Answer:
Staying single makes it a whole lot easier to focus on yourself, gain self love, and work on yourself!
Explanation:
According to Clark Hull, our behavior is based on the need to reduce unwanted arousal
caused by physiological needs like hunger, thirst, and fatigue. He called these physiological
needs...
urges
drives. Desires. None of these.
Answer:
Clark Hull put the emphasis of his work on experimentation, an organized theory of learning, and the nature of habits, which he argued were associations between a stimulus and a response
Explanation:
1. Some ripples spread across a pond with a frequency of 5 Hz. How much would be the period of these ripples.
2. A sound wave has a time period of 0.01 seconds. What is its frequency?
3. A radio wave has a time period of 0.0000002 seconds. What is its frequency?
1)The period of these ripples will be 0.2 sec.
2)The time period of sound wave will be 100 Hz.
3)The frequency of the sound wave will be 5×10⁶ Hz.
What is frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
Frequency is given by the formula as,
Frequency of ripples (f₁)=5 Hz
The period of these ripples will be;
T₁=1/f₁
T₁=1/5
T₁=0.2 sec
The time period of sound wave (T)=0.01 seconds
The time period of sound wave;
f=1/T
f=1/0.01
f=100 Hz
Time period of A radio wave = 0.0000002 seconds
The frequency of the sound wave is;
f=1/T
f=1/0.0000002
f=5×10⁶ Hz
Hence,the period of these ripples will be 0.2 sec.
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what particle moves from one object to another so that the object is either positively charged or negatively charged
Answer:
electrons move causing the object to be positive or negative charged
7. It has been suggested that rotating cylinders about 20 km in length and 8 km in diameter be placed in space and used as colonies. The purpose of the rotation is to simulate gravity for the inhabitants. Explain this concept for producing an effective imitation of gravity.
The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.
What is centrifugal force?when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.
It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.
The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.
To simulate gravity for the inhabitants, the concept of the centrifugal force is used.
Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.
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what are the 5 super typhoons that entered the Philippine Area of Responsibility (PAR)?
Answer:
2.1 Typhoon Damrey (Asiang)
2.2 Tropical Storm Longwang (Biring)
2.3 Tropical Depression 03W (Konsing)
2.4 Tropical Depression 04W.
2.5 Unnamed tropical depression.
Explanation:
Which is the load
Answer:
A is the load in the diagram
Answer:
i think the answer is A
Spirderman’s nemesis Electro delivers 4kJ of electrical energy in half a second. How powerful is he?
A triangular prism made of crown glass (n=1.52) with base angles of 30.0 is surrounded by air. If parallel rays are incident normally on its base as shown in fig., what is the angle of ϕ between the two emerging rays?
Answer:
es lo que es
Explanation:
es lo que es es que slep vaka vee
the angle ϕ= will be equal to angle of refraction and it is equal to 49.4°C.
What is refractive index ?When a light is going from medium 1 to medium 2. The refractive index is defined as a ratio of velocity of light in medium 1 to velocity of light in medium 2. Refractive index is the factor which deals with the amount of bending of light. More refractive index means more it will bend in the medium 2. When it is 1 we can say that light has not been bent.
By Snell's law, Refractive index is given by,
sin (i) ÷ sin (r) = μ₂÷μ₁
where i is the the angle of incidence
r is the angle of refraction
μ₂ & μ₁ are refractive index of medium 2 and 1 resp.
Hence it is due to Refractive index.
In this problem the light is going from prism to air, the refractive index of air is 1. From figure it is clear that the angle of incidence is 30°C.
From snell's law,
sin (30) ÷ sin (r) = μ₂÷1.52
0.5 ÷ sin (r) = 1÷1.52
0.5×1.52 = 1×sin (r)
0.76 = sin (r)
The angle of refraction r = sin⁻¹(0.76) =49.4°C
Hence angle ∅ = 49.4°C.
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3. A bottle of vitamin C contains 100 tablets and weighs 80 g. If the
bottle alone weighs 23 g. (a) What is the mass of one tablet? (b) What is
the mass of 36 tablets? (c) What is the weight of 50 tablets?
Answer:
a
0.57g
b
20.52
c
28.5
Explanation:
a
The bottle weighs 80g with tablets
If the bottle alone weighs 23g, the tablets weigh 57g
100 tablets weigh 57g, 1 tablet weighs 0.57g
b
0.57g is one tablet, so to achieve 36 tablets we must multiply by 36
0.57 multiplied by 36 is 20.52
c
To find 50 tablets we can use the same method we used before or a slightly faster method
100 tablets is 57g, so all we have to do is halve to find 50
57 divided by 2 is 28.5
Where on the periodic table are nonmetal elements mostlikely found?
A. Along the stairstep line
B. On the right side
C. On the left side
D. At the bottom
Answer: B. On the right side
Explanation: Metals are located on the left of the periodic table, and nonmetals are located on the upper right.
PLEASE ANSWER ASAP FOR 75 POINTS!!!!
λ = c : f
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.86 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.86
E = 1.896 x 10⁻³³ J
λ = 3 x 10⁸ : 1.011 x 10⁸
λ = 2.97 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.97
E = 1.97 x 10⁻³³ J
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.96 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.96
E = 1.96 x 10⁻³³ J
The weight of an object on the surface of mass is 1850 Newton and its mass is 500kg.Find the acceleration due to gravity on mars
F = m.a
a = F/m
a = 1850/500
a = 3.7 m/s²
An 845–g bar of ice is initially at –25 °C. The latent heat of fusion of ice is 334 kJ/kg, the specific heat of ice is 2050 J/(kg·°C), and the specific heat of water is 4180 J/(kg·°C). Determine how much energy is required if the final temperature of the system is to reach 39 °C.
Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 463.28 kJ.
Calorimetry, sensible heat and latent heatCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
Latent heat is defined as the energy required by a quantity of substance to change state.
When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.
Energy required in this case-25°C to 0 °CIn firts place, the melting point of water (temperature at which it changes state from solid to liquid) is 0°C.
So, first of all you must increase the temperature from -25 ° C (in solid state) to 0 ° C, in order to supply heat without changing state (sensible heat).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
c(ice)= 2050 [tex]\frac{J}{kgC}[/tex] m= 845 g= 0.845 kgΔT= Tfinal - Tinitial= 0 °C - (-25) °C= 25 °CReplacing:
Q1= 2050 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 25 °C
Solving:
Q1= 43,306.25 = 43.3 kJ
Change of stateThe heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to
Q = m×L
where L is called the latent heat of the substance and depends on the type of phase change.
In this case, you know:
n= 0.845 kgΔHfus= 334 [tex]\frac{kJ}{kg}[/tex]Replacing:
Q2= 0.845 kg× 334[tex]\frac{kJ}{kg}[/tex]
Solving:
Q2= 282.23 KJ
0 °C to 39 °CSimilar to sensible heat previously calculated, you know:
c(liquid)= 4180[tex]\frac{J}{kgC}[/tex]m= 0.845 kgΔT= Tfinal - Tinitial= 39 °C - 0 °C= 39 °CReplacing:
Q3= 4180 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 39 °C
Solving:
Q3= 137,751.9 J= 137.75 kJ
Total heat requiredThe total heat required is calculated as:
Total heat required= 43.3 kJ + 282.23 kJ + 137.75 kJ
Total heat required= 463.28 kJ
In summary, the amount of heat required is 463.28 kJ.
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The amount of energy required if the final temperature of the system is to reach 39 °C is 463288.15 J
How to determine the heat required change the temperature from –25 °C to 0 °C Mass (M) = 845 g = 845 / 1000 = 0.845 KgInitial temperature (T₁) = –25 °C Final temperature (T₂) = 0 °Change in temperature (ΔT) = 0 – (–25) = 25 °C Specific heat capacity (C) = 2050 J/(kg·°C) Heat (Q₁) =?Q = MCΔT
Q₁ = 0.845 × 2050 × 25
Q₁ = 43306.25 J
How to determine the heat required to melt the ice at 0 °Mass (m) = 0.845 KgLatent heat of fusion (L) = 334 KJ/Kg = 334 × 1000 = 334000 J/KgHeat (Q₂) =?Q = mL
Q₂ = 0.845 × 334000
Q₂ = 282230 J
How to determine the heat required to change the temperature from 0 °C to 39 °C Mass (M) = 0.845 KgInitial temperature (T₁) = 0 °C Final temperature (T₂) = 39 °Change in temperature (ΔT) = 39 – 0 = 39 °C Specific heat capacity (C) = 4180 J/(kg·°C)Heat (Q₃) =?Q = MCΔT
Q₃ = 0.845 × 4180 × 39
Q₃ = 137751.9 J
How to determine the heat required to change the temperature from –25 °C to 39 °CHeat for –25 °C to 0°C (Q₁) = 43306.25 JHeat for melting (Q₂) = 282230 JHeat for 0 °C to 39 °C (Q₃) = 137751.9 JHeat for –25 °C to 39 °C (Qₜ) =?Qₜ = Q₁ + Q₂ + Q₃
Qₜ = 43306.25 + 282230 + 137751.9
Qₜ = 463288.15 J
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Mr. McSparin can walk one mile in 0.25 hours. Calculate his velocity.
Answer:
4 mph
Explanation:
velocity = miles divided by time = miles/time
= 1 mile / .25 hr = 4 mph
What is the purpose of an acid-base titration?
Answer:
the detection of the equivalence point, the point at which chemically equivalent amounts of the reactants have been mixed.
A reversible reaction is in
_______ when forward and reverse
directions of the reaction occur at the same rate so there is no overall change in the
amounts of reactants and products.
Answer:
Equilibrium
Explanation:
Equilibrium is a special situation or stage of a reactionAt equilibrium the concentrations of reactants and products are equalThe rate of change of forward and backward reaction is also sameWhat factors affect the strength and direction of electrical forces?
Answer:
The strength of the electric field is determined by the amount of charge on the source charge (Q) and the separation distance (d) from the source charge.
Explanation:
The interaction of charged objects is a non-contact force that operates over a certain separation distance. Distance, distance, distance. Every electrical contact is accompanied by a force, emphasizing the significance of these three factors. Whether it's a plastic golf tube attracting paper bits, two like-charged balloons repelling, or a charged Styrofoam plate interacting with electrons in a piece of metal, the three crucial factors that impact the strength of the interaction are always two charges and a distance between them. The electrical force, like all other forces, is usually measured in Newtons. The electrical interaction's intensity is a vector quantity with both magnitude and direction since it is a force. The electrical force's direction is determined by whether the charged objects are charged with similar or opposing charges, as well as their spatial orientation. With a little logic and knowledge of the two objects' charge types, the direction of the force on either of them may be determined. Objects A and B in the figure below have similar charges, hence they repel each other.
If a constant force of 917 N is exerted on a scooter for 6 s, thenwhat is the change in momentum?
a 6 kg-m/s
b 5502 kg-m/s
c 917 kg-m/s
d 153 kg-m/s
Answer: 917
Explanation:
The change in momentum if a constant force of 917 N is exerted on a scooter for 6s is 5502kg-m/s.
How to calculate momentum?Momentum is the tendency of a body to maintain its inertial motion. It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities.
Force = mass x (velocity/time)
Force = (mass x velocity)/time
Force = momentum/time
According to this question, a constant force of 917 N is exerted on a scooter for 6s. The change in momentum is calculated as follows:
917N = p/6
p = 5502kg-m/s
Therefore, 5502kg-m/s is the change in momentum of the scooter.
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A bullet of mass 25 g moving with a velocity of 200 cm/s is stopped within 5 cm of the target. The average resistance offered by the target is:
[tex]\huge{\boxed{{\colorbox{red}{1 N}}}}[/tex]
that's my answer
vf²=vi²-2ad (vf=0, stop)
vi²=2ad
200²=2.a.5
a = 200² : 10
F = ma
F = 25 x 200² : 10
F = 1 x 10⁵ dyne = 1 N
A student repeats a reaction several times to test the effects of various
changes on the reaction rate. The data table shows the results. How does
increasing the temperature of the system change thereaction rate?
A. Increasing the temperature decreases the reaction rate.
B. Increasing the temperature increases the reaction rate.
C. More information is needed to determine what happens to the reaction rate.
D. Increasing the temperature has no effect on the reaction rate.
Answer:
B. Increasing the temperature increases the reaction rate.
Explanation:
This is as with a higher temperature the particles have more kinetic energy, this is the consequece of the increase in reaction rate as the frequency of particles colliding is increased.
Answer: B
Explanation:
why is m² called derived unit?
Explanation:
The unit of energy is a derived unit because it is expressed with the help of fundamental units (kg) unit of mass and four basic units meter (m), meter (m) unit of length second (s), second (s) unit of time.
A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)
Answer:
[tex]\huge\boxed{\sf f=0.55 \ Hz}[/tex]
Explanation:
Given Data:
Length = l = 820 mm = 0.82 m
Acceleration due to gravity = g = 9.8 ms⁻²
Required:
Frequency = f = ?
Formula:
[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} }[/tex]
Solution:
[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} } \\\\Put\ the\ givens\\\\f=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.82} }\\\\ f = 0.159 \times \sqrt{11.95} \\\\f=0.159 \times 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}[/tex]
what is the gravitation potential energy of a 57 kg sightseer standing at the top of the empire state building which is 381m above ground level
GPE = mgh
GPE = 57 x 9.8 x 381 = 2.12 x 10⁵ J
What is the angle of refraction for a beam of light moving from air (n =1.00) into a prism if the angle
of incidence is 70° and the prism's index of refraction is 1.73?
big sorry for this
imma follow you
It is often said the media can make or break a person especially, sports personalities. Explain how that happens.
I'm going to school tomorrow so I can get the best of it
What happens to the force applied by the person pushing the crate (Fapplied
) as the frictional force increases? What can they do to change this force?
The force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.
What is friction?Friction is defined as the force resisting the relative motion of an object when moving on the surface of another object. This force slow down the speed of a moving object.
So we can conclude that the force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.
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Which of the following can refer to the form of exercise that uses free weights, weight machines, resistance bands, or the weight of the body to put stress on the muscles? A. Strength training B. Weight training C. Resistance training D. All of the above
Answer:
option C...
resistance training is the correct answer
A few friends went skating on the frozen lake in their hometown. At one point you can hear the ice cracking. What advice can you give them so that the ice does not break and the skaters on the lake are not endangered?
Answer: i'll tell them to be careful. However, the most common is using a drill bit. Take a step close to the shore and listen for cracking. If there is cracking, do not risk going out on the ice. If there is no cracking, take a cordless drill and check the thickness using an extended drill bit.
How could you reduce the cost of lighting? Explain your answer
Answer:
Don't over-light roomsInstall dimmers on your lightsTurn lights off
1. The sketch shows two 4 kg blocks on a horizontal surface, joined by a string S. They are attached to a 2 kg mass by another string which passes over a frictionless pulley, allowing the 2 kg mass to hang freely. Each of the blocks experiences 6 N of friction.
a) Show that the system accelerates to the right at 0.8 m/s². Calculate the tension in string S.
b) 4 kg S 4 kg 2 kg [4] [4]
Answer:
M g - T = M a acceleration of hanging block (M = 2)
2 g - T = 2 a where M = 2
T = 2 g - 2 a
T = 8 * a + 12 N acceleration of blocks on table
2 g - 2 a = 8 a + 12
10 a = 2 g - 12
a = .8 m/s^2 (assuming g = 10 m/s^2)
T = 2 g - 2 a = 2 * 10 - 2 * .8 = 20 - 1.6 = 18.4 N
Check: For blocks on table
a = (18.4 - 12) / 8 = 6.4 / 8 = .8 m/s^2