Bricklayer Ben places 42 bricks per hour. Bricklayer Bob places 36 bricks per hour. Bricklayer Bob worked twice as many hours as Bricklayer Ben, and the two of them placed a total of 1254 bricks. How many bricks did Bricklayer Ben place

Answers

Answer 1

Bricklayer Ben placed a total of 462 bricks.

How to use equation to find the number of bricks placed?

Bricklayer Ben places 42 bricks per hour.

Bricklayer Bob places 36 bricks per hour.

Let

x = number of hours worked by Bricklayer Bob

y = number of hours worked  by Bricklayer Ben

Therefore,

x = 2y

42y + 36x = 1254

42y + 36(2y) = 1254

42y + 72y = 1254

114y = 1254

y = 1254 / 114

y = 11

Hence,  Bricklayer Ben placed a total of 42 × 11 = 462 bricks.

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Related Questions

Simplify the following expression.

Answers

Answer:

-70x, 26y^3, -3z

Step-by-step explanation:

The way to solve this is by combining like terms. The terms we have given to us include x, y^3, and z. As a result, we will group terms based on these variables.

1. Find all the terms with each variable.

* -35x, -35x

* 23y^3, 3y^3

* -3z

2. Combine like terms.

* -35x + (-35x) = -35x - 35x = -70x

* 23y^3 + 3y^3 = 26y^3

* -3z + 0 = -3z

Answer:

Hello! The answer is: [tex]-70x - 3z + 26y^3[/tex]

Step-by-step explanation:

First, rearrange to combine like terms:

[tex]-35x - 35x - 3z + 23y^3 + 3y^3[/tex]

Now, combine like terms:

[tex]-70x - 3z + 26y^3[/tex]

A line of a slope 1/4 and passes through the point (0.2,4/5)
Find the value of b, the y-intercept.

Answers

The y-intercept of the line is 0.75 or 3/4

How to determine the y-intercept?

The given parameters are:

Slope, m = 1/4

Point (x, y) = (0.2, 4/5)

A linear equation is represented as:

y = mx + b

This gives

4/5 = 1/4 * 0.2 + b

Evaluate the product

4/5 = 0.05 + b

Subtract 0.05 from both sides

b = 0.75

Hence, the y-intercept of the line is 0.75 or 3/4

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this hyperbola is centered at the origin find its equation
foci: (-2,0) and (2,0)
vertices: (-1,0) and (1,0)

Answers

The equation of the hyperbola with foci (-2, 0), (2, 0), and vertices, (-1, 0), (1, 0) is [tex] \underline{\frac{ {x}^{2} }{ {1}^{2} } - \frac{ {y}^{2} }{ 3} } = 1[/tex]

Which method is used to find the equation of the parabola?

The general form of the equation of an hyperbola is presented as follows;

[tex] \frac{ {x}^{2} }{ {a}^{2} } - \frac{ {y}^{2} }{ {b}^{2} } = 1[/tex]

Where a is obtained from the vertex written as (-a, 0), (a, 0)

The given vertex are (-1, 0), (1, 0), which gives;

a = 1

The general form of the foci of a hyperbola are; (-c, 0), (c, 0)

The given foci of the hyperbola are; (-2, 0), (2, 0)

Where;

c² = a² + b²

Therefore;

b² = c² - a²

By comparison, we have;

c² = 2²

Which gives;

b² = 2² - 1² = 3

The equation of the hyperbola is therefore;

[tex] \underline{\frac{ {x}^{2} }{ {1}^{2} } - \frac{ {y}^{2} }{ 3} } = 1[/tex]

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Dan's Dependable Delivery Given the following information calculate Dan’s Dependable Delivery’s debt ratio for two consecutive years. Show your calculations using Excel formulas. After the calculations, write a short message to Dan explaining what the ratios mean. Is there improvement? Current year Last year Total Assets $3,750,250 $3,590,750 Total liabilities $1,500,250 $1,470,000 Debt Ratio for the current year Debt Ratio for last year Message to Dan below:

Answers

Current year's debt ratio is 2.50

Last year's debt ratio is 2.44

Compute Dan's Dependable Delivery debt ratio for two consecutive years?

The debt ratio is the total liabilities divided by the total assets

The debt ratio for the current year =  2.50

The debt ratio for last year =2.44(find attached excel file and formula sheet)

Debt ratio means the portion of the firm's total assets funded using borrowing(external funding), the lower the ratio, the better since having a higher debt means a higher interest would be paid, the higher the debt, the higher the chance of the firm defaulting on paying interest and repaying the principal borrowed.

The fact that the debt ratio has increased in the current year, means that the ratio has worsened because more debt has been taken.

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PLEASE HELP GUYS!!!

which of the following is equivalent to the complex number i^38?

Answers

Answer:

The answer is C = -1

To babysit one child, Fernando charges $10 to drive to the appointment plus $4 per hour. He saves 30% of the total amount he earns. Brenna charges $6 per hour and saves 25% of the total amount she earns. Which equation can be used to determine the number of hours, h, after which Fernando and Brenna will have saved the same amount of money?
a 10 + 0.3(4h) = 0.25(6h)
b 0.3(10) + 4h = 0.25(6h)
c 0.3(10 + 4h) = 0.25(6h)
d 0.3(14h) = 0.25(6h)

Answers

Th equation that can be used to determine when they would have saved the same amount is 0.3(10 + 4h) = 0.25(6h).

When would they have saved the same amount?

The equation that can be used to determine the amount saved by Fernando is:

total amount saved = percentage saved x (amount charged to drive to the appointment + total amount earned)

0.3( $10 + $4h)

The equation that can be used to determine the amount saved by Brenna is:

percentage saved x total amount earned

0.25h

When they save the amount amount, the two above equations would be equal:  0.3(10 + 4h) = 0.25(6h).

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Find the surface area of the figure!! pls show work thank you!!! geometry!!

Answers

Answer:165

Step-by-step explanation:

please help i dont get it

Answers

Answer:

78.5

Step-by-step explanation:

pi(r^2)

3.14(5^2)

3.14(25)

78.5

pls kindly see the attached picture for the answer and explanation thank you

Explain the different ways you can name an angle how can you determine if two triangles are similar

Answers

Answer:

angle angle theorem.

Step-by-step explanation:

If you want to determine whether a few angles are similar you can use formulas such as SAS AAA ASA etc.

this means

side angle side

angle angle anlge

angle side angle

A princess has two pet dragons. The dragons can eat 300kg of chocolate in 12 days. How many days will the same 300kg last if got 4 more dragons for her birthday?

Answers

The chocolate will last for 1 day, if she gets 4 more dragons

How to determine the number of days?

The expression can be represented using the following ratio:

Ratio = Dragons : Days : Chocolate

For the 2 dragons she has, we have:

Ratio = 2 : 12 : 300

When she gets 4 more dragons, we have:

Ratio = 6 : days : 300

Equate both ratios

6 : days = 12 : 2

Express as fraction

days/6 = 2/12

Multiply both sides by 6

days = 6 * 2/12

Evaluate

days = 1

Hence, the chocolate will last for 1 day

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
A group of high school students were surveyed about which type of movie they enjoy watching most. The results are shown in the two-way
relative frequency table below.
Female
Male
Total
Comedy
64
54
118
Drama
16
6
22
Action
20
22
42
Sci-Fi
6
27.2% 57.4% 5.7%
12
18
Use the information provided in the table to match each description with the correct percentage of students.
Total
106
94
200
18.9%
6.4%
percentage of female students who prefer sci-fi
45.8% 33.3%
percentage of students who prefer comedies that are male
percentage of male students who prefer dramas
percentage of students who prefer action movies that are female
47.6%

Answers

Answer:

a) 5.7%

b) 45.8%

c) 6.4%

d) 47.6%

Step-by-step explanation:

remember, we find percentage as:

specific / total

(ex. if we have 2 dogs and 2 cats, and we want to find what percentage of total animals are dogs, we divide 2/4 to get 0.5, or 50%)

percentage of female students who prefer sci-fi

here, we know we have 106 female students (total: 106)

and we have 6 of those students who prefer sci-fi (specific: 6)

6 / 106 = 0.05660..

which we can round to: 0.0566

So, the first percentage is 5.66%

(5.7%)

percentage of students who prefer comedies that are male

we have 118 students who prefer comedies (total: 118)

and 54 of those students that are male (specific: 54)

54 / 118 = 0.4576...

which we can round to 0.4576

So, the second percentage is 45.76%

(45.8%)

percentage of male students who prefer dramas

we have 94 male students (total: 94)

and 6 who prefer dramas (specific: 6)

6 / 94 = 0.0638298...

which we can round to 0.0638

So, the third percentage is 6.38%

(6.4%)

percentage of students who prefer action movies that are female

we have 42 students who prefer action movies (total: 42)

and 20 of those who are female (specific: 20)

20 / 42 = 0.47619..

which we can round to 0.4762

So, the fourth percentage is 47.62%

(47.6%)

hope this helps! have a lovely day :)

What is the probability of obtaining in a row when flipping a​ coin?.

Answers

There are 50-50 chances that you will get a head or a tail

12. Todd graphs a quadratic function. The graph of his quadratic
function passes through the points
(-2,0), (4,0), and (0,-32). Which quadratic function could be Todd's
function?
a. y = 4x² - 8x - 32
b. y = 4x² + 8x - 32
C. y = 2x² - 16x - 32
d. y = -4x² + 8x - 32
a
b
OC
d

Answers

Answer: A

You already know that the y-intercept in -32 for every equation by plugging in 0 for x, so disregard the coordinate (0,-32). Plug in -2 and 4 as your x values and check if they are equal to your y-value 0.

y = 2x² - 16x - 32 is the quadratic function of function passes through the points (-2,0), (4,0), and (0,-32).

What is Quadratic function?

y=ax²+bx+c is called as Quadratic function

y=ax²+bx+c

The three points are (-2,0), (4,0), and (0,-32)

Let,

(-2,0) in equation

0=a(-2)²+b(-2)+c

0=-2b+c...(1)

(4,0)

0=a(4)²+b(4)+c

0=16a+4b+c..(2)

(0,-32)

-32=a(0)²+b(0)+c

c=-32...(3)

Hence put c value in (1)

0=-2b-32

2b=-32

b=-16

Now put b and c value in 2

0=16(a)+4(-16)+32

0=16a-64+32

0=16a-32

a=2

Hence y = 2x² - 16x - 32 is the quadratic function of function passes through the points (-2,0), (4,0), and (0,-32).

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need help finding this C measure

Answers

Answer:

<C = 45 degrees.

Step-by-step explanation:

This is a right triangle (indicated by the square representing <A). All angles in a triangle add up to 180 degrees

180 - 90 is 90. Knowing that there are only two angles left, you can divide 90 by 2, resulting in 45.

<C = 45.

There were three parts to Rita's race. She ran the first part, which was 4/9
of the total distance, in 20 minutes. She ran the second part, which was 2/5
of the remaining distance, in 12 minutes. She finally ran the third part in 15 minutes at a speed of 300 meter per minute.
How long was the second part of the race? What was Rita's speed in that section of the race?

Answers

Hello!

d₁ = distance covered in Part 1

d₂ = distance covered in Part 2

d₃ = distance covered in Part 3

Distance in Part 2 :

⇒ d₃ = 15 x 300 = 4500 m

⇒ d₂ = 2/5d₃

⇒ d₂ = 2/5 x 4500

⇒ d₂ = 1800 meters

Speed in Part 2 :

⇒ v₂ = 1800 m / 12 min

⇒ v₂ = 150 meters per minute

PLEASE 100 POINTS AND BRAINLIEST

Answers

Answer:

29u

Step-by-step explanation:

a = (V-U)/t = (1.2u-u)/10 = 0.02u

D1: V₀t+0.5at² = (u)(10)+(0.5)(0.02u)+(10)(10) = 11u

D2: (V)(t) = (1.2u)(15) = 18u

D = D1 + D2 = 29u

For first half

Initial velocity=uFinal velocity=v=1.2uTime=10s

We need acceleration first

a=(1.2u-u)/10a=0.2u/10a=0.02u

So distance traveled (Apply second equation of kinematics

s=10u+1/2(0.02u)(10)²s=10u+2/2×100/100×us=11u m

For second half

No acceleration

Distance=Speed×Time

1.2u(15)18u m

Total distance

D=11u+18uD=29u m

What is the multiplicative rate of change of the function?

0.2
0.25
0.5
0.75

Answers

The multiplicative rate of change of the function will be 0.5. Then the correct option is C.

What is an exponent?

Let b is the base and x is the power of the exponent function and a is the leading coefficient. The exponent is given as

y = a(b)ˣ

The missing table is attached below.

For x = 2, y will be 0.125

0.125 = ab²  ...1

For x = 3, y will be 0.0625

0.0625 = ab³   ...2

Divide equation 2 by equation 1, we have

b = 0.0625 / 0.125

b = 0.5

Then the correct option is C.

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helppppppppppppppppppppppppppppppppppppp

Answers

♨ANSWER♥

2x = 10

...hope this helps...

_♡_mashi_♡_

Answer:

A. 2x = -10

E. 2x = 10

Explanation:

[tex]\sf |2x| = 10[/tex]

If |a| = b then a = b or a = -b

[tex]\sf 2x = 10 \quad or \quad 2x = -10[/tex]

divide both sides by 2

[tex]\sf x = 5 \quad or \quad x = -5[/tex]

What has to be true for the triangles to be congruent?

Answers

Answer:

Step-by-step explanation:

Argument

I think the answer is A = N or D. It that is true, then M = C because all three angles are equal which gives similarity. But there is a side involved. OM = CB. Therefore the two triangles are congruent by ASA

Answer

ASA

Given: ΔABC with

Prove: AD/DB=CE/EB





Statement Reason

1. given

2. If two parallel lines are cut by a transversal, the corresponding angles are congruent.

3. ΔABC ~ ΔDBE AA criterion for similarity

4. Corresponding sides of similar triangles are proportional.

5. AB = AD + DB

CB = CE + EB segment addition

6. Substitution Property of Equality

7. division

8. Subtraction Property of Equality

6

What is the missing step in this proof?

A.

∠CAB ≅ ∠ACB, ∠EDB ≅ ∠DEB

B.

∠ADE ≅ ∠DBE, ∠CED ≅ ∠EBD

C.

∠CAD ≅ ∠ACE, ∠ADE ≅ ∠CED

D.

∠CAB ≅ ∠EDB, ∠ACB ≅ ∠DEB

Answers

Given that DE||AC, by similar triangles, we have;

D. <CAB congruent to <EDB, <ACB congruent to <DEB

How can the missing step be found?

A part of the question that appears missing is; side DE||AC

The completed two column proof is presented as follows;

Statement. Reason

1. DE||AC 1. Given

2. <EDB congruent to <CAB

<DEB congruent to <ACB

Which can be written as; <CAB congruent to <EDB, <ACB congruent to <DEB

2. If two parallel lines are cut by a common transversal, the corresponding angles are congruent

3. ∆ABC ~ ∆DBE 3. by AA criterion for similarity

4.

[tex] \mathbf{\frac{ AB }{ CB} } = \frac{ DB }{ EB} [/tex]

4. Corresponding sides of similar triangles are proportional

5. AB = AD + DB

CB = CE + EB 5. Segment addition postulate

6. [tex] \mathbf{\frac{ AD + DB }{ CE + EB} } = \frac{ DB }{ EB} [/tex]

6. Substitution property of equality

7. [tex] \frac{ AD + DB }{ DB} = \frac{ CE + EB }{ EB} [/tex]

7. Division property

8. [tex] \frac{ AD }{ DB} + 1 = \frac{ CE }{ EB} + 1 [/tex]

[tex] \frac{ AD }{ DB} = \frac{ CE }{ EB} [/tex]

8. Subtraction property

Therefore, the missing step in the proof is the option;

D. <CAB congruent to <EDB, <ACB congruent to <DEB

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The roots of the quadratic function describing the relationship between number of products produced and overall profit margin are x=0 and 28. The vertex is a minimum at (14,−40).

Answers

the quadratic equation is:

y = 0.2*x*(x - 28)

How to find the quadratic equation?

If we know that the roots are J and K, and the leading coefficient is a, then the quadratic equation is:

y = a*(x - K)*(x - J)

Here we know that the roots are at x = 0 and x =28, then:

y = a*(x - 0)*(x - 28).

We also know that the vertex is a minimum, so a is positive, and we know that the vertex is (14, -40), then we have:

-40 = a*(14)*(14 - 24) = -a*196

a = 40/196 = 0.20

Then the quadratic equation is:

y = 0.2*x*(x - 28)

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1. take away five from twelve times f. 2. one-half of the sum of k and six 3.x squared minus the sum of 5 4.the sum of the product of a and b, and three times c 5.twenty-four times the product of x and y, plus g.

Answers

The expressions formed are,

12f -5(k+6)/2x²-x+5ab+3c24xy+g

Formation of expressions in 1, 2 and 3:

In 1, twelve times f is, 12f

Taking away 5, it becomes (12f-5)

In 2, sum of k and 6 is, (k+6)

One-half of the above quantity is, (k+6)/2

In 3, sum of 5 with x is, (x+5)

Now, x squared minus the above expression indicates (x²-x+5)

Formation of expressions in 4 and 5:

In 4, product of a and b, is ab and 3 times c is 3c

Sum of the expressions evaluated in the previous statement = ab+3c

In 5, 24 times the product of x and y is, 24xy

Adding, g in the above computed expression, we get, 24xy+g

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You have a total of 16 coins, all quarters and dimes. The total value is $3.10. Which
of the following is the system of linear equations that represent this scenario? Let q =
the number of quarters and let d = the number dimes.

Answers

Benjamin has 6 dimes and 10 quarters.

The system of linear equations that represents this scenario is: q + d = 16

0.25q + 0.10d = 3.10

To represent the scenario described, we can set up a system of linear equations using the given variables:

Let q represent the number of quarters.

Let d represent the number of dimes.

We are given two conditions:

1) The total number of coins is 16:

q + d = 16

2) The total value of the coins is $3.10:

0.25q + 0.10d = 3.10

Therefore, the system of linear equations that represents this scenario is:

q + d = 16

0.25q + 0.10d = 3.10

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What is the simplified form of 4 log3y - 6 log3x + 7 log3z?

Answers

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[ b ] is the Correct one

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

[tex] \qquad❖ \: \sf \:4 \: log_{3}(y) - 6 \: log_{3}(x) + 7 \: log_{3}(z) [/tex]

[tex] \qquad❖ \: \sf \: \: log_{3}(y {}^{4} ) - \: log_{3}(x {}^{6} ) +\: log_{3}(z {}^{7} ) [/tex]

[tex] \qquad❖ \: \sf \: \: log_{3}(y {}^{4} ) + \: log_{3}(z{}^{7} ) - \: log_{3}(x {}^{6} ) [/tex]

([tex] \sf a\: log (b) = log {b}^{a}[/tex])

[tex] \qquad❖ \: \sf \: log_{3}( {y}^{4} {z}^{7} ) - log_{3}( {x}^{6} {}^{} ) [/tex]

([tex] \sf{log (a) + log (b) = log (ab)} [/tex])

[tex] \qquad❖ \: \sf \: log_{3} \bigg( \dfrac{y {}^{4} {z}^{7} }{ {x}^{6} } \bigg ) [/tex]

([tex] \sf{log (a) - log (b) = log (a/b)} [/tex])

[tex] \qquad \large \sf {Conclusion} : [/tex]

[ b ] is the Correct choice

Find f(g(2)) if f(x) = 2x-1 g(x) = -3x Find f(g(2)) if f(x) = 2x-1 g(x) = -3x -6 -9 3 -13Let Q (in grams) represent the mass of a quantity of carbon-14, which has a half-life of 5730 years. The quantity present after t years is Q(t)=10\cdot\left(\frac12\right)^{\left(\frac t{5730}\right)}Q(t)=10⋅(
2
1

)
(
5730
t

)
.

Determine the quantity present after 2000 years.


Let Q (in grams) represent the mass of a quantity of carbon-14, which has a half-life of 5730 years. The quantity present after t years is Q(t)=10\cdot\left(\frac12\right)^{\left(\frac t{5730}\right)}Q(t)=10⋅(
2
1

)
(
5730
t

)
.

Determine the quantity present after 2000 years.


7.851 grams

1.117 grams

0.785 grams

1.745 grams

Answers

The quantity that is present after 2000 years will be A. 7.851 grams.

How to calculate the quantity?

From the information given, initially at t = 0, the quantity is 10 grams.

After 2000 years, the appropriate quantity will be:

Q(2000) = 10 (1/2) × (2000/5730)

Q(2000) = 7.851 grams.

In conclusion, the correct option is A.

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Which graph represents viable values for y = 2x, where x is the number of pounds of rice scooped and purchased from a bulk bin at the grocery store and y is the total cost of the rice?

On a coordinate plane, a straight line with a positive slope begins at point (0, 0), and ends at point (2.5, 5).
On a coordinate plane, blue diamonds appear at points (0, 0), (1, 2), (2, 4).
On a coordinate plane, a straight line with a positive slope begins at point (negative 2.5, negative 5), crosses the x- and y-axis at point (0, 0), and ends at point (2.5, 5).
On a coordinate plane, blue diamonds appear at points (negative 2, negative 4), (negative 1, negative 2), (0, 0), (1, 2), (2, 4).
Mark this and return Save and Exit Next

Answers

The correct match for the graph of the total cost function is the option B graph.

What is a function?

The function is a type of relation, or rule, that maps one input to specific single output.

Given;

y = 2x is function

so, our graph should be of function y = 2x

Here, x is the number of pounds of rice scooped and purchased from a bulk bin at the grocery store and y is the total cost of the rice.

it means x is a number like 0, 1, 2, 3

so, the graph of the total cost function is a discrete function in nature.

Hence, graph-B is correct answer.

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What is the center of MN given M(3, -1) and N(7,-5)

Answers

Answer:

(5, -3)

Step-by-step explanation:

So the center of the two points, or a line can be defined using the equation: [tex]midpoint=(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})[/tex]. So using the two points you gave, you simply plug the values in to get

[tex]midpoint=(\frac{3+7}{2}, \frac{-1+(-5)}{2})\\[/tex]

Add numerators:

[tex]midpoint=(\frac{10}{2}, \frac{-6}{2})[/tex]

Simplify fraction:

[tex]midpoint=(5, -3)[/tex]

Triangle MRN is created when an equilateral triangle is folded in half.

Triangle N R M is shown. Angle N R M is a right angle. An altitude is drawn from point R to point S on side M N to form a right angle. The length of N S is 6, the length of S M is 2, the length of R M is x, the length of N R is y, and the length of R S is z.

What is the value of y?

2 StartRoot 3 EndRoot units
4 units
4 StartRoot 3 EndRoot units
8 units

Answers

Answer:

4 units

Step-by-step explanation:

Write the decimal as a fraction.
0.12

Answers

Answer:

3/25

Step-by-step explanation:

0.12=12/100

12/100 can be simplified 6/50 = 3/25

Imagine you want to create a model of Solar system (and beyond) with the Sun

represented by a beach ball of diameter 60 cm = 0.60 m. (i.e. of radius 30 cm = 0.30

m). On that same scale:
What is the diameter of the Milky Way?
And the diameter or Radius of Earth

Answers

The diameter of the milky way is given as 4.3 x 10¹¹m while the diameter of the radius of the earth is 0.00276

How to solve for the diameter of the milky way

The transformed system is given as 23.18 x 10⁸ in real length

Hence the diameter is

10 x 10²⁰ / 23.18 x 10⁸

= 4.3 x 10¹¹ m

How to solve for the diameter of the radius of the earth

Distance from the sun to the earth = 1.496 x 10¹¹m

Transformed system = 1.496 x 10¹¹m/23.18 x 10⁸

= 64.5 m

Actual radius = 6.4 x10⁶ / 23.18 x 10⁸

= 0.00276

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