ASAP please

The sequence of transformations that can be performed on quadrilateral ABCD to show that it is congruent to quadrilateral GHIJ is followed by a--------------.

The distance between points M and N according to the task content is; 9.8 meters.

From observation of the task content information; it can be deduced for a fact that the line segment MN which joins points M and N is parallel to the line JK. This follows from the fact that M and N are midpoints KL and JL respectively.

Hence, it follows that triangles NLM and JLK are congruent and by the ratio of corresponding sides equality;

NM/19.6 = 7.4/(2×7.4)

NM = 19.6/2 = 9.8 meters.

This follows from congruence theorems in which case, the ratio of corresponding sides of congruent triangles are equal.

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Answer: 9.8 meters

Step-by-step explanation:  Trust Me!! I got the answer correct on Edge.

Q:  What is the distance between points M and N?

A:  9.8 meters  

Inequalities help us to compare two unequal expressions. The algebraic expression for fifteen more than n is at least 48 is n+15 ≥ 48; n≥33. Thus, the correct option is C.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The given statement "fifteen more than n is at least 48" can be written in the form of an algebraic expression as,

n+15 ≥ 48

Solving the inequality,

n ≥ 48 - 15

n  ≥ 33

Hence, the algebraic expression for fifteen more than n is at least 48 is n+15 ≥ 48; n≥33. Thus, the correct option is C.

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The graph which is the best interpretation of the table given is; On a coordinate plane, the x-axis is labeled Quantity and the y-axis is labeled price. Points are at (1, 2), (2, 3.5), (3, 5), (4, 6.5), (5, 8), (6, 9).

The table given in the task content is a tabular representation of the quantity and the corresponding prices. On this note, plotting the quantity on the x-axis and the price on the y-intercept with the point descriptions above best represents the graph of the table.

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Answer:

The short answer to my well taught friend, is A

The statement (A) As x approaches negative infinity, f(x) approaches infinity. As x approaches infinity, f(x) approaches infinity is correct.

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]

We have a polynomial function:

[tex]\rm f(x) = x^{3}+2x^{2}-5x-6[/tex]

The function is a cubic function and the graph of the cubic function will be a curve.

As we can see in the graph, f(x) grows larger as x approaches negative infinity. f(x) also becomes closer to infinity as x does.

Thus, the statement (A) As x approaches negative infinity, f(x) approaches infinity. As x approaches infinity, f(x) approaches infinity is correct.

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Answer: -23

Step-by-step explanation:

-5-2x-2y

-5-2(3)-2(6)

-5-6-12 = -23

Answ

Step-by-step explanation:

By using the concept of circumference and all known inputs, we conclude that an arc length of 23 and a radius of 15 is equal to 23/15 radians.

According to the statement, arc length (s) and radius (r) are given:

s = 23, r = 15

The central angle (θ), in radians, is determine by dividing the former by the latter:

θ = s/r

θ = 23/15 rad

By using the concept of circumference and all known inputs, we conclude that an arc length of 23 and a radius of 15 is equal to 23/15 radians.

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Drawing a scatter plot for the given values on a graphing calculator, we have;

The values are;

Day; Running time

1; 8.2

2; 8.1

3; 7.5

4; 7.8

5; 7.4

6; 7.2

7; 7.1

Entering the above values in a graphing calculator, we have;

Therefore;

0 = -8.36 + y-intercept

The equation found using the statistics function for scatter plot on a calculator is therefore;

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Answer:

  y = 1/4x +2

Step-by-step explanation:

The slope-intercept form of the equation for a line can be found by solving the given equation for y. It can be written directly from the slope and the y-intercept.

It is helpful to simplify the equation first, then isolate the y-variable by eliminating non-y terms from that side of the equation.

  y -4 = (1/4)(x -8) . . . . . . . given

  y -4 = (1/4)x -2 . . . . . . . . eliminate parentheses

  y = 1/4x +2 . . . . . . . . . . add 4. This is the desired form

Alternatively, you can use the given information to write the slope-intercept equation directly. The slope in the point-slope form is the multiplier outside parentheses. In y-4 = 1/4(x -8), the slope is 1/4.

The y-intercept is the point where the line crosses the y-axis. Its coordinates always have an x-coordinate of 0. That is, the given point (0, 2) tells you the y-intercept is 2.

Using the slope and intercept in the slope-intercept form, you get the equation you're looking for:

  y = mx +b . . . . . line with slope m and y-intercept b

  y = 1/4x +2 . . . . . line with slope 1/4 and y-intercept 2

2) [tex]\overline{AE} \cong \overline{EC}[/tex] (a segment bisector splits a segment into two congruent parts)

3) [tex]\overline{BE} \cong \overline{ED}[/tex] (a segment bisector splits a segment into two congruent parts)

4) [tex]\angle AEB \cong \angle CED[/tex] (vertical angles are congruent)

5) [tex]\triangle BEA \cong \triangle DEC[/tex] (SAS)

6) [tex]\angle EBA \cong \angle EDC[/tex] (CPCTC)

7) [tex]\overline{AB} \parallel \overline{CD}[/tex] (converse of alternate interior angles theorem)

8) [tex]\angle BEC \cong \angle AED[/tex] (vertical angles are congruent)

9) [tex]\triangle BEC \cong \triangle DEA[/tex] (SAS)

10) [tex]\angle ECB \cong \angle EAD[/tex] (CPCTC)

11) [tex]\overline{BC} \parallel \overline{AD}[/tex] (converse of alternate interior angles theorem)

The information about SAS Congruence is illustrated below.

The complete information wasn't found. Therefore, an overview will be given. SAS congruence simply means that two triangles are congruent.

This implies that the sides of the triangles are equal. The rule states that if two sides and the angles if one triangle are equal to two sides and included in another triangle, then the triangles are congruent.

For example, given AC = PQ, BC = RQ and angle C = angle P. Then according to SAS, ABC = QRP.

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(4x + 5)(3x + 10) or 12x² + 55x +50

Forming the Expression for the Area of Rectangle

The formula for the area of a rectangle is given as,

Area, A = length × breadth

Here, the dimensions of the rectangle are given as,

length = (4x + 5)

breadth = (3x + 10)

∴ The equation for the area of the rectangle is,

A = (4x + 5)(3x + 10)

A = 12x² + 55x +50

Hence, 12x² + 55x +50 is the required expression.

Degree and Classification of the Expression

The highest power of a variable that is present in an expression is known as its degree.

Since the degree of the expression formed in part a is 2, it is classified to be a quadratic expression.

Closure Property For Polynomials

When the output is the same kind of object as the inputs, an expression is said to be closed. The expression obtained for the area of the rectangle is a combination of constants and variables closed under multiplication and addition.

Hence the expression formed in part a indicates at the closure property for polynomials.

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Mark the point on the coordinate system and draw the polygon (attachment).

This is the trapezoid.

The formula of an area of a trapezoid:

[tex]A=\dfrac{a+b}{2}\cdot h[/tex]

a, b - the lengths of the parallel sides

h - the height

Substitute:

[tex]a=9,\ b=7,\ h=8\\\\A=\dfrac{9+7}{2}\cdot8=\dfrac{16}{2}\cdot8=8\cdot8=64[u^2][/tex]

[tex]\huge\boxed{A=64u^2}[/tex]

The smallest possible area of the new rectangle is 52 square units.

In the question, we are given that a rectangle has side lengths of integral value.

We assume the lengths to be x and y units respectively, such that x and y are integers.

In the new arrangement, one pair is increased by 30%, and the other pair is decreased by 20%, such that the new sides are also integers.

We assume a 30% increase in x.

New side = x + 30% of x = x + 30/100 of x = x + 3x/10 = 13x/10.

For this to be an integer, x needs to be a multiple of 10.

Since we are considering the smallest area, we will consider the smallest multiple of 10, that is, 10 itself.

Hence, side 1 = 13 units.

We assume a 20% decrease in y.

New side = y - 20% of y = y - 20/100 of y = y - y/5 = 4x/5.

For this to be an integer, y needs to be a multiple of 5.

Since we are considering the smallest area, we will consider the smallest multiple of 5, that is, 5 itself.

Hence, side 2 = 4 units.

Now, the area of this rectangle is the product of its sides = 13*4 sq. units = 52 sq. units.

Therefore, the smallest possible area of the new rectangle is 52 square units.

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Answer:

<CBA

Step-by-step explanation:

<CBA = 90 degrees (given)

<ADB = 90 degrees (given)

Hence They are congruent, so choose A

From the diagram below, we can tell that < ADB is congruent to <CBA.

Here, we have,

given that,

from, the given diagram, we get,

both the triangles ABD and BCA are right angle triangle.

here, we have,

angle D = 90

and angle B = 90

so, we have,

<CBA = 90 degrees (given)

<ADB = 90 degrees (given)

Hence They are congruent, so choose A.

From the diagram below, we can tell that < ADB is congruent to <CBA.

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Answer:

x ≈ 6.5 , y ≈ 12.1

Step-by-step explanation:

(2x)² + (10.2)² = (16.5)²

4x² = 272.25 - 104.04

x² = 168.21 ÷ 4

x = √(42.0525) ≈ 6.5

y² = 42.0525 + 104.04 = 146.0925

y = √(146.0925) ≈ 12.1

Your question is incomplete. Please read below to find the complete questin.

B. Sampling error is the inevitable result of running statistical inference on a random sample rather than on an entire population.

A sampling mistake is a statistical blunder that occurs when an analyst does now not pick out a sample that represents the entire population of records. As a result, the outcomes found in the pattern no longer constitute the outcomes that would be received from the entire population.

Sampling error takes place when a sample is chosen from the incorrect populace statistics. Non-reaction errors occur when a user reaction is not received from the surveys. it can happen because of the incapacity to contact capability respondents or their refusal to respond.

The maximum generally used measure of sampling errors is referred to as the same old errors (SE). the standard error is a measure of the spread of estimates across the "true fee". In exercise, only one estimate is available, so the same old blunders can not be calculated at once.

What is the inevitable result of running statistical inference on a random sample rather than on an entire population?

A. Standard deviation

B. Sampling error

C. Sampling distribution

D. Stratified sampling

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The ordered pair that can be removed so that the resulting graph represents a function is (1, 3) or (1, -2)

The ordered pairs are given as:

(-5, -3), (-4, -4), (-2, 2), (1, 3), (1, -2), (2, 1), (5, -4)

For a set of ordered pairs to represent a function, each x value must point to exactly one y value

From the above ordered pairs, we have:

(1, 3) and (1, -2)

The x value 1 has y values 3 and -2

When one of these pairs is removed, the graph becomes a function

Hence, the ordered pair that can be removed so that the resulting graph represents a function is (1, 3) or (1, -2)

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[tex] \: \: \: \: \: \: \: \: \: \: \: \large\underline{\bf{ANSWER}}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: [/tex]

[tex] \tt↠(y^2+6)(−2y^2+7)[/tex]

[tex]\tt↠(-2y^2+7)y^2+6(-2y^2+7)[/tex]

[tex]\tt↠-2y^4+7y^2+6(−2y^2+7)[/tex]

[tex]\tt↠-2y^4+7y^2-12y^2+42[/tex]

[tex]\tt↠-2y^4-5y²+42[/tex]

Answer:

-2y⁴ - 5y² + 42

Step-by-step explanation:

[tex](y^2 + 6)(-2y^2 + 7)[/tex]

[tex]\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd[/tex]

Here First terms are
[tex]y^2 \textrm{ and } -2y^2\\(y^2)(-2y^2) = -2y^4[/tex]

Outer terms are y² and 7 ==>  (y²)(7) = 7y²

Inner terms are 6 and -2y² ==> 6(-2y²) = -12y²

Last terms are 6 and 7 ==> 6.7 = 42

So result is obtained by adding all these terms

-2y⁴ + 7y² - 12² + 42 ==> -2y⁴ - 5y² + 42

Answer:

8125 x 10^-3

= 8.125

8125 g

= 8.125 kg

Step-by-step explanation:

First, note that g is the same as grams and kg is the same as kilograms. Thus, when you are asking to convert 8125 g to kg, you are asking to convert 8125 grams to kilograms.

A gram is smaller than a kilogram. Simply put, g is smaller than kg. In fact, a gram is "10 to the power of -3" smaller than a kilogram.

Since a gram is 10^-3 smaller than a kilogram, it means that the conversion factor for g to kg is 10^-3. Therefore, you can multiply 8125 g by 10^-3 to get 8125 g converted to kg.

Here is the answer with the math showing you how to convert 8125 g to kg by multiplying 8125 by the conversion factor of 10^-3.

Answer:

8.125kg and 8125g

Step-by-step explanation:

1kg=1000g

Answer: 4x-1

Step-by-step explanation:

[tex](f+g)(x)\\\\=f(x)+g(x)\\\\=3x-2+x+1\\\\=\boxed{4x-1}[/tex]

The length of QJ is 4√20 units if the QJ = 4×PQ after using the intersecting chords theorem.

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

By intersecting chords theorem:

QM×QL = QJ×PQ

10×8 = QJ(QJ/4)

4×80 = QJ²

QJ = 4√20 units

Thus, the length of QJ is 4√20 units if the QJ = 4×PQ after using the intersecting chords theorem.

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Answer:

Step-by-step explanation:

Step-by-step explanation:

[tex] = \sqrt{48} [/tex]

[tex] = \sqrt{16 \times 3} [/tex]

[tex] = \sqrt{ {4}^{2} \times 3 } [/tex]

[tex] = \sqrt{ {4}^{2} } \times \sqrt{3} [/tex]

[tex] = 4 \times \sqrt{3} [/tex]

[tex] = 4 \sqrt{3} [/tex]

The answer is B.

The confidence interval for the mean noise at locations is (127.09,148.51).

Given noise levels at 5 airports=152,154,139,124,120

We have to find the confidence interval for the mean noise and sample mean of the data. We know that mean is the sum divided by the number of items taken.

Mean = sum of X values/n

=137.8 (calculated in figure)

s=[tex]\sqrt{(x-x bar)^{2} /n-1}[/tex]

=[tex]\sqrt{972.8/4}[/tex]

=[tex]\sqrt{243.2}[/tex]

=15.59

t value at 80% confidence level with degree of freedom 4  (5-1) is 1.533.

standard error=t value*s/[tex]\sqrt{n}[/tex]

=1.533*15.59/[tex]\sqrt{5}[/tex]

=10.71

Upper level= Mean + standard error

=137.8+10.71

=148.51

Lower level=Mean - standard error

=137.8-10.71

=127.09

Hence the confidence interval for the true mean noise is (127.09,148.51) and sample mean is 137.8.

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[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Solving for your equation:}[/tex]

[tex]\mathbf{|4x^2| - 3x - (9 - |-3x|)}[/tex]

[tex]\mathbf{= |(4)(9)|-(2)(-3)-(9-|(-3)(-3)|)}[/tex]

[tex]\mathsf{= |36| - (2)(-3)- (9 - |(-3)(-3)|)}[/tex]

[tex]\mathbf{=36 - (2)(-3) - (9 - |(-3)(-3)|)}[/tex]

[tex]\mathbf{= 36 -(-6) - (9 - |(-3)(-3)|)}[/tex]

[tex]\mathbf{= 42 - (9 - |(-3)(-3)|)}[/tex]

[tex]\mathbf{= 42 - (9 - |9|)}[/tex]

[tex]\mathbf{= 42 - (9 - 9)}[/tex]

[tex]\mathbf{= 42 - (0)}[/tex]

[tex]\mathbf{= 42 - 0}[/tex]

[tex]\mathbf{= 42}[/tex]

[tex]\huge\textbf{Notice that your equation kept getting}\\\huge\textbf{getting smaller and smaller?}\\\\\\\huge\textbf{That's because we kept solving as we got}\\\huge\textbf{closer to your result and we got there}\\\huge\textbf{sooner than we thought :)}[/tex]

[tex]\huge\textsf{ANYWAY!}[/tex]

[tex]\huge\textsf{Therefore, the answer is: \boxed{\mathsf{Option\ D. 42}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

1

Step-by-step explanation:

Just  '1'  

Answer:

D. 0≤y≤5

Step-by-step explanation:

The range refers to how far on the y axis a function exists on a graph. This function starts at y=0 and ends at y=5, meaning you can find a point on the function for any  y-level between 0 and 5. So y is greater than or equal to 0, and is less than or equal to 5.

A: A function with a range of all real numbers goes both up and down infinitely, however this function does not go up and down infinitely so we can rule out A.

B: If y>0, the function would start above y-level 0 and go up infinitely, however this graph does not display that so we can rule out B as well.

C: C is the domain of the graph, which is how far left and right the function exists.