As shown in the figure, a square insulating slab 5.0 mm thick measures 2.0 m ×
2.0 m. It has a charge of 8.0 × 10^-11 C distributed uniformly throughout its volume. Use Gauss’s law to determine the electric field at point P, which is located within the slab, 1.0 mm from the top face.
Assume P is far from the (front, back, left, and right) sides of the slab. (ε0 = 8.85 × 10^-12 C2/N ∙ m2)

So, we have that the speed of the person relative to the dock is 6.36 m/s

Let

where their speeds are the magnitudes of their velocities

Given that a ferry approaches shore, moving north with a speed of 6.2 m/s relative to the dock and a person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.4 m/s relative to the ferry.

We have that their velocities are

So, V' = v + V

So, V' =  (1.4 m/s)i + (6.2 m/s)j

So, the speed of the person relative to the dock is the magnitude of V which is

V' = √(v² + V²)

So, substituting the value of the variables into the equation, we have

V' = √(v² + V²)

V' = √[(1.4 m/s)² + (6.2 m/s)²]

V' = √[1.96 m²/s² + 38.44 m²/s²]

V' = √[40.4 m²/s²]

V' = 6.36 m/s

So, the speed of the person relative to the dock is 6.36 m/s

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The speed at which the dish move after combining into a single, wonderful concoction is 1.92 m / s

p = m v

p = Momentum

m = Mass

v = Velocity

According to law of conservation of momentum,

Total initial momentum = Total Final momentum

[tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex] [tex]v_{2}[/tex] = [tex]m_{1}[/tex] [tex]v_{1}[/tex]' + [tex]m_{2}[/tex] [tex]v_{2}[/tex]'

Since the dish is combined into a single, wonderful concoction, it will move with the same velocity,

[tex]v_{1}[/tex]' = [tex]v_{2}[/tex]' = v'

[tex]m_{1}[/tex] [tex]v_{1}[/tex]+ [tex]m_{2}[/tex] [tex]v_{2}[/tex] = [tex]m_{1}[/tex] v' + [tex]m_{2}[/tex] v'

[tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex] [tex]v_{2}[/tex] = ( [tex]m_{1}[/tex] + [tex]m_{2}[/tex] ) v'

v' = ( [tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex] [tex]v_{2}[/tex] ) / ( [tex]m_{1}[/tex] + [tex]m_{2}[/tex] )

[tex]m_{1}[/tex] = 215 g

[tex]m_{2}[/tex] = 349 g

[tex]v_{1}[/tex] = 1.63 m / s

[tex]v_{2}[/tex] = 2.10 m / s

Substituting these values in v'

v' = [ ( 215 * 1.63 ) + ( 349 * 2.10 ) ] / ( 215 + 349 )

v' = ( 350.43 + 732.9 ) / 564

v' = 1083.33 / 564

v' = 1.92 m / s

Therefore, the dish moves at 1.92 m / s

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Total momentum of masses after collision is : 100kgm/s

velocity of the masses after collision is : 5m/s

The conservation of momentum principle states that the amount of momentum within a problem domain remains constant; momentum is neither created nor destroyed, but only changed by the action of forces as described by Newton's laws of motion.

To find total momentum ,

we have to find momentum of each object .

Momentum of object with 16kg masses,

p = mv

here m = 16 kg  and v = 5m/s

p1 =16×5

=80kgm/s

momentum of object with 4kg masses, and v =5m/s

p2 = 4 x 5

= 20kgm/s

total momentum is,

P = p1 + p2

80 + 20 = 100kgm/s

total momentum after collision,

100kgm/s (law of conservation of momentum)

velocity of masses is ,

total p= (m1+m2)×v

100 = (16+4)v

v = 100÷20

v = 5m/s

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121 m far up the hill does he go.

Vo = 31.3 m/s

Angle [tex]\theta[/tex] = [tex]20^o[/tex]

Yo = 31.3*sin20

     = 28.57 m/s.

[tex]Y^2 = Yo^2 + 2g*h = 0.[/tex]

[tex]28.57^2 - 19.6h = 0 \\19.6h = 816.4\\ h = 41.6 m.[/tex]

[tex]d*sin20 = 41.6\\ d = 121 m. -- > up \ hill.[/tex]

Friction is a force that opposes the relative motion of solid surfaces, fluid layers and material elements that slide against each other.

There are four types of friction and they are classified as follows:

Applications of friction

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Considering the definition of power, the amount of power used was 405 W.

Power is the amount of work (force or energy applied to a body) in a unit of time.

In this sense, mechanical power is the amount of force applied to a body in relation to the speed with which it is applied.

Mathematically, the power P is the result of multiplying the force by the execution speed:

P = F×v

where

In this case, you know:

Replacing in the definition of power:

P = 225 N× 1.8 m/s

Solving

P= 405 W

Finally, the amount of power in this case is 405 W.

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A skier has just begun descending a 20° slope, so the Acceleration of the skier will be -4.7 m/s².

Average velocity is a vector quantity. The change in position or displacement divided by the periods during which the displacement happens is known as average velocity. Depending on how the displacement is displaced, the average velocity may be positive or negative. Meters per second (m/s), the SI unit of average velocity, is used.

Average Velocity= [tex]Total\ Displacement/ Total\ Time[/tex]

According to the question,

Skier is on a 20° down slope.

Portion of weight parallel to and down slope.

f₁ = (sin20°)mg = 0.3 × mg

The friction force resists motion parallel to the slope, therefore its sign is opposite that of f1, and it is equal to the kinetic coefficient of friction times the weight's surface normal component.

f₂ = -μ(cos30°)mg = -0.9*0.8660 × mg

f₂ = -0.7794 × mg

The net force on the skier parallel to and down the slope

F = f₁ + f₂ = (0.3 -0.7794)mg

F = -0.4794 × mg

By Newton’s second law, net acceleration parallel to and down slope.

a = F/m = -0.4794 × g

For g = 9.807 m/s²,

a = -0.4794 × 9.807 = -4.7 m/s².

So, the acceleration of the skier will be -4.7 m/s².

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The chicken needs to have an acceleration such that after time t his Velocity is 0, shown in the equation:

0 = V + at

-5.8 = 1.1 x a

a = -5.8 / 1.1

a = -5.2727 m/s/s.

The distance traveled in a time t with velocity V and acceleration is given by:

D = Vot + 1/2 at2

D = 5.8 x 1.1 - 1/2 x 5.2727 x 1.12

D = 3.19m.

Acceleration is the name we give to the process of changing velocity. Velocity is both speed and direction, so there are only two ways to accelerate. Either change speed, change direction, or change both. There are three main types of accelerated motion uniform acceleration, unequal acceleration, and average acceleration.

The term uniform acceleration refers to the motion of a body moving in a straight line with an increasing velocity at equal time intervals. Velocity is the rate of change of displacement. Acceleration is the rate of change of velocity. Velocity is a vector quantity because it consists of both magnitude and direction. Since acceleration is the rate of change of velocity it is also a vector quantity. Acceleration occurs whenever an object increases or decreases its speed or changes direction.

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We can use the following equation to solve for V, voltage:

V = IR, where

I: current, and R: resistance

Let's plug in our known variables, current and resistance:

V = 4.5*100

Then solve for V:

V = 450V

Based on the structure of the element shown, the element belongs to group 2A of the periodic table.

Families of elements in the periodic table refer to the elements that are found in the same vertical column in the periodic table.

The families of elements in the periodic table are also called groups.

Elements belonging to the same family in the periodic table have similarities in their properties, both physical and chemical.

The group or family to which an element belongs to depends on the number of electrons found in the valence shell of the element.

Elements in the same group have the same number of electrons in their valence shells. For example, elements in group 1A of the periodic table have one valence electron in their valence shell.

Considering the given element;

The element has three electron shells.

In the valence or outermost shell, there are 2 electrons in the atom of the element. This means that the element would belong to the family of elements that have two valence electrons, group 2A.

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The velocity of the ship heading due north at 9.00 m/s relative to the water has a velocity of 10 m / s relative to the earth.

Let S represent ship, W represent water and E represent Earth.

[tex]V_{SW}[/tex] = 9 m / s N

[tex]V_{WE}[/tex] = 1.52 m / s NE

Resolving [tex]V_{OE}[/tex] into its x and y components.

cos θ = Adjacent side / Hypotenuse

cos 40° = [tex]V_{OE}_{x}[/tex] / [tex]V_{OE}[/tex]

[tex]V_{WE}_{x}[/tex] = 0.77 * 1.52

[tex]V_{WE}_{x}[/tex] = 1.17 m / s

sin θ = Opposite side / Hypotenuse

sin 40° = [tex]V_{OE}_{y}[/tex] / [tex]V_{OE}[/tex]

[tex]V_{WE}_{y}[/tex] = 0.64 * 1.52

[tex]V_{WE}_{y}[/tex] = 0.97 m / s

[tex]V_{SE}[/tex] = [tex]V_{SW}[/tex] + [tex]V_{WE}[/tex]

[tex]V_{X}[/tex] = [tex]V_{SW}_{x}[/tex] + [tex]V_{WE}_{x}[/tex]

[tex]V_{X}[/tex] = 0 + 1.17

[tex]V_{X}[/tex] = 1.17 m / s

[tex]V_{Y}[/tex] = [tex]V_{SW}_{y}[/tex] + [tex]V_{WE}_{y}[/tex]

[tex]V_{Y}[/tex] = 9 + 0.97

[tex]V_{Y}[/tex] = 9.97 m / s

R = √ [tex]V_{X}[/tex]² + [tex]V_{Y}[/tex]²

R = √ 1.17² + 9.97²

R = √ 1.37 + 99.4

R = √ 100.77

R = 10 m / s

Therefore, the velocity of the ship relative to the earth is 10 m / s

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Considering the energy systems:

Energy is the ability to do work.

There are several forms of energy such as:

Generally, all matter possesses energy that can be used to do work.

The various forms of energy can be interconverted.

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Answer:

W = 5593.3 J

Explanation:

The work can be calculated as

W = Fdcosθ

Where F is the force, d is the distance and θ is the angle.

So, replacing F = 156N, d = 45.5 m and θ = 38, we get:

W = (156N)(45.5m)(cos38)

W = (156N)(45.5m)(0.788)

W = 5593.3 J

Average velocity is total distance divided by total time. The magnitude of his average velocity for the entire trip is 23.15 m/s

Velocity is the distance travel in a specific direction per time taken. It is a vector quantity. And it is measured in m/s

If Billie travels 3.2 km due east in 0.1 hr, then 3.2 km at 15.0 degrees eastward of due north in 0.21 hr, and finally another 3.2 km due east in 0.1 hr. Then,

Billie total distance S travel = 3.2 + 3.2Cos 15 + 3.2

S = 9.49 Km

Billie total time T  = 0.1 + 0.21 + 0.1

T = 0.41 s

The magnitude of his average velocity for the entire trip = S/T

Average velocity = 9.49/ 0.41

Average velocity = 23.15 m/s

Therefore, the magnitude of his average velocity for the entire trip is 23.15 m/s

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Answer: w=1.84 rad/s

Explanation:  

During the experiment, the angular velocity will be allowed to vary. If the mass of the rotating object is 5 kg and the radius of rotation is 0.2 m, what will be the angular velocity, ω, when the force sensor reads 3.4 N?

first we set 3.4N = to the equation [tex]5kg(w)^{2}* .20[/tex]

solving for w [tex]w^2=17/5[/tex]

[tex]w=(\sqrt{85})/5 \\[/tex]

[tex]w=1.84391[/tex]

w=1.84 rad/s

Answer:

See below

Explanation:

INTAKE   -   compression   -    power    -   exhaust    for a 4 stroke engine

Answer:  intake

Explanation:

I took the quiz.

The surface charge density on the disk is 1.73 x 10⁻⁸ C/m².

The surface charge density of the glass is 9.36 x 10⁻⁵ C/m²

The magnitude of the charge is calculated as follows;

V = kQ/r

where;

kQ = Vr

Q = Vr/k

Q = (1800 x 0.68 x 10⁻³) / (9 x 10⁹)

Q = 1.36 x 10⁻¹⁰ C

The surface charge density of the disk is calculated as follows;

σ = Q/A

σ = Q/(4πr²)

where;

σ = Q/(4πr²)

σ = (1.36 x 10⁻¹⁰ )/(4π x 0.025²)

σ = 1.73 x 10⁻⁸ C/m²

The surface charge density of the glass is calculated as follows;

σ = Q/A

σ = Q/(4πr²)

where;

σ = Q/(4πr²)

σ = (1.36 x 10⁻¹⁰ )/(4π x 0.00034²)

σ = 9.36 x 10⁻⁵ C/m²

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Answer:

Answer:

Explanation:4.0-135m/ 18s = 131/18s = -7.2 m/

The electric force on the charge Fc = 9.439 x 10⁹N(m/C)²

To calculate the electric force on different charges and a certain distance,

Use formula,

Fc = k (q₁q₂)/r²

Where,

Fc is electric force

k is coulomb's constant

q₁ is charge at one point

q₂ is charge at second point

r is the distance

Known values,

q₁ = 15μC

q₂ = 7μC

k =  8.99 × 10⁹ Nm² /C²

r = 10cm

Fc = ?

Now, putting the values

Fc =  8.99 × 10⁹ Nm² /C² (15μC x 7μC)/(10cm)²

Fc =  8.99 × 10⁹ N(m/C)² x 1.05

Fc = 9.439 x 10⁹N(m/C)²

Hence, the electric force is Fc = 9.439 x 10⁹N(m/C)².

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Answer: global wind systems

Explanation: Surface currents in the ocean are driven by global wind systems that are fueled by energy from the Sun. Patterns of surface currents are determined by wind direction, Coriolis forces from the Earth's rotation, and the position of landforms that interact with the currents.

The acceleration of the motorcycle = -11m/s²

The initial speed of the motorcycle, u = 55 m/s

The motorcycle takes 5 seconds to stop and relax

That is, the final speed, v = 0 m/s

Time, t = 5 seconds

Acceleration = (Change in speed)/Time

The acceleration of the motorcycle = -11m/s²

"Y is directly related to the square of x" is represented by the polynomial equation y = kx². A polynomial equation is one that has the polynomial factored down to zero.

Polynomial equations would be those created using exponent, variables, and factors. The greater of its potential exponents is referred to as the equation's degree. By multiplying polynomials as according their degree and the variables in the equation, we can find the solutions.

The highest or greatest power of a variable in a polynomial equation is referred to as the degree of the polynomial. The degree denotes the polynomial's highest exponential power (ignoring the coefficients).

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The force of attraction between Mars and one of its moon;                                                                                                           F= 5.16*10²¹

The gravitational force is the force that the earth exerts on a body to attract it. Examples of motion caused by gravitational force include the downward motion of water in rivers and streams, the upward motion of thrown objects such as balls, and the downward motion of the leaves and fruits of trees as they fall to the earth.

"The bigger of Mars' two moons, Phobos, measures 17 x 14 x 11 miles (27 x 22 x 18 kilometers) in diameter. It makes three daily circuits around Mars and is so near the planet's surface that it cannot always be seen there."

The product of mass and mass is directly proportional to the gravitational force between two large objects. The gravitational attraction between Mars and Phobos is.

Newton's law of universal gravitation:  Fg = Gm1m2/r2

Where,

F = Force =

G = Gravitational constant = 6.6743 × 10-11 N.m²/kg²

m2 = Mass of Mars = 6.42 x 10²³ (approx 10.7 % of Earth)

m2 = Mass of Phobos = 10.6 x 1015                                                                                        r = Distance between centers of the masses= 9,376 km

Put the values in the formula,                                                                                              

F = 6.6743 * 10-11 *  [tex]\frac{6.42 x 10^2^3 * 10.6 x 10^1^5}{ 9,376^2}[/tex]                                                                                              F= 5.16*10²¹

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Explanation:

The heat flow can be calculated as

Where k is the thermal conductivity, A is the area, T1 is the temperature of the ice water, T2 is the temperature of the room, and L is the thickness.

Replacing k = 0.01 J/(s m °C), A = 0.950 m², T1 = 0°C, T2 = 35 °C and L = 2.50 cm = 0.025 m, we get

Therefore, the heat flow through the walls is 13.3 W.

The negative sign indicates the direction of the heat flow, in this case, the heat goes to the water.

Answer:

F=ma

=60×1

=60N

Explanation:

straightforward formula

C9H20 is expected to have the largest dispersion forces among the given four options.

The strength of dispersion force increases with number of electrons in the molecule.

Number of electrons in an element = Atomic number * Number of atoms

Atomic number of

Number of electrons in C9H20 = ( 6 * 9 ) + ( 1 * 2 ) + ( 8 * 1 )

Number of electrons in C9H20 = 64

Number of electrons in F2 = 9 * 2

Number of electrons in F2 = 18

Number of electrons in CH4 = ( 6 * 1 ) + ( 1 * 4 )

Number of electrons in CH4 = 10

Number of electrons in PH3 = ( 15 * 1 ) + ( 1 * 3 )

Number of electrons in PH3 = 18

Therefore, C9H20 is expected to have the largest dispersion forces.

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Syncopation in music is the off-beating of all or a portion of a tune or piece of music by combining different rhythms. Adding syncopation is NOT a way to change a rhythm.

Syncopation in music is the off-beating of all or a portion of a tune or piece of music by combining different rhythms. Syncopation can be defined more simply as "a disruption or interruption of the regular flow of rhythm" or "the placement of rhythmic stresses or accents where they wouldn't normally occur."

By challenging our perceptions of where the beat should be, syncopation adds excitement to the music. When every note falls on the anticipated beat, this groove-inducing technique departs from the straight feel. Syncopation also draws the listener's attention. Syncopation is NOT a method of altering rhythm.

Therefore, the correct answer is option A. Adding syncopation.

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The energy needed to raise the temperature of 1 kg of lead from 40 °C to 60°C will be 2600 Joules.

We can calculate the energy of a substance by using the given formula:

Q = mc∆T

where;

Q = quantity of heat absorbed or released

m = mass of the substance

c = specific heat capacity

∆T = change in temperature(°C)

Now, according to the given question, 1 kg of lead has to be raised from 40°C to 60°C and we also have the specific heat capacity(c) of lead that is 130J/kg°C.

We can calculate the energy by putting the given values in the above equation:

Q = mc∆T

= 1 × 130 × (60-40)

= 20 × 130

Q = 2600J

Therefore, the amount of energy required to raise the temperature of 1 kg of lead from 40°C to 60°C is 2600J.

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Answer:

Explanation:

Scientific laws or laws of science are statements, based on repeated experiments or observations, that describe or predict a range of natural phenomena.

On the apple, we apply "antigravitational force."

The apple exerts "gravitational force" on us.

The gravitational attraction, an attractive force whose magnitude is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another, draws all mass-containing things together.

You can never decrease the gravitational pull produced by adding mass. It is possible for gravitational forces acting in opposition to one another to cancel one another out and leave no net force. It would be conceivable for gravity to push objects instead of always dragging them if it weren't always additive.

A place or thing being free from the pull of gravity is the goal of the hypothetical phenomena known as anti-gravity. It doesn't mean balancing the force of gravity with another force, like electromagnetism or aerodynamic lift, or the lack of weight under gravity felt in free fall or orbit.

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