The net work done on the cart is 1.17 J.
The average net force on the cart is 1.65 N.
The work done by frictional force over the same distance is 0.078 J.
What is net work done on the cart?The net work done on the cart is calculated by applying the principle of conservation of energy as follows;
W = ΔK.E
W = ¹/₂m(v² - u²)
where;
v is the final velocity of the caru is the initial velocity of the cartm is mass of the cartW = ¹/₂(0.53)(2.1² - 0²)
W = 1.17 J
The average net force on the cart is calculated as follows;
W = Fd
where;
F is the net forced is the displacement of the cartF = W/d
F = (1.17) / (0.71)
F = 1.65 N
The work done by frictional force over the same distance is calculated as follows;
W = fd
W = 0.11 x 0.71
W = 0.078 J
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PLEASE HELP QUICKLY
Félix baumgartner jumps out of a hot air balloon at a height of 39km. He wears a special suit and his total mass is 120kg. He was the first person to break sound barrier( at a velocity of 343m/s). Calculate how far in km he had fallen to break the sound barrier
The distance in Km he has fallen to break the sound barrier is 6 Km
To obtain the answer to the question, we'll beging by calculating the time taken to break the sound barrier. This can be obtained as follow:
Initial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) = 343Time (t) = ?v = u + gt
343 = 0 + (9.8 × t)
343 = 0 + 9.8t
343 = 9.8t
Divide both sides by 9.8
t = 343 / 9.8
t = 35 s
How to determine the heightFinally, we can obtain the height as follow:
Time (t) = 35 sAcceleration due to gravity (g) = 9.8 m/s²Height (h) =?h = ½gt²
h = ½ × 9.8 × 35²
h = 4.9 × 1225
h = 6002.5
Divide by 1000 to express in Km
h = 6002.5 / 1000
h = 6 Km
Thus, Félix baumgartner broke the sound barrier when he had fallen 6 Km
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Hydraulic systems utilize Bernoulli’s principle. T. F.
its FALSE
The answer is true, that the hydraulic press utilizes Bernoulli's principle.
It can be derived from the Principle of conservation of energy.
What is Bernoulli's Principle?According to Bernoulli's principle, which governs fluid dynamics, a fluid's speed increases concurrently with a reduction in pressure or potential energy. The mathematical concept is named after Swiss mathematician Daniel Bernoulli, who first published it in his book Hydrodynamics in 1738.
The venturi tube is a real-world example of Bernoulli's Principle in action. The venturi tube has an air intake that constricts to a throat and an exit segment that widens as it moves backward. The entrance and outflow both have the same diameter.
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Calculate the braking distance force for a driver of a 1200kg car traveling at an initial speed of 10m/s above with a braking force of -8000N
The braking distance of the driver of a 1200 kg car traveling at an initial speed of 10m/s is 7.5 m
How to determine the distanceWe'll begin by obtainig the acceleration of the car. This can be obtained as follow:
Mass (m) = 1200 KgForce (F) = -8000 NAcceleration (a) =?Force = mass × acceleration
-8000 = 1200 × a
Divide both sides by 1200
a = -8000 / 1200
a = -6.67 m/s²
Finally, we shall determine the distance. Details below
Initial velocity (u) = 10 m/sFinal velocity (v) = 0 m/s (at maximum height)Acceleration(a) = -6.67 m/s²Distance (s) =?v² = u² + 2as
0² = 10² + (2 × -6.67 × s)
0 = 100 - 13.34s
Collect like terms
0 - 100 = -13.34s
-100 = -13.34s
Divide both side by -13.34
s = -100 / -13.34
s = 7.5 m
From the above calculation, we conclude that the breaking distance is 7.5 m
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The components of a 15 meters per second velocity at an angle of 60 above the horizontal are
The components of a 15 meters per second velocity at an angle of 60 above the horizontal are 13.05 m / s and 0.435 m / s
Resolving the velocity into its horizontal and vertical components, it makes a right angled triangle.
Hypotenuse = V = 15 m / s
θ = 60°
Opposite side = components = [tex]V_{y}[/tex]
Adjacent side = Horizontal component = [tex]V_{x}[/tex]
In a right angled triangle,
sin θ = Opposite side / Hypotenuse
cos θ = Adjacent side / Hypotenuse
sin 60° = [tex]V_{y}[/tex] / V
[tex]V_{y}[/tex] = 15 * 0.87
[tex]V_{y}[/tex] = 13.05 m / s
cos 60° = [tex]V_{x}[/tex] / V
[tex]V_{x}[/tex] = 0.5 * 0.87
[tex]V_{x}[/tex] = 0.435 m / s
Therefore,
The horizontal component, [tex]V_{x}[/tex] = 0.435 m / sThe vertical component, [tex]V_{y}[/tex] = 13.05 m / s.To know more about components of velocity
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Which one is the answer
The graph that shows the relationship between the speed and the kinetic energy is option B.
What is the relationship between kinetic energy and speed?Recall that the kinetic energy is referred to as the speed that a body possess by virtue of its motion. Thus an object that is in motion is said to posses the kinetic energy. The kinetic energy is the energy of an object that has a velocity
The kinetic energy is linearly related to the speed of the object. This implies that the speed is directly proportional to the kinetic energy of the object. If there is a direct relationship, it the follows that the graph of the speed against the kinetic energy of the object ought to be a straight line graph.
As such, the relationship between the kinetic energy and the speed of the object can be seen from the image in option B.
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A group of students must design an egg-carrying device that will prevent a raw egg from breaking when it is dropped from a two-story
window The diagram shows one group's design. How does the parachute help to minimize the force on the egg upon impact with the
ground?
(Figure 1) is the potential-energy diagram for a 500 g
particle that is released from rest at A. What is the particles speed at B?
The particles speed at B is 12 m/s .
What are kinetic and potential energy?Potential energy is the energy that is held in reserve in any system or object as a result of how its components are positioned or assembled. The external environment, such as air or height, is not a factor in this, though. The energy that an object or a system's particles have while in motion, however, is known as kinetic energy. An item or particle's motion gives it kinetic energy, which it might use to move. An item accelerates and gains kinetic energy when work, which transfers energy, is done on it by exerting a net force. Potential energy is a form of stored energy that is dependent on the arrangement of a system's components. In a compressed state, a spring has higher potential energy.
The mass of the particle = 500g
= 0.5 kg
The energy of the particle when it is released
E = 5g
The potential energy at B
= 2 J
Loss in potential energy = gain in kinetic energy.
K.E.= 1/2 × m × v²
Here after putting values we get
speed at B = 12m/s.
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module 2 question 3
You drive 5.00 km in a straight line in a direction 20° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.
The distance to drive East is 1.7 km and the distance you would have to drive North is 4.7 km
The North-East, East and North travel distances from a right angled triangle. So trigonometric ratios are applicable.
sin θ = East distance / NE distance
sin 20° = East distance / 5
East distance = 1.7 km
cos θ = North distance / NE distance
cos 20° = North distance / 5
North distance = 4.7 km
Some of the basic trigonometric ratios are:
sin θ = Opposite side / Hypotenusecos θ = Adjacent side / Hypotenusetan θ = Opposite side/ Adjacent sideTherefore, the distance to drive East is 1.7 km and the distance to drive North is 4.7 km
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the angular velocity of a rotating rigid body is -4+j-2k.find the linear velocity if a point p(5,1,3) on the body relative to a point Q(3,4,2) on the axis of rotation
The linear velocity of a point p(5,1,3) on the body relative to a point Q(3,4,2) on the axis of rotation is 17.13 m/s.
What is linear velocity?
Linear velocity is defined as the rate of change of displacement with respect to time when the object moves along a straight path.
The relationship between linear velocity and angular velocity is given as;
v = ωr
where;
ω is angular speed of the objectr is the radius of the circular pathv is the linear speed of the objectThe magnitude of the radius is calculated as follows;
r = √[(5-3)² + (1-4)² + (3-2)²]
r = 3.74 m
The magnitude of the angular speed is calculated as;
ω = √[(-4)² + (1)² + (-2)²]
ω = 4.58 rad/s
The linear speed of the object is calculated as follows;
v = ωr
v = (4.58 rad/s) x (3.74 m)
v = 17.13 m/s
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A vehicle of mass 1,084 kg is traveling in the +y-direction along a straight, horizontal road at a speed of 18.2 m/s when the driver applies the brakes, stopping the car in a distance of 244 m. Find the y-component of the constant net force applied to the car to bring it to a stop.
[Note: Remember that vector components can be positive or negative.]
The y-component of the constant net force applied to the car to bring it to a stop is mathematically given as
F_y =666.38N
This is further explained below.
What is force?Generally, In the field of physics, an influence that may alter the motion of an object is referred to as a force.
An object having mass may experience a change in its velocity, often known as acceleration, when subjected to a force.
Intuitively, force may also be conceptualized as either a push or a pull. Because it may be measured in both magnitude and direction, a force is considered a vector quantity.
When considering coplanar force of a point or a body we tend to consider the x components and the y components of force as they come together to give the Net Force or the resultant for and directions of force.
But for this case we shall strictly consider the y company of force as it pertains to this body and its force independent of the x components force as regards to Resultant force
In conclusion,
v^2 =2 a s
[tex]a &=\frac{v^2}{25}=\frac{(18.4)^2}{2 \times 268} \\\\[/tex]
a =0.631ms^2
F_y =m a
F_y=1055* 0.631
F_y =666.38N
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14. A 5.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball
How fast does the ball need to be moving in order to send the man off at a speed of
3.00 m/s?
Answer:
V₁ = 48 m/s
Explanation:
Using the Conservative Law of Momentum:
∑Qₓ = 0
Q₁ + Q₂ = 0
Q₁ = Q₂ (In absolute values)
Where:
Q₁: right before the impact
Q₂: right after the impact
So:
Q₁ = Q₂
m₁*V₁ + m₂*V₂ = m₁*V + m₂*V (Because both ball and man moves together)
5 * V₁ + 75 * 0 = (5 + 75)*3
5V₁ = 80 * 3
V₁ = 240/5
V₁ = 48 m/s
A hydraulic lift is used to lift a car. The small piston has a radius of 5 cm and the large piston has a radius of 50 cm. If a driver applies a force of 88 N to the small piston, what is the weight of the car the large piston can support?
Answer:
F = 880 N
Explanation:
Apply Pascal's Principle.
f / a = F / A
Because the pressure (P = F/A) is equal on both sides of the piston.
So, using the International System of Units:
f / a = F / A
88 / 0.05 = F / 0.50
F = (88/0.05) * 0.50
F = 880 N
calculate the current that flows through a 60W bulb if the voltage across is 230V
The current flow through a 60W bulb if the voltage across is 230V is 0.26 A.
P = V I
P = Power
V = Voltage
I = Current
P = 60 W
V = 230 V
I = P / V
I = 60 / 230
I = 0.26 A
Ohm's law states that if the temperature across a conductor remains the constant, the ratio of potential difference across the conductor to the current flowing in the conductor will also be constant.
Therefore, the current flow through a 60W bulb if the voltage across is 230V is 0.26 A.
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Figure 3 shows a 40 kg crate that is being pushed with constant velocity at a distance 8.0 m along a 30° incline plane by the horizontal force of 500N. The coefficient of kinetic friction between the crate and the incline, µk is 0.42. Assuming the crate is moving upwards towards the right, calculate the work done by the applied force, the frictional force and the gravitational force and the net work done on the crate.
Based on the given figure, you have that the components of the forces on the direction of the incline are:
applied force:
Fa = 500N*cos(-30°) = 433.01N
friction force:
Fr = µk*N = µk*m*g*cos(30°) = (0.42)(40kg)(9.8 m/s^2)cos(30°) = 142.58N
gravitational force:
Fg = m*g*sin(30°) = (40kg)(9.8)sin(30°) = 196.0N
Next, consider that the work done by a force is equal to the product of the force and the distance at which the force is applied. In this case, such distance is 8m.
Then, you have:
Work done by the applied force:
WFa = (433.01N)(8.0m) = 3464.08 J
Work done by the friction force:
WFr = (142.58N)(8.0m) = 1140.64 J
Work done by the gravitational force:
WFg = (196.0N)(8.0m) = 1568.0 J
Finally, the net work, based on the direction of the forces, is:
Net work = WFa - WFr - WFg = 3464.08J - 1140.64J - 1568.0J = 755.44J
Hence, the net work is 755.44 J
Answer: Wfr = -1883.25 J
Explanation:
1) In the x direction (direction of motion of the crate):
Fcos(30^o) - f_fr - mgsin(30^o ) = 0 (because a_x = 0)
f_fr = Fcos(30^o ) - mgsin(30^o)
f_fr = (498)(√3/2) - (40)(9.81) (1/2) = 235.28 N
⇒ W_fr = f_fr.s.cos(180^o) = -(235.28)(8.0) = -1882.25 J (1)
2) In the y direction (perpendicular to the motion of the crate):
n - Fsin(30^o) - mgcos(30^o) = 0 (because a_y = 0)
⇒ n = Fsin(30^o) + mgcos(30^o) = (498)(1/2) + (40)(9.81)(√3/2) = 588.83 N
⇒ f_fr = μ_k.n = (0.40)(588.83) = 235.53 N
⇒ W_fr = f_fr.s.cos(180^o ) = -(235.53)(8.0) = -1884.24 J (2)
Average of calculations (1) & (2): W_fr = -1883.25 J
A ball is thrown vertically upward with a speed of
25.0 m/s from a height of 2.0 m.
a. How high does the ball rise?
b. How long does it take to reach its highest point?
c. How long does the ball take to hit the ground
after it reaches its highest point?
d. What is the ball's velocity when it returns to
the level from which it started?
a.) the ball rises to a height of 31.88m
b.) It takes the ball 2.55 seconds to reach its highest point
c.) It takes the ball 2.55 seconds to hit the ground
d.) The ball's velocity is -24.99 m/s in the negative direction which is downwards.
What is velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
From the given question, we have that
b.) At highest point velocity of the ball will become zero so v=0m/s.
So using equation
v = u + gt
0 = 25 - 9.8t
t = 25/9.8 s =2.551 s
Time taken by the ball to reach its highest point will be 2.551 seconds .
a.) The height the ball rises is given by
v²-u²=2gh
=> 0-(25.0)²=-2*9.8*h
=> 19.6h= (25.0)²
=> h= 31.88m.
c.) It will take the ball 2.55 seconds to hit the ground
after it reaches its highest point because it will take the ball same time for the ball to reach its highest point or fall to the ground.
d.) velocity = u - gt
V = 0 - 9.8 * 2.55
V= -24.99 m/s in the negative direction which is downwards.
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A 227.1 g sample of water at 12.2°C is heated to steam at 115.6°C. How much heat was absorbed?
??? kcal
According to the given statement the heat absorbed is 43676.78 J .
How do you calculate heat absorbed?The water's specific heat and the formula Q= mcΔT are used to compute the amount of heat absorbed. At 100°C, water vaporizes into steam. Calculating the amount of heat absorbed requires multiplying the number of moles of water by the molar heat of vaporization.
Briefing:Mass, m = 227.1grams
To find how much heat is absorbed when 227.1 grams of steam is heated from 115.6°C to 12.2°C.
Heat absorbed is given by :
Q= mcΔT
c is specific heat of water
Put all the values, we get :
Q = 227.1 * 1.86 * (115.6 - 12.2)
Q = 43676.78 J
43676.78 J heat is absorbed.
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Three forces act on a moving object. One force has a magnitude of 84.4 N and is directed due north. Another has a magnitude of 42.7 N
and is directed due west. What must be (a) the magnitude and (b) the direction of the third force, such that the object continues to
move with a constant velocity? Express your answer as a positive angle south of east.
The direction of the third force, such that the object continues to
move with a constant velocity is 94.5N at 0.19° south of east.
What is applied force?The force that one thing exerts on another. A barrel being pushed by a human is an illustration of applied force. When the individual pushes the barrel, the barrel experiences an applied force. Newton's second law of motion defines the force formula as follows: A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force. a push or pull that an object has experienced. Here, an object is given a force by a person or any other thing. A chair being pushed to the opposite side of the room, for instance.
For the object to move with constant velocity the total acceleration must be zero.
So,
Total F = [tex]F_{1} +F_{2} +F_{3}[/tex]
ma = 0
[tex]F_{1}[/tex] = 84.4N
[tex]F_{2}[/tex] = 42.7 N
[tex]F_{3} = -F_{1} - F_{2}[/tex]
= 94.58 N
TanФ = 0.19°
Hence [tex]F_{3}[/tex] = 94.5N at 0.19° south of east.
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When light falls on a soap bubble or on the oily film spread on a water puddle, a spectrum of colors is observed. How is this spectrum of colors formed?1) separation of white light by a prism2) absorption of colors in a pigment present3) constructive and destructive interference of light waves4) reflection of light by soap bubble or oil film
When the light falls on a soap bubble spread on a water puddle, and a spectrum of color is observed due to constructive and destructive of light waves which means option (3) is correct. Light waves interfere into each other to produce a spectrum which consists of bright and dark fringes.
Problem 7(a) Two different heavy objects are dropped from the same height. State
a) the acceleration of free fall of each object.
b) State any assumptions made.
The acceleration of free fall of each object will be the same.
An assumption made is that both objects must be on Earth.
What is acceleration of free fall?
The acceleration of free fall of every object is the acceleration experienced by the freely falling object as a result of the effect of gravitation of earth alone.
Mathematically, the formula for acceleration of free fall of every object on earth is given as;
g = GM/R²
where;
G is universal gravitation constantM is mass of the objectR is radius of the objectg is acceleration due to gravityThe value of acceleration due to gravity on Earth is 9.8 m/s².
Since both objects are dropped from same height on Earth, they will experience equal acceleration of free fall.
The assumptions made are;
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what is friction with its SI unit
When two surface attach each other a force is produced called friction. It's SI unit is newton
Jerry is unable to pick up the picnic
basket, then he eats spinach and
becomes stronger. Now he can easily lift
up the basket.
This is an example of F=ma
because.
This is an example of F = ma because the net force applied is directly proportional to the weight (mass) of the basket.
What is Newton's Second Law of Motion?Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.
Mathematically, Newton's Second Law of Motion is given by this expression;
F = ma
Where:
F represents the net force.m represents the mass of a physical object.a represents the acceleration of a physical object.In conclusion, the above scenario is an example of the demonstration of Newton's Second Law of Motion.
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What is a 65 kg
k
g
rider's apparent weight as the ride is coming to rest?
The weight of the rider will remain the same that is 65 kg after the ride is finished because the weight does not depend on speed.
What is Weight?It gauges how much gravity is pulling on a body.
Weight being a force, the SI unit of weight is the Newton, which is also the same as the SI unit of force (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change from one location to another, the acceleration caused by gravity does.
According to the question, the weight will remain same because weight depends on mass and gravity but not the speed. As per the definition of weight it is the product of mass and gravity, it means for different plants the weight will be different but for the same planet the weight will be the same everywhere.
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Every second, the Sun converts 4 million tons of matter to energy. How long will it take the Sun to reduce its mass by 1% (the mass of the Sun is 2×10^30kg)? Compare your answer with the lifetime of the Sun so far.
I need this as soon as possible thanks.
Answer:
That is human_scale thinking and understanding
Explanation..
If you are going to consider stars(sun's), then you have to thik on a more cosmological scale stars are prodigiously immense which means they can burn 4 million tons of their fuel per second and not even realize it.
Consider this_if the life of our sun is of the order of 8 billion years, then it takes two billion years to bum only a quit of its fuel.
The universe is a very large place and if you are going to understand it, you have to think large.
Which of the following describes how deforestation impacts the climate in areas where trees once stood?The elimination of a protective covering causes the sun to dry out the ground.The lack of carbon in the atmosphere causes radical temperature fluctuations.The decrease in plants to absorb water causes a greater level of water precipitation.The change in covered areas causes winds to be stronger and colder weather results.
Take into accouint that the regions that suffer deforestation tend to generate soil erosion to eventually become non-productive land.
Then, from the given choices you have that deforestation impacts in the following way:
The elimination of a protective covering causes the sun to dry out the ground.
calculate the net force acting on the box in the following. refer to the screenshot below.
The net force acting on the box is 5N , and it is unbalanced.
since the forces acting on the system is 7N and 2N which is opposite direction.
Explanation:The sum of all forces acting on an object is known as net force. Newton's second law, which states that F = ma, where F is the net force, can be used to calculate the net force. m is the object's mass. a represents acceleration.When two forces act in the same direction on an object, the net force equals the sum of the two forces.In general, when opposing forces act on an object, such as the book on the table, the net force equals the difference between the two forces. In other words, the net force is calculated by subtracting one force from the other. The net force is zero if the opposing forces are equal or balanced.
here given two forces ,
f1 = 7N
f2 = 2N
since both forces are in opposite direction ,
Net force = f1 - f2
= 7N - 2N
= 5N
so the net force that act on the given box is 5N and unbalanced .
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Atwood machine question: details are in photos attached
First, let's calculate the forces in the 3 kg mass:
[tex]W_1-T=m_1\cdot a[/tex]Then, the forces in the 2 kg mass:
[tex]T-W_2=m_2\cdot a[/tex]From the first equation, let's solve it for T:
[tex]T=W_1-m_1a[/tex]Using this value of T in the second equation, we have:
[tex]\begin{gathered} W_1-m_1a-W_2=m_2\cdot a \\ W_1-W_2=m_2a+m_1a \\ m_1g-m_2g=a\cdot(m_1+m_2)_{} \\ a=g\frac{(m_1-m_2)}{(m_1+m_2)} \end{gathered}[/tex]Finally, using the given values (with g = 10 m/s²), we have:
[tex]a=10\cdot\frac{(3-2)}{(3+2)}=10\cdot\frac{1}{5}=2\text{ m/s2}[/tex]If the acceleration is 2 m/s², after 2 seconds the speed is:
[tex]\begin{gathered} V=V_0+a\cdot t \\ V=0+2\cdot2 \\ V=4\text{ m/s} \end{gathered}[/tex]Therefore the correct option is the second one.
pls help me with my question
In astronomy, luminosity is the power (amount of energy per unit of time) emitted in all directions by a celestial body. It is directly related to the absolute magnitude of the star. The luminosity of the Sun, L☉ is the classical unit used in astronomy to compare the luminosity of other stars. Its approximate value is:
[tex]L=3.827\times10^{26}W[/tex]From the options, the correct one is:
A. Sun
D-A6 kg cart moving at 2 m/s hits another car that has a mass of 3 kg. What is the velocity of the second car after impact?(Use the conservation of momentum equation)
The conservation of momentum states that the total intiial momentum is equal to the total final momentum. In this cae this will mean that:
[tex]p_{1i}+p_{2i}=p_{1f}+p_{2f}[/tex]A hot air balloon with a mass of 371 kg is flying 615 m above the ground. How much gravitational potential energy does the balloon have?
The formula for determining the gravitational potential energy of the balloon is expressed as
Energy = mgh
where
m is the mass of the ballon
g is the accelaration due to gravity and the value is 9.8m/s^2
h is the height of the balloon above the ground
From the information given,
m = 371
h = 615
Thus,
= 371 x 89.8 x615 = 22316017 NKJoulesJoules8298.651
What helped Northwest Coast tribes develop complex societies? Choose three correct answers.
having to travel to search for resources
being able to plant and harvest crops
having an abundant supply of fish
being able to save and store food
having a wealth of resources
The development of complex societies depends of the Northwest Coast tribes on;
having a wealth of resourceshaving an abundant supply of fishbeing able to plant and harvest cropsWhat are complex societies?The term society just has to do with people that are found to live around a give geographical area. This is the way the people tend to live along with the civilization that they may tend to have actually created over a long period of time as we can see.
Having said thus, the people of the are the people that there originally found around the west of which the original native Americans also formed a huge part of. These were the people that tend to be found around the Americas before the onset of modern civilization as we can se.
The factors that helped Northwest Coast tribes develop complex societies are found in the section above. These factors saw to the development of the region.
Learn more about complex societies:https://brainly.com/question/9321341
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