$14.90 spent with the amount left for an extra pencil or notebook being $0.30 or $1.50 short respectively indicates that a notebook costs $1.8 more than a pencil.
Which method can be used to calculate the difference in costs?Let x represent the cost of a notebook and let y represent the cost of a pencil. The following equations can be obtained;
4•x + 3•y = 14.9...(1)
Let a represent the total money Tina has, which gives;
4•x + 4•y = a - 0.3...(2)
5•x + 3•y = a + 1.5...(3)
Subtracting equation (2) from equation (3) gives;
5•x - 4•x + 3•y - 4•y = a - a + 1.5 - (-0.3) = 1.8
Which gives;
x - y = 1.8...(4) From the above, we have that the difference between the cost of a notebook and pencil is 1.8Multiplying equation (4) by 4 and subtracting the result to equation (1) gives;
4 × (x - y) = 4 × 1.8 = 7.2
4•x - 4•y = 7.2
4•x - 4•x + 3•y - (-4•y) = 14.9 - 7.2 = 7.7
7•y = 7.7
y = 7.7 ÷ 7 = 1.1The cost of a pencil, y = $1.1x - y = 1.8
x = 1.8 + 1.1 = 2.9
Cost of a notebook, x = $2.9The difference between the cost of a notebook and the cost of a pencil is therefore;
x - y = $2.9 - $1.1 = $1.8
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A team of 10 volunteers is visiting families in a local community to deliver canned goods. It takes one volunteer 24 hours to complete one visit. What is the capacity of the team over the course of an 8-hour workday?
1/3 of the volunteers can complete the 8-hour workday
How to determine the capacity of the team
Total number of volunteers = 10
If it takes 1 volunteer = 24 hours = 1 day
It would take x number of volunteers = 8 hours
To find 'x' , cross multiply
We have,
x * 24 hours = 8 hours * 1
24x = 8
Make 'x' the subject of formula
x = 8/ 24
x = 1/3
Therefore, 1/3 of the volunteers can complete the 8-hour workday
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5. Tom travels 60 miles per hour going to a neighboring city and 50 miles per hour coming back using the same road. He drove a total of 5 hours away and back. What is the distance from Tom's house to the city he visited?
I have a 79.43 and if I add 10% would it raise it to 80% grade wise
Answer:
87 grade
Step-by-step explanation:
if yo add a 10% overall grade to you 79.43 you will get an 87.373
79.43 x 10% = 7.943 (points added bc of your 10%added)
79.43 + 7.943 = 87.373
round it and you'll have 87 overall grade
If EF = 2x – 12, FG = 3x – 15, and EG = 23, find the values of x, EF, and FG.
The values of x, EF, and FG from the line segment are 10, 8 and 15 respectively.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
EG = EF + FG (segment addition postulate)
Hence:
23 = (2x - 12) + (3x - 15)
x = 10
EF = 2(10) - 12 = 8
FG = 3(10) - 15 = 15
The values of x, EF, and FG from the line segment are 10, 8 and 15 respectively.
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solve:
7(2)^x=224
( help pls )
Answer:
5
Step-by-step explanation:
Original equation:
[tex]7(2)^x=224[/tex]
Divide both sides by 7
[tex]2^x=32[/tex]
Rewrite in log
[tex]log_232=x[/tex]
You can do mental math to realize this equals 5, or plug this into your calculate (if it allows you to set the base), but if you can't do either, you can use the change of base formula:
[tex]log_ba=\frac{log (a)}{log(b)}[/tex]
You get:
[tex]log_232=\frac{log(32)}{log(2)}[/tex]
When you calculate using a calculator you should get 5
Answer: x = 5
Step-by-step explanation:
[tex]7(2)^x=224[/tex]
start by dividing 7 from both sides
[tex]\frac{7(2)^x}{7} =\frac{224}{7}[/tex]
[tex]2^x=32[/tex]
take the log of both sides
[tex]log(2^x) = log(32)[/tex]
move the x to the left of the log
[tex]xlog(2) = log(32)[/tex]
divide both sides by log(2)
[tex]x=\frac{log(32)}{log(2)}[/tex]
use change-of-base formula
[tex]\frac{log(a)}{log(b)} =logx_{b} (a)[/tex]
[tex]x = log_{2} (32)[/tex]
since [tex]2^5 = 32[/tex], x = 5
Hope this helped :)Which expression is equivalent to (tangent (startfraction theta over 2 endfraction) ) (negative sine theta)?
The given expression is equivalent to -1 + cos θ. Option B
What is trigonometry?
Trigonometry can be seen as the branch of mathematics that deals with the relations of the sides and angles of triangles and with the functions of any angles.
The problem deduced from the information is;
[tex]-tan\frac{\alpha }{2} ( -5 sin\alpha)[/tex]
It is simplified thus
[tex]\frac{\frac{sin\alpha }{2} }{\frac{cos \alpha }{2} }[/tex] × [tex](- 2 sin\frac{\alpha }{2} * cos \frac{\alpha }{2} )[/tex]
We then have
[tex]-1 + cos \alpha[/tex]
Therefore, the given expression is equivalent to -1 + cos θ. Option B
The complete question is;
Which expression is equivalent to (tangent (StartFraction theta Over 2 EndFraction) ) (negative sine theta)?
– 1 – cos(ϴ)
– 1 + cos(ϴ)
1 + cos(ϴ)
1 – cos(ϴ)
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What is the horizontal asympote of this graph?
Using it's concept, it is found that the graph has no horizontal asymptote.
What are the horizontal asymptotes of a function f(x)?The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, we have that:
The function is undefined for x < 0, hence [tex]\lim_{x \rightarrow -\infty} f(x)[/tex] is undefined.For x > 0, the funciton goes to infinity, hence [tex]\lim_{x \rightarrow \infty} f(x) = \infty[/tex].Thus, the graph has no horizontal asymptote.
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simplify:
5 whole, 3 out of 10 + 2 whole, 1 out of 5.
Fractions are written as the ratio of two integers. The sum of 5 3/10 and 2 1/5 is 7 1/2
Sum of fractionsFractions are written as the ratio of two integers. Given the following expression
5 3/10 + 2 1/5
convert the mixed into improper fraction
53/10 + 11/5
Find the LCM
53+22/10
75/10
7.5
Hence the sum of 5 3/10 and 2 1/5 is 7 1/2
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Each treasure hunt team will have 5 people. So far 42 people have signed up. How many more people are needed to make every team equal? How many teams will there be?
Answer:
1) 3 more people
2) 9 teams
Step-by-step explanation:
The divisibility rule for 5 is that it must end in 5 and 0
so the next one is 45, so 3 more people
----------------------- ----------------------- ----------------------- -----------------------
45/5=9 teams
Find the best fit line for the scatter plot.
The figure below is painted on the street. It consists of a rectangle and an isosceles triangle.
Answer:
62 cmStep-by-step explanation:
add all sides, the top is the same as the bottom, (the side of 6 must be counted only once).
[2 * ( 18 + 3 + 7)] + 6 =
(2 * 28) + 6 =
56 + 6 =
62
62 m is the parameter of the given figure.
What is Perimeter?The perimeter of a two-dimensional form is the space surrounding it. It represents the total length of the shape's sides. The units used to measure the sides of the form, such as meters, centimeters, inches, or feet, determine the units used to measure the perimeter.
In a statistical context, parameters often refer to the unknown values of a probability distribution. In this case, parameters can be estimated using statistical methods such as maximum likelihood estimation or Bayesian inference.
Add all sides, the top is the same as the bottom, (the side of 6 must be counted only once).
[2 * ( 18 + 3 + 7)] + 6 =
(2 * 28) + 6 =
56 + 6 =
62
The perimeter of the given arrow is 62 m.
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Determine the value of K that will cause f(x)=Kx^2+4x-3 to intersect the line g(x)=2x-7 at 2 points
By using the definition of second order polynomials and the discriminant from quadratic formula, we conclude that the values of k must be less than 1/4.
How to determine the value of k such that a line intersects a quadratic equation
In this question we must determine the set of values of k such that the function g(x), a linear function, intersects a quadratic function f(x) at two points. In this case, we must solve the following second order polynomial:
k · x² + 4 · x - 3 - g(x) = 0
k · x² + 4 · x - 3 - 2 · x + 7 = 0
k · x² + 2 · x + 4 = 0
In this case, the discriminant of the equation described above must be positive:
2² - 4 · k · 4 > 0
4 - 16 · k > 0
4 > 16 · k
16 · k < 4
k < 1/4
By using the definition of second order polynomials and the discriminant from quadratic formula, we conclude that the values of k must be less than 1/4.
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Find the slope of the line containing the points (5, -1) and (-8, -4).
A.
B.
13
D.
5/3
OC. 13
To prove that ΔAED ˜ ΔACB by SAS, Jose shows that StartFraction A E Over A C EndFraction = StartFraction A D Over A B EndFraction.
Triangle A E D is shown. Line segment B C is drawn from side A D to A E to form triangle A C B.
Jose also has to state that
The other equality which must be stated by Jose is that angles BAC and BAE are congruent and their measures are equal.
What other congruence statements must Jose state?It follows from the task content that Jose is trying to prove the congruence of both triangles by means of the Side-Angle-Side congruence theorem.
It therefore follows that since, Jose has identified that the ratio of corresponding sides are equal as indicated in the task content, the equality which Jose has to state is the angle congruence equality.
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Answer:a. angle A= angle A
Step-by-step explanation: i took edg
Which is the graph of f(x) = √x?
The graph is shown in the attached image.
Consider the quadratic function f(x) = x² - 8x -4. What is the value of the leading coefficient?
-8
01
Answer:
1
Step-by-step explanation:
f(x) = x² - 8x - 4 ← is in standard form
with leading term x² and so
leading coefficient is the coefficient of the x² term, that is 1
Point O is the centroid of triangle ABC, BY = 3.3, CY= 3, Find BO.
Applying the centroid theorem, the length of BO is: A. 2.2.
What is the Centroid Theorem?Based on the centroid theorem, the length of BO equals two third of the length of BY.
That is:
BO = 2/3(BY)
Plug in the values
BO = 2/3(3.3)
BO = 2.2.
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OF
Fo
T
The first equation from the previous system of
equations is graphed. Graph the second equation to
find the solution of the system of equations
VH-2x+4
13-1
What is the solution to the system?
Answer:
(3,-2)
Step-by-step explanation:
See attached image.
dans dog walking job pays $15 per hour. his job as a car-wash attendant pays $400 each week. dan wants to know how many hours he needs to spend walking dogs to earn more than $520 in a week. which three inequalities can model this situation? select all the correct answers. x(15+400)>520 520<400+15x 15x>120 15x+520>400 520<15x+400x 15x+400>520
Answer: 400 520<15x+400x 15x+400>520
Step-by-step explanation:
i don't know this problem someone help please
Answer:
Points shouldn't be connected by straight lines but rather a curve
Step-by-step explanation:
None of the points seem to be incorrect, and the x and y-axis are labeled correctly as well as the points, the only issue I would say there is, is that this is a quadratic equation, so Brogan shouldn't be drawing straight lines between points, but rather a curve.
Stuart wants to raise $100 for the Rainbow Club charity. He already has three donations of $30.20.
$10.50 and $5.00. How much does Stuart still need to raise?
Answer:
$54.30
Step-by-step explanation:
Given Total Donations already raised
= $30.20 + $10.50 + $5.00
= $45.70
Donations still required = Total Donations needed - Donations already raised
= $100 - $45.70 = $54.30
How long is the blue ribbon if the red ribbon is 12 inches?
Tyler has 3 times as many books as Mai.
How many books does Mai have if Tyler has:
The length of the blue ribbon given the length of red ribbon is 8 inches
AlgebraLength of red ribbon = 12 incheslength of blue ribbon = 2/3 of red ribbon
= 2/3 × 12
= (2×12)/3
= 24/3
= 8 inches
Let
Number of books Mai has = xNumber of books Tyler has = 3x = 15 books3x = 15
x = 15/3
x = 5 books
Therefore, the number of books Mai has is 5 books
Complete question:
The length of the blue ribbon is two-thirds the length of the red ribbon. How long is the blue ribbon if the red ribbon is 12 inches?
Tyler has 3 times as many books as Mai. How many books does Mai have if Tyler has 15 books?
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g Using the latest observation in a sequence of data to forecast the next period is an associative forecast. a regression analysis. a naive forecast. a moving average forecast. an exponentially smoothed forecast.
Using the latest observation in a sequence of data to forecast the next period is a naïve forecast. Option C
What is a naïve forecast?
A naïve forecast is a forecasting technique in which the last sequence of data are used for the next period's forecast without predictions or adjusting the factors that could affect it.
Forecasts that are produced using a naïve approach are equivalent to the final observed value gotten.
Thus, using the latest observation in a sequence of data to forecast the next period is a naïve forecast
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which of the following of these numbers represents the three sides of a right triangle?
Answer:
3,4 and 5 is the ratio between the sides of a right triangle, therefore also the multiples (6-8-10 .... 9-12-15 etc.)
Step-by-step explanation:
3,4 and 5 is the ratio between the sides of a right triangle, therefore also the multiples (6-8-10 .... 9-12-15 etc.)
What is the ratio of the two values and what new value do they produce?
$280 in 7m
(Write Explaination)
The required ratio is give by $40/m, 4 miles/min, 30 mile/liter. .
Let, just assume a vehicle is given an economy of $280 of 7m.
The ratio can be defined as the comparison of the fraction of one quantity towards others. E.g.- water in milk.
Now,
The ratio can be given as for economy = 280/7
= $40/m
here for new values,
suppose the vehicle travel for 40miles in 10 mins
ratio = 40/10= 4 miles/min
and vehicle consumes 2 liter fuel on 60 miles of distance ratio can be given as
ratio = 60/2 = 30 mile/liter.
Thus the required ratios can be given as $40/m, 4 miles/min, 30 mile/liter.
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Marlon jogs two miles to the park in 25 minutes, turns around, and takes another 55 minutes to walk the same path back to his house. What is his average speed for the round-trip?
Answer:
3 mph
Step-by-step explanation:
So the average speed is simply: [tex]\frac{distance}{time}[/tex]. In case, the total time is 25 minutes + 55 minutes which is a total of 80 minutes, or 1.33 hours. The total distance traveled is two miles + two miles, since he jogged two miles to the park, and then he turns around and walks the same path. So in total he traveled 4 miles. Plugging this in to the formula gives you the equation: [tex]\overline{v}=\frac{4 \text{ miles}}{\frac{4}{3}\text {hours}}=\frac{4\text{ miles}}{1}*\frac{3}{4}\text{ hours} = 3mph[/tex]
Solve the system of equations 2x-y=132x−y=13 and 6x+5y=-336x+5y=−33 by combining the equations.
Answer: (2;-9).
Step-by-step explanation:
[tex]\left \{ {{2x-y=13\ |*(-3)} \atop {6x+5y=-33}} \right. \ \ \ \ \left \{ {{-6x+3y=-39} \atop {6x+5y=-33}} \right. .\\Summing\ up\ these\ equations:\\8y=-72\ |:8\\y=-9.\\2x-(-9)=13\\2x+9=13\\2x=4\ |:2\\x=2.[/tex]
Which topic is this and how to solve ?
Answer:
Step-by-step explanation:
to be honest, I have no idea what topic this is anymore but to solve it plug in 5 for f(x) and then use -3 for x and then simplify for B.
In the following exercises, multiply the binomials. Use any method.
252. (3r − 8)(11r + 1)
Answer:
Hence the expression [tex]$$(3r-8)(11r+1)=33r^2-85r-8$$[/tex].
Step-by-step explanation:
Explanation
The given expression is (3 r-8)(11 r+1).We have to multiply the given expression.Multiply the (3 r-8) by 1 , multiply the (3 r-8) by 11r then add like terms.[tex]$$\frac{\begin{matrix}{} & {} & 3r & - & 8 \\ \times & {} & 11r & + & 1 \\ \end{matrix}}[/tex]
___________
[tex]{\frac{\begin{matrix}{} & {} & 3r & - & 8 \\ 33{{r}^2} & - & 88r & {} & {} \\ \end{matrix}}{\begin{matrix}33{{r}^2} & - & 85r & - & 8 \\ \end{matrix}}}$$[/tex]
Which point corresponds to the real zero of the graph of y = log3 (x+2) - 1?
O (-1,-1)
O (1,0)
O (-1,0)
O (0,-.369)
E
Answer:
(1, 0 )
Step-by-step explanation:
using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex] , then
y = [tex]log_{3}[/tex] (x + 2) - 1
to find the zero let y = 0 , that is
[tex]log_{3}[/tex] (x + 2) - 1 = 0 ( add 1 to both sides )
[tex]log_{3}[/tex] (x + 2) = 1 , then
x + 2 = [tex]3^{1}[/tex] = 3 ( subtract 2 from both sides )
x = 1
the zero is (1, 0 )