C++ coding, help
In this program you will be reading numbers from a file. You will validate the numbers and calculate the average of all of the valid numbers.
Your program will read in a file with numbers. The numbers will be of type double.
The numbers should be in the range from 0 to 110 (inclusive). You need to count all of the numbers between 0 and 110. You also need to calculate the average of these numbers.
If a number is not valid (that is, it is less than 0 or greater than 110) you need to count it (as a count of invalid values) and you need to write out the number to a file called "invalid-numbers.txt". Values written to file invalid-numbers.txt should be in fixed format with two digits to the right of the decimal point.
As you did in lab lesson 7 part 1 you need to read in the input file name using cin.
The output from your program will be written to cout. The output must contain the file being processed, the total number of values read in from the file, the number of invalid values read in, the number of valid values read in.
The last thing you need to output is either the average of the valid values or an error message. The average must have two digits of precision to the right of the decimal point and must be in fixed format. If there is not valid average you should output the message:
An average cannot be calculated
In what case would you display this message?
If the input file cannot be opened, you will need to output a message. Assume the input file name is badinput.txt and it cannot be opened. You will display the following error message to cout
File "badinput.txt" could not be opened
Here is an example of a working program:
Assume the file name read in from cin is:
input.txt
and that input.txt contains:
-12
0
98.5
100
105.5
93.5
88
75
-3
111
89
-12
Your program would output the following:
Reading from file "input.txt"
Total values: 12
Invalid values: 4
Valid values: 8
Average of valid values: 81.19
The contents written out to file invalid-numbers.txt are:
-12
-3
111
-12
You are reading from an input file and you are writing to an output file. Make sure you close both files after you are finished using them. You must do this in your program, you cannot just let the operating system close the files for you.
For tests where there is output written to an output file the contents of the output file will determine if you passed that test or not. For cases where you have written out to cout the tests will check the output sent to cout. In some cases output will be written to a file and to cout. When this is the case the test will be run twice with the same input. Once to test cout and once to test the contents of the output file. An example of this would be tests 2 and 3. Both use the same input file. Test 2 check the output written to cout and test 3 checks the output written to the file invalid-numbers.txt.

Answer:

The program in C++ is as follows:

#include <fstream>

#include <iostream>

#include <iomanip>

using namespace std;

int main() {

 string filename;

 cout<<"Filename: ";

 cin>>filename;

 ifstream inFile(filename);

 if(!inFile) {

   cout << endl << "Cannot open file " << filename;

   return 1;  }  

 ofstream fout;

 ifstream fin;

 fin.open("invalid-numbers.txt");  

 fout.open ("invalid-numbers.txt",ios::app);  

 double sum = 0; int valid = 0; int invalid = 0;

 double num = 0;

 while(!inFile.eof()) {

   inFile >> num;

   if(num >= 0 && num<=110){   sum+=num; valid++; }

else{ invalid++;

if(fin.is_open()){

   fout<<fixed<<setprecision(2)<<num<<"\n";    }  }  }

 fin.close();

 fout.close();

 inFile.close();

 cout<<"Total values: "<<valid+invalid<<endl;

 cout<<"Invalid values: "<<invalid<<endl;

 cout<<"Valid values: "<<valid<<endl;

 cout<<"Average of valid values: "<<fixed<<setprecision(2)<<sum/valid<<endl;    

 double inv;

 ifstream inFiles("invalid-numbers.txt");

 while(!inFiles.eof()) {

   inFiles >> inv;

   cout<<inv<<"\n";

}

inFiles.close();

 return 0;

}

Explanation:

See attachment for source file where comments are used to explain each line

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Rick is a fan of logic-based games. However, he is bored of the classic ones, like Sudoku and Mastermind, since he has solved so many of them. Recently he found a new game in which one is given a string with some question marks in it. The objective is to replace all of the question marks with letters (one letter per question mark) in such a way that no letter appears next to another letter of the same kind.
Write a function:
def solution(riddle)
that, given a string riddle, returns a copy of the string with all of the question marks replaced by lowercase letters (a-z) in such a way that the same letters do not occur next to each other. The result can be any of the possible answers as long as it fulfils the above requirements.
Examples:
1. Given riddle = "ab?ac?", your function might return "abcaca". Some other possible results are 'abzacd", "abfacf".
2. Given riddle = "rd?e?wg??", your function might return "rdveawgab".
3. Given riddle = "????????", your function might return "codility".
Write an efficient algorithm for the following assumptions:
• the length of the string is within the range [1..100,000);
• string riddle consists only of lowercases letters (a - z) or '?';
• it is always possible to turn string 'riddle' into a string without two identical consecutive letters.
1 # you can write to stdout for debugging purposes, e.g.
2 # print("this is a debug message")
3
4 def solution (riddle):
5
6 # write your code in Python 3.6
7 pass

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Python program
You are given the following text file called Mytext.txt. Write a Python function called search_file that accepts the name of the file (i.e. filename) and a string to look for in the file (i.e. mystring) as parameters. The function then looks for mystring in the file. Whenever it finds the string in a line, it saves the line number and the text for that line in a dictionary. Finally, it returns the dictionary after reading all the lines in the file and populating the dictionary with all matching line numbers and line text. If an empty string or a blank string is passed as mystring then an empty dictionary is returned.
Sample Input: search_file("Mytext.txt","python")
Sample Input: search_file("Mytext.txt","")
Contents of Mytext.txt
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Python was conceived in the late 1980s.
Python 2.0, was released in 2000.
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def shared_motif(dna_list):
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The returned longest common substring:
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I WANT IT TO HAVE USER INPUT TO CHANGE AND IMAGE FILTER TO BLUE RED OR GREEN.


user_color = input("What color would you like to paint the canvas, blue, red or green?:")



def user_red(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]

return pixel

def user_green(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]

return pixel

def user_blue(pixel):
pixel[0] = 100 + pixel[0]
pixel[1] = 100 - pixel[1]
pixel[2] = 100 - pixel[2]

return pixel


def custom_filter(image, user_color):
for x in range(image.get_width()):
for y in range(image.get_height()):
pixel = image.get_pixel(x,y)
new_colors = invert_pixel(pixel)
image.set_red(x, y, new_colors[0])
image.set_green(x, y, new_colors[1])
image.set_blue(x, y, new_colors[2])



return image


def change_image():
global image
image = custom_filter(image, user_color)



timer.set_timeout(change_image, IMAGE_LOAD_TIME)

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Provide three constructors Complex(a, b), Complex(a), and
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Complex(a) creates a Complex object with 0 for b. Also provide
the getRealPart() and getImaginaryPart() methods for returning
the real and imaginary part of the complex number, respectively.
Your Complex class should also implement the Cloneable
interface.
Write a test program that prompts the user to enter two complex numbers and display the result of their addition, subtraction, multiplication, and division.
Here is the main class. It cannot be changed.
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the first complex number: ");
double a = input.nextDouble();
double b = input.nextDouble();
Complex c1 = new Complex(a, b);
System.out.print("Enter the second complex number: ");
double c = input.nextDouble();
double d = input.nextDouble();
Complex c2 = new Complex(c, d);
System.out.println("(" + c1 + ")" + " + " + "(" + c2 + ")" + " = " + c1.add(c2));
System.out.println("(" + c1 + ")" + " - " + "(" + c2 + ")" + " = " + c1.subtract(c2));
System.out.println("(" + c1 + ")" + " * " + "(" + c2 + ")" + " = " + c1.multiply(c2));
System.out.println("(" + c1 + ")" + " / " + "(" + c2 + ")" + " = " + c1.divide(c2));
System.out.println("|" + c1 + "| = " + c1.abs());
Complex c3 = (Complex)c1.clone();
System.out.println(c1 == c3);
System.out.println(c3.getRealPart());
System.out.println(c3.getImaginaryPart());
}
}

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d. Group policy, password history, password encryption