branches of sicence​

Answers

Answer 1

Answer:

Natural science can be divided into two main branches

Explanation:

life science and physical science. Life science is alternatively known as biology, and physical science is subdivided into branches: physics, chemistry, astronomy and Earth science.

Answer 2

Answer:

Astronomy  

Biology

Geology

Chemistry

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Related Questions

Why does water have a much higher boiling point than methane even though water (H20) and methane (CH4) molecules are approximately the same size?
A. Only metallic bonds exist between methane molecules.
B. Only Van der Waals forces exist between water molecules.
C. Only metallic bonds exist between water molecules.
D. Only Van der Waals forces exist between methane molecules.​

Answers

Answer:

Water has a higher boiling point because the hydrogen bonds that form water molecules are stronger than the Van der Waals interactions among methane molecules, therefor more energy must be provided in order to break the hydrogen bonds and allow the water molecules to escape the liquid state.

Explanation:

Water has a much higher boiling point than methane because only Van der Waals forces exist between methane molecules.

What are chemical bonds?

Chemical bonds are forces of attraction between ions, molecules, and atoms.

There are different types of bonds present

Covalent bonds are the strongest bonds.

The molecules of water are joined by a hydrogen bond, thus its boiling point is high.

The molecules of Methane are attached by the van der Waals force, and it is weaker than the hydrogen bond.

Thus, methane has a lower boiling point than water.

Weaker bonds easily get broken.

Thus, the correct option is D.

Learn more about Chemical bonds

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As you decreased the volume of the chamber, what effect did this change have on the frequency of collisions between
atoms?

Answers

Answer: increase number of collisions

Explanation:

Decreasing the volume increases the likelihood of particles interacting more often.

Answer:

Atoms collided more often when the volume was lower.

Explanation:

plato

PLEASE HELP ME ASAP

N2 + 3H2 → 2NH3
How many grams of ammonia,
NH3, would be formed from the
complete reaction of 4.50 moles
hydrogen, H2?

Answers

Answer:

Mass =   51 g

Explanation:

Given data:

Mass of ammonia formed = ?

Number of moles of hydrogen = 4.50 mol

Solution:

Chemical equation:

N₂ + 3H₂     →     2NH₃

Now we will compare the moles of hydrogen and ammonia.

                H₂           :            NH₃

                  3           :              2

                 4.50       :           2/3×4.50 = 3 mol

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 3 mol × 17 g/mol

Mass =   51 g

given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt

Answers

Answer:

See Explanation

Explanation:

Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.

This implies that this compound Pb2O3  (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.

Hence Pb2O3  contains PbO and PbO2 units.

Density equals _____.

volume divided by mass
mass divided by volume
weight divided by area
weight divided by volume

Answers

density= mass divided by volume

What groups of elements are ionic compounds made of?​

Answers

Answer:

Ionic compounds generally form between elements that are metals and elements that are nonmetals. For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion.

Generally it is elements that are metals bonding with elements that are nonmetal.

An isotope of the element fluorine has 9 protons and 10 neutrons. What is the name of this isotope?

fluorine

Answers

Answer:

fluorine atom

Explanation:

(a) Given that the path length of the cuvette is 1 cm, what is the extinction coefficient of the 0.020 mM Yellow 5 dye at lambda max?(b) Given the data in the table below, what is the concentration of the diluted solution?Stock solution concentration 0.075 MStock solution absorbance 1.84Diluted solution absorbance 0.78

Answers

Answer:

(a). Kindly check the explanation section.

(b). 24.5 M^-1 cm^-

(c). 0.0318 M

Explanation:

So, we are given the following data parameters which is going to aid us in solving the above Question;

The path length = 1cm, extinction coefficient = unknown, absorbance is unknown and concentration= 0.02mM.

Using the formula below; we can determine the extinction coefficient as;

Absorbance = extinction coefficient × concentration × path length. -----------(1).

(a). Since, the absorbance is not given in the Question it won't be possible to determine the value of the extinction coefficient. Thus, say the value of absorbance = A.

Then, extinction coefficient = A/ 0.02 × 1 cm.

(b). Making use of the formula above, the extinction coefficient can be Determine as follows;

extinction coefficient = 1.84/0.075 × 1 = 24.5 M^-1 cm^-1.

(c). The concentration can be Determine by also making use of the formula above and making the concentration the subject of the formula;

Concentration = absorbance/ extinction coefficient × path length.

Concentration = 0.78/24.5 M^-1 cm^-1. × 1cm = 0.0318 M.

liquid to gas require heat?

Answers

Answer:

yes

Explanation:

Answer:

yes

Explanation:

let's say you have ice, you put it on a pan then it heats up you get a liquid after a while it turns into a gas

The rate constant for the radioactive decay of tritium 3H is 0.056 1/yr. The percentage of tritium remaining after 50 years is:_________

Answers

Answer:

6.05%

Explanation:

From the question given above, the following data were obtained:

Decay constant (K) = 0.0561 /yr

Time (t) = 50 years

We can obtain the percentage of tritium remaining after 50 years by using the following formula:

Log (N₀/N) = kt /2.303

NOTE:

N₀ is the original amount.

N is the amount remaining.

K is the decay constant.

t is the time

Log (N₀/N) = (0.0561 × 50) /2.303

Log (N₀/N) = 2.805/2.303

Log (N₀/N) = 1.218

Take the anti log of 1.218

(N₀/N) = anti log (1.218)

(N₀/N) = 1.218

N₀/N = 16.52

Invert and multiply by 100 to obtain the percentage.

N/N₀ = 1/16.52 × 100

N/N₀ = 6.05%

Thus, the percentage of tritium remaining after 50 years is 6.05%

Answer:

6.08% remains after 50 years

Explanation:

The radioactive decay follows the equation:

Ln[A] = -kt + Ln [A]₀

Where [A] is concentration of reactant after time t, [A]₀ is its initial concentration, k is rate constant and t is time.

Assuming its Initial concentration is 100%

Time is 50 yr

k is 0.056 yr⁻¹

And [A] is our incognite

Ln[A] = -0.056 yr⁻¹*50yr + Ln [100%]

ln[A] = 1.805

[A] =

6.08% remains after 50 years

Consider the reaction: 3Co2+(aq) + 6NO3¯(aq) + 6Na+(aq) + 2PO43¯(aq) â Co3(PO4)2(s) + 6Na+(aq) + 6NO3¯(aq) Identify the net ionic equation for this reaction.A. 3CO2(aq) + 6NO3(aq) + 6Na+(aq) + 2PO43-(aq) â Co3(PO4)2(s) + 6NaNO3(aq). B. Na+(aq) + NO3-(aq) â NaNO3(aq).C. 3CO2(aq) + NO3(aq) + Na*(aq) + 2PO43-(aq) â Co3(PO4)2(s) + NaNO3(aq).D. 3C02(aq) + 2PO43-(ag) â CO3(PO4)2(s).E. None of these choices are correct.

Answers

Answer:

D. 3 Co²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Co₃(PO₄)₂(s)

Explanation:

The complete ionic equation includes all the ions and the insoluble species. Let's consider the following complete ionic equation.

3 Co²⁺(aq) + 6 NO₃⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇒ Co₃(PO₄)₂(s) + 6 Na⁺(aq) + 6 NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the insoluble species. The corresponding net ionic equation is:

3 Co²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Co₃(PO₄)₂(s)

Which of the following elements has the heaviest atom?


a. nickel

b. lead

c. iron

d. gold

Answers

Answer:

Iron

Explanation:

Because it is never because iron weights 9 tons or 17,000 pounds

Answer:

b. lead

Explanation:

look on the periodic table and it has its atomic mass and lead (Pb) is the heaviest

how do you determine number of valence electrons an element has

Answers

Answer:the first column has one valance electron the second has 2 and so on.

The only exception is helium that has 2.

Explanation:

What are two properties that can differentiate between pure nickel and pure
iron?
A. Density and electrical conductivity
B. Magnetism and thermal conductivity
C. Appearance and density
D. Appearance and state at room temperature

Answers

Answer:  Its "C"

Explanation:

Appearance and density

sorry this took 14 hours lol

pls mark brainiest

An atom of an element has two electrons in the first energy level and five electrons in the second energy level. Write the electron configuration and name the element. How many unpaired electrons does an atom of this element have?

Answers

Answer:

electronic configuration: 1s^2,2s^2,2p^3            

name: nitrogen

unpaired electron: 3

Explanation:

The atom with 2 electrons and 5 electrons in the first and second energy level is NITROGEN. The element has 3 unpaired electron.

The electronic configuration of the atom is 1s² 2s² 2p³

Since the atom has 7 Electrons, the element which has 7 electrons is NITROGEN.

The 2p orbital has 3 unpaired electrons in it's second energy level.

Therefore, the 2p orbital has 3 unpaired electrons in it's outermost shell.

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Which of the following is NOT a property of gases?
Your answer:
A.They are easy to compress.
B.They expand to fill their containers.
C.They have a definite shape and a definite volume.
D.They occupy far more space than the liquids or solids from which they form.

Answers

Answer: C

Explanation:

A. As they do not have a given shape and expand to fill the container, modifying the size of the container modifies the space the gas occupies

B. They are nearly free molecules, which means no bound between them, moving fast and freely around the container

C. NOT A PROPERTY. As said before, as there are no bindings between molecules and move freely, they cannot have a fixed size cause they're always on the move.

D. Because they expand to fill the container, it's easy to them to occupy more space than in any other state, as the container is the only thing that defines how much volume they occupy

From one run of the proposed electron transport chain, how many ATP equivalents in energy could theoretically be generated?a) 3 b) 4 c) 5 d) 6 e) 7

Answers

Answer:

b) 4

Explanation:

The electron transport chain may be defined as the series of the complexes which transfer the electrons from electron donors to the electron acceptors through a redox reactions, and also couples the electron transfer along with the transfer of the protons across the membrane.

The electron transport chain or the ETC is made up of peptides and enzymes, and some other molecules.

The full form of ATP is Adenosine triphosphate. It is a chemical compound that provides energy to the living cells.

From one run in the ETC or the electron transport chain, 4 ATP can be generated.

How do living systems follow the laws of conservation of mass?

Answers

Answer:

they use it when a living organism dies.

Explanation:

when d organism decomposes carbon is released that enters back into d earth. this follows d law of mass

In an aqueous solution of a certain acid the acid is 0.094% dissociated and the pH is 4.55. Calculate the acid dissociation constant Ka of the acid. Round your answer to 2 significant digits

Answers

Answer:

Explanation:

pH = 4.55

[ H⁺ ] = 10⁻⁴°⁵⁵

= 2.82 x 10⁻⁵

Let the acid be HA and its molar concentration be a .

         HA         ⇄       H ⁺       +        A ⁻

a - .094x10⁻³a      .094x10⁻³a    .094x10⁻³a

.094x10⁻³a  = 2.82 x 10⁻⁵

a = 30 x 10⁻²

= .3

a - .094x10⁻³a   = .3 - .094 x 10⁻³ x .3

= .29997 approx

Ka =  2.82 x 10⁻⁵ x  2.82 x 10⁻⁵ /  .29997

= 7.95 x10⁻¹⁰ / .29997

= 26.5 x 10⁻¹⁰

= 27 x 10⁻¹⁰ ( rounding off to two digits )

Metamorphic rocks with a non-foliated texture show metamorphic change that involves ____.
a.
mineral grains arranging into layers
b.
growth in the size of the mineral grains
c.
mineral grains flattening under pressure
d.
mineral grain melting

Answers

Answer:

b.  growth in the size of the mineral grains

Explanation:

Non-foliated texture shown by a metamorphic change is depicted by growth in the size of the mineral grains.

Examples of non-foliated metamorphic rocks are quartzite and marble. In these metamorphic rocks, mineral grains are not aligned with their long axis. Non-foliated texture occurs under high temperature and low pressure conditions.As minerals are able to grow, the size can be used to show a metamorphic change.

Answer:

its b home slice

Explanation:

A buffer is prepared by mixing 204.0 mL of 0.452 M HCl and 0.500 L of 0.400 M sodium acetate (NaC2H3O2):
Calculate the pH of the buffer.
How many grams of KOH must be added to 0.500 L of the buffer to change the pH by 0.15 units?

Answers

Answer:

pH = 4.89

0.6171g of KOH must be added

Explanation:

Sodium acetate reacts with HCl producing acetic acid as follows:

NaC2H3O2 + HCl → HC2H3O2 + NaCl

That means the moles added of HCl are moles of acetic acid produced and moles of acetate are initial moles - moles of HCl

Moles HCl = Moles acetic acid:

0.204L * (0.452mol / L) = 0.0822 moles acetic acid.

Initial moles sodium acetate:

0.500L * (0.400mol / L) = 0.200 moles

Moles sodium acetate:

0.200 moles - 0.0822 moles = 0.1172 moles sodium acetate

The pH of this buffer (Mixture of a weak acid and its conjugate base) is obtained using H-H equation:

pH = pKa + log [A-] / [HA]

Where pH is pH of the buffer,

pKa is pKa of the buffer (4.74 for acetic acid)

[A-] Moles of sodium acetate -Conjugate base-

And HA moles of acetic acid -Weak acid-

pH = 4.74 + log [0.1172 moles] [0.0822 moles]

pH = 4.89

In 0.500L the moles of the buffer are:

0.500L * (0.200moles / 0.704L) = 0.142 moles of buffer

For a pH of 0.15 units more (4.89 + 0.15 = 5.04):

5.04 = 4.74 + log [Acetate] / [Acetic acid]

0.3 = log [Acetate] / [Acetic acid]

1.9953 = [Acetate] / [Acetic acid] (1)

And as:

0.142 = [Acetate] + [Acetic acid] (2)

Replacing (2) in (1):

1.9953 = 0.142 - [Acetic acid]  / [Acetic acid]

1.9953 [Acetic acid] = 0.142 - [Acetic acid]

2.9953 [Acetic acid] = 0.142 moles

[Acetic acid] = 0.0474 moles of acetic acid must remain after the addition of KOH.

In the beginning, moles of acetic acid are:

0.0822 moles * (0.500L / 0.704L) = 0.0584 moles.

That means moles added of KOH (Equal to moles of acetic acid that react) are:

0.0584 moles - 0.0474 moles = 0.0110 moles of KOH

In grams (Molar mass KOH = 56.1g/mol):

0.0110 moles KOH * (56.1g/mol) =

0.6171g of KOH must be added

Compound Y has a distribution coefficient of 4.0 when extracted from water with chloroform, with Y being more soluble in chloroform. How many 10.0 mL chloroform extractions would be required to extract at least 95% of Y from a 50.0 mL aqueous solution of water?

Answers

For the extraction of at least 95% of Y in water, 3 extractions are to be performed.

Distribution coefficient can be defined as the ratio of the concentration of solute in an organic solvent to water.

Distribution coefficient = [tex]\rm \dfrac{concentration\;in\;solvent}{concentration\;in\;water}[/tex]

For the first extraction, the concentration in organic solvent = X per 10 ml

Concentration in water = 100-X per 50 ml

Distribution coefficient = [tex]\rm \dfrac{\frac{X}{10} }{\frac{100-X}{50} }[/tex]

4 = [tex]\rm \dfrac{\frac{X}{10} }{\frac{100-X}{50} }[/tex]

4 = [tex]\rm \dfrac{50X}{1000-X}[/tex]

4000 - 4X = 50X

X = 74.1 %

Thus, after the first extraction, the amount of Y extracted is 74.1%.

We have to extract at least 95% of Y. Thus, the second extraction is performed.

Remaining y = 100 - 74.1

Remaining y = 25.9%

The concentration in organic solvent = X per 10 ml

Concentration in water = 25.9 -X

Distribution coefficient = [tex]\rm \dfrac{\frac{X}{10} }{\frac{25.9-X}{50} }[/tex]

4 = [tex]\rm \dfrac{\frac{X}{10} }{\frac{25.9-X}{50} }[/tex]

4 = [tex]\rm \dfrac{50X}{259-X}[/tex]

1036 - 4X = 50X

X = 19.2%

Thus, after the second extraction the amount of Y extarcted = first extraction + second extraction

The amount of Y extracted = 74.1 + 19.2 %

The amount of Y extracted = 93.3%

To reach at least 95% extraction, the third extraction has to be performed.

The remaining Y for third extraction = 100 - 93.3

The remaining Y for the third extraction = 6.7%

Concentration in water = 100 - 6.7

Distribution coefficient = [tex]\rm \dfrac{\frac{X}{10} }{\frac{6.7-X}{50} }[/tex]

4 = [tex]\rm \dfrac{\frac{X}{10} }{\frac{6.7-X}{50} }[/tex]

4 = [tex]\rm \dfrac{50X}{67-X}[/tex]

268 - 4X = 50X

X = 5.0%

The total extraction after third extraction = 93.3 + 5%

The total extraction after third extraction = 98.3%.

Thus for the extraction of at least 95% of Y in water, 3 extractions are to be performed.

For more information about the distribution coefficient, refer to the link:

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what are the existing evidences to support the existence of pangea?
salamat.​

Answers

Fossil evidence for Pangaea includes the presence of similar and identical species on continents that are now great distances apart.

Which of these compounds do not have a pH dependent solubility at less than pH 7.00?

Answers

Answer:

tbh idekkk

Explanation:

A 1.50 mol sample of He occupies a volume of 2.50 L at a pressure of 14.7 atm. What will be the pressure of a 1.50 mol sample of H2 gas under the same conditions? a 7.33atm b 14.7atm c 29.4 atm d 1.00 atm

Answers

Answer:

el n = M/m. El nº de moles = m/M

Se utiliza la fórmula general de los gases: P*V = n*R*T

P = 760/760 = 1 atm

V = 0,5 L

n = masa de Cl2/masa molecular = masa de Cl2/70

R = 0,082

T = 273 + 20º C = 293 K

1*0,5 = masa de Cl2/70*0,082*293

0,5/0,082*293 = masa de Cl2/70

0,0208 = masa de Cl2/70

masa de Cl2 = 70*0,0208 = 1,46 g

epilacion:

Suerte

Which element would most likely have a chemical reactivity similar to bromine?

Answers

Answer:

Bromine is a very reactive element. While it is less reactive than fluorine or chlorine, it is more reactive than iodine. It reacts with many metals, sometimes very vigorously. For instance, with potassium, it reacts explosively.

Explanation:

Answer: Bromine is a high reactive element. While it is not as reactive as fluorine or chlorine, it is still more reactive than iodine. It reacts with many metals, and even sometimes very aggressively. For example, when mixed with potassium, it will explode.  

Explanation:

How many molecules are in 2.0 grams of
Na2SO4?

Answers

Answer:

450 grams of Na2SO4

Explanation:

hope that helps

Answer

450 grams of Na2SO4.

Hope this helps!

Calculate the maximum mass of a metal, with equivalent mass of 20 g, that should be used in an equivalent mass determination with a 100-mL eudometer tube for collection. For the purposes of calculation, assume 80 mL of hydrogen gas produced at standard conditions. (Round to 2 sig figs)

Answers

Answer:

Explanation:

In the equivalent mass measurement , one gram equivalent of metal produces 11200 mL of hydrogen gas .

11200 mL hydrogen gas is produced by 1 gram equivalent of gas at STP

11200 mL hydrogen gas is produced by 20 g  of gas at STP

80 mL hydrogen gas is produced by 20 x 80 / 11200  g  of gas at STP

= 142.85 mg .

= 140 mg . ( rounded to 2 sig figures )

The compound stannous(II) nitride is incorrectly named. Rename the compound correctly.

Answers

Answer:

Answer: Tin (II) nitride

according to the conveyor belt mode of ocean circulation, what happens when water reaches the poles

Answers

Answer: Some salt is trapped between ice crystals, but most are left behind in the unfrozen seawater.

Explanation:

Answer: The salinity of the water increases

Explanation: Hope this helps!

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The admission fee at an amusement park is $1.50 for children and $6.40 for adults. On a certain day, 286 people entered the park, and the admission fees collected totaled $1164. How many children and how many adults were admitted? i suck at spanish please help w these 3 questions. or one just help please i beg u PLEASE I NEED HELP ASAP 5.2) Which of the following are equivalent tothe ratio, "There are 6 brunettes for every 4blondes"? CIRCLE ALL THAT APPLY.A) 4:6C) 3:2B) 9:6D) 2:3 There would be no familiar faces to greet him when he arrived. But Altaf could expect the children to hear his call.The dub-dub rhythms of the engine spread out and beckoned every boy and girl within earshot. Their short brown legs kicking up a cloud of dust, they flocked to the riverbank. They jumped up and down, their shrill voices piercing the air.Altaf had encountered this scene a hundred times as he made his way east from Calcutta through the tangled waterways of the delta. This time his motorboat did not rush past the children. It slowed down and headed right towards them. Their jumps turned into stomps and their shouts became screams of delight. When he cut the engine, Altaf heard what they were saying.Ingreji-shaheb! Ingreji-shaheb!From the back of the boat, Shiraj chuckled, They think you are an Englishman. Altaf smiled. Why not? These children might never have seen the English but having just crowned George the Sixth as Emperor of India,1 they were still the masters of this land. Altaf doubted that any other motorboat had ever come into this village. No one would expect a Bengali man to bring one here. Besides, Altaf was taller than average, fair in complexion, and wearing European clothes. He would have been more comfortable travelling in a lungi2, but today he had put on khaki pants and a sky-blue shirt. A straw hat protected his head from the sun.Exhausted after three days of travel, Altaf was relieved the journey was over. When he had turned off the Meghna river and entered this smaller channel, he was not sure this was the one that led to his village. Then he sighted, on the horizon, the corrugated iron roof framed by the twin palmyra trees with their broad leaves spread like huge fans. Home.Still, he could not be positive. He was returning after ten years. This is Modhupur village, isnt it? he shouted at the children.He-speaks-in-Bangla. Not-an-Ingreji-shaheb! Our-folk! One-of-us!He repeated his question.Yes-this-is-Modhupur. But-who-are-you? Who-do-you-want? Where-did-you-come-from?I belong to that house over there, he said, thrusting a finger towards the palmyra trees.The children swivelled their necks to look. None of them were old enough to remember him. They questioned him and each other. Are-you-this-ones-brother? Is-he-that-ones son? The-other-ones-cousin? Finally a voice made itself heard over the rest and said, Masooms-uncle-who-went-away-to-the-city. It could have been the certainty in his voiceslightly older than the othersor they may have run out of possibilities to consider, but the boys remark settled the debate. The children quieted down and just stared at Altaf, as if searching his face for some sign of familiarity so they could place him as part of their world.Clutching the mooring rope in his hands, Shiraj jumped into the water and tugged the boat towards the bank. A few of the children rushed forward to help him pull. Shiraj tied the rope around a tree. Nearby a few small dinghies were also moored. They rocked in the water from the waves stirred up by the motorboat.While Altaf supervised the mooring, the children craned their necks to look inside the boat and resumed their inquiries. Where-are-your-sails? How-can-it-move-without-sails? What-is-that-thing-you-call-an-engine? Why-does-it-make-the-loud-noise? Where-did-you-get-it-from? Are-you-a-very-rich-man?Altaf could not keep up with them. 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(Consider the notion of a "migraine personality," which Didion describes as "ambitious, inward, intolerant of error, rather rigidly organized, perfectionist." Migraine has physiological and chemical origins, but manifests in reaction to psychological stimuli and quirks of personality. How does this make it different from cancer, a flu?)3)What is the silver lining, benefit of a migraine? If a flower is not pollinated what will happen? help me I only have until 8:50 to finish this please help me What is the radius of an automobile tire that turns with a period of 0.091 s and has a linearspeed of 20.0 m/s? What kind of force is the centripetal force? Suppose that the age of all the U.S. first ladies when they married was recorded. The mean age of U.S. first ladies when they married would be a:________A) PopulationB) StatisticC) SampleD) Parameter WILL GIVE BRAINLIEST! PLEASE ANSWER! Based on the given information, which of the following is the students' correct conclusion about their experiment? A company manufactures acoustic guitars. The table shows the number of units that the company sold each month over a nine-month period beginning in January.Month, x 1 2 3 4 5 6 7 8 9Units, y 150 300 380 425 425 480 520 550 575Which equation best models the situation?a y=148.4 x-1-154b y=46.4x+191.7c y=148.4 x-1+154d y= -46.4x+191.7 At the beginning of the current period, Rose Corp. had balances in Accounts Receivable of $200,000 and in Allowance for Doubtful Accounts of $9,000 (credit).During the period, it had net credit sales of $800,000 and collections of $763,000.It wrote off as uncollectible accounts receivable of $7,300.However, a $3,100 account previously written off as uncollectible was recovered before the end of the current period.Uncollectible accounts are estimated to total $25,000 at the end of the period.(Omit cost of goods sold entries)Required:(a) Prepare the entries to record sales and collections during the period.(b) Prepare the entry to record the write-off of uncollectible accounts during the period.(c) Prepare the entries to record the recovery of the uncollectible account during the period.(d) Prepare the entry to record bad debt expense for the period.(e) Determine the ending balances in Accounts Receivable and Allowance for Doubtful Accounts. need 3 equivalent ratios for 22:55 Is it bad that the smell of burnt pie crust is nasally offending when its in the oven but gratous when its through the house.... Is this what holidays smell like? Over baked gramcracker? In the inequality 2x + $10,000 $70,000, x represents the salary of an employee in a school district. Which phrase most accurately describes the employee's salary? Which list shows the absolute values in order from least to greatest? Question 5 options: |2.36|, |5.98|, 6.1 0.2, |0.3|, |0.1| |7.6|, 5.3, 1.3