In the diagram below of AACT, BE | AT.
C
F
If CB = 3, CA = 10, and CE = 6, what is the length
of ET?
1)
5
2)
14
3)
20
4)
26

The spring .2m far when it is compressed on being supported by a mass of 10kg.

Given: Mass of 30 kg which compresses spring by 0.6m

To find: The compression of the spring when it is supported by a mass of 10 kg

Concept: Compression springs are coiled springs that hold mechanical energy in a compressed state. When these springs are subjected to compressive loads, they compress and shorten, capturing and storing significant potential force.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

By using unitary method,

10 is 3 times less than 30.

so, 30/3=10

Also applying the same proportion over the lengths compressed,

we get, 0.6/3=.2

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Answer:

"If I know the measures of A and B, I can subtract those measures from 180 to find the measures of the other

two angles."

Step-by-step explanation:

i did it

Answer:

B. x = -6

Step-by-step explanation:

Use a graphing calculator such as desmos and enter each equation, you'll find the only one that falls on (-6, -9) and is perpendicular is B.

Answer:

B. x = -6

Step-by-step explanation:

Answer:

4 slices for all the brothers

Step-by-step explanation:

Answer:

a)

[tex](x^{2} + 2)(x^{2} + 2)\\x^{4} + 2x^{2} + 2x^{2} + 4\\= x^{4} + 4x^{2} + 4\\[/tex]

b)

[tex](x +1)(x + 1)(x^{2} -2x +3) = (x + 1)^{2} (x^{2} -2x +3)[/tex]

Volume

Volume

Answer:

Step-by-step explanation:

Domain is the set of all inputs for which the given function is defined.

graphically it represents the shadow of the graph taken on the x axis from above and below the x axis

Here is the shadow will be formed from -3 till +∞, hence we have our domain  as [-3 , ∞ ]

The equation of parabola passing through coordinates A (-2,0), B (-1.5,-2.5), C (0,5), D (1, 0), E (1.5, 2.5), and F (2, 0) is y = -2.5(2x+4)², and the graph is attached.

Each element of X receives exactly one element of Y when a function from one set to the other is used. The sets X and Y are collectively referred to as the function's domain and co-domain, respectively.

Given:

The coordinates of the point of parabola A (-2,0), B (-1.5,-2.5), C (0,5), D (1, 0), E (1.5, 2.5), and F (2, 0).

Calculate the equation of parabola by the formula given below,

[tex]y=a(x-h)^2+k[/tex]

Here (h, k) are the coordinates,

Put A (-2,0)

y = a[x- (-2)] ² + 0

y = a(2x + 4)²

Put B (-1.5,-2.5)

y = a[x- (-1.5)]² + (-2.5)

y = a(x + 1.5)² - 2.5

y = 2ax + 3a -2.5

Solve the above equation

a = -2.5

Thus, the equation of the parabola is,

y = -2.5(2x+4)²

Therefore, the equation of parabola passing through coordinates A (-2,0), B (-1.5,-2.5), C (0,5), D (1, 0), E (1.5, 2.5), and F (2, 0) is y = -2.5(2x+4)², and the graph is attached.

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Answer:

Step-by-step explanation:

Let the sides be a, b and c.

The length of one side of a triangle is 2 feet less than three times the length of its second side

The length of the third side is 3/4 of the sum of the lengths of the first two sides:

The perimeter of the triangle is 17.5 feet:

Substitute a with b in the second equation:

Now substitute a and c with b in the third equation and solve for b:

Find the value of a:

Find the value of c:

The sides of the triangle are:

The half life of the radioactive Rutherford-265 is;

13.1 hours.

It follows from the task content that the given function represents the decay function of the radioactive material. Since half-life corresponds to the point at which only half of the starting material remains, hence we have;

(1/2) = e ^(-0.053t)

By taking the natural log of both sides, we have;

-0.6931 = -0.053t

Hence, t = -0.6931/ -0.053 = 13.1 hours.

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20 gallons of gas was consumed by the car that has efficiency of 20 miles per gallon  and 30 gallons of gas was consumed by the car that has  efficiency of 30 miles per gallon .

The first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of 30 miles per gallon of gas.

Therefore,

let

x = number of gallons for car that consume 20 miles per gallon of gas

y = number of gallons for car that consume  30 miles per gallon of gas

Hence,

x + y = 50

20x + 30y = 1300

20x + 20y = 1000

20x + 30y = 1300

10y = 300

y = 300 / 10

y = 30

Therefore,

x = 50 - 30

x = 20

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Answer:

(-2,-1,0,1,2)

(1,4,6,7)

It takes 3 hours for the cats to catch 27 fish in the pond.

Zarko can catch 5 fish per hour.

Manchu can catch 2 fish every 0.5 of an hour, so in an hour, the cat would catch 2 times that, which is 4 fish.

When working together, the cats can catch 4 + 5 = 9 fish per hour

If the cats work for x hours, then they catch 9*x fish.

To get the time that takes them to catch 27 fish we just need to solve the linear equation:

9x = 27

Solving for x:

x = 27/9 = 3

It takes 3 hours for the cats to catch 27 fish in the pond.

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The relations from the following sets of ordered pairs which is a function is; {(8,1),(−4,1),(3,5),(0,4),(−1,2)}

It follows from the definition of a function that a function from an array of X-values to a set Y-values assigns only one Y-value to each X-value.

Hence, it follows from the definition above that the relation; {(8,1),(−4,1),(3,5),(0,4),(−1,2)} is that which is a function.

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Answer:

11 inches

Step-by-step explanation:

90 divided by 18 is 5 so each inch is worth 5 cents so 55 cents would give you 11 inches of wire because 55/5 is 11

We have an exponential growth. The domain is the set of all real numbers and the range is R: (0, ∞).

Here we have the exponential function:

[tex]h(x) = 125^x[/tex]

Notice that the base, 125, is larger than 1, which means that we have an exponential growth.

Now, the domain of any exponential equation is the set of all real numbers.

For the range, as x tends to negative infinity, the function will tend to zero.

And as x tends to infinity, h(x) also tends to infinity.

So the range is R: (0, ∞).

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Answer:

just multiply 20.50 by 8 and how many days she work in a week

The answer depends on how many total teams there are. The team players always end up with multiple of 6: 6, 12, 18 24... etc.

Hope it helps!

Answer:

9.6 lbs per acre

Step-by-step explanation:

96lbs for 10acres

96 divided by 10= 9.6 lbs per acre.

Answer:

Step-by-step explanation:

The Pink Party Punch has a stronger lemon-lime flavor because it has a higher volume of 6 liters.

Volume can be defined as the total quantity of a substance that a container can hold at a given period of time. Also, the volume of a container is measured in:

Based on the information provided in the table above, we can infer and logically deduce that the Pink Party Punch has a stronger lemon-lime flavor because it has a higher volume of 6 liters.

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Based on the various assets and liabilities that the family has, the debt ratio can be calculated to be D. 54.1%.

the debt ratio can be found as:

= Total debt / Total assets

Solving:

= (5,500 + 210,000 + 180,000+ 25,000) / (3,000 + 13,000 + 320,000 + 25,000 + 15,000 + 64,000 + 39,000)

= 258,500 / 479,000

= 54.1%

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The Inventory Turnover for 2021 is 5.9 times and for 2022 is 10 times.

2021

Inventory Turnover = Cost of Goods sold / Average Inventory

Cost of Goods sold = $1,165,250/[($170,000+$225,000)/2]

Cost of Goods sold = $1,165,250/($395,000/2)

Cost of Goods sold = $1,165,250/197,500

Cost of Goods sold = 5.9 times

2022

Inventory Turnover = Cost of Goods sold / Average Inventory

Cost of Goods sold = $1,525,000/[($225,000+$80,000)/2]

Cost of Goods sold =  $1,525,000/($305,000/2)

Cost of Goods sold =  $1,525,000/152,500

Cost of Goods sold = 10 times

Therefore the Inventory Turnover for 2021 is 5.9 times and for 2022 is 10 times.

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The complete question is:

Pina Colada Corp. switched to a just-in-time inventory system. Its sales and Inventory amounts for 2021 and 2022 are shown below.

                                 2021            2022

Sales revenue $3,360,000  $3,900,000

Cost of goods sold  1,165,250 1,525,000

Beginning inventory  170,000 225,000

Ending inventory        225,000  80,000

Determine the inventory turnover for 2021 and 2022.

(a) The differential equation

[tex]y' + \dfrac14 y = 3 + 2 \cos(2x)[/tex]

is linear, so we can use the integrating factor method. We have I.F.

[tex]\mu = \displaystyle \exp\left(\int \frac{dx}4\right) = e^{x/4}[/tex]

so that multiplying both sides by [tex]\mu[/tex] gives

[tex]e^{x/4} y' + \dfrac14 e^{x/4} y = 3e^{x/4} + 2 e^{x/4} \cos(2x)[/tex]

[tex]\left(e^{x/4} y\right)' = 3e^{x/4} + 2 e^{x/4} \cos(2x)[/tex]

Integrate both sides. (Integrate by parts twice on the right side; I'll omit the details.)

[tex]e^{x/4} y = 12 e^{x/4} + \dfrac8{65} e^{x/4} (8\sin(2x) + \cos(2x)) + C[/tex]

Solve for [tex]y[/tex].

[tex]y = 12 + \dfrac8{65} (\sin(2x) + \cos(2x)) + Ce^{-x/4}[/tex]

Given that [tex]y(0)=0[/tex], we find

[tex]0 = 12 + \dfrac8{65} (\sin(0) + \cos(0)) + Ce^0 \implies C = -\dfrac{788}{65}[/tex]

and the particular solution to the initial value problem is

[tex]\boxed{y = 12 + \dfrac8{65} (\sin(2x) + \cos(2x)) - \dfrac{788}{65} e^{-x/4}}[/tex]

As [tex]x[/tex] gets large, the exponential term will converge to 0. We have

[tex]\sin(2x) + \cos(2x) = \sqrt2 \sin\left(2x + \dfrac\pi4\right)[/tex]

which means the trigonometric terms will oscillate between [tex]\pm\sqrt2[/tex]. So overall, the solution will oscillate between [tex]12\pm\sqrt2[/tex] for large [tex]x[/tex].

(b) We want the smallest [tex]x[/tex] such that [tex]y=12[/tex], i.e.

[tex]0 = \dfrac8{65} (\sin(2x) + \cos(2x)) - \dfrac{788}{65} e^{-x/4}[/tex]

[tex]\dfrac{788}{65} e^{-x/4} = \dfrac{8\sqrt2}{65} \sin\left(2x + \dfrac\pi4\right)[/tex]

[tex]\dfrac{197}{\sqrt2} e^{-x/4} = \sin\left(2x + \dfrac\pi4\right)[/tex]

Using a calculator, the smallest solution seems to be around [tex]\boxed{x\approx21.909}[/tex]