Answer: 6,277,647m
Explanation:
Radius of Earth = 6400km
To calculate the gravitational acceleration of a planet, we use the following formula:
g = mG/r^2
Gravitational acceleration is equal to the mass of the planet multiplied by the gravitational constant all divided by the radius of the planet squared.
We already know what the gravitational acceleration will be, 2.45m/s^2.
So, 2.45m/s^2 = mG/r^2
the mass of the earth is equal to 5.9*10^24.
And the gravitational constant is equal to 6.67408 * 10^-11.
We don't know the radius though.
2.45m/s^2 = 5.9*10^24 * 6.67408 * 10^-11 divided by r^2
2.45m/s^2 = 3.93 * 10^14 divide by r^2
Now, we can cross-multiply.
2.45m/s^2 * r^2 = 3.93 * 10^14
divide r^2 from both sides.
r^2 = 3.93 * 10^14 divided by 2.45m/s^2
r^2 = 1.6*10^14.
Now, take the square root of both sides.
r = 12,677,647 meters from the center of the Earth.
To calculate the height from the surface of the Earth, we need to subtract r by the Earth's radius.
That will be 12,677,647-6.400.000m = 6,277,647m from the surface of Earth.
an oculist charges 30 for an eye exam, frames and glasses lenses, but 42 for an eye examination, frames, and plastic lenses. If the plastic lenses cost four times as much as the glass lenses, how much do the glass lenses cost
Using algebra to solve for the the cost of the glass lenses gives the value for cost of glass lenses to be 4.
What is the cost of the glass lenses?The cost of the glass lenses is calculated as follows:
Let cost of glass be y
Cost of plastic lenses = 4y
Cost of eye exam and frames be z.
z + y = 30 (i)
z + 4y = 42 (ii)
(ii) - (i)
3y = 12
y = 4
Inconclusion, the cost of the glass lenses is 4.
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What force is acting on a 2 kg apple falling on the Earth (g = 10)?
A. 15 N
B. 4 N
C. 5 N
D. 20 N
Answer:
D. 20 N
Explanation:
Force = mass(m) × acceleration due to gravity (g)
Force = 2kg × 10m/s²
Force = 20N
What must change in order for electromagnetic induction to occur in a wire coil?.
Answer:
The magnetic field through the coil must change.
Explanation:
When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 35 cm . What is the second student's mass
Answer:
The mass of the second student is 60 kg.
Explanation:
Note: It is assumed that radius of piston is 0.23 m and density ρ is 850 kg/m^3 and mass of first student is 55 kg.
There occurs a change in pressure on a piston when some mass is added on the other piston.
This change of mass on the piston is given by the formula,
Δm=ρhA/g
where A is the area of piston.
Given h=35 cm or 0.35 m, change in mass is,
Δm=850*(0.35)*π*(0.23)^2 / 9.8
Δm=5.0 kg
Therefore, the mass of the second student is 55+5=60 Kg
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A person is using a rope to lower a 8.0-N bucket into a well with a constant speed of 2.0 m/s. What is the magnitude of the force exerted by the rope on the bucket
The magnitude of the force exerted by the rope on the bucket is 8N.
To find the answer, we need to know about the force.
What's force?According to Newton's second law, force is expressed as rate of change of momentum.It can be written as mass × acceleration.What's the force experienced by an object, when it moves with constant velocity?When an object moves with constant velocity, its acceleration is zero.Since acceleration is zero, so the force experienced by it is zero.Thus, we can conclude that there's no force on the bucket by the person as he is lowering it by constant velocity. But force on the bucket by the rope is 8N.
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Calculate the light intensity 1.51 m from a light bulb that emits 100 W of visible light, assuming that the light radiates uniformly in all directions.
Intensity of light emitting from the bulb is 3.5 watt/m².
To find the answer, we need to know about the intensity of the light.
What's the expression of intensity of light?Intensity of light= power/area
What's the intensity at 1.51 m away from a 100W light bulb?Light bulb emitis spherical waves of light. The area of the spherical wave front at 1.51m from the bulb = 4π(1.51)²= 28.65 m²Intensity= 100/28.65 = 3.5 watt/m²Thus, we can conclude that the intensity of light bulb at 1.51 m is 3.5 watt/m².
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meme on newtons law of motion (should me made ur self not from any searh engine)
What is the average velocity.
Answer:
0.10 m/s
Explanation:
The graph appears to be linear, so the velocity is constant and is represented by the slope of the graph. The slope can be calculating by taking any two points and inputting them into the equation: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] which is essentially rise/run. In this case the slope is really easy to calculate taking the two points of (0, 0) and (10, 1). In this case you can easily see the rise is 1 and the run is 10. So the slope is 1/10. So the average velocity of the object was 0.10 m/s or 1/10 m/s
A solid cylinder of mass 3.6 kg and radius 25 cm is rotating counterclockwise around a vertical axis running through the centers of its circular faces at 580 rev/min. A second solid cylinder of the same mass and radius is rotating clockwise around the same vertical axis running through the centers of its circular faces at 890 rev/min. If the cylinders couple so that they rotate about the same vertical axis, what is the angular velocity (in rev/min) of the combination?
A solid cylinder of mass (M=1 kg) and radius R=0.5 m is pivoted at its center The axis of rotation of the cylinder is horizontal. Three small particles of mass (m=0.1 kg) are mounted along its surface as shown in the figure. The system is initially at rest.
Solid cylinders need to be cut or split into small thin rings.
Each ring consists of a thickness dr of length L.
The moments of these thin cylindrical shells should be summed to infinitesimal.
Follow the instructions given.
1st place Use the general moment of inertia equation.
dI = r2 dm
Next, proceed to the dm determination. It is usually given as follows: To get
dm = ρdV
dm, you first need to calculate DV. It is given as follows:
dV = dA L
where dA is the area of the large ring (radius: r + dr) minus the small ring (radius: r). as a result;
Please check the attached file for ta detailed answer.
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Kendra lifts a box using a force of 80 N. She lifts the box a height of 0.5
meters in 2 seconds. How much work does she do on the box?
A. 80 J
B. 40 J
C. 160 J
D. 120 J
The work she on the box will be 40 J. Here the displacement due to the force is height.
What is work done?Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Given data;
Force,F = 80 N
height, h = 0.5 m
Work,W = ? J
Here the displacement is height;
W = F × d
W = F × h
W = 80 N × 0.5 m
W = 40 Nm
W=40 J
Hence work she on the box will be 40 J.
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A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1869 N to the right. What is the acceleration of the crate?
a=(6.0 or 6.00 or 8.10 or 8.1)=m/s^2
The acceleration of the steel crate, given the data from the question is 6.0 m/s²
How to determine the net forceForce to the left (Fբ) = 480 NForce to the right (Fᵣ) = 1869 NNet force (Fₙ) = ?Fₙ = Fᵣ - Fբ
Fₙ = 1869 - 480
Fₙ = 1389 N
How to determine the accelerationMass (m) = 230 KgNet force (Fₙ) = 1389 NAcceleration (a) = ?Fₙ = ma
Divide both sides by m
a = Fₙ / m
a = 1389 / 230
a = 6.0 m/s²
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The figure below shows a ball on a curved surface. The ball is released at point A. At which point does the ball have maximum gravitational potential energy?
Answer:
A
Explanation:
At point 'A' the ball is highest to the ground.As the formula of gravitational potential energy is Eg=MGH, in which 'M' is mass,'H' is height and 'G' is the gravitational pull of earth
Please. Physics is so difficult.
A pendulum on a grandfather clock is supposed to oscillate once every 2.00 s, but actually oscillates once every 1.99 s. How much must you increase its length to correct its period to 2.00 s?
Answer:
0.010 m
Explanation:
So the equation for a pendulum period is: [tex]y=2\pi\sqrt{\frac{L}{g}}[/tex] where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:
[tex]1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\[/tex]
Evaluate the multiplication in front
[tex]1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}[/tex]
Divide both sides by 6.28
[tex]0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}[/tex]
Square both sides
[tex]0.100 s^2= \frac{L}{9.8 m\backslash s^2}[/tex]
Multiply both sides by m/s^2 (the s^2 will cancel out)
[tex]0.984 m = L[/tex]
Now now let's find the length when it's two seconds
[tex]2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}[/tex]
Divide both sides by 6.28
[tex]0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}[/tex]
Square both sides
[tex]0.101 s^2 = \frac{L}{9.8 m\backslash s^2}[/tex]
Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)
[tex]0.994 m = L[/tex]
So to find the difference you simply subtract
0.984 - 0.994 = 0.010 m
the answer should be 0.00988 m
Which type of electromagnetic wave is used to transmit signals for
communication?
OA. X-rays
OB. Rdio
OC. Gamma rays
OD. Ultraviolet
Answer:
OB. Radio Waves
Explanation:
Radio Waves are wireless transmission of sound messages or info
The fact that some asteroids cluster in what are called asteroid families is probably the result of:
Answer:
The families are thought to form as a result of collisions between asteroids. In many or most cases the parent body was shattered, but there are also several families which resulted from a large cratering event which did not disrupt the parent body (e.g. the Vesta, Pallas, Hygiea, and Massalia families).
Explain E=mc2 in Short And Easy Definition
It means mass can be converted into energy.
I. E. In a nuclear fission, we start of with a greater mass of our rectant, which then decrease due to mass being converted into the (thermal) energy released, in our reaction. Later, being used to produce electricity, for example.
Hope this helps!
A 4.30 kg sign hangs from two wires. The
left wire exerts a 31.0 N force at 122°.
What is the magnitude of the force exerted
by the second wire?
F₁"
*W
magnitude (N)
F2
Enter
The magnitude of the force exerted by the second wire is 16.5 N.
Resultant of the forcesApply cosine rule to determine the force on the second wire;
W² = F₁² + F₂² - 2F₁F₂ cos(θ)
where;
W is the suspended weightθ is the angle between the two wires(4.3 x 9.8)² = 31² + F₂² - 2(31) F₂(cos 122)
1775.78 = 961 + F₂² + 32.85F₂
814.78 = F₂² + 32.85F₂
F₂² + 32.85F₂ - 814.78 = 0
Solve the quadratic equation using formula method;
F₂ = 16.5 N
Thus, the magnitude of the force exerted by the second wire is 16.5 N.
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factors that affect pressure in solids
Answer:
PRESSUREPressure is the force acting normally per unit area.
Pressure due to solids depends on the factors:Force.
Area.
This also proved by formula:
P=F/A.
Also pressure due to liquid depends on density ,gravity and height
A movement that keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement? Open kinetic chain movement Lateral kinetic chain movement Dynamic kinetic chain movement Closed kinetic chain movement
A movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.
What is a closed kinetic chain movement?A closed kinetic chain movement is defined as that position where the most distal aspects of a particular extremity are fixed to the earth or another solid object.
In conclusion; a movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.
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A sky diver, mass 90 kg, reaches a terminal velocity of 60 m/s. What is the approximate magnitude of the force of air resistance?.
The approximate magnitude of the force of air resistance is 882 N
Data obtained from the questionMass (m) = 90 KgTerminal velocity = 60 m/sForce (F) =?How to determine the forceThe magnitude of the force of air resistance can be obtained as illustrated below:
Mass (m) = 90 KgAcceleration due to gravity (g) = 9.8 m/s²Force (F) =?F = mg
F = 90 × 9.8
F = 882 N
Thus, approximate magnitude of the force of air resistance is 882 N
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An effective display of trend and magnitude is achieved by using a combination of a _____. Group of answer choices time series plot and sparklines line chart and trendlines heat map and sparklines bubble chart and trendlines
An effective display of trend and magnitude is achieved by using a combination of a C)heat map and sparklines.
While the standard chart is designed to expose as a great deal fact as possible and is set off from the float of text, sparklines are meant to be succinct, memorable, and located in which they are mentioned.
A heatmap (or warmness map) is a graphical illustration of facts wherein values are depicted through color. They are crucial in detecting what does or does not paintings on a website or product page.
A warmth map visualization is a mixture of nested, colored rectangles, each representing an attribute detail. Heat Maps are regularly used inside the monetary services industry to review the reputation of a portfolio.
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A 6.0 kg box is at rest on a table. The static friction coefficient μ, between the box and table is 0.40, and
the kinetic friction coefficient is 0.20. Then, a 30 N horizontal force is applied to the box.
What is the best estimate of the magnitude of the box's acceleration?
Answer:
3.038 m/s^2
Explanation:
What we have
m = 6.0 kg
[tex]\mu_{k}[/tex] = 0.20
[tex]\mu_{s}[/tex] = 0.40
[tex]F_{applied}[/tex] = 30 N
Since the situation is that the box has already been pushed, lets get the total net force of both components.
∑Fy = [tex]ma_{y}[/tex] = 0 (bc the normal and weight cancel out each other)
∑Fx = [tex]F_{applied}[/tex] - [tex]f_{k}[/tex] = [tex]ma_{x}[/tex] (We are going to use this equation to find acceleration)
To find the friction force
[tex]f_{k}[/tex] = [tex]\mu_{k}[/tex] * N
[tex]f_{k}[/tex] = .20 * 6.0 kg * 9.81 m/s^2 = 11.772 N
Now we can use ∑Fx equation to actually find the acceleration of the box!
∑Fx = [tex]F_{applied}[/tex] - [tex]f_{k}[/tex] = [tex]ma_{x}[/tex]
Plug it in
30 N - 11.772 N = 6 kg * a
Do the algebra...
a = [tex]\frac{30 N - 11.772 N}{6 kg}[/tex] = 3.038 m/s^2
A driver jumped from a top of a 15-meter-high cliff down to the water below. if he moved with an initial horizontal velocity of 10m/s
a.) Find his Vx or horizontal Velocity
b.) Calculate the time it took him to reach the water
c.) How many meters will his range or horizontal displacement
Given:
Formula:
Solution:
Final Answer:
.
Hi please help I need it bc I'm still confuse
(a) The initial horizontal velocity of the driver is 10 m/s.
(b) The time taken for him to reach the water is 1.75 s.
(c) The horizontal displacement is 17.5 m.
Horizontal velocity of the driver (Vx)
The initial horizontal velocity of the driver is given as 10 m/s.
Time of motion of the driverh = vy(t) + ¹/₂gt²
where;
vy is initial vertical velocityt is time of motionh is height of fallh = 0 + ¹/₂gt²
2h = gt²
t = √(2h/g)
t = √(2 x 15 / 9.8)
t = 1.75 s
Horizontal displacement of the driverX = Vx(t)
X = 10 x 1.75
X = 17.5 m
Thus, the initial horizontal velocity of the driver is 10 m/s, the time of motion is 1.75 s and the horizontal displacement is 17.5 m.
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A metal disk of radius 10 cm has a hole at a distance of 2.5 cm from the center. The size of the hole is 1 cm in diameter. If you heat the disk, what will happen to the size of the disk .
The size of the disc will Increase
The hole will enlarge in proportion to the metal if the disc is homogeneous and isotropic (the same in all directions). This is evident because, since the hole's edge is constructed of metal, the thermal expansion equation dL=LdT holds true for all lengths related to the metal, including the circle of the hole. Additionally, if the diameter of the hole increases, so does its circumference.
The analysis becomes more challenging if your disc has distinct areas formed of various metal kinds or if the metal that makes up your disc has an anisotropic crystal structure, meaning that it expands by different amounts in different directions. But given the total change in size is still an expansion, I believe the hole would become bigger in all scenarios.
Hence ,The size of the disc will Increase
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Which phenomena support only the wave theory of light? select 2 options. reflection refraction diffraction interference photoelectric effect
Interference and diffraction are the phenomena that support only the wave theory of light. Options 2 and 3 are correct.
What is the interference of waves?The result of two or more wave trains flowing in opposite directions on a crossing or coinciding pathways. This phenomenon is known as the interference of waves.
The phenomenon of interference occurs when two wave pulses are traveling along a string toward each other.
The light wave hypothesis states that light behaves like a wave. Since light is an electromagnetic wave, it may be transmitted without a physical medium.
Light has magnetic and electric fields, much like electromagnetic waves do.
Transverse waves, such as those seen in light waves, oscillate in the same direction as the wave's path. A wave of light may experience interference as well as diffraction as a result of these properties.
All of the remaining options are the light phenomenon.
Hence, options 2 and 3 are correct.
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Select the correct answer. You travel in a circle, whose circumference is 8 kilometers, at an average speed of 8 kilometers/hour. If you stop at the same point you started from, what is your average velocity? A. 0 kilometers/hour B. 2 kilometers/hour C. 4 kilometers/hour D. 8 kilometers/hour E. 16 kilometers/hour
Answer:
Since velocity is a vector quantity there is no net displacement and the average velocity is zero
(A) is correct
How do the accelerations of the rifle and bullet compare?
Answer:
The acceleration of the rifle equals the force that the bullet exerts on the rifle divided by the mass of the rifle. The two forces are equal, but since the mass of the rifle is much greater than the mass of the bullet, the acceleration of the rifle is much less than the bullet's acceleration.
For a pull box housing shielded conductors carrying over 1,000V and used in an angled pull, the distance between a conductor entry and exit must be________
Answer: For a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.
Explanation: To find the correct explanation to the question, we have to find more about the pull box housing shielded conductors.
What is pull box?Pull box is an underground electrical container, that made up of composite materials that used in traffic signal installation and also provide access to underground detectors as well as interconnected cables. These are used to simplify the wiring installation. What are the types of pull boxes?There we have two types of pull boxes, such as, one is for straight pulls and the other is for angle or U pulls.For straight pulls the length of the box shall not be less than 48 times the outside diameter of the cable.Angled pulls can be again classified as, Distance to opposite wall, Distance between entry and exit and removable sides.The distance between a conductor entry and exit from the box shall not be less than 36 times the outside diameter of the conductor.Thus, we can conclude that, for a pull box housing shielded conductors carrying over 1000V and used in an angled pull, the distance between a conductor entry and exit must be 36 times the outside diameter.
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How much work is done when a hoist lifts a 210-kg rock to a height of 3 m? (Use 9.8 m/s2 for the acceleration due to gravity.)
Work done to lift the rock is 6174 Joule.
To find the answer, we need to know about the work done.
What's the work done?Mathematically, work done = force × distance
What's the gravitational force acts on the stone here?The gravitational force on the stone = mg
= 210× 9.8= 2058N
What's the work done to lift the stone?Work done= 2058× 3
= 6174 Joule
Thus, we can conclude that the work done to lift the stone is 6174 Joule.
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A diver is standing on the diving board. The diver has a mass of 59 kg and has a gravitational potential energy of 832 J standing on the diving board.
Determine how high the diver is above the water surface. (Assume the water is at ground level.)
Answer:
1.44 m
Explanation:
Potential energy = mgh
832 = 59 * 9.81* h
h = 832/(59*9.81) = 1.44 m
The diver has a mass of 59 kg and a gravitational potential energy of 832 J standing on the diving board. 1.44 meters high, the diver is above the water's surface.
Utilizing mechanical energy conservation, we can estimate the diver's height above the water's surface. The diver has gravitational potential energy at the top of the diving board, which is transformed into kinetic energy when they jump and descend towards the ocean. Each and every ounce of potential energy is changed into kinetic energy at the water's surface.
Given:
Mass of the object (diver) = 59 kg
Acceleration due to gravity = 9.81 m/s²
The height can be computed as:
h = GPE / (m × g)
h = 832 J / (59 kg × 9.81 m/s²)
h = 1.44 meters
Hence, the diver has a mass of 59 kg and a gravitational potential energy of 832 J standing on the diving board. 1.44 meters high, the diver is above the water's surface.
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