Answer:
The distance is [tex]d = 112.5 \ m[/tex]
Explanation:
From the question we are told that
The horizontal speed is [tex]v_x = 30 \ m/s[/tex]
The height is [tex]s = 69 \ m[/tex]
Generally from kinematic equation we have that
[tex]s = ut + \frac{1}{2} gt^2[/tex]
Here u is the initial velocity of the turd in the vertical direction and the value is 0 m/s
So
[tex]69 = 0 * t + \frac{1}{2} * 9.8 t^2[/tex]
=> [tex]t = \sqrt{\frac{2 * 69}{4.9} }[/tex]
=> [tex]t = 3.75 \ s[/tex]
Generally the distance which the robot have to hood the bucket in order to catch the turd is mathematically represented as
[tex]d = v_x * t[/tex]
=> [tex]d = 30 * 3.75[/tex]
=> [tex]d = 112.5 \ m[/tex]
A constant force acting on a body of mass 2 kg changes its
velocity from 1 m/s to 2 m/s in 20 s. If the direction of motion of
the body remains unchanged, the magnitude of the force that acted
on the body was 0.1 N.
True or False
Answer:
the correct answer is b
Answer:
true
Explanation:
just did it on ck12 lol
What quantities belong in cells X and Y?
X: centripetal acceleration
Y: period
X: tangential speed
Y: radius
X: radius
Y: centripetal acceleration
X: period
Y: tangential speed
Answer:
X: period
Y: tangential speed
Explanation:
100% on quiz your welcome(:
The quantities belonging in cells X and Y is to be considered as the
X: period
Y: tangential speed
Quantities belong in cells X and Y:The equation for centripetal acceleration is
= v² / r
here, v should be the tangential velocity of the body
And the radius of curvature.
So based on this, we can say that
Column X. Tangential Speed
Column Y. radius
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Do you always need
more than one reactant
or more than one
product to have a
chemical reaction?
Answer:
no
Explanation:
2. An object is moving with an initial velocity of 12 m/s. It accelerates at a rate of 1.5 m/s^2 over a distance of 40 m. What is its new velocity?
Answer:
16.2 m/s
Explanation:
2ad=Vf^2-Vi^2
2 (1.5) (40) = Vf^2 -(12)^2
Vf= 16.2 m/s
Una fuerza resultante constante de módulo igual a 40 [N], actúa sobre un cuerpo que se mueve en línea recta.¿Que distancia ha recorrido ese cuerpo si su energía cinética varió en 8 [J]?
Responder:
0,2 m
Explicación:
Usando la fórmula para calcular el trabajo realizado expresada como;
Workdone = Fuerza * Distancia
Dado
Fuerza = 40N
Trabajo realizado = 8 julios
Necesario
Distancia
Sustituya los parámetros dados en la fórmula como se muestra;
Distancia = Trabajo / Fuerza
Distancia = 8/40
Distancia = 0,2 m
Por tanto, el cuerpo recorrió una distancia de 0,2 m
How far will you travel in 3.5 hrs if you have an average velocity of 90 km/hr
Answer:
The answer is 315 km
Water boils at 212°F. Which temperature is an equivalent temperature?
[tex]\mathrm {Hey, there!}[/tex]
Let's solve your problem:
We will convert your number, 212°F, to Kelvin and Celsius.
212°F is equal to 100° Celsius.
Now, let's do the Kelvin convert.
To convert Celsius to Kelvin, we have to add 273.5 to the amount of Celsius.
100° + 273.5 = 373.5
We have all our conversions. Finally, let's set them out.
Fahrenheit: 212°F
Celsius: 100°C
Kelvin: 373.5°K
List the three astronomical causes for the seasons
I need help, worth 40 Points!
A plane flies due north (90° from east) with a velocity of 100 km/h for 3 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 3 hours, where will the plane’s position be relative to its starting point?
*Please try to fill the data table.
Answer:
thank you
Explanation:
Split up the two given velocity vectors into horizontal and vertical components.
Plane:
p = (100 km/h) (cos(90°) i + sin(90°) j ) = (100 km/h) j
Its direction is given, 90° relative to east.
Traveling for 3 hours with this velocity results in a displacement of
p * (3 h) = (300 km/h) (3h) j = (900 km) j
meaning that this velocity contributes to a north-facing displacement of 900 km.
Wind:
w = (30 km/h) (cos(315°) i + sin(315°) j ) ≈ (21.2 km/h) i + (-21.2 km/h) j
Its direction is also given, 315° relative to east.
After 3 h, this velocity contributes to a displacement of
w * (3h) ≈ (63.6 km) i + (-63.6 km) j
meaning if the plane had no velocity of its own but somehow stayed in the air, the wind would have pushed it about 63.6 km south and 63.6 km east, which translates to a net displacement of
√((63.6 km)² + (-63.6 km)²) = 90 km
due southeast.
Putting everything together, your table displacement table should read:
. | wind | plane
velocity | 30 | 100 ... km/h
direction | 90° | 315° ... relative to east
x | 63.6 | 0 ... km
y | -63.6 | 900 ... km
The resultant vector is the sum of these, r = p + w :
r ≈ (21.2 km/h) i + (78.8 km/h) j
After 3 h, the resultant displacement is
r * (3h) ≈ (63.6 km) i + (236.4 km) j
with magnitude
√((63.6 km)² + (236.4 km)²) ≈ 244.8 km
and direction θ such that
tan(θ) ≈ (236.4 km) / (63.6 km)
θ ≈ arctan(3.714) ≈ 74.9°
So the resultant table should read
xnet | 63.6 km
ynet | 236.4 km
magnitude | 244.8 km
theta | 74.9° relative to east
A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time that has passed
is 300 seconds, how much of the of the original material is still radioactive? Show all work
Answer:
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
Explanation:
From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:
[tex]\frac{dm}{dt} = -\lambda\cdot m[/tex] (1)
Where:
[tex]\frac{dm}{dt}[/tex] - Rate of change of the mass of the radioactive material, measured in kilograms per second.
[tex]m[/tex] - Current mass of the radioactive material, measured in kilograms.
[tex]\lambda[/tex] - Decay constant, measured in [tex]\frac{1}{s}[/tex].
The solution of the differential equation is:
[tex]m(t) = m_{o}\cdot e^{-\lambda\cdot t}[/tex] (2)
Where:
[tex]m_{o}[/tex] - Initial mass of the radioactive material, measured in kilograms.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]m_{o} = 20\,kg[/tex], [tex]\lambda = 0.179\,\frac{1}{s}[/tex] and [tex]t = 300\,s[/tex], then the initial mass of the radioactive material is:
[tex]m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}[/tex]
[tex]m(t) \approx 9.537\times 10^{-23}\,kg[/tex]
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
If Chris throws the baseball 60 meters forward in 4.2 sec, what is the velocity of the ball? I need answer immediately
Answer:
14.3 m/s
Explanation:
velocity equation
v= d/t
v= 60/4.2
v=14.28
round it to 1 decimal place
v= 14.3m/s
what is electricity
Answer:
Electricity is the flow of electrical power or charge. It is a secondary energy source which means that we get it from the conversion of other sources of energy, like coal, natural gas, oil, nuclear power and other natural sources, which are called primary sources.
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Answer:
The answer is 1376 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 8 × 10 × 17.2
We have the final answer as
1376 JHope this helps you
Explanation:
potential energy = mgh
potential energy = 8 * 10 * 17.2
potential energy = 1376 joules
If an object has a fast velocity, the dots on a ticker tape diagram will be _____.
very long
far apart
very short
close together
Answer:
If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.
A person with a weight of 120 lbs. is standing on a scale. What force is the
scale exerting on the person? *
O Olbs up
O 60 lbs up
O 120 lbs up
240 lbs up
Those 4 numbers are the answer choices plz help
Answer:
The answer is 120lbs
Explanation:
because the scale exerts enough force to equal out to 0 and since the person is putting 120lbs onto the scale it then pushes back enough force to keep them up
The upward force acting on the body is 534 N which is equal to 240 lbs in the upward direction, hence, option d is correct.
What is force?Force is an external agent acting on a body to change it from the state of motion or rest. There are various kind of forces namely, gravitational force, magnetic force, nuclear force etc.
Gravitational force is the force by which an object attracts other objects to its center of mass. Gravitational force depends on the mass of the object and the distance from the surface of earth.
The weight of the person is 120 lbs.
1 Kg = 2.2 lbs
120 lbs = 54.5 Kg.
The force acting on the body by their weight = mg = 54.5 Kg × 9. 8 m/s².
= 534 N.
Hence, 534 N is 240 lbs (534 /2.2 ) of force upward.
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s the statement, "You run faster than I do," qualitative or quantitative?
Answer:
qualitative, its an expression, not specific #'s
Explanation:
It is Qualitative
What is Qualitative or Quantitative?Quantitative : Data is number based , countable or measurable
Qualitative : Data is interpretation based , descriptive and relating to language
Since , the statement given in question does not in include any kind of number or measurable quantity and its just an descriptive and relating to language . It is Qualitative
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it is harmful to settle near the airport why
Classify each resource as renewable or nonrenewable.
Answer:
coal: nonrenewable
geothermal energy: renewable
wind: renewable
natural gas: nonrenewable
Explanation:
Have a good day
Thanks
Answer:
coal is non-renewable, the wind is renewable, I belive natural gas is not but I'm not to sure with that one. geothermal energy is renewable.
Explanation:
Is Time and Light both connected in anyway?
Answer:
It is not connected by any way
A roller coaster is travelling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is travelling 36 m/s. What is the average acceleration?
7.2 m/s2
0.14 m/s2
36 m/s 2
7 m/s2
Answer:
7m/s²
Explanation:
Given parameters:
Velocity at the top = 1m/s
Velocity at the bottom = 36m/s
Time = 5s
Unknown:
Average acceleration = ?
Solution;
Acceleration is the rate of change of velocity with time. It is expressed as;
A = [tex]\frac{v -u}{t}[/tex]
v is the velocity at the top
u is the velocity at the bottom
t is the time taken
Now, insert the parameters and solve;
A = [tex]\frac{36 - 1}{5}[/tex] = 7m/s²
Given values:
Top velocity,
v = 1 m/sBottom velocity,
u = 36 m/sTime,
t = 5 sThe acceleration is:
→ [tex]A = \frac{v -u}{t}[/tex]
By putting the values,
[tex]= \frac{36-1}{5}[/tex]
[tex]= \frac{35}{5}[/tex]
[tex]= 7 \ m/s^2[/tex]
Thus the answer above i.e., "option d" is correct.
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15. Which element will donate electrons?
nitrogen
chlorine
aluminum
sulfur
The flaming gorge bridge, in wyoming rises above a dry gulch. If you throw a rock straight out from the bridge, horizontally, and the rock's horizontal displacement is 255 cm, what was the speed that you thew the rock
Answer:
12.495m/s
Explanation:
Horizontal displacement is the range of the projectile motion.
The range is expressed as;
R = 2U/g
U is the speed at which the rock is thrown (initial speed)
g is the acceleration due to gravity.
Given
R = 255cm = 2.55m
g = 9.8m/s²
Required
Speed U
Substitute the given parameters into the formula as shown;
2.55 = 2U/9.8
Cross multiply
2U = 2.55×9.8
2U = 24.99
U = 24.99/2
U = 12.495m/s
Hence the speed that you thew the rock is 12.495m/s
A car drives 400 meters in 5 seconds. What is the cars speed in m/s?
Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))
What would be the y-component of a velocity vector that had a
magnitude of 37m/s in a direction 30° from the x-axis?
Answer:
18.5 m/s
Explanation:
Just did it on EdPuzzle
The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.
The y-component of a velocity vector = 37 × sin 30
= 18.5 m / s
Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.
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1. A pumpkin with a mass of 2 kg accelerates 2 m/s/s when an unknown force is applied to it. What is the amount of the force?
Answer:
The answer is 4 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 2 × 2
We have the final answer as
4 NHope this helps you
11. The professor who first
implemented a scientific approach in
order to investigate a problem, and
who is often referred to as ‘the father
of scientific methodology’, is:
a. Galileo
b. Democritus
c. Newton
d. Einstein
12. Which of the following adjustments
to a pendulum would affect the
period of oscillation?
a. Increasing the mass
b. Decreasing the length
c. Increasing the length
d. Increasing the angle of
displacement
13. The width of a desk was measured
using a meter ruler, which of the
following is the most appropriate
reading expressing the result?
a. 0.724 m
b. 0.7248 m
c. 0.72 m
d. 72 cm
Answer:Newton
Explanation:
When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?
Ο Α. 2Ω
Ο Β. 4 Ω
Ο C. 8Ω
Ο D. 16 Ω
Answer:
B
Explanation:
V=IR I= curren V=volt R=resistor
8=2.R 8/2=R R=4
for which colour of light is. the index of refraction of glass largest
Answer:
don't know sorry for the irreverent answer..
Answer:
The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.
The components of a 15-meters-per-second velocity at an angle of 60.° above the horizontal are (1) 7.5 m/s vertical and 13 m/s horizontal (2) 13 m/s vertical and 7.5 m/s horizontal (3) 6.0 m/s vertical and 9.0 m/s horizontal (4) 9.0 m/s vertical and 6.0 m/s horizontal
Answer:
13 m/s vertical and 7.5 m/s horizontal
Explanation:
❤️
The vertical and horizontal components of a projectile is required.
The correct option is (2) 13 m/s vertical and 7.5 m/s horizontal
u = Initial velocity of projectile = 15 m/s
[tex]\theta[/tex] = Angle of projectile = [tex]60^{\circ}[/tex]
The horizontal component
[tex]u_x=u\cos \theta\\\Rightarrow u_x=15\cos60^{\circ}\\\Rightarrow u_x=7.5\ \text{m/s}[/tex]
The vertical component
[tex]u_y=u\sin \theta\\\Rightarrow u_x=15\sin60^{\circ}\\\Rightarrow u_x=13\ \text{m/s}[/tex]
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Three vectors , , and , each have a magnitude of 52.0 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 29.0 ˚, 191 ˚, and 311 ˚, respectively. What are (a) the magnitude and (b) the angle of the vector (relative to the +x direction in the range of (-180°, 180°)), and (c) the magnitude and (d) the angle of in the range of (-180°, 180°)? What are (e) the magnitude and (f) the angle (in the range of (-180°, 180°)) of a fourth vector such that ?
Answer:
a) A´= A
b) θ₁´ = 29º, θ₂´ = - 169º , θ₃´ = -49º
Explanation:
In this exercise you are asked to give the magnitudes and angles of the vectors from another system of
reference
a) The magnitudes
The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector
A = [tex]x_{f}[/tex]- x₀
if the vectors are measured in another reference frame
x_{f}´ = xx_{f}- U
x₀´ = x₀ -U
where U is the distance between the two reference frames
A´ = x_{f}´ - x₀´
we substitute
A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀
A´ = A
it does not change
b) Angles
The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis
θ₁ = 29º
does not change
θ₁´ = 29º
θ₂ = 191º
we measure clockwise
θ₂´ = θ₂ - 360
θ₂´ = 191 - 360
θ₂´ = - 169º
θ₃ =311º
we measure clockwise
θ₃´ = 311 -360
θ₃´ = -49º