Based on the diagram, which is a true statement?

- If a student plays in the band, then he/she is an honor student.
- If a student is an honor student, then he/she plays in the band.
- If a student is not an honor student, then he/she cannot play in the band.
- If a student is an honor student, then he/she may also be a band member.

Based On The Diagram, Which Is A True Statement?- If A Student Plays In The Band, Then He/she Is An Honor

Answers

Answer 1

Based on the diagram, the true statement is "If a student is an honor student, then he/she may also be a band member."

What does the diagram show?

It shows the intersection between two groups:

Honor studentsBand members

This intersection implies some band members are honor students and vice versa. However, not all band members are honor students and not all honor students are band members.

What can be concluded?

A correct conclusion is that an honor student may also belong to the band.

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Related Questions

find the values of m&n if x
2
−2
[tex]f(x) = mx ^{4} + 2x ^{3} - 3x ^{2} + nx - 4[/tex]

Answers

The values of m and n from the given equation are 1/4 and -2

Polynomial functions

Given the polynomial function below

f(x) = mx^4+2x^3-3x^2+nx-4

If the zeros are 2 and -2, hence;

0 = 16m+16-12+2n-4
0 = 16m-16+12-2n-4

_______________
16m+2n = 0
16m - 2n = 8

Subtract

2n+2n = -8
4n = -8

n = -2

Substitute for "m'

16m + 2(-2) = 0
16m = 4

m = 1/4

Hence the values of m and n from the given equation are 1/4 and -2

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Maria spends ​$19 on lottery tickets every week and spends ​$122 per month on food.On an annual​ basis, the money spent on lottery tickets is ______% of the money spent to buy food.

Answers

The money spent on lottery tickets is 15.6% of the money spent to buy food.

How to determine the proportion?

The given parameters are:

Food = $122

Lottery = $19

The proportion of the lottery tickets is:

Proportion = Lottery/Food * 100%

This gives

Proportion = 19/122* 100%

Evaluate

Proportion = 15.6%

Hence, the money spent on lottery tickets is 15.6% of the money spent to buy food.

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What is the simplified value of the exponential expression​

Answers

the simplified value of the exponential expression is 1/9

The answer is 3.

Hope this helped :)

If n + 2, 5, and 9 represent the lengths of the sides of a triangle then < n

Answers

Answer:

n>2      (see below)

Step-by-step explanation:

Triangle side rule says    n+2   + 5   must be greater than 9

    n+2   +5  > 9

    n > 2      

      (but it must be less than 12   o/w   5 + 9 will not be greater than n+2)  

   

BRAINLIEST!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

Move all the points on the graph two points to the right

Step-by-step explanation:

f(x-2) is just a translation to the right by 2. The whole formula is typically y = a f(b(x + c)) + d. In this case, the C value is the one being changed and that indicates a translation left or right. -2 indicates 2 to the right.

Answer:

The Slope: 0

The y-intercept: (0,0_

x y

0 0

1 0 (there is supposed to be a line between the x and y that goes down all the way down the numbers but i cannot type that)

Step-by-step explanation:

Please help! Consider the following subset of the real number line. How can this set be expressed using inequalities?

Answers

Answer:

-2 ≤ x ≤10

Step-by-step explanation:

Notice that x can never be less than -2  and can never exceed.

-2 and 10 are all inclusive  thus the last answer is not correct as it tries to leave them out

A tennis ball can in the shape of a right circular cylinder holds four tennis balls snugly. If the radius of a tennis ball is 3.5 ​cm, what percentage of the can is not occupied by tennis​ balls?

Answers

Answer:

  about 33.3%

Step-by-step explanation:

The fraction of space not occupied will be the same as the unoccupied fraction of a cylinder of the same height and diameter as a sphere.

Volume of a cylinder

The volume of a cylinder of diameter d and height d will be ...

  V = πr²h = π(d/2)²(d) = (π/4)d³

Volume of a sphere

The volume of a sphere of diameter d is ...

  V = 4/3πr³ = 4/3π(d/2)³ = (π/6)d³

Unoccupied space

The fraction of space that is occupied is ...

  occupied space = (sphere volume)/(cylinder volume)

  occupied space = ((π/6)d³) / ((π/4)d³) = 4/6 = 2/3

The fraction of unoccupied space is ...

  unoccupied fraction = 1 -2/3 = 1/3

  unoccupied fraction ≈ 33.3%

Answer:

Putangina okay

Step-by-step explanation:

#CarryOnLearning

Translate and solve: the product of
p
and

2.5
is
4.8

Answers

Answer:

p = 7.3

Step-by-step explanation:

Equation: p - 2.5 = 4.8

add 2.5 to both sides:

P - 2.5 + 2.5 = 4.8 + 2.5


simplify

P = 7.3


hope that helps! :)

px2.5=4.8

Divide by 2.5 on both sides.

P=1.92

Hope this helped!

Which of the following are geometric sequences?
Check all that apply.
A. 5, 10, 15, 20, 25
B. 10, 5, 2.5, 1.25, 0.625, 0.3125
C. 1, 1, 2, 3, 5, 8, 13
D. -9, -3, -1, -1/3, -1/9, -1/27

Answers

Answer: B and D

Step-by-step explanation:

A is not, it's an arithmetic sequence where each term is +5 greater than the previous

B is because each term is 1/2 the previous term (common ratio of 1/2) thus making it a geometric sequence

C is not, it's the Fibonnaci sequence which is neither an arithmetic or geometric sequence

D is because each term is 1/3 the previous term (common ratio of 1/3) thus making it a geometric sequence

To raise funds for a new fire truck, a fire department is conducting a raffle. Residents can purchase a raffle ticket for $10.00 each. After writing his/her name on the ticket, the resident will place it in a container. Later on, a fire department official will randomly select one ticket from the container. The resident who purchased the selected ticket will win a prize of $2,000.00.

a. Suppose at the time of the drawing there are a total of 1000 purchased raffle tickets in the container. If a particular resident has purchased 10 tickets, what is his/her probability of winning the prize?

b. Compute the expected profit (winnings − cost) for a particular resident who purchased 10 raffle tickets.

c. After paying out the $2,000.00 prize, how much money has the fire department raised for its new fire truck? Other than the prize, ignore any other raffle costs incurred by the fire department.

Answers

a. The probability of winning the prize by the resident who purchased 10 tickets is 1% (10/1,000).

b. The expected profit (winnings - cost) for the resident who purchased 10 raffle tickets is $1,900 ($2,000 - $100).

c. The amount raised by the fire department after paying out the $2,000 prize (ignoring other raffle costs) is $8,000 ($10,000 - $2,000).

What is a raffle?

A raffle is a gambling competition or lottery organized to raise money for a purpose.

A raffle involves the sale of tickets which are drawn randomly to select some winners.

Data and Calculations:

Price of a raffle ticket = $10

Prize = $2,000

Cost of purchasing 10 tickets = $100 ($10 x 10)

Number of raffle tickets sold = 1,000

Total revenue realized = $10,000 ($10 x 1,000)

Thus, if a resident purchases 10 tickets, the chance of winning the raffle is 1%.

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I need help with this question please!!

Answers

Answer:

31465

Step-by-step explanation:

n!/((n-r)! r!)

= 31!/(31-4)! 4!

= 31!/ 27! 4!

= 31465

They work-infested $18,000 into accounts, one yielding 4% interest and the other yielding 12%. If he received a total of $1,280 and interest at the end of the year, how much did he invest at 4%?​

Answers

Answer:

$11,000

Step-by-step explanation:

Let amount invested for 12% yield be p . Amount for 4% yield is therefore (18000-p)

Interest for 12%: 12% of p=0.12p

Interest for 4%: 4% of (18000-p)=0.04(18000-p)=720-0.04p

Total interest:

=0.12p + (720-0.04p)

=0.12p-0.04p+720

=0.08p+720

But we already know the total interest is 1280

Therefore: 0.08p+720=1280

0.08p=1280-720

0.08p=560

p=560÷0.08

p=7000

Therefore at 4% the person invested:

(18000-p)

18000-7000

$11,000

c. Divide 45 into three parts which are in A.P. Such that the pr oduct of last two is 300.​

Answers

(a−b)+a+(a+b)=45

⟹3a=45

a=15

a(a+b)=300

⟹15(15+b)=300

⟹225+15b=300

⟹15b=300−225

⟹15b15=7515

b=5

a−b=10⟹a=15⟹a+b=20

The three numbers are 10, 15, and 20.

Proof:

10+15+20=45✓

A town has population of 5000 and grows at 3.5% every year. To the nearest tenth
of a year, how long will it be until the population will reach 7300?

Answers

It would take approximately 11 years for this population to reach 7300.

How to calculate the time?

Based on the information provided, the future size of the population can be modelled by using an exponential function:

F = Pe^rt

Substituting the given parameters into the formula, we have;

7300 = 5000e^{0.035 × t}

7300/5000 = e^{0.035t}

1.46 = e^{0.035t}

Taking the ln of both sides, we have:

ln(1.46) = ln(e^{0.035t})

0.378 = 0.035t

t = 0.378/0.035

Time, t = 10.8 11 years.

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can you please help me with this question? thanks!

Answers

Answer:

Step 2

Step-by-step explanation:

In step 1, Gary had the right idea of multiplying both sides by 4 to eliminate the denominator, but in step 2, Gary makes a mistake since e should equal 10 not 8. 2.5 * 4 = 10 not 8

Answer:

B) Step 2

Step-by-step explanation:

Gary's mistake occurs in Step 2. He was right to multiply both sides of the equation by 4 to find e, but his error is in the multiplication of 2.5*4. 2.5*4 = 10, not 8.

Sandy borrows $1250 from the bank. The loan terms is 18 months with 5% annual interest. How much interest will she pay? How much will she pay back in all?

Answers

Answer:

Step-by-step explanation:

1250x0.05x1.5=93.75

93.75 is the interest

1343.75 is the total ammount.

If the cost of milk is $3 per gallon, what is the amount of money a farmer can make by selling the milk produced by the cow in the month of April?

Answers

The amount of money a farmer can make by selling the milk produced by the cow in the month of April is $90

How to determine the amount

From the equation given, we have that

$3 = I gallon

Let's take it that the farmer sells one gallon by per day

We know that the month of April has 30 days

So if he makes $3 in 1 day

He would make x in 30 days

Collect like terms

$30 × 30 days = amount

Multiply through

Amount = $90

Thus, the amount of money a farmer can make by selling the milk produced by the cow in the month of April is $90

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Parentheses three times to parentheses divided by parentheses 5×4 parentheses

Answers

(3x2)/(5x4) = 6/20 = 3/10 or .3

Find f(x-4) if f(x)=-x+2. f(x-4)

Answers

Answer:

= -x+6

Step-by-step explanation:

we can simply substitute (x-4) in x place because when we say function of x , we are basically saying when we substitute a given value in the place of x we will find a given y.so for example if we have a question f(4), we can simply plug 4 to -x +2 so we will find y or f(x) = -2.

so the answer for the above question will be f(x)= -x +6.

Can someone please help me

Answers

Answer:

Number 4

Standard form - Not sure if right

y = − 0.2734375x^2 − 1.09375x +11.40625

Factored form - Not sure if right

y= 0.0390625 (−7x^2 −28x+292)

Number 5

Either form of the equation other than standard form

Vertex form : y = −(x +3)^2 + 25

Vertex of the parabola

(-3,25)

X and Y intercepts

x-intercept(s): (2,0) ,(−8,0)

y-intercept(s): (0,16)

What is the radius of a sphere that has a surface area of 2903.33 in²?

Answers

Answer:

15.2 in

Step-by-step explanation:

The surface area of a sphere is given by the formula below:

Surface area of sphere= 4πr², where r is the radius

Given that the surface area is 2903.33 in²,

2903.33= 4πr²

Divide both sides by 4π:

[tex] {r}^{2} = \frac{2903.33}{4\pi} [/tex]

Square root both sides:

[tex]r = \sqrt{ \frac{2903.33}{4\pi} } [/tex]

r= 15.2 in (3 s.f.)

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Problem
A [tex]prime\left trio[/tex] is a collection of three prime numbers [tex]\{p, q, r\}[/tex] in arithmetic progression, with common difference [tex]q-p=r-q[/tex]. For example, the prime trio [tex]\{3, 5, 7\}[/tex] has common difference 2.
Prove that there is no prime trio with common difference 70.
P.S. I want actual proof.

Answers

Answer:

Proof below

Step-by-step explanation:

General outlineLemma regarding remainders of non-small primes divided by 6Check [tex]p=2[/tex] and [tex]p=3[/tex] directlyProof the rest by contradiction

Lemma

If [tex]p[/tex] is prime such that [tex]p \neq2[/tex] and [tex]p \neq 3[/tex], then [tex]p[/tex] divided by 6 has remainder of 1 or 5.

Case 1: p/6 has remainder 0, 2, or 4.

Then there exists some natural number [tex]n[/tex] such that either [tex]p=6n[/tex], [tex]p=6n+2[/tex], or [tex]p=6n+4[/tex].  However,

if [tex]p=6n[/tex], then [tex]p=2*3n[/tex],if [tex]p=6n+2[/tex], then [tex]p=2*(3n+1)[/tex], and if [tex]p=6n+4[/tex], then [tex]p=2*(3n+2)[/tex].

By definition of divisibility, [tex]p[/tex] is divisible by 2.  Since [tex]p \neq2[/tex], [tex]p[/tex] cannot be prime.  This contradiction implies [tex]p[/tex] cannot have a remainder of 0, 2, or 4 when divided by 6.

Case 2: p/6 has remainder 3.

Then there exists some natural number [tex]n[/tex] such that [tex]p=6n+3[/tex].  However, if [tex]p=6n+3[/tex], then [tex]p=3*(2n+1)[/tex], so [tex]p[/tex] is divisible by 3.  Since [tex]p \neq 3[/tex], [tex]p[/tex] is not prime.  This contradiction implies [tex]p[/tex] cannot have a remainder of 3 when divided by 6.

Therefore, if [tex]p[/tex] is a prime number such that  [tex]p \neq2[/tex] and [tex]p \neq 3[/tex], then when divided by 6, [tex]p[/tex] must have a remainder of 1 or 5.

Main proof of no prime trio with common difference of 70.

Check p=2

Consider [tex]p=2[/tex].  Then [tex]q=2+70=72[/tex].  However, [tex]72=2*36[/tex], so [tex]q[/tex] is not prime.  Hence, [tex]p \neq2[/tex].

Check p=3

Consider [tex]p=3[/tex].  Then [tex]q=3+70=73[/tex], and [tex]r=73+70=143[/tex].  However, [tex]143=11*13[/tex], so [tex]r[/tex] is not prime.  Hence, [tex]p \neq 3[/tex].

So, thus far, we've proven that if there is a prime trio with a common difference of 70, that [tex]p \neq2[/tex] and [tex]p \neq 3[/tex].

Proof of the rest of primes by contradiction

By way of contradiction, assume that there does exist some prime trio [tex]\{ p,q,r \}[/tex] such that [tex]q-p=r-q=70[/tex], and [tex]p \neq2[/tex] and [tex]p \neq 3[/tex].

Then, by the Lemma proven earlier, when [tex]p[/tex] is divided by 6, it must have a remainder of 1 or 5.

Case 1: p/6 has remainder 5

Assume that [tex]p[/tex] has remainder 5 when divided by 6.  Then, there exists some natural number [tex]n[/tex], such that [tex]p=6n+5[/tex].  

[tex]q=p+70\\q=(6n+5)+70\\q=6n+75\\q=3*(2n+25)[/tex]

Since [tex]n[/tex] was a natural number, and the natural numbers are closed over multiplication and addition (meaning, multiplying and adding more natural numbers results in another natural number), then [tex]q[/tex] is divisible by 3.

Since [tex]p[/tex] is prime, [tex]0 < p[/tex], which implies [tex]0+70 < p+70[/tex]

Since [tex]q=p+70[/tex], [tex]70 < q[/tex], so [tex]q[/tex] cannot equal 3.  Since [tex]q[/tex] is divisible by 3, but [tex]q \neq 3[/tex], [tex]q[/tex] is not prime, which is a contradiction to the existence of this prime trio.

Therefore, either [tex]p[/tex] cannot have a remainder of 5 when divided by 6, or the prime trio does not exist.

Case 2: p/6 has remainder 1

Assume that [tex]p[/tex] has remainder 1 when divided by 6.  Then, there exists some natural number [tex]n[/tex], such that [tex]p=6n+1[/tex].  

[tex]q=p+70\\q=(6n+1)+70\\r=q+70\\r=((6n+1)+70)+70\\r=6n+141\\r=3*(2n+47)[/tex]

Since [tex]n[/tex] was a natural number, and the natural numbers are closed over multiplication and addition (meaning, multiplying and adding more natural numbers results in another natural number), [tex]r[/tex] is divisible by 3.

Since [tex]q[/tex] is prime, [tex]0 < q[/tex], implying [tex]0 +70 < q+70[/tex].

Since [tex]r=q+70[/tex], then [tex]70 < r[/tex].  Therefore, [tex]r\neq 3[/tex].

Since [tex]r[/tex] is divisible by 3, but [tex]r\neq 3[/tex], [tex]r[/tex] is not prime, which is a contradiction to the existence of this prime trio (with a common difference of 70).  Therefore, either [tex]p[/tex] cannot have a remainder of 1 when divided by 6, or the prime trio does not exist.

Since [tex]p[/tex] was prime, by our lemma [tex]p[/tex] must have either a remainder of 1 or 5.  Since both remainder possibilities resulted in a contradiction, our contradiction assumption is false, so there cannot exist a prime trio such that their common difference is 70.

What are the solutions of the equation x4 + 3x² + 2 = 0? Use u substitution to solve.
O x=+√√√2 and x = +1
Ox=ti√√2 and x = ti
Ox=± √√2 and x = ti
Ox=+√√2 and x = +1

Answers

Answer:

[tex]\pm i\sqrt{2}\text{ and } \pm i[/tex]

Step-by-step explanation:

[tex]\text{let u = } x^2[/tex] so then [tex]u^2=x^4[/tex].

This gives you the equation: [tex]u^2+3u+2=0[/tex].

Now factor the equation by looking for factors of 2 that add up to 3, which is just 2 and 1. Use these to rewrite the equation: [tex](u+2)(u+1)[/tex]. So now just set each factor equal to 0:

[tex]u+2=0\\u=-2[/tex]

Now substitute x^2 back in as u

[tex]x^2=-2[/tex]

Take the square root of both sides

[tex]x=\pm \sqrt{-2}[/tex]

Separate the radical into sqrt(-1) * sqrt(2)

[tex]x=\pm \sqrt{-1}*\sqrt{2}[/tex]

Rewrite using i

[tex]x=\pm i\sqrt{2}[/tex]

Now set the other factor equal to 0

[tex]u+1=0\\u=-1[/tex]

substitute x^2 back in as u

[tex]x^2=-1[/tex]

Take the square root of both sides

[tex]x=\pm\sqrt{-1}[/tex]

rewrite using i

[tex]x=\pm i[/tex]

Write the augmented matrix of the system of equations given below. (10 points)
−2 + 2 − = −13
−3 − + = 7
− + 3 − 2 = 0

Answers

The augmented matrix of the system of equations is [tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]

How to determine the augmented matrix?

The system of equations is given as:

-2x + 2y - z = 13

-3x - y + z = 7

-x + 3y - 2z = 0

Remove the variables x, y and z

-2      2    -1  13

-3    -1        1    7

-1     3      -2     0

Express as matrix

[tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]

Hence, the augmented matrix of the system of equations is [tex]\left[\begin{array}{ccc}-2&2&-1\\-3&-1&1\\-1&3&-2\end{array}\right] \left[\begin{array}{c}13&7\\0\end{array}\right][/tex]

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Complete question

Write the augmented matrix of the system of equations given below. (10 points)

-2x + 2y - z = 13

-3x - y + z = 7

-x + 3y - 2z = 0

Barn Yard Inc. is a wholesaler that stocks engine components and tests equipment for the commercial aircraft industry. A new customer has placed an order for eight high-bypass turbine engines, which increase fuel economy. The variable cost is $1.6 million per unit, and the credit price is $1.725 million each. Credit is extended for one period, and based on historical experience, payment for about one out of every 200 such orders is never collected. The required return is 1.8% per period.Suppose that customers who don’t default become repeat customers and place the same order every period forever. Further assume that repeat customers never default.

Answers

The NPV is positive, therefore, this order can be placed.

How to calculate the NPV?

The calculation of probability of default will be:

= 1 / 200 = 0.005

We use NPV formula to find out whether the order should be filled or not

NPV = -Variable cost per unit +[(1-π)(price of equipment/1+percentage of return)]

= -$1.6 million +[(1-0.005)($1.725m/1.018)]

= -$1.6m + $1.6860

= 0.0860 million

As NPV is positive this order can be placed.

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What’s one of the goals set out by the Healthy People 2010 program?:

a)

Ensuring that complaints against unfair billing are addressed

b)

Ensuring that private hospitals accept payment from any health insurance company

c)

Encouraging all employers to provide health insurance to their employees


d)

Eliminating the difference between the healthcare available to low and high income persons

Answers

Answer:

d i did the thing

Step-by-step explanation:

What will sue pay for 18 oranges if the cost 0.49 for 6 show the process

Answers

Answer:

[tex]\huge\boxed{\sf \$ \ 1.47}[/tex]

Step-by-step explanation:

Given that,

6 oranges = $0.49

Multiply 3 to both sides

6×3 oranges = $0.49 × 3

18 oranges = $1.47

[tex]\rule[226]{225}{2}[/tex]

Use the spinner to identify the probability to the nearest hundredth of the pointer landing on a non-shaded area

Answers

So when identifying the probability of a non-shaded area count all of the areas that are shaded and non-shaded.

In this instance it’s five so each individual section of being landed on is 20%

So there are three non-shaded areas out of five.

Use this fraction 3/5, and divide the nominator by a denominator which is 3 divided by 5.

3/5 = 0.6 or 60%

So the probability of landing on a non-shades are is 60%

Write this in logarithm form √x = y

Answers

The logarithmic form of √x = y is ㏒ₓy = 1/2

How to determine the logarithmic form

We have, logarithmic form as;

㏒ₓ n = bⁿ

Given √x = y

Convert the square root to power of 1/2 as that is what it represents, we get

x^1/2 = y

Then compare with the universal logarithmic form, we have

㏒ₓy = 1/2

Thus, the logarithmic form of √x = y is ㏒ₓy = 1/2

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Work out the reciprocal of 0.0005. Give your answer in standard form. 7 Work out the reciprocal of 0.0005 . Give your answer in standard form .​

Answers

Answer:

that's all I could do. hope it helps.

good day.

Other Questions
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