Assuming an efficiency of 49.70%, calculate the actual yield of magnesium nitrate formed from 139.0 g of magnesium and excess copper(II) nitrate. Mg+Cu(NO3)2⟶Mg(NO3)2+Cu

Answer:

i

b because it says it in the question

The standard enthalpy of formation of substance in its standard state is zero.

Enthalpy is defined as a thermodynamic quantity that describes the energy of a system. For substances in their standard state, the enthalpy of formation is zero.

The standard state of a substance is defined as the state in which it is found under standard conditions.  The following substances has their standard ethalpy of formation as zero or not zero;

Zero enthalpy of formation           Non zero enthalpy of formation

Cl2(g)                                                     I2(s)

Br(g)                                                       Br2(l)

I2(g)                                                       Br2(s)

Hg(l)                                                       Hg(s)

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Answer:

The answer has to be A, greater force of attraction than the gas, only

Explanation:

I really hope this helps! Have a good day and good luck!

Answer:

W I think good luck I think

Answer: w

Explanation: potential energy is greater when higher from the ground. i took the test

Answer:

Explanation:

The liquid nitrogen and oxygen are then separated by fractional distillation . The liquefied air is passed into the bottom of a fractionating column. Just as in the columns used to separate oil fractions , the column is warmer at the bottom than it is at the top.

Answer:

Radiation therapy

Explanation:

I hope this helps

Crystallization, followed by filtration to remove excess solution, followed by drying on a watch glass or in a warm oven, can yield pure dry crystals of zinc chloride.

Crystallization is defined as the formation of a solid in which the atoms or molecules are highly organized into a structure known as a crystal.

It can also be defined as a natural process that occurs when materials solidify from a liquid or precipitate from a liquid or gas.

There are basically three types of crystallization.

Filtration is defined as the process of removing solid particles from a liquid or gaseous fluid by using a filter medium that allows the fluid to pass through but retains the solid particles.

Zinc oxide that could react with hydrochloric acid to give you the desirable product because acid is a neutralizing base, the reaction of hydrochloric acid with zinc oxide to form zinc chloride and water is a neutralization reaction .

Thus, crystallization, followed by filtration to remove excess solution, followed by drying on a watch glass or in a warm oven, can yield pure dry crystals of zinc chloride.

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Answer:

strawberry blueberry raspberry walang compound at element

[tex]\underline{\boxed{\bf 15.05\times 10^{22} molecules\: of\: Carbon}}[/tex]

[tex]\underline{\boxed{\bf 6.023\times 10^{23} molecules\:of\: Hydrogen}}[/tex]

Refer to the attachment for calculations

Answer:

The rice will move

Explanation:

the sound vibration and waves will cause the rice to move

Answer:

The rice will begin to move.

Explanation:

Answer:

CH4+3/2O2⇒CO2+2H2O

mCO2=2.8*44=123.2

Explanation:

The sum of the coefficients for all reactants and products is: 12.

Here, we first need to balance the equation of the reaction between Fe2S3(s) and H+.

The sum of the coefficients for all reactants and products is therefore;

Sum = 1 + 6 + 3 + 2.

Sum of coefficients = 12

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Answer:

Someone Said Telophase II. Ill update if its right or wrong when I finish.

Update : He is.... Wong. False.

Explanation:

The answer is Prophase I. It is not Telophase II.

Answer:

424 grams of sodium are contained in 4moles of na2co3

Answer:

C(s) + O2(g) --> CO2(g)

Explanation:

Answer:

True

Explanation:

Solid carbon and oxygen gas when mixed together reacts, and forms carbon dioxide gas.

Answer:

yes

Explanation:

it's easy

Answer:

Ga₂O

Explanation:

Phosphorous has 5 valence electrons and so gaining 3 electrons will make it isoelectronic with the stable noble gas argon, and will produce the P3- ion

Answer:

Approximately [tex]81.84\%[/tex].

Explanation:

Balanced equation for this reaction:

[tex]{\rm Na_{2}CO_{3}}\, (aq) + {\rm CaCl_{2}} \, (aq) \to 2\; {\rm NaCl}\, (aq) + {\rm CaCO_{3}}\, (s)[/tex].

Look up the relative atomic mass of elements in the limiting reactant, [tex]\rm CaCl_{2}[/tex], as well as those in the product of interest, [tex]\rm CaCO_{3}[/tex]:

Calculate the formula mass for both the limiting reactant and the product of interest:

[tex]\begin{aligned}& M({\rm CaCl_{2}}) \\ &= (40.078 + 2 \times 35.45)\; {\rm g \cdot mol^{-1}} \\ &= 110.978\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

[tex]\begin{aligned}& M({\rm CaCO_{3}}) \\ &= (40.078 + 12.011 + 3 \times 15.999)\; {\rm g \cdot mol^{-1}} \\ &= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the quantity of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) available to this reaction:

[tex]\begin{aligned}n({\rm CaCl_{2}) &= \frac{m({\rm {CaCl_{2}})}}{M({\rm CaCl_{2}})} \\ &= \frac{17.87\; \rm g}{110.978\; \rm g \cdot mol^{-1}} \\ &\approx 0.161023\; \rm mol \end{aligned}[/tex].

Refer to the balanced equation for this reaction. The coefficients of the limiting reactant ([tex]\rm CaCl_{2}[/tex]) and the product ([tex]{\rm CaCO_{3}}[/tex]) are both [tex]1[/tex]. Thus:

[tex]\displaystyle \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} = 1[/tex].

In other words, for every [tex]1\; \rm mol[/tex] of [tex]\rm CaCl_{2}[/tex] formula units that are consumed, [tex]1\; \rm mol\![/tex] of [tex]\rm CaCO_{3}[/tex] formula units would (in theory) be produced. Thus, calculate the theoretical yield of [tex]\rm CaCO_{3}\![/tex] in this experiment:

[tex]\begin{aligned} & n(\text{${\rm CaCO_{3}}$, theoretical}) \\ =\; & n({\rm CaCl_{2}}) \cdot \frac{n({\rm CaCO_{3}})}{n({\rm CaCl_{2}})} \\ \approx \; & 0.161023\; {\rm mol} \times 1 \\ =\; & 0.161023\; \rm mol\end{aligned}[/tex].

Calculate the theoretical yield of this experiment in terms of the mass of [tex]\rm CaCO_{3}[/tex] expected to be produced:

[tex]\begin{aligned} & m(\text{${\rm CaCO_{3}}$, theoretical}) \\ = \; & n(\text{${\rm CaCO_{3}}$, theoretical}) \cdot M(({\rm CaCO_{3}}) \\ \approx \; & 0.161023\; {\rm mol} \times 100.086\; {\rm g \cdot mol^{-1}} \\ \approx \; & 16.1161\; \rm g \end{aligned}[/tex].

Given that the actual yield in this question (in terms of the mass of [tex]\rm CaCO_{3}[/tex]) is [tex]13.19\; \rm g[/tex], calculate the percentage yield of this experiment:

[tex]\begin{aligned} & \text{percentage yield} \\ =\; & \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\% \\ \approx \; & \frac{13.19\; {\rm g}}{16.1161\; {\rm g}} \times 100\% \\ \approx \; & 81.84\%\end{aligned}[/tex].

Answer:

but where is yr question????

Answer:

Where is your question bro

i hope this calculation will help you  

The sodium ion concentration in the solution of 17.5 mL of 0.1050 M Na₂CO₃ and 46.0 mL of 0.1250 M NaCl is 0.148 M.

To find the Na⁺ concentration in the final solution, we need to find the number of moles of the ion in the Na₂CO₃ and NaCl solutions and the volume of the final solution.  

[tex] C_{Na^{+}} = \frac{n_{t}}{V_{t}} [/tex]  (1)

Where:

[tex] n_{t} [/tex]: is the total number of moles of Na⁺

[tex] V_{t} [/tex]: is the volume of the final solution

The number of moles of Na₂CO₃ can be calculated as follows:

[tex] n_{Na_{2}CO_{3}} = C_{Na_{2}CO_{3}}*V_{Na_{2}CO_{3}} [/tex]

Where:

[tex] C_{Na_{2}CO_{3}} [/tex]: is the concentration = 0.1050 mol/L

[tex] V_{Na_{2}CO_{3}} [/tex]: is the volume = 17.5 mL = 0.0175 L

[tex] n_{Na_{2}CO_{3}} = 0.1050 mol/L*0.0175 L = 1.84 \cdot 10^{-3} \:moles [/tex]

We can find the number of moles of Na⁺ knowing that in 1 mol of Na₂CO₃ we have 2 moles of Na⁺.

[tex] n_{Na^{+}} = \frac{2 \:mol\: Na^{+}}{1\:mol \:Na_{2}CO_{3}}*mol \:Na_{2}CO_{3} = \frac{2 \:mol\: Na^{+}}{1\:mol \:Na_{2}CO_{3}}*1.84 \cdot 10^{-3} \:moles = 3.68 \cdot 10^{-3} \:moles [/tex]

The number of moles of Na⁺ in the NaCl solution is:

[tex] n_{NaCl} = C_{NaCl}*V_{NaCl} = 0.1250 mol/L*0.046 L = 5.75 \cdot 10^{-3} \:moles [/tex]

In 1 mol of NaCl we have 1 mol of Na⁺, so the number of moles of Na⁺ in the NaCl solution is 5.75x10⁻³ moles.

The total number of moles of Na⁺ in the final solution can be calculated as follows

[tex] n_{t} = n_{{Na^{+}}_{Na_{2}CO_{3}}} + n_{{Na^{+}}_{NaCl}} = 3.68 \cdot 10^{-3} \:moles + 5.75 \cdot 10^{-3} \:moles = 9.43 \cdot 10^{-3} moles [/tex]

Hence, the number of moles of Na⁺ in the final solution is 9.43x10⁻³ moles.

The volume of the final solution is given by:

[tex] V_{t} = V_{Na_{2}CO_{3}} + V_{NaCl} = 0.0175 L + 0.046 L = 0.0635 L [/tex]

The concentration of Na⁺ in the final solution is (eq 1):

[tex] C_{Na^{+}} = \frac{n_{t}}{V_{t}} = \frac{9.43 \cdot 10^{-3} moles}{0.0635 L} = 0.148 mol/L [/tex]

Therefore, the concentration of sodium ions in the final solution is 0.148 M.

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Symbol: O

Name: Oxygen

as number of protons + number of neutrons = atomic mass

8+8=16

The element is Oxygen (O) in the given element model.

The atomic number of an element is equal to the number of protons in its nucleus. Since the element in question has 8 protons, its atomic number is 8. Oxygen has an atomic number of 8, making it the element with 8 protons. Additionally, the atomic number determines the identity of an element; no other element has 8 protons in its nucleus.

The element's name is Oxygen, and its chemical symbol is O. Oxygen is a vital element in the Earth's atmosphere and is essential for supporting life. It is commonly found in the form of diatomic molecules (O2), which make up a significant portion of the air we breathe. Oxygen plays a crucial role in various biochemical and chemical processes, and its presence is essential for the respiration of most living organisms.

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A detail report is very important for better decisions of President about economy.

It is very important to have such a detailed report on the economy because it helps the president as well as Congress to make better decisions about the imposing of taxes. It greatly helps and provides all information to the president and Congress so that they make better decisions about taxes and expenditures.

Without this detailed report, the Congress can't take right decisions about taxes and economy of the country so we can conclude that detail report is very important for better decisions of president about economy.

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Answer:

should be earthquake

Explanation:

Answer:

spring and summer

Explanation:

Answer:

summer and spring

Explanation:

Answer:

i think it might be a giant astroid came and killed everything  sorry if im wrong

Explanation:

Explanation:

at the Anode, Oxide ions lose electrons and produce Oxygen gas

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