +3.
2: Iodic anhydride
[tex]\bold{ \: I + O₂ \rightarrow \: I₂ \: O₅}[/tex]
We take into account its symbol that in this would be me and to solve it we must look for its valence that in this case ends in ICO which is already known that its ICO valence is +5.
3: Per bromic anhydride
[tex]\bold{\:Br + O₂ \rightarrow \:Br₂ \:O₇}[/tex]
We take into account its symbol, which in this case would be Br, and to solve it we must find its valence, which in this case ends in ICO, which is already known to have an ICO valence of +7.
The Table of metals and non-metals is attached.
You need a 9.0% NaCl solution for an IV drip. If your IV bag can hold 239 grams of total solution, how many grams of NaCl are in the IV bag?
The 12.5 g of NaCl is required to make 9.0% of the NaCl solution.
How the percentage is related to grams in terms of Chemistry?
Both percentages and grams both are units or parameters used to express the concentrations in chemistry.
Given:
The % of NaCl = 9.0% or = 9/10 = 0.9
The weight of the solution = 239 grams
The molar mass of the NaCl = 58.44 g/mol
Here, we use formula = 0.9 = (Mass of the solute*1000)/(Mass of the solvent)
Let us assume the mass of the solute = x = mass in the gram/ molecular mass of the solute.
Now, by using the above formula, we get
X= 0.9*239*58.44/1000
X = 12.5 grams
Hence, 12.5 grams is the answer
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10.00 moles of H2(g) react with 5.000 mol of O2(g) to form 10.00 mol of H2O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then
10.00 moles of H₂(g) react with 5.000 mol of O₂(g) to form 10.00 mol of H₂O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then ΔE° is 646.00kJ
Energy that is transferred from one body to another as the result of a difference in temperature called as heat
Here given data is
H₂(g) + O₂(g) → H₂O(l)
H₂(g) = 10.00 mole , O₂(g) = 5.000 mol , gives H₂O(l) = 10.00 mol and heat are released during this reaction are 683.0 kJ and PΔV is equal to -37.00 kJ then we have to find ΔE° = ?
ΔH° = 683.0 kJ
ΔE° = heat are released - PΔV
So, ΔE° = 683.0 kJ - 37.00 kJ
= 646.00kJ
And the calculated answer is the ΔE°
So, ΔE° = 646.00kJ
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List all possible values of the magnetic quantum number ml for a 4p electron.
Answer:
-1, 0, 1
Explanation:
for n = 4
l = 0, 1, 2, 3
p corresponds to 1
so ml of 4p is -1, 0, 1
Which of the following is an isotope of Carbon (atomic number 6)?
A 7 protons, 6 neutrons, 8 electrons
B 7 protons, 8 neutrons, 6 electrons
C 8 protons, 6 neutrons, 7 electrons
D 6 protons, 8 neutrons, 7 electrons
Answer:
D
Explanation:
Carbon has atomic number of 6 so it has 6 protons.
What is TRUE about soil used as evidence in forensic science?
A.
It only includes dirt.
B.
It may include pieces of asphalt.
C.
It only includes natural substances.
D.
It cannot be used in a criminal case.
The statement 'It may include pieces of asphalt' is TRUE about soil used as evidence in forensic science (Option B).
What is forensic science?Forensic science is a sub-discipline aimed at solving police cases based on evidence found at the crime scene, thereby being a key part of a police investigation. in this sense, pavement structural evaluation may result very useful in forensic science.
Therefore, we can conclude that forensic science is based on evidence found in the crime scene, which may include evidence in the asphalt ([pavement) that is collected by investigators in order to analyze it.
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Answer: B
Explanation:
hello, can someone please help me with this problem
In order of degreasing Size :
O2- > O > Ne.
Br- > Cl- > F-
Mg > Al > S
what are factors affects the radius of the atom? How many protons are in the nucleus (called the nuclear charge). The number of electron-carrying energy levels (and the number of electrons in the outer energy level). a measure of how many electrons are kept between the nucleus and its outermost electrons (called the shielding effect).The separation between an ion's nucleus and its furthest-reaching electrons is known as the ionic radius. However, the atomic radius measures the separation between an atom's outermost shell and its nucleus.To learn more about : Atomic radius
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molar mass of rhodonite mnsio3
The molar mass of rhodonite MnSiO₃ is 131.0 g.
What is the molar mass of a substance?The molar mass of a substance is the mass of 1 mole of that substance.
The molar mass of a compound is obtained from the sum of the product of the number of moles of atoms and the molar masses of the elements in the compound.
The molar mass of rhodonite MnSiO₃ is calculated as follows:
Molar mass of Mn = 55 g
Molar mass of Si = 28 g
Molar mass of O = 16.0 g
Molar mass of MnSiO₃ = 55 + 28 + 16 * 3
Molar mass of MnSiO₃ = 131.0 g
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If a population consist of large portion of reproductive Indvidual's, how would you expect the future population size to respond?
If a population consist of large portion of reproductive Indvidual's, then the future population size is also increase .
As previously said, populations with early reproduction have the ability to increase far more quickly than populations with later reproduction. The life tables for a certain species show how the age of first reproduction affects population growth.
Preoperative people make up a large amount of the triangular age pyramid, whereas reproductive people make up a more moderate number and post-reproductive people make up less of it. It signifies a young or populace that is expanding quickly.
In an age pyramid with an urn shape, there are more reproductive people than pre-reproductive people. It symbolises population loss or reduction and negative growth.
The proportion of pre-reproductive and reproductive people in the age pyramid has a bell shape. Comparatively fewer people are post-reproductive. It indicates a population that is steady or stationary and is neither increasing nor decreasing.
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A certain quantity of helium gas is at a temperature of 27°C and a pressure of 1.00 atm. What will the new temperature be if its volume is doubled at the same time that its pressure is decreased to one-half its original value? (Hint: Three variables have been given so what equation will you use?)
The new temperature of certain quantity of helium gas is at a temperature of 27°C and a pressure of 1.00 atm will be 300 K if its volume is doubled at the same time that its pressure is decreased to one-half its original value.
We will use combined gas law equation to find the new temperature.
We know that
Initial temperature T₁ = 27°c +273 K = 300 K
Initial pressure P₁ = 1.00 ATM
Initial volume V₁ = V
Final volume V₂ = 2 V
Final pressure P₂ = P/2 = 1/2 = 0.5 atm
Now, using the combined gas law equation, which is given as -
P₁V₁ = P₂V₂
T₁ T₂
where,
P₁ = Initial pressure
P₂ = Final pressure
V₁ = Initial volume
V₂ = Final volume
T₁ = Initial temperature
T₂= Final temperature
Avogadro's law states that equal volumes of gases contains equal number of molecules at same temperature and pressure.
P₁V₁T₂ = P₂V₂T₁
Dividing P₁V₁ on both the sides
P₁V₁T₂ = P₂V₂T₁
P₁V₁ P₁V₁
We get,
T₂ = P₂V₂T₁
P₁V₁
Substituting values,
T₂ = 0.5 × 2V × 300 × V
1
T₂ = 300K
Hence, the new temperature is 300 K.
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write out step by step explanation of the process of fission
A bigger atom fission when a neutron smashes against it, causing it to excite and split into two smaller atoms known as fission products. A chain reaction may be initiated by other neutrons that are also released.
What examples of fission?By dissolving large, heavy atoms, like uranium, into smaller ones, like iodine, cesium, strontium, xenon, and barium, to name just a few, fission produces energy. To create the heavier helium, fusion combines light atoms, such as the two hydrogen isotopes deuterium and tritium.
Why is fusion so important?Nuclear fission fuels the explosion of nuclear weapons and creates energy for nuclear power. Due to the fact that certain compounds known as nuclear fuels undergo fission when impacted by fission neutrons and then break apart, both uses are feasible.
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What is the percent by mass of carbon in Al(CO3)3
The percent by mass of carbon in Al₂(CO₃)₃ is 15.38%.
Mass number(A) of various elements of molecule,
A of Aluminum(Al) = 27
A of Carbon(C) = 12
A of Oxygen(O) = 16
Total molecular mass or molecular weight is the sum of individual atomic masses of each atom in a molecule.
Thus, total molecular mass of molecule Al₂(CO₃)₃ is:
= 27×2 + (12 + 16 × 3)3
= 54 + 180
= 234
Hence, percent % of Carbon = (12×3/ 234)× 100
= (36/ 234 )× 100
= 15.38 %
Thus, the percent by mass of carbon is 15.38 %.
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The mass of a single barium atom is 2.28×10-22 grams. How many barium atoms would there be in 166 milligrams of barium?
166 milligrams is equal to 0.166 grams.
If 2.28x10^-22 grams is the mass of 1 atom, then 0.166 grams would constitute how many atoms?
The equation we would make is as follows:
2.28x10^-22/1 = 0.166/x
- If we cross multiply and solve for x, we get the answer which is 7.28x10^20 atoms.
If 3.05 mol of an ideal gas at 273 K has a volume of 208 L, what will its pressure be in kPa?
Use one of the following values:
R=0.0821 atm. L/mol. K
R= 8.31 kPa L/mol K
R= 62.4 torr. L/mol K
kPa
Ideal gas equation PV =nRT
The parameters are given in problem : moles (n) = 2.55 Volume (V) = 205L:Temperature(T) = 273K Pressure = ?kPa
Universal Gas constant R = 8.31kPa.L/mol.K substitue all these values in ideal gas equation in PV = nRT
PV = nRT
Px205 = (2.55)x(8.31)x(273)
P = (3.05)x(8.31)x(273) /205 kPa
P = 33.75 kPa.
The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. An ideal gas is one that obeys the law pv=RT at all pressures and temperatures. At high temperatures and low pressure, the potential energy due to intermolecular forces becomes almost insignificant compared to the kinetic energy of the particles, and the size of the molecules increases compared to the intermolecular voids.
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"What volume of 0.642 M [Molar ]magnesium Chloride (MgCl2, MM 95.21 g/mol) solution would be required to deliver 4.50g of MgCl2?"
Explanation:
n=m/MM
MM of MgCl2=95.2
n=4.5/95.211
M=n/V
0.652=0.0473/V
V=0.0724 L
=72 ml
The investigators were able to determine that the footprints were made by a Nike, size 10 tennis shoe; however, they couldn’t match it exactly to the suspect’s shoe. What is TRUE about this piece of evidence?
A.
They were unable to find class nor individual characteristics.
B.
They were only able to find class characteristics.
C.
They were only able to find individual characteristics.
D.
They were able to find both class and individual characteristics.
Answer
the correct answer would be A
Explanation:
They were unable to find class nor individual characteristics.
Law of conservation of mass 21 g of A and 21 g of b produce 17 g of c
The fact that 21 g of A and 21 g of B produce 17 g of C does not obey the law of conservation of mass.
What is the law of conservation of mass?The law of conservation of mass states that the mass of a substance can neither be created nor destroyed.
This law further explains that in a chemical reaction, the amount of reactants must be equal to the amount of products in the reaction.
For example, if a substance A of mass 21g reacts with another substance B of mass 21g, the mass of the product C should be 21g + 21g = 42g in order to align with the law of conservation of mass.
However, according to this question, the product C has a mass of 17g, which shows that the law of conservation of mass is not obeyed.
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. What volume of a 15.2 M H3PO4 solution (in mL) do you need to make the following solutions?
a. 3.50 L of a 0.750 M H3PO4 solution
b. 12.5 L of a 0.155 M H3PO4 solution
C.
475 mL of a 1.20 M H3PO4 solution
15.2 M H3PO4 solution (in mL) do you need to make 475 mL of a 1.20 M H3PO4 solution
an H3PO4 solution be created
As a result, you must combine 0.9316 liters (931.6 ml) of water with 0.0684 liters (68.4 ml) of concentrated solution to create 1 liter of 1 M. Solution of phosphoric acid
How can I figure out what a solution's concentration is?
Subtract the solute's mass from the solution's overall volume. C = m/V, where m is the solute's mass and V is the entire volume of the solution, should be written down. To calculate the concentration of your solution, divide the mass and volume quantities you discovered by the corresponding plug-in values.
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How many atoms are there in 10 g of Kr?
From the periodic table, we know that 1 mole of Krypton has a molar mass of 83.798 grams/mole.
So 10 grams would have (10/83.798) which is 0.1193345903 moles.
If we multiply this by Avogadro's number, we get the amount of Krypton atoms in 10 grams.
0.1193345903 x 6.02 x 10^23 = 7.184 x 10^22 atoms
Accounting for significant figures, the answer would be: 7 x 10^22 atoms