Cai drove 189 miles in 7 hours. If he continued at the same rate, how far would he travel in 12 hours?

The solution is Option B , Option D , Option E

The athletes with speeds 20m/s and 30m/s will meet at every minute

What is Speed?

Speed is defined as the rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude

Speed = Distance / Time

Given data ,

Let the equation be represented as A

Now , the value of A is

The distance of the track is D = 600 m

Let the first athlete be A

Let the second athlete be B

The speed of A = 20 m/s

The speed of B = 30 m/s

The time taken by A to complete 600 m = 600 / 20 = 30 seconds

The time taken by B to complete 600 m = 600 / 30 = 20 seconds

Now , the time at which A and B will cross each other is the LCM of their respective time

So , The LCM of 20 and 30 is = 60 seconds

Therefore , the athletes will meet together at every 60 seconds or every 1 minute

Hence , the athletes will meet at every minute

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∠8 is the corresponds with ∠3.

Hence, option B is the correct answer.

Congruent angles are those that correspond. Corresponding pairs are all angles that are positioned in relation to the parallel and transversal lines in the same way. When two parallel lines are intersected by another line, comparable angles are the angles that are created in matching corners or corresponding corners with the transversal (i.e. the transversal).

we know that

m∠3=m∠8 --------> by corresponding angles

m∠7=m∠8 -------> by vertical angles

so

m∠3=m∠7 -------> by alternate interior angles

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NOTE: The given question is incomplete on the portal. Here is the complete question.

QUESTION: Which angle corresponds to ∠3?

A) ∠6

B) ∠8

C) ∠1

D) ∠7

The answers reasonably approximates the requested value of the sample mean with justification is c. "Bar-w"=13.70 since we can use a normal approximation by the CLT.

Since the sample size is large (n=50), we can use the central limit theorem (CLT) to approximate the sampling distribution of the sample mean with a normal distribution.

The mean of the sampling distribution of the sample mean is equal to the mean of the population, which is 13 feet in this case. The standard deviation of the sampling distribution of the sample mean is equal to the standard deviation of the population divided by the square root of the sample size. This is known as the standard error of the mean, and is denoted by SE(Bar-W).

In this case, SE(Bar-W) = 2.4/sqrt(50) = 0.48.

To find the 98th percentile of a normal distribution with mean 13 and standard deviation 0.48, we can use a standard normal table or a calculator to find that the 98th percentile is approximately 2.05.

Therefore, the value that 98% of samples will have the realized value of Bar-W less than is approximately 13 + 2.05 * 0.48 = 13.70. This means that the correct answer is (c) "Bar-w"=13.70 since we can use a normal approximation by the CLT.

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Answer:

the answer is 10 degrees Celsius

50 Degrees Fahrenheit is 10 degrees Celsius.

Here is the formula

(50°F − 32) × 5/9 = 10°C

The expression that is equivalent to the given expression, (8×10−2) (2.4×10−3), is 1.92 × 10⁻⁴

From the question, we are to determine the expression that is equivalent to the given expression

From the given information,

The given expression is

(8×10−2) (2.4×10−3)

First, we will write this expression properly

The given expression written properly is

(8 × 10⁻²)(2.4 × 10⁻³)

Now, we will evaluate the expression

Evaluating the expression

(8 × 10⁻²)(2.4 × 10⁻³)

8 × 2.4 × 10⁻² × 10⁻³

19.2 × 10⁻⁵

= 1.92 × 10⁻⁴

Hence, the expression is 1.92 × 10⁻⁴

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Answer: 2 times 2 times 2 times 2 times 3 times 3

Step-by-step explanation:

The length of the arc is 10.47 units

From the question, we have the following parameters that can be used in our computation:

Radius = 10

Angle = π/3

The length of the arc can be calculated using

Arc length = Radius * Angle

Substitute the known values in the above equation, so, we have the following representation

Arc length = 10 * π/3

Evaluate

Arc length = 10.47

Hence, the arc length is 10.47

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Answer:

BAG 1 IS BETTER. IT IS BETTER TO PAY $18 FOR 12 POUNDS OF CAT FOOD.

Step-by-step explanation:

To find the unit cost, we need to know how much one pound of cat food cost for each bag

Bag 1

It said you get 12 pounds for $18

Divide $18 by 12 to find how much ONE pound is.

18 ÷ 12 = 1.5

ONE POUND COST   $1.5  

This is the unit cost

Let's do the same for the other bag of cat food!

Bag 2

Divide $24 by 15

24 ÷ 15 = 1.6

ONE POUND COST   $1.6

This is the unit cost

It is better to pay for $1.5 per pound because it is LESS than $1.6

You will save money this way.

BAG 1 IS BETTER. IT IS BETTER TO PAY $18 FOR 12 POUNDS OF CAT FOOD.

Let x be the length of the shorter wall of the rectangular room and y be the length of the longer wall of the rectangular room. Since the longer wall is 7 ft longer than the shorter wall, we can write the equation y = x + 7. We can also express the diagonal of the rectangular room using the Pythagorean theorem as x^2 + y^2 = 13^2. We can solve for x and y by substituting the equation y = x + 7 into the equation x^2 + y^2 = 13^2 and then solving for x. Doing this, we get x^2 + (x + 7)^2 = 13^2. Expanding the square on the right side of the equation and then rearranging the terms, we get x^2 + 2x^2 + 14x + 49 = 169. Combining like terms, we get 3x^2 + 14x - 120 = 0. This quadratic equation can be factored as (x - 8)(3x + 15) = 0. Since the length of a side of a rectangle must be positive, we can ignore the solution x = -15/3. So, the length of the shorter wall of the rectangular room is x = 8 ft. The length of the longer wall can be found by substituting this value into the equation y = x + 7, giving us y = 8 + 7 = 15 ft. Therefore, the dimensions of the rectangular room are 8 ft by 15 ft.

A shape's highest possible area is called its maximum area.The size of the rectangle that will result in the greatest area is 4 by 2 units.

The equation is given as:

x + 2y - 8 = 0

Rewrite as:

2y = 8 - x

Divide both sides by 2,

y =  [tex]\frac{8 - x}{2}[/tex]

y = 4 - [tex]\frac{x}{2}[/tex]

The area (A) of the rectangle is:

A = xy

Substitute

y = 4 - [tex]\frac{x}{2}[/tex]

A = x[tex](4 - \frac{x}{2})[/tex]

Expand

A = 4x - [tex]\frac{x^{2} }{2}[/tex]

Differentiate

A' = 4 - x

Set the derivative to 0,

4 - x = 0

Collect like terms

x = 4

Recall that:

y = 4 - [tex]\frac{x}{2}[/tex]

Substitute 4 for x,

y = 4 - [tex]\frac{4}{2}[/tex]

y = 4 - 2

y = 2

So, we have:

x = 4 and y = 2

Hence, the dimension of the rectangle that will produce the maximum area is 4 units by 2 units.

The complete question is:

A rectangle is inscribed in the region bounded by the x-axis, the y-axis, and the graph of x+2y-8=0. Approximate the dimensions of the rectangle that will produce the maximum area.

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The function y= f(x)= [tex]x^{3}+3x-1[/tex] and a= -5 the real number is [tex]\frac{1}{6}[/tex].

y= f(x)= [tex]x^{3}+3x-1[/tex] and a= -5.

The slope of inverse functions are reciprocals at their corresponding points that is,

[tex]f^{-1}'(a)=\frac{1}{f'(b)}[/tex]

Where, [tex]f^{-1}'(a) = b[/tex] and f(b) = a

Now, determine the value of b for a= -5 using f(x)=[tex]x^{3}+3x-1[/tex]

f(b) = a

[tex]b^{3}+3b-1=-5[/tex]

[tex]b^{3}+3b= -4[/tex]

[tex]b = -1[/tex]

Therefore, [tex]f^{-1}'(a) = \frac{1}{f'(b)}[/tex]

[tex]f^{-1}'(-5)=\frac{1}{f'(-1)}[/tex]

Now, find f'(x) and evaluate it at

x= -1

f(x)=[tex]x^{3}+3x-1[/tex]

[tex]f'(x)= 3x^{2}+3[/tex]

f'(x)= [tex]3(x^{2} +1)[/tex]

then, f'(-1)= 3(1+1) = 6

Therefore, [tex]f^{-1}(-5)=\frac{1}{f^{-1}(-1)}=\frac{1}{6}[/tex].

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The expected value E(X) is 7 and the value of variance of X is 5.8333.

Two dice are rolled. Let X be the random variable measuring the sum of the two numbers rolled.

a) The probability of mass function is obtained below:

The possible outcomes in each of the dice are 1 to 6. Therefore, the possible outcomes when two dice is rolled is 36

The sample space, s for fair dice (red die and blue die) is given below:

N(s) = 36

From the given information, two dice are rolled let X be the random variable measuring the sum of the two numbers rolled.

b) The expected value is calculated below:

The probability mass function of X is,

The required mean is,

E(x) = ∑xP(X=x)

[tex]=[2[/tex]×[tex]\frac{1}{36}+3[/tex]×[tex]\frac{2}{36}[/tex]+....+11×[tex]\frac{2}{36}+12[/tex]×[tex](\frac{1}{36} )[/tex]]

=[0.0556+0.1667+0.3333+0.5556+0.8333+1.1111+1.000+0.8333+0.6111+0.3333

=7

C) The variance V(X) is calculated below:

The probability mass function of X is,

The required variance is,

V(x)= ∑[tex](X-x)^{2}P(x) = 5.8333[/tex]

Therefore, the expected value E(X) is 7 and the value of variance of X is 5.8333.

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Answer: 11.35

Step-by-step explanation: The residual for the rideshare cost with a distance of 16 miles can be calculated using the equation of the least-squares regression line and the observed fare for that distance. The residual is defined as the difference between the observed value and the predicted value.

To find the predicted fare for a distance of 16 miles, we can substitute 16 for x in the equation of the least-squares regression line: ý = 5.20 + 2.33x. This gives us ý = 5.20 + 2.33 * 16 = 42.49.

The observed fare for a distance of 16 miles is 53.84, so the residual is 53.84 - 42.49 = 11.35. Therefore, the answer is 11.35.

Answer: -32

Step-by-step explanation:

To solve the equation -128 = 4x for x, we need to isolate the x variable on one side of the equation. We can do this by dividing both sides of the equation by 4. This gives us:

-128/4 = 4x/4

Dividing -128 by 4 gives us -32, so we have:

-32 = 4x/4

We can simplify this by dividing both sides by 4/4 to get:

-32 = x

Thus, the solution to the equation -128 = 4x is x = -32.

Answer:

A. Reflection

Step-by-step explanation:

I believe the answer would be reflection

The domain is the set of all values in the set (- ∞, ∞).

Function : In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function

Expression : A mathematical expression is made up of terms (constants and variables) separated by mathematical operators

Equation : A mathematical equation is used to equate two expressions.

Given is a quadratic function as follows -

ax² + bx + c

For any quadratic equation (with vertex at origin), the value of [y] or the range is either the set of all positive values from 0 to infinity when the quadratic function open upwards and  the set of all negative values from 0 to -infinity when the quadratic function open downwards. The domain is the set of all values in the set (- ∞, ∞).

Therefore, the domain is the set of all values in the set (- ∞, ∞).

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{Question in english language is as follows -

How the domain of the quadratic function is determined.}

Answer:

  x = 16 1/3°

Step-by-step explanation:

You have parallel lines with consecutive interior angles marked 7x-28° and 5x+12°, and you want to find the value of x.

At parallel lines, consecutive interior angles, or same-side interior angles, are supplementary. This means the total of the two marked angles is 180°.

  7x -28° +5x +12° = 180°

  12x -16° = 180° . . . . . . . . . . simplify

  12x = 196° . . . . . . . . . add 16°

  x = (49/3)° = 16 1/3° . . . . . . . divide by 12

__

Additional comment

∠3 = 86 1/3°

∠5 = 93 2/3°

The measures of the angles of a triangle are 76⁰, 41⁰, and 63⁰.

What is Angle Sum Property?

The sum of all angles of a triangle is equal to the angle of a straight line i.e. 180°. If we have a triangle ABC, then the Sum of angles A , B, and angle C will be 180 ° and the value of the exterior angle is equal to the sum of two interior opposite angle.

We have,

The measures of the angles of a triangle are:

x,

76⁰,

41⁰.

so, we have to calculate the value of the x⁰:

The sum of all the angles in the triangle is 180⁰

so,

to calculate the measure of x put the all values in equation such that using the above rule:

x + 76⁰ + 41⁰ = 180⁰

x = 180⁰ -  76⁰ - 41⁰

x =  63⁰

Hence, the measures of the angles of a triangle are 76⁰, 41⁰, and 63⁰.

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This sequence is not convergent because the nth term does not approach a single limit as n approaches infinity. The limit does not exist, so the answer is DNE.

This sequence does not converge to a single limit because the nth term of the sequence, an, has a coefficient of n, which means that the value of an increases without bound as n increases. This means that the value of an does not approach a single limit as n approaches infinity, and so the limit does not exist. Therefore, the answer for the limit as n approaches infinity is DNE.

This sequence does not converge to a single limit because the nth term of the sequence, an, has a coefficient of n, which means that the value of an increases without bound as n increases. As n increases, the value of an increases, and so the value of an does not approach a single limit as n approaches infinity. This means that the limit does not exist, and so the answer for the limit as n approaches infinity is DNE.

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The number of  caramel apples that are covered with sprinkles is; 20

We are given;

Total number of caramel apples to sell = 120

1/5 of the caramel apples are covered with peanuts.

1/3 of the caramel apples are covered with chocolate chips.

3/10 of the caramel apples are covered with coconut.

The rest are covered with sprinkles.

Let 'n' be the number of caramel apples are covered with sprinkles. Thus, we can develop the equation as;

120 = (1/5 * 120) + (1/3 * 120) + (3/10 * 120) + n

120 = 24 + 40 + 36 + n

n = 120 - 100

n = 20

Which means that 20 are those covered with sprinkles

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Complete question is;

Maya has 120 caramel apples to sell. Each caramel apple is covered with one topping.

1/5 of the caramel apples are covered with peanuts.

1/3 of the caramel apples are covered with chocolate chips.

3/10 of the caramel apples are covered with coconut.

The rest are covered with sprinkles.

How many caramel apples are covered with sprinkles?

The distribution of Z = X/Y is  λ₁ / (λ₁+λ₂).

The probability distribution of random variables is described using the cumulative distribution function. The probability for a discrete, continuous, or mixed variable may be described using it. The cumulative probability for a random variable is calculated by adding the probability density function.

Given:

X and Y are independent exponential random variables with respective parameters λ₁ and λ₂.

To find the distribution of Z = X/Y:

First, we have

[tex]f_x_y[/tex](x,y) = λ₁λ₂[tex]e^{-\lambda_1x[/tex][tex]e^{-\lambda_2y[/tex]

First, we find the cumulative distribution function (CDF) for Z = X/Y.

Derivative of Z, f(z) and put  a = x/y

[tex]F_z[/tex](a)  = P (X/Y ≤ a)

        = P (X ≤ aY)

        = [tex]\int\limits^{\infty}_ {x} \ \int\limits^{ay}_0 {\lambda_1\lambda_2e^{-\lambda_1x}e^{-\lambda_2y}\ dx dy[/tex]

       [tex]= \int\limits^{\infty}_ {0} {\lambda_1\lambda_2e^{-\lambda_2y}\ dy [ -1/{\lambda_1}{e^{-\lambda_1x}]\limits^{ay}_ {0}[/tex]

       [tex]= \lambda_2\int\limits^{\infty}_ {0} {e^{-\lambda_2y} - e^{-y(\lambda_2 + \lambda_1a)} \ dy[/tex]

        [tex]= \lambda_2[ [{1/{\lambda_2}+{\lambda_1a]-{e^{-\lambda_2y} + e^{-y(\lambda_2 + \lambda_1a)}]\limits^{\infty}_ {0}[/tex]

        [tex]= -[({\lambda_2}/{\lambda_2 + \lambda_1) - 1][/tex]

        [tex]= -[({\lambda_2}/{\lambda_2 + \lambda_1a) - 1][/tex]

       [tex]= [({\lambda_1a}/{\lambda_2 + \lambda_1a)][/tex]

So, P(X<Y) = P (X/Y <1)

                 = λ₁ / (λ₁+λ₂)

Therefore, distribution is λ₁ / (λ₁+λ₂).

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a.) The amount that Sammy will have in his account after 10 years will be= $2,165.8

$2,165.8b.) The value of 'r' required would be = 0.27%

Interest rate is defined as the rate at which an individual receives an amount of money from an investment made over a period of time.

The amount invested by Sam(P) = $1700

The interest rate(R) = 2.74%

The time of investment (T) = 10 years

Simple interest = P×T×R/100

= 1700×10×2.74/100

= 46580/100

= $465.80

Therefore, the amount that Sammy will have in his account after 10 years will be = $1700 + $465.80

= $2,165.8.

For David's account interest rate the following is carried out:

The amount invested by Sam(P) = $1700

The interest rate(R) = r%

The time of investment (T) = 10 years

Simple interest (SI) = $465.80

Using the formula for simple interest;

SI = P×T×R/100

Make R the subject of formula;

R = SI×100/P×T

R = 465.80×100/1700×100

R= 46580/170000

R= 0.27%

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Complete question:

Sam invests $1700 in a saving account that pays a nominal annual rate of interest of 2.74% compounded half-yearly. Sam makes no further payments to, or withdrawals from, this account. (a) Find the amount that Sam will have in his account after 10 years.

David also invests $1700 in a savings account that plays an annual rate of interest of r%, compounded yearly. David makes no further payments or withdrawals from this account. (b) Find the value of 'r' required so that the amount in David's account after 10 years will be equal to the amount in Sam's account.

Answer:

the answer is 90 mins option b

Step-by-step explanation:

Answer:

the answer is 90 minutes or B

hope this helps

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Step-by-step explanation:

James owns just 5% of the company after the investment.

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

Percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%".

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100. It is given by:

Percentage = (value / total value) * 100%

How to find the Percentage owned by James;

James' investment: $10,000

The other 3 people invested;

x = $10,000

y = $10,000

z = $10,000

Total investment made was = $200,000

James' Percentage = [tex]\frac{10000}{200000\\}[/tex] x 100

James' Percentage = 5%

So, we can say that James owns 5% of the total investment in the business.

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Answer:

Area = 12a m²

Step-by-step explanation:

Given information,

→ Length = 4a m

→ Width = 3a m

Now we have to,

→ find the area of rectangular park.

Formula we use,

→ Area = L × W

Then the area of rectangle is,

→ L × W

→ 4a × 3a

→ (4 × 3)a

→ 12a m²

Therefore, the area is 12a m².

The graph of a quadratic function is called a parabola

The complete table is

x = -6, -3, 0, 3 6

y = -12  -3 0 -3 -12

From the question, we have the following equation that can be used in our computation:

y=-1/3 x²

From the table of values , we have the following x values

x = -6, -3, 0, 3 and 6

Substitute x = -6, -3, 0, 3 and 6 in y=-1/3 x²

So, we have the following representation

y = -1/3 (-6)² = -12

y = -1/3 (-3)² = -3

y = -1/3 (0)² = 0

y = -1/3 (3)² = -3

y = -1/3 (6)² = -12

So, the complete table of values is

x = -6, -3, 0, 3 6

y = -12  -3 0 -3 -12

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The graph of x-3y = 12 is given.

A graph is a visual representation or diagram that displays facts or values in an organized manner in mathematics. The points on a graph are typically used to depict the relationships between two or more things.

The equation is

x-3y = 12.

The graph of this line intersects the x-axis and y-axis.

And end behavior is infinity on both positive and negative.

And the graph is a straight line graph.

Therefore, behavior of x -3y = 12 is given in the graph.

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On solving the provided question, From the question, our region is defined by: lower bound: y= [tex]x^2[/tex] and upper bound: y = [tex]\sqrt{x}[/tex]

Integrals are mathematical representations of numbers and functions that express notions such as volume, area, displacement, and other outcomes of the combination of little data. Finding integrals is the term used to describe the procedure.

By green's theorem -

[tex]\int\limits^{}_{} {} \, \int\limits^{}_{a} {5dA} \, = 5/3[/tex]

First, the integral given in this exercise corresponds to:  

[tex]\int\limits^{}_{C} {((3y + 7e\sqrt{x}dx) +( 8x+ 5cos(y^2)) } \, dy[/tex]

Greens Theorem given as,

[tex]\int\limits^{}_{C} {(P(x,y)dx +Q(x,y)dy)} \, = \int\limits^{}_{} {x} \, \int\limits^{}_a {(-\beta /\beta _{y} )P(x,y) + (\beta /\beta _{y} )Q(x,y)} \, dA[/tex]

and we have -

P(x,y) = 3y + [tex]7e^{\sqrt{x}}[/tex]

Q(x,y) = 8x + 5cos([tex]y^2[/tex])

And,

[tex]\int\limits^{}_{C} {(P(x,y)dx +Q(x,y)dy)} \, = \int\limits^{}_{} {x} \, \int\limits^{}_a {5dA} \, dA[/tex]

From the question, our region is defined by:

lower bound: y= [tex]x^2[/tex]

upper bound: y = [tex]\sqrt{x}[/tex]

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Answer:

21 m/ph

Step-by-step explanation:

2016 divided by 96

The balloon travels 21 miles in one hour.

In mathematics, division is one kind of operation. The phrases or numbers in this process are split into the same number of parts.

Given, a hot air balloon travels 2016 miles in 96 hours.

And the balloon travels the same number of miles each hour.

To find the same numbers of miles per hour:

We use the division of 2016 by 96.

That means,

2016 / 96

= 21

Therefore, the travel time of the balloon is 21 miles per hour.

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Option C, The research situation that would be most likely to use an independent-measures design is to compare the mathematics skills of 9th-grade boys versus 9th-grade girls.

An independent-measures design is used when there are two or more groups that are being compared and each individual only belongs to one group. In this research situation, the two groups being compared are 9th-grade boys and 9th-grade girls. Each individual in the study belongs to one group or the other, and they are not part of both groups. This makes it an ideal situation for using an independent-measures design.

Option a) examine the development of vocabulary as a group of children mature from age 2 to age 3 would likely use a within-subjects design, as the same group of children is being measured at two different time points.

Option b) Examining the long-term effectiveness of a stop-smoking treatment by interviewing subjects 2 months and 7 months after the treatment ends would also likely use a within-subjects design, as the same group of subjects is being measured at two different time points.

Option d) compare the blood-pressure readings before medication and after medication for a group of patients with high blood pressure would likely use a repeated-measures design, as the same group of patients is being measured at two different time points and the order of the measurements (before or after medication) is being controlled.

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