What is the total number of Joules lost when 10. grams of water at 80.°C is cooled to 60.°C?

Answers

Answer 1

Answer:

[tex]\boxed {\boxed {\sf 836.8 \ Joules \ lost}}[/tex]

Explanation:

Since we are given the mass and change in temperature, we should use the following formula for heat.

[tex]q= mc \Delta T[/tex]

In this formula, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

We know the mass of the water is 10 grams. We will have to look up water's specific heat, because it is not given. It is 4.184 J/g °C.

Let's find the change in temperature. This is the difference of the final and initial temperature. The water started at 80 °C and cooled to 60°C.

ΔT= final temperature - initial temperature ΔT= 60° C - 80°C ΔT= -20 °C

Now we have values for each variable.

m= 10 gc= 4.184 J/g°C ΔT= -20°C

Substitute the values into the formula.

[tex]q= 10 \ g * 4.184 \ J/g \textdegree C * -20 \textdegree C[/tex]

Multiply the first 2 numbers. The units of grams will cancel each other out.

[tex]q= 41.84 \ J/ \textdegree C * -20 \textdegree C[/tex]

Multiply again. This time, the degrees Celsius cancel.

[tex]q= -836.8 \ J[/tex]

A total of 836.8 Joules are lost.


Related Questions

Give the name of the products formed
between Benzene and the following Compounds
Br2,Cl2,HNO3,H2SO4,HCOCl
1-chlore-2,2-dimethylpropane

Answers

Answer:

With Br2 - Bromobenzene

With Cl2 - Chlorobenzene

With HNO3- Nitrobenzene

With H2SO4 - Benzenesulphonic acid

With HCOCl - Benzoyl chloride

With 1-chloro-2,2-dimethylpropane - 2,2dimethyl-1-phenyl propane

Explanation:

The common thread joining all these reactions is that they are all electrophillic reactions. They are so called because the attacking agents in each reagent is an electrophile. Electrophiles are species that have electron deficient centers and are known to attack molecules that are high in electron density at regions of high electron density.

The benzene molecule has rich electron density. Any substituents that donates electrons to the ring improves the likelihood that benzene will undergo electrophillic substitution reactions while electron withdrawing substituents decrease the likelihood that benzene will undergo electrophillic substitution reactions.

The names of the compounds formed when benzene undergoes electrophillic reaction with the attacking agents listed in the question are displayed in the answer section.

For a multistep reaction the observed order of
the reaction is generally determined by the
1. stoichiometric coefficients of the net reaction.
2. ratio of reactant and product concentrations.
3. slowest reaction of the sequence.
4. time at which the concentrations of all
species are measured.
5. activation energy.

Answers

Answer: 3 slowest reaction of the squence

Explanation:

The order of reaction is obtained from the slowest step in the reaction.

An elementary reaction refers to any reaction that takes place in one reactive encounter. On the other hand, a multistep reaction occurs in several steps and involves multiple reactive encounters.

The rate determining step in a multistep reaction is the slowest step in the reaction sequence. The order of reaction is obtained from this slowest step in the reaction.

Learn more: https://brainly.com/question/6505878

If you have 7 moles of water, how many atoms do you have?

Answers

Answer:

Explanation:

Given 7  moles H₂O

By definition, the 'mole', in chemical process, is the mass of substance (usually in grams and includes elements or molecules) that contain 6.023 x 10²³ particles (Avogadro's Number)  of the given substance. The mole is also related (or, equal) to the following:

1 mole = 1 Avogadro's number of particles = 6.023 x 10²³ particles = 1 formula wt. = 1 molecular wt. = 1 gram formula weight

So, if given 7 moles of water (H₂O) => ? molecules of water (H₂O)

By the Avogadro relationship => 1 mole H₂O = 6.023 x 10²³ molecules of H₂O

Then 7 moles H₂O => 7 moles x 6.023 x 10²³ molecules H₂O/mole H₂O

= 4.216 x 10²⁴ water molecules.

_________________________________-

General FYI note ... if needed ...

The subscripts identify number of moles of element in one mole of formula weight. That is while 1 mole H₂O contains 6.023 x 10²³ molecules of water it also contains 2 moles of hydrogen or, 2 x 6.02 x 10²³ atoms of hydrogen and moles of oxygen 1 x 6.023 x 10²³ atoms of oxygen.

in the cell, newely made proteins move directly from the ribosomes into the rough _____ _____, where they are chemically modified

Answers

Answer:

endoplasmic reticulum

Explanation:

there it is

Which organisms in soil helps relieve element so they can be recycled

Answers

Answer:

Explanation:

Protozoa and Bacteria: Protozoa are very small one-celled creatures. They play an important role in helping to make the soil better by feeding on bacteria and releasing excess nitrogen, which is really good for plants. Bacteria are among the tiniest and most numerous organisms in the soil.

Answer: Hewo there! your answer is Below

Soil bacteria perform recycling of soil organic matter through different processes, and as a result they produce and release into the soil inorganic molecules

Explanation:

Bacteria consume organic matter and other compounds and recycle them into substances that can be used by other organisms. Bacteria can live anywhere that has water. They are more numerous, can reproduce faster and can survive harsher conditions than any other organism on Earth.

Hope this helps you!!

Have a great day❤️❤️

-August-

When determining the amount of an oxidant present by titration, you can use iodine and starch as an indicator.
First, the oxidant, like hypochlorite, oxidizes
Choose...
neutral iodine into iodide ion
iodide ion into neutral iodine
iodate polyatomic ion into iodide ion
When starch and iodine are both present, the solution is
Choose...
blue-black
brownish yellow
clear
During the titration, the titrant, like thiosulfate, reduces the
Choose...
iodide ion into iodate polyatomic ion
neutral iodine into iodide ion
iodide ion into neutral iodine
When the iodine has completely reacted at the endpoint of the titration, the solution should become
Choose...
clear
blue-black
brownish yellow

Answers

Answer:

1. iodide ion into neutral iodine

2. blue-black

3. neutral iodine into iodide ion

4. clear

Explanation:

The function of hypochlorite in iodine titration is to oxidize the iodide ion into iodine molecule as shown below;

ClO-(aq) + 2H+(aq) + 2I-(aq) ---------> 6 I2(l) + Cl- (aq)+ H2O(l)

The addition of starch to iodine leads to the formation of a starch iodide complex which has a blue black colour.

the titrant, thiosulfate, reduces neutral iodine into iodide ion as shown below;

I2  +  2S2O32-  → 2I- + S4O62-

At end point, the solution becomes clear again.

0.329 M copper (II) nitrate was reacted with 0.528 M potassium carbonate as follows: Cu (NO subscript 3 )subscript 2 italic (a q italic )space plus space straight K subscript 2 CO subscript 3 italic (a q italic )rightwards arrow CuCO subscript 3 italic (s italic )space plus space 2 thin space KNO subscript 3 italic (a q italic )Determine the percent yield if 163.9 mL of each reactant were allowed to react, and a mass of 4.883 g of solid were obtained.

Answers

Answer:

73.33% is the percent yield

Explanation:

Percent yield is defined as:

Actual yield (4.883g) / Theoretical yield * 100

Based on the reaction:

Cu(NO₃)₂(aq) + K₂CO₃(aq) → CuCO₃(s) + 2KNO₃(aq)

1 mole of copper nitrate reacts per mol of potassium carbonate.

To solve this question we must find limiting reactant. With limiting reactant we can find the theoretical moles of solid produced and its mass as follows:

Moles Cu(NO₃)₂:

0.1639L * (0.329mol / L) = 0.0539 moles

Moles K₂CO₃:

0.1639L * (0.528mol / L) = 0.0865 moles

As the reaction is 1:1, the limiting reactant is Cu(NO₃)₂.

1 mol of Cu(NO₃)₂ produces 1 mol of CuCO₃. That means theoretical moles produced are 0.0539 moles. And the mass is:

Mass CuCO₃ -Molar mass: 123.55g/mol-

0.0539 moles * (123.55g / mol) = 6.659g of CuCO₃ is the theoretical mass

And percent yield:

4.883g / 6.659g * 100

73.33% is the percent yield

Select the TRUE statements below regarding the coordination compound prepared in lab. Group of answer choices The coordination compound contained a complex ion that was covalently bonded to sulfate. The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound. Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol. The ammonia is covalently bonded to the transition metal. The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal.

Answers

Answer: Hello the compound is missing but I was able to get the Full question and missing compound . ( compound = copper sulfate )

answer : statement ; 2 , 3 and 5

Explanation:

The true statements regarding the coordination compound ( copper sulfate ) are :

The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound ( statement 2 )Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol ( statement 3 ) The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal ( statement 5 )

During the coordination of compounds dative bonds exits between the transition metals and the Ligands molecules

hellppppppp asap please NO FILES ​

Answers

Answer:

Q1: c. 7.2 g.

Q2: a. 0.42 M.

Explanation:

Hello there!

In this case, according to the definition of molarity as moles of solute divided by volume of solution in liters, we can proceed as follows:

Q1: Here, given the molarity and volume we can calculate the moles of the sugar as follows:

[tex]n=M*V=0.4mol/L*0.1L\\\\n=0.04 mol[/tex]

Next, since its molar mass is about 180 g/mol, the mass turns out:

[tex]0.04mol*\frac{180g}{1mol} =7.2 g[/tex]

Therefore, the answer is c. 7.2 g.

Q2: Here, recalling the definition of molarity, we can just plug in the 0.629 moles and 1.500 L to obtain:

[tex]M=\frac{0.629mol}{1.5L}\\\\M=0.42M[/tex]

Therefore, the answer is a. 0.42 M.

Best regards!

state the type of enthalpy in the followinv equation Koh+Hcl-kcl+h2o ∆h+=-57kj\mol​

Answers

Answer:

The Enthalpy of neutralization

Explanation:

The reaction of a base (KOH) with an acid (HCl) produce water and its salt (KCl) is called Neutralization Reaction.

This neutralization releases 57kJ/mol.

As the type of enthalpy is due the type of reaction. This enthalpy is:

The Enthalpy of neutralization

What are the things that is solid?

A. water
B. rock
C. oil
D. module​

Answers

Answer:

The answers for these questions are B. rock and D. Module because they are both solids. The other two water and oil are liquids.

How many carbon atoms are in 6.5 moles of carbon?

Answers

Just do 6.5 * (6.02 * 10^23)
Sorry I don’t have a calculator on me
Type that into the calculator to get your answer

3.91 ×10²⁴ carbon atoms are in 6.5 moles of carbon. The smallest unit of matter that may be divided without producing electrically charged particles is the atom.

What is atom?

The smallest unit of matter that may be divided without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. As a result, the atom serves as the fundamental unit of chemistry. Space makes up the majority of an atom.

The rest is made up of a cloud of electrons that are negatively charged surrounding a nucleus that is positively charged made up of protons and neutrons. Compared to electrons, which are the smallest charged particles in nature, the nucleus is small and dense. Electric forces, which link radicals to the nucleus of atoms, cause them to be drawn to any positive charge.

number of atoms= 6.5 ×  6.022×10²³

          =3.91 ×10²⁴  

Therefore, 3.91 ×10²⁴ carbon atoms are in 6.5 moles of carbon.

To know more about atom, here:

https://brainly.com/question/29712157

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What is the molarity of a solution that contains 224 grams of KOH in 2
liters of solution?

Answers

Answer:

[tex]\boxed {\boxed {\sf 2 \ M \ KOH}}[/tex]

Explanation:

Molarity is a measure of concentration in moles per liter.

1. Grams to Moles

The first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.

We have 224 grams of KOH. Look up the molar masses for the individual elements.

Potassium (K): 39.098 g/mol Oxygen (O): 15.999 g/mol Hydrogen (H): 1.008 g/mol

Since the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.

KOH: 39.098 + 15.999 + 1.008=56.105 g/mol

Use this number as a ratio.

[tex]\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}[/tex]

Multiply by the value we are converting: 224 g KOH

[tex]224 \ g \ KOH *\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}[/tex]

Flip the ratio so the units of grams KOH cancel.

[tex]224 \ g \ KOH *\frac {1 \ mol \ KOH}{56.105 \ g\ KOH}[/tex]

[tex]224 *\frac {1 \ mol \ KOH}{56.105}[/tex]

[tex]\frac {224}{56.105} \ mol \ KOH[/tex]

[tex]3.992514036 \ mol \ KOH[/tex]

2. Calculate Molarity

Remember molarity is moles per liter.

[tex]molarity = \frac{moles}{liters}[/tex]

We just calculated the moles and we know there are 2 liters of solution.

[tex]molarity = \frac{ 3.992514036 \ mol \ KOH}{ 2 \ L}[/tex]

[tex]molarity= 1.996257018 \ mol \ KOH/ L[/tex]

3. Round and Convert Units

First, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.

1.996257018

The 9 in the tenths place tells us to round to 1 up to a 2

[tex]2 \ mol \ KOH/ L[/tex]

Next, convert units. 1 mole per liter is equal to 1 molar or M.

[tex]2 \ M \ KOH[/tex]

The molarity of the solution is 2  M  KOH

Answer:

2M of KOH

Explanation:

224 g of KOH in 2 liters of KOH

?  of KOH in 1 liters of KOH

[tex]\frac{224}{2} = 112g of KOH[/tex]

1 mole of KOH = 39 + 16+ 1 = 56g

?mole of KOH = 112g

[tex]\frac{112}{56}[/tex]moles of KOH = 2 moles/1liter of KOH

written as 2M KOH

4. Calculate the volume of ammonia gas, at s.t.p., formed from 4.28 g of ammonium
chloride

Answers

I’m not too sure, but I could try to figure it out

sdfsdfsdfsfsdfsdfdfdre

Answers

Answer:

310 mmHg

Explanation:

All you have to do here in order to figure out the pressure exerted by gas  

D  is use Dalton's Law of Partial Pressures.


If the empirical formula of an organic compound is CH20, then the molecular mass of the compound could be

A. 15g
B. 45g
c. 60g
D. 135g

Answers

I think the answer is C

List 2 ways that the increase in human population has had a negative impact on
the environment.
I

Answers

an increase in greenhouse gases in the atmosphere, and deforestation. hope this helps!

3.2 g of a gas at STP occupies a volume of 2.24 L. The gas is

Answers

Answer:

Oxygen

Explanation:

If anyone has done the edge acids and bases lab please help me it would be deeply appreciated

Answers

Answer:

Do you mean a biology lab

Explanation:

what's the question

Using the balanced reaction below, answer the following question:

2 Al + 3 ZnCl2 → 3 Zn + 2 AlCl3

How many moles of ZnCl2 are needed to react when 1.75 moles of AlCl3 form?

Answers

Answer:

Calculate the number of grams of AlCl3 produced from 2.5 moles of Cl2. The reaction between H2 and O2 produced 31.0 g of water. How many grams of O2 reacted?

Explanation:

Balance the equation ___ CaCO3 -> ____ CaO + ____ CO2

Answers

Answer:

CaCO3 -> CaO + CO2

Explanation:

Woahhhh, did you balance it yourself just then?

What factors – physical, historical, and otherwise – have contributed to the traditional identification of multiple “oceans” versus the concept of a single, global ocean?

Answers

Answer:

According to this theory, the ocean formed from the escape of water vapor and other gases from the molten rocks of the Earth to the atmosphere surrounding the cooling planet. After the Earth's surface had cooled to a temperature below the boiling point of water, rain began to fall—and continued to fall for centuries.

Explanation:

electron configuration assignment pleaseee help asappp its 100 points and I give out brainly <3

Answers

Answer:

https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Quantum_Mechanics/10%3A_Multi-electron_Atoms/Electron_Configuration

Explanation:

My swimming pool is rectangular (16 feet by 34 feet) and has a depth of 6 feet. Lets imagine that my pool water is full to the top and is heated by a laser that emits photons with a wavelength of 520 nm. The starting temperature of my pool is a chilly 52 degrees Celsius. How many moles of photons would be required to heat the pool to a balmy 80 degrees Celsius

Answers

Answer:

Number of moles of photons required = 5.04 × 10⁴ moles

Explanation:

The energy of a photon can be calculated from Planck's equation E = hc/λ

Where h = 6.63 × 10-³⁴ Js and c, the velocity of light = 3.0 × 10⁸ m/s

Energy of one mole of photons = N₀ × hc/λ

wavelength of photon, λ = 520 nm = 5.20 × 10-⁷ m

Energy of one mole of photons = 6.02 × 10²³ × 6.63 × 10−³⁴ × 3 × 10⁸/5.20 × 10-⁷

Energy of one mole of photons = 2.30 × 10⁵ J/mol

Energy required to raise the temperature of a given mass of a substance, E = mcΔT

Where m is mass of substance,  c is specific heat capacity,  ΔT is temperature difference

Mass ofnwternin the pool = volume × density

Volume of water = Volume of swimming pool

Volume of water = 16 × 34 × 6 ft³ = 3264 ft³

1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³

Density of water = 1 g/cm³

Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g

ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K

Energy required to raise 92426035.2 g water by 30° C = 92426035.2 × 4.18 × 30

Energy required = 1.16 × 10¹⁰ J

Hence, number of moles of photons required = 1.16 × 10¹⁰ J/2.30 × 10⁵ J/mol

Number of moles of photons required = 5.04 × 10⁴ moles

What volume will 28 grams of nitrogen gas occupy at 27 Celsius and a
pressure of 785 mm Hg?

Answers

Answer: [tex]2.49\ m^3[/tex]

Explanation:

Given

Mass of nitrogen present [tex]m=28\ g[/tex]

Temperature [tex]T=27^{\circ}C\equiv 300\ K[/tex]

Pressure [tex]P=785\ mm\ \text{of}\ Hg\ \text{or}\ 1.032\ atm[/tex]

The molar mass of Nitrogen [tex]M=28\ g/mol[/tex]

No of moles of nitrogen present

[tex]n=\dfrac{m}{M}\\\\n=\dfrac{28}{28}\\\\n=1[/tex]

Using [tex]PV=nRT[/tex]

[tex]\Rightarrow 1.032\times V=1\times 8.314\times 300\\\\\Rightarrow V=\dfrac{2494.2}{1.032}\\\\\Rightarrow V=2494.2\ L\ \text{or}\ 2.49\ m^3[/tex]

Object X carries a net negative charge. Danny touches object X and all of the excess negative charge leaves it. Danny effectively grounds object X by touching it.

Answers

Answer: B.) Object X Is A Conductor

Explanation: Since object X was able to lose all of its charge by being grounded, this means that its charges were able to move about freely. This strongly suggests that object X is a conductor. If object X had been an insulator, the ground would have had virtually no effect on its net charge.

Is water an acid, base, or neutral?

Answers

Water is neutral because there is an balance between hydroniums and hydroxyls

how a scientist might use a graph of the
relationship between population growth and time to identify
a trend

Answers

Agora hemorrhage resqoio

The bullet train was traveling at a speed of 200mi/hr for 2 hours. What
was the total distance traveled? *
O 100mi
O 01mi
O 40mi
O 400mi

Answers

Answer:

Distance is speed x time

So 200 x 2 =400mi

At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppose a vessel contains SO3 at a concentration of 1.44M . Calculate the concentration of SO3 in the vessel 0.240 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.

Answers

Answer:

[tex][SO_3]=0.25M[/tex]

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

[tex][SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}[/tex]

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

[tex][SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\[/tex]

[tex][SO_3]=0.25M[/tex]

Best regards!

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