As the effective nuclear charge increases, electron affinity generally increases.
What is the relationship between electron affinity and effective nuclear charge?Electron affinity increases to the right, while EI increases to the right and upwards. Thus, the general trend of electronegativity is to grow to the right and upwards. The further to the right, the greater the effective nuclear charge and the greater the atom's ability to pull electrons toward it.
In this case, we can say that as the effective nuclear charge increases, electron affinity generally increases.
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word equation into balanced formula equation and also mention the types of reaction sodium➕chlorinesodium chloride
Answer:
it's
answer
is
chlorinesodium gives sodium a different texture
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1.What is the specific heat capacity of granite when 20 kg absorbs 237 000 J of heat energy, causing its temperature to increase by 15 °C? (you are finding c)
Given :
Amount = 20 kgHeat energy absorbed = 237,000 JTemperature change = 15 °CFormula applied :
[tex]\boxed {Q = mc \triangle T}[/tex]
Q = absorbed heatm = massc = specific heat capacityΔT = temperature changeLet's solve for c !
⇒ 237,000 = 20 × c × 15
⇒ c = 237,000 ÷ 300
⇒ [tex]\boxed {c = 790 J kg^{-1} K^{-1}}[/tex]
∴ The specific heat capacity of granite is 790 J kg⁻¹ K⁻¹.
write differences between homogeneous mixture and heterogeneous mixture
Answer:
Homo means same
Hetero means different.
Homogeneous mixtures have one phase, it all looks the same, Fruit juice is homogeneous, solutions are homogeneous.
Heterogeneous mixtures have different phases, you can see the different parts, pepper is an example of a heterogeneous mixture.
A homogeneous mixture - Think Kool Aid (Completely Dissolved)A heterogeneous mixture - Like pepper poured into a glass of milk.In a homogeneous mixture the constituents are able to dissolve in each other due to their similar intermolecular forces, whereas in a heterogeneous mixture the constituents are not miscible- meaning they can't dissolve in each other.
To clarify: intermolecular forces describe the way that types of molecules will interact with each other. For instance, water (a polar molecule) and naphthalene (a non-polar molecule) are said to be "immiscible" because their intermolecular forces do not match. The saying goes: "like dissolves like". Meaning that molecules that have similar IFs will be mutually soluble (miscible, in other words).
Homogenous means the same all over...every cubic millimeter is about the same as every other one. Like water or soda.Heterogenous means difference in places, like salsa, with slightly different chunks of stuff depending on where you dipped your chip.Identify the Bronsted-Lowry base:
the numbers are subscripts.
Group of answer choices
a)KOH
b)BF3
c)KCl
d)Her
Answer:
Bronsted-Lowry's base is A)KOH
KOH
KOH on dissolving in water gives two ions K+ and OH-OH- can accept one H+As it accepts proton it acts as bronsted Lowry baseScience is divided in various fields of study except:
Science is divided into various fields of study except for pseudoscience which is not based on the scientific method.
What is science?Science refers to the total body of knowledge obtained by applying the scientific method.
Science can be divided into physical sciences, mathematics, life sciences, and social sciences.
In conclusion, science is divided into various fields of study except for pseudoscience which is not based on the scientific method.
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How many moles of ammonia are in 0.40 l of a 6.00 m ammonia solution?
if this solution were diluted to 1.00 l, what would be the molarity of the resulting solution?
Moles of ammonia is 2.4 moles
Molarity of solution after dilution is 2.4 M
Given:
volume of ammonia solution = 0.40 l
molarity of solution = 6.00 m
To Find:
moles of ammonia
Solution:
1 molar (M) solution will contain 1.0 GMW of a substance dissolved in water to make 1 liter of final solution
M = n / V
M is the molality of the solution that is to be calculated
n is the number of moles of the solute
V is the volume of solution given in terms of litres
n = M x V
= 6 x 0.4
= 2.4 moles
So moles of ammonia are 2.4 moles
molarity of the resulting solution after dilution
M = n/V
= 2.4/1
= 2.4 M
So Molarity after dilution will be 2.4 M
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A gas at 300 k and 4.0 atm is moved to a new location with a temperature of 250 k. the volume changes from 5.5 l to 2.0 l. what is the pressure of the gas at the new location? use the formula: p1v1 t1 = p2v2 t2
Answer:
9.17 atm
Explanation:
To find the new pressure of the gas, you need to use the following manipulated formula:
P₁V₁ / T₁ = P₂V₂ / T₂
In this formula,
P₁ = initial pressure (atm) P₂ = new pressure (atm)
V₁ = initial volume (L) V₂ = new volume (L)
T₁ = initial temperature (K) T₂ = new temperature (K)
Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.
P₁ = 4.0 atm P₂ = ? atm
V₁ = 5.5 L V₂ = 2.0 L
T₁ = 300 K T₂ = 250 K
P₁V₁ / T₁ = P₂V₂ / T₂ <----- Given formula
(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K) <----- Insert variables
0.073333 = P₂(2.0 L) / (250 K) <----- Simplify left side
18.33333 = P₂(2.0 L) <----- Multiply both sides by 250
9.17 = P₂ <----- Divide both sides by 2.0
Answer:
=> 13.2 atm
Explanation:
From the question, we have question we have been provided with pressure, volume and temperature. Based on these variables, we are supposed to use the combined gas law formula (P1V1T1 = P2V2T2)
At location 1;
P1 = 4.0 atm
V1 = 5.5 L
T1 = 300 K.
At location 2;
P2 = ?
V2 = 2.0 L
T2 = 250 K.
We are required to determine the pressure (P2).
To begin, we make pressure (P2) the subject of in the formula:
P2 = (P1V1T1)/(V2T2) ................ eq. (i)
Then substitute the known values into the eq. (i).
P2 = (4.0 x 5.5 x 300)/(2.0 x 250) atm
= 13.2 atm.
Therefore, the pressure (P2) at location 2 is 13.2 atm.
enna took an open bowl of leftover mashed potatoes from the refrigerator and noticed a difference in smell. She determined that chemical changes occurred since the potatoes were first placed there.
Which observations most likely led to Jenna’s conclusion?
a change of odor
a decrease in temperature
a change in moisture content
a decrease in mass
How can the arrangement of furniture in a room influence an individual’s behavior?
a.
The arrangement of furniture in a public room can either encourage or discourage social interaction.
b.
The arrangement of furniture in a room can influence an individual’s attitude toward survival.
c.
An individual’s overall mental health can be severely negatively impacted by the arrangement of furniture in a room.
d.
An individual’s behavior cannot be influenced by the arrangement of furniture in a room.
Please select the best answer from the choices provided
The arrangement of furniture in a public room can either encourage or discourage social interaction. The correct option is A.
What is social interaction?It is the process of exchanging information with others, verbally or otherwise.
The arrangement of furniture in a room filled with people can go a long way to encourage or discourage social interactions.
If physical barriers are put in between two seats such that people can barely see each other, the message may be that very little to no social interaction is allowed.
Without any physical barriers between seats, the message may be that people are free to interact, all other things being equal.
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Will a real gas ever reach absolute zero? Will an ideal gas ever reach absolute zero? Why or why not? Compose a report that answers these two questions. 125 words.
It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high.
What is the absolute zero?The absolute zero is the temperature at which the movement of all the gas molecules is theoretically believed to cease. At the absolute zero, gas molecules remain at fixed positions because according to the third law of thermodynamics, the entropy of a perfectly ordered system is zero.
It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high such that it is impractical to attain the absolute zero.
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3.03 Plate Tectonics
Objective(s):
In your own words, what was the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name
Boundary Type
(C=Convergent, D=Divergent, or T=Transform)
Year Observed
(5, 10, or 20 million years)
Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas
5
Event 1-
20
Event 2-
Location Two
East Africa
5
Event 1-
10
Event 2-
20
Event 3-
Location Three
San Andreas fault zone
5
Event 1-
10
Event 2-
20
Event 3-
Location Four
Aleutian Islands
5
Event 1-
20
Event 2-
Location Five
Mid-Atlantic Ridge
5
Event 1-
10
Event 2-
20
Event 3-
Location Six
Alpine Fault
5
Event 1-
20
Event 2-
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
What types of geological events or changes occur at divergent plate boundaries?
What types of geological events or changes occur at convergent plate boundaries?
What types of geological events or changes occur at transform plate boundaries?
Explain how these geological processes and interactions have changed Earth's surface through the years. Be sure to use evidence to support your answer.
The types of geological events or changes that occur at divergent plate boundaries are earthquakes and magma because there is a fault when two plates move away from each other.
The types of geological events or changes that occur at convergent plate boundaries are earthquakes, volcanoes, and the formation of mountains because the tectonic plates are moving towards each other.
The types of geological events or changes that occur at transform plate boundaries are shallow earthquakes, lateral displacement of rock, and a broad zone of crustal deformation.
These geological processes have changed the surface of the earth as they have helped to form ocean basins, and mountain chains, and the formation of glaciers and volcanoes, and earthquakes have changed the underground geology of the earth.
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Samples of this drawing medium have been dated back to 30,000 BCE. Group of answer choices silverpoint charcoal pencil color pencil pastel
Charcoal is the sample of this drawing medium have been dated back to 30,000 BCE and is denoted as option B.
What is Charcoal?This is referred to a black carbon residue which is heated in insufficient oxygen to give it a light weight.
It is used for drawing and has been in existence for as long as 30,000 BCE hence the reason why it is the most appropriate choice.
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a. The dissociation constant of the weak acid HF is K₂ = [H][F]. If at equilibrium
Ka
[HF]
the concentrations of H* and F are each 2.6 x 10-3 M and the concentration of
HF is 0.010 M, what is K₂ for HF? (3 points)
Answer:
6.76*10^-4 , or 6.8*10^-4 if you consider sig figs
Explanation:
This is a bit of a confusing question, since it incorrectly states that the acid disassociation constant is simply [H+][F-].
Ka = [H+][F-]/[HF] , so plugging in the values, we get
[tex]K=\frac{[2.6*10^{-3}][2.6*10^{-3}]}{[0.01]}\\K=\frac{[2.6*10^{-3}]^2}{[0.01]}\\K=0.000676=6.76*10^{-4}[/tex]
If we were to use the equation in the question, Ka=[H+][F-], we would get the answer 6.76 * 10^-6 , which is not the Ka for HF
Please helpppp!!!!!!!
Answer:
NaCl + H²O
Double replacement
Answer:
HCL + NAOH ------ Nacl + h2o here double displacement reaction takes place Na displaces h from its salt solution and form a bond with cl to make Nacl. the remaining H and OH forms a bond as h+ and oh- gives H2o( water) na+ and cl- as NaclIn forming a molecular compound, each atom should have ______ electrons around it unless there is some specific reasons why this cannot be achieved.
In forming a molecular compound, each atom should have valence electrons around it unless there is some specific reasons why this cannot be achieved.
What is Valence Electrons ?Valence electrons is a negatively charged particle present in the outermost shell of an atom.
Example: Oxygen has 6 valence electrons in its outermost shell, Water has 8 valence electrons.
Thus from the above conclusion we can say that In forming a molecular compound, each atom should have valence electrons around it unless there is some specific reasons why this cannot be achieved.
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Cold solvents are preferred for recrystallization because Group of answer choices Hot solvents catch fire easily to prevent dissolution of the crystals impurities are expected to have high solubility in cold solvents Cold solvents are cost effective
Crystals impurities are expected to have high solubility in cold solvents. Hence, option C is correct.
What is a cold solvent?Cold solvent cleaning is a process used to remove grease, wax and other impurities from metal and other parts.
The process is also called degreasing. Cold solvents are sprayed onto the dirty part and it is brushed clean.
Once the filtration process is done the collected crystals should be washed with a little more ice-cold solvent to remove final soluble impurities which would otherwise be left on the surface of the crystals.
Hence, option C is correct.
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300 mL of salt solution contains 6.5 grams of NaCl (molecular mass of sodium chloride is 58.44 ul.
What is its molarity?
M=n/V
M=(6.5/58.44) mol : 0.3 L
M=0.371
Answer:
.371 M
Explanation:
Molarity, M, is calculated as moles solute/ liters of solvent
6.5 gms of salt is 6.5 / 58.44 = .111225 moles
300 ml = .3 L
.111225 moles / .3 L = .371 M
When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass of sodium sulphate that was used
The mass of sodium sulfite that was used will be 1,890 grams.
Stoichiometric problemsFirst, the equation of the reaction:
[tex]NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2[/tex]
The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.
Mole of 960 grams SO2 = 960/64 = 15 moles
Equivalent mole of sodium sulfite that reacted = 15 moles
Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams
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Ferric chloride is being applied for coagulation at a 15.0 MGD surface water treatment plant, at a rate of 195 pounds per day. At this application rate, how many pounds of this chemical will be used in a 30-day month
5850 pounds of this chemical will be used in a 30-day month.
195 pounds per day.
So, 30 days = 195 * 30
= 5850 pounds
Iron(III) chloride is the inorganic compound with the components FeCl 3. additionally known as ferric chloride, it is a commonplace compound of iron inside the +3 oxidation country. The anhydrous compound is crystalline and stable with a melting point of 307.6 °C.
The primary use of ferric chloride is to dispose of impurities in water and for wastewater treatment. Ferric chloride is likewise one of the few water remedy chemical compounds that can sequester odors.
Reasonably poisonous with the aid of ingestion but a strong irritant to the skin and eyes. it's far moderately corrosive and skin touch should be avoided and avoid skin and eye contact.
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At constant pressure, the ratio between the volume expansion of a mole of gas with a high Cp to that of a mole of gas with a low Cp for a given heat input will be
At constant pressure, the ratio between the volume expansion of a mole of gas with a high Cp to that of a mole of gas with a low Cp for a given heat input is Less than 1.
How are Cp and Cv related to one another?The molar heat capacity of a substance is expressed as Cp when the pressure is constant and as Cv when the volume is constant. These two parameters so describe the molar heat capacity at various pressures and temperatures.
Constant Volume and PressureThe first law of thermodynamics states that heat delivered to a system can either be converted into internal energy or used to generate work in the environment. An isochoric process is one in which the volume is constant, whereas an isobaric process is one in which a gas interacts with its surroundings at constant pressure.
Constant PressureAn isobaric process takes place at constant pressure. Since the pressure is constant and the work is denoted by PV, the force applied is constant.
If gas is to expand at an isobaric pressure at a certain pressure, heat must be introduced into the system at a specific rate. For instance, a movable piston in a cylinder keeps the pressure inside the cylinder constant at atmospheric pressure despite the fact that it is isolated from the atmosphere. In other words, a moveable barrier serves as a dynamic link between the system and a constant-pressure reservoir.
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what is a neutral atom of nitrogen-14
Answer:
You know that nitrogen-14 has 7 protons in the nucleus because it is an isotope of nitrogen, which has an atomic number equal to 7 . Because nitrogen-14 is a neutral atom, the number of protons it has in its nucleus must be equal to the number of electrons that surround its nucleus.
How many moles of PCl5 can be produced from 28.0 g of P4 (and excess Cl2 )? Express your answer to three significant figures and include the appropriate units.
0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).
What is Stoichiometry ?Stoichiometry helps us to use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the balanced chemical equation
P₄ + 10 Cl₂ → 4PCl₅
1 mole of P₄ react with 10 mole of Cl₂ produces 4 moles of PCl₅.
According to Stoichiometry
[tex]\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}[/tex]
[tex]n_{P_4} = \frac{\text{Given Mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{28\ g}{124\ g/mol}[/tex]
= 0.22580645161 mol
Now put the value in above equation
[tex]\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}[/tex]
[tex]\frac{0.22580645161}{1} = \frac{n_{PCl_5}}{4}[/tex]
[tex]n_{PCl_5} = 0.903[/tex] mol
Thus from the above conclusion we can say that 0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).
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Set up the math problem. But don’t do any of it. Just leave your answer as a math expression. Also be sure you’re answering clues all the correct the units symbols.
Answer:
Length = 681 grams / (44.5 grams / kilometers) = (681 / 44.5) kilometers
Explanation:
The diameter is there to throw us off, so ignore that. There is 681 grams of wire, and since there is 44.5 grams of copper per km of wire, and we want to know how many kilometers of wire makes 681 grams, the equation would be X*44.5 = 681, or X = 681/44.5
Also quora's censoring system is terrible i can't even say kilometers by adding the letter s after "km"
What mass of Na2CrO4 is required to precipitate all of the silver ions from 75.0 mL of a 0.100 M solution of AgNO3
The mass of [tex]Na_2CrO_4[/tex] required will be 0.6075 g.
Calculation of mass:
The reaction:
[tex]Na_2CrO_4 + 2AgNO_3 \rightarrow Ag_2CrO_4 + 2NaNO_3[/tex]
Volume of [tex]AgNO_3[/tex] = 75 mL
Concentration of [tex]AgNO_3[/tex] = 0.100 M
Step 1:
Molarity is moles of solute in 1000 mL of the solution.
[tex]M=\frac{n}{V}\times 1000\\\\ n=\frac{M\times V}{1000} \\\\n=\frac{0.100\times 75}{1000}\\\\n= 0.0075[/tex]
Moles of [tex]AgNO_3[/tex] = 0.0075
Step 2:
From the above equation,
2 moles of [tex]AgNO_3[/tex] is precipitated by 1 mole of [tex]Na_2CrO_4[/tex]
So, 0.0075 moles will be precipitated by-
[tex]\frac{1}{2}\times 0.0075[/tex] moles of [tex]Na_2CrO_4[/tex]
= 0.00375 moles of [tex]Na_2CrO_4[/tex]
Step 3:
[tex]mole=\frac{Given \,weight}{Molar\, mass} \\[/tex]
Molar mass of [tex]Na_2CrO_4[/tex] = 162 g/mol
[tex]0.00375=\frac{x}{162} \\x= 0.00375\times 162\\x= 0.6075 g[/tex]
So, Mass of [tex]Na_2CrO_4[/tex] required will be 0.6075 g.
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Are isotopes similar to ions, yes or no?
Use distributive law evaluate
Answer:
The distributive property of multiplication is used when we need to multiply a number with the sum of two or more addends. The distributive property of multiplication is applicable to addition and subtraction of two or more numbers.
Hope its helpful!
Answer:
The distributive property of multiplication is used when we need to multiply a number with the sum of two or more addends. The distributive property of multiplication is applicable to addition and subtraction of two or more numbers.
Explanation:
You have been asked to determine the thermometer correction for a melting point apparatus. You obtain a pure sample of benzoic acid and determine its melting point range carefully. After several trials, you obtain a very sharp melting point of 125.7 degrees celsius. What is the thermometer correction at this temperature
The thermometer correction at this temperature is =125.7 -122.4
=3.3 degrees celsius
(Very pure benzoic acid has a melting point of 122.4 degrees Celsius.)
ThermometerA thermometer is a device used to measure and display temperature. It normally consists of a short, glass tube that is hermetically sealed, graduated, and has a mercury or alcohol bulb at one end that expands and contracts with temperature changes.
Calibration of thermometers:-A significant source of measurement error in melting points could be our thermometer. It is occasionally possible for ordinary laboratory thermometers to be inaccurate and to read temperatures up to 10°C high or low. we should calibrate your thermometer regularly to identify any errors and be able to make adjustments. This will help us avoid this issue.
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One of the nuclides in spent nuclear fuel is U-235 , an alpha emitter with a half-life of 703 million years. How long will it take for an amount of U-235 to reach 29.0% of its initial amount
It will take 1.254 billion years to reach 29% of the original amount of U-235.
First-order Radioactive Decay:The rate constant can be calculated from the half-life. The relationship of the two is shown below:
[tex]t_{0.5} =\frac{In 2}{k}[/tex]
[tex]k=\frac{In 2}{703}[/tex]
[tex]= 9.86[/tex] × [tex]10 ^-^{4} my^{-1}[/tex]
The first-order integrated rate law of a nuclide undergoing radioactive decay is;
ln[A]_t = -kt + ln[A]_0.
[tex]ln 0.29 = ln1 - 9.86[/tex] × [tex]10^-^4[/tex] [tex]t[/tex]
[tex]ln0.29= -9.86[/tex] × [tex]10^-^4[/tex]
[tex]t=[/tex] [tex]1254.5 my[/tex]
It will take 1.254 billion years to reach to 29% of the original amount.
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A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The calorimeter and the water have a combined mass of 250.0 g and an overall specific heat of 1.035 cal/g•°C. The initial temperature of the calorimeter is 10.00°C. The system reaches a final temperature of 11.08°C when the metal is added.
Taking into account the definition of calorimetry, the specific heat of metal is 0.165 [tex]\frac{cal}{gC}[/tex].
Definition of calorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.C is the specific heat substance.ΔT is the temperature variation.Specific heat capacity of the metalIn this case, you know:
For metal:
Mass of metal = 50 gInitial temperature of metal= 45 °CFinal temperature of metal= 11.08 ºCSpecific heat of metal= ?For water:
Mass of water = 250 gInitial temperature of water= 10 ºCFinal temperature of water= 11.08 ºCSpecific heat of water = 1.035 [tex]\frac{cal}{gC}[/tex]Replacing in the expression to calculate heat exchanges:
For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)
For water: Qwater= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× (11.08 C - 10 C)
If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.
Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:
- Qmetal = + Qwater
- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× (11.08 C - 10 C)
Solving:
- Specific heat of metal× 50 g× (-33.92 C)= 1.035 [tex]\frac{cal}{gC}[/tex] × 250 g× 1.08 C
Specific heat of metal× 1696 g×C= 279.45 cal
Specific heat of metal= [tex]\frac{279.45 cal}{1696 gC}[/tex]
Specific heat of metal= 0.165 [tex]\frac{cal}{gC}[/tex]
Finally, the specific heat of metal is 0.165 [tex]\frac{cal}{gC}[/tex].
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Project: practice in measuring metric volumes
Either a Pyrex measuring cup or a graduated cylinder can be used to measure the metric volumes of any liquid.
What is a graduated cylinder?A graduated cylinder is also called a measuring cylinder and it can be defined as a narrow, cylindrical piece of laboratory equipment with marked lines, which are used to measure the volume of a liquid.
How to measure metric volumes?Generally, a student or researcher can use a Pyrex measuring cup to measure the metric volumes of any liquid when a graduated cylinder isn't available.
In conclusion, you should record your estimates and the actual measurements for all the containers that were used in your project.
Read more on graduated cylinder here: https://brainly.com/question/24869562
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