Bond length is the distance between the centers of two bonded atoms. On the potential energy curve, the bond length is the internuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Consider that the atomic radius (sometimes called the covalent or bonding atomic radius) of an element is defined as one-half the distance between the bonded atoms in a homonuclear diatomic molecule. Actual bond lengths in molecules are determined experimentally by such methods as X-ray diffraction and microwave spectroscopy. However, these atomic radii values can be used to give an estimate of the upper limit of bond length in other (heteronuclear) molecules. Given that the atomic radii of H and Br are 37.0 pm and 115 pm , respectively, predict the upper limit of the bond length of the HBr molecule.

Answer:

after millions of years underground the compounds that make up plankton and plants turn into fossil fuels Franklin decomposes into natural gas and oil white plants become cal today humans extract these resources through coal mining and the drilling of Oil and Gas Wells on land and Offshore

Answer:

See explanation

Explanation:

Synthesis reaction and decomposition reactions are two opposing processes.

While a synthesis reaction has to do with the formation of a substance from its constituents, decomposition deals with the breakdown of a substance into its constituents.

While decomposition requires energy and is an endothermic process, synthesis is usually an exothermic process in which energy is given off as stable products are formed.

Answer:

Mass =  142.25 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Number of moles of Ca(OH)₂ = 1.92 mol

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of Ca(OH)₂ = 74.09 g/mol

by putting values,

Mass = 1.92 mol × 74.09 g/mol

Mass =  142.25 g

Answer:

7.90

Explanation:

Gay-Lussacs law states that P1/T1 = P2/T2

if:

P1 = 6.32

T1 (in Kelvins) = 25.1 + 273.1 =298.2

P2= ?

T2 = 100 + 273.1 = 373.1

so

6.32/298.2 = P2/373.1

P2 = 7.90

Answer:

All employees should know how to work the system

How many grams of zinc (Zn) are in 32.7 g of Zn?

Answer:

32.7g

Explanation:

The mass of Zinc in the given substance is 32.7g.

Mass is the quantity of matter contained in a substance. The sum total of the amount of matter is the mass.

Since this problem gives us 32.7g of Zn then the substance will also contain 32.7g of Zinc.

Even when the Zinc is used in chemical reactions, we are expected to produce an equal amount of zinc as the product.

This way, mass is always conserved.

Answer:

Explanation:

Weight = mass x gravity

mass given = 85 kg

gravity = 8.87 m /s²

Weight = 85 x 8.87 = 753.95 N .

Weight on Uranus = 753.95 N .

Answer:

Explanation:

From the information given;

Consider using Lande's Interval rule which can be expressed as:

[tex]\Delta E = E_{j+1} - E_jj \ = \alpha (j+1)[/tex]

here;

[tex]j+1[/tex]  = highest level of j

and

[tex]\dfrac{\Delta E_1}{\Delta E_2} = \dfrac{(j+2)}{(j+1)}[/tex]

[tex]\dfrac{5}{3} = \dfrac{(j+2)}{(j+1)}[/tex]

[tex]5(j+1) = 3(j+2)[/tex]

[tex]5j+5 = 3j+6[/tex]

[tex]2j = 1\\ \\ j = \dfrac{1}{2}[/tex]

recall that:

[tex]j = |S-L| \ \to \ |S+L |[/tex]

So;

[tex]S-L = \dfrac{1}{2} --- (1)[/tex]; &

[tex]S+L = \dfrac{5}{2} --- (1)[/tex]

Using the elimination method, we have:

[tex]2S = \dfrac{6}{2}[/tex]

[tex]S = \dfrac{3}{2}[/tex]

Since [tex]S = \dfrac{3}{2}[/tex]; then from (1)

[tex]\dfrac{3}{2} -L = \dfrac{1}{2}[/tex]

[tex]L = \dfrac{2}{2}[/tex]

[tex]L = 1[/tex]

Answer/Explanation:

This electrical energy now travels through the phone supplying the phone with electricity. Batteries in a cell phone supply chemical energy to electric charges. The electric charges use the energy to be put into motion.

Answer:

D. spectator ions.

Explanation:

Hello!

In this case, when going over net ionic equations by which precipitation reactions are analyzed, we can consider the example of lead (II) nitrate with potassium iodide to yield insoluble lead (II) iodide and soluble potassium nitrate according to:

[tex]2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)[/tex]

Whereas aqueous species remain in solution:

[tex]2K^+(aq)+2I^-(aq)+Pb^{2+}(aq)+2(NO_3)^-(aq)\rightarrow PbI_2(s)+2K^+(aq)+2(NO_3)^-(aq)[/tex]

It means that potassium and nitrate ions are spectator ions because they are not involved in the precipitation reaction, which is represented by the net ionic one:

[tex]2I^-(aq)+Pb^{2+}(aq)\rightarrow PbI_2(s)[/tex]

Thus, the answer to this question is D. spectator ions.

Best regards!

Answer:

decreases a bit then stays constant

Explanation:

Answer:

It would be 151.832775 because one mole is 44.0095*3.45 i hope this helps!

Explanation:

Answer:

construct using only recycled materials ^^

Explanation:

Answer:

Hydrosphere

Explanation:

The biosphere simply refers to the zone of life found on earth. It refers to the portion of the earth inhabited by living things.

The biosphere is divided into three, namely; hydrosphere, atmosphere and lithosphere.

The atmosphere is simply the layer composed of air, the lithosphere is the solid part of the earth while the hydrosphere is the part composed of water.

Since jelly fish is an aquatic animal, it will certainly inhabit the hydrosphere. Hence the answer above.

Answer:

The answer is "0.38 A".

Explanation:

Please find the missing image file in the attachment.

In the given image let:

[tex]R_{12} =R_1+R_2=16 \ \Omega \\\\R_{34} =R_3+R_4=20 \ \Omega \\[/tex]

[tex]R_P=\frac{R_{12} \cdot R_{34}}{R_{12} +R_{34}}[/tex]

     [tex]= \frac{16 \cdot 20 }{16 +20}\\\\= \frac{320 }{36}\\\\= \frac{80 }{9}\\\\= 8.88 \ \Omega[/tex]

similarly,

[tex]R_{eq} =R_p+R_5+R_6\\\\[/tex]

      [tex]=8.88+24+20\\\\=52.89 \ \Omega \\\\[/tex]

calculating the current value through a switch:

[tex]\to I=\frac{V}{R_{eq}} = \frac{20 \ v}{52.89 \Omega }=0.38\ A[/tex]

Answer:

D. 0.38 amperes

Explanation:

Got it correct on Gizmos

Gizmos explanation: This compound circuit contains two parallel branches connected in series to 2 more resistors. Each parallel branch contains 2 resistors in series. The resistance of the first branch is 5+11=16 ohms, and the resistance of the second branch is 20 ohms. Using the equivalent resistance formula, the resistance of this section is

1R=116+120=580+480=980

So R is 809, or 8.89 ohms. This is connected in series to a 24-ohm and a 20-ohm resistor, for a total resistance of 52.89 ohms. The battery voltage is 20 volts, so by Ohm's law

I=VR

I=2052.89=0.38amperes

Answer:

4.71 g of sodium and 7.25 g of chlorine

Explanation:

Note: The question is incomplete. the complete question is given below:

Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?

4.71 g of sodium and 3.30 g of chlorine

4.71 g of sodium and 7.25 g of chlorine

4.71 g of sodium and 1.31 g of chlorine

4.71 g of sodium and 13.7 g of chlorine

The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.

This means that irrespective of the source of any sample of a pure chemical compound, the constituents elements are always combined in the same mass ratio.

In the first sample, the mass ratio of Sodium to chlorine is given below:

mass of sodium = 2.55 g

mass of chlorine = 3.93 g

mass ratio; sodium to chlorine = 2.55 / 3.93 = 0.65

From the set of masses give above, we can determine the result of the decomposition of the second sample.

4.71 g of sodium and 3.30 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 3.30 = 1.43

4.71 g of sodium and 7.25 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 7.25 = 0.65

4.71 g of sodium and 1.31 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 1.31 = 3.59

4.71 g of sodium and 13.7 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 13.7 = 0.34

From the results above, the correct set of masses for the second sample is 4.71 g of sodium and 7.25 g of chlorine

Answer:

Observational evidence is essential for investigating the way disease affects populations, the patterns and distribution of risk within them, and the emergence of trends in health and disease over time.

Answer:

It tests a prediction It supports the results. It asks a testable question It predicts what will happen

Explanation:

The lethal dose and how ounces of soda in a can of soda is not given, however, the standard lethal dose and volume of soda are given as below:

Lethal dose: 10 gm of caffeine

The volume of soda per can =  12oz/can

Answer:

The correct answer is - 324.254 cans or round up to 325 cans. Ans.

Explanation:

Given:

2.57 mg caffeine / 1oz

12oz / 1can

Lethal dose: 10.0g or 10,000mg of caffeine

Solution:

Caffeine per soda can = (2.57 mg caffeine / 1oz) * (12oz / 1can) = 30.84 mg caffeine / 1can.

lethal dose would be in =

(10,000mg caffeine) * (1can / 30.84 mg caffeine) = 324.254 cans or round up to 325 cans. Ans.

Answer:

yes

Explanation:

yes

Answer:

well heat travels by conduction, convection, and radiation but I think it's 2.

Explanation:

heat travels to colder things trying to make a balanced temperature for both of the objects.

Answer:

The soil has a percentage of water by mass of 27.8 %.

Explanation:

Keeping in mind that

we can calculate the mass of water:

We can then calculate the mass percentage of water in the soil:

Answer: The specific heat of the metal in [tex]1.34J/g^0C[/tex]

Explanation:

[tex]Q_{absorbed}=Q_{released}[/tex]

As we know that,  

[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]

[tex]m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)][/tex]      

where,

[tex]m_1[/tex] = mass of metal = 31.7 g

[tex]m_2[/tex] = mass of water = 100.0 g

[tex]T_{final}[/tex] = final temperature = [tex]24.6^oC[/tex]

[tex]T_1[/tex] = temperature of metal = [tex]96.5^oC[/tex]

[tex]T_2[/tex] = temperature of water = [tex]17.3^oC[/tex]

[tex]c_1[/tex] = specific heat of metal= ?

[tex]c_2[/tex] = specific heat of water =  [tex]4.184J/g^0C[/tex]

Now put all the given values in equation (1), we get

[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex]

[tex]-(31.7\times c_1\times (24.6-96.5)^0C)=(100.0\times 4.184\times (24.6-17.3)][/tex]

[tex]c_1=1.34J/g^0C[/tex]

Therefore, the specific heat of the metal in [tex]1.34J/g^0C[/tex]

Answer:

negative charge

Explanation:

protons have a positive, nuetrons have a neutral charge , and electrons have a negative.

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

Answer:

A) By decreasing the effort needed to do the work

Explanation:

The answer fam is....... A) By decreasing the effort needed to do the work

Hence the word simple Machine

Answer:

The sun will appear to rise and set more slowly

have a nice day! (^o^)

Answer:

The sun will appear to rise and set more slowly

have a nice day! (^o^)

Answer:

0.52 g of KNO₃ are contained in 19.7 mL of diluted solution.

Explanation:

We can work on this problem in Molarity cause it is more easy.

Molarity (mol/L) → moles of solute in 1L of solution.

100 mL of solution = 0.1 L

We determine moles of solute: 44.7 g . 1mol /101.1 g = 0.442 mol of KNO₃

Our main solution is 0.442 mol /0.1L = 4.42 M

We dilute: 4.42 M . (11.9mL / 200mL) = 0.263 M

That's concentration for the diluted solution.

M can be also read as mmol/mmL, so let's find out the mmoles

0.263 M . 19.7mL = 5.18 mmol

We convert the mmol to mg → 5.18 mmol . 101.1 mg / mmol = 523.7 mg

Let's convert mg to g → 523.7 mg . 1 g / 1000 mg = 0.52 g