Answer:
To find the range and time of flight of the elf, we need to use the equations of motion under the influence of gravity. The range is the horizontal distance covered by the elf and the time of flight is the total time that the elf is in the air.
The initial velocity of the elf in the x-direction (horizontal direction) is 25 m/s and the initial velocity in the y-direction (vertical direction) is 0 m/s, since the elf is thrown horizontally from the top of the iceberg. The acceleration due to gravity is -9.8 m/s^2 in the downward direction.
Using these values, we can find the range and time of flight of the elf using the following equations:
Range:
x = x0 + v0x*t
Where x is the range, x0 is the initial position (in this case, x0 is 0 since the elf is thrown from the top of the iceberg), v0x is the initial velocity in the x-direction (25 m/s), and t is the time of flight.
Time of flight:
y = y0 + v0y*t + (1/2)at^2
Where y is the vertical position of the elf, y0 is the initial position (in this case, y0 is 110 m since the elf is thrown from the top of the iceberg), v0y is the initial velocity in the y-direction (0 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time of flight.
We can solve for t in the second equation and then substitute it into the first equation to find the range.
Solving for t in the second equation:
t = (-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a)
Where y is the vertical position of the elf (0 m since the elf lands on the ground), y0 is the initial position (110 m), v0y is the initial velocity in the y-direction (0 m/s), and a is the acceleration due to gravity (-9.8 m/s^2).
Substituting this expression for t into the first equation:
x = x0 + v0x*((-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a))
Plugging in the values:
x = 0 + 25*((-0 + sqrt(0^2 - 4*(-9.8)(110))) / (2(-9.8)))
Simplifying:
x = 25*(sqrt(5832) / -19.6)
x = 25*(sqrt(5832) / -19.6)
x = (25*74.6) / -19.6
x = 1865.4 / -19.6
x = -95.1 m
So, the range of the elf is approximately -95.1 m. This means that the elf lands 95.1 m to the left of the starting point (the top of the iceberg).
The time of flight can be found by solving for t in the second equation:
t = (-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a)
Plugging in the values:
t =
Explanation:
what is the frequency of damped vibration for a single degree of freedom system with a spring of stiffness k n/m, a mass of m kg and a damping ratio of 0.1?
The frequency of damped vibration for a single degree of freedom system is Wd = 0.99[tex]\sqrt{\frac{k}{m} }[/tex]
Calculation :
Natural frequency (Wn)= [tex]\sqrt{\frac{k}{m} }[/tex]
Damped frequency (Wd) = Wn[tex]\sqrt{1-s^{2} }[/tex] (s = damping ratio)
= Wn[tex]\sqrt{1-0.1^{2} }[/tex]
= Wd = 0.99[tex]\sqrt{\frac{k}{m} }[/tex]
Frequency is the number of occurrences of a repeating event per unit time. For clarity, also called temporal frequency, which is different from angular frequency. Frequency is measured in hertz (Hz) and corresponds to one event per second. Duration is the reciprocal of frequency because duration is the time interval between events.
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. find the initial voltage for the capacitor and the initial current for the inductor. b. find the s-domain circuit equivalent. c. find il(s). d. find il(t).
The current change is 3e^-t [3cos (4.9t) - 0.306sin(4.9t)] Amperes.
(A) At t= 0 [inductor is short at steady rate and capacitor is open at steady rate]
Switch is in closed position
By applying KVL for loop
The sum of the voltage does in a closed loop is equal to zero
0.2 + 0.1 [iL (o⁻)] - 0.1 = 0
0.1 [iL (o⁻)] = 0.2 + 0.1
0.1 [iL (o⁻)] = 0.3
[iL (o⁻)] = 0.3 / 0.1
[iL (o⁻)] = 3A
By applying for loop 2
0.1v + 0 + v(o⁻) = 0
v(o⁻) = -0.1 v
B
At t = 0
Switch opens
Apply Laplace transform (S-domain)
Source transformation,
[vc(o⁻)] = 0.1/s
1/cs = 1/0.25
cs = 0.25
3/1.25 * 0.25 = 0.6
C
By applying KVL,
(-0.2/5) + (0.1+0.25)iL(s) - 0.6 + 0.3 [iL(s)] + [-0.1/s] + 5/5 [iL(s)] = 0
iL(s)[0.1 +0.25 +0.3 +5/s] = 0.2/5 + 0.6 + 0.1/5
iL(s)[0.4 + 0.2s + 5/s] = (0.2 + 0.65 + 0.1)/5
iL(s)[(0.2s² +0.4s +5)/s] = 0.2/5 + 0.6 + 0.1/5
iL(s) = (3s + 1.5) / (s² + 2s + 25)
D
iL(s) = 3s + 1.5 / (s² + 2s + 25)
= 3s + 1.5 / (s+1)² + 24
= 3(s+1-1)+1.5 / (s+1)² + (4.9)²
= 3(s+1) - 1.5 / (s+1)² + (4.9)²
iL(s) = 3(s+1) / (s+1)² + (4.9)²
iL(s) = [3(s+1) / (s+1)² + (4.9)²] - 0.306 * [(4.9) / (s+1)² + (4.9)²]
By applying inverse Laplace transform,
iL(t) = 3e^-t [3cos (4.9t) - 0.306sin(4.9t)] Amperes
Therefore, the current change is 3e^-t [3cos (4.9t) - 0.306sin(4.9t)] Amperes.
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The current is 3e^-t [3cos (4.9t) - 0.306sin(4.9t)] Amperes.
(A) At t= 0 [inductor is short at steady rate and capacitor is open at steady rate]
Switch is in closed position
By applying KVL for loop
The sum of the voltage does in a closed loop is equal to zero
0.2 + 0.1 [iL (o⁻)] - 0.1 = 0
0.1 [iL (o⁻)] = 0.2 + 0.1
0.1 [iL (o⁻)] = 0.3
[iL (o⁻)] = 0.3 / 0.1
[iL (o⁻)] = 3A
By applying for loop 2
0.1v + 0 + v(o⁻) = 0
v(o⁻) = -0.1 v
At t = 0
Switch opens
Apply Laplace transform (S-domain)
Source transformation,
[vc(o⁻)] = 0.1/s
1/cs = 1/0.25
cs = 0.25
3/1.25 * 0.25 = 0.6
By applying KVL,
(-0.2/5) + (0.1+0.25)iL(s) - 0.6 + 0.3 [iL(s)] + [-0.1/s] + 5/5 [iL(s)] = 0
iL(s)[0.1 +0.25 +0.3 +5/s] = 0.2/5 + 0.6 + 0.1/5
iL(s)[0.4 + 0.2s + 5/s] = (0.2 + 0.65 + 0.1)/5
iL(s)[(0.2s² +0.4s +5)/s] = 0.2/5 + 0.6 + 0.1/5
iL(s) = (3s + 1.5) / (s² + 2s + 25)
iL(s) = 3s + 1.5 / (s² + 2s + 25)
= 3s + 1.5 / (s+1)² + 24
= 3(s+1-1)+1.5 / (s+1)² + (4.9)²
= 3(s+1) - 1.5 / (s+1)² + (4.9)²
iL(s) = 3(s+1) / (s+1)² + (4.9)²
iL(s) = [3(s+1) / (s+1)² + (4.9)²] - 0.306 * [(4.9) / (s+1)² + (4.9)²]
By applying inverse Laplace transform,
iL(t) = 3e^-t [3cos (4.9t) - 0.306sin(4.9t)] Amperes
Therefore, the current change is 3e^-t [3cos (4.9t) - 0.306sin(4.9t)] Amperes.
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a 29 kg child is coasting at 2.4 m/s over flat ground in a 5.0 kg wagon. the child drops a 1.4 kg ball from the side of the wagon. what is the final speed (in m/s) of the child and wago
The final speed of child and wagon is 2.503 m/s.
Given that, mass of the child is 29 kg
Mass of the wagon is 5 kg
Initial mass of the child and the wagon mi = 29 + 5 = 34 kg
It is said that the child dropped 1.4 kg ball from the wagon.
So, final mass mf = 29 + 5 - 1.4 = 32.6 kg
From the law of conservation of linear momentum, we know that
Initial momentum = Final momentum
mi * vi = mf * vf
where, vi is the initial velocity
vf is the final velocity
Making vf as subject, we have
vf = (mi * vi)/mf
Initial velocity is given as 2.4 m/s
Placing the values in the above equation, we have
vf = (mi * vi)/mf = (34 * 2.4)/32.6 = 2.503 m/s
Thus, the final speed of child and wagon is 2.503 m/s.
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Which of the following is incorrect?
A) 3kg20g-3.02kg
B) 5kg5g=5.005kg
C) 230g=0.23kg
D) 8kg80g-8.008kg
please please
Answer:
A) 3kg20g-3.02kg
Explanation:
A) 3kg20g-3.02kg is incorrect. In order to subtract two quantities in the metric system, they must be expressed in the same unit of measurement. In this case, 3kg20g and 3.02kg are not expressed in the same unit of measurement, so it is not possible to subtract them. The correct way to subtract these two quantities would be to convert one of them to the same unit as the other, such as by converting 3kg20g to 3.020kg. Only then could they be subtracted, giving the result 0.000kg.
what value of the bullwhip measure would indicate that a dampening scenario exists? greater than 0 0 less than 0 greater than 1 less than 1
The value that the bullwhip measure would indicate if a dampening scenario exists is less than 1. Therefore, the correct answer is the last option.
The bullwhip effect is a phenomenon of the supply chain that describes how small fluctuations at the retail level can cause larger fluctuations in demand at the distributor, manufacturer, and material supplier levels. It is measured by dividing the variance of order by the variance of demand.
Bullwhip = 1 means that the order variance is equal to the demand variance, which implies that there is no variance amplification.Bullwhip > 1 means amplification is present.Bullwhip < 1 means that the orders are less variable than the demand. This scenario is often called a dampening scenario or smoothing.Learn more about bullwhip effect at https://brainly.com/question/29802823
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calculate the energy required to lift an elevator and its occupants with a mass of 1000 kg through a vertical distance of 5 m. group of answer choices 49000 j 5000 j 11000 j 2500 j
The energy required to lift an elevator and its occupants with a mass of 1000 kg through a vertical distance of 5 m is 49000 j .
Calculation :
Work done by any object . will be stored in the form of energy .
Energy stored = Work done = Force * Distance
= Mass * acceleration * Distance
As lift moving up force is acting on it due to gravity,
force = Mass * acceleration due gravity
Energy = Mass * acceleration due gravity* Distance
= 1000 kg * 9.8 m/sec² * 5m
= 49000 joule
energy as the ability to do work. Modern civilization is possible because humans have learned to convert energy from one form to another and use it for work.
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A pring of force contant 120N/m i acted upon by a contant force of 240N. Calculate the elatic potential energy tored in the pring
A spring of force constant 120N/m is acted upon by a constant force of 240N. The elastic potential energy stored in the spring is 240 Nm.
The elastic potential energy stored in a spring is given by the formula:
= U = 1/2 x k x x^2
Where U is the elasticity potential energy, k is the force constant of the spring, and x is the displacement of the spring from its equilibrium position. In this case, the force constant of the spring is 120 N/m, and the constant force acting on the spring is 240 N. To find the displacement of the spring, we can use the formula:
= F = k x x
Where F is the force applied to the spring, k is the force constant, and x is the displacement.
Solving for x, we get:
= x = F / k
= 240 N / 120 N/m
= 2 m
Substituting this value for x into the formula for elastic potential energy, we get:
= U = 1/2 x 120 N/m x 2 m^2
= 240 Nm
So the elastic potential energy stored in the spring is 240 Nm.
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A ball is thrown upward. What is its initial vertical speed? The acceleration of gravity is 9.8 m/s^2 and maximum height is 4.4 m. Neglect air resistance.. Answer in units of m/s.
The initial velocity of the ball thrown to a maximum height of 4.4 m is 9.29 m/s.
What is velocity?Velocity is the rate of change of displacement.
To calculate the initial velocity of the ball, we use the formula below.
Formula:
v² = u²+2gs.................Equation 1Where:
v = Final velocity of the ballu = Initial velocity of the ballg = Acceleration due to gravitys = Maximum height reached by the ballFrom the question,
Given:
v = 0 m/s (at the maximum height)g = - 9.8 m/s²s = 4.4 mSubstitute these values into equation 1 and solve for u
0 = u²+(-9.8×2×4.4)0 = u²-86.24u² = 86.24u = √86.24u = 9.29 m/sHence, the initial velocity is 9.29 m/s.
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The ball's initial vertical speed is 86.24m/s.
What is the acceleration of gravity?This refers to the acceleration of a body in free fall under the influence of the earth's gravity. it can be represented as the rate of increase of velocity per unit of time. It is measured in meters per second square, m/s².It can be represented with the letter, g.
Formula for calculating speed in free fall;v = 2 * g * h
where,
v= speed / velocity
g = acceleration of gravity
h= maximum height
Given in the question:g = 9.8 m/s²
h = 4.4 m.
Substituting the values in the formula we have:
v = 2 * 9.8 m/s² * 4.4 m
v = 86.24m/s.
Hence, the ball's initial vertical speed is 86.24m/s.
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which one of the following conditions would always result in an increase in the internal energy of a system? a. The system loses heat and does work on the surroundings.
b. The system gains heat and does work on the surroundings.
c. The system loses heat and has work done on it by the surroundings.
d. The system gains heat and has work done on it by the surroundings.
Option D; The system gains heat and has work done on it by the surroundings.
The force required to move an object a predetermined distance is referred to as the work done. It basically measures the amount of energy that is transmitted to or from an object to enable movement. The formula Work = Force Distance can be used to compute work. The joule (J) or Newton-meter (N-m) is the SI unit for work. When we apply a force called "F" to a block, the body moves with an acceleration or, additionally, its speed changes depending on the force's direction. The system's kinetic energy changes depending on whether the speed increases or decreases. Energy must be transformed into something other because, as we know, it cannot be created or destroyed.
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in the circuit shown in the figure (figure 1), find the magnitude of current in the upper branch.
0.8 A of current is flown through the upper branch of the circuit shown below:
as shown in the figure the current through lower loop is [tex]I_1+I_2[/tex] and the current through the upper loop is [tex]I_2[/tex].
the kirchoff's loop eqns in lower loop is:
-4[tex]I_1[/tex] + 5 -[tex]I_1[/tex] - 10([tex]I_1+I_2[/tex]) = 0
=> 2[tex]I_1[/tex] +[tex]I_1[/tex] + 2[tex]I_2[/tex] = 1
=> 3[tex]I_1[/tex] + 2[tex]I_2[/tex] =1 ----- (i)
we have obtanied 1 equation
the kirchoff's loop eqns in upper loop is:
-3[tex]I_2[/tex] +10 -2[tex]I_2[/tex] + [tex]I_1[/tex] - 5 +4[tex]I_1[/tex] = 0
=> - 5 [tex]I_2[/tex] +10+ 5 [tex]I_1[/tex] -5 =0
=> [tex]I_2[/tex] - [tex]I_1[/tex] =1 -------(ii)
solving equation (i) and equation (ii) we get
[tex]I_1[/tex] = -0.2
here negative sign represents that the current direction is opposite to our assumption.
so [tex]I_2[/tex] = 1 + [tex]I_1[/tex]
=> [tex]I_2[/tex] = 0.8A
So the current through the upper branch is 0.8A
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Complete question:
in the circuit shown in the figure , find the magnitude of current in the upper branch.
at what grazing angle in degrees from the surface will x-rays of wavelength 0.27 nm on a crystal with interatomic spacings between the bragg planes of 0.64 nm result in a first-order interference fringe?
12.18 degree grazing angle in degrees from the surface will x-rays of wavelength 0.27 nm on a crystal with interatomic spacings between the planes of 0.64 nm result in a first-order interference fringe.
According to diffraction law
[tex]$\lambda=0.27 \times 10^{-9} \mathrm{~m}$[/tex]
[tex]$$\hat{d}=0.64 \times 10^{-9} \mathrm{~m}$$[/tex]
[tex]\Rightarrow \quad \sin \theta=\frac{\lambda}{2 d}=\frac{0.27 \times 10^{-9}}{2 \times 0.64 \times 10^{-9}}[/tex] = 0.2109375
sin [tex]\theta[/tex] = 0.2109375
[tex]\theta[/tex]= [tex]sin^{-1} (0.2109375)[/tex]
[tex]\theta[/tex] = 12.18 degree
The grazing angle is the angle formed by the tangent to the earth at the target's location and a line drawn from the sensor to the target's surface.
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if you look with a magnifying glass at pictures printed in full color in books or magazines, you'll notice three colors of ink plus black. what are these colors?
Seeing the visible light spectrum of the rainbow through a prism and sunlight.
A white item will evenly reflect all shades of white light. If an object absorbs all colors except for one, we see that color. All of the colors in the color spectrum are combined to create white light. It is every shade of the rainbow. Yellow, cyan, and magenta are secondary colors that result from mixing the three fundamental hues of light—red, blue, and green. The three primary colors can be combined in various ways to create all additional colors. The item may absorb the light wave, in which case its energy is changed to heat. The object might reflect the light wave.
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if c(x) is a cost function, then c'(x) would be called the
The cost C is defined by the cost function as a function of the quantity x of things. As a result, C(x) is the price of x products. A linear cost function is one that has the formula C(x) = mx + b.
The quantity mx is referred to as the fixed cost, and the intercept b is referred to as the variable cost. The incremental cost per item is measured by the slope m, or marginal cost.
As a result, the relationship between the cost function and the profit function posits that a company cannot alter its profit without also altering its output and overall production costs. The cost function can also be used to calculate the average cost and the marginal cost of production in addition to calculating the overall production cost.
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What is the condition necessary for free fall
Answer:
The free fall is a motion that happens when we let something fall from certain height, this motion only happens when the object falls because of its own weight without any initial force or initial velocity, because then we would be talking about a vertical motion.
The free fall is a uniformly accelerated motion that only moves in the vertical axis (“y” axis), with the condition that the initial velocity will always have to be equals to 0 and the acceleration will be the value of the gravity in the place of the motion (9.8m/s). When a free fall motion happens in perfect conditions (this means that there is no air or any other factor that affects the trajectory of the object) the object only moves vertically.
When an object is in free fall, it will star with a 0m/s velocity, but while time passes, the velocity of the object will increase progressively until it impacts the floor or any object that is in its trajectory, this is why, the higher the initial height is, the stronger the impact will be against the floor.
Free Fall Conditions
The trajectory of an object in free fall could be affected by the air masses, an atmospheric phenomenon also known as aerodynamic resistant. In theory an object in free fall only moves vertically, but because of the air masses the trajectory of the object could change, both vertically and horizontally, how much will the air masses affects the object will depend on the weight of the object, if the object is heavier, then the air masses will not affect the object that much.
The condition depends on the property of the material under free fall. For example, if the body has a certain mass as well as charged, it causes a deflection due to Earth's magnetic field. Also the Coriolis effect due to Earth's rotation (when dropped from space to earth) comes into play when the object falls from a much higher altitude.
if α = 40°, β = 60°, and m = 4.0 kg, determine the tension in string 1.
The tension in string 1 will be 20 N , if α = 40°, β = 60°, and m = 4.0 kg .
SI unit of tension is Newton (N) and its CGS unit is dyne.
This tension calculator will show you how to calculate the tension force in a rope or string that is being used to lift an object. You can also note how to find tension in ropes used to pull an object .
Tension force is an axial force that passes through a pulling object such as a rope, string, or chain. Tension force can also be observed in other materials, such as rods and bars, when they are subjected to external pulling or tensile loads.
High tensile strength materials make the best rods and bars because they do not break easily when subjected to tension forces. Tension force is also an excellent illustration of Newton's Third Law of Motion.
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The motion of the piston in an automobile engine is oscillatory as the piston travels back and forth. if the piston makes 2,000 complete cycles every minute, what is the period of the motion of the piston?
The Time period of the motion of the piston is 30ms.
The time taken per cycle(t) = 1 min= 60 seconds
The number of the cycles per minute(N) = 2000
To find the Time period(T)
We have,
T= [tex]\frac{t}{N}[/tex]
Where,
T is the time period,
t is the time taken,
N is the number of cycles.
T= [tex]\frac{t}{N}[/tex]
T= [tex]\frac{60}{2000}[/tex]
T = 0.03 sec
T= 30×[tex]10^{-3}[/tex]
T = 30 ms.
What is Time period ?A vibrating body's time period is the length of time it takes to complete one oscillation.
The letter T is used to denote time.
The SI unit of time is the second (s).
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if the intensity of a sound beam remains unchanged while the beam area is reduced in half, what has happened to the power?
If the intensity of a sound beam remains unchanged while the beam area is reduced in half, the power will also be Halved.
As intensity = Power / area
I1 = P1 / A1
I2 = P2 / A2
If I1 = I2 and A2 = A1 / 2
I = P1 / A1 I = P2 / (A1/2)
I = P1 / A1 I = 2 P2 / A1
P1 = I A1 P2 = I A1 / 2
P2 = P1 /2 = Halved
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if the internal energy of a thermodynamic system is increased by j while j of expansion work is done, how much heat was transferred and in which direction, to or from the system?
U=q+w In other words, heat (q) and work (w) are added to define internal energy (w). Now that you are exerting force on your surroundings to do expansion work, you are losing energy and are aware that x joules of work are being lost by the system.
You may now connect those in and find a heat solution. The symbol on your heat indicates which way the flow was. Positive indicates that internal energy increased, which caused the system to gain heat; negative indicates that internal energy decreased, which caused the system to lose heat if that was the case.
like as U=300 and Work=75
The terms exothermic and endothermic simply denote whether heat is entering or exiting the system. Therefore, in this instance, we may conclude that it is endothermic since it absorbed heat because q ends up being 375, which is positive.
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Which of the following statements describes why the sky is blue: The sky is blue because blue lightA. is scattered more by air molecules than red light
B. is absorbed by air molecules more than red light
C. can shine through air molecules more easily than red light
D. can be reflected by air molecules more easily than red light
mye o O 20
The sky is blue because blue light is scattered more by the air molecules than the red light.
When light coming from the sun falls on the surface of the earth it travels as the white light. The components of this white light are violet, blue, green, yellow, orange and red colors.
This white light gets scattered over the atmosphere of the earth because of the particles of the air.
The sky appears to be blue because of the ability of the blue light to scatter more on the air particles then the other lights because blue light travels as shorter and smaller waves.
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what are the benefits of aerobic activity and what effect does that have on endurance during exercise
help plsssssssssssssssssssssssssssss
Aerobic exercise helps you lose weight and keep it off when combined with a good diet.
When you first begin regular aerobic exercise, you could feel exhausted. But over time, you'll benefit from more endurance and less weariness.
Over time, you can also improve your bone and muscle strength as well as your heart and lung health.
Regular aerobic exercise like walking, cycling, or swimming can improve your health and length of life.
You repeatedly contract your arms, legs, and hip muscles when engaging in aerobic exercise. You'll become aware of your body's reactions immediately.
You'll deepen and speed up your breathing. The amount of oxygen in your blood is increased as a result. As a result of your heart beating more quickly, more blood will reach your muscles and return to your lungs.
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after its most recent delivery, the infamous stork announces the good news. if the sign has a mass of 10.0 kg, then what is the tensional force in each cable?
To help with the solution, use a sketch and trigonometric functions. the 56.6 Newtons of stress.
An object must not be accelerating in order for it to be in equilibrium. This dictates that the object's net force and torque must both be zero. A spring stretches when a load is hung vertically from it. The amount the spring is stretched determines how much force the spring exerts on the mass. There is a location where the weight and spring force are equal in magnitude but in the opposite direction. The equilibrium position is where you are at this moment.
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a rope goes from one building to another. the distance between the buildings is 12 m, and the rope is tied to each building at a point 8 m and 3 m high above the ground. find the length of the rope.
By using the Pythagorean Theorem, the Length of the rope is 13 m.
The Pythagorean Theorem states that the square of the length of the hypotenuse (in this case, the rope) is equal to the sum of the square of the lengths of the other two sides (in this case, the distance between the buildings and the difference in heights of the buildings).
The length of the rope can be calculated using the Pythagorean Theorem as:
Length of rope = √(12² + (8-3)²)
Length of rope = √(144 + 25)
Length of rope = √169
Length of rope = 13 m
Therefore, we can calculate the length of the rope by taking the square root of the sum of the squares of the distance between the buildings (12²) and the difference in heights of the buildings (8-3)².
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What is the weight of a 72-kg astronaut on the Moon (g = 1.7 m/s2)?
W=117.36 N is the weight of a 72-kg astronaut on the Moon (g = 1.7 m/s2)
Equation
W=mg
W=72 kg *1.63 m/s²
W=117.36 N
Weight is force, and the Newton is its unit.
what is an astronaut?
An astronaut is a person who has been trained, outfitted, and sent into space by a human spaceflight programme to work as a commander or crew member on a spaceship. The word astronaut is derived from the Ancient Greek words v (astron), which means "star," and (nautes), which means "sailor." The phrase is occasionally used to refer to anyone who travels into space, including scientists, politicians, media, and tourists, despite the fact that it is typically designated for professional space travellers.
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why is the uncertainity principle or the wave nature of particles not significant when looking at macroscopic objects
The uncertainty principle of the wave nature of particles does not matter as much when looking at macroscopic objects because, unlike microscopic objects, their location and velocity don't change when photons strike them.
The uncertainty principle states that an object's position and velocity can't be measured exactly at the same time. It applies commonly to particles that can only be observed using a microscope. That is because, for objects as small as them, when light strikes them, their location and velocity may get altered.
Macroscopic object, on the other hand, does not get any significant alteration by photons. While they may be altered, the amount is very minuscule that it has hardly any consequence, making the uncertainty principle insignificant for macroscopic objects.
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what is the adjusted ampacity for each of six no. 4/0 thhn copper current-carrying conductors in a single conduit? (given: the ampacity of 4/0 thhn is 260a.)
The adjusted ampacity for each of the six No. 4/0 THHN copper current-carrying conductors in a single conduit is 220 amps.
This is because the ampacity of 4/0 THHN is 260 amps, but when more than three current-carrying conductors are in the same conduit, they must be derated. To derate, multiply the ampacity by the appropriate factor. In this case, the factor is 0.85, so 260 multiplied by 0.85 gives 220. Additionally, the National Electrical Code requires that the ampacity of the conductor must not be less than the rating of the overcurrent device which is protecting the circuit. In other words, the ampacity of the conductor must not be less than the rating of the fuse or circuit breaker protecting the circuit. This means that the ampacity of the conductors must be 220 amps or greater.
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an electron volt, ev, is a unit of energy. which is larger, a gev or a mev?
GeV is 1000 times larger than MeV .
"When an electron crosses a one volt potential, which is measured in electron volts, it gains energy" (eV). An electron volt, or ev, serves as the sign for energy. Electron volts, a measure of energy often used in atomic and nuclear physics, are the amount of energy that an electron (a charged particle carrying one unit of charge) acquires when the electric current at the electron increases by one volt.
Mega electron-volts, or MeVs, are a million times more potent than electron-volts. An electron has an energy of one eV.
When the giga-electron volt, or 109 eV, is initialised, energy is released in units of meV that are equivalent to 3108 ms 1 for every kilogramme of mass that is completely converted to energy.
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in the circuit below, the switch has been open for a long time, and the current is zero everywhere.
Due to the incomplete question I answered it in general way.
If the switch is closed, there will be current in the ammeter; otherwise, there won't. The presence of a current in the ammeter is independent of how long the switch has remained in any given state.)
The ammeter won't show any current if the switch has just been opened. The electrical connection is broken when the switch is opened, stopping electricity from passing through the circuit and preventing the ammeter from reading any current.
The ammeter won't register any current even after the switch has been open for a lengthy period. The switch is still in the open position, which prevents electricity from flowing through the circuit, which is the source of this.
The voltage V applied across the inductor and the inductance L of the inductor both affect the inductor current I that flows through it. The voltage V fluctuates with time t due to the switch 1, 2 timing.
I= 1/L∫Vdt,
where I is the amount of current passing through the inductor, L is the inductor's inductance, and V is the voltage applied across the inductor.
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What is the electric flux through the surface shown in the figure? Assume that E = 340N/C. Express your answer in newton meters squared per coulomb.
In this case, the electric field is 340 N/C, and the area vector is normal to the surface, so the dot product of the two is 0.
Electric flux is a measure of the amount of electric field that passes through a given area. It is measured in units of coulombs per meter squared (C/m2). Electric flux is important in electric circuits and fields, as it allows for the calculation of electric field strength, current, and other electrical properties. Electric flux is related to the concept of electric field lines, which represent the direction of the electric field at any point.
The electric flux through the surface shown in the figure is 0 N ⋅ m2/C. This is because the electric field is perpendicular to the surface and so no electric flux is passing through it. The electric flux is calculated as the dot product of the electric field and the area vector, and since the two are perpendicular, the result is 0.
Mathematically, electric flux is given by the formula Φ = E · A, where E is the electric field and A is the area vector.
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. consider the 65.0-kg ice skater being pushed by two others shown below. (a) find the direction and magnitude of ftot, the total force exerted on her by the others, given that the magnitudes f1 and f2 are 26.4 n and 18.6 n, respectively. (b) what is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of ftot? (c) what is her acceleration assuming she is already moving in the direction of ftot? (remember that friction always acts in the direction opposite that of motion or attempted motion between surfaces in contact.)
For the purpose of determining the acceleration, we will employ Newton's second law. F (totally) = ma, a = F(totally) / m, a = 32.0 N / 65.0 kg = 0.492 m/s2. If she starts out motionless and skating on steel blades, her initial acceleration is about 0.492 m/s2.
By magnitude, what do you mean?"Distance or quantity" is the simplest definition of magnitude. It depicts the amount and direction that even a body travels in either an absolute or comparative perspective.
What is an illustration of magnitude?Size is referred to as magnitude. A automobile is traveling more quickly than a bike, for instance, when it comes to speed. In this case, the car is moving faster than the bike by a larger margin.
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calculate the amount of work (in joules) required for your heart to pump 2.71 gram of blood from heart level to your head over a distance of 0.500 m.
The calculated value is 0.6 J. The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.
The work performed by the human heart is generally equal to
W = 0.6 N/cm2
100 cm3
= 60 N cm
= 0.6 N m
= 0.6 J,
as the work of a pump running at constant pressure is
W = PV.
The work is W = fd cos
if the force is applied at an angle of to the displacement. Two numbers are used to determine blood pressure: The first and higher figure, or systolic blood pressure, gauges the pressure inside your arteries while your heart beats. Diastolic blood pressure, which is the second and lower value, gauges how much pressure is there in the arteries between heartbeats.
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