The value of the integral C1 and C2 are below:
∫[C1] (y + x – 4ix³) dz = -1/2 + 4/3 i
∫[C2] (y + x – 4ix³) dz = 0
To evaluate the integral, we need to parameterize the given contour C and express it as a function of a single variable. Then we substitute the parameterization into the integrand and evaluate the integral with respect to the parameter.
Let's evaluate the integral along contour C1: the straight line from Z = 0 to Z = 1 + i.
Parameterizing C1:
Let's denote the parameter t, where 0 ≤ t ≤ 1.
We can express the contour C1 as a function of t using the equation of a line:
Z(t) = (1 - t) ×0 + t× (1 + i)
= t + ti, where 0 ≤ t ≤ 1
Now, we'll calculate the differential dz/dt:
dz/dt = 1 + i
Substituting these into the integral:
∫[C1] (y + x – 4ix³) dz = ∫[0 to 1] (Im(Z) + Re(Z) - 4i(Re(Z))³)(dz/dt) dt
= ∫[0 to 1] (t + 0 - 4i(0)³)(1 + i) dt
= ∫[0 to 1] (t + 0)(1 + i) dt
= ∫[0 to 1] (t + ti)(1 + i) dt
= ∫[0 to 1] (t + ti - t + ti²) dt
= ∫[0 to 1] (2ti - t + ti²) dt
= ∫[0 to 1] (-t + 2ti + ti²) dt
Now, let's integrate each term:
∫[0 to 1] -t dt = [-t²/2] [0 to 1] = -1/2
∫[0 to 1] 2ti dt = [tex]t^{2i}[/tex][0 to 1] = i
∫[0 to 1] ti² dt = (1/3)[tex]t^{3i}[/tex] [0 to 1] = (1/3)i
Adding the results together:
∫[C1] (y + x – 4ix³) dz = -1/2 + i + (1/3)i = -1/2 + 4/3 i
Therefore, the value of the integral along contour C1 is -1/2 + 4/3 i.
Let's now evaluate the integral along contour C2: along the imaginary axis from Z = 0 to Z = i.
Parameterizing C2:
Let's denote the parameter t, where 0 ≤ t ≤ 1.
We can express the contour C2 as a function of t using the equation of a line:
Z(t) = (1 - t)× 0 + t × i
= ti, where 0 ≤ t ≤ 1
Now, we'll calculate the differential dz/dt:
dz/dt = i
Substituting these into the integral:
∫[C2] (y + x – 4ix³) dz = ∫[0 to 1] (Im(Z) + Re(Z) - 4i(Re(Z))³)(dz/dt) dt
= ∫[0 to 1] (0 + 0 - 4i(0)³)(i) dt
= ∫[0 to 1] (0)(i) dt
= ∫[0 to 1] 0 dt
= 0
Therefore, the value of the integral along contour C2 is 0.
In summary:
∫[C1] (y + x – 4ix³) dz = -1/2 + 4/3 i
∫[C2] (y + x – 4ix³) dz = 0
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During an experiment in which you are investigating the acceleration changes due to force changes, what value must stay constant during these trials?
a. Force
b. Velocity
c. Acceleration
d. Mass
During an experiment of acceleration changes, the value that must stay constant during these trials is d. Mass
Inertia, a basic characteristic of all matter, may be measured quantitatively using mass. When a force is applied, an item effectively provides resistance to changes in velocity or position. The change brought about by an applied force is less the more mass an item has. According to Newton's second law of motion an object's acceleration is inversely proportional to its mass and directly proportional to the net force that has been applied to it. It may be expressed mathematically as F = ma.
The goal of this experiment is to see how variations in force impact acceleration. It is crucial to maintain the mass constant throughout the trials in order to isolate the impact of force on acceleration. Any observable variations in acceleration may be entirely attributable to variations in the applied force by maintaining the mass constant.
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Which is the correct stem-and-leaf plot for the data set?
16, 15, 47, 41, 40, 39, 16, 37
Answer:
the first plotting was correct.
Step-by-step explanation:
the values will be arranged in an ascending order from their roots which are the first digit
A math teacher is trying to analyze her test grades. She surveys the students to find out how many minutes they studied. She then makes a scatterplot of time studying and test grades.
What is the domain?
A) the students' grades on their tests
B) the number of students in the class
C) the different courses the teacher teaches
D) the number of minutes the students studied
In the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).
The domain refers to the set of possible inputs or variables in a given context. In this case, the scatterplot is being created based on the relationship between the time students spent studying and their corresponding test grades. Therefore, the domain in this context would be the number of minutes the students studied (option D).
The domain represents the independent variable, which is the variable that is controlled or manipulated in the analysis. In this scenario, the math teacher wants to analyze the relationship between studying time and test grades, so the number of minutes studied would be the independent variable. The teacher surveys the students to collect data on the time spent studying, and this variable becomes the domain of the scatterplot.
The range, on the other hand, represents the dependent variable, which is the variable that is measured or observed as an outcome or response. In this case, the dependent variable would be the students' test grades. The scatterplot will show how the test grades correspond to the amount of time students studied.
To summarize, in the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).
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Let W = {a + 2x + bx^2 ∈ P2 : a, b ∈ R} with the standard operations in P2. Which of the following statements is true?
A. W is not a subspace of P2 because 0 € W.
The above is true
B. W is a subspace of P2.
The above is true
C. None of the mentioned
D. 1+xEW
A subspace must satisfy three conditions: closure under addition, closure under scalar multiplication, and containing the zero vector. Therefore, the correct statement is B. W is a subspace of P2.
In order to determine whether statement A or B is true, we need to check the subspace criteria.
Let's analyze the statements:
A. W is not a subspace of P2 because 0 € W.
If 0 € W, then W does not contain the zero vector. However, the zero vector is the polynomial 0 + 2(0)x + (0)x^2 = 0, which is an element of W. Thus, statement A is false.
B. W is a subspace of P2.
For W to be a subspace, it needs to satisfy all three subspace criteria. Let's check each criterion:
Closure under addition: Let's take two arbitrary polynomials in W: a + 2x + bx^2 and c + 2x + dx^2. Their sum is (a + c) + 2x + (b + d)x^2, which is also a polynomial in W. Therefore, W is closed under addition.Closure under scalar multiplication: Let's take an arbitrary polynomial in W: a + 2x + bx^2. If we multiply it by a scalar, say k, we get k(a + 2x + bx^2) = ka + 2kx + bkx^2, which is still a polynomial in W. Hence, W is closed under scalar multiplication.Contains the zero vector: The zero vector is the polynomial 0 + 2(0)x + (0)x^2 = 0, which is an element of W. Therefore, W contains the zero vector.Since W satisfies all three subspace criteria, statement B is true.
Therefore, the correct statement is B. W is a subspace of P2.
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11 Megan has $500 in her savings account. The interest rate is 7%, which is not compounded. How much money in dollars) will she have in her account after 5 years? Write the correct
answer.
Answer:
701
Step-by-step explanation:
At the end of 5 years, your savings will have grown to $701.
You will have earned in $201 in interest.
answer.
Does the residual plot show that the line of best fit is appropriate for the data?
The correct statement regarding the residual plot in this problem, and whether the line of best fit is a good fit, is given as follows:
Yes, the points have no pattern.
What are residuals?For a data-set, the definition of a residual is that it is the difference of the actual output value by the predicted output value, hence it is defined by the subtraction operation as follows:
Residual = Observed - Predicted.
Hence the graph of the line of best fit should have the smallest possible residual values, and no pattern between the residuals.
As there is no pattern between the residuals in this problem, the line is in fact a good fit and the first option is the correct option.
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8 divided by 618 ..............
Answer:
0.0129449838188
What is the value of t? need an answer asap
Answer:
im pretty sure its 69
Step-by-step explanation:
im not joking im pretty sure both angles are 69 because of the triangle formula
Caught error while evaluating the code in this question: syntax error, unexpected" Let S be the universal set, where: Let sets A and B be subsets of S, where: LIST the elements in the set (AUB) [(AUB)]={ } Enter the elements as a list, separated by commas. If the result is the empty set, enter DNE You may want to draw a Venn Diagram to help answer this question.
The solution to the problem is `{5, 10, 15, 20, 25, 30}`.
The error message "syntax error, unexpected" is a common message you might encounter when there is a syntax error in your code.
This error message often points to an unexpected symbol or typo in your code. For instance, in the context of a code snippet like this, such an error message could be prompted due to an invalid command or misspelling, or a misused symbol or expression.
Also, another likely cause could be an incorrect use of a function or a non-existent variable or keyword. Hence, to solve the error message, you might need to double-check your code and fix any errors that could cause such an issue. Now, let's answer the question that follows: Given the universal set, S, as;`S = {5, 10, 15, 20, 25, 30}` and the subsets A and B as; A = {5, 10, 15, 20} B = {15, 20, 25, 30}.
To list the elements in the set (AUB) we need to find the union of A and B. The union of two sets A and B is a set of all the elements that are either in A or in B or in both. That is, `AUB = {x: x ∈ A or x ∈ B}`
Therefore, the union of sets A and B is the set `AUB = {5, 10, 15, 20, 25, 30}`
Thus, the list of elements in the set (AUB) is:`{5, 10, 15, 20, 25, 30}` Hence, the solution to the problem is `{5, 10, 15, 20, 25, 30}`.
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Given the solid Ethat lies between the cone z2 = x2 + y2 and the sphere x2 + y2 + (z + 2)2 = 2 a) Set up the triple integrals that represents the volume of the solid E in the rectangular coordinate system b)Set up the triple integrals that represents the volume of the solid E in the cylindrical coordinate system c) Evaluate the volume of the solid E
a) The volume of the solid E in rectangular coordinate system is given by: [tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]
b) The volume of the solid E in cylindrical coordinate system is given by: [tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]
c) The volume of the solid E is 11π/3.
a) The solid E that lies between the cone z² = x² + y² and the sphere x² + y² + (z + 2)² = 2.
Volume of solid E in rectangular coordinate systemLet the limits of x, y, z be X, Y, Z respectively.
The limits of X:
From the equation, z² = x² + y²
Z² = X² + Y²
X² = Z² - Y²
Let Z = 0, then X² = - Y² which is impossible. Therefore, Y can take any value such that Y < Z.
The limits of Y:
From the equation, z² = x² + y²
Z² = X² + Y²
Y² = Z² - X²
Let Z = 0, then Y² = - X² which is impossible. Therefore, X can take any value such that X < Z.
Limits of Z:
From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6
The limits of z are Z < 2 and Z > - 2.
Volume in rectangular coordinate system:
[tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]
b) Volume of solid E in cylindrical coordinate system
Let the limits of ρ, θ, z be R, Θ, Z respectively.
The limits of R:
From the equation, z² = ρ² cos²θ + ρ² sin²θ
Z² = ρ²
Rho² = Z²/ cos²θ + sin²θ
Rho = Z/ cosθ
Let Z = 0, then Rho = 0. Therefore, R can take any value such that 0 ≤ R < 2.
Limits of Θ:
From the equation, z² = ρ² cos²θ + ρ² sin²θ
Z² = ρ² sin²θ
Theta² = tan⁻²(Z²/ ρ²)
Let Z = 0, then Θ = 0. Therefore, Θ can take any value such that 0 ≤ Θ ≤ π/2.
Limits of Z:
From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6
The limits of Z are -2 ≤ Z < 2.
Volume in cylindrical coordinate system:
[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]
c) Evaluation of the volume of solid E:
Using rectangular coordinate system, the volume of solid E is
[tex]$$\iiint_{E} dx dy dz[/tex] = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$$$[/tex]
[tex]=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} [x]_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dy dz$$$$=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} 2\sqrt{z^2 - y^2} dy dz$$$$=\int_{-2}^{2} \left[-\frac{1}{2}(z^2 - y^2)^{3/2}\right]_{y=0}^{y=\sqrt{z^2}} dz$$$$=\int_{-2}^{2} \frac{1}{2}z^3 dz = 0$$[/tex]
Therefore, the volume of solid E using rectangular coordinate system is 0.
Using cylindrical coordinate system, the volume of solid E is
[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \left[\frac{\rho^2}{2}\right]_{0}^{\sqrt{4 - z^2}} d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} 2 - \frac{z^2}{2} d\theta dz$$$$=\int_{0}^{2} \left[2\theta - \frac{\theta z^2}{2}\right]_{\theta = 0}^{\theta = \frac{\pi}{2}} dz$$$$=\int_{0}^{2} \pi - \frac{\pi z^2}{4} dz = \frac{11\pi}{3}$$[/tex]
Therefore, the volume of solid E using cylindrical coordinate system is 11π/3.
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A researcher would like to estimate the mean amount of money the typical American spends on lottery tickets in a month. The researcher would like to estimate the mean with 99% confidence. Which sample size options would yield the smallest margin of error?
Based on the formula, we can say that the margin of error will be reduced if the sample size is increased.
To obtain the smallest margin of error with 99% confidence, a sample size of 1689 would be needed.
A margin of error refers to the degree of error that may arise due to chance when attempting to estimate a population parameter such as a mean. It is calculated as the product of a critical value, a standard deviation, and a confidence interval, then divided by the square root of the sample size.
N is the sample size, which refers to the number of items included in the sample from the population. A larger sample size would be beneficial since it lowers the margin of error. When the sample size rises, the standard error of the mean decreases, implying that we are more confident in our estimate of the population mean. A smaller margin of error is desirable since it results in a more precise estimate of the population parameter.
The formula for the margin of error is given by:
Margin of Error = (Critical Value) (Standard Deviation) / sqrt(N).
To obtain the smallest margin of error with 99% confidence, a sample size of 1689 would be needed. The formula for the sample size calculation for this scenario is:
N = [(Zα/2)σ / E]²
Where, Zα/2 = 2.58, σ is the standard deviation, and E is the margin of error.
Using Zα/2 = 2.58 for a 99% confidence interval and the smallest possible margin of error to obtain a sample size for which the margin of error is minimized, we have:
N = [(Zα/2)σ / E]² = [(2.58)σ / E]²
Since the goal is to minimize the margin of error, we use the smallest possible value for E:1.
Therefore, N = [(2.58)σ / 1]²2.
Solving for N:
N = 6.6564σ²
To obtain the smallest margin of error with 99% confidence, we must solve for the smallest possible value of N that satisfies the above equation. We obtain:
N = 6.6564σ²
We don't have any information about the standard deviation, σ, in the given question, so we can't solve for N.
However, based on the formula, we can say that the margin of error will be reduced if the sample size is increased.
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Ahmed received a box of gifts. The box is a rectangular prism with the same height and width, and the length
is twice the width. The volume of the box is 3,456 in? What is the height of the box?
Answer:
12 inches
Step-by-step explanation:
Ahmed received a box of gifts. The box is a rectangular prism with the same height and width, and the length
is twice the width. The volume of the box is 3,456 in? What is the height of the box?
Volume of a Rectangular pyramid = Length × Width × Height
From the above question
Height = Width = x
Length = 2 × Width
Length = 2x
Volume = 3,456 cubic inches
Hence,
3,456 = 2x × x × x
3456 = 2x³
x³ = 3456/2
x³ = 1728
Cube root both sides
Cube root(x³) = cube root (1728 cubic Inches)
x = 12 inches
Therefore, the height is 12 inches
Width, Height and Length of rectangular prism are 12, 12 and 24 inch respectively.
Assume;Width of rectangular prism = a
Height of rectangular prism = a
Length of rectangular prism = 2a
We know that;Volume of the rectangular prism = (l)(b)(h)
Volume of the rectangular prism = (2a)(a)(a)
3,456 = 2a³
a³ = 1,728
a = 12 inch
So,
Width of rectangular prism = 12 inch
Height of rectangular prism = 12 inch
Length of rectangular prism = 2(12)
Length of rectangular prism = 24 inch
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PLEASEEEE HELP ‼️‼️1️⃣
Answer:
8/7
Step-by-step explanation:
12*2=24.
7*3=21
24/21 is divisible by 3
=8/7
Sam just purchased a new car. After his employee discount and the sale that the dealership applied to the original
price, Sam paid $13,734.60. If Sam's employee discount was applied to the original price after the dealer discount,
then determine the original price of the vehicle given that the employee discount was 8% and the dealership
discount was 25%. Round your answer to the nearest cent.
a $20,375.21
c. $19,250.13
b. $18,350.33
d. $19,905.22
Answer:
D 19,905
Step-by-step explanation:
19,905.22×25%=4976.31
19905.22-4976.31=14,928.91
14928.91×8%=1194.31
14928.91-1194.31=13734.6
help me please, i’m confused. thanks!
Answer:
Step-by-step explanation:
ALGEBRAICALLY solve the following system of equations:
y= 22 - 4x + 6 and y=x + 2
How many bit strings of length 8 can you have if each string has
only two zeros that are never together
There are 28 different bit strings of length 8 that satisfy the condition of having two zeros that are never together.
To count the number of bit strings of length 8 with two zeros that are never together, we can use the concept of combinations.
First, let's consider the possible positions for the two zeros. The zeros cannot be adjacent to each other, which means they must be placed in non-adjacent positions in the string.
Since there are 8 positions in the string, we can choose 2 positions for the zeros in C(8, 2) ways. This gives us the number of ways to select the positions for the zeros.
Once we have chosen the positions for the zeros, the remaining 6 positions must be filled with ones. There is only one way to do this, as all the remaining positions will be filled with ones.
Therefore, the total number of bit strings of length 8 with two zeros that are never together is equal to C(8, 2) = 28.
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Compare lengths. Select >, <, or = ,
2 km _ 4,000 m
Answer:
2 km < 4,000 m
Step-by-step explanation:
2 km = 2,000 m
Therefore, 2,000 m is less than 4,000 m.
Rewrite the expression in the form 3^n
Answer:
n=2
Step-by-step explanation:
[tex]\frac{3.3.3.3.3.3}{3.3.3.3} = 3^{n}[/tex]
[tex]3^{2}[/tex]= [tex]3^{n}[/tex]
n=2
Answer:
[tex]3^1[/tex]
Step-by-step explanation:
[tex]\frac{3*3*3*3*3}{3*3*3*3} =3^1[/tex]
A bag contains white, blue and red ping-pong balls in the ratio 8 : 3 : 2. There are 10 balls. If 10 white and 10 blue balls are removed from the bag, the new ratio is ?
Answer:
the new ratio of white, red and blue balls is 6:2:1
Step-by-step explanation:
The computation of the new ratio is shown below:
If you have 10 red balls, so the blue balls is in proportion of 3:2 that means 15 would be the blue balls. In addition to this, the while balls is in proportion 8:2 = 4:1 so there is a 40 white balls
Now if 10 white and 10 blue balls would be eliminated
So there is 30 white, 10 red, 5 blue bals
Also
30 = 5 × 6
And,
10 = 5 × 2
so the new ratio of white, red and blue balls is 6:2:1
use a reference angle to write sec290 (where the angle is measured in degrees) in terms of the secant of a positive acute angle. do not include the degree symbol in your answer.
sec 290° = 1/cos 110°= -2.9238.
To find the value of sec 290° using a reference angle, we first need to determine the reference angle for 290°.
The reference angle is the acute angle formed between the terminal side of the given angle (290°) and the x-axis. To find the reference angle, we subtract the nearest multiple of 180° from the given angle:
Reference angle = 290° - 180° = 110°
Now, we can express sec 290° in terms of the secant of the reference angle (110°). The secant function is defined as the reciprocal of the cosine function:
sec(x) = 1/cos(x)
Therefore, sec 290° can be written as:
sec 290° = 1/cos 110° = -2.9238.
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What is the surface area of this prism?
5 yd
5 yd
11 yd
6 yd
You may need to use the appropriate appendix table to answer this question.
Automobile repair costs continue to rise with the average cost now at $367 per repakt Assume that the cost for an automobile repair is normally distributed with a standard deviation of $88. Answer the following questions about the cost of automobile repairs
(a) What is the probability that the cost will be more than $480 (Round your answer to four decimal places.________
(b) What is the probability that the cost will be less than $240 (Roxind your answer to four decimal places.)________
(c) What is the probability that the cast will be between $240 and $480 (Round your answer to four decimal places.)________
(d) of the cost for your car repair is in the lower 5% of automoble repair charges, what is your matmum possible cast in dollars? (Round your answer to the nearest cent)
$________
The maximum possible cost in dollars is $226.76 (approx).
Standard deviation = $88
Let X be the cost of the automobile repair, then X ~ N(367, 88^2) (normal distribution)
Now, we need to find the following probabilities:
(a) P(X > 480)(b) P(X < 240)(c) P(240 < X < 480)(d)
Find X such that P(X < X1) = 0.05, where X1 is the lower 5% point of X(a) P(X > 480)
We need to find P(X > 480)P(X > 480) = P(Z > (480 - 367)/88) [Standardizing the random variable X]P(X > 480) = P(Z > 1.2955)
Using the standard normal table, the value of P(Z > 1.2955) = 0.0983 (approx)
Hence, the required probability is 0.0983 (approx)(b) P(X < 240)
We need to find P(X < 240)P(X < 240) = P(Z < (240 - 367)/88) [Standardizing the random variable X]P(X < 240) = P(Z < -1.4432)
Using the standard normal table, the value of P(Z < -1.4432) = 0.0749 (approx)
Hence, the required probability is 0.0749 (approx)(c) P(240 < X < 480)
We need to find P(240 < X < 480)P(240 < X < 480) = P(Z < (480 - 367)/88) - P(Z < (240 - 367)/88) [Standardizing the random variable X]P(240 < X < 480) = P(Z < 1.2955) - P(Z < -1.4432)
Using the standard normal table, the value of P(Z < 1.2955) = 0.9017 (approx)and the value of P(Z < -1.4432) = 0.0749 (approx)
Hence, the required probability is 0.9017 - 0.0749 = 0.8268 (approx)(d)
Find the maximum possible cost in dollars, if the cost for your car repair is in the lower 5% of automobile repair charges.
This is nothing but finding the lower 5% point of X.We need to find X1 such that P(X < X1) = 0.05.P(X < X1) = P(Z < (X1 - 367)/88) [Standardizing the random variable X]0.05 = P(Z < (X1 - 367)/88)
Using the standard normal table, the value of Z such that P(Z < Z0) = 0.05 is -1.645 (approx)
Hence, we get,-1.645 = (X1 - 367)/88
Solving for X1, we get: X1 = 88*(-1.645) + 367 = $226.76 (approx)
Therefore, the maximum possible cost in dollars is $226.76 (approx).
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Find the radius of a cone with a volume of 196 x 3.14 mm and a height of 12 mm.
Answer:
r=7 my
answer needs to be 20 characters long
Over a 5-year period, a company reported annual profits of $8 million, $3 million, $2 million, and $9 million. In the fifth year, it reported a loss of $7 million. What was the mean annual profit?
Given
Annual profits of four years $8 million, $3 million, $2 million, and $9 million.
In the fifth year, it reported a loss of $7 million.
To find:
The mean annual profit.
Solution:
Formula for mean is:
[tex]\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Number of observations}}[/tex]
Annual profits are $8 million, $3 million, $2 million, $9 million and -$7 million. Here negative sign represent loss.
So, the mean annual profit is:
[tex]\text{Mean}=\dfrac{8+3+2+9+(-7)}{5}[/tex]
[tex]\text{Mean}=\dfrac{22-7}{5}[/tex]
[tex]\text{Mean}=\dfrac{15}{5}[/tex]
[tex]\text{Mean}=3[/tex]
Therefore, the mean annual profit is $3 million.
Marissa has a yard service to help people in her neighborhood. She earns $15 for each lawn she mows, $10 for each yard she weeds, and $5 for each yard she rakes. This month Marissa spent $3 on flyers to send out to neighbors, she purchased a new blower for $26, and paid her brother $18 for helping her mow lawns. If Marissa mowed 4 lawns and raked 8 yards, how much money did she make in profit? 1. 53 2. 100 3. 36 4. 71
Answer:
100-47=53 so 53$ profit
Step-by-step explanation:
if T= 101+102+103+...+199 find T
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PLEASE HELP ME OUT! QUICK POINTS FOR YOU!
All information needed can be found in the image below
Thank you in advance.
Answer:
circle area = 50.24 units²
Step-by-step explanation:
circle area = πr² = 3.14(4²) = 3.14(16) = 50.24 units²
What percent of a day does this child spend doing homework? (Round to the nearest whole percent)
Answer:
Step-by-step explanation:
Look at the graph, look at homework and then look at the number right outside of it.
Expand x(4 --3.4y) show FULL work
Answer:
4x - 3.4xy
Step-by-step explanation:
x(4 - 3.4y)
4x - 3.4xy