The IUPAC name for the compound shown is 3-ethyl-2,2-dimethylpentane.
International Union of Pure and Applied Chemistry is referred to as IUPAC. The terminology for naming organic compounds has been provided by IUPAC. The root name, prefix, and suffix are the three components that make up an IUPAC name.
There are five carbon atoms in the longest chain. Consequently, pent is the structure's root name. Choose the longest chain where the substituents are represented by the fewest numbers.
On the longest chain, three substituents are present. It consists of one ethyl group and two methyl groups. One ethyl group and two methyl groups are substituted at C-2 and C-3, respectively. Therefore, 3-ethyl-2,2-dimethyl will be the prefix. Alkane makes up the functional group. Therefore, the suffix is ane.
This ends up naming the compound as 3-ethyl-2,2-dimethylpentane.
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The synthesis of sodium chloride according to the reaction: ___ Na + ___ Cl2 → ___ NaCl.a. What volume of chlorine gas at STP is necessary for the complete reaction of 4.85 grams of sodium metal.
Answer:
[tex]2.36\text{ L }[/tex]Explanation:
Here, we want to know the volume of chlorine gas necessary to complete the reaction
We can start by writing a balanced equation of reaction as follows:
[tex]2Na\text{ + Cl}_2\text{ }\rightarrow2NaCl[/tex]From the balanced equation, we can see that 1 mole of chlorine gas requires 2 moles of sodium metal
Now, let us get the number of moles of sodium metal that actually reacted
We have that as the mass of sodium metal divided by the atomic mass
The atomic mass of sodium metal is 23 amu
Thus, we have the number of moles as:
[tex]\frac{4.85}{23}\text{ = 0.211 mole}[/tex]Since the mole ratio is 2 to 1, half of this number of moles is needed by the chlorine gas
Mathematically, 1 mole of a gas occupies a volume of 22.4 L at STP
the volume occupied by the calculated number of moles will be:
[tex]\frac{0.211}{2}\times\text{ 22.4 = 2.36 L }[/tex]How should the electrode of a pH meter be preserved? Explain your answer.
We can care for the pH meter electrode by;
1) Making sure that the electrode remains moist
2) The electrode should be stored in a 4M solution of KCl
3) Electrodes should not come in contact with deionized water.
What is pH?The term pH has to do with the negative logarithm of the hydrogen ion concentration. Now we know that the pH of a solution tells us the amount of the hydrogen ions or the hydroxyl ions that is present in the solution. The pH mete is the instrument that we could use to be able to measure the pH of the solution.
The pH scale runs between 0 - 14. The points on the scale that have been labeled from 0 - 6 tells us that the solution is an acidic solution and contains more hydrogen ions. If the solution has a pH of 7, then it is neutral and contains equal concentration of hydrogen and hydroxyl ions. A solution of pH 8 - 14 is basic and contains more hydroxyl than hydrogen ions.
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The first-order rate constant for the decomposition of N2O5,
2N2O5(g)→4NO2(g)+O2(g)
at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.50×10−2 mol of N2O5(g) in a volume of 1.6 L What is the half-life of N2O5 at 70 ∘C ?
The half-life of N₂O₅ at 70°C then it is 50s or 0.8min
Half life is the the interval of time required for one half of the atomic nuclei of a radioactive sample to decay
The first-order rate constant for the decomposition of N₂O₅ and reaction is
2N₂O₅(g) → 4NO₂(g)+O₂(g)
The half life is the time at which the concentration of N₂O₅ is the half initial concentration that is [ N₂O₅ ] = 1/2 [ N₂O₅ ]₀
Using this same equation then
ln ([N₂O₅]) = -2kt + ln ([N₂O₅]₀)
We replace [ N₂O₅ ] by 1/2[ N₂O₅ ]₀ and solve for t
ln (1/2 [N₂O₅]₀) = -2kt + ln ([N₂O₅]₀) applying logarithmic property
ln 1/2 + ln([N₂O₅]₀) = -2kt + ln ([N₂O₅]₀) solving for t and applying logarithmic property (ln 1/2 = ln 1 - ln 2 = 0 - ln 2 = - ln 2)
t = ln 2/2k
t = 50s or 0.8min
The half-life of N₂O₅ at 70°C then it is 50s or 0.8min
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Calculate the number of mol corresponding to 18.8 g Na2SO4.
Answer: 0.132 moles of Na2SO4
Explanation:
Multiply the grams of Na2SO4 by the 1/molar mass of Na2SO4, which is the sum of all the elements 2(Na)+S+4(O)= 142.04.
10) The chemistry lab has had a power cut and the electronic balance isn't working. You need to find the mass of a sample of zinc. You found
an old reference book and know that zine has a density of 7.14 g/mt. You found the volume of the sample using water displacement; 15.0
ml. of water was placed into a graduated cylinder, the zinc sample was added and the volume of the zinc with the water was 17.9 ml.
What is the mass of the zinc sample?
Atomic mass of zinc is 65. Simply dip one strip into the water for 3 seconds, remove it and shake once to remove excess water, wait 20 seconds for the color to develop, and compare it to the closest color match to determine your zinc concentration.
What is zinc in water?Water naturally contains zinc. In seawater, the average zinc concentration is 0.6-5 ppb. Zinc concentrations in rivers range between 5 and 10 ppb. Algae have 20-700 ppm, sea fish and shellfish have 3-25 ppm, oysters have 100-900 ppm, and lobsters have 7-50 ppm.Zinc has the chemical symbol Zn and the atomic number 30. At room temperature, zinc is a slightly brittle metal with a shiny-greyish appearance when oxidation is removed. It is the first element in periodic table group 12. Zinc is a trace mineral, which means that the body only requires trace amounts, but it is required by nearly 100 enzymes to carry out vital chemical reactions.To learn more about zinc, refer to:
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The Lewis dot model of a molecule is shown.
H
c=o
H
Based on the model, which of the following is true? (5 points)
O a
Ob
Oc
d
Oxygen is the least electronegative of the three atoms.
Carbon has a total of four bonded pairs of electrons around it.
Oxygen has four pairs of non-bonding Innermost shell electrons.
Carbon has an incomplete octet as it transfers an electron to each hydrogen.
Time left for this
The Lewis dot model of a molecule is shown as -
H \ C = : O : / HOn the basis of this model, the statement which is true is Carbon has a total of four bonded pairs of electrons around it.
Formaldehyde, HCHO has two hydrogen atoms, one carbon atom and one oxygen atom. Oxygen and carbon has double bond between them. Carbon atom is located at the center in the lewis dot structure. Valence electrons in the outer shell of carbon is four. Four electrons of carbon are bonded as it is bonded with two hydrogen atoms and one oxygen atom and oxygen and carbon atom has double bond between them.
Therefore, Carbon has total of four bonded pairs of electrons around it. Hence, this statement is true.
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Draw a flow sheet to show how you would separate the components of a mixture containing an acid substance, toluic acid, a basic substance, p-bromo-aniline, and anthracene, a neutral substance.
In order to separate the mixture of toluic acid, p-bromo-aniline, and anthracene, the difference in their physical properties such as solubility in organic or inorganic solvents is utilized.
The flow chart for the separation method is found in the attachment.
What are mixtures?Mixtures are substances that consist of two or more substances that are physically combined together.
The physical properties of the components of the mixture are employed in the separation of the constituents of the mixture
In separating the given mixture, it is first dissolved in dichloromethane, and then dilute NaOH is added to separate the toluic acid in the aqueous phase. The toluic acid is then precipitated by adding HCl.
Dilute HCl is then added to the organic phase to separate p-bromo-aniline into an aqueous phase and then precipitated by adding 10% NaOH.
Anthracene is left in the organic phase.
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2Al + 3Cl₂ 2AlCl₃molar mass of AlCl3 => 133 g/molIf 25.0 moles of chlorine is used, how many grams of aluminum chloride can be produced?
Answer
Explanation
Given:
2Al + 3Cl₂ 2AlCl₃
Molar mass of AlCl3 => 133 g/mol
Moles of Cl₂ = 25.0 mol
What to find:
The grams of aluminum chloride that can be produced.
Step-by-step solution:
Step 1: Determine the mole of AlCl₃ produced.
From the given chemical equation for the reaction,
3 mol Cl₂ produce 2 mol AlCl₃
So 25.0 mol Cl₂ will produce
[tex]\frac{25.0mol\text{ }Cl_2\times2mol\text{ }AlCl₃}{3mol\text{ }Cl_2}=16.67mol\text{ }AlCl₃[/tex]16.67 moles of AlCl₃ produced.
Step 2: Calculated the grams of AlCl₃ produced.
Using the mole formula
[tex]undefined[/tex]In aqueous solution, 5.2 mg of iron(III) chloride reacts with excess ammonium hydroxide.A. Write and kalance the equation, including phasesB. Is this a limiting reactant problem? Why or why not?C. Calculate the moles of each product that are formedD. Calculate the grams of each product that are formedI already answered part a and b. I need help on part c and d.
With a balanced reaction, we can determine the moles of products. The balanced equation will be:
FeCl3 + 3NH4OH → Fe(OH)3 + 3NH4Cl
They says that NH4OH is in excess, so, the limiting reactant will be FeCl3 and we will do all the calculations with this reactant.
We have to calculate the moles of FeCl3, we will use the molar mass:
[tex]\begin{gathered} molFeCl_3=5.2mg\times\frac{1g}{1000mg}\times\frac{1molFeCl_3}{MolarMass,gFeCl_3} \\ molFeCl_3=5.2mg\times\frac{1g}{1,000mg}\times\frac{1molFeCl_3}{162.2gFeCl_3}=3.2\times10^{-5}molFeCl_3 \end{gathered}[/tex]Now, to calculate the moles of the products we must take into account the product/reactive ratios, for this we are guided by the coefficients that accompany the molecules.
Ratio Fe(OH)3 to FeCl3 = 1/1
Ratio NH4Cl to FeCl3 = 3/1
Moles of each product
Moles of Fe(OH)3
[tex]molFe(OH)_3=3.2\times10^{-5}molFeCl_3\times\frac{1molFe(OH)_3}{1molFeCl_3}=3.2\times10^{-5}molFe(OH)_3[/tex]Moles of NH4Cl
[tex]molNH_4Cl=3.2\times10^{-5}molFeCl_3\times\frac{3molNH_4Cl}{1molFeCl_3}=9.6\times10^{-5}molNH_4Cl[/tex]The grams of each product we will find by multiplying the moles by the molar mass. So we have.
g of Fe(OH)3
[tex]\begin{gathered} gFe(OH)_3=3.2\times10^{-5}molFe(OH)_3\times106.87g/molFe(OH)_3 \\ gFe(OH)_3=3.4\times10^{-3}g=3.4mg \end{gathered}[/tex]g of NH4Cl
[tex]\begin{gathered} gNH_4Cl=molNH_4Cl\times MolarMassNH_4Cl \\ gNH_4Cl=9.6\times10^{-5}molNH_4Cl\times53.491g/molNH_4Cl=5.1\times10^{-3}g=5.1mg \end{gathered}[/tex]If carbon has undergone neutron capture what happened?
Answer:
It would generate a electro lithium nucleous
Lidocaine, a widely used local anesthetic, it’s available as a 0.5% (w/v) Solution for injection. Calculate the mass of lidocaine and 6.0 mL of the solution. Be sure your answer has a unit symbol and is rounded to the correct number of significant digits.
• We are given that Lidocaine is available as 0.5%(w/v) , 0.5%(w/v) represents the amount of Lidocaine in grams per 100mL. so, 0.5% is the same as 0.5g of Lidocaine in 100ml.
,• Since our solution has a volume of 6.0mL:
mass of Lidocaine = 6mL * (0.5g /100mL)
= 0.03g of Lidocaine in 6.0mLsolution.
This means that, in 6.0ml of this injection solution, we have 0.03g of Lidocaine .
The planet Jupiter is composed mostly of hydrogen gas.To what temperature, in ºc, must a 20.2 g sample of hydrogen gas be heated to, at 140 kPa, tooccupy a volume of 224 L?
We are asked to find the temperature of hydrogen gas (H2) given certain pressure and temperature conditions. Since the pressure to which the gas will be subjected is low we can apply the ideal gas law which is represented by the following equation:
[tex]PV=nRT[/tex]Where,
P= Pressure = 140kPa = 1.38169 atm
V= Volumen = 224 L
R= Ideal gas constant = 0.08206 (atm L)/(mol K)
n= Number of moles
T= Temperature in K
Now we are going to find the number of moles of the gas, n. We will use the molar mass of the hydrogen gas (2.01594g/mol). So, we have:
[tex]n=\text{ }\frac{\text{Mass}}{Molar\text{ mass}}=\frac{20.2\text{ g}}{2.01594\text{ g/mol}}=10.02\text{ mol}[/tex]Now, we will clear the temperature T from the first equation:
[tex]T=\frac{PV}{nR}[/tex]We replace the known values:
[tex]\begin{gathered} T=\frac{1.38169atm\times224L}{10.02mol\times0.08206\frac{atm.L}{mol.K}} \\ T=376.40K \end{gathered}[/tex]So, the temperature of hydrogen gas will be 376.40K
Uranium-238 is an unstable nuclide that emits an alpha particle, three neutrons, and
gamma particles. A = 231 and Z = 90. What daughter nuclide is formed from this
reaction?
OA) Ra
232U2a + 2x + 3 n + Y
-
B) Pu
C) Th
D) Fr
Uranium-238 is an unstable nuclide that emits an alpha particle, three neutrons, and
gamma particles and produces a daughter nuclide Thorium.
The atomic mass of alpha particle is 4g and atomic number 2. Since an alpha particle emits, so there is reduction in the atomic mass 4 and atomic number 2.
The atomic number of neutron is 0 and the atomic mass of neutron is 1. When three neutrons emit the atomic mass reduces to 3 while atomic number remains same.
Gamma particles have no mass and charge. So, atomic number and atomic mass remains same.
Total reduction in atomic mass : 238 - 4 - 3 = 231.
Total reduction in atomic number = 92- 2 = 90
Therefore, the daughter nuclide is Thorium.
Thus, we concluded that the Uranium-238 is an unstable nuclide that emits an alpha particle, three neutrons, and gamma particles and produces a daughter nuclide Thorium.
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Which of the following changes are chemical changes?
Answer:
flammability, toxicity etc..
Explanation:
are chemical changes
PLEASE HELP!! What is the WEIGHTED average atomic mass of this element?
An isotope with mass 185 amu is 19% abundant
An isotope with mass 180 amu is 81% abundant
Hello. This is Mr. Biederman, your science teacher at Insight School of Michigan. You are obviously one of my students. Posting content here is against school policy. Just ask me directly for help. I am always happy to help with anything!
After an afternoon party, a small cooler full of ice is dumped onto the hot ground and melts. If the cooler contained 9.10 kg of ice and the temperature of the ground was 42.0 °C, calculate the energy that is required to melt all the ice at 0 °C. The heat of fusion for water is 80.0 cal/g
The heat energy that is required to melt all the ice at temperature of 0° C is 7.28x10^5 cal.
What is heat energy?
Heat energy is created by the movement of tiny atoms, molecules, or ions in solids, liquids, and gases. It is possible to transfer heat energy from one thing to another. Heat is a flow or transfer that happens when two objects have different temperatures from one another.
We know that the initial temperature of the ice (T) is 0° C
Latent heat of ice is given in the question as 80.0 cal/g
The mass of ice given in question is 9.10 kg
So, the heat required to change the phase of the ice is given as:
[tex]Q=mL[/tex]
[tex]Q =(9.10 \times 10^3)(80)[/tex]
[tex]Q = 728 \times 10^3[/tex]
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Give the names of following compounds (in aqueous solution):
HBr
7 HBrO
2 HCN
3 H₂CO3
4 HC₂H302
5 H₂SO4
6 H3ASO3
8 HNO2
9 HC104
10 H₂C2O4
11 H3PO4
12 H₂CrO4_
Here are all names of compounds in aqeous solution.
What is aqeous solution?
An aqeous solution is one in which the solvent is liquid water .
In this solution water act as a solvent.
Sol-
HBr- Hydrogen bromide
1-HBrO- hydrobromic acid
2-HCL-hydrochloric acid
3-H2O3- hydrogen peroxide
4- HC2H3O2- glacial acetic acid
5-H2SO4-sulfuric acid
6- H3ASO3- Arsenous acid
7- HNO2- Nitrous acid
8- HC104- Perchloric acid
9-H2C2O4- oxalic acid
10- H3pO4- phosporic acid
11-H2CrO4- chromic acid
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If 335g water at gains 102.3 J of heat, how much does the temperature of the water change? The specific heat of water is 4.184 J/g*C
Temperature is a measure of how hot a substance or radiation is expressed numerically.
There are three different types of temperature scales:
those that depend only on macroscopic properties and thermodynamic principles, like Kelvin's original definition;
those that depend on practical empirical properties of particles rather than theoretical principles;
and those that are defined by the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron, in a body, like the SI scale.
How much heat is gained or lost by a sample can be calculated using the equation q = mcΔT, where m is the mass of the sample, c is the specific heat, and T is the temperature change (q).
Therefore,
q = m*c*ΔT
102.3 = 335 * 4.184 * ΔT
ΔT = 0.073 °c
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What are the strengths, weaknesses, and implications of risk/benefit analysis as a method for deciding whether a technology should be employed?
A risk-benefit analysis compares the risks and benefits of a situation and determines whether the advantages outweigh the disadvantages.
What is Risk-benefit analysis in technology?Strengths
Risk-benefit analysis calculates the amount of time will be worth it to the production of technology and whether the technology will have a healthy impact on the industry or not.
Weaknesses
Risk-benefit analysis cannon determine product implementation and the outcomes of real life experiences of individual customers. It has some drawbacks like benefits of customer is take under consideration but pollution in nature is not calculated.
Implication
Risk-benefit analysis is implied in almost all technical industry as it the decision maker of any developing team to work on a particular project or not. Some examples are automobile industry and smartphone industry.
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The Lewis dot model of a molecule is shown.
H
c=o
H
Based on the model, which of the following is true? (5 points)
O a
Ob
Oc
d
Oxygen is the least electronegative of the three atoms.
Carbon has a total of four bonded pairs of electrons around it.
Oxygen has four pairs of non-bonding Innermost shell electrons.
Carbon has an incomplete octet as it transfers an electron to each hydrogen.
Time left for this
Answer:
b.Carbon has a total of four bonded pairs of electrons around it.
Find the volume in liters of the 0.505 molar NaOH solution needed to react with 40 milliliters of the 0.505 molar H2SO4 solution.
A//: 80 mililiters
Please, it's urgent, I need it ASAP
The volume of NaOH required is 80ml.
Sulfuric acid is a dibasic acid and NaOH is monoacidic base.
M1V1 = M2V2
where, M1 = initial concentration,
V1 = initial volume,
M2 = concentration after mixing
V2 = total final volume.
This formula is used for calculating the final volume or molarity after mixing two solutions.
Given the question,
M1 = 0.505M
V1 =?
M2 = 0.505M
V2 = 40 ml
M1V1 = 2×M2V2
0.505 × V2 = 2 × 0.505 × 40
V2 = 2×0.505×40
0.505
V2 = 80ml
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What is the mass of this piece of porcelain in oz?Show all work/use conversions/metric prefixes. I
The mass of the piece of porcelain is 27.3 oz.
1st) It is necessary to calculate the mass of the porcelain with the density formula:
[tex]\begin{gathered} \text{density}=\frac{mass}{\text{volume}} \\ 2.40g\mathrm{}mL^{-1}=\frac{mass}{325mL} \\ 2.40g.mL^{-1}\cdot325mL=\text{mass} \\ 780g=\text{mass} \end{gathered}[/tex]2nd) Now it is necessary to convert the gram unit to oz. Here we need to use the relation that 1 g is equal to 0.035 oz:
[tex]780g\text{.}\frac{0.035oz}{1g}=27.3oz[/tex]So, the mass of the piece of porcelain is 27.3 oz.
Phthalic acid ( H2C8H4O4) is a diprotic acid with a1=1.12×10−3 and a2=3.90×10−6. Determine the pH of a 0.294M phthalic acid ( H2C8H4O4 ) solution.
pH of the acid can be calculated from the first and second ionization constants of the acid. The pH of 0.294 M of Phthalic acid is 0.53.
What is pH?pH of a solution is the measure of its H+ ion concentration.It measures the acidity or basicity of the solution. Mathematically it is the negative logarithm of hydrogen ion concentration.
pH = -log [H+]
Give that the first ionization constant of the acid is 1.12 × 10 ⁻³ and second ionization constant is 3.90 × 10⁻⁶. The diprotic acid can be represented as H2A and after its first ionization it produce HA- and H+ On the second ionization the base A- and H+ ion is produced.
The second ionization constant a₂ is written as follows:
a₂ = [A-] [H+] / [HA - [A]] = 3.90 × 10⁻⁶
From this simply we can get [A] = 3.90 × 10⁻⁶
Thus [H+] = H₂A - [A]
The concentration of the diprotic acid H₂A is given 0.294 M.
Thus [H+] = 0.294 - 3.90 × 10⁻⁶
= 0.2933 M
Now, the pH is calculated as follows:
pH = -log (0.2933)
= 0.53.
Therefore, the pH of 0.294 M of Phthalic acid is 0.53.
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13. A gas of unknown molecular mass was allowed to effuse through a small opening under
constant pressure conditions. It required 72 s for the gas to effuse. Under identical
experimental conditions, it required 28 s for O₂ gas to effuse. Determine the molar mass
of the unknown gas.
The molar mass of unknown gas is 211.59 g/mol.
What is effusion of gases?Effusion occurs when a gas pass through an opening that is smaller than the mean free path of the particles, which is the average distance traveled between collisionsGraham's law is an empirical relationship which states that ratio of the rates of diffusion or effusion of two gases is the square root of the inverse ratio of their molar masses.Higher the molar mass of a gas, slower the effusionSince both the gases are present in identical experimental condition, using Grahams law of effusion:
[tex]\frac{time req for unknown gas}{time of oxygen}[/tex] = [tex]\sqrt{\frac{Molar mass of unknown gas}{molar mass of Oxygen} }[/tex]
Given:
Time of unknown gas = 72 sec
Time of Oxygen = 28 sec
we know the molar mass of oxygen = 32 g/mol
Now substituting:
[tex]\frac{72 sec}{28 sec} = \sqrt{\frac{M.M of unknown}{32g/mol} }[/tex]
M.M of unknown = (72 / 28)² × 32 g/mol
= 211.59 g/mol
So the molar mass of unknown gas is 211.59 g/mol
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How many moles of water will be produced if 3.50 moles of hydrogen react completely?___H2(g) + ___O2(g) ___H2O (l)
ANSWER
Moles of water is 3.50 moles
EXPLANATION
Given that:
The mole of hydrogen gas is 3.50 moles
Firstly, write a balanced equation for the reaction
[tex]\text{ 2H}_{2(g)}+\text{ O}_{2(g)}\rightarrow\text{ 2H}_{2_}O[/tex]In the reaction, 2 moles of hydrogen will give you 2 moles of H2O
Since the number of moles of hydrogen given id 3.5 moles, then the number of moles of water.
The mass of acetic acid in a 2.00 mL sample of vinegar (density of the vinegar is 0.996 g/mL) is determined to be 0.101 g. What is the mass % of acetic acid in the vinegar using 1 decimal place in your final answer?
The percentage of mass of 0.101g in 2.093g of vinegar comes out to be 4.8%. Mass percentage does not have any unit as numerator and denominator contains the same unit.
What is percentage by mass?Mass percentage represents the the percentage of each element that is making a particular compound.
mass of vinegar solution =density of vinegar solution× volume of vinegar solution
=0.996 g/mL×2.00 mL
=1.992g
Percentage of mass=(mass of acetic acid ÷ total mass of solution) x 100%
=[0.101÷(0.101+1.992)]×100
=0.048×100
=4.8%
Thus the mass percentage of acetic acid is 4.8%
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Two different samples, A and B, of zinc oxide were obtained from different sources. When heated in a stream of hydrogen, they were reduced to yield the following results: sample A mass of sample 10.0g mass of zinc residue 8.11g sample B mass of sample 13.2g mass of zinc residue 10.70g. Show that the figures illustrate the law of constant composition
-ZnO is the compound illustrated by the law of constant composition.
According to the rule of constant proportion, the elements are always present in certain amounts to one another by mass in chemical compounds. For instance, regardless of how or where water is obtained, it always contains H2O, hydrogen, and oxygen in a mass ratio of 1:8, according to an example.
for sample A
mass Zn = 8.11g
mass of O =10-8.11=1.89g
Zn= 8.11/65 = 0.1
O= 1.89/16 =0.1
ratio is 1:1
compound = ZnO
for sample b
Zn= 10.70g
O= 13.2-10.7=2.5g
Zn= 10.70/65 =1
O= 2.5/16 =0.16=1
ratio = 1:1
compound= -ZnO
Therefore, it is shown that the figures illustrate the law of constant composition.
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A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O2 gas to produce carbon dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of 0.900mol of octane. Be sure your answer has a unit symbol, if necessary, and round it to 3 significant digits.
When 0.900mol of octane is burned in air it reacts with oxygen Oxygen gas to produce carbon dioxide gas and water vapor, then 7.20mole of carbon dioxide is produced.
What is combustion reaction?
Combustion reaction is a reaction in which a substance, basically hydrocarbons burns in presence of oxygen to produce carbon dioxide and water.
The balanced reaction is
[tex]2C_{8} H_{18}+25O_{2} \rightarrow16CO_{2} +18H_{2}O[/tex]
The mole ratio of octane to carbon dioxide is 2:16 that is 1:8
2 mole of octane produce =16 mole of carbon dioxide
1 mole of octane produce = 8 mole of carbon dioxide
0.900mol of octane produce= 8× 0.900
= 7.20mole
Thus the mole of carbon dioxide produced is 7.20mole.
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Following the Experiment 3 procedure, you combine 50.0 mL H2O, 50.0 mL of 2.2 M HCl(aq), and 4.039 g NaOH(s) (molar mass of NaOH = 40.00 g/mol) in a Styrofoam calorimeter, recording a maximum solution temperature change of 22.9 oC and a final solution mass of 104.153 g (csolution = 4.184 J/g.oC). Calculate the molar change in enthalpy of reaction
The molar change in enthalpy of reaction is 99.6 kJ/mol.
the formula for the specific heat capacity expressed as :
Q = mcΔT
where,
m , mass = 104.153 g
c, specific heat = 4.184 J/g °C
dt, change in temperature = 22.9 °C
Q = 104.153 × 4.184 × 22.9
Q = 9969.7 J = 9.96 kJ
now, the molar change in enthalpy is give by:
Q = ΔH / n
n is no. of moles
morality of HCl = 2.2 M
v = 50 mL = 0.05 L
n = 0.05 × 2.2
= 0.11 moles
no. of moles of NaOH = mass / molar mass
= 4.039 / 40
= 0.100
NaOH is limiting reactant.
using the formula we get:
Q = ΔH / n
ΔH = Q / n
ΔH = 9.96 kJ/ 0.10
ΔH, change in enthalpy = 99.6 kJ/mol
Thus, combine 50.0 mL H₂O, 50.0 mL of 2.2 M HCl(aq), and 4.039 g NaOH(s) (molar mass of NaOH = 40.00 g/mol) in a Styrofoam calorimeter, recording a maximum solution temperature change of 22.9 °C and a final solution mass of 104.153 g (c solution = 4.184 J/g°C). the molar change in enthalpy of reaction is 99.6 kJ/mol.
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Acetone has a density of 0.7857 g/cm^3. What is the volume in mL of 5.52 g of acetone?
Let's see that the formula to find the volume using density and mass is:
[tex]V=\frac{m}{d}\begin{cases}V=\text{volume} \\ m=\text{mass} \\ d=\text{density}\end{cases},[/tex]In this case, the problem is asking about the volume in mL but remember that mL is the same that cm^3, so using the formula we're going to obtain:
[tex]V=\frac{5.52\text{ g}}{0.7857\text{ }\frac{g}{mL}}=7.02\text{ mL.}[/tex]The volume of 5.52 g of acetone is 7.02 mL.