18. In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile)
and the following results were obtained: 0.06, 0.11, 0.16, 0.15, 0.14, 0.08, 0.15. Assuming that
this sample is representative of the cars in use, construct a 98% confidence interval estimate of
the mean amount of nitrogen-oxide emissions for all cars. If the EPA requires that nitrogen-oxide
emissions be less than 0.165 g/mi, can we safely conclude that this requirement is being met?
Assume the population is normally distributed.

What the value of k means in the proportional relationship y =kx is; the change in depth per second of the ascent.

We are told that;

James Cameron descended to the bottom of Challenger Deep in the Marianas Trench; the deepest point in the ocean.

The vessel he rode in called DeepSea Challenger was 35,814 feet deep at its lowest point.

Now, if the time spent is denoted as x in seconds and the depth is denoted as y, the the relationship will be;

y = -kx

where -k is the constant of proportionality which is the change in depth per second of descent.

Now, if the ascent can be modeled by a different proportional relationship y = kx, then it means that k here will be the change in depth per second of the ascent.

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From the first two rows we can see that:

Fill in the missing values.

The cubic function is f(x) = x^3 + 8x^2 - 32x + 32, which has a local maximum value of 4 at x = -4 and a local minimum value of 0 at x = 2.

The cubic function f(x) is of the form f(x) = ax^3 + bx^2 + cx + d, where a, b, c, and d are constants. In this case, a = 1, b = 8, c = -32, and d = 32. The local maximum value of 4 occurs when x = -4 and the local minimum value of 0 occurs when x = 2.To find the equation, we must use the given information to solve for the constants. The function must equal 4 when x = -4, so f(-4) = 4. Plugging in the values for the constants we have 4 = -4^3 + 8(-4)^2 - 32(-4) + 32. Solving this equation, we find that d = 32, so the equation becomes f(-4) = -64 + 256 + 128 + 32 = 4. Similarly, we set f(2) = 0, so 0 = 8 + 16 - 64 + 32. Solving this equation, we find that c = -32, so the equation becomes f(2) = 8 + 16 - 32 + 32 = 0. Finally, we have the equation f(x) = x

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find a cubic function, in the form below, that has a local maximum value of 4 at -4 and a local minimum value of 0 at 2.f (x) = x^3 + 8x^2 - 32x + 32

The height of the rocket in given time using regression equation is 586 feet.

The regression equation is, y =  7.70961x² + 176.30826x - 12.44515

Given,

A rocket is shot off from a launcher. The accompanying table represents the height of the rocket at given times, where x is time, in seconds, and y is height, in feet

That is,

x ; 0.6, 1.3, 1.8, 2.5, 3.1

y ; 108, 218, 285, 368, 436

We have to write a quadratic regression equation for the given set;

The quadratic regression equation is;

y =  7.70961x² + 176.30826x - 12.44515

Now,

We have to find the height at a time of 3 seconds using the equation;

So,

y =  7.70961 x 3² + 176.30826 x 3 - 12.44515

y =  69.38649 + 528.92478 - 12.44515

y = 585.86612

y = 586

Height of the rocket= 586 feet

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The equation of the linear regression is y = 1.49x- 2.76

From the question, we have the following parameters that can be used in our computation:

X 1 2 3 4 5 6 7 8

Y 0,5 0,8 1,2 1,9 3 4,8 7,5 11,9

Rewrite as

X 1 2 3 4 5 6 7 8

Y 0.5  0.8  1.2  1.9  3  4.8 7.5 11.9

When the points are entered in a graphing calculator, we have

The regression equation is represented as

Regression Equation

ŷ = bX + a

Substitute the known values in the above equation, so, we have the following representation

b = SP/SSX = 62.6/42 = 1.49048

a = MY - bMX = 3.95 - (1.49*4.5) = -2.75714

So, we have

y = 1.49048X - 2.75714

Approximate

y = 1.49x- 2.76

Hence, the regression equation is y = 1.49x- 2.76

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Complete question

Given that

X 1 2 3 4 5 6 7 8

Y 0,5 0,8 1,2 1,9 3 4,8 7,5 11,9

Calculate the regression linear equation

At the null hypothesis, it is tested if the mean is of 15 years, that is:

[tex]H_0: \mu = 15[/tex]

At the alternative hypothesis, it is tested if the mean is different of 15 years, that is:

[tex]H_1: \mu \neq 15[/tex]

The equation that gives the test statistic is defined as follows:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which:

The values of these parameters in this problem are given as follows:

[tex]\overline{x} = 17.4, \mu = 15, s = 6.3, n = 75[/tex]

Hence the test statistic is of:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{17.4 - 15}{\frac{6.3}{\sqrt{75}}}[/tex]

t = 3.30.

Considering a two-tailed test, as we are testing if the mean is different of a value, with t = 3.30 and 75 - 1 = 74 df, the p-value of the test is of:

0.0015.

Since the p-value is less than the significance level of 0.05, the null hypothesis is rejected, meaning that there is enough evidence to conclude that prisoners spend a time different of 15 years in the death row.

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Answer:

this very easy to factorize this because (-+)is- (+-)-

(++)+ (--)+ but the sign which is bigger we have to keep that

the scalar surface integral ∬T(z+y)dS where T is the triangle (including its interior) with vertices (0,0,2), (0,1,0)( and (1,0,0) is 1

We can compute the scalar surface integral ∬T(z+y)dS using the parametric form of the surface integral.

Let S be the surface of the triangle. We can parameterize S as follows:

S(u,v) = (u, v, 2-u-v)

where 0 ≤ u ≤ 1 and 0 ≤ v ≤ 1-u.

Then, the scalar surface integral ∬T(z+y)dS is defined as:

∬T(z+y)dS = ∬S(u,v) (2-u-v + v) dudv

= ∫0→1∫0→1-u (2-u-v + v) dudv

= ∫0→1 [2u + (1-u)2 - (1-u)2u - u2(1-u)] du

= ∫0→1 (2u + 1 - 2u2 - u3) du

= [u2 + u - u4/4]0→1

= 1/4 + 1 - ¼

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The DF value we get after is 143 and the integration value we get is 1.76

What is a value ?

Value in ethics and social sciences refers to the degree of significance of something or an activity, with the goal of deciding the best courses of action to take or the best ways to live, or to define the significance of certain activities.

The value describes the value of each digit in relation to its position in the number. The place value and face value of the digit are multiplied to arrive at the answer. Value equals Place Value minus Face Value. Consider this: If we take 45 into consideration. The tens column is where the fourth digit is located in this instance.

The things that someone values are known as their values. In other terms, values are what a person or a group of people see as "important."

(a)

DF for Factor A = 6 - 1 = 5

DF for Factor B = 4 - 1 = 3

DF for Interaction of Factor A and B = 5*3 = 15

Number of replications per cell = 6

Total no of observations = 6*(N_Factor A)*(N_Factor B) = 6 * 6 * 4 = 144

DF Residuals = 144 - 5 - 3 - 15 - 1 = 120

Total DF = N - 1 = 143

(b) Critical F values

Factor A = F(5,120) = 2.30

Factor B = F(3,120) = 2.69

Interaction = F(15,120) = 1.76

(c) As F statistics for Factor A, Factor B as well as Interaction is >> Fc, Hence we can Reject the Null Hypothesis and warrant the rejection of the claim for equality of means

Hence there is a significant difference in Factor A and there is a significant difference in Factor B.

(d) As the F statistics for Interaction = 4.2 >> Fc (1.76), Hence we can conclude that there is a significant Interaction impact of Factor A and Factor B.

Hence there is a significant difference for Interaction term.

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The expression (2/15x - 5) - (-0.7x + 2) is simplified to 5/12x - 3

An algebraic expression can be defined as an expression made up of variables, terms, coefficients, factors and constants.

These expressions are also made up of arithmetic operations.

From the information given, we have;

2/15x - 5) - (-0.7x + 2)

expand the bracket

2/15x - 5 + 7/10x - 2

collect like terms

2/15x + 7/10x - 5 + 2

Add the like terms

4x + 21x /30 - 3

Add the numerators

25x/60 - 3

Divide the common terms, we have;

5/12x - 3

Hence, the expression is 5/12x - 3

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Answer:

-12

Step-by-step explanation:

If g(x) = 5x, then plugging in -60 for g(x) gives -60 = 5x. Dividing both sides of this equation by 5 gives -12 = x. Therefore, the correct answer is -12.

 The arithmetic mean of the three altitudes is equal to 10.1533 or 1523/150

The Arithmetic Mean (AM) or called average is the ratio of the sum of all observations to the total number of observations and is given by   [tex]A= \frac {1}{n} \sum \limits_{i=1}^n a_i[/tex]    

A = arithmetic mean

n = number of values

a₁ = data set values

Given here length of two equal sides is 13 cm and the other side is 10cm

let the Δ be ΔABC with AC=AB= 13 & BC=10cm and the altitudes on sides AC, AB, and BC  with the midpoints P, Q, and R  be AP, BQ, and CR respectively than by Pythagoras theorem we get AP = √13²-5²

                                                                                               = 12

As the altitude of an isosceles triangle bisects the base in this case BC

Then by area of ΔABC is = 1/2×12×10

                                         = 60 cm²

Again BQ is an altitude therefore area ⇒ 60=1/2×BQ×13

                                                                ⇒BQ=9.2307cm

Similarly, we can find  CR = 9.2307 cm

Thus Arithmetic mean of the altitudes is =( 9.2307+9.2307+12)/3        

                                                                  =10.1533 cm

                                                                   = 1523/150 cm

Hence, the answer as a common fraction is 1523/150

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The exponential function is  y = 2400(1.78)x

Since 1.78 < 1, the function is an exponential decay function.

The function can also be written as 2400(1 - 0.04)x.

The rate of decrease is 4% (that's 0.04 expressed as a percent)

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Answer:

5x + 2x + 5x + (3/5x) = 180

12x + 0.6x = 180

12.06x = 180

x = 14

Step-by-step explanation:

a complete description of simple harmonic motion must take into account several physical quantities and various mathematical relations then the position of a 60 gg oscillating mass is given by x(t) -20 sin 10t

this information is needed to solve oscillation problems of this type

the position of a 60 gg oscillating mass is given by x(t)

x = 2 cos wt = 2 cos 10t ; w = 10

velocity = dx/dt = -2 x 10 sin 10 t.=- 20 sin 10t

t = .4

velocity = -20 sin 10 x .4 = -20 sin 4 = -20 x -0.7568 = 15.136 cm /s

w = √ k / m = 10 = √ k / .05

k = 15.136  N/m

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The completed Venn Diagram is given by the image shown at the end of the answer.

The percentages are given as follows:

The Venn diagram starts to be filled from the most restrictive conditions, towards the least restrictive.

2% of people answered all three, hence:

V = 2%.

3% of people answered light rail and bus, hence:

IV + V = 3%

IV = 1%.

6% of people answered light rail and carpool, hence:

II + V = 6%

II = 4%.

2% of people answered carpool and bus, hence:

V + VI = 2%

V = 0%.

11% of people answered carpool, hence:

III + II + V + VI = 11

III + 4 + 2 + 0 = 11

III = 5%.

10% of people answered bus, hence:

IV + V + VI + VII = 10

1 + 2 + 0 + VII = 10

VI = 7%.

16% of people answered light rail, hence:

I + II + IV + V = 16

I + 4 + 2 + 1 = 16

I = 9%.

Then the or percentage is given as follows:

9 + 7 + 5 + 1 + 2 + 4 = 28%.

The percentage that uses other mediums is given as follows:

VIII = 100 - 28 = 72%.

Then the missing percentages are given as follows:

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Answer:

x = 0

Step-by-step explanation:

x + 5/4 = 20/16

x + 5/4 = 5/4

x = 0

Hello,

I hope you and your family are doing well!

To find the number of students who took Science, Dance, or English, you can add the number of students in each individual category and then subtract the number of students who took all three courses, since those students were counted twice. This gives a total of 1031 + 1058 + 1059 - 218 = 3100 students.

To find the number of students who took Dance and English, but not Science, you can add the number of students in region VII and region VIII, which is 456 + 11 = 467 students.

To find the number of students who took Science or didn't take Dance, you can add the number of students in region I and region III, which is 1031 + 218 = 1249 students.

To find the number of students who took none of the courses, you can add the number of students in region II and region IV, which is 449 + 459 = 908 students.

To find the number of students who took Science or English, but not Dance, you can add the number of students in region V and region VI, which is 1059 + 459 = 1518 students.

----

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Happy Holidays!

Answer:

D

Step-by-step explanation:

m^ (-3 · -4) = m^12

n ^ (-2 · -4) = n^8

m^12 n^8

Answer:

0.5a + 0.75p ≤ 23

Step-by-step explanation:

Cost of a apples: 0.5a

Cost of p pears: 0.75p

The total cost must be $23 or less.

0.5a + 0.75p ≤ 23

The regression equation is Y=1117.84+73.62X for the data as follows:

(20,3200), (15,3600), (25,3400), (10,1800), (18,2200), (18,2400), (15,2400), (12,1500), (22,2500), (15,2400), (25,3000), (16,2700), (12,2000), (20,2600), (25,2800)

where (x,y) denotes infomercials and sales, respectively.

According to regression equation Y=a+bX,

a = ((Σy) x (Σx^2) - (Σx) x (Σxy)) / (n x (Σx^2) - (Σx)^2)

a = ((36500 x 5126)-(268 x 677000)) / ((15 x 5126)-(268 x 268))

a = 1117.84

and, b = (n(Σxy)-(Σx)(Σy)) / (n(Σx^2)-(Σx)^2)

b = ((15 x 677000)-(268 x 365000)) / ((15 x 5126)-(268 x 268))

b = 73.62

Putting the values of a and b in the regression equation, we get the desired equation Y=1117.84+73.62X.

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Answer:

  see the attachment

Step-by-step explanation:

You want to match several expressions with fractional exponents to their equivalent radical forms.

The relationship between the two forms is ...

  [tex]a^{\frac{m}{n}}=\sqrt[n]{a^m}[/tex]

If n=2, or m=1, these are omitted from the radical form.

The attachment shows the matching values.

The system does not have a periodic solution in each of 10 and 11.

A solution of the period depends on the independent variable t is called Periodic Solution. For a periodic solution x(t)( in the case of a system, x is a vector), there is a number T≠0 such that

x(t+T)=x(t)  for t∈R.

The given equations are:

      [tex]\frac{dx}{dt} =-2x-3y-xy^2\\\\\frac{dx}{dt} =y+x^3+x^2y[/tex]

F is the derivative of dx/dt and Gis the derivative of dy/dt:

[tex]F(x,y)=-2x-3y-xy^2\\G(x,y)=y+x^3+x^2y[/tex]

When Fx+Gx has the same sign on the entire domain D, then there are no periodic solutions on the domain D.

Fx+Gx=-2-y^2+1-x^2

          =-1-y^2-x^2

             <for all real numbers x,y[tex]\neq[/tex]0

Fx+Gx have the same sign  for all pairs of real numbers with x[tex]\neq[/tex]0 and y[tex]\neq[/tex]0

Thus, there are no periodic solutions in the system(excluding contact solutions)

Hence proved.

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Descartes's number is the 46.989, which is less than 47 and higher than 46.98.

A Descartes number is an odd number with the formula n = m p, where m and p are coprime numbers and 2n = (m) (p + 1). P is regarded as a "spoof" prime in this formula. The only known example is the one that was provided. The invention of Cartesian or analytic geometry, which employs algebra to describe geometry, is one of Descartes's most enduring contributions. In equations, Descartes "introduced the convention of denoting unknowns by x, y, and z, and knowns by a, b, and c." A Descartes number is an odd integer that, if one of its composite elements were prime, would have been an odd perfect number.

Given,

Descartes's number is,

46.989, which is less than 47 and higher than 46.98.

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The position of E as a mixed number is [tex]2\frac{4}{5}[/tex].

What is number line?

A number line is a diagram of a graduated straight line used to represent real numbers in elementary mathematics. It is assumed that every point on a number line corresponds to a real number, and that every real number corresponds to a point.

Let on a number line the position of E is given.

We have to find E as a mixed number.

As we can see there are 5 parts between 2 and 3.

So each part is 0.2 cm.

The position of E is in fourth part.

So, 4 x 0.2 = 0.8 cm

2 + 0.8 = 2.8 is the position of E.

2.8 can be written as.

28/10 = 2 8/10 = 2 4/5

Hence, the position of E as a mixed number is [tex]2\frac{4}{5}[/tex].

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Taylor Series for following parts,

a) f(x) = 7 - (7/2)x² + (7/24)x⁶ +......

b)f(x) = 21 - 18(x+2) + 25(x + 2)² - 8(x+3)³ +......

c)f(x) = 2 + 2log(2)(x -1) +(log2)²(x-1)² + (1/3 (log2)³(x-1)³ + --------

d)f(x) = x² + ----

The Taylor series giving the expansion of the function f(x) in the neighborhood of the point a. If the function is continuous in the neighborhood, all its derivatives exist, and the series converges, then The form f(x) = f(a)+f′(a)/1!(x−a)+(f′′(a)/2!)(x−a)²+⋯+(fⁿ(a)/n! )(x−a)ⁿ --(1) where fⁿ(a) is the nᵗʰ derivative of f(x) evaluated at a.

a) f ( x) = 7 cos(-x) = 7 cos(x) , a = 0

f(a ) = 7 cos(0°) = 7

f'(x) = - 7 sin(x) , f'(a) = 7 sin(0°) = 0

f"(x) = - 7cos(x) , f"(a) = -7 cos(0°) = -7

f"'(x) = 7 sin(x) , f"'(a) = 7 sin(0° ) = 0

....................................

put all the values in above equation (1) we get,

f(x) = 7 + 0/1! (x -0) - (7/2!)(x-0)² )+ 0 +(7/4!) (x-0)⁴-0 + ----------

f(x) = 7 - (7/2)x² + (7/24)x⁶ +......

b) f(x) = x⁴ + x² + 1, a = -2

f(a= -2) = (-2)⁴ +(-2)² +1 = 21

f'(x) = 4x³ + 2x

f'(a= -2) = 4(-2)³ + 2×(-2) = -36

f"(x) = 12x² + 2

f"( a = -2) = 12(-2)² + 2 = 50

.....

put all the values in above equation (1) we get,

f(x) = 21 - (36/2)(x+2) + (50/2!)(x + 2)² - ( 48/3!)(x+3)³ +......

f(x) = 21 - 18(x+2) + 25(x + 2)² - 8(x+3)³ +......

c) f(x) = 2ˣ ; a = 1

f( a= 1) = 2¹ = 2

f'(x) = 2ˣ log(2)

f'(a= 1) = 2 log(2)

f"(x) = 2ˣ ( log(2) )²

f"( a = 1) = 2 ( log(2) )²

................

put all the values in above formula we get,

f(x) = 2 + 2log(2) +( 2/2!)(log2)² + (2/3!)(log2)³

+--------

f(x) = 2 + 2log(2)(x -1) +(log2)²(x-1)² + (1/3(log2)³(x-1)³ + --------

d) f(x) = x tan⁻¹(x²) ; a= 0

f(a=0) = 0

f'(x) = x (1/(1+x⁴) + tan⁻¹(x²)

f'(a = 0) = 0

f"(x) = ((1+x⁴) - x 4x³)/(1+x⁴)² + (1/(1+x⁴)

= (2/(1+x⁴) - 4x⁴/(1+x⁴)²

f"( a = 0) = 2 - 0 = 2

f"'(x) = - 8x³/(1+x⁴)² - 12x³/ (1+x⁴)² + 16x⁷/(1+x⁴)⁴

f"'(a = 0) = 0

..............

f(x) = 0 +0 + 2/2! (x-0)² + 0 +-------

f(x) = x² + ----

Hence, we get all required Taylor Series for

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Step-by-step explanation:

it is really a simple concept : instead of the isolated variable x you grab the whole function of g(x) and put that into the place of any x appearance in f(x) : g(x) becomes the input argument for f(x).

so,

f(g(x)) = sqrt(36/(x + 3)) = 6×sqrt(1/(x + 3))