Answer:
=0.855V
Explanation:
The induced voltage can be calculated using below expression
E =B x dA/dt
Where dA/dt = area
B= magnetic field = 6.90×10-5 T.
We were given speed of 885 km/h but we will need to convert to m/s for consistency of unit
speed = 885 km/h
speed = 885 x 10^3 m/hr
speed = 885 x 10^3/60 x60 m/s
speed = 245.8 m/s
If The aircraft wing sweep out" an area
at t= 50.4seconds then we have;
dA/dt = 50.4 x 245.8
= 123388.32m^2/s
Then from the expression above
E =B x dA/dt substitute the values of each parameters, we have
E = 6.90 x 10^-5 x 12388.32 V
E =0.855V
Hence, the average induced voltage between the tips of the wings is =0.855V
Why did scientist's gather at Los Alamos in 1945.
How is a metre related to kilometre?
Answer:
The kilometer is unit of length in the metric system equivalent to one thousand meters. 1Km is equivalent to 0.6214 miles.
Explanation:
Length is the measurement of the distance from the initial point to the final point.
________________________________________________________
SI Unit:The Si unit of length is meter, that means length is measured in meter units.
____________________________________Relation:The Relation between meter and kilometer is that they both are the units of the length, also the Kilometer(Km) is equals to the 1000 meters(m).
1Km = 1000 meter
1m = 0.001 Km
____________________________________Best Regards,'Borz'Do larger bodies orbit smaller bodies or do smaller bodies orbit larger bodies? Provide some examples to support your answer.
Explanation:
the small bodies in the solar system include comets, asteroids, the objects in the Kuiper Belt and the Oort cloud, small planetary satellites, Triton, Pluto, Charon, and interplanetary dust. As some of these objects are believed to be minimally altered from their state in the young solar nebula from which the planets formed, they may provide insight into planet Earth and the formation and evolution of the solar system.
A car accelerates uniformly from rest to a final speed of 19 m/s in 10. seconds. How far does it travel during this period of acceleration?
Answer:
x = 95 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} +a*t[/tex]
where:
Vf = final velocity = 19 [m/s]
Vo = initial velocity = 0 (starts from the rest)
a = acceleration [m/s²]
t = time = 10 [s]
Now we can find the acceleration
19 = 0 *a*(10)
a = 1.9 [m/s]
With the second equation we can find the distance:
[tex]v_{f} ^{2} =v_{o} ^{2} +(2*a*x)[/tex]
where:
x = distance [m]
(19)² = (0)² + (2*1.9*x)
3.8*x = 361
x = 95 [m]
Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2
,
what is the greatest possible magnitude of the other force?
Given :
Two forces act on a 6.00-kg object. One of the forces is 10.0 N.
Acceleration of object 2 m/s².
To Find :
The greatest possible magnitude of the other force.\
Solution :
Let, other force is f.
So, net force, F = 10 + f.
Now, acceleration is given by :
[tex]a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N[/tex]
Therefore, the greatest possible magnitude of the other force is 2 N.
Hence, this is the required solution.
Calculate the p.e. of a 5 kg mass when it is (i) 3 m, (ii) 6 m, above the ground. (g = 10 N/kg)
Explanation:
P.E=MGH
(1) P.E=5×10(G)×3
= 150 kg m^/s^ ( ^ =sqaure)
(2) P.E=5×10×6
= 300 kg m^/s^
Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)
help me plsss, this is worth 30 points!! can someone pls help even if u can only give a few answers it would be helpful.
In a physics lab, students take a long piece of string and cut it into two unequal pieces. One piece is used to suspend a large weight. The second piece is tied to the bottom of the weight as seen in the diagram below. Student 1 predicts that the upper string will always break first since it has to support the weight and the applied force, while Student 2 disagrees and predicts that the shorter piece of string will always break first if you pull slowly but with enough force to exceed the strength of the string.
(a) Which aspect(s) of Student 1’s reasoning, if any, are correct? Explain your answer.
(b) Which aspect(s) of Student 2’s reasoning, if any, are correct? Explain your answer.
(c) Which aspect(s) of both Student 1’s and 2’s reasoning, if any, are incorrect? Explain your answer.
(d) The experiment is performed and both students are surprised to learn that whether
the upper or lower string breaks first depends on whether you pull slowly or with a
sudden pull. Resolve the two lines of reasoning of Student 1 and Student 2 by
explaining the results of the experiment in a clear, concise paragraph.
Answer:
(a) The aspect of the upper string supporting the weight and the applied force
Student 1 is correct because the upper string is the source of support of the large weight and the force applied to the short string reacts at the support of the long string
(b) The aspect of Student's (2) reasoning that is correct is that the shorter piece of string will always break first, however, the statement is only true for sudden pull due to the increased force experienced by the shorter string from a more rapid change in momentum
(c) The aspect of Student 1's statement that is incorrect is the that the upper string will always break first
The aspect of Student 2's statement that is incorrect is the that the shorter piece of string will always break first
(d) A string will break when subject to a force equivalent to its breaking force. The force experienced by the string increases as the rate of pull (suddenness) increases and the suddenness increases inversely with the length of the string, as such the shorter lower string will break first from a sudden pull before the force of the pull is completely transmitted to the upper string. Whereby the lower string is slowly pulled, the force is evenly transmitted to the upper string which is then taking up the load of the weight and the applied force together and is likely to break first
Explanation:
Using a force of 10 N, you
push a shopping cart 10 m.
How much work did
you
do?
Answer:
100 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 10 × 10
We have the final answer as
100 JHope this helps you
From Smallest to Largest
Moon
asteroid
meteorite
meteoroid
An object is lifted upward at a constant speed. The gain in potential energy of the object is due to the
(A) work done on the object
(B) total force applied to the object
(C) weight of the object
(D)change in kinetic energy of the object
PLEASE HELP ME
Answer:
b
Explanation:
If the weight of an object on the moon is 1/6 of the weight of an object on earth. What
would be the weight of an object on the moon who has the weight of 4800 N on earth?
Answer:
1200 N
Explanation:
Answer:
1200N
Explanation:
Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon ;which means weight on the moon).Mass of the moon is "M"
and its radius is "R"
Weight of an object on the moon = "F"(Force)with which the moon pulls.
Wm = GM*m/r2
Weight of the same object on the earth is We(where W is the weight and "e" is the earth; which means weight on the earth).
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2(Pronounced 4 R square)
We = G100M*m/(16R)2(Pronounced 16 R square)
Wm/We = G * M * m * 16R2/R2 * g * 100M * m
=16/100
Therefore, 4800N on earth= 1200N on moon
Which of the following statements is correct.
A. A direct relationship exists between frequency and wavelength, as the frequency increase from Radio waves to Gamma rays so does the wavelength.
B. A direct relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays so does the wavelength.
C. An indirect relationship exists between frequency and wavelength, as the frequency increase
from Radio waves to Gamma rays the wavelength decrease.
D. An indirect relationship exists between frequency and wavelength, as the frequency decrease
from Radio waves to Gamma rays Wie wavelength increase
A bar magnet is a permanent magnet, While an electromagnetic temperary?
yes an electromagnetic is temporary
What is the root of all electrical systems?
1 batteries
2 electrons
3 atoms
4 non of the above
Answer:
I believe it's 2. I am not sure though.
Answer if you know
If you give me a good explanation on how quantum mechanics work, you get 20 points and possibly a brainliest.
Answer:
spectra.
Atomic spectra is series of colored lines which occures when atoms emit light of certain wavelengths. Element produces a particular set of spectral lines.
Electrons exist in shells and each shell has a specific energy. Electrons absorb photons and jump to higher energy levels.
Explanation:
When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?
A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
how is an object's motion related to speed, velocity, and acceleration?
Answer:
Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration
A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances friction *
Fg sin 36 degrees
Fg cos 36 degrees
Fg tan 36 degrees
Fg x N
Given :
A box weighing 12,000 N is parked on a 36° slope.
To Find :
What will be the component of the weight parallel to the plane that balances friction.
Solution :
The component of that will be parallel to the plane to balance friction is :
[tex]F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)[/tex]
Therefore, component of force to balance friction is F sin 36° .
Hence, this is the required solution.
What would happen to the number of home runs a player could hit if the air was removed from above the field? Use your understanding of Newton's laws to explain.
Answer:
number of home runs a player would hit would drastically increase
Explanation:
In a hypothetical scenario, if this were to happen the number of home runs a player would hit would drastically increase. When a player hits the ball force is applied to the ball which sends it flying, then the ball meets an opposing force of air resistance and a downward force of gravity which ultimately causes the ball to fall to the ground. This is explained in Newton's first law which states that "objects in motion remain in uniform motion and in a straight line unless they are met by an opposing unbalanced force." Without the force of air resistance, the ball will only be met with a downward force of gravity which would allow it to travel at a much greater distance before hitting the ground, thus resulting in a drastic increase of home runs.
Answer:
number of home runs a player would hit would drastically increase
Explanation:
FOR 45 POINTS PLS ANSWER FAST
1. coefficient of friction
force that opposes a sliding object
2. drag
a force that resists motion
3. friction
friction between a solid and a liquid or gas
4. rolling friction
a force that develops when a mass is accelerated by gravity; stated as Fw = mg
5. sliding or kinetic friction
force that opposes a rolling object
6. starting or static friction
force that opposes the start of motion
7. weight
the ratio of the force necessary to move an object (or keep it moving) and the normal force
Answer:
Other than gravity, the most commonly encountered force is what or the force that resists motion.
friction
the ratio of the force necessary to move an object (or keep it moving) and the normal force
coefficient of friction
friction between a solid and a liquid or gas
drag
a force that resists motion
friction
the force that presses two surfaces together and is directed perpendicular to the contact surface; on a level surface, its magnitude is equal to the force of the object's weight but in the opposite direction
normal force
force that opposes a rolling object
rolling friction
force that opposes a sliding object
sliding or kinetic friction
force that opposes the start of motion
starting or static friction
a force that develops when a mass is accelerated by gravity; stated as Fw = mg
weight
Friction is a force that resists what
motion
It occurs when a surface in motion rubs against another what
surface
What acts parallel to the surfaces that are moving against one another and in the direction opposite to the direction of the motion (represented by F).
Friction
riction is caused by the interaction of the what or what of each object sliding over each other.
atom or molecules
he more contact the atoms are able to make, the greater the what
frictional effect
A what surface will produce more friction (resistance) than a smooth surface
rough surface
The high points on one surface interact with the high points on the other surface allowing atoms and molecules to form temporary what
intermolecular bonds
The more bonds that are allowed to form, the greater the what
friction
he force that opposes the start of motion is referred to as what
starting or static friction
This force is caused by the what that form between two surfaces
tiny bonds
The pull required to keep the block moving at a constant speed in the example above is due to what
sliding or kinetic friction
What occurs as tiny intermolecular bonds are constantly being formed and broken.
Sliding friction
Sliding friction is also affected by the weight of the object and another force called the what
normal force
What is the force of the contact surface pressing opposite the weight of the object, as seen in the diagram below.
normal force
The normal force is always perpendicular to the what
contact surface
The ratio between the sliding friction and the perpendicular normal force is called the what of sliding friction
coefficient
What is represented by the Greek letter mu, μ,
coefficient
he third type of friction that can exist between solid surfaces is what or the force that opposes a rolling object
rolling friction
Friction can also exist between what
solids liquids and gases
Gases and liquids, such as air and water, offer what
resistance to motion
the opposing force between a solid and a liquid or gas
drag
What happens to the kinetic energy of a hot drink when an ice cube is put into the drink?
Answer:
Heat is kinetic energy -- the higher the temperature of a substance, the faster and farther its molecules move.
Explanation:
... Conversely, when heat transfers from your beverage to the ice and the temperature of the liquid drops, the molecules in the beverage slow down. When those molecules slow down, their kinetic energy decreases.
Please help I need this right now
Answer:
The basket ball
Explanation:
The heavier an object is the more kinetic energy it will have even if it is thrown at the same speed; therefore, since the basketball is the heaviest, it is the logical answer.
While a marble is heavy for its size, it would not have the same kinetic energy as the basket ball.
Beach balls weigh the least out of the options given so this cannot be the answer.
Golf balls, while they are dense, they do not weigh nearly as much as a basketball would!
Hope this helps <3
Answer:
The answer is B the basketball
Explanation:
1. Calculate the pressure of an object with an area of 10m2 force of 5N exerted
on it
Answer:
2
Explanation:
pressure(p)=force(f)\area(a)
A fighter jet flies 3 km west and then 2 km east in 8 minutes. Determine the jet's average velocity. (Remember to convert!)
Answer:
7.69km/hr due east
Explanation:
Given parameters:
Displacement due west = 3km
Displacement due east = 2km
Time taken = 8 minutes
Unknown:
Average velocity = ?
Solution:
Average velocity is the rate of change of displacement with time.
Velocity = [tex]\frac{displacement}{time }[/tex]
Displacement is deals with the start and the end;
Here, displacement = 3km - 2km = 1km due east
Time = 8min
60min = 1hr
8min = [tex]\frac{8}{60}[/tex] = 0.13hr
Average velocity = [tex]\frac{1km}{0.13hr}[/tex] = 7.69km/hr due east
the gravitational field strength on mars is 3.7n/kg
Answer:
True
Explanation:
1. Day and Night are caused by
10 points
A. The Tilt of the Earth’s Axis.
B. Earth’s Revolution around the sun
C. Earth's ellipical orbit
D. Earth's rotation on its axis.
A constant force acting on a body of mass 2 kg changes its
velocity from 1 m/s to 2 m/s in 20 s. If the direction of motion of
the body remains unchanged, the magnitude of the force that acted
on the body was 0.1 N.
True or False
Answer:
the correct answer is b
Answer:
true
Explanation:
just did it on ck12 lol
Length of table is 1.0m,1.00m and 1.000m.Which one is more accurate?
Answer:
1.00 m is a more accurate measured length.
Explanation:
Denote length of the table by L.
For L=1.0 m, there is one significant digit after the decimal.
Care 1: When one more significant digit after decimal considered, the exact number can be from 0.95 to 1.05.
So, the possible span of error [tex]\Delta E_1= 1.05-0.95= 0.1m[/tex]
For L=1.00 m, there is two significant digits after the decimal.
Case 2: When one more significant digit after decimal considered, the exact number can be from 0.095 to 1.005.
So, the possible span of error [tex]\Delta E_2= 1.005-0.095= 0.01m[/tex]
Case 3: For L=1.000 m, there is three significant digits after the decimal.
When one more significant digit after decimal considered, the exact number can be from 0.0095 to 1.0005.
So, the possible span of error [tex]\Delta E_3= 1.0005-0.0095= 0.001m[/tex]
As [tex]\Delta E_1 >\Delta E_2>\Delta E_3[/tex]
So, the least error is in the third case when L=1.00m, hence, L= 1.00m is more accurate.