Answer:
2.5 m/s²
Explanation:
F = ma (Newton's 2nd Law)
a = F/m = 3,000 N / 1,200 kg = 2.5 m/s²
dog sits 1.25 m from the center of a merry go round and revolves at a tangential speed of 2.0 m/s. if the dog's mass is 19.3 kg, what is the magnitude of the centripetal force on the dog?
Dog is seated 1.25 metres from the centre and rotates at a tangential speed of 2.0 metres per second. If the dog weighs 19.3 kg, the centripetal force acting on it will be 61.76 N.
A total net force acting on an object moving in a circular motion is known as a centripetal force.
It is given that radius(r) of the merry go round = 1.25m
tangential speed of the merry go round (v) = 2m/s
Mass of the dog (m) = 19.3kg
Centripetal acceleration (ac) is calculated as = v^2/r
So ac = (2x2)/1.25 = 3.2m/s^2
According to centripetal force(Fc) = mxac
Then Fc = 19.3 x 3.2 = 61.76N
Hence the centripetal force acting on the dog is 61.76N
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a rope is used to pull a3.57 kg block at constant speed 4.06 m along a horizontal floor. the force on the block from the rope is 7.68 n and directed 15.0o above the horizontal. what are (a) the work done by
The work done by the rope is 30.1 J
The displacement when it is pulled by the constant speed = 4.06 m
The Mass of the rope = 3.57 kg
The force on the block from the rope is 7.68 N
The angle above the horizontal where the force has been applied = 15 °
Work Done is given by the dot product of force and displacement.
Work is a Scalar Quantity,
The formula for Work Done is
W = F.s
W = Fscosθ
Putting the given parameter in the above equation, we get
W = (7.68) ( 4.06 m) cos 15 ° = 30.1 J
The work done by the rope is 30.1 J
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which factor will not affect the strength of a solenoid? question 13 options: number of wraps strength of current radius of the wraps core type
The factor that will not affect the strength of a solenoid will be the radius of the wraps. So option c. is correct.
Solenoids are simple components that can be used for various applications. A solenoid is a long piece of wire which is wound in the shape of a coil. When the electric current passes through the coil it creates a relatively uniform magnetic field inside the coil. The solenoid can create a magnetic field from electric current and this magnetic field can be used to generate a linear motion with the help of a metal core.
The solenoid simply works on the principle of electromagnetism. The magnetic strength of the solenoid can be increased by increasing the density of the turns or by increasing the current flow in the coil.
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A train locomotive pull a train with a ma of 1. 30 ✕ 107 kg on level rail. The locomotive exert a contant force of 6. 90 ✕ 105 N on the train. How much time doe it take to increae the peed of the train from ret to 78. 0 km/h? (Ignore any reitance force from the rail on the wheel of the train. Enter your anwer in minute. )
A train locomotive pull a train with a mass of 1. 30 ✕ 107 kg on level rail. The locomotive exert a constant force of 6. 90 ✕ 105 N on the train. 244.5 minutes time does it take to increase the speed of the train from rest to 78. 0 km/h.
The time it takes to increase the speed of the train from rest to 78.0 km/h, you need to use the equation for acceleration:
= a
= F / m
where a is the acceleration of the train, F is the force exerted on the train by the locomotive, and m is the mass of the train.
Putting the values from the problem gives:
a = (6.90 x 10^5 N) / (1.30 x 10^7 kg)
= 5.31 m/s^2
To find the time it takes to increase the speed of the train from rest to 78.0 km/h, you can use the equation:
v = v0 + at
where v is the final speed of the train, v0 is the initial speed of the train (which is 0 in this case), a is the acceleration of the train, and t is the time.
Putting the values from the problem and solving for t gives:
= t
= (78000 m/h - 0 m/s) / (5.31 m/s^2)
= 14670 s
Since there are 60 seconds in a minute, the time it takes to increase the speed of the train from rest to 78.0 km/h is approximately 14670 s / 60 s/min = 244.5 minutes.
Therefore, the correct answer is "244.5".
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are there other classes of stars besides those in the primary obafgkm sequence? what are they, and are they significantly different from their more or less massive peers?
The other classes of stars besides those in the primary obafgkm sequence are spectral types L, T, and Y. They significantly different from their more massive peers.
Stars are substantial gas spheres. The star's core is compressed by the force of gravity, which raises its temperature to almost 10 million Kelvin. Nuclear fusion can commence at these temperatures and densities. When four hydrogen atoms unite to make a single helium atom, energy is released. The starlight comes from this. More massive stars have hotter cores, which fuse hydrogen more quickly. They emit more light and heat than the Sun. The Sun has enough hydrogen to last for roughly 10 billion years; larger stars burn away more quickly. According to their spectra, astronomers categorize stars. Given that stars are, roughly speaking, black things, the hotter stars are blue and the colder stars are red.
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FILL IN THE BLANK. using a windows computer, to expand a branch of the folder tree you would _____.
Using a windows computer, to expand a branch of the folder tree you would
click the + (plus symbol) on the folder tree.right-clicking next to different disks and folders.The act of opening a folder and showing every item inside. For instance, in Microsoft Windows' Explorer, a user can double-click or click the plus (+) sign adjacent to a folder to expand it and view its contents. Click the minus (-) sign to collapse the folder if you wished to hide its contents.
The contents of a folder can range from papers and music to programs [such Word, Excel, or your preferred browser]. However, computer folders can also include numerous other folders, and those sub-folders can also contain more folders. Then, there are a number of folders, including Control Panel and Recycle Bin. The "Libraries" branch is the most significant one.
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when the center of gravity of the meter bar was determined in part i, was the bar supported at a point above, or coinciding with the center of gravity? would any difficulty have been encountered in trying to balance the bar if the clamp were inverted? explain.
In general, the center of gravity of an object can be determined by suspending the object from a single point and observing the object's balance. If the object is in balance, then the point of support is coincident with the object's center of gravity. If the object is not in balance, then the point of support is not coincident with the object's center of gravity, and the object will rotate or tilt until it comes to rest in a stable position.
If the clamp used to support the meter bar were inverted, it would still be possible to determine the center of gravity of the bar by suspending it from the inverted clamp and observing its balance. However, it may be more difficult to balance the bar in this configuration, as the clamp would be applying a force to the bar that is not aligned with the bar's center of gravity. This could cause the bar to rotate or tilt, making it more difficult to determine its center of gravity accurately.
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determine the minimum value of the coefficient of static friction which will prevent the blocks from moving in a pulley system
The minimum value of the coefficient of static friction which will prevent the blocks from moving in a pulley system is Fs=μsFN.
Create an inclination plane out of one of the materials, then place a body made of the other material on it to determine the minimum coefficient of static friction between the two. Up until the body begins to slide, steepen the incline. The coefficient of friction is the angle's tangent. A force that opposes motion is friction. Both static and kinetic friction work to keep a body at rest and to slow down its motion once it is moving. The normal force (FN), also known as the force produced perpendicularly by a body against the surface along which it is traveling, is proportional to the force generated by static friction (Fs). Fs=μsFN.
The properties of the two surfaces that are in contact with one another affect this coefficient.
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a linebacker strikes a side referee with a force of 100 n (on accident of course). the linebacker is in contact with the referee for 0.10 s. what is the magnitude of the change in momentum of the referee?
The magnitude of the change in momentum of the referee will be 10 Ns.
What does a momentum unit change mean?Mass times velocity equals mass (M) times momentum (P) (v). However, there are alternative perspectives on momentum. The change in momentum (P) over the time period (t) equals force (F). And the impulse is equal to the shift in momentum (P) (J). The units for momentum and impulse are kg*m/s and N*s, respectively.
How to calculate change in momentum or Impulse?Given, Force = 100N
time = 0.1. s
Impulse, J = F.t
J = 100×0.1
J or Δp = 10 Ns
The magnitude of the change in momentum of the referee will be 10 Ns.
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the planets that are farthest from the sun are the largest bodies in the solar system, but have the lowest average densities. which is the best explanation for this arrangement of the planets?
The temperatures on the Jovian planets were low enough to for the buildup of ice, which resulted in planets with massive sizes.
The largest planets in the solar system are also the ones with the lowest average densities because they are the ones closest to the sun. The larger gas and ice giants have a tendency to form further from the Sun because the regions closer to the Sun are too warm for the lighter gases to condense there. Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune are in order of proximity to the sun. Pluto, which was once thought to be the outermost planet, is now categorized as a dwarf planet. Pluto is not the only dwarf planet that has been found farther from the Sun. Out of all the planets in our solar system, Saturn has the lowest density. Saturn would float in a large enough body of water because it is less dense than water. But Saturn's mass is over 95 times greater than that of the Earth.
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the closest saturn comes to earth is 1,277,400,000 km. the closest jupiter comes to earth is 628,760,000 km. in au, how much closer does jupiter come to earth than saturn?
The Jupiter is closest to earth is 648,640,000.
The closest Saturn comes to earth is 1,277,400,000 km
The closest Jupiter comes to earth is 628,760,000 km
1277400000 - 628760000 = 648,640,000
The largest planet in the Solar System is Jupiter, which is located five planets from the Sun. It is a gas giant with a mass that is slightly less than one thousandth that of the Sun, but more than two and a half times greater than the combined mass of all the other planets in the Solar System. Observed since ancient times, Jupiter is the third brightest natural object in the night sky of the Earth after the Moon and Venus. It was given the title "Jupiter" in honor of the Roman god and supreme deity.
Helium makes up one-tenth of Jupiter's volume and one-quarter of its mass, despite the planet's primary chemical composition being hydrogen. Though, like the other major planets in the Solar System, it likely contains a rocky core made of heavier elements.
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ap physics 1 orbital velocity frq and what happen if mass of satellite increases and what happens if the radius increases
if the mass of the satellite increases, the orbital velocity will increase, and if the radius increases then the orbital velocity will decrease.
Orbital velocity is the speed at which a satellite must move to remain in orbit, and is determined by a combination of the satellite’s mass and the radius of its orbit. The formula for orbital velocity is: V = sqrt(GM/R) Where G is the gravitational constant, M is the mass of the satellite, and R is the radius of the orbit. If the mass of the satellite increases, the orbital velocity will increase. This is because the equation for orbital velocity is directly proportional to the mass of the satellite. That is, the higher the mass, the higher the orbital velocity. If the radius of the orbit increases, the orbital velocity will decrease. This is because the equation for orbital velocity is inversely proportional to the radius of the orbit. That is, the larger the radius, the lower the orbital velocity.
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Which of the following radiations has a wavelength longer than that of visible light?
A
X-ray waves
B
Gamma waves
C
Ultraviolet waves
D
Infrared waves
Infrared waves are radiations that have a wavelength longer than that of visible light. Thus, option D is the correct answer.
Electromagnetic radiation includes infrared light and waves. People come into touch with infrared radiation every day, which is heat-producing but invisible to the human eye.
Due to their longer wavelengths than visible light, infrared waves can travel across crowded areas of gas and dust in space without being significantly scattered or absorbed. As a result, employing optical telescopes, infrared energy can also show celestial objects that are invisible to the human eye.
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how people use the second law of thermodynamics to argue that they might be living more sustainably than someone who eats meat?
According to the second law, entropy always rises in closed systems. Let's use the growing of a leaf as an example. The sun emits low-entropy radiation that the leaf absorbs and then emits higher-entropy radiation into its surroundings.
The leaf is encouraged to reduce its own entropy in order to sustain the overall process's required increase in entropy as a result of this significant entropy increase.
Using this illustration, we can draw the conclusion that living things adhere to the second law of thermodynamics. second law of thermodynamics
A process that exchanges or transfers heat can result in a certain amount of useful work, according to the second law of thermodynamics.
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a slingshot consists of a light leather cup attached between two springs. (a) if it takes a force of 32 n to stretch the springs 1.2 cm, what is their spring constant?
A light leather cup placed between two springs makes up a slingshot. The springs' spring constant is 2667N/m if it takes a force of 32N to stretch them 1.2 cm.
In accordance with Hook's law, the spring's restoring force is proportional to its extension. The term "proportionality constant" also refers to the stiffness or spring constant. The formula for the hook's law is F = kx. The restoring force, spring constant, and spring elongation are represented in this equation by F, k, and x, respectively. Effective spring constant ke = k1+k2 when two springs with spring constants k1, k2 are linked in series, and ke = k1k2/k1+k2 when the springs are connected in parallel.
Considering the force on the spring (F) = 32N
elongation in spring (x) = 1.2cm
spring constant (k) = F/x = 32/1.2= 2667N/m
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When a rock tied to a string is whirled in a horizontal circle, doubling the speed _______
doubles the velocity, but the string tension remains the same.
decreases the velocity.
quadruples the tension in the string. doubles the tension in the string.
When a rock on a string is spun in a horizontal circle, the speed is doubled, quadrupling the tension in the string.
When the rope breaks, there is no force in the radial direction, thus the stone flies off tangentially because of inertia. Until the stone is attached to a string, the tension in the string causes centripetal force and centrifugal force along in radial direction of motion.
What is Tension in the string?
Tension is the force that is sent through a rope, string, or wire when two opposing forces pull on it. Along the whole length of the wire, the tension force pulls energy equally on the bodies at the ends.
Every physical object that comes into contact with another one exerts a force on it. These contact forces have names based on the types of things they are applied to. One of the forces exerted on an object, such as a rope, cable, or chain, is tension.
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FILL IN THE BLANK. when the cyclin‒cdk complex phosphorylates rb, the cell cycle progresses from _______ to _______.
The cell cycle advances from G1 phase to S phase when the cyclin–CDK complex phosphorylates RB.
The management of eukaryotic cell proliferation depends on the precise transition from G1 phase to S phase of the cell cycle, and its dysregulation encourages oncogenesis. Growth-dependent cyclin-dependent kinase (CDK) activity encourages DNA replication and starts the transition from G1 to S phase during G1 phase.
By causing alterations in transcription across the entire genome, CDK activation sets off a positive feedback loop that drives up CDK activity even more, committing the cell to division. G1-S transcripts produce proteins that control subsequent cell cycle processes. The intricate molecular mechanisms that regulate the temporal order of transcriptional activation and inactivation, identify distinctive functional subgroups of genes, and link cell cycle-dependent transcription are just now starting to come into focus as a result of recent research.
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consider the cantilevered w14×30 beam shown in (figure 1) . e = 29(10^3) ksi, i = 291 in^4.
(a) Determine the expression for the elastic curve using the coordinate x for 0 < x < 9 ft where x is in feet.
(b) Determine the maximum slope of the beam , measured counterclockwise from the positive x-axis.
(c) Determine the maximum deflection of the beam.
The cantilever beam's elastic curve equation, including the deflection at the free end and the slope at the free end
(a) For the cantilever beam AB, the elastic curve equation is
y(x) = (F/2EI)*x^2
(b) The deflection at the free end is given by
y(L) = (F/2EI)*L^2
(c) The slope at the free end is
dy/dx = (F/EI)*L
A system's behaviours when a force is applied to it is described mathematically by an elastic curve. Its formula is the product of the ratio of the change in stress to the change in strain. Elastic curves are used to gauge a material's stiffness and forecast how a material will respond to different forces. They are also employed in the calculation of a material's elastic modulus, which is a measure of stiffness. For constructing structures and for comprehending how various materials respond to forces, elastic curves are crucial. They are also employed in engineering and industrial processes to calculate the strain and force required to distort a material.
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suppose we discover a new comet on an orbit that brings it closer to the sun than mercury every 125 years. what can we conclude?
Compared to the antiquity of our solar system, it has only been in its present orbit for a very little period of time.
Some of the ice begins to melt and boil off as the comet approaches the Sun, along with some dust. A COMA, or cloud of particles and gases, surrounds the nucleus. The Sun shines into the coma. Additionally, the sunlight forces this material into the comet's gorgeous, brilliantly lighted TAIL.
A comet always travels tail first after passing the Sun because, as the diagram shows, its tail always points away from the Sun.
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Sherwin and Lia are playing bumper car at town fair. Sherwin and hi cart have a ma of 150 kg. Lia and her cart have a ma of 95 kg. Sherwin i topped when Lia, moving at a velocity of 12 m/, collide with him. If Lia come to a complete top after the colliion, then what i Sherwin' reulting velocity after the colliion?
Sherwin's resulting velocity after the collision is 18.94m/sec. if his initial velocity is 12m/sec and mass of 150kg.
It is given that Sherwin has initial velocity and Lia is going to start the bumper car. It means that initial velocity of Sherwin is 12m/sec and initial velocity of Lia is 0m/sec. Since, the collision is elastic, it means that energy will not lost during the collision and momentum will remain conserved.
So, applying the law of conservation of momentum which is
Initial momentum =Final momentum
=>Initial momentum of Sherwin is=mass × velocity
=>Initial momentum of Sherwin=150 × 12m/sec
Now, initial momentum of Lia is =mass × velocity
=>Initial momentum of Lia is =95×0=0m/sec
Now, final momentum of Sherwin=0m/sec since collision is elastic
Also, final momentum of Lia is =95×v
According to the formula, we get
=>150 × 12 +0 =0 + 95×v
=>95×v=150 × 12
=>v=(150 × 12)/95
=>v=1800/95
=>v=18.94m/sec
Hence, Sherwin velocity is 18.94m/sec.
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for a particular process q = –17 kj and w = 21 kj. which of the following statements is false?
The statement 'the system does work on surroundings' is false because the work done is a positive quantity.
This question can be answered using the first law of thermodynamics.
The First Law of Thermodynamics is a thermodynamic adaptation of the law of conservation of energy. "The overall energy in a system remains constant, even when it may be transformed from one form to another," says one basic expression. Another typical phrase is "energy cannot be generated or destroyed" (in a "closed system"). While there are other nuances and consequences that may be better conveyed in more sophisticated formulations, this is the fundamental premise of the First Law.
According to first law,
U= Q+W
U: internal energy of the system
Q: amount of heat
W: work done
Q= -17 kJ, W= 21 kJ
If Q is positive it means heat flows into the system. If Q is negative it means heat flows out of the system.
In the given question heat s negative which means heat flows into the system.
Work done is positive hence work is done on the system.
U= Q+W
U= -17+21= 4kJ
This is an exothermic process since Q is negative.
Complete question:
For a particular process q = –17 kj and w = 21 kj. Which of the following statements is false?
a) heat flows from the system to the surrounding
b) the system does works on the surrounding
c) U= +4kJ
d) the process is exothermic
e) none of the above is false
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PLEASE HELP!!
If the heat that is released is 450 J what is the heat absorbed if the efficiency of the engine is 55%?
-7.18 J
1000 J
-1000 J
8.18 J
If possible can you also explain how you got the answer?
The heat absorbed if the efficiency of the engine is 55% is determined as 1,000 J.
What is the heat absorbed by the system?The heat absorbed by the system is the positive heat gain by the system or the useful energy of the system.
From the fist law of thermodynamics, when heat is added to a system or absorbed by the system, the system gains heat.
Mathematically, the first law of thermodynamics is given as;
ΔU = q + w
where;
ΔU is the change in internal energy of the systemq is the heat added to the systemw is the work done on the systemThe heat absorbed by the system is calculated as follows;
q = ΔH / ( 1 - e )
where;
e is the efficiency of the system = 55 % = 0.55q = 450 J / ( 1 - 0.55 )
q = 450 J / 0.45
q = 1,000 J
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atp is considered a high-energy molecule. when atp undergoes hydrolysis to adp, how much energy is produced?
a. 7.3 kcal/mole is required
b. 14.6 kcal/mole is released
c. 7.3 kcal/mole is released
d. 21.9 kcal/mol is released
The molecule ATP is regarded as having great energy. Energy is generated at a rate of 7.3 kcal/mol during the hydrolysis of ATP to ADP.
To keep the cell running continually, ATP must be replenished. Normally, ATP is present in cells in concentrations of 1 to 10 uM.
Describe hydrolysis.
When chemicals and water interact chemically, the result is hydrolysis, which decomposes both the material and the water.
Reactions involving salts, carbohydrates, proteins, lipids, etc. can undergo hydrolysis.
In catabolic processes, organic materials are typically hydrolyzed with the aid of enzymes.
Polysaccharides are broken down into monosaccharides, glycerol and fatty acids into lipids, and amino acids into proteins.
Hydrolysis is regarded as a crucial phase in the breakdown of silicate and aluminosilicate glasses, ceramics, and minerals because it destroys the bond network in silicates.
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A worker pushes a 22.0 kg barrel, giving it an initial velocity of 6.8 m/s. Calculate the displacement of the barrel before it stops if the force of friction acting on the barrel is 36 N.
Answer:
14 m
Explanation:
The force of friction has to do work equal to the barrel's kinetic energy for the barrel to stop.
work = f * d and KE = 1/2 mv^2
36 N * d = 1/2 (22 kg)(6.8 m/s^2)
d=~ 14 meters
which of these correctly compares the masses of different objects in the universe?
A moon has more mass than the planet it circles and less mass than a star.
Do planets have a greater mass than stars?
By this definition, "stars" must be larger than planets in terms of mass. The size of a white dwarf would be comparable to that of a moon or small planet, but its mass would be approximately 200–1300 times that of Jupiter. Even more extreme are neutron stars, which are about the size of an asteroid but have a mass of several thousand Jupiters.
Why is the weight of the same object different on different planets Class 7?
The weight of an object is determined by its mass and the gravitational force that it experiences. The separation between two objects affects how strong gravity is. Because of this, an object weights differently on many planets.
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suppose that the pendulum bob is suspended from a light flexible cord instead of a stiff rod. now what is the minimum value of v such that the pendulum bob will swing through a complete vertical circle?
The particle's minimum speed required to complete the vertical circular motion at the highest position is (g r). As a result, tension can be zero at its peak.
When a body circles in a vertical circle in such a way that its motion at different points differs, the motion is said to be vertical circular motion. Consider an object of mass m tied at one end of an int extensible string and whirling in a vertical radius of radius r. It is written as FC = mv2 /r. The centripetal force of an object attached to a string moving in a vertical circular motion is the sum of the object's weight (mg) and the tension in the thread.
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which will have the greater acceleration rolling down an incline: a hoop or a solid disk? why?
Answer: Solid disk have the greater acceleration than the hoop.
Explanation:The body will have the maximum implicit energy at theThe body will have the maximum implicit energy at the top, but as the body rolls down the aeroplane , its implicit energy thresholds transubstantiating into translational and rotational kinetic energy. The body which will have a advanced moment of indolence will have advanced rotational kinetic energy and lower translational kineticenergy.However, also a circle has a lesser moment of indolence than a solid fragment, If we consider the case of a circle and a solid fragment. So the final speed of the circle is lower than the solid fragment. Acceleration will be the change in speed. So the acceleration of the solid fragment will be advanced than the circle. top, but as the body rolls down the aeroplane , its implicit energy thresholds transubstantiating into translational and rotational kinetic energy. The body which will have a advanced moment of indolence will have advanced rotational kinetic energy and lower translational kineticenergy.
However, also a circle has a lesser moment of indolence than a solid fragment, If we consider the case of a circle and a solid fragment. So the final speed of the circle is lower than the solid fragment. Acceleration will be the change in speed. So the acceleration of the solid fragment will be advanced than the circle.
earth is closer to the sun in january than in july. therefore, in accord with kepler’s second law:
Earth is closer to the sun in january than in july. therefore, in accord with Kepler’s second law: Earth travels faster in its orbit around the sun in january than in july.
In January, Earth orbits the sun more quickly than in July. According to Kepler's second law, planets cover equal regions in equal amounts of time. Because the Earth is nearer the Sun in January than it is in July, it must move around its orbit more quickly in January than it does in July in order to cover the same area in the same period of time.
Kepler's Law:-
According to Kepler's First Law, the Sun is one of the two foci of an elliptical planet's orbit.according to Kepler's Second Law, A line segment connecting a planet to the Sun sweeps away equal areas at equal times.Simply said, the planet moves faster as it gets closer to the sun and slower as it moves away from the sun.
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1. a million kg asteroid is in the asteroid belt. a 50000 kg chunk of rock floats 400m away. what is the force of gravity between the two asteroids?
The force of gravity between the two asteroids will be 125 *10^6 n
From the data,
The mass of the first asteroid is = 1 million kg = 1000000 Kg.
The mass of the second asteroid is = 50000 Kg.
The distance between both the asteroids = 400 m
We know,
The force of gravity between two objects can be determined by using the relationship
[tex]F_g=\frac{M_1M_2}{d}[/tex]
So, for determining the value of the force of gravity we will put the value of m1, m2 and d in the above formula:
Thus we will get:
[tex]F_g=\frac{1000000\times 50000}{400}=125,000,000=125\times 10^6\:N[/tex]
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suppose earth orbited the sun in 6 months rather than 1 year but had the same rotational period how much longer would a solar day be than sidereal day
A solar day is 0.50001917 times longer than a sidereal day if the earth's orbital period is shortened to six months.
Earth, what is it?Earth is just a rocky, earthy planet and is home to us. There are mountains, valleys, canyons, plains, and much more on its stable and dynamic surface. Being an ocean planet, Earth is unique. The Earth's surface is 70% covered by water.
Briefing:1 Sidereal year = 365.256 days
1 Solar year (1 tropical year) = 365.242 days
The length of time inside a sidereal year is equal to 365.256/2 days, or 182.628 days, if the earth's orbital period is six months.
1 Solar day = 182.256/365.242 sidereal days
1 Solar day = 0.50001917 sidereal day
A solar day is 0.50001917 times longer than a sidereal day if the earth's orbital period is shortened to six months.
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The complete question is-
Solar and Sidereal Days. Suppose Earth orbited the Sun in 6 months rather than 1 year but had the same rotation period. How much longer would a solar day be than a sidereal day? Explain.